Answer:
Steel
Explanation:
Sound waves travel over 17 times faster through steel than through air.
Answer:
Steel
Explanation:
This is because solid objects molecules are more packed together, therefore it travels faster, in which time oxygen by 17 times faster
A solid sphere of radius 40.0cm has a total positive charge of 26.0μC uniformly distributed throughout its volume. Calculate the magnitude of the electric field(c) 40.0cm
The magnitude of the electric field for 40 cm is 1.46 × 10^6 N/C
We choose a Gaussian sphere of radius r = R. Apply Gauss’s law from Equation (1):
[tex]\Phi_{\text{E}}=\oint \overrightarrow{\mathbf{E}}\cdot d\overrightarrow{\mathbf{A}}=\dfrac{q_{\text{in}}}{\epsilon_0}[/tex]
[tex]\oint EdA=\dfrac{q_{\text{in}}}{\epsilon_0}[/tex]
[tex]E\oint dA=\dfrac{q_{\text{in}}}{\epsilon_0}[/tex]
[tex]EA=\dfrac{q_{\text{in}}}{\epsilon_0}[/tex]
Where A is the area of the solid sphere found from Equation (2) and [tex]q_{\text{in}}[/tex] is the charge enclosed by the Gaussian surface which is the total charge of the sphere found from Equation (3):
[tex]E(4\pi r^2)=\dfrac{\rho V}{\epsilon_0}[/tex]
[tex]E(4\pi r^2)=\dfrac{(Q/\bcancel{V})\bcancel{V}}{\epsilon_0}[/tex]
Solve for E:
[tex]E=\dfrac{Q}{4\pi\epsilon_0 r^2}\tag{6}[/tex]
Substitute numerical values:
[tex]E&=\dfrac{26\times 10^{-6}}{4\pi (8.8542\times 10^{-12})(0.4)^2}\\ &={1.46\times 10^{6}\;\mathrm{N/C}\;\text{directed radially outward}}}[/tex]
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consider two stars, star a and star b. star a has a temperature of 4900 k , and star b has a temperature of 9900 k . how many times larger is the energy flux from star b compared to the energy flux from star a?
The Energy flux from Star B is 16 times of the energy flux from Star A.
We have Two stars - A and B with 4900 k and 9900 k surface temperatures.
We have to determine how many times larger is the energy flux from Star B compared to the energy flux from Star A.
State Stephen's Law?Stephens law states that if E is the energy radiated away from the star in the form of electromagnetic radiation, T is the surface temperature of the star, and σ is a constant known as the Stephan-Boltzmann constant then-
[tex]$\frac{Energy}{Area} = \sigma\times T^{4}[/tex]
Now -
Energy emitted per unit surface area of Star is called Energy flux. Let us denote it by E. Then -
[tex]$E= \sigma\times T^{4}[/tex]
Now -
For Star A →
[tex]T_{A}[/tex] = 4900 K
For Star B →
[tex]T_{B}[/tex] = 9900 K
Therefore -
[tex]$\frac{T_{B} }{T_{A} } =\frac{9900}{4900}[/tex]
[tex]\frac{T_{B} }{T_{A} }=[/tex] 2.02 = 2 (Approx.)
Now -
Assume that the energy flux of Star A is E(A) and that of Star B is E(B). Then -
[tex]$\frac{E(B)}{E(A)} = \frac{\sigma\times T(B)^{4} }{\sigma \times T(A)^{2} }[/tex]
E(B) = E(A) x [tex](\frac{T(B)}{T(A)} )^{4}[/tex]
E(B) = E(A) x [tex]2^{4}[/tex]
E(B) = 16 E(A)
Hence, the Energy flux from Star B is 16 times of the energy flux from Star A.
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Answer each question yes or no. (a) Is it possible for each of three stationary charged particles to exert a force of attraction on the other two? (b) Is it possible for each of three stationary charged particles to repel both of the other particles? (c) Is it possible for each of three current-carrying metal wires to attract the other two wires? (d) Is it possible for each of three current-carrying metal wires to repel the other two wires? André-Marie Ampère's experiments on electromagnetism are models of logical precision and included observation of the phenomena referred to in this question.
(a) No, it is not possible if one attract other two then it means rest of two have some sign of charge which repel to each other.
(b)Yes, similarly & it is not possible
(c) Yes, Two current carrying having same direction current, it
attract, If one attract others two it means all have same direction. Hence it is true
(d) (Not possible) Because of one repel other two it means other two have same direction which attract to each other.
