Electric utility poles in the form of right cylinders are made out of wood that costs $13.72 per cubic foot. Calculate the cost of a utility pole with a radius of 0.75 ft and a height of 40 ft. Round your answer to the nearest cent.

The number of boxes of cookies Kai buy : independent variable

The amount of the cookies will cost in dollars : dependent variables      

Based on the given conditions, formulate,

Each box of cookies costs is = \$4$4dollar (sign, 4).

Cookie represented by c

The required equation is,

d = 4cd = 4cd = 4c

The price is determined by the number of cookies purchased.

c is the independent variable

when c is changes d is changed

So, d is the dependent variable    

variables of the equation.          

So,

We can write,

d = 4c

where d represents the cost of cookies in dollar and c represents the number of boxes of cookies.

Then, the cost of each box of cookies is $4.

It means,

The cost of 1 box of cookies is = $4.

The cost of 2 boxes of cookies is = $(4+4)  = $(2×4)

The cost of 3 boxes of cookies is = $(4+4+4)  = $(3×4)

The cost of cookies = (Number of boxes × 4)

The required equation is,

d = 4c

where d represents the cost of cookies in dollar and c represents the number of boxes of cookies.

Therefore,

The boxes of cookies Kai buy : independent variable

The cookies will cost in dollars : dependent variables    

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Boxes of cookies (c) is Independent.

Dollars spent (d) is Dependent.

Answer:

The answer is 28.26 square feet.

Step-by-step explanation:

The area of a circle is [tex]\pi r^{2}[/tex], so if the radius is 36, [tex]\pi *36^{2}[/tex] is equal to about 4071.5. The formula for converting square inches to square feet is to divide by 144, and [tex]\frac{4071.5}{144}[/tex] is around 28.26.

The simplified expression of 4y - 4(-2z + 6y) - 2z is -20y  + 6z

Expressions are mathematical statements that are represented by variables, coefficients and operators

The expression is given as

4y - 4(-2z + 6y) - 2z

Open the bracket

4y - 4(-2z + 6y) - 2z = 4y + 8z - 24y - 2z

Collect the like terms

4y - 4(-2z + 6y) - 2z = 4y - 24y  + 8z - 2z

Evaluate the like terms

4y - 4(-2z + 6y) - 2z = -20y  + 6z

Hence, the simplified expression of 4y - 4(-2z + 6y) - 2z is -20y  + 6z

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The surface area covered by the rectangular cookie crumble topping is of 35.1 m².

The surface area of a rectangular prism of height h, width w and length l is given by:

S = 2(hw + lw + lh).

For this problem, the bottom is not covered, hence the surface area will be of:

S = 2(hw + lh) + lw.

The dimensions are given as follows:

l = 4.45, w = 4.06, h = 1.

Hence the surface area is:

S = 2(4.06 x 1 + 4.45 x 1) + 4.45 x 4.06 = 35.1 m².

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Answer: 18=18

Step-by-step explanation:

Answer:

$507 958.20

Step-by-step explanation:

11 100 x   table value for 20 years , 8%

11,100 x 45.762 = $ 507,958.20

Answer:

28 degrees

Step-by-step explanation:

We know that (4x + 7) + (2x + 5) add up to a straight angle = 180 degrees, so we have the equation 4x + 7 + 2x + 5 = 180.

By combining like terms, we get 6x + 12 = 180.

Subtract 12 from both sides of the equation to get 6x = 168. Divide both sides by 6 and you get x = 28.

-[tex]\sqrt{3}[/tex] is the exponent of the power function.

The power function is generally just f(x) = c x^p for some constant c and some real number exponent p. (It can only be defined for positive values ​​of x.) For example, the square root function f(x) = √x is a power function with p = 1/2.

In this case, N=kA‾‾√3 , -[tex]\sqrt{3}[/tex] is the exponent of this function.

Exponentiation is a mathematical operation, written as bⁿ, involving two numbers, the base b and the exponent or power n, and pronounced as "b to the n".

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The exponent of the power function is 1/2.

How often we are multiplying a number by itself is indicated by its exponent. To multiply 3 four times, for instance, we get 34. It is 3333 in its enlarged form. A number's power is another name for an exponent. It may take the form of an integer, a fraction, a negative integer, or a decimal.

A fractional exponent is one where the exponent of a number is a fraction. Parts of fractional exponents include square roots, cube roots, and nth roots. Square root of the base is a number having a power of half.

Hence we get the exponent of the function as 1/2.

