Domain and range graph helppppppp plssssss

Domain And Range Graph Helppppppp Plssssss

Answers

Answer 1

For graph number 13:

We can see that the domain is: {-3, 3} the range is: R: {-4, 2} this is not a function

How to find the domain and range with a graph?

For a relation that maps elements x into elements y, we define the domain as the set of the inputs and the range as the set of the outputs. And we say that the relation is a function if each input is mapped into, at most, one output.

If you look at the graph 13 you can see several points, which are of the form (x, y) and are:(-3, 2), (3, 2), (-3, -4), (4, -4)And it makes a little square.

Then you can see that the inputs are -3 and 3, so the domain is:

{-3, 3}

And the outputs are 2 and -4, then the range is:

R: {-4, 2}

And this is not a function, because for example, output 3 is being mapped into two different values.

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Related Questions

what is 209.3 ÷ 80 without a remainder

Answers

Answer:

2.61625

Step-by-step explanation:

209.3 divided by 80


Write each equation in logarithmic form. 10⁻³=0.001

Answers

-3 is equation in logarithmic form.

What is the purpose of logarithm?

A logarithm is a mathematical formula that calculates how many times the base, or initial number, must be multiplied by itself to produce the target number.

A logarithm is defined simply?

The power to which a number must be increased in order to obtain another number is known as a logarithm (see Section 3 of this Math Review for more about exponents). For instance, since ten raised to the power of two equals 100, the base ten logarithm of 100 is 2: log 100 = 2.

10⁻³=0.001

log. 001 = -3 log 10 = -3

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4. Calculate the length of each line segment.
Round answers to the nearest tenth of a
unit, when necessary.

a) AB
b) CD
c) EF

Answers

The length of AB is 4.47 units, the length of CD is 2.83 units and the length of EF is 5 units.

We are given different right angled triangles.

We need to find AB, CD and EF

We will do this by using the Pythagoras theorem.

Pythagoras theorem states that:

Hypotenuse² = Base² + Perpendicular²

For AB,

Hypotenuse = AB

Base = 2 units

Perpendicular = 4 units

So, we get that:

AB² = 2² + 4²

AB² = 4 + 16

AB² = 20

AB = √ 20

AB = 2√5 units

AB = 4.47 units.

For CD:

Hypotenuse = CD

Base = 2 units

Perpendicular = 2 units

So, we get that:

CD² = 2² + 2²

CD² = 4 + 4

CD² = 8

CD = √ 8

CD = 2√2

CD = 2.83 units

For EF:

Hypotenuse = EF

Base = 4 units

Perpendicular = 3 units

So, we get that:

EF² = 4² + 3²

EF² = 16 + 9

EF² = 25

EF = 5 units.

Therefore, we get that, the length of AB is 4.47 units, the length of CD is 2.83 units and the length of EF is 5 units.

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Write a radical function such that for its domain, the function is onto the set of real numbers such that y≤3

Answers

A radical function such that y≤3 is given by y=-√|x|+3 .

A radical function is defined as a function which has the independent variable within a radical sign.

A radical sign is also defined as the power of the variable to be a fraction.

We know that the n-th root of x is similar to x to the power of (1/n) .

The domain of the function is onto the set of real numbers which means that the domain contains all real numbers.

The range of the function is given as y≤3, that is the value of y can take a maximum value of 3.

Hence we can write a function where x ∈ R and y ≤ 3 .

Let us consider the function y=-√|x|+3

The above functions satisfies all the criteria for the question. It is a radical function and the maximum value can be 3 as -√|x| can have a max value of 0 for all  x ∈ R .