What is the force of attraction called?Gravity is an invisible force that pulls things toward Earth. Actually, there are other places with gravity than our planet. Every thing in the universe possesses gravity, including you and the stars, planets, and moons. All objects are attracted to one another by gravity.
Every thing on Earth experiences weight, or a gravitational pull produced by the mass of the planet that is proportional to the object's mass. A measure of the force of gravity is the acceleration that freely falling objects experience.
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A series of pulses, each of amplitude 0.1m, is sent down a string that is attached to a post at one end. The pulses are reflected at the post and travel back along the string without loss of amplitude.(i) What is the net displacement at a point on the string where two pulses are crossing? Assume the string is rigidly attached to the post.(a) 0.4 m(b) 0.3 m(c) 0.2 m(d) 0.1 m(e) 0
(e) The net displacement at a point on the string is zero.
The term "displacement" refers to a shift in an object's position. It has a magnitude and a direction, making it a vector quantity. An arrow pointing from the starting point to the finishing point serves as its symbol.
A string that is connected to a post at one end is used to transmit a sequence of pulses, each measuring 0.1 meters in amplitude.
At the post, the pulses are reflected and return along the string without losing any of their amplitude.
Now, let's say the post is firmly fastened to the string.
The pulse will then be inverted upon reflection if one of the endpoints is fixed. As a result, when they collide, they cancel one another, leaving the amplitude at zero. As a result, the displacement at a string position where two pulses intersect is zero.
The correct option is (e).
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reid runs away from jarharri after an intense political debate. his initial acceleration is 0km/h and his final acceleration is 25km/hour in 10 seconds. what is reid's average acceleration? pls explain the answer. 100 POINTS!!h
Reid runs away from Jarharri after an intense political debate. The average acceleration of Reid will be 0.69 m/s².
What is Acceleration?Acceleration is like the angry, fire-breathing dragon of motion variables in comparison to displacement and velocity. It can be dangerous, some people find it frightening, and if it's large, it makes you pay attention. You can feel yourself accelerating in scenarios like sitting in a plane during takeoff, slamming on the brakes in a car, or speeding around a corner in a go-kart.
Acceleration is of various types :
Uniform AccelerationNon-Uniform AccelerationAverage Acceleration.According to the question, the given values are :
Initial velocity, u = 0 km/hr,
Final Velocity, v = 25 km/hr
v = 25 × (5/18) = 6.9 m/s and,
Time, t = 10 seconds
Now, use the Equation of motion :
v = u+at
6.9 m/s = 0 + a (10 sec)
a = 6.9/10
a = 0.69 m/s²
Hence, the acceleration that we get here is 0.69 m/s².
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compare and contrast the excited state and the ground state of electrons. please use proper grammar and mechanics.
The primary distinction between a system's ground state and excited state is that a system's ground state is any state in which its electrons are at their lowest potential energy levels, whereas an excited state is any state in which they are at an energy higher than the system's ground state.
What do you mean by the excited state and the ground state of the electron?
Any quantum state of a system that has higher energy than the ground state is considered to be in an excited state in quantum mechanics. An increase in energy level over a predetermined starting point, typically the ground state, but occasionally an already excited state, is referred to as excitation.
A ground-state atom is one in which moving one or more electrons to different orbitals will not reduce the overall energy of the electrons in the atom. In other words, all of the electrons in a ground-state atom are at their lowest conceivable energy levels.
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A proton moves at 0.950 c . Calculate its (b) total energy,
The total energy of the proton is 2882.31 MeV.
We need to know about relativistic energy to solve this problem. The rest energy of the object can be determined by
Eo = m₀ . c²
where Eo is rest energy, m₀ is rest mass and c is speed of light (3 x 10⁸ m/s).
The total energy of object can be described as
E = Eo / √(1 - v²/c²)
where E is total energy, v is the object speed.
From the question above, we know that :
m₀ = 1.6 x 10¯²⁷ kg
c = 3 x 10⁸ m/s
v = 0.95c
Find the rest energy
Eo = m₀ . c²
Eo = 1.6 x 10¯²⁷ . (3 x 10⁸)²
Eo = 1.44 x 10¯¹⁰ joule
Eo = 1.44 x 10¯¹⁰ / (1.6 x 10¯¹⁹) eV
Eo = 900 x 10⁶ eV
Eo = 900 MeV
Determine the total energy
E = Eo / √(1 - v²/c²)
E = 900 / √(1 - (0.95c)²/c²)
E = 900 / 0.31
E = 2882.31 MeV
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A ship at sea is due into a port 307 km due south in two days. However, a severe storm comes in and blows it 178 km due east from its original position. How far is the ship from its destination
The ship is 354.87 km far away from its destination.
