Find the perimeter of the polygon with the given vertices:
U (-1,4)
V (3, 4)
W (3, 1)
The perimeter of the polygon = ?

I need help with this

[tex] \bold \implies{ \bold{The \: correct \: option \: is \: c) \: sin \: 141° < 0}}[/tex]

[tex] \bf \longrightarrow \tan141\degree = - \frac{b}{a} < 0 \\ \\ \bf \longrightarrow \sin141\degree = \frac{b}{c} > 0 \\ \\ \bf \longrightarrow \cos141 \degree = - \frac{a}{c} < 0[/tex]

The original price based on the gift card of $15 and discount of 30% is $55.50

What deductions are taken from the original price?

In order to arrive at the total cost before taxes, the gift card of $15 was first of all deducted from the original price before grossing up to 100% since the total cost before taxes represents 70% after the gift card has been deducted

original price(total cost before taxes+gift card)/(1-discount rate)

total cost before taxes=$23.85

gift card=$15

discount rate=30%

original price=($23.85+$15)/(1-30%)

original price=$55.50

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Answer:

Step-by-step explanation:

30.466666.999

2.81*10^4

the number of times you move the decimal adds to the exponent

Answer:

He has to pay $223.68 after 6 months

Step-by-step explanation:

I don't know if I understood you right but I think you meant how much does he have to pay in 6 months. That would be 37.28x6=223.68

Answer:

50 I think

Step-by-step explanation:

30% of 500 is 150 so we have 150 red balls

40% of 500 is 200 so we can assume 50 balls were taken out

Answer:

Step-by-step explanation:

hey Can u help me answer this question ? The way you use your money reveals your true priorities. Knowing that, how could having budget categories help you prioritize your money ?

Answer:

P = 4s

Step-by-step explanation:

All the numbers in column P are equal to 4 times the numbers in column s

The domain of the function is (0,∞) , {x|x>0}

and the range is  (₋∞, ∞) ,  {y|y ∈ R}

Given the function is y = log₅x

A function's domain and range are its constituent parts. A function's range is its potential output, whereas its domain is the set of all possible input values. Range, Domain, and Function. A is the domain and B is the co-domain if a function f: A B exists that maps every element of A to an element in B. 'b', where (a,b) R, provides the representation of an element 'a' under a relation R. The set of images is the function's range. In general, a function's domain and range are denoted as follows: Range(f) = f(x): x domain(f) and domain(f) = f(x): x R

hence we get the domain and range as (0,∞) , {x|x>0} and  (₋∞, ∞) ,  {y|y ∈ R} respectively.

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Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. (x+4)⁸ is expanded as x⁸ + 32x⁷ + 448x⁶ + 3584x⁵ + 17920x⁴ + 57344x³ + 114688x² + 131072x + 65536

The Binomial theorem tells us how to expand expressions of the form (a + b)ⁿ, for example, (x + y)⁷. The larger the power is, the harder it is to expand expressions like this directly.

The total number of terms in the expansion of (x+y)ⁿ are (n+1).

The sum of exponents of x and y is always n.

nC₀, nC₁, nC₂,….., nCₙ are called binomial coefficients and also represented by C₀, C₁, C₂, ….., Cₙ

The binomial coefficients which are equidistant from the beginning and from the ending are equal.

i.e. nC₀ = nCₙ, nC₁ = nCₙ₋₁ , nC₂ = nCₙ₋₂ ,….. etc.

Let the expression be (x + 4)⁸

Use the binomial expansion theorem to find each term. The binomial theorem states

(a+b)n=n∑k=0nCk⋅(an−kbk)(a+b)n=∑k=0n⁡nCk⋅(an-kbk).

8∑k=08!(8−k)!k!⋅(x)8−k⋅(4)k∑k=08⁡8!(8-k)!k!⋅(x)8-k⋅(4)k

Expand the summation

8!/(8−0)!0!.(x)⁸⁻⁰⋅(4)⁰+8!/(8−1)!1!(x)⁸⁻¹⋅(4)¹+…+8!/(8−8)!8!(x)⁸⁻⁸⋅(4)⁸

Simplify the exponents for each term of the expansion.

