Answer:
A campfire is an example of entropy. The solid wood burns and becomes ash, smoke and gases, all of which spread energy outwards more easily than the solid fuel. Ice melting, salt or sugar dissolving, making popcorn and boiling water for tea are processes with increasing entropy in your kitchen.
Explanation:
If this helped you, the please mark me the brainliest.
which type on bond is present in copper wire?
A. Covalent
B. Ionic
C Electrovalent
D. Metallic
Answer:
metallic bonding
Explanation:
Copper wire consists of Cu nuclei (that are positively charged due to the positively charged protons) that are surrounded by a "sea" of delocalized electrons (that are negatively charged that move freely throughout the material which is known as metallic bonding.
Answer:
Metallic bonding.
Explanation:
Pure copper is neither covalent nor ironic. It is a bonding called metallic bonding.
PLSSSSSSSSSS HELP!!! I REALLY NEED IT SO MUCH :( I PROMICE TO GIVE BRAINLIEST AND FIVE STARS AND A THANKS! 6TH GRADE SCIENCE! i used all my points for this! You measure the mass of an apple using a balance. You get these three measurements:
Trial 1: 167.0 g
Trial 2: 166.9 g
Trial 3: 167.2 g
You know that the true mass of the apple is 172 g. Describe your results in terms of precision and accuracy. Explain your answer.
Answer:
100 POINTS! (50 split up) PLSSSSSSSSSS HELP!!! I REALLY NEED IT SO MUCH :( I PROMICE TO GIVE BRAINLIEST AND FIVE STARS AND A THANKS! 6TH GRADE SCIENCE! i used all my points for this!
You measure the mass of an apple using a balance. You get these three measurements:
Trial 1: 167.0 g
Trial 2: 166.9 g
Trial 3: 167.2 g
You know that the true mass of the apple is 172 g. Describe your results in terms of precision and accuracy. Explain your answer in a paragraph for the best grade.
Explanation:
Loren is examining a hair found at a crime scene. He notes radical changes in the coloring of the hair. What is the term for this type of coloring?
Answer:
Granules of the hair cortex.
Explanation:
hope it helpfully...Answer:
It is banding for plato / edmentum
Explanation:
I took notes in the class and in my notes it says -
Human hairs have consistent coloring, whereas animal hair coloring may change radically. This radical change is called banding.
What would happen if we did not have an atmosphere?
Answer:
The air would still be too thin to breathe. The lack of atmosphere would chill the Earth's surface. Organisms that need air to breathe would die.
Explanation:
Hope it helped!
will give brainliest!! please help ! .. Calculate the total pressure of the mixture in atmospheres ( atm ).
Answer:
13.94 atm
Explanation:
From the question given above, the following data were obtained:
Pressure of H₂ = 2 atm
Pressure of NH₃ = 303 KPa
Pressure of CO₂ = 3000 mmHg
Pressure of N₂ = 3800 torr
Total pressure (Pₜ) in atm =?
Next, we shall convert 303 KPa, 3000 mmHg and 3800 torr to atm.
This can be obtained as follow:
Converting 303 KPa to atm
101.325 KPa = 1 atm
Therefore,
303 KPa = 303 KPa × 1 atm / 101.325 KPa
303 KPa = 2.99 atm
Thus, 303 KPa is equivalent to 2.99 atm.
Converting 3000 mmHg to atm
760 mmHg = 1 atm
Therefore,
3000 mmHg = 3000 mmHg × 1 atm / 760 mmHg
3000 mmHg = 3.95 atm
Thus, 3000 mmHg is equivalent to 3.95 atm
Converting 3800 torr to atm
760 torr = 1 atm
Therefore,
3800 torr = 3800 torr × 1 atm / 760 torr
3800 torr = 5 atm
Thus, 3800 torr is equivalent to 5 atm.
Finally, we shall determine the total pressure of the mixture as follow:
Pressure of H₂ (P₁) = 2 atm
Pressure of NH₃ (P₂) = 2.99 atm
Pressure of CO₂ (P₃) = 3.95 atm
Pressure of N₂ (P₄) = 5 atm
Total pressure (Pₜ) in atm =?