What is Pythagoras' theorem?Pythagoras' Theorem states that the square of the hypotenuse side in a right-angled triangle is equal to the sum of the squares of the other two sides.
This triangle's three sides are known as the Perpendicular, Base, and Hypotenuse. Due to its position opposite the 90° angle, the hypotenuse, in this case, is the longest side. When the positive integer sides of a right triangle (let's say sides a, b, and c) are squared, the result is an equation known as a Pythagorean triple.
H²=P²+B² where,
H= Hypotenuse of the triangle
P= Perpendicular of the triangle and,
B= Base of the triangle
According to the question,
The ship is 307 km due south and 178 km east due to the storm.
So, H²=P²+B²
⇒H²=(307)²+(178)²
⇒H=√125933
H=354.87 km.
Hence, the ship is 354.87 km far away from its original position.
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How long would it take the Concorde to travel the 6265 km between New York City and London England, assuming that the jet travels at its maximum speed of 2,150 km/h during the entire trip?
Answer:
2.9 Hrs
Explanation:
Time = Distance/velocity
6265 / 2150 ≈ 2.9 hrs
What is the slope of the line plotted below?
Consider (a) an electron (b) a photon, and (c) a proton, all moving in vacuum. Choose all correct answers for each question. (iv) Which carry momentum?
Electron, photon and proton carry momentum .
De Broglie derived the relationship between the wavelength and momentum of matter. This relationship is known as de Broglie's relationship.De Broglie's relationship is given by [tex]\lambda=\frac{h}{mv}[/tex] ...(1)Momentum is the product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction.Equation (1) can be written as [tex]\lambda=\frac{h}{p}[/tex] where λ is known as de Broglie wavelength and p is momentum , h = Plank’s constant
For photon , the momentum is given by [tex]p=\frac{E}{c}[/tex] ...(2) where c is the speed is the speed of light .
From equation (1) and (2) we can conclude that electron, photon and proton carry momentum .
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the outer gaseous giants are characterized by abundant (a. while the inner terrestrial planets are characterized by abundant (b. .
The outer gaseous giants are characterized by abundant gases like hydrogen, helium, methane, etc while the inner terrestrial planets are characterized by abundant solid elements like iron, nickel, silicon, etc.
Our solar system consists of the Sun and eight planets orbiting around it that are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune.
Out of the eight, the four planets closest to the sun i.e Mercury, Venus, Earth, and Mars are terrestrial, which means that their surfaces are rock solid and are composed of elements like iron, nickel, aluminum, silicon, etc.
They also have no moons or a few moons.
On the other hand, the remaining four planets i.e Jupiter, Saturn, Uranus, and Neptune are composed mainly of gases like hydrogen, helium, and methane. They are devoid of solid surfaces.
Also, they all have a large number of moons orbiting them.
Therefore, the outer gaseous giants are characterized by abundant gases like hydrogen, helium, methane, etc while the inner terrestrial planets are characterized by abundant solid elements like iron, nickel, silicon, etc.
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The rest energy of an electron is 0.511MeV. The rest energy of a proton is 938MeV. Assume both particles have kinetic energies of 2.00MeV. Find the speed of(c) By what factor does the speed of the electron exceed that of the proton?
The speed of electron exceeds that of the proton by 0.917c given that the rest energy of an electron is 0.511MeV and the rest energy of a proton is 938MeV, with both particles having kinetic energies of 2.00MeV.
From,
v=√1-1/γ^2 ×c (1)
Where γ=4.91 for electrons and γ=1.002 for protons
The speed of proton is 0.063c and the speed of the electron is 0.98c
∆V is the change in velocity or speed
V_e is the velocity of the electron
V_p is the velocity of the proton
Change in velocity between the electron and proton ∆V=V_e-V_p
∆V=0.98c-0.063c
∆V=0.917c
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A long solenoid that has 1000 turns uniformly distributed over a length of 0.400 m produces a magnetic field of magnitude 1.00 ×10⁻⁴T at its center. What current is required in the windings for that to occur?
0.03185A current is required in the windings for that to occur.
