Explain how the solar system is a system.

The car in a time of 4 seconds will travel a distance of: 32 m

The formulas for uniformly varied rectilinear motion (UVRM) and procedures we will use to solve this exercise are:

Where:

Information about the problem:

Applying the acceleration formula we have:

a = (vf - vi) /t

a = (0 m/s - 16 m/s) /4 s

a = (-16 m/s) /4 s

a = -4 m/s²

Acceleration is negative because the car is decelerating

Applying the distance formula, we get:

x = (vf²-vi²)/ (2a)

x = [(0 m/s)²- (16 m/s)²]/ (2 * -4 m/s²)

x = (0 m²/s²- 256 m²/s²)/ -8 m/s²

x =  -256 m²/s²/ -8 m/s²

x = 32 m

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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Answer:

penalty

Explanation:

Penalties can gain your team yards if assessed against the opposition...their are multiple penalties which are assessed 10 yards

Answer:

450

Explanation:

I think answer is 450.

gravitational potential energy was gained when it was winched up 15 m is  73500 J.

GPE is turned

into kinetic energy as the pumpkin drops

Then,

pumpkin speed is 17.14 m/s.

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Compare the energy of a 1-megaton hydrogen bomb to the energy released by a major earthquake. Earthquake/Ebomb = 5.

Compare the energy of a 1-megaton hydrogen bomb to the energy released by a major earthquake. Earthquake/Ebomb = 5.

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Antelope's acceleration as it passes the second point is 1.65 m/s².

Speed: The ratio of distance to time can be used to quantify speed. M/s is the S.I. unit of speed.

Newton's equation of motion yields the following: S = (v+u)t/2.

u is the starting speed, v is the final speed, and S is the distance.

Given: v = 16.0 m/s, t = 7.10 s, S = 72 m.

making u the subject of the equation,

7.1(16+u) = 72×2

113.6+7.1u = 144

7.1u = 144-113.6

7.1u = 30.4

u = 30.4/7.1

u = 4.28 m/s

Thus the speed at the first point = 4.28 m/s .

The rate at which velocity changes is known as acceleration. M/s2 is the SI unit of acceleration.

a = (v-u)/t............................ Equation 2: acceleration is given by a.

v = 16.0 m/s, u = 4.28 m/s, and t = 7.10 s are given.

Replace in equation 2

a = (16-4.28)/7.1

a = 11.72/7.10

a = 1.65 m/s²

Thus the acceleration = 1.65 m/s².

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The first acceleration is 20276.6 m/s² and the second one is 4427.2 m/s².

                         [tex]\begin{aligned}\\\\\omega &= 2\pi.f\\\\&= 2\pi.\big(\frac{4300\,\text{rpm}}{60\,s})\\\\&= 450.29\, rad/s\end{aligned}[/tex]

                         [tex]\begin{aligned}\\\\a &= r\omega^2 \\\\&= 0.1\, m\,\times\,(450.29\,rad/s)^2\\\\&= 20276.1\, m/s^2 \end{aligned}[/tex]

                            [tex]\begin{aligned}\\\\v &= \sqrt{2.\times 9.8\,m/s^2\,\times 1.0\,m }\\\\&= 4.427\,m/s\\\\a &=\frac{\Delta v}{\Delta t}\\\\&= \frac{0-4.427\,m/s}{0.001\,s}\\\\&= -4427\, m/s^2\cdots(\text{- indicates a deceleration})\end{aligned}[/tex]

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(b) the set of points is in a plane

A circle has points in a plane, a center, a radius, and a diameter. Depending on the situation, at least one of the following words must be included in the definition of a circle:

Based on James' definition of a circle, he needed to specify that the points are in a plane (option b).

The phrase "the set of all the points," as he defines it, has a variety of meanings. among them are:

the set of points on a line.

a plane's set of points.

the region's collection of points

James should have made it clear that the collection of points is in a plane.