1⋅(x)⁸⋅(4)⁰+8⋅(x)⁷⋅(4)1+…+1⋅(x)⁰⋅(4)⁸¹⋅(x)⁸⋅(4)⁰+8⋅(x)⁷⋅(4)¹+…+1⋅(x)⁰⋅(4)⁸

Simplify the polynomial equation, we get

x⁸ + 32x⁷ + 448x⁶ + 3584x⁵ + 17920x⁴ + 57344x³ + 114688x² + 131072x + 65536

Therefore, by expanding the binomial equation, we get

(x + 4)⁸ =  x⁸ + 32x⁷ + 448x⁶ + 3584x⁵ + 17920x⁴ + 57344x³ + 114688x² + 131072x + 65536

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The value of x based on the equation illustrated as BM=x+7,DM=2x+3 is 10.

It should be noted that an equation is used to show the relationship that exists between rte variables.

The expression given are

BM=x+7

DM=2x+3

Equate both equations

x + 7 = 2x - 3

Collect like terms

2x - x = 7 + 3

x = 10

Therefore, the value of x is 10.

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Answer:

Step-by-step explanation:cevap çok basit cevap eşittir cevap yani çok basit

Answer:

3^x=x^(x/3)

3^(3*x)=x^(3*x/3)

3^(3x)=x^x

(3^3)^x=x^x

27^x=x^x

27^(x*1/x)=x^(x*1/x)

27^(x/x)=x^(x/x)

27^1=x^1

x=27

Step-by-step explanation:

Answer:

J.o.i.n p.l.z pqp-yuth-ygd

Answer:

[tex]10j \leqslant 130[/tex]

[tex]j \leqslant 13[/tex]

Given the data in the table, the slope, y-intercept and equation of the table are 1/3, (0,-2), and y = (1/3)x - 2 respectively.

Given that;

x           y

-3        -3

0         -2

3         -1

6         0

9         1

Slope m = rise/run = (y₂ - y₁)/(x₂-x₁)

Using the, the points (-3,-3) and (0,-2) from the table

Slope m = rise/run = (y₂ - y₁)/(x₂-x₁)

Slope m = rise/run = ((-2) - (-3)) / ( 0 - (-3) )

Slope m = 1/3

To determine the y-intercept b, use the formula for equation of line.

y = mx + b

Substitute in Point( -3,-3 ) and m = 1/3 and solve for b

y = mx + b

-3 = (1/3)(-3) + b

-3 = -3/3 + b

-3 = -1 + b

b = -3 + 1

b = -2

Hence the y-intercept in point form is (0,-2)

The equation of the line in slope-intercept form will be;

y = mx + b

y = (1/3)x + (-2)

y = (1/3)x - 2

Given the data in the table, the slope, y-intercept and equation of the table are 1/3, (0,-2), and y = (1/3)x - 2 respectively.

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Answer: (x−3)(3x−8)

Step-by-step explanation:(x−3)(3x−8)

Apply the distributive property by multiplying each term of x−3 by each term of 3x−8.

3x

2

−8x−9x+24

Combine −8x and −9x to get −17x.

3x

2

−17x+24

The solutions to the equations are:

A. b = ac² (dark green); b = 2

B. v = m - k (light blue); v = 5

C. p/q = r/s; q = 8

D. m = 3n/4 (red); m = 6

E. x = y(w + z) (light green); x = 10

F. d1 = 2m - d2 (dark blue); d1 = 7

G. s = 8r/9 (purple); s = 4

H. w = [tex]\sqrt{\frac{x - y}{v} }[/tex] (orange); w = 3

I. x = [tex]\frac{y - y_1 }{m} + x_1[/tex] (pink); x = 1

J. c = 5a - 7 (brown); c = 9

To solve for a variable in an equation, we need to isolate the variable to one side of the equation.

A. a = b/c²

a(c²) = b/c²(c²) [multiplication property of equality]

ac² = b

b = ac² (dark green)

Substitute a = 1/8 and c = 4 into the equation

b = (1/8)(4²)

b = (1/8)(16)

b = 2

B. m - v = k

m - v - m = k - m [subtraction property]

-v = k - m

v = -k + m

v = m - k (light blue)

Substitute k = -7 and m = -2 into the equation

v = -2 - (-7)

v = -2 + 7

v = 5

C. p/q = r/s

Cross multiply

qr = ps

qr/r = ps/r [division property]

q = ps/r (yellow)

Substitute k = -7 and m = -2 into the equation

q = (14)(-4)/-7

q = 8

D. 4m + 2n = 5n

4m + 2n -2n = 5n - 2n [subtraction property]

4m = 3n

4m/4 = 3n/4 [division property]

m = 3n/4 (red)