Pₜ = P₁ + P₂ + P₃ + P₄
Pₜ = 2 + 2.99 + 3.95 + 5
Pₜ = 13.94 atm
Therefore, the total pressure of the mixture is 13.94 atm
45 points! How much heat in Joules would it take to heat up a block of aluminum that weighs 1000.0 grams from a temperature of 70 degrees C, to it's melting point at 192.4C? specific heat for aluminum is .89 J/g-C. do not round answer- pls help
Answer:
1.1 × 10⁵ J
Explanation:
Step 1: Given data
Mass of the aluminum block (m): 1000.0 gInitial temperature: 70 °CFinal temperature: 192.4 °CSpecific heat for aluminum (c): 0.89 J/g.°CStep 2: Calculate the change in the temperature
ΔT = 192.4 °C - 70 °C = 122 °C
Step 3: Calculate the heat required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 0.89 J/g.°C × 1000.0 g × 122 °C
Q = 1.1 × 10⁵ J
Chlorine, iodine, and bromine are located near each other on the periodic table. Which of these elements is the atom with the highest first ionization energy?
Answer:
Chlorine has the highest amongst all of those
Ethylene glycol is the main component in automobile antifreeze. To monitor the temperature of an auto cooling system, you intend to use a meter that reads from 0 to 100. You devise a new temperature scale based on the approximate melting and boiling points of a typical antifreeze solution (-45oC and 115oC). You wish these points to correspond to 0oA and 100oA, respectively. What is a temperature of 45oC in oA
Answer:
X = 27 .
Explanation:
Centigrade scale : melting point O⁰C , boiling point 100⁰C
New scale melting point -45⁰C , boiling point 115⁰C
Formula relating the two scale
[tex]\frac{C- 0 }{100-0} =\frac{X-(-45)}{115-( -45) }[/tex]
[tex]\frac{C }{100} =\frac{(X+45)}{(115 +45) }[/tex]
[tex]\frac{C }{100} =\frac{(X+45)}{160}[/tex]
Given C = 45
X = ?
[tex]\frac{45 }{100} =\frac{(X+45)}{160}[/tex]
X + 45 = 72
X = 27 .
How many calories are required to heat 10 ml of water from -5 to 25 0C?
a. 110 cal.
b. 0.48 cal.
c. 300 cal.
d. 2.1 cal.
Answer:
c. 300 cal
Explanation:
To calculate the heat, we use the following equation:
heat = m x Cp x ΔT
Where m is the mass of water, Cp is the specific heat of water (which is 1 cal/g.°C) and ΔT is the change in temperature (calculated as the difference between the final T and the initial T).
We have the volume of water (10 ml) but not the mass. As the density of water is 1 g/ml, the mass of water is:
density = mass/volume ⇒ mass = density x volume = 1 g/ml x 10 ml = 10 g
The change in temperature (ΔT) is:
ΔT= Final T - Initial T = 25°C - (-5°C) = 30°C
Finally, we introduce the data to calculate the heat:
heat = 10 g x 1 cal/g.°C x 30°C = 300 cal
Therefore, the correct option is c. 300 cal
what are all the products of a hydrocarbon combustion reaction
Answer: carbon dioxide and water
Explanation: hydrocarbons are compounds of carbon and hydrogen. Combustion is another word for oxidation. Oxygen splits, the CH bonds, oxidising both the C and the H. The simplest hydrocarbons, the alkanes, have the general formula C(n)H(n+2)
The combustion reaction is
(3n+1)O2 + 2C(n)H(2n+2) —> 2nCO2 + (2n+2)H2O
The products of a complete combustion reaction of a hydrocarbon in the presence of sufficient oxygen are carbon dioxide ([tex]CO_2[/tex]) and water ([tex]H_2O[/tex]).
Carbon dioxide and water are the end products of a hydrocarbon's full combustion reaction when there is enough oxygen present. The general equation: can be used to express this reaction.
Hydrocarbon + Oxygen -> Carbon Dioxide + Water
For example, if we consider the combustion of methane ([tex]CH_4[/tex]), the equation would be:
[tex]CH_4 + 2O_2 - > CO_2 + 2H_2O[/tex]
Here, one molecule of methane reacts with two molecules of oxygen to produce one molecule of carbon dioxide and two molecules of water.
Thus, the specific products of a hydrocarbon combustion reaction depend on the hydrocarbon being burned.
For more details regarding combustion, visit:
https://brainly.com/question/31123826
#SPJ6
What is the final temperature of 630.1 g of water (specific heat = 4.18
J/g.°C) at 24.2°C that absorbed 950. J of heat?