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The complete question is mentioned below:

James defines a circle as "the set of all the points equidistant from a given point." His statement is not precise enough

because he should specify that

(a) a circle includes its diameter

(b) the set of points is in a plane

(c) a circle includes its radius

(d) the set of points are collinear

the frequency of each wavelength of electromagnetic radiation is

A)frequency of wavelength 632.8nm(red light from helium–neon laser)

is 4.738×10¹⁴ s⁻¹

B)frequency of wavelength 503 nm (maximum solar radiation)

is5.960×10¹⁴ s⁻¹

C)frequency of wavelength 0.052nm (medical x-rays)

is5.765×10¹⁸s⁻¹

A)

632.8 nm (wavelength of red light from helium–neon laser)

1 nm = 10⁻⁹ m

632.8 nm = 632.8×10⁻⁹ m = 6.328×10⁻⁷ m

The speed of light is c = 2.998×10⁸ m/s

λ = 6.328×10⁻⁷ m

the frequency can be calculated as

ƒ = c / λ

ƒ = (2.998×10⁸m/s) / (6.328×10⁻⁷ m)

ƒ = 4.738×10¹⁴ s⁻¹

frequency of wavelength 632.8nm is 4.738×10¹⁴ s⁻¹

B)

503 nm (wavelength of maximum solar radiation)

1 nm = 10⁻⁹ m

503 nm = 503×10⁻⁹m = 5.03×10⁻⁷ m

c = 2.998×10⁸ m/s

λ = 5.03×10⁻⁷ m

the frequency can be calculated as;

ƒ = c / λ

ƒ = (2.998×10⁸ m/s) / (5.03×10⁻⁷m)

ƒ = 5.960×10¹⁴ s⁻¹

frequency of wavelength 503 nm is5.960×10¹⁴ s⁻¹

C)

0.052 nm (wavelength contained in medical x-rays)

1 nm = 10⁻⁹ m

0.0520 nm = 0.0520×10⁻⁹ m = 5.20×10⁻¹¹m

Where the speed of light is

c = 2.998×10⁸ m/s

λ = 5.20×10⁻¹¹ m

the frequency can be calculated as

ƒ = c / λ

ƒ = (2.998×10⁸ m/s) / (5.20×10⁻¹¹ m)

ƒ = 5.765×10¹⁸s⁻¹

frequency of wavelength 0.052nm is5.765×10¹⁸s⁻¹

A)frequency of wavelength 632.8nm(red light from helium–neon laser)

is 4.738×10¹⁴ s⁻¹

B)frequency of wavelength 503 nm (maximum solar radiation)

is5.960×10¹⁴ s⁻¹

C)frequency of wavelength 0.052nm (medical x-rays)

is5.765×10¹⁸s⁻¹

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The ball was in motion for 16.7 seconds before coming to rest.

Let us assume that the ball was in motion for a time equal to 't' seconds before coming to rest.

Given in the question

Initial velocity = u = 50 m/s

Final Velocity = v = 0 m/s ( As the ball stops moving after some time, its final velocity hence becomes zero. )

Acceleration = a = -3 m/s²

To find

Time = t seconds

Using the first equation of motion,

v = u + at

Put in the value in the equation, we get

0 = 50 + (-3)(t)

3t = 50

t = 50/3

t = 16.66 seconds

t = 16.7 seconds ( rounding off to one decimal place )

Therefore, the ball was in motion for 16.7 seconds before coming to rest.

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The substante that is insoluble and floats is the wood chip and the one that is insoluble is a sugar cube.

Solubility is a property that a substance has to dissolve in another that is called a solvent, this can also depend on the conditions of the temperature to which the solution can be exposed and also the pressure. The solubility will depend on the properties of each of the components, it is not always the same in all types of solutions.

When no more of the solute can dissolve in a solution, the solution is said to be saturated.

Therefore, we can confirm that the substante that is insoluble and floats is the wood chip and the one that is insoluble is a sugar cube.

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The ball will stop after 6 s.

The initial velocity of the ball is u.

u = 0.2 m/s

Acceleration of the ball is a.

a = 0.05 m/s²

The time interval is t.

t = 6 seconds.

The displacement of the ball at time t is s.

The displacement of the ball at time t is,

[tex]s= ut + \frac{1}{2} at ^{2} [/tex]

[tex]s= 0.2 \times 6+ \frac{1}{2} \times ( - 0.05) \times (6)^{2} [/tex]

[tex]s= 0.3 \: m[/tex]

Therefore, the displacement of the ball at time t is 0.3 meters.

The time at which the ball will stop is,

Distance = Speed × Time

0.3 = 0.05 × Time

Time = 6 seconds.

Therefore, the ball will stop after 6 s.

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Answer:

77ruririfusjd u 6r7r u y9r8

Based on the problem, the distance between two parallel conducting plate is x=10cm=0.10mx=10cm=0.10m

a)

The potential difference is V= 593VV= 593V

The distance between is d=7.05cm= 0.705md= 7.05cm= 0.705m

Recall the expression for the electric field.