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Read and try to solve the problem below. Look at the circumference of each of the circles below. What do you think would be the circumference of a circle with diameter 1 cm? 2 cm C = 6.28 cm 3 cm C = 9.42 cm 4 cm C = 12.56 cm 2.5 cm C = 15.70 cm​

Answers

The formula for calculation of circumference of the circle = d π or 2πr where d is diameter of circle and r is the radius of circle

As given in the question the circumference of the circle whose diameter is 2 cm is 6.28cm and we come to know that value of π used here is 3.14 and not 22/7

So, the circumference of the circle whose diameter is 1cm = d π

              = 1 π

            = 1 3.14

                                                                                          = 3.14 cm

Hence the circumference of the circle whose diameter is 1cm using the value of pi as 3.14 comes out to be pi that is 3.14 cm

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Let f(x)=2 x+5 and g(x)=x²-3 x+2 . Perform each function operation, and then find the domain.
5 f(x) / g(x)

Answers

The values for  5 f(x) / g(x) = (10x+25) / x²-3 x+2

What are the domain of the function f(x)=2 x+5 and g(x)=x²-3 x+2?

Given;

f(x)=2 x+5 and g(x)=x²-3 x+2

5 f(x)= 5(2x+5 )

        = 10x+25

5 f(x) / g(x) = (10x+25) / x²-3 x+2

       

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Find the distance between the points L(7,-1) and M(-2, 4). Answer in simplest exact
Form

Answers

[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ L(\stackrel{x_1}{7}~,~\stackrel{y_1}{-1})\qquad M(\stackrel{x_2}{-2}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ LM=\sqrt{(~~-2 - 7~~)^2 + (~~4 - (-1)~~)^2} \implies LM=\sqrt{(-2 -7)^2 + (4 +1)^2} \\\\\\ LM=\sqrt{( -9 )^2 + ( 5 )^2} \implies LM=\sqrt{ 81 + 25 } \implies LM=\sqrt{ 106 }[/tex]

A pair of parallel lines is cut by a transversal.

If m∠A = (5x − 4)° and m∠B = (8x − 28)°, what is the value of x?

A) 8
B) 9.4
C) 16.3
D) 36

Answers

Answer:

A

Step-by-step explanation:

∠ A and ∠ B are alternate exterior angles and are congruent , then

∠ B = ∠ A , that is

8x - 28 = 5x - 4 ( subtract 5x from both sides )

3x - 28 = - 4 ( add 28 to both sides )

3x = 24 ( divide both sides by 3 )

x = 8

First off, angle A = angle B due to the fact that alternate exterior angles are the same. After that, we just need to solve for X, thus making the final answer 8° (option A). Feel free to clarify if you have any questions after looking at the picture!

what do i subtract with a positive number to produce a negative number?

Answers

Answer:9

Step-by-step explanation:draw a line threw the equal sign, add 36 instead of subtracting it, which then would be 9.

Answer:

down below

Step-by-step explanation:

In order for you to get a negative number, you need to put in the variables place, 9.

9 is your answer.

find many solutions to the system of inequalities:

Answers

1) Solve each inequality individually.

[tex]\dfrac{2x-3}5 - \dfrac{4x-9}6 > 1 \\\\ 6(2x-3) - 5(4x-9) > 30 \\\\ (12x-18) - (20x+45) > 30 \\\\ -8x > 3 \\\\ x < -\dfrac38[/tex]

and

[tex]5(x-1) + 7(x+2) > 3 \\\\ (5x-5) + (7x+14) > 3 \\\\ 12x > -6 \\\\ x > -\dfrac12[/tex]

Then the solution set is

[tex]-\dfrac12 < x < -\dfrac38[/tex]

since -1/2 = -4/8 is smaller than -3/8.

2)

[tex]\dfrac{x+1}2 - \dfrac{x+2}3 < \dfrac{x+12}6 \\\\ 3(x+1) - 2(x+2) < x+12 \\\\ (3x+3) - (2x+4) < x + 12 \\\\ x - 1 < x + 12 \\\\ -1 < 12[/tex]

This is true for all values of [tex]x[/tex].