Substitute n = 8 into the equation

m = 3(8)/4

m = 6

E. w = x/y - z

w + z = x/y - z + z [addition property]

w + z = x/y

y(w + z) = x/y(y) [multiplication property]

y(w + z) = x

x = y(w + z) (light green)

Substitute w = -8, y = -5, and z = 6 into the equation

x = -5(-8 + 6)

x = -5(-2)

x = 10

F. m = 1/2(d1 + d2)

2m = d1 + d2 [multiplication property]

2m - d2 = d1 [subtraction property]

d1 = 2m - d2 (dark blue)

Substitute m = 10 and d2 = 13 into the equation

d1 = 2(10) - 13

d1 = 20 - 13

d1 = 7

G. 2r = 5s/2 - s/4

2r = (10s - s)/4

2r = 9s/4

2r(4) = 9s/4(4) [multiplication property]

8r = 9s

8r/9 = 9s/9 [division property]

8r/9 = s

s = 8r/9 (purple)

Substitute r = 9/2 into the equation

s = 8/9(9/2)

s = 4

H. vw² + y = x

vw² + y - y = x - y

vw² = x - y

vw²/v = (x - y)/v

w² = (x - y)/v

w = [tex]\sqrt{\frac{x - y}{v} }[/tex] (orange)

Substitute v = 5, x = 38, y = -7 into the equation

w = [tex]\sqrt{\frac{38 - (-7)}{5} }[/tex]

w = √9

w = 3

I. [tex]y - y_1 = m(x - x_1)[/tex]

[tex]\frac{y - y_1 }{m} = x - x_1\\\\\frac{y - y_1 }{m} + x_1 = x[/tex]

x = [tex]\frac{y - y_1 }{m} + x_1[/tex] (pink)

Substitute x1 = 9, y = 19, y1 = -5, and m = -3 into the equation

x = (19 - (-5))/-3 + 9

x = -8 + 9

x = 1

J. 2a + 3c = 17a - 21

2a - 17a = -3c - 21

-15a = -3c - 21

-15a + 21 = -3c

-15a/-3 + 21/-3 = -3c/-3

5a - 7 = c

c = 5a - 7 (brown)

Substitute a = 16/5 into the equation

c = 5(16/5) - 7

c = 16 - 7

c = 9

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=========================================================

Explanation:

We'll use Heron's Formula.

When given the three sides a,b,c, the area of the triangle is

[tex]A = \sqrt{s(s-a)(s-b)(s-c)}[/tex]

where s = (a+b+c)/2 is the semi-perimeter, aka half the perimeter.

Let's compute the value of s first

s = (a+b+c)/2 = (8+9+3)/2 = 20/2 = 10

Then we can say,

[tex]A = \sqrt{s(s-a)(s-b)(s-c)}\\\\A = \sqrt{10(10-8)(10-9)(10-3)}\\\\A = \sqrt{140}\\\\A \approx 11.8321595661992\\\\A \approx 11.83\\\\[/tex]

The triangle has area of roughly 11.83 square meters.

Based on the given equation which has been solved in the table (see attachment), we know that: D. the subtraction property of equality was not applied to solve this equation.

An equation can be defined as a mathematical expression which shows that two (2) or more thing are equal.

The subtraction property of equality states that the two (2) sides of an equation would still remain equal even when the same number has been subtracted from both sides of an equality.

Based on the given equation which has been solved in the table (see attachment), we can reasonably and logically deduce that the subtraction property of equality wasn't applied to solve this equation.

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The string can be cut into 50 pieces of 10 cm length.

Length is a measurement of how long an object is or the distance between two points. Length is the term used to identify the size of an object or the distance from one point to another. It can be used to determine an object's size or the distance between two points.

A measurement of length is the distance between two locations or the length of an item. The term "length" is used to describe an object's size or the separation between two points. It may be used to calculate the size of an item or the separation between two places. Distance is measured in length. Length has the dimension of distance in the International System of Quantities. The majority of measuring systems choose a base unit for length from which all other units are derived.

Centimeters, meters, kilometers, inches, feet, and yards are some examples of conventional units used to measure length.

1 m = 100 cm

so, no. of pieces = 500/10 = 50.

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Answer: 50 pieces

Step-by-step explanation:

      First, we need both of the measurements to be in the same unit.

5 m ➜ 500 cm

      Next, we will use division to see how many 10 cm pieces of string can be cut.

