Answer:
Create
Broken
Explanation:
Bond formation or creation requires the use of energy. Energy is used during bond formation between chemical species. The energy is required for the reaction to occur.
When bonds are broken, energy is releasedBond breaking process is a procedure that releases energy. This energy makes them able to react.the traits of friends
Answer:
someone you trust the most
Explanation:
The planes LA534 and LA639 are coming in for a landing on the same runway which means they are each lowering their altitude. Note that LA534 is traveling at twice the speed of LA 639. What must they do to keep from crashing into each other on the runway
Answer:
plane LA534 will have to decrease it speed by twice that of plane LA639.
Explanation:
Since both planes want to land there must be a decrease in speed.
We are told that plane LA534 velocity is twice that of plane LA639.
Now for the two planes to land without a crash. the opposite or reverse will be the case in terms of deceleration, that is
Plane LA639 will have to decrease its speed by twice the decrease in speed of plane LA534
A ball rolling on the ground has what form of energy?
A. KE
B. Chemical
C. PE
D. None
Answer:
a kinetic energy
Explanation:
because it is moving
El cloro (Z igual a 17) es un elemento utilizado generalmente en la desinfección de piscinas en la naturaleza hay 2 isótopos del cloro: el Cl-35, con una abundancia del 75% y el Cl-37 con una abudancia del 25%. Determina : a)los protones y los neutrones que hay en el nucleo de cada uno de estos isotopos b) la masa atomica media del cloro expresada en u c) el numero de atomos de cloro que hay en 15g de cloro
Answer:
a) El número de neutrones de Cl-35 es 18 y del Cl-37 es 20.
b) La masa atómica media del cloro es 35.5 uma.
c) En 15 g de cloro hay 2.55x10²³ átomos.
Explanation:
a) Para calcular los protones y neutrones de los isótopos Cl-35 y Cl-37 debemos usar la siguiente fórmula:
[tex] A = Z + N [/tex]
En donde:
Z: es el número de protones = 17
N: es el número de neutrones
A: es la masa atómica
Los isótopos de un elemento dado tienen el mismo número de protones (número atómico) y en ellos sólo varia la la masa atómica (y por ende el número de neutrones); por lo que el Cl-35 y Cl-37 tienen igual Z (17).
Para el Cl-35 tenemos:
[tex] N = A - Z = 35 - 17 = 18 [/tex]
Y para el Cl-37 tenemos:
[tex]N = 37 - 17 = 20[/tex]
Por lo tanto, el número de neutrones de Cl-35 es 18 y del Cl-37 es 20.
b) La masa atómica media del cloro está dada por:
[tex]M_{Cl} = A_{Cl-35}*\%_{Cl-35} + A_{Cl-37}*\%_{Cl-37} = 35 u*\frac{75}{100} + 37 u*\frac{25}{100} = 35.5 u[/tex]
Entonces, la masa atómica media del cloro es 35.5 uma.
c) Para encontrar el número de átomos de Cl que hay en 15 g debemos usar el número de Avogadro (6.022x10²³ átomos/mol):
[tex] N = \frac{1 mol}{35.5 g}*15 g*\frac{6.022 \cdot 10^{23} atomos}{1 mol} = 2.55 \cdot 10^{23} atomos [/tex]
Finalmente, en 15 g de cloro hay 2.55x10²³ átomos.
Espero que te sea de utilidad!
diffrence uniform and non uniform
A catapult with a spring constant of 10,000 N/m is used to launch a target from the deck of a ship. The spring is compressed a distance of 0.5 m
before the 1.56-kg target launched. What is the target's velocity as it leaves the spring?
Please help.
(A) 10m/s
(B) 20m/s
(C) 40m/s
(D) 30m/s
Answer:
(C) 40m/s
Explanation:
Given;
spring constant of the catapult, k = 10,000 N/m
compression of the spring, x = 0.5 m
mass of the launched object, m = 1.56 kg
Apply the principle of conservation of energy;
Elastic potential energy of the catapult = kinetic energy of the target launched.