E= VdE= Vd

Substitute the given values in above equation.

E= 5930.705= 841.13V/ mE =5930.705 = 841.13V/Vmm

Thus, the electric field strength is 841.13V/m.841.13V/Vmm.

b)

Recall the term for the voltage between the plate.

ΔV= E× x ΔV= E×x

Substitute the given values in above equation.

ΔV=841.13V/m×0.10m=84.11VΔV=841.13V/Vmm×0.10m=84.11V

Thus, the voltage within the plate is 84.11V.

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Surface Charge density on each plate  sigma =+- Q/a = +4.9×10²⁴/4.6×10⁻²C/m² and Electric field is found to be 0.12×10³⁸N/C.

Given, here the cross sectional area of the conducting plate (A)

A = 460 cm² = 460 x 10-4 m² = 4.6 x10-²m² and distance between plate, d = 4.0 cm = 4x10² m²

Charge on the plate, Q = ne ,where n= 1×10¹²

Q = ± 10¹² x4.9x 10¹²c = ± 4.9x 10²⁴ c

Now, we have to find charge density on each plate  sigma =+- Q/a = +4.9×10²⁴/4.6×10⁻² C/m²

σ= 1.09× 10²⁶ C/m²

Now we have to find electric field between the plates.

E= σ /E°= 1.09× 10²⁶/ 8.85×10⁻¹²

E= 0.12×1038N/C

Charge density is a measure of the amount of electric charge present in a space per unit volume in one, two, or three dimensions. The quantity of electric charge per surface area or volume, respectively, is known as the linear surface or volume charge density.

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If the starship drops the engine force output to 3000 N of force he ship's acceleration going to be at acceleration, a = 4.28 m/s².

In the given equation we can see the different force working on engine so,

To find the acceleration first we need the mass of engine

Using formula,

F = m x v

10,000 - 3000 N = m x 10 m/s

7000N = m x 10 m/s

m = 700 kg

Now as we have mass of the engine,

By the formula,

a = F / m

F = 3000 N

m = 700 kg

So, putting values we have :

a = 3000 / 700

a = 4.28 m/s²

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Ammonia is a weak base and Potassium hydroxide is a strong base, then then the solution of potassium hydroxide will always have a higher pH than a solution of ammonia, therefore the correct answer is option C.

A chemical compound is a combination of two or more  either similar or dissimilar chemical elements.

As given in the problem, ammonia is a weak base. Potassium hydroxide is a strong base then we have to find out which statement is correct from the given list of statements,

Since ammonia is a weak base and potassium hydroxide is a strong base, their solutions will always have a higher pH than ammonia solutions. Option C is the right response.

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The equilibrium temperature is required and to find whether the temperature change can be measured by a thermometer is required. The temperature is 310 K.

A physical measure that describes how hot a substance or radiation is is called temperature.

There are three different types of temperature scales: those, like the SI scale, that are defined in terms of the average translational kinetic energy per freely moving microscopic particle, like an atom, molecule, or electron, in a body; those that only rely on strictly macroscopic properties and thermodynamic principles, like Kelvin's original definition; and those that are defined by practical empirical properties of particulates rather than by theoretical principles.

With a thermometer, temperature is measured. It is calibrated in a number of temperature scales that historically defined themselves using different reference points and thermometric substances. The Celsius scale, originally known as "centigrade," is the most popular scale.

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Weight of the vehicle on Earth is 6736.72 kg.

What is the weight of an object?

The weight of an object is the force exerted on it owing to gravity in science and engineering. Weight is defined as a vector quantity in certain standard textbooks, as the gravitational force exerted on the item. Others describe weight as a scalar quantity, the magnitude of gravity.

Weight on Mars = (Weight on earth/10) x 3.711

Given, weight on mars = 2500 kg

Therefore, weight on Earth = 6736.72 kg.

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A girl delivering newspapers covers her route by traveling so resultant displacement is 5 blocks.

Her net x (east-west) displacement is –3.00+0+6.00= +3.00 blocks, while her net y (north-south) displacement is 0+4.00+0=+4.00 blocks.

The magnitude of the resultant displacement is

R= [tex]\sqrt{x^{2} +y^{2} } =\sqrt{3^{2} + 4^{2} }[/tex] = 5 blocks

and the angle made by the resultant

= [tex]\theta[/tex] = [tex]tan^{-2} =[/tex] 4/3

= 53.1°

The resultant displacement is 5 blocks at 53.1°

The term “displacement” refers to a shift in an object’s position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial location to the ending place.