Solenoids are essentially coils of cord. These generate a magnetic subject which strives a pressure over a steel element.A solenoid is a fundamental time period for a coil of cord that we use as an electromagnet. We additionally consult with the tool which could convert electric power into mechanical power as a solenoid.Actually it generates a magnetic subject for developing linear movement from the electrical cutting-edge. With using a magnetic subject.Magnetic field at the centre of a solenoid of length 'L' having 'N' number of turns with a current 'I' is given by [tex]B=\frac{u_0NI}{L}[/tex] ...(1)It is given that 1000 turns uniformly distributed over a length of 0.400 m produces a magnetic field of magnitude 1.00 ×10⁻⁴T .
Putting above values in equation (1) , we get
[tex]1.00\times10^{-4}=\frac{4\pi \times10^{-7}\times1000I}{0.400} \\\\I=\frac{1.00\times10^{-4} \times0.400}{4\pi \times1000} \\\\I=0.03185A[/tex]
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I give the crown I offer 20 points please I really need it tonight now!!!!
Answer:
It's all in the Explanation.
Explanation:
You round the number of the IP address and boom. You have your answer.
Question 1 (1 point)
Joe walks 57m north followed by 70m west. What is his magnitude of displacement
from the start?
Answer: All that seems to be needed to be done, is for you to subtract 57m from 70m and that equals: 13m displacement! hope this is helpful! good luck!
A boat moves with a velocity of 15 m/s N in a river which flows with a velocity of 8 m/s W. Calculate the boats resultant velocity with respect to due North.
The resultant velocity of the boat with respect to the North is 17 m/s North-West.
What is resultant velocity?Resultant velocity is the single velocity obtained when two or more velocities are are combined.
To calculate the resultant velocity of the boat, we use the formula below.
Formula:
R² = P²+Q²............... Equation 1From the question,
Given:
P = 15 m/s NQ = 8 m/s WWhere R is the resultant velocity of the boat.Substitute these values into equation 1
R² = 15²+8²R² = 289R = √(289)R = 17 m/s North-West.Hence, the resultant velocity of the boat with respect to the North is 17 m/s North-West.
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I don’t understand this problem. Please help!
Based in the frame rate and the distance travelled by the ball, the speed of the ball is 398.6 cm/s.
What is the speed of an object?
The speed of an object or a moving body is the ratio of the distance covered by the moving body or object and the time taken to cover that distance.
Mathematically:
Speed = distance covered/time takenThe speed of the ball in the diagram is determined as follows:
Total distance covered by the ball will the product of the distance between the points and the number of point covered by the ball after the original point.
Distance between points = 19 cm
number of points = 6
Total distance covered by the ball = 6 *19 cm
Total distance covered by the ball = 114 cm
Time taken = 1/frame rate * number of points
Time taken = 1/22 * 6
Time taken = 0.286 s
Speed = 114 cm/0.286 s
Speed = 398.6 cm/s
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A foam dart is fired a height of 1.69 m. How many seconds does it take to hit the ground
Answer:
.587 s
Explanation:
d = 1/2 a t^2
1.69 m = 1/2 ( 9.81 m/s^2) (t^2)
t = .587 s
what are the components of the displacement vector from camp to summit? choose the x axis east, y axis north, and z axis up.
Consider east-west direction along x-axis and north-south direction along y-axis, x = x- component of the displacement vector = - 4580 Sin32.4 = - 2454.1 m
y = y- component of the displacement vector = 4580 Cos32.4 = 3867.02 m
z = z-component of the displacement vector = 2450 m
magnitude of displacement vector is given as
magnitude = sqrt(x² + y² + z²) = sqrt((- 2454.1)² + (3867.02)² + (2450)²) = 5194.13 m
Work is the result of displacement and a part of force acting in the displacement direction. 2. The result of force and displacement is work. 3. Work is a result of force and a part of displacement that moves in the force's direction.
When examining a force's geometric representation or its algebraic equivalent, the components of a force can be viewed as horizontal and vertical changes. The vertical and horizontal forces that combine to create the resulting force are represented by a force's components.
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A SQUARE induction coil with a side length 3 cm and 400 windings, is placed perpendicularly in a uniform magnetic field and then rotated through an angle of 45⁰ in 0,08 s. C E S An emf of 7 V is induced in the coil. 3.1 Calculate the change in the magnetic flux. 3.2 Calculate the magnitude of the magnetic field.
The result will be E1=E2>E4>E3
When the plane of the armature of an a.c. dynamo is parallel to the lines of force of the magnetic field, the amplitude of the induced e.m.f. is at its greatest. Additionally, the rate of change of the magnetic flux associated with the armature is at its greatest. As a result, in this orientation, the e.m.f. induced in the armature is greatest.
