Answer:
the work done by friction on the car is 524,582 J.
Explanation:
Given;
mass of the roller coaster, m = 800 kg
distance moved by the coaster, d = 225 ft = 68.58 m
final velocity of the coaster, v = 80 mi/h = 35.76 m/s
The time taken for the coaster to drop down the hill is calculated as;
[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\ \times \ 68.58}{9.8} } \\\\t = 3.74 \ s[/tex]
The work done by friction on the car is calculated as;
[tex]W =F\ \times \ d = \frac{mv}{t} \times \ d\\\\W = \frac{800 \ \times \ 35.76 }{3.74} \times \ 68.58\\\\W = 524,582 \ J[/tex]
Therefore, the work done by friction on the car is 524,582 J.
Before working this problem, review Conceptual Example 14. A pellet gun is fired straight downward from the edge of a cliff that is 14.7 m above the ground. The pellet strikes the ground with a speed of 27.2 m/s. How far above the cliff edge would the pellet have gone had the gun been fired straight upward
Answer:
23.04 m
Explanation:
We'll begin by calculating the initial velocity of the pellet. This can be obtained as follow:
Height (h) of cliff = 14.7 m
Final velocity (v) = 27.2 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Initial velocity (u) =?
v² = u² + 2gh
27.2² = u² + (2 × 9.8 × 14.7)
739.84 = u² + 288.12
Collect like terms
u² = 739.84 – 288.12
u² = 451.72
Take the square root of both side
u = √451.72
u = 21.25 m/s
Thus, the initial velocity of the pellet is 21.25 m/s.
Finally, we shall determine the maximum height to which the pellet would have gone assuming the gun was fired straight upward. This can be obtained as follow:
Initial velocity (u) = 21.25 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) = 0 m/s (at maximum height)
Maximum height (h) =?
v² = u² – 2gh (since the pellet is going against gravity.
0² = 21.25² – (2 × 9.8 × h)
0 = 451.5625 – 19.6h
Collect like terms
0 – 451.5625 = –19.6h
–451.5625 = –19.6h
Divide both side by –19.6
h = –451.5625 / –19.6
h = 23.04 m
Therefore, the pellet will reach a maximum height of 23.04 m above the cliff.
1. li took 2 } seconds for a car's vclocity to change from 20 m/s to 15 m/s. The mass of the car was 1370 kg. What force was required to cause the acceleration? (Hint: First calculate the acceleration.
Answer:
Do you still need help??
Explanation:
Explain why your PE and KE are usually not both high at the same time (If PE is high then usually KE is low)
Two forces P and Q act on an object of mass 7.00 kg with Q being the larger of the two forces. When both forces are directed to the left, the magnitude of the acceleration of the object is 1.40 m/s2. However, when the force P is directed to the left and the force Q is directed to the right, the object has an acceleration of 0.700 m/s2 to the right. Find the magnitudes of the two forces P and Q .
Answer:
Explanation:
Q is larger than P . When two forces act in the same direction , Resultant force
can be calculated by adding them up . When two forces act in the opposite direction , Resultant force can be calculated by subtracting them .
Force = mass x acceleration .
In the first case
Resultant force = mass x acceleration
P + Q = 7 x 1.4 = 9.8 N
In the second case
Q - P = 7 x 0.7 = 4.9
Adding up these two equations
2 Q = 14.7
Q = 7.35 N
P = 9.8 - 7.35 = 2.45 N .
Problem 6: A bullet in a gun is accelerated from rest from the firing chamber to the end of the barrel at an average rate of 6.3 × 105 m/s2 for 8.2 × 10-4 s.Ball,removedc795646bb4371e1754411a7dadf94458c503446af1b6450bb3269c1f97e8ef53removedremoved58b1e9a401041b69266daacea519e828d050d14013adc67f8c64697e40f2ef89removedtheexpertta - tracking id: 0W86-2A-6A-4E-962A-28979. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account.show answer No Attempt What is the gun’s muzzle velocity (that is, the bullet’s final speed), in meters per second
Answer:
v = 5.166 10² m / s
Explanation:
We can solve this exercise using the kinematics equations
v = v₀ + at
as the bullet starts from rest its initial velocity is zero
v = a t
let's calculate
v = 6.3 10⁵ 8.2 10⁻⁴
v = 5.166 10² m / s
4. John drives his car 5 miles north to visit his friend, and then drives 7 miles east to go to the store,
What is John's displacement? * 1
Answer:
John's displacement is 8.6 miles.