Answer: Final temperature for given mass of water is [tex]24.6^o C[/tex].
Explanation:
Given: mass = 630.1 g, specific heat = 418 [tex]J/g^{o} C[/tex], q = 950 J, T = [tex]24.2^o C[/tex]
Formula used: [tex]q = mC \Delta T[/tex]
where, q = heat energy
m = mass
C = specific heat
[tex]\Delta T[/tex] = change in temperature = [tex](T_2 - T_1)[/tex]
950 J = [tex]630.1 g \times 4.18 J/g^o C \times (T_2 - 24.2^o)[/tex]
[tex]T_2 = 24.6^o C[/tex]
Answer:
T2 = 24.56°C
Explanation:
Given data:
Mass of water = 630.1 g
Specific heat of water = 4.18 J/g.°C
Initial temperature = 24.2°C
Heat absorbed = 950 J
Final temperature = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
by putting values
950 J = 630.1 g × 4.18 J/g.°C × (T2 - 24.2°C)
950 J = 2633.82 j/°C × (T2 - 24.2°C)
950 J / 2633.82 j/°C = (T2 - 24.2°C)
0.36°C + 24.2°C = T2
T2 = 24.56°C
in which way does a balanced chemical equation demonstrate the conservation of matter?
Answer:
Every chemical equation adheres to the law of every conservation of mass and the states of matter cannot be created or destroyed
Explanation:
How many grams of hydrogen gas would be required to produce 100.0 g H2O
Explanation:
11.11 grams of hysrogen is requited to make 100 g of water
HF(aq) and Ba(OH)2(aq) Express your answer as a balanced chemical equation. Identify all of the phases in your answer.
Answer:
[tex]2HF(aq)+Ba(OH)_2(aq)\rightarrow BaF_2(s)+H_2O(l)[/tex]
Explanation:
Hello!
In this case, since the neutralization reaction between hydrofluoric acid and barium hydroxide (both aqueous) produce insoluble barium fluoride and liquid water, we can write the chemical reaction as follows:
[tex]HF(aq)+Ba(OH)_2(aq)\rightarrow BaF_2(s)+H_2O(l)[/tex]
However, it needs to be balanced as hydrogen and fluorine are not properly balanced, therefore, we obtain:
[tex]2HF(aq)+Ba(OH)_2(aq)\rightarrow BaF_2(s)+H_2O(l)[/tex]
Best regards!
Help ASAP I will give you a brainliest
Answer:
light blue
Explanation:
the second one
can someone help I don't understand how to find the amount for the name.
Answer:
A) 6.023*10^23
B)6.023*10^22
Explanation:
AVAGADRO it would take nearly 1 mole of chalk so
1 mole of any substance contain 6.023*10^23 particles.
AVAGADRO it would take nearly 1 mole of ink to print so
1 mole of any substance contain 6.023*10^23 particles.
A sample of water is cooled from 45°C to 35°C by the removal of 84 Joules of heat. What is
the mass of the water?
Answer:
m = 2 g
Explanation:
Given data:
Initial temperature = 45°C
Final temperature = 35°C
Heat evolved = 84 j
Mass of water = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
specific heat capacity of water is 4.18 J/g.°C
ΔT = 35°C - 45°C
ΔT = - 10°C
84 j = m ×4.18 J/g.°C ×- 10°C
84 j = m × -41.8 J/g
m = 84 j / -41.8 J/g
m = 2 g
negative sign shows heat is evolved.
The the balanced equations to: solutions of lithium sulfate and potassium phosphate are mixed together to make lithium phosphate and potassium sulfate
Answer:
[tex]3Li_2SO_4+2K_3PO_4\rightarrow 2Li_3PO_4+3K_2SO_4[/tex]
Explanation:
Hello!
In this case, when lithium sulfate and potassium phosphate solutions are mixed to yield lithium phosphate and potassium sulfate, the following chemical equation comes up:
[tex]Li_2SO_4+K_3PO_4\rightarrow Li_3PO_4+K_2SO_4[/tex]
However, as atoms are not balanced we apply the inspection method to obtain:
[tex]3Li_2SO_4+2K_3PO_4\rightarrow 2Li_3PO_4+3K_2SO_4[/tex]
Best regards!
A student pours some water into a plastic bag, seals the bag, and
places it in the freezer. Which aspect of the water molecules is the
same before and after freezing takes place?
