For all of their diversity, many less developed countries are linked by a range of common problems. what are these problems? which do you think are the most important? why?

The acceleration of the stalled car is 0.5 m/ s^2 forward.

By the formula of force we know that F = m X a

so in this question, mass = 1000kg , and F = 2000N

so acceleration of the car = 2000N= 1000kg X a

a = 1000kg / 2000N, = 0.5 m/ s^2 forward.

Force is a factor that has the power to alter an object's motion. An object with mass can change its velocity, or acceleration, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

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Acceleration of the stalled car is 2 m / s ² in forward direction .

Force is defined as the rate of change of momentum or as the product of mass and acceleration .

F = m ( v - u ) / t

F = m x a

F  = Force

m = Mass

a = Acceleration

It is given that ,

F = 2,000 N

m = 1,000 kg

Since , F = m x a

So ,

a = F / m

a = 2,000 N / 1,000 kg

a = 2 m / s ² Forward

Hence , Acceleration of the stalled car is 2 m / s ² in forward direction .

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After 3.0 s, If the first player makes up his mind to chase his opponent. If he accelerates uniformly at 3.5 m/s^2 then it would take 3.13 seconds to catch his opponent.

There are three equations of motion given by  Newton,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

As given in the problem, a hockey player is standing on his skates on the Rideau Canal when an opposing player, moving with a uniform speed of 2.8 m/s, skates by with the puck. After 3.0 s, the first player makes up his mind to chase his opponent. If he accelerates uniformly at 3.5 m/s^2,

Let us assume the time taken to catch up would be t seconds.

The distance traveled by the hockey player = 2.8×3 + 2.8×t

By using the second equation of the motion,

s = ut+0.5at²   = 2.8×3 + 2.8×t

1.75t² - 2.8t -8.4 = 0

t = 3.13 seconds

The distance traveled by the hockey player to catch up = 2.8×(3+3.13)

                                                                                             =17.164 meters

Thus, it would take 3.13 seconds to catch his opponent.

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To a stationary observer, a man jogs east at 6 m/s and a woman jogs west at 2 m/s. From the man's frame of reference, the woman's velocity is 4 m/s.

Velocity is a term that defines that how much a particle covered the distance in a particular time. Velocity is a vector quantity. It can be measured in m/s or cm/s.

To calculate the velocity we are using the formula, Δv= v₁-v₂

Here we are given,

v₁= According to a stationary observer, velocity of a man=6 m/s East.

v₂=According to a stationary observer, velocity of a woman= 2 m/s West.

We have to calculate the woman's velocity, from the man's frame of reference=  Δv

Now we put the values in the above equation, we get

Δv= v₁-v₂

Or, Δv= 6-2

Or, Δv=4m/s.

According to the calculation we can say that, From the man's frame of reference, the woman's velocity is 4 m/s.

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D. The slope of the line is equal to zero and the object will be in motion.

Velocity of a body is said to be constant, if it covers equal distances in equal intervals of time, and also does not change the direction it is moving in

To have a constant velocity, an object must have a constant speed in a constant direction.

slope = change in velocity / change in time

if the velocity is constant, then change in velocity = 0

slope = 0/change in time = 0

In constant velocity, the object will be in motion, but the velocity of the object will not change.

Thus, the slope of the line is equal to zero and the object will be in motion.

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Hello! Lets begin!

1. Which answer best describes displacement?

2. Kelley is playing pool and hits the cue into the nine ball, which is directly in the center of the pool table. The nine ball travels a total of 7 meters before stopping, 1 meter to the left of the initial starting point of the nine ball. Which sentence reflects the correct statement regarding distance and displacement when considering the motion of the nine ball?

3. What is velocity?

4. Imagine a time-position graph where the velocity of an object is constant. What will be observed on the graph concerning the slope of the line segment as well as the velocity of the object?

5. Select the option that best summarizes the reason for the use of position-time graphs when studying physical science.

_______________________________________________________

Good luck my peeps! ;D

Answer:

SEE below

Explanation:

MASS is a measure of the amount of matter in an object....it will remain the same ....

  WEIGHT is a measure of gravitational pull on the object and is inversely dependent on the square of the distance between the two bodies...so weight will be LESS than on the surface of the planet

Elastic potential energy is initially at rest, making it move.