Explanation:
We need to fin the magnitude of the sum of the partial displacement. So we will have:
[tex]d=\sqrt{5^{2}+7^{2}}[/tex]
[tex]d=8.6\: miles[/tex]
I hope it helps you!
Potential energy is defined as
A. energy of motion
B. moving another object
C. stored energy
Answer:
c
Explanation:
it is stored energy because it is built up in said object
please help me out with these !! 50 points would greatly appreciate it.
Answer:
Its nymber 2
Explanation:
Please help! This is due in 10 minutes
Answer:
Atom - the basic particle of matter
Density - calculated from measurements of mass and volume
Motion - calculated from measurements of distance and time
Energy - can change form and move matter
Matter - the scientific word for stuff
Hope this helps! Please mark brainliest if correct :D
When observing the two diagrams, what is a concept shared by both?
Answer:
Convection
Explanation:
Convection refers to the transfer of heat by the actual movement of the heated molecules from the hot parts to the cooler parts.
Thus, the two diagrams show illustrate transfer of heat by the movement of molecules of a fluid.
This mode of heat transfer is known as convection. It is the concept illustrated by both diagrams.
It takes 52,000 Joules to heat a cup of coffee to boiling from room temperature. How long a piece of 20 cm wide Aluminum foil would it take to make a capacitorlarge enoughto hold this amount of energy if one were to use plastic garbage bag with a 2.6 x 10-5m thickness that breaks down at 610 volts as a dielectric
Answer:
L = 1.11 x [tex]10^{6}[/tex] m, is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.
Explanation:
Solution:
Data Given:
Heat Energy = 52000 J
Dielectric Constant of the plastic Bag = 3.7 = K
Thickness = 2.6 x [tex]10^{5}[/tex] m =d
V = 610 volts
A = width x Length
width = 20 cm = 20 x [tex]10^{-2}[/tex] m
Length = ?
So,
we know that,
U = 1/2 C Δ[tex]v^{2}[/tex]
U = 52000 J
C = ?
V = 610 volts'
So,
U = 1/2 C Δ[tex]v^{2}[/tex]
52000 J = (0.5) x (C) x ([tex]610^{2}[/tex])
C = 0.28 F
And we also know that,
C = [tex]\frac{K*E*A}{d}[/tex]
E = 8.85 x [tex]10 ^{-12}[/tex]
K = 3.7
A = 0.20 x L
d = 2.6 x [tex]10^{5}[/tex] m
Plugging in the values into the formula, we get:
0.28 = [tex]\frac{3.7 * 8.85 .10^{-12} * (0.20 . L) }{2.6 . 10^{5} }[/tex]
Solving for L, we get:
L = 1.11 x [tex]10^{6}[/tex] m,
is the length of piece of 20 cm wide Aluminum foil to make capacitor large enough to hold 52000 J of energy.
What is the momentum of a 0.000015 kg mosquito flying straight at you with a velocity of 5.20 m/s?
Answer:
Momentum, [tex]p=7.8\times 10^{-5}\ N-m[/tex]
Explanation:
Given that,
Mass of a mosquito, m = 0.000015 kg
Velocity of the mosquito, v = 5.2 m/s
We need to find the momentum of the mosquito. The momentum of an object is given by :
p = mv
Put all the values in the above formula.
[tex]p=0.000015\ kg\times 5.2\ m/s\\\\p=0.000078\ N-m\\\\\text{or}\\\\p=7.8\times 10^{-5}\ N-m[/tex]
So, the momentum of the mosquito is [tex]7.8\times 10^{-5}\ N-m[/tex].
write short note on fulcrum
Answer:
The definition of a fulcrum is a pivot point around which a lever turns, or something that plays a central role in or is in the center of a situation or activity.
Which is an advantage of storing data digitally?
A. It is easy to change the data if you have the right computer
programs.
B. It is easy to copy a computer virus to a device along with the data.
C. The quality of copies decrease as more copies are made.
D. Other people can access personal data from unsecured devices.
Answer:
A
Explanation:
Because I said so
Answer:
A
Explanation:
i took the test and got it right please mark me ❤️
Jojo and Roro begin side-by-side at one end of the playground. At the same moment, they begin to move toward the other end of the playground, Jojo at a constant velocity of 3.0 m/s, Roro at a constant velocity of 2.0 m/s. Sometime during her trip, Roro stops to rest for 2.0 s, but then starts again at her original constant speed. When Jojo reaches the end of the playground, she is 10 m ahead of Roro.
(a) For how much time did Roro move?
(b) How far did Roro move? (Set it up, good notation, equations in symbols first, etc.)