5 of 11 QUESTIONS
Their speed
O Their number
O Their arrangement
O Their ability to move
Answer:
Their number
Explanation:
Freezing is the process of decreasing the activity of the molecules in the medium and their arrangement will change to take on the new shape but no new molecules are added or taken away
If you have 9.3×1026 molecules of iron that rusts, how many molecules of oxygen does it take?
__Fe + __O2 à __Fe2O3
Answer:1.395x10^27 molecules of O2
Explanation:
2Fe + 3/2O2 —> Fe2O3
for every 2 atoms of Fe, 1.5 molecules of O2 —> 1.395x10^27
Not all elements readily fit in the metal or non metal groupings. These elements are called metalloids. Examine the table below and classify W, X and Y as metals, metalloids or non-metals.
W= Lustre: Moderately high
Electrical conductivity: Low
Density: Medium
Melting point: Very high
X= Lustre: Low
Electrical conductivity: Nil
Density: Low
Melting point: Low
Y= Lustre: High
Electrical conductivity: High
Density: High
Melting point: High
help put them in order
Answer:
hello
Explanation:
hi
If a compound has 24.0g of carbon, 6.0g of hydrogen, and 16.0g of oxygen what is its
empirical formula?
Answer:
CH2
Explanation:
What is the empirical formula of a compound that contains 20.0g carbon and 3.37g hydrogen? Divide by the smallest number of moles. The empirical formula is CH2.
Which statement correctly describes the actual yield and the theoretical yield of a reaction? (1 point)
The actual yield is calculated from the reactant amounts, but the theoretical yield must be measured for each instance of a reaction
The actual yield is calculated from the amount of the limiting reactant, and the theoretical yield is calculated from the amount of the excess
The actual yield depends on the reaction conditions, but the theoretical yield varies only with reactant amounts.
The actual yield represents the maximum yield possible, and the theoretical yield assumes perfect reaction conditions.
Answer:
C: The actual yield depends on the reaction conditions, but the theoretical yield varies only with reactant amounts
Explanation:
Looking at the options, the correct one is Option C because the actual yield usually depends on the conditions of the reaction, while the theoretical yield usually varies with only the amount of reactant.
More accurate dates of the reigns of ancient Egyptian pharaohs have been determined recently using plants
that were preserved in their tombs. Samples of seeds and plant matter from King Tutankhamun’s tomb have
a C-14 decay rate of 9.07 disintegrations/min/g of C. How long ago did King Tut’s reign come to an end?
Please show how to achieve the answer. I do not know how to get the answer of 3350 years. Please explain what equations
King Tut's reign came to an end at 3350 years ago
Further explanationCarbon-14 is a radioactive isotope that can decay. This isotope can be used to determine how long ago an organism died by knowing the ratio from 12C to 14C
Can be formulated
[tex]\tt Nt=No\dfrac{1}{2}^{t/t1/2}[/tex]
Or we can use :
[tex]t=-\frac{1}{\lambda }\text{ln}\left(\frac{{N}_{t}}{{N}_{0}}\right)\longrightarrow t=-\frac{1}{\lambda }\text{ln}\left(\frac{{\text{Rate}}_{t}}{{\text{Rate}}_{0}}\right)[/tex]
The half-life of C-14, 5730 years, so the decay constant :
[tex]\tt \lambda =\dfrac{\text{ln 2}}{{t}_{1\text{/}2}}=\dfrac{0.693}{\text{5730 y}}=1.21\times {10}^{-4}}[/tex]
Assume the initial C-14 activity was 13.6 disintegrations/min/g of C
[tex]\tt t=-\dfrac{1}{\lambda }\text{ln}\left(\dfrac{{\text{Rate}}_{t}}{{\text{Rate}}_{0}}\right)=-\dfrac{1}{1.21\times {10}^{-4}}\text{ln}\left(\dfrac{9.07}{13.6}\right)=\text{3348}\approx 3350~y[/tex]
A solution of potassium sulfate dissolved in 750 g of phenol boils at 183.5 degrees Celsius. What is the molal concentration of the solution. Phenol boils at 181.8 degrees Celsius.
A. 0.48 m
B.0.34 m
C.0.21 m
D.0.16 m
Answer:
D.
Explanation:
Yan Lang po Alam ko
Fill in the blanks with the correct words to complete the sentence.