Elastic potential energy is what causes a ball to bounce or rebound because it is transformed into kinetic energy and used to raise the ball back up. However, because some of the ball's energy was transferred to the ground or changed into sound (in the noise it makes upon impact) and heat energy, the ball won't go as high as it did at first (friction with the table). Additionally, even though we cannot see it, the ball alters once it strikes the ground or a table, energy is needed to take shape for a brief period of time.

Because of this, each bounce has a slightly lower height than the one before it. The ball has some kinetic energy when it hits the floor, but some of it is changed, so it loses some of it each time it bounces. After a few bounces, the ball has so little kinetic energy remaining that it stops bouncing.

Thus the correct answer is option A.

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Answer: twice as much

Explanation:

you're welcome!

If A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90s then the building is 17.69 meters tall.

Velocity is the directional speed of a moving item as an indication of its rate of change in position as seen from a specific frame of reference and measured by a specific time standard (e.g., 60 km/h northbound). The idea of velocity is crucial in kinematics, the part of classical mechanics that explains the motion of bodies.

A physical vector quantity called velocity requires both magnitude and direction to be defined. Speed is a coherent derived unit that expresses the scalar absolute value (magnitude) of velocity. Its quantity is expressed in SI units (metric system) of metres per second (m/s or ms1). For example, "5 meters per second" is a scalar while "5 meters per second east" is a vector.

We have given that

u = 0 m/s                          (initial velocity)

t = 1.90 s                           (time)

a = g = 9.80 m/s²             (acceleration = falling = gravity)

We will use the second equation of motion to determine the height(S) of the building in meters:

⇒ S =  [tex]ut + \frac{1}{2} at^2[/tex]

⇒ S = (0)(1.90) + [tex]\frac{1}{2}[/tex](9.80)(1.90)²

⇒ S = 4.9 × 3.61

       = 17.69 meters

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Full question

A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90 s. You may ignore air resistance, so the brick is in free fall. (a) How tall, in meters, is the building?

The athlete is 7.5 km North east from the starting point.

According to Pythagoras theorem,

[tex]AD^{2}[/tex] = [tex]6^{2}[/tex] + [tex]4.5^{2}[/tex]

AD = √ 36 + 20.25

AD = √ 56.25

AD = 7.5 km

Therefore, the athlete is 7.5 km North east from the starting point.

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Gravity is the sole force acting on the body during free fall motion.

The student should launch the sphere at 2v0 because it will land in the 3 point zone at a distance of around 1.41D.

The variables mentioned are;

the sphere's travel distance when thrown from a height, H = D

The speed at which the ball travels to D = v0

The launcher's current available height is H/2.

The available speeds are v0 and 2v0.

Using the formula H = ut + (1/2)gt2, where u is the beginning velocity of the ball's vertical motion, the following is obtained:

H = (1/2)·g·t²

The time it takes for the ball to fall from H is given by t = ((2H/g)).

The length, D = v0 (2H/g),

we obtain when the height is H/2;

t = √(2·H/(2·g)) = √(H/g)

D1 = v0 (H/g) is the distance traveled.

D = (2) v0 (H/g) = ((2)) D1 follows.

D₁ = D/(√2) ≈ 0.71·D

D₁ ≈ 0.71·D

We have at pace 2v0;

D2 = 2v0 (H/g) = 2 v2 v0 (H/g) = 2 v0 (2H/g) = 2D1 1.41D

D₂ ≈ 1.41·D

The 2 point zone is equal to D/2 x D = 0.5 D x D. (This is where position D1 0.71D is placed)

The 3 Point Zone is located at position D2 1.41D and is defined as D x 3D/2 = D x 1.5D.

The student should launch the sphere at the speed, 2v0, such that the ball will land at D2 1.41D, which is in the 3 Point Zone, given that the ball lands at D2, where it is in the 3 Point Zone.

A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizontal direction with variable speed and from a variable vertical position and a fixed horizontal position x=0.

The robot is calibrated by adjusting the speed at which the sphere is launched and the height of the robot’s sphere launcher. Depending on where the spheres land on the ground, students earn points based on the accuracy of the robot. The robot is calibrated so that when the spheres are launched from a vertical position y=H and speed v0, they consistently land on the ground on a target that is at a position x=D. Positive directions for vector quantities are indicated in the figure.

When the students arrive at the competition, it is determined that the height of the sphere launcher can no longer be adjusted due to a mechanical malfunction. Therefore, the spheres must be launched at a vertical position of y=H2. However, the spheres may be launched at speed v0 or 2v0.