¹/₂kx² = ¹/₂mv²
where;
v is the target's velocity as it leaves the catapult
kx² = mv²
v² = kx² / m
v² = (10000 x 0.5²) / (1.56)
v² = 1602.56
v = √1602.56
v = 40.03 m/s
v ≅ 40 m/s
Therefore, the target's velocity as it leaves the spring is 40 m/s
Do you always need
more than one reactant
or more than one
product to have a
chemical reaction?
Answer:
no
Explanation:
HELP ASAP ILL DO ANYTHING.!!!!!!
Why does ice cream melt when you are holding it in a cone but not when it is sitting
in the freezer? Answer in terms of particles.
Answer: the heat from the environment melts the ice cream. When it’s in the freezer it doesn’t melt because both the freezer and ice cream are the same temperature
Explanation:
Answer:
the freezer and the ice cream is at the same temp while your hand and the cone is warmer so he heat from the cone transfers to the ice cream and heat it up and its particles move faster as it changes from a solid to a liquid.
You can add an easy question and give me some points if you would like!
PLS HELP THIS IS DUE IN TWO HOURS
Answer:
C
Explanation:
How does the law of conservation of mass apply to this reaction: C2H4 + O2 → 2H2O + 2CO2?
Answer:
The equation needs to be balanced. There are fewer oxygen atoms in the equation than hydrogen or carbon. ... There is an equal number of each element on both sides of the equation.
Explanation:
Which of the following describes the acceleration of an object with constant velocity?
a) Negative acceleration
b) Positive acceleration
c) Not enough acceleration to tell
d) No acceleration
Please help I will give brainliest
Answer:
ask questions that the findings bring up
Explanation:
hope this helps :)
Answer:
ask questions that the findings bring up
Connor is the paper
football champion of
all of Black Middle
School. If he thumps a
paper football with an
initial velocity of 3.0
meters per second at
an angle of 30
degrees, how far will
the football travel?
Explanation:
First we have to descompose velocity, and get Velocity of X and Y side:
Vx = V * cos 30°
Vx = 3 m/s * 0,866...
Vx = 2,598 m/s
Vy = V * sen 30°
Vy = 3 m/s * 0,5
Vy = 1,5 m/s
Lets calculate time of fly:
Firat, lets calulate up time:
uT = (Fv - Iv) / g
uT = (0 m/s - 1,5 m/s) / -9,8 m/s^2
uT = -1,5 m/s / -9,8 m/s^2
uT = 0,15 s
Like up time is equal to down time, time of fly will be:
T =uT + dT
T = 0,15 s + 0,15 s
T = 0,3 s
Now for calculate how far will reach, lets aplicate the formula:
d = Vx * T
d = 2,598 m/s * 0,3 s
d = 0,779 meters
Will reach 0,779 meters
Gud luck
Miguel's parents drove him to a track meet that was 305 km away from the school. It took them 3 hours, which included a 30 minute break for breakfast. What was their average speed?
A.101.7 km/h
B.915 km/
C.122 km/h
D.275 km/h
I have a really long assignment I don't understand! please help
I can try and help whats it about?
At which point does the image appear?
W
X
Y
Z
Un gas ideal ocupa un volumen de 4.00 m3 a una presión absoluta de 200 kPa. ¿Cuál será la nueva presión si el gas es comprimido lentamente hasta 2.00 m3 a temperatura constante?
Given :
Initial pressure, [tex]P_i=200\ kPa[/tex].
Initial volume, [tex]V_i= 4\ m^3[/tex].
Final volume, [tex]V_f = 2 \ m^3[/tex].
To Find :
Final pressure, [tex]P_f[/tex].
Solution :
We know, at constant temperature :
[tex]P_iV_i=P_fV_f\\\\P_f=\dfrac{P_iV_i}{V_f}\\\\P_f=\dfrac{200\times 4}{2}\\\\P_f=400\ kPa[/tex]
Therefore, new pressure is 400 kPa.