For instance, if an object shifts from location A to position B, its position changes.

An object’s displacement is equal to its velocity times its acceleration times its time squared plus one-half (t2).

A scalar quantity known as distance measures “how much ground an object has traversed” while moving.

The term “how far out of place an object is” is referred to as displacement, a vector quantity.

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The tension in the string is 19.8 N.

Find the tension in the string:

The net force on the block will be:

T - Fr = Fnet = ma

Where T is the tension and Fr is the frictional force

T - ukR = ma

Where R is the upwards normal force equal to the block's weight. R = mg

therefore,

T - uk mg = ma

T - 0.2(5 x 9.8) = 5(2)

=> T = (0.2 x 5 x 9.8) + 5(2) = 19.8 N

This is the tension in the string.

For the free body diagram, draw a block and show a rope connected horizontally to it. The tension in the string will be along the rope outwards from the block. Now, the frictional force will be between the ground and the block and it will be in the opposite direction to the direction of tension of the rope. The force due to gravity will act vertically downwards while the normal force R will act vertically upwards.

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A shaded pole is a short-circuited winding, which consists of a single turn of copper wire and acts on only a portion of the stator windings.

Most single-phase motors just require the two start leads to be switched in order to turn the rotor in the opposite direction.

An AC motor that starts using a shaded stator pole. A partial short-circuited winding that affects only some of the stator windings, made up of a single turn of copper wire.

The motor is momentarily changed into a two-phase motor during the starting time to get around this problem and make it self-start. A single-phase motor’s stator is equipped with an additional winding, referred to as the starting winding, for this function (or auxiliary).

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OD. 2kg of liquid oxygen at -225 *C has the least thermal energy.

The thermal energy for a phase of matter is given by the formula

Q = mCΔT where

m = mass

C = Specific heat constant

T = Temperature

For Oxygen, the Specific heat constant = 0.92 J/gK

Let's calculate the thermal energy for each case, assuming that the initial temperature is 0 Kelvin

OA.

m= 5000 g

ΔT = 303 K

So Q =5000×0.92×303 = 1393800 J = 1393.8 KJ

OB.

m= 5000 g

ΔT = 48 K

So Q =5000×0.92×48 = 220800 J = 220.8 KJ

OC.

m= 2000 g

ΔT = 293 K

So Q =2000×0.92×293 = 539120 J = 539.12 KJ

OD.

m= 2000 g

ΔT = 48 K

So Q =2000×0.92×48 = 88320 J = 88.32 KJ

Therefore, OD 2kg of liquid oxygen at -225 *C has the least thermal energy which is 88.32 KJ.

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Answer:

2 kg of liquid oxygen at -225°C

Explanation:

B has the same temperature, yet it's more mass. So, to use this as an example--B has the most thermal energy. If the mass decreased, then the thermal energy would decrease. More mass=more thermal energy. Hence, why the mass decreasing to 2 kg would equal the least amount of thermal energy.

The temperature from t=0 to 10min with a step size of 2 min is as follows:

t (in min)   0      2       4           6         8         10

T ( in °C )  70  68.1  66.27  64.514  62.82  61.2

We know that,

The solution of first order differential equation is

dT / dt = - k ( T - [tex]T_{a}[/tex] )

where,

T = Initial temperature

[tex]T_{a}[/tex] = Ambient temperature

Given that,

k = 0.019 / min

[tex]T_{a}[/tex] = 20 °C

Using Euler method

[tex]T_{i} ^{'}[/tex] = - 0.019 ( [tex]T_{i}[/tex] - 20 )

[tex]T_{i+1}[/tex] = [tex]T_{i}[/tex] + ( [tex]T_{i+1}[/tex] * h )