Question: In a clear response that may also contain diagrams and/or equations, describe which speed, v0 or 2v0, the students should launch the sphere at so that they earn the maximum number of points in the competition.

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A. The force of gravity causes the coin to change its velocity.

Force of gravity always act toward the center of the earth , so when an object is thrown up, the force of gravity will act in opposite direction of motion, that's toward the center of earth.

This will cause the object moving upwards to slow down due to the force of gravity acting on the opposite direction of the object's upward motion.

When a coin is tossed in the air, it travels upward, gradually slows down, momentarily reaches zero speed, then moves back downward with increasing speed due to effect of force of gravity.

Thus, the statement that best explains the change in the coin's motion is "The force of gravity causes the coin to change its velocity".

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Dilution is needed to bring the unknown’s absorbance within the range of the standard curve.

If the dilution procedure is documented, it is possible to calculate the full-strength concentration after determining the diluted unknown quantity. Beer’s Law only applies to diluted solutions; hence it is preferable to dilute the unknown than to create new standards.

Spectrophotometers gauge transmittance (T) and absorbance (A) (T). Photons per second are used to quantify the light’s intensity. A blank sample, which does not absorb light when light passes through it, is represented as (I).

The principle of the spectrometer. The spectrophotometer is a device that calculates how much light a substance absorbs.

The spectrophotometer measures the light intensity of a sample by passing a light beam through it.

A spectrophotometer is a device that counts the number of photons (light’s energy) absorbed after they have passed through a sample solution.

The spectrophotometer can also be used to determine the concentrations (amounts) of known chemical substances.

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The waves that differ is:

Δx = 2λ

The constructive interference is equal: ΔΦ = 2nπ

If

n = 0, central bright fringe

n = ±1, first maxima on both fringes

n = ±2, second maxima on both fringes

What is maxima?

The maxima and minima of a function, collectively referred to as extrema in mathematical analysis, are the highest and lowest values of the function, either on the whole domain or within a specific range.

Therefore,

identify the fringe or fringes that result from the interference of two waves whose path difference differs by exactly 2λ2λ . enter the letter(s) indicating the fringe(s) in alphabetical order. for example, if you think that fringes a and c are both correct,

The waves that differ is:

Δx = 2λ

The equation for phase difference is:

The constructive interference is equal: ΔΦ = 2nπ

If

n = 0, central bright fringe

n = ±1, first maxima on both fringes

n = ±2, second maxima on both fringes

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Answer:

2800 N

Explanation:

Acceleration = change in velocity / change in time

                     =    14 m/s  /  7 s = 2 m/s^2

F = ma

 = 1400 (2) = 2800 N

Explanation:

Throughout this question, we will be taking the position at which the package is dropped as the origin.

We know that the package lands 100 m from the initial position. We have to investigate the position in the horizontal direction.

To do that, let's first calculate the time of flight of the package.

Here is what we know about the vertical motion taking the downward direction as the positive direction:

the vertical displacement is

s

=

100

m

.

the acceleration is

a

=

g

=

9.81

m

/

s

2

.

the initial velocity of the package is

u

=

0

m

/

s

.

By using an equation that connects the details that we have with the time of flight

t

, we get the time of flight as follows:

s

=

u

t

+

1

2

a

t

2

s

=

0

+

0.5

a

t

2

Make

t

the subject

0.5

a

t

2

=

s

t

2

=

s

0.5

a

t

=

√

s

0.5

a

=

√

100

m

0.5

(

9.81

m

/

s

2

)

≈

4.52

s

The horizontal displacement

x

equals the product of the horizontal velocity

v

x

=

40.0

m

/

s

and the time of flight

t

=

4.52

s

, i.e.

x

=

v

x

t

=

40.0

m

/

s

(

4.52

s

)

≈

181

m

The package will strike the ground at

(

181

m

;

−

100

m

)

.

Part b)

The horizontal component of the velocity is constant throughout the flight and is

v

x

=

40.0

m

/

s

.

For the downward motion, here is what we know:

the vertical displacement is

s

=

100

m

.

the acceleration is

a

=

g

=

9.81

m

/

s

2

.

the initial velocity of the package is

u

=

0

m

/

s

.

By applying an equation that combines the details that we have with the final instantaneous velocity

v

=

v

y

, we get the final instantaneous velocity as follows:

v

2

=

u

2

+

2

a

s

v

=

√

u

2

+

2

a

s

v

y

=

√

(

0

m

/

s

)

2

+

2

(

9.8

m

/

s

2

)

(

100

m

)

≈

44.3

m

/

s

The velocity vector at the instant the package just hits the ground is (40.0 m/s ; 44.3 m/s).