Answer:
Explanation:
Salt water intrusion can cause the fresh water in wells to become contaminated with saltwater.
There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, salt water intrusion can cause the fresh water in wells to become contaminated with salt water.
What is chemical Compound?Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.
An ionic compound is a metal and nonmetal combined compound. Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.
The compound that is ionic in nature can be dissociated very easily in water. Since ionic compounds are polar in nature, they readily dissolve in water. Salt water intrusion can cause the fresh water in wells to become contaminated with salt water.
Therefore, salt water intrusion can cause the fresh water in wells to become contaminated with salt water.
To learn more about chemical compound, here:
brainly.com/question/26487468
#SPJ2
Identify the following measurements as being either Pressure ( P) , Volume ( V) , or temperature ( T) . will give brainliest !
Answer:
The answers to your questions are given below
Explanation:
To successfully answer the questions given above, it is important that we know the various units of measurement of volume, pressure and temperature respectively.
For Volume:
Some measuring units of volume include:
1. Litre (L)
2. Millilitre (mL)
3. Cubic centimetres (cm³) etc
For Pressure:
Some measuring units of pressure include:
1. Atmosphere (atm)
2. Millimetres of Mercury (mmHg)
3. Torr
4. Pascal (Pa)
5. Kilo pascal (KPa) etc
For Temperature:
Some measuring units of temperature include:
1. Kelvin (K)
2. Degree Celsius (°C)
3. Degree Fahrenheit (°F)
Now, we shall answer the questions given above as follow:
A. 56 °C => Temperature
B. 247.3 KPa => Pressure
C. 23.3 mL => Volume
D. 298 K => Temperature
E. 1.24 atm => Pressure
F. 482 torr => Pressure
G. 0.50 L => Volume
H. 120.9 mmHg => Pressure
sodium atoms differ from sodium ions in that sodium atom contains
1. one less proton
2. one less proton
3. one more electron
4. one less electron
Explanation:
sodium atom is neutral while sodium ion is a charged specie with a charge of +1
) Calculate the pH of a polyprotic acid given and sketch the titration curves for the following reactions: (a) A 20.0-mL aliquot of 0.100M arsenic acid, H3AsO4, with 0.100M NaOH
Answer:
Following are the solution to the given question:
Explanation:
Let us indicate H3AsO4, an H3A triprotic acid; the ionising equations are as follows:
[tex]\to H_3A \Leftrightarrow H^+ + H_2A^- \\\\[/tex]
[tex]\to Ka_1 = \frac{[H^+][H_2A^-]}{[H_3A]}[/tex]
[tex]= 10-2.2 = 6.31 \times 10^{-3} \ \ \ \ \ \ \ \ [since\ pKa_1 = 2.2\ and \ Ka = -\log_{10}(pKa)]\\[/tex]
[tex]\to H_2A^{-} \Leftrightarrow H^{+} + HA_2^{-}; \\[/tex]
[tex]\to Ka_2 = \frac{[H^+][HA_2^-]}{[H_2A^-]} = 10-6.8 = 1.58 \times 10^{-7} \\(since pKa2 = 6.8)\\\\\to HA_2^- \Leftrightarrow H^+ + A_3^- ;\\\\ \to Ka_3 = \frac{[H^+][A_3^-]}{[HA_2^-]} = 10-11.6 = 2.51 \times 10^{-12} \\ (given pKa_3 = 11.6)[/tex]
The initial pH; we've 0.00 mL of 0.100 M NaOH – H3A is the main species; Ka1>>Ka2>>Ka3 is also noted. They therefore ignore H2A's disconnection but set up next ICE chart.
[tex]\to H_3A \Leftrightarrow H^+ + H_2A^- \\\\[/tex]
[tex]initial \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.100 \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \\\\[/tex]
[tex]change \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ - x \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ + x \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ + x\\\\equilibrium \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (0.100 - x) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x\\\\[/tex]
[tex]Ka_1 = \frac{[H^+][H_2A^-]}{[H_3A]} = \frac{(x)(x)}{(0.100 - x)}[/tex]
[tex]\text{x to be much smaller than 0.100 M}\\\\to 6.31 \times 10^{-3} = \frac{x^2}{0.100}\\\\\to x^2 = 6.31 \times 10^{-4}\\\\ \to x = 0.025\ M\\\\\to pH = -\log_{10}[H^+] = -\log_{10}(0.025) = 1.60[/tex]