The EMF's amplitude is equal to Nr2B. N is the number of turns, and r is the square's half-side.
In example 3, the axis is perpendicular to the magnetic field, hence the flux is zero and the amplitude is zero as a result.
Case 4 has an axis that falls between types 1, 2, and 3.
Here, we must consider the angular velocity's x and y components.
Component in the x direction will be zero.
Additionally, the new angular velocity will be 2w because it is exactly halfway between x and y.
So now put these numbers in actual formula. The result will be E1=E2>E4>E3
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3. How does the shape of a sail affect the distance a boat will travel?
Independent Variable:
Dependent Variable:
Answer:
IV: Sail shape
DV: Travel distance
Explanation:
The independent variable is the variable we are changing to see its effects. If we are seeing how the shape of a sail affects travelling distance, the independent variable will be the shape of the sail. This could be achieved by using different dimensions or different geometric shapes.
The dependent variable is the one we are measuring in response to the independent variable. In this case it will be the distance that the boat travels. This could be measured using a ruler or distance meter.
Hope this helped!
A plane travels 2.5km at an angle of 35 degrees to the ground and then changes direction and travels 5.2km at an angle of 22 degrees to the ground. What is the magnitude and direction of the plane's total displacement?
The magnitude and direction of the plane's total displacement will be 7.66 km, 26.20° to the ground.
What is displacement?It should be noted that displacement is a vector quantity which explains the change in the distance to the overall change in position of the object.
The sine and cosine function can be used to solve for the resultant x and y components.
Resultant x = 2.5 cos 35 + 5.2 cos 22
= 6.87 km
Resultant y = 2.5 sin 35 + 5.2 sin 22
= 3.38 km
The resultant displacement is calculated using hypotenuse equation:
displacement = ✓(6.87² + 3.38²)
displacement = 7.66 km
The resultant angle will be:
θ = tan^-1 (3.38 / 6.87)
θ = 26.20°
Therefore the magnitude and direction will be 7.66 km, 26.20° to the ground.
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Q|C The speed of a one-dimensional compressional wave traveling along a thin copper rod is 3.56 km/s . The rod is given a sharp hammer blow at one end. A listener at the far end of the rod hears the sound twice, transmitted through the metal and through air, with a time interval Δt between the two pulses.(b) Find the length of the rod as a function of Δt.
The length of the rod as a function is 379.57 Δt
(b) The speed of a wave in metal=3560 m/s
Let L be the length of the rod.
[tex]-\frac{l}{3560}+\frac{l}{343}=\Delta t \\&l=\Delta t\left(\frac{1}{-\frac{1}{3560}+\frac{1}{343}}\right)[/tex]
[tex]\\&l=379.571 \Delta t \\&\text[/tex]
As a result, the rod's length as a function is 379.57 Δt.
Where does the wave travel?A wave in which the medium's particles travel gradually in the direction of the wave's propagation with a gradation of speeds such that the faster particles overcome the slower and are then overtaken themselves, similar to a standing wave.A wave is the result of an object moving through a medium, such as water or air. When an object moves, it creates waves in the surrounding area that are similar to the shape and size of the original object. This phenomenon can be observed quite easily when you put two smooth rocks next to each other and watch how their respective waves crash against each other.To learn more about wave, visit:
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A string of length L , mass per unit length μ , and tension T is vibrating at its fundamental frequency. (i) If the length of the string is doubled, with all other factors held constant, what is the effect on the fundamental frequency?(a) It becomes two times larger.(b) It becomes √2 times larger. (c) It is unchanged.(d) It becomes 1 /√2 times as large. (e) It becomes one-half as large.
Fundamental frequency will be [tex]\frac{1}{{2} }[/tex] times that of original frequency on doubling the length of the string which is option (e) .
Fundamental frequency, also called simply fundamental wave, is defined as the lowest frequency of a periodic waveform. In music, the root is the pitch of the note that is perceived as the lowest partial present.A wave traveling on the string is reflected at the other end. Standing waves are created as a result of interference between incident and reflected waves propagating in opposite directions. The fundamental frequency of the standing wave of a taut string is given by [tex]f=\frac{1}{2l} \sqrt{\frac{T}{u} }[/tex] ....(1) where T is the tension in the string, u is the mass per unit length of the string , l is the length of the string.From equation (1) it can be seen clearly that fundamental frequency in inversely proportional to the length of the string.
On putting double the length of the string in equation (1) keeping the all factor same , we get
[tex]f'=\frac{1}{2\times2l} \sqrt{\frac{T}{u} }\\\\f'=\frac{1}2 } f[/tex]
Where f ' is the new frequency and f is the original frequency .