Part c)

At the instant that the plane hits the ground, the plane's position is (181 m ; 0 m): i.e. the plane is directly on top of the package and 100 meters above the ground. This is because horizontally, the plane and the package move with the same velocity.

Part d)

The vertical component of the velocity of the package increases at a steady rate. In fact, the rate or gradient is the acceleration

g

=

9.8

m

/

s

2

.

L = 24 + 12 + 6 + 3 + 1.5 + 0.75 + 0.375 + 0.1875 + ......+ 0.5X(n-1) expression gives the total length the monkey swings in her first n swings.

The first swing's length was 24 meters.

The monkey only covers half of the arc's length in each swing.

First, n swings' cumulative length equals?

Total swing length is equal to the initial swing's length plus 0.5 times that amount plus the next number of swings.

i.e., Total length of n swings = length of first swing + 0.5 X length of first swing + .....+ length of n swings

L = 24 + 12 + 6 + 3 + 1.5 + 0.75 + 0.375 + 0.1875 + ...

Therefore, the expression is

L = 24 + 12 + 6 + 3 + 1.5 + 0.75 + 0.375 + 0.1875 + ......+ 0.5X(n-1)

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Answer:

Positive: Proton, Negative: Electron, Neutral: Neutron

Explanation:

Option A) Since the p-value is greater than 0.05, we have no evidence that the sandwiches are not purchased similarly across all the four different states as per the statistical data.

A statistic, according to the Longman Dictionary of Contemporary English, is a person who has perished as a result of a specific type of accident or illness and is merely another statistic.

These things cannot be reduced to a statistic data.

In conclusion, there are a total of five reasons to study statistics. These are, to be able to conduct research efficiently, to read and evaluate journal articles, to further develop critical thinking and then also develop proper analytical skills, to act as an informed consumer, and to then recognize the times whenever you get the need to hire outside statistical help.

As per the question,

p = 0.7682

and thus, we have p > 0.05

And if p > 0.05 then we fail to reject the null hypothesis and results are not significant.

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The distance d between the golfer and point b where the ball first lands is 4933.17 ft

Initial velocity = 250.0ft/s

Launch angle ([tex]\theta[/tex]        )= 25°

slope angle([tex]\phi[/tex]) = 5°

Let d is the distance on the slope after which projectile lands

∴ horizontal distance covered by projectile

x = dcos[tex]\theta[/tex]

Vertical distance covered by projectile

y = dsin[tex]\theta[/tex]

now Considering horizontal motion

Initial horizontal velocity [tex]v_{x} = v cos25[/tex]

then position after time t

d cos5 = 250cos25×t

d = 227.44t          ---------1.

when we consider vertical motion then

Initial vertical velocity [tex]v_{y} = v sin25[/tex]

[tex]v_{y} = v sin\theta t-\frac{1}{2}gt^{2}[/tex]

-d sin5 = 250 sin25.t - gt²/2

-d = 1212.25t - 56.221 t²

1212.25t - 56.221 t² + d = 0         ----2

put value of d in equation 2

1212.25t - 56.221t² + 227.44t =0

t(1212.25+227.44 - 56.221 t) =0

t(1234.69 - 56.221 t) = 0

t = 21.96 ,t≠0

substitute the value of t in equation 1

d = 227.44t    

d = 227.44×21.96

d = 4933.17 ft

The distance d between the golfer and point b where the ball first lands is  4933.17 ft

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If a score in a distribution change in numerical value, it will necessarily change mean.

Increasing a current score: Changing one score into another will change the mean since every score in a distribution affects the mean’s value.

The mean will increase in value if an existing score is valued higher. The value of the mean will fall if an existing score’s value is reduced.

There are 50% of observations on either side of the median value, which divides the distribution in half.

The median value is the midpoint in distribution with an odd number of observations.

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Answer:Transverse waves cause the medium to move perpendicular to the direction of the wave.

Explanation:

In a transverse wave, particles of the medium vibrate up and down perpendicular to the direction of the wave. In a longitudinal wave, particles of the medium vibrate back and forth parallel to the direction of the wave.