500 cm / 10 cm = 50 pieces

3.22 approx. is the value of x in equation [tex]e^{\frac{x}{2}[/tex] = 5 solved by using natural logarithms

We have been asked to find x in [tex]e^{\frac{x}{2}[/tex] = 5 using natural logarithms

⇒  [tex]e^{\frac{x}{2}[/tex] = 5

⇒ [tex]\frac{x}{2}[/tex] = ㏑(5)

⇒ x = ㏑(25)

      = 3.22 approx.

A number's natural logarithm is its logarithm to the base of the transcendental and irrational number e, which is roughly equivalent to 2.718281828459.

Typically, the natural logarithm of x is denoted by the symbols ln x, loge x, or, if the base e is implicit, just log x. When adding parentheses for clarity, the values ln(x), loge(x), or log (x). In order to avoid ambiguity, this is notably done when the argument to the logarithm is not a single symbol.

The power to which e would need to be raised in order to equal x is the natural logarithm of x.

For instance, e2.0149... = 7.5, thus ln 7.5 equals 2.0149.

Since e1 = e, the natural logarithm of e itself, or ln e, is equal to 1, while the natural logarithm of 1 is 0, since e0 = 1.

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Use natural logarithms to solve each equation.

[tex]e^{\frac{x}{2}[/tex] = 5

Two identical figures with all sides of equal length = Both are square

Solution :

The perimeter of a square is defined as the total length that its boundary covers. The perimeter of any closed geometrical shape is calculated by finding the distance around that shape. For a square, the perimeter can be calculated by finding the sum of all the sides. Since all four sides are equal, it is four times the length of each side of a square. Let us learn about perimeter of square in detail in this article.

Derivation of Perimeter of Square Formula

The perimeter of the square is defined as the total length of the boundary of a square. In order to calculate the perimeter of the square, we will find the sum of all of its sides. Since all sides of a square are equal for a square, with each side measuring "s" units, perimeter will thus be given as,

Perimeter of square = s + s + s + s

⇒ Perimeter of square = 4s, where "s" is the side length of the square.

Squares :

A square is a special kind of rectangle (an equilateral one) and a special kind of parallelogram (an equilateral and equiangular one). A square has four axes of symmetry, and its two finite diagonals (as with any rectangle) are equal. Bisection of a square by diagonal results in two right triangles.

The formula for the perimeter of a square is,

P = Side + Side + Side + Side. Or,

P = 4 × Side.

two identical figures with all sides of equal length the combined perimeter of the figure is 80centimeters

2(4*side ) = 80

8*side = 80

side = 10

length of one side =10

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keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the PQ line

[tex]P(\stackrel{x_1}{-3}~,~\stackrel{y_1}{9})\qquad Q(\stackrel{x_2}{8}~,~\stackrel{y_2}{-2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{9}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{(-3)}}} \implies \cfrac{-11}{8 +3}\implies -1[/tex]

if indeed RS || PQ, then their slopes are exactly the same, thus

[tex]R(\stackrel{x_1}{-8}~,~\stackrel{y_1}{8})\qquad S(\stackrel{x_2}{0}~,~\stackrel{y_2}{y}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{y}-\stackrel{y1}{8}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-8)}}} \implies \cfrac{y -8}{0 +8}~~ = ~~\stackrel{\stackrel{slope}{\downarrow }}{-1} \\\\\\ \cfrac{y-8}{8}=-1\implies y-8=-8\implies \boxed{y=0}[/tex]

The required statement is proved.

Given y = ax² ₊ bx ₊ c, which is the general formula of quadratic form)

vertex = (-b/2a , 4ac ₋ b²/4a) which is the quadratic vertex formula

according to y = ax² ₋ 2px ₊ ap² ₊ q

therefore, a = a

b = ₋2xp

c = ap²₊q

⇒ (₋(₋2p/2a , 4a× (ap² ₊ q)₋ (2ap)²/4a)

⇒ (p , 4a²p² ₊ 4aq ₋ 4a²p²/4a)

⇒ (p , 4aq/4a)

⇒ (p,q)

hence we proved the quadratic equation .

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The given function y=4(0.2) ^x+1 is a exponential function because value of x could be any number. Whenever we have a degree of x in terms of y then it is a part of exponential function.

In the biological sciences, exponential functions are frequently used to simulate the evolution of a particular quantity over time, such as population size. Experimental data graphs are typically created with the quantity on the y-axis and the time on the x-axis.

Exponential functions play a key role in economic analysis of growth and decay. Examples include investment values that rise by a fixed percentage each period, business sales that rise by a fixed percentage each period, models of economic expansion, or models simulating the spread of an epidemic.

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