For the second inequality, (I use periods in place of commas because it renders better as TeX)

[tex]0.3x - 19 \le 1.7x - 5 \\\\ -1.4x \le 14 \\\\ x \ge -10[/tex]

Taken together, the solution set is

[tex]\boxed{x\ge-10}[/tex]

3)

[tex](x-6)^2 < (x-2)^2 - 8 \\\\ x^2 - 12x + 36 < (x^2 - 4x + 4) - 8 \\\\ -8x < -40 \\\\ x > 5[/tex]

and

[tex]3(2x-1) - 8 < 34 - 3(5x-9) \\\\ (6x - 3) - 8 < 34 - (15x - 27) \\\\ 21x < 72 \\\\ x < \dfrac{72}{21} = \dfrac{24}7[/tex]

But [tex]x[/tex] cannot be both larger than 5 = 35/7 and smaller than 24/7, so there are no solutions.

4)

[tex]\dfrac{3x-2}3 - \dfrac{4x+1}4 \le 1 \\\\ 4(3x-2) - 3(4x+1) \le 12 \\\\ (12x-8) - (12x + 3) \le 12 \\\\ -11 \le 12[/tex]

This is true for all [tex]x[/tex].

[tex](x-1)(x-2) > (x+4)(x-7) \\\\ x^2 - 3x + 2 > x^2 - 3x - 28 \\\\ 2 > -28[/tex]

This is also true for all [tex]x[/tex].

Any value of [tex]x[/tex] is a solution.

Two water tanks 50 inches tall. tank a is empty and for each minute the water increases by 3.7 inches. tank b is draining and the water decreases 1.9 inchesveach minute. how many minutes will pass so the height of the water in each tank is the same

Answers

If two water tanks are 50 inches tall and tank a is empty and for each minute the water increases by 3.7 inches and tank b is draining and the water decreases by 1.9 inches each minute, then the minutes after which the height of the water in each tank is the same is equal to 9.

The time in minutes after which the height of the water in each tank is the same can be determined by using a linear equation.

The equation for this problem can be given as,

0 + 3.7(x) = 50 - 1.9(x)

Here x is equal to minutes. To find the minutes after which the water level will be the same can be determined by calculating the value of x in this linear equation.

3.7(x) + 1.9(x) - 50 = 0

5.6(x) = 50

x = 50 / 5.6

x = 8.92 ≈ 9

Hence, the height of the water in tank a and tank b is equal after 9 minutes.

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Eduardo started a business selling sporting goods. He spent $7500 to obtain his merchandise, and it costs him $300 per week for general expenses. He earns $850 per week in sales. What is the minimum number of weeks it will take for Eduardo to make a profit?


Which inequality models this problem?




300w>7500+850w




850w≥7500+300w




850w<7500+300w



850w>7500+300w

Answers

The minimum number of weeks it will take for Eduardo to make a profit

850w > 7500 + 300w. Option D

This is further explained below.

What is the minimum number of weeks it will take for Eduardo to make a profit?

Generally, the Total cost  is  mathematically given as

X= $7500+$300w

Where he is earning each week

=$850

Therefore,

He will be paid in n weeks=$850n

The information that has been presented states that the very bare minimum number of weeks that it will take for Eduardo to earn a profit is by.

Total revenue is more than total expenditures

850w > 7500 + 300w

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Nicole and Daniel are splitting a pizza. Nicole eats 1/4 of the pizza and Daniel eats 2/3 of it. How much pizza is left? Write an equation to represent this situation.

Answers

Answer:

1 - 1/4 - 2/3 = r

Step-by-step explanation:

N=1/4, D=2/3

whole pizza=1

r=remainder pizza

1 - 1/4 - 2/3 =r

(1 - 1/4 - 2/3 =r)*12 ==> multiply by 12 to get rid of denominators

12 - 12/4 - 12*2/3=12r

12-3-24/3=12r

9-8=12r

12r=1

r=1/12 of a pizza left

Answer:

1/12

Step-by-step explanation:

the common number of 3 and 4 is 12. You multiply 1/4 by three and you get 3/12, and you multiply 2/3 by 4 and you get 8/12. You add 8 and 3 and you get 11, that's the number that indicates the part of the eaten pizza. 12-11=1. 1/12 left from the pizza.