With t = 0 to 10, h = 2, the iterative solution is as follows

At i=1, [tex]t_{i}[/tex] = 0, [tex]T_{i}[/tex] = 70

[tex]T_{i} ^{'}[/tex] = - 0.019 ( 70 - 20 ) = - 0.95

[tex]T_{i+1}[/tex] = 70 - ( 0.95 * 2 ) = 68.1

At i=2, [tex]t_{i}[/tex] = 2, [tex]T_{i}[/tex] = 68.1

[tex]T_{i} ^{'}[/tex] = - 0.019 ( 68.1 - 20 ) = - 0.914

[tex]T_{i+1}[/tex] = 68.1 - ( 0.914 * 2 ) = 66.27

At i=3, [tex]t_{i}[/tex] = 4, [tex]T_{i}[/tex] = 66.27

[tex]T_{i} ^{'}[/tex] =  - 0.019 ( 66.27 - 20 ) = - 0.88

[tex]T_{i+1}[/tex] = 66.27 - ( 0.88 * 2 ) = 64.514

At i=4, [tex]t_{i}[/tex] = 6, [tex]T_{i}[/tex] = 64.514

[tex]T_{i} ^{'}[/tex] =  - 0.019 ( 64.514 - 20 ) = - 0.846

[tex]T_{i+1}[/tex] = 64.514 - ( 0.846 * 2 ) = 62.82

At i=5, [tex]t_{i}[/tex] = 8, [tex]T_{i}[/tex] = 62.82

[tex]T_{i} ^{'}[/tex] =  - 0.019 ( 62.82 - 20 ) = - 0.8136

[tex]T_{i+1}[/tex] = 62.82 - ( 0.8136 * 2 ) = 61.2

At i=6, [tex]t_{i}[/tex] = 10, [tex]T_{i}[/tex] = 61.2

Euler's method is used for solving ordinary differential equation with a given initial value. It is a first order numerical procedure.

The given question is incomplete. The complete question is:

Newton's law of cooling says that the temperature of a body changes at a rate proportional to the difference between its temperature and that of the surrounding medium (the ambient temperature), dT/dt = -k(T-Ta) where T = the temperature of the body (°C), t = time (min), k = the proportionality constant (per minute), and Ta = the ambient temperature (°C). Suppose that a cup of coffee originally has a temperature of 70 °C. Use Euler's method to compute the temperature from t = 0 to 10 min using a step size of 2 min if Ta = 20 °C and k = 0.019/min.

Therefore, the temperature from t =0 to 10 min with a step size of 2 min is as follows:

t (in min)   0      2       4           6         8         10

T ( in °C )  70  68.1  66.27  64.514  62.82  61.2

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Answer:

number 3

Explanation:

the effort is almost equal to the load

Im confused on your questions, however they both need each other to work :D

Answer:

Photosynthesis and cellular respiration are processes by which plants and animals use to create energy from food.

Photosynthesis is exclusive to plants only though. It starts with sunlight which goes through the Electron Transport Chains (ETC's) and then through a cycle known as the Calvin-Benson cycle to create glucose.

Cellular respiration (cell resp) takes the glucose made in photosynthesis (or in the case of humans, from our food) and takes it through the Krebs cycle (sometimes referred to as the Citric Acid cycle) to create Adenosine Triphosphate (ATP) which is used to give us energy.

Hope that helps.

the smallest deceleration needed, in m/s^2, to avoid rear-ending the car

will we of a = -12.5m/s^2.

A reduction in velocity, or momentum, is referred to as a deceleration. The slowing of a rise is referred to as a deceleration. For instance, the wind has a certain amount of momentum. We may say that the wind is decelerating when its momentum slows down, i.e., when it blows less forcefully.

To avoid rear-ending the car

Reduce final velocity of the car to less or equals to the speed of bad driver's car before car travels 20 m

Because if final velocity of car is less than or equal to the speed of bad driver's car then car can't able to cross bad driver's car.

Final velocity of the car (Vf) = 20 m/s

Using equation of motion

[tex]v^{2} _{f} = v^{2} _{i} + 2as\\ a = v^{2} _{f} - v^{2} _{i} / 2s\\= 20 ^{2} - 30 ^{2}/ 2 *20\\= -12.5m/s^{2}[/tex]

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The exoplanet where the human expedition landed has a surface gravity acceleration of -0.20 meters per square second.

The relationship between a moving body's distance, velocity, acceleration, and time is known as the equation of motion.

Here, is the beginning body, is the final body, is the acceleration of the body, and is the distance travelled. This is the third equation of motion for distance.

The greatest distance leapt by one of the explorers is 19.5 metres, as stated in the problem.

The starting velocity is 2.80 m/s.

It is necessary to determine the gravitational acceleration on the exoplanet's surface.

The explorers' velocity is currently zero. As a result, according to the third equation of motion, the explorers are moving downhill as shown by the negative sign.

Thus, the gravitational acceleration on the surface of the exoplanet is -0.20 meter per squared second.

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