Answer:
Roro's total travel time = 6 seconds out of which he rested for 2 seconds
Distance covered by Roro = 8 meters
Explanation:
Given that :
Jojo:
Constant velocity, v = 3m/s
Travel time = h
Roro:
Constant velocity, v = 2m/s
Roro rest for 2 seconds
Travel time = h - 2
Recall:
Distance = speed * time
Distance covered by Jojo:
3 * h = 3h
At this distance ;
Roro's distance = 3h - 10
Using formula :
Roro's distance = 2 * (h - 2)
Hence,
2(h - 2) = 3h - 10
2h - 4 = 3h - 10
2h - 3h = - 10 + 4
-h = - 6
h = 6
Hence, Roro moved for :
h - 2 = 6 - 2 = 4seconds
Distance moved by Roro:
2(h - 2) = 2(6 - 2) = 2(4) = 8 meters
Answer this and you get 100 points
You better answer it quick though
Answer what? Apologies, but I don't see anything. (。>︿<)
which particles do not affect the stability of the atom
Electrons are the particle pr4esent inside the atom that does not affect the stability of the atom,
What is radioactivity?The ability of some unstable atoms to emit nuclear radiation spontaneously, typically in the form of alpha or beta particles frequently accompanied by gamma rays, is known as radioactivity.
An overabundance of neutrons or protons can make the nucleus of an atom unstable.
A radioactivity atom will try to become stable by extruding other particles, such as protons or neutrons, or by releasing energy in various ways.
Thus, Electrons are the particle present inside the atom that does not affect the stability of the atom,
To learn more about radioactivity here, refer to the link;
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There is a very long straw of charge that is uniformly charged in electro static equilibrium. It has a charge per unit length of 4.0E-9 C/m (4.0 nC/m) and a radius of 0.5 m. What is the strength of the electric field a distance of 10.0 m from its center outside the straw
Answer:
2880 N/c
Explanation:
Given that:
Charge per unit length ; λ = 4 * 10^-9
radius, r = 10
Radius, R = 0.5m
Using the relation :
2λr / 4πE0R²
Columb's constant, k = 1/4πE0 =. 9* 10^9Nm²/C²
Hence, we have :
2λrk/ R²
(2 * 4 * 10^-9 * 10 * 9 * 10^9) / 0.5^2
(720 ÷ 0.25)
= 2880 N/c
What does Fgrav or Fg mean when its next to a vector arrow?
Renee looks out a window. The window is clear, or transparent. This means most of the light that hits the window is:
А
scattered
B
reflected
с
transmitted
D
absorbed
Answer:
the answer is transmitted
Explanation:
Please answer the question
Answer:
Option B. 300 m/s².
Explanation:
From the question given above, the following data were obtained:
Mass (m) of student = 100 Kg
Mass (m) of ball = 1.5 Kg
Force (F) applied on the ball = 450 N
Acceleration (a) of ball =?
From Newton's 2nd law,
F = ma
Where
F => Force applied
m => mass of object
a => acceleration of object.
With the above formula, we can obtain the acceleration of the ball as follow:
Mass (m) of ball = 1.5 Kg
Force (F) applied on the ball = 450 N
Acceleration (a) of ball =?
F = ma
450 = 1.5 × a
Divide both side by 1.5
a = 450 / 1.5
a = 300 m/s²
Therefore, the acceleration of the ball is 300 m/s²
On a level test track, a car with antilock brakes and 90% braking efficiency is determined to have a theoretical stopping distance (ignoring aerodynamic resistance) of 408 ft (after the brakes are applied) from 100 mi/h. The car is rear-wheel drive with a 110-inch wheelbase, weighs 3200 lb, and has a 50/50 weight distribution (front and back), a center of gravity that is 22 inches above the road surface, an engine that generates 300 ft-lb of torque, and overall gear reduction of 8.5 to 1 (in first gear), a wheel radius of 15 inches and a driveline efficiency of 95%. What is the maximum acceleration from the rest of this car on this test track
Answer:
a = 30.832 ft/s²
Explanation:
To solve this problem let's start by finding the braking acceleration using kinematics, where the distance is x = 408 ft, the initial velocity vo = 100 mi / h and the final velocity is zero v = 0
v² = v₀² - 2 a x
0 = v₀² - 2ax
a = [tex]\frac{v_o^2}{2x}[/tex]
Let's start by reducing the magnitudes to ft / s
v₀ = 100 mi / h (5280 foot / 1 mile) (1h / 3600 s) = 146.666 ft / s
let's calculate
a = [tex]\frac{146.66^2}{2 \ 408}[/tex]
a = 26.36 ft / s²
Let's call this acceleration a_effective, this acceleration is in the opposite direction to the speed of the vehicle.