WILL GIVE BRAINLIST TO BEST ANSWER
Arabella sells cars at a local dealership and gets paided by commission. she has already made $750 and will continue to earn $200 per car that's she sells. If her goal is to make $2750 by the end of the month, write + solve the equation below that models this months goal.

Answers

Answer:

$2,750 = $200x + $750

10 cars to meet the goal

Step-by-step explanation:

We will pull details we need to solve out of the question:

     If her goal is to make 2,750 dollars, the money earned must equal at least $2,750.

     If she's already made $750, then we can subtract that from what is needed left to make (or add it to what needs to be made).

     Finally, she makes $200 per car. Let x equal the number of cars she sells.

Next, we will write an equation:

     $2,750 = $200x + $750

Lastly, we will solve this equation.

     $2,750 = $200x + $750

     $2,000 = $200x

     10 = x

           She needs to sell 10 cars to meet her goal.

Answer=$2,750=$200x +$750 10 cars meet the monthly goal.

Write the equation of the line that passes through (5, −2) and is perpendicular to y equals 5 thirds times x minus 3 period.

y equals negative 3 fifths times x plus 1
y equals negative 3 fifths times x plus 19 fifths
y equals 3 fifths times x minus 5
y equals 5 thirds times x minus 31 thirds

Answers

We need to use the concept of lines and slopes to solve the problem.The equation of the line that passes through (5,-2) and is perpendicular to y=[tex]\frac{5}{3} x-3[/tex] is [tex]y=\frac{-3}{5} x+\frac{19}{5}[/tex].

We will be using the concept of lines and slopes to solve the question. When two lines are parallel their slopes are equal and when two lines are perpendicular the product of their slopes equal to -1.

Here we know that the line passes through a point (5,-2) and is perpendicular to another line,we need to find out the slope of the line first.

Let slope of given line be m1 and slope of the line that we need to find out be m2.

[tex]y=\frac{5}{3} x-3[/tex]

slope is the coefficient of x, thus m1=[tex]\frac{5}{3}[/tex]

we know that m1xm2=-1

[tex]\frac{5}{3}[/tex]×m2=-1⇒m2=[tex]\frac{-3}{5}[/tex]

The formula that we need to find the equation of a line is

(y-y1)=m(x-x1)

here (x1,y1) is (5,-2) and m is m2

[tex]y-5=\frac{-3}{5} (x+2)\\y-5=-\frac{3}{5} x-\frac{6}{5} \\y=\frac{-3}{5} x+5-\frac{6}{5} \\y=\frac{-3}{5} +\frac{19}{5}[/tex]

Thus using the concept of lines and slopes we found out that the equation of line that has been asked for is [tex]y=\frac{-3}{5} x+\frac{19}{5}[/tex]

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(a) A booster rocket for a spacecraft has a mass ratio of about 15 , an exhaust velocity of 2.1 km /s , and a firing time of 30s . Can the spacecraft achieve a stable orbit 300km above Earth?

Answers

Using the mass ratio, the spacecraft's velocity was determined to be 7.7025 km/s.

Here, c = 2.7 km/s, t = 30s, R = 20

On substituting the values of 'R', 't', 'v', we get:

v = -0.0098 ( 30) + 2.7 ( ln (20))

=> v = - 0.294 + 2.7 (2.995)

=> v = 7.7025 km/s

What is a spacecraft?

A spaceship is a machine or vehicle built to travel through space. Spacecraft are a form of artificial satellite used for a wide range of tasks, such as communications, Earth observation, meteorology, navigation, space colonization, planetary exploration, and cargo and person transfer.

Following are the main distinctions between spaceships and rockets: The spacecraft is launched into space by rockets, which then crash to Earth. Rockets are never manned, whereas spacecraft can be either manned or unmanned. Additionally, spacecraft cannot match the power of rockets.