The speed of the elevator, given that it travels a distance of 210 m in 35 s is 6 m/s

The formula for calculating the speed of an object is given as follow:

Speed = distance / time

Considering the question given above, we can obtain the speed of the elevator as follow:

Speed = distance / time

Speed = 210 / 35

Speed = 6 m/s

From the calculation made above, we can see that the speed of the elevator is 6 m/s

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[tex] \large \bf \implies{s = 200 \: m}[/tex]

The distance has the proton been deflected sideways when it reaches the far edge of the capacitor is [tex]1.08 * 10^-3[/tex].

What is parallel-Plate Capacitor:

When two parallel plates are connected across a battery, the plates are charged and an electric field is established between them, and this setup is known as the parallel plate capacitor.

The parallel plate capacitor formula is given by:

C = k∈0 A / d.

Now,

The electric field is, E = sigma/epsilon_{o} = (1 * 10 ^ - 6)/(8.85 * 10 ^ - 12) = 1.129 * 10 ^ 5 * N / C

The force on the proton is (F) = q E = 1.6 * 10 ^ - 19 * 1.129 * 10 ^ 3 = 1.81 * 10 ^ - 14 * N

So, the acceleration of the proton is,

a = F/m = (1.81 * 10 ^ - 14)/(1.67 * 10 ^ - 27) = 1.084 * 10 ^ 13 * m / (s ^ 2)

Time taken to cross the plate is (t) = d/u = (2.4 * 10 ^ - 2)/(1.7 * 10 ^ 6) = 1.41 * 10 ^ - 8

Therefore, the required distance travelled distance is,

d = u t + 1/2 * a * t ^ 2

d = 0 + 1/2 * 1.084 * 10 ^ 13 * (1.41 * 10 ^ - 4) ^ 2

d = 1.08 * 10 ^ - 3 * m

Therefore, the distance is 1.08*10^-3 m

A parallel-plate capacitor has 2.4 cm × 2.4 cm electrodes with surface charge densities ±1.0×10^−6C/m2. A proton traveling parallel to the electrodes at 1.4×10^6 m/s enters the center of the gap between them.

By what distance has the proton been deflected sideways when it reaches the far edge of the capacitor? Assume the field is uniform inside the capacitor and zero outside the capacitor

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The reaction force is string pulling on the Nellie when a tether ball in a horizontal circular path over her head .

A reaction force is a force that acts in the opposite direction to an action force. i.e. Newton's third law of motion describes action and reaction forces and the law states that for every action force, there is an equal and opposite reaction force.

There are Newton's three law of motion which can be describe as ,

The first law is can be stated as, an object will not change its motion unless a external force acts on it.

The second law is describe as, the force on an object is equal to its mass times its acceleration. i.e.

F = ma

In above equation F is force , m is mass and a is acceleration on an object.

The third law can be explained as, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Therefore , from the above discussion can be said as Nellie whirls a tether ball in a horizontal circulars path over her head. if the action force is nellie pulling on the string, the reaction force is string pulling on the Nellie.

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Answer:

H= Mass × specific heat capacity ×change in temperature

= 2×380×(10-0)

=2×380×10

=7600 Joules

The energy of a photon with wavelength of 410nm can be calculated as 4.85 x [tex]10^{-19}[/tex] j

Any energy unit, such as the electron volt (eV) or the joule (J), can be used to express photon energy.

P = F × E (equation 3)

P = F × hc/l (equation 4)

P (mW) is equal to 1.989 10-10 F/l (nm)

Ensure that your wavelength is expressed in meters.

The wavelength is multiplied by the speed of light, which is roughly 300,000,000 m/s, to determine the wave’s frequency.

Add the Planck constant, 6.626 1034 J/Hz, to the frequency.

The resulting figure represents a photon’s energy.

[tex]\lambda[/tex] = 410nm = 410 x 10^(-9).

E = hc/[tex]\lambda[/tex]  = [6.626 x 10^(-34) x 3 x 10^(8) ] / 410 x 10^(-19)

= 0.0485 x 10^(-17)

= 4.85 x 10^(-19)

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The power supplied by the gravitational force will increase because (Power=work/time).

A falling object gains momentum as it descends.

An increase in air resistance is caused by a speed increase.

At some point, the force of air resistance grows strong enough to counteract the pull of gravity.

Since there is no net force at this point, the object will stop accelerating.

Although the direction and magnitude of velocity fluctuate, the acceleration caused by gravity remains constant and downward.

The ball has zero velocity at the highest point in its trajectory, and it picks up speed as it descends back toward the earth.

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