Let's use a rule of three (direct proportions) to find the acceleration applied by the brake system (a1) which has an efficiency of 95%. or 0.95
a₁ = [tex]\frac{a_e}{0.95}[/tex]
Let's use another direct proportion rule If the acceleration of the brake system (a₁) for an applied acceleration (a) with an efficiency of 0.90
a = [tex]\frac{a_1}{0.90}[/tex]
we substitute
a = [tex]\frac{a_e}{0.95 \ 0.90}[/tex]
let's calculate
a = [tex]\frac{26.36}{ 0.95 \ 0.90}[/tex]
a = 30.832 ft/s²
This is the maximum relationship that the vehicle can have for when it brakes to stop at the given distance
A major source of water pollution comes from that washes chemicals and other pollutants from improperty managed land.
A car has a mass of 2000 kg and accelerates at 2 meters per second per second. What is the magnitude of the net force exerted on the car?
Hello!
[tex]\large\boxed{4000 N}[/tex]
Use the following equation to solve for the net force (N):
∑F = m × a
Plug in the given mass (kg) and speed (m)
∑F = 2000 * 2
Simplify:
∑F = 4000 N
what is the mathematical definition of momentum? what is a more conceptual or descriptive definition of momentum?
Answer:
Momentum can be defined as "mass in motion." All objects have mass; so if an object is moving, then it has momentum - it has its mass in motion. The amount of momentum that an object has is dependent upon two variables: how much stuff is moving and how fast the stuff is moving.
Explanation:
How much force does it take to give a 70 kg object an acceleration of 20 mls2
Answer:
heyy
Explanation:how r uuu
What composes about 71% of Earth's outermost layer?
A
oceanic crust
B
asthenosphere
С
lithosphere
D
continental crust
Answer:
A. oceanic crust
Explanation:
I remember that the ocean is said to cover 71% of the Earth's surface. If you look at a globe, notice that most all the surface is blue like the ocean.
One other note: the surface is the Earth's outermost layer. Think of it this way: surface implies the top of something, something exposed to the outside.
Therefore, the answer is A. Hope this helps you understand the question more! Have a great day, 'kay?
formula for percentage error
Answer:
PE = (|accepted value – experimental value| \ accepted value) x 100%
Explanation:
As an electromagnetic wave travels, what is the relationship between the
magnetic field and the electric field along its path?
A. They are parallel to each other.
B. The angle between them decreases with an increase in energy
O C. The angle between them increases with an increase in energy.
D. They are at a 90° angle to each other.
Answer:
Its D
Explanation:
They are at a 90° angle to each other.
Do good on your tests :]
The answer is D) They are at a 90° angle to each other.
What is an electromagnetic wave?One of the waves which are propagated with the aid of simultaneous periodic versions of electrical and magnetic subject depth and consists of radio waves, infrared, seen mild, ultraviolet, X-rays, and gamma rays.
Radio waves, microwaves, seen light, and x-rays are all examples of electromagnetic waves that range very differently in wavelength. (a) Longer wavelength; (b) shorter wavelength. Electromagnetic waves are produced by means of the motion of electrically charged debris.
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Review Conceptual Example 6 as background for this problem. A car is traveling to the left, which is the negative direction. The direction of travel remains the same throughout this problem. The car's initial speed is 17.8 m/s, and during a 4.68-second interval, it changes to a final speed of (a)23.5 m/s and (b)15.3 m/s. In each case, find the acceleration (magnitude and algebraic sign).
Answer:
(a) 1.21 m/s² (b) 1.75 m/s²
Explanation:
The initial speed of the car, u = 17.8 m/s
Case 1.
Final speed of the car, v = 23.5 m/s
Time, t = 4.68-s
Acceleration = rate of change of velocity
[tex]a=\dfrac{23.5 -17.8 }{4.68}\\\\a=1.21\ m/s^2[/tex]
Case 2.
Final speed of the car, v = 15.3 m/s
[tex]a=\dfrac{23.5 -15.3}{4.68}\\\\a=1.75\ m/s^2[/tex]
Hence, this is the required solution.
Acceleration is the change in the velocity of a body with time.
What is acceleration?The term acceleration is the change in the velocity of a body with time. We have to find the acceleration in two separate cases;
Case 1;
a = -(23.5 m/s - 17.8 m/s)/4.68-s
a = -1.2 m/s^2
Case 2;
a = -(15.3 m/s - 17.8 m/s)/4.68-s
a = 0.53 ms-2
Learn more about acceleration: https://brainly.com/question/12134554