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i need help with this

Answers

Answer:

y = 3x² + 2

Step-by-step explanation:

I'm help to number on more this, thank for subject on help for today.


Find the inverse of each function. Is the inverse a function?
f(x)=x⁴

Answers

The domain of f(x) to be [0,∞).

If the domain R, f(x) is not one to one, so its inverse exists not a function.

If we restrict the domain of f(x) then we can define an inverse function.

What is meant by inverse function?

An inverse function, even comprehended as an anti function, is a function that can be reversed into another function. Simply put, if any function " f " takes x to y, then its inverse will take y to x. The inverse function is denoted by f-1 or F-1 if the function exists denoted by ' f ' or ' F '.

In order to have an inverse function, a function must be one to one.

In the case of f(x) = x⁴ we find that f(1) = f(−1) =1.

If f(x) exists not one to one on its implicit domain R.

If we restrict the domain of f(x) to [ 0, ∞) then it does contain an inverse function, then [tex]f^{-1}(y)=\sqrt[4]{y }[/tex]

Let the given function be y = f(x) = x⁴

Taking the square root of both ends, then we get

± √y = x²

Let the real values be x, then

We require the left hand side to be non-negative, so assume the non-negative square root.

Take the square root of both sides of the equation then

±[tex]\sqrt[]{\sqrt{y} }[/tex] = x

⇒ x = ± [tex]\sqrt{\sqrt{y} }[/tex] = ± [tex]\sqrt[4]{y}[/tex]

It  does not give us a unique value of x in terms of y.

So the inverse function exists not defined, then x ≥ 0,  

i.e., restrict the domain of f(x) to be [0,∞).

If the domain R, f(x) exists not one to one, so its inverse exists not a function.

The domain of f(x) then we can describe an inverse function.

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you have c pieces of candy to share among 6 friends what epression shows the nnmber of the candies each freind will get

Answers

Answer:1

Step-by-step explanation if c is for 6 its 1 p

Answer:

C/6

Step-by-step explanation:

you have c pieces to share with 6 friends.

A Blue Line train and a Yellow Line train just left the station at the same time. Blue Line trains run every 10 minutes, and Yellow Line trains run every 12 minutes. How long will it be until a Blue Line train and a Yellow Line train are at the station at the same time?

Answers

It takes 60 minutes (1 hour) for the Blue Line train and the Yellow Line train to be at the station at the same time, using their running time LCM.

How is the meeting time determined?

The time that it will take the Blue Line train and the Yellow Line train to meet again at the station is determined using the Least Common Multiple or Factor.

The LCM is the smallest positive integer that is evenly divisible by both numbers, 10 and 12.

For instance, the LCM of 10 and 12 include 60 and 120 with 60 as the least.

Data and Calculations:

The time the Blue Line runs is every 10 minutes.

The time the Yellow Line runs is every 12 minutes.

The LCM of 10 and 12 is 60 because 10 and 12 can divide 60 without a remainder.

Thus, it will take 60 minutes for the two trains to meet again at the station.

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PLEASE WORK OUT THE PROBLEMS CORRECTLY. GET IT RIGHT AND GET BRAINLIEST!!!!

Answers

Answer:

Question 1 is x = 2, y = 2, z = 2

Question 2 is x = 1, y = 1, z = -3

Question 3 is x = 13, y = -10, z = -7

Question 4 is x = 5, y = -2, z = -3 (C)

Question 5 is x = 2, y = 0, z = -2

Step-by-step explanation:

I did not have time to do this...

The larger of two numbers is one more than four times the smaller number. If the sum of the numbers is 106, find the numbers.

a
32,56
b
32,74
c
21,85
d
52,54

Answers

Answer:

c.  21, 85

Step-by-step explanation:

Define the variables:

Let the two numbers be x and y, where x > y.