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Answer:

500

Step-by-step explanation:

Answer:

[tex]\sf y = \dfrac{x }{\boxed{26}} +\boxed{-2}[/tex]

Step-by-step solution:

[tex]\rightarrow \sf x - 26y = 52[/tex]

[tex]\rightarrow \sf - 26y = 52-x[/tex]

[tex]\rightarrow \sf - 26y = -x + 52[/tex]

[tex]\rightarrow \sf y = \dfrac{-x + 52}{-26}[/tex]

[tex]\rightarrow \sf y = \dfrac{-x }{-26} + \dfrac{ 52}{-26}[/tex]

[tex]\rightarrow \sf y = \dfrac{x }{26} -2[/tex]

Answer:50.63

Step-by-step explanation: line them up on top of each other and multiply 9 by all them and if its over 10 put the 2nd digit the the next number.

Domain = ∈ [2, ∞]

Range = ∈ [0, ∞]

Graph [tex]\sqrt{x - 2 [-10, 10, -5, 5]}[/tex]

Just outline the function.

The typical root operation is:

[tex]y = a * \sqrt{(x - h)} + k[/tex]

where x - h ≥ 0

The value within the root sign of a square root function CANNOT be < 0

∴ x - h ≥ 0

∴ x ≥ 2

Therefore, Domain = ∈ [2, ∞]

Regarding range, the function we were provided doesn't have a K value.

As a result, the range spans from 0 to infinity.

Therefore, Range = ∈ [0, ∞]

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Answer:

Can you please send the picture of the graph

Step-by-step explanation:

Answer:

16

Step-by-step explanation:

Difference means subtract

Let the two numbers be x and y

x-y = 6

Let y be the smaller number

2y = x+4

Using substitution

x = 6+y

2y = 6 +y +4

2y = y+10

Subtract y from each side

2y-y = y+10-y

y = 10

Now we need to find x

x-y = 6

x-10 = 6

Add 10 fo each side

x-10+10 =6+10

x = 16

Answer: To the nearest thousand.

Step-by-step explanation:

   First, we will round 126,945 to the requested place values;

(it says ten thousand once, so I'm going to include hundred thousand)

hundred thousand ➜ 126,945 ➜ 100,000

ten thousand ➜ 126,945 ➜ 130,000

thousand ➜ 126,945 ➜ 127,000

   Next, we will subtract these values from 126,945, and see which absolute value is the smallest.

hundred thousand ➜ 126,945 - | 100,000 | = 26,945

ten thousand ➜ 126,945 - | 130,000 | = 3,050

thousand ➜ 126,945 - | 127,000 | = 55

   The rounded amount that is closest to the actual attendance is thousand.

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The probability to win 25$ and 2$ are 1/18 and 1/6

Probability is the ratio of favorable cases to total sample cases.

If two dice are rolled,

Total sample cases or combinations= 6x6=36

The favorable cases to get 2 or 12 ={1,2}{6,6}= 2 total cases

The favorable cases to get 7 ={1,6}{6,1}{2,5}{5,2}{3,4}{4,3}=6 cases

The probability to win 25$=2/36=1/18

The probability to win 2$=6/36=1/6

Thus the probability to win 25$ and 2$ are 1/18 and 1/6

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Main Answer: $1.27

Given data:

If you rolled two dice and got a sum of 2 or 12, you won $25. If you rolled a 7, you won $2. Any other roll was a loss. It cost $1 to play one game with one roll of the dice.

Solving part

Step-by-step explanation:

For 2 and 12

Number of possible outcomes = 2

Gain = 25 -1 = $24

For 7

Number of possible outcomes = 6

Gain = 5-1 = $4

For others

Number of possible outcomes = 36-(4+6) = 26

Gain = -$1

Expectation of the gain;

X= (2×$24 + 6×$4 - 26×1)/36

X = $46/36

X = $1.27

Final Answer: $1.27

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Answer:

13:

x= 86°

14:

x= 30°

16:

x= 59°

Answer:

139/200

Step-by-step explanation:

.695 can be represented as 695/1000. Divide the numerator and denominator by 5, you get 139/200.

Answer: 139/200

Step-by-step explanation:

I am guessing

Part 1

∠FBA = 42° (alternate interior angles)

Part 2

∠FDC = 23° (linear pair)

∠BAD = 23° (alternate interior angles)

Part 3

∠AFBA = 115° (sum of angles in a triangle)

Answer:c

Step-by-step explanation:

c

We need to know about roots of a quadratic equation to solve the problem. The quadratic equation is [tex]x^{2} -3x-40=0[/tex]

Quadratic equation is an equation with the highest degree of the variable being 2. A quadratic equation has two roots. The two roots can be real and different or real and equal or imaginary. The roots of a quadratic equation can be found using factorization method. The roots of a quadratic equation can be used to find the quadratic equation itself. Here in this question we have two points (-5,0) and (8,0). These points lie on the x-axis hence we can say that they are the two roots of the equation and the quadratic equation is in terms of x since it cuts the x-axis. Hence we can say that the two roots of the equation are -5 and 8.