Thus, If the length of the string is doubled, with all other factors held constant, then the fundamental frequency will reduce to half.
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there are two types of waves: electromagnetic and mechanical. can either type travel regardless of the presence of a medium?
Yes, electromagnetic can travel without medium.
Mechanical waves and electromagnetic waves are two important ways that energy is transported in the world around us.
Waves in water and sound waves in air are two examples of mechanical waves.
Mechanical waves are caused by a disturbance or vibration in matter, whether solid, gas, liquid, or plasma.
Matter that waves are traveling through is called a medium.
These mechanical waves travel through a medium by causing the molecules to bump into each other, like falling dominoes transferring energy from one to the next.
Sound waves cannot travel in the vacuum of space because there is no medium to transmit these mechanical waves.
On the other hand electromagnetic waves don't require medium for its propagation.
An easy example would be light which is an EM wave reaches earth even though space has no medium.
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The most soaring vocal melody is in Johann Sebastian Bach's Mass in B Minor. In one section, the basses, tenors, altos, and sopranos carry the melody from a low D to a high
A. In concert pitch, these notes are now assigned frequencies of 146.8Hz and 880.0 Hz . Find the wavelengths of(b) the final note. Assume the cho-rus sings the melody with a uniform sound level of 75.0 dB .
The wavelength of the final note is 0.389m
What do you mean by the term wavelength?The distance between two successive crests or troughs of a wave is known as its wavelength. It is measured in the wave's direction. The distance a wave travels between its crests or troughs is known as its wavelength (which may be an electromagnetic wave, a sound wave, or any other wave). The wave's crest is its highest point, while its dip is its lowest. Because a wavelength represents a distance or length, it is expressed in length units like meters, centimeters, millimeters, nanometers, etc. Light's wavelength changes with color, or it differs for each hue. While violet has the shortest wavelength, red has the longest.
wavelength = v/f
wavelength = 343/800 m = 0.389m
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GP A series RLC circuit contains the following components: R=150Ω, L=0.250H, C=2.00µF, and a source with Δ Vmax=210V operating at 50.0Hz. Our goal is to find the phase angle, the power factor, and the power input for this circuit. (a) Find the inductive reactance in the circuit.
A ball is projected 125 meters straight upward and then falls the same distance back to its starting point. Neglecting air resistance, its total time in the air is about.
The ball that is projected 125 meters straight upward has a total time in the air of: 10.1 s
The formulas for the vertical launch upward and the procedures we will use are:
y max = v₀²/(2*g)t max = v₀/ gt(of)=2*t maxWhere:
v₀ = initial velocityg = gravityy max = maximum heightt max = time to reach maximum heightt(of) = time of flightInformation about the problem:
g = 9.8 m/s²y max= 125 mv₀ = ?t max =?t(of) =?Applying the maximum height formula and clearing the initial velocity we get:
y max = v₀²/(2*g)
v₀ = √(y max * (2*g))
v₀ = √( 125 m * (2 * 9.8 m/s²))
v₀ = √( 125 m * 19.6 m/s²)
v₀ = √2450 m²/s²
v₀ = 49.497 m/s
Applying the maximum time formula we get:
t max= v₀ / g
t max= 49.497 m/s / 9.8 m/s²
t max = 5.050 s
Applying the time of flight formula, we get:
t(of) =2 * t max
t(of) =2 * 5.050 s
t(of) = 10.1 s
What is vertical launch upwards?In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.
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The time spent in the air by the ball is 10.01 seconds.
What is the total time in the air by the ball?The total time spent in the air by the ball is the sum of the time it spends moving up and the time it spends falling down.
The time spent by the ball moving up - time spent by the ball travelling down.
Time spent by the ball traveling down a distance of 125 meters is calculated using the formula given as follows:
t = √2h/g
Total time spent = 2 * √2h/g
where:
h = 125 m
g = 9.81 m/s²
T = 2 * √(2 * 125/9.81)
T = 10.01 s
Therefore, the time spent in the air by the ball is the sum of the time spent moving up and the time it spends falling down which are both equal.
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Fill in the blanks to complete the statements.
If an object changes speed or
, its velocity also changes. Any change in ______ results in acceleration.
Answer: velocity
Explanation: Acceleration = change in velocity / time interval
5m/s to 25 m/s, in 2 seconds. So 25m/s - 5 m/s, then divide by time =
10m/s squared