Given information:

The larger of two numbers is one more than four times the smaller number.The sum of the number is 106.

Create two equations from the given information and defined variables:

[tex]\begin{cases}x = 4y + 1\\x + y = 106\end{cases}[/tex]

Substitute Equation 1 into Equation 2 and solve for y:

[tex]\implies (4y+1)+y=106[/tex]

[tex]\implies 4y+1+y=106[/tex]

[tex]\implies 5y+1=106[/tex]

[tex]\implies 5y+1-1=106-1[/tex]

[tex]\implies 5y=105[/tex]

[tex]\implies \dfrac{5y}{5}=\dfrac{105}{5}[/tex]

[tex]\implies y=21[/tex]

Substitute the found value of y into the second equation and solve for x:

[tex]\implies x+21=106[/tex]

[tex]\implies x+21-21=106-21[/tex]

[tex]\implies x=85[/tex]

Therefore, the two numbers are 21 and 85.

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What is 3/4c - 1 = 1 + 3/4c? Thanks!

Answers

Answer:

  False

Step-by-step explanation:

You want to know "what is 3/4c - 1 = 1 + 3/4c?"

Solution

Subtracting the left-side expression from both sides, we get ...

  (3/4c -1) -(3/4c -1) = (1 +3/4c) -(3/4c -1)

  0 = 2 . . . . a False statement

__

Additional comment

Since the equation is written without parentheses, we have to assume that c is in the numerator in each expression, and that its coefficient is (3/4).

Miles caught a fish that weighed 4 1/6 pounds and then caught another that weighed 6 5/8 pounds. How much more did the second fish weigh? Create an expression to represent this situation.

Answers

Answer: 2 11/24

Step-by-step explanation: First we have to subtract it, so 6 5/8 - 4 1/6 which is 2 11/24


A store is offering a 15 % discount on all items. Also, employees get a 20 % employee discount. Write composite functions

b. to model taking the 20 % discount and then the 15 % discount.

Answers

The composite functions of the model taking the 20 % discount and then the 15 % discount is (D ◦ E)(x) = 0.68x.

What is meant by function composition?

In mathematics, function composition is an operation in which two functions, f and g, generate a new function, h, in such a way that h(x) = g(f(x)). This means that function g is being applied to the function x. So, in essence, a function is applied to the output of another function.

Define fog, the composition of f and g, as (fog)(x) = f(g(x)) for functions f and g. g should be applied to x. If fog(x) = x and gof (x) = x for all x values in the domain of f and g, then they are inverse functions.

In math, the domain (the x-values) of one function becomes the range (the y-value answers) of the next function. Composition notation is as follows: (f o g)(x) = f(g(x)) and exists read “f composed with g of x” or “f of g of x”.

Let D(x) = cost after applying the 15% discount,

E(x) = cost after applying the 20% employee discount, and x = cost of item(s).

Then D(x) = 0.80x and E(x) = 0.85x.

(D ◦ E)(x) = 0.68x.

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What is an equation of the line that passes through the points (-5, -5) and
(5, -7)?

Answers

Answer: You can use Math apps to help you easily

Step-by-step explanation:


WHAT I SHOULD HAVE DONE
1 CUP MILK
4 SCOOPS
CHOCOLATE
WHAT I DID
1 CUP MILK
5 SCOOPS
CHOCOLATE
Answer the questions on each slide.
Use complete sentences. You do not have to show your work.
If it asks to explain, please provide an explanation.


How should I fix this to equal 1/4?

Answers

Answer:

just add more to the milk and another scoop of chocolate

Step-by-step explanation:

1.5 cups milk

6 scoops of chocolate


Use a table to solve each equation. Round to the nearest hundredth.
2x⁺³=512

Answers

[tex]2^{(x + 3)} = 512[/tex] => x = 6, by properties of exponentiation.

What is exponentiation?Exponentiation is a mathematical operation that involves the base number (b) and the exponent (or power) number (n), and is represented as [tex]b^n[/tex]. Its pronunciation is "b (raised) to the (power of) n."