For a quadratic equation [tex]ax^{2} +bx+c=0[/tex] let us say that the roots are α and β

α+β=-b/a

αβ=c/a

Here α and β are -5 and 8

-5+8=-b/a ⇒b/a=-3

c/a=-5 x 8=-40

The quadratic equation is given by [tex]x^{2} +\frac{b}{a} x+\frac{c}{a} =0[/tex] which is [tex]x^{2} -3x-40=0[/tex]

Therefore we found the quadratic equation using the two points given, the equation is [tex]x^{2} -3x-40=0[/tex]

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The distance between the two points is 8.6 units

The points are given as

(4, 9) and (9, 2)

The distance between the two points is then calculated as

d = √(x2 - x1)^2 + (y2 - y1)^2

This gives

d = √(4 - 9)^2 + (9 - 2)^2

Evaluate the sum of exponents

So, we have

d = √74

Evaluate the exponents

So, we have

d = 8.6

Hence, the distance between the two points is 8.6 units

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Answer:

For the first 15 minutes his average speed is 40 mph. He then stops for 25 minutes. He then completed the journey at an average speed of 45 mph. The total journey time is 1 hour.

Answer:

See attached graphs Graph1, Graph2 and Graph3 and detailed explanation below

Step-by-step explanation:

The process for plotting and shading are essentially the same but with different inequalities

To plot any line

To determine area to shade

Choose a point on either side of the line from the graph. See if the corresponding (x,y) values satisfy the inequality. If they do, then that's the area to shade. If not, shade the other area

1. Inequality y > -3x - 2

The line equation is y = -3x -2

Let's choose x = 0. Then y = -3(0) -2 = -2. So one point is (0, -2)

Choose another value for x, say x = 1

y = -3(1) - 2 = -3-2 = -5. So another point is (1,-5).

Draw a straight line through both points (see attached Graph1)

Determining area to shade

Choose a point on the graph on one side of the line. Let's choose (1,2). So x = 1 and y = 2. Does this satisfy the inequality y = -3x -2? Let's see

Is 2 > -3(1) - 2 ?

2 > -3-2 ?

2 > -5 ? YES since a positive number is greater than a negative number. So the area containing (1,2) should be shaded as shown in Graph 1

2. Inequality 4x + 5y ≤ 20

Line equation is  4x + 5y =20

Convert to a function of x as follows

Choose two values of x and find corresponding y values to get the coordinates of two points

Plug x = 0 into line equation ==> y = 4- 4x/5

==> y = 4 - 4(0)/5 = 4

==> (0, 4) is one point

Choose another value of x, say 5(this is a convenient value since we are dividing by 5)

==> y = 4- 4(5)/5 = 4-4 = 0

==> (5, 0) is another point

Draw straight line through (0,4) and (5,0)

To determine area to shade let's choose a point on the graph. (0,0) is a convenient point.  Do the values of x=0 and y=0 satisfy the inequality
4x + 5y ≤ 20?

Plugging in x = 0 and y = 0 gives us

4(0) + 5(0) = 0 and 0 is indeed ≤ 20

So the inequality is satisfied at (0,0)

Shade the region on the side of the line where (0,0) is (see Graph2)

3. Inequality y > -4

The line equation is y = -4

Since this equation does not involve x, the line plot will be a horizontal line at y = -4 for all x values

Simply draw a horizontal line which crosses the y axis at y = -4

To determine which area to shade, choose a point. Use (0,0)

Does y = 0 satisfy the inequality y > -4?

0 > -4 so indeed the point (0,0) satisfies the inequality. Just shade the area on the side of the line which contains (0,0). This will be the region above the line y = -4 See Graph3

Hope that helps :)

[tex]\textit{internal division of a segment using a fraction}\\\\ A(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-8})\qquad B(\stackrel{x_2}{10}~,~\stackrel{y_2}{5})~\hspace{8em} \frac{7}{10}\textit{ of the way from A to B} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_2}{10}-\stackrel{x_1}{(-3)}~~,~~ \stackrel{y_2}{5}-\stackrel{y_1}{(-8)})\qquad \implies \qquad \stackrel{\stackrel{\textit{component form of}}{\textit{segment AB}}}{\left( 13 ~~,~~ 13 \right)} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\left( \stackrel{x_1}{-3}~~+~~\frac{7}{10}(13)~~,~~\stackrel{y_1}{-8}~~+~~\frac{7}{10}(13) \right)\implies \left(-3+\cfrac{91}{10}~~,~~-8+\cfrac{91}{10} \right) \\\\\\ \left( \cfrac{-30+91}{10}~~,~~\cfrac{-80+91}{10} \right)\implies \left(\cfrac{61}{10}~~,~~\cfrac{11}{10} \right)\implies \left(6\frac{1}{10} ~~,~~1\frac{1}{10} \right)[/tex]

Answer:

[tex]x = 28[/tex]

[tex]2x { } ^{2} - 5x - 6 = 0[/tex]