Now,

[tex]2^{(x + 3)} = 512[/tex]

=> [tex]2^{(x + 3)} = 8^3 = (2^3)^3[/tex]

As [tex](a^b)^c = a^{bc}[/tex],

=> [tex]2^{(x + 3)} = 2 ^9[/tex]

=> x + 3 = 9

=> x = 6

Hence, [tex]2^{(x + 3)} = 512[/tex] => x = 6, by properties of exponentiation.

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I dont know how to do this please help!

Answers

Hello and Good Morning/Afternoon:

Let's take this problem step-by-step:

We want to find the value of 'x':

   [tex]\hookrightarrow \text{ thus we must first find the value of '4x'}[/tex]

         [tex]\hookrightarrow \text{EC and GH are parallel lines intersected by the same line BG}[/tex]      

              [tex]\hookrightarrow \text{angles formed by the parallel lines and a intersecting lines}[/tex]                                  [tex]\hookrightarrow \text{ are equal in measure }[/tex]

                         [tex]\hookrightarrow \text{thus angles BEC and EGH are equal in measure}[/tex]

Angle EGH is made up of two angles, ∠EGC and ∠CGH

∠EGC is 78 degrees∠CGH = ∠FGI = 14 degrees (Vertical Angle Theorem)

            ⇒ ∠EGH = ∠EGC + ∠CGH = 78 + 14 = 92 degrees

Since ∠BEC = ∠EGH

 [tex]\hookrightarrow 4x = 92\\\hookrightarrow x = 92/4 = 23[/tex]

Answer: 23

Hope that helps!

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Vertical Angle Theorem: two angles that are formed by two intersecting lines and are opposite each other are equal

The value of x is 23 because Angle FGI and Angle HGC are vertically opposite angles, the answer is 23.

What are vertically opposite angles?

It is defined as the angles when two lines intersect each other and at the intersecting point, some pair of angles are formed which we call vertically opposite angles, as the name describes that they have vertically opposite angles.

It is given that:

The triangle and two parallel lines are shown in the picture.

As we know, from the definition of the vertically opposite angle, two lines intersect each other at the intersecting point.

Angle FGI = Angle HGC = 14 degrees

4x = 78 + Angle HGC

4x = 78 + 14

4x = 92

x = 92/4

x = 23

Thus, the value of x is 23 because Angle FGI and Angle HGC are vertically opposite angles, the answer is 23.

Learn more about the vertically opposite angles here:

brainly.com/question/24287162

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please explain how you got it also ​

Answers

a WHOLE is always simplified to "1", and we can use any denominator for that, so 5/5 is 1, and 7/7 = 1, and [tex]\cfrac{4}{4}\implies \cfrac{113}{113}\implies \cfrac{1000000}{1000000}\implies \text{\LARGE 1}whole[/tex]

so hmmm for this case we'll be use thirds or namely the denominator of 3, so a whole bunch of basketballs was originally 3/3 of "b", "b" was the whole amount, so originally we had 3/3, but then during the day we sold 2/3 of them, so we were left with 3/3 - 2/3 = 1/3, and then 8 came back, because they were deflated or something, now the store has a total of 38 basketballs.

[tex]\stackrel{whole}{\cfrac{3}{3}b}~~ - ~~\stackrel{sold}{\cfrac{2}{3}b}\implies \cfrac{3b-2b}{3}\implies \cfrac{b}{3}\implies \stackrel{\textit{remaining in store}}{\cfrac{1}{3}b} \\\\\\ \stackrel{in~store}{\cfrac{1}{3}b}~~ + ~~\stackrel{coming~back}{8}~~ = ~~\stackrel{new~total}{38} \\\\\\ \cfrac{b}{3}+8=38\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3\left( \cfrac{b}{3}+8 \right)=3(38)}\implies b+24=114\implies \stackrel{originally}{b=90}[/tex]

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