Hence, this is the required solution.
At a local swimming pool, the diving board is elevated h = 9.5 m above the pool's surface and overhangs the pool edge by L = 2 m. A diver runs horizontally along the diving board with a speed of v0 = 2.7 m/s and then falls into the pool. Neglect air resistance. Use a coordinate system with the horizontal x-axis pointing in the direction of the diver’s initial motion, and the vertical y-axis pointing up. Let the y-axis be directed vertically down. Express the time t_w it takes the diver to move off the end of the diving board to the pool surface in terms of v_0, h, L, and g. Calculate the time, t_w in seconds, it takes the diver to move off the end of the diving board to the pool surface. Determine the horizontal distance, d_w in meters, from the edge of the pool to where the diver enters the water.
Answer:
1) The time it takes the diver to move off the end of the diving board to the pool surface, [tex]t_w[/tex], is approximately 1.392 seconds
2) The horizontal distance from the edge of the pool to where the diver enters the water, [tex]d_w[/tex], is approximately 5.76 meters
Explanation:
1) The given parameters are;
The height of the diving board above the pool's surface, h = 9.5 m
The length by which the diving board over hangs the pool L = 2 m
The speed with which the diver runs horizontally along the diving board, v₀ = 2.7 m/s
Taking [tex]t_w[/tex] = The time it takes the diver to move off the end of the diving board to the pool surface
Therefore, we have from the equation of free fall;
h = 1/2 × g × [tex]t_w[/tex]²
Where;
g = The acceleration due to gravity = 9.81 m/s²
Substituting the values, gives;
9.5 = 1/2 × 9.81 × [tex]t_w[/tex]²
[tex]t_w[/tex] = √(9.5/(1/2 × 9.81)) ≈ 1.392 s
The time it takes the diver to move off the end of the diving board to the pool surface = [tex]t_w[/tex] ≈ 1.392 s
2) The horizontal distance, [tex]d_w[/tex], in meters from the edge of the pool to where the diver enters the water is given as follows;
[tex]d_w[/tex] = L + v₀ × [tex]t_w[/tex] = 2 + 2.7× 1.392 ≈ 5.76 m
∴ The horizontal distance from the edge of the pool to where the diver enters the water ≈ 5.76 meters.
Does water pressure depend on the total amount of water present?
(Will pick brainliest)
Answer:
No, because pressure is determined by force and the area over which that force acts.
Explanation:
Hi there can you guys please help me write 2 paragraphs (4-6 sentences) about in article ("How Many Sets & Reps Should I Do? (Building the Correct Workout Plan)" (Links to an external site.)
Answer:
well, to create the correct workout plan I think the first day you should do as many reps as you can for each muscle you are targeting. you should also have a day you rest so your body's muscles can build. Monday, Wednesday, Friday are your workout days. Tuesday, Thursday, and Saturday are your rest days. And Sunday can be anything whether it's going to the gym, yoga, or another rest day. But back to the reps, the days you do reps, each day you should be trying to get one more rep/set than the last. If a person is new to working out then they should have a goal of ten rep/sets or something like that, so they don't overwork themselves or tear a muscle. I don't really have any other ideas for a workout plan besides just trying to be consistent and not overworking yourself, but I hope this helps. <3
Explanation:
You'll have to add on your own ideas to make it longer and add a bit more detail of course but I think you'll do well.
NEED ASAP!! 23 POINTS!! Look at the pic above and tell me the velocity, distance and time. Thanks!
Answer:
Vp = 66.67 [mi/h]
Explanation:
To solve this type of problem we must remember that speed is defined as the relationship of space between time.
speed = distance/time
7)
v = speed = 100 [km/h]
distance = 750 [km]
time = distance/speed
time = 750/100
t = 7.5 [h]
8)
v1 = 200/3 = 66.67[mi/h]
v2 = 100/1.5 = 66.67 [mi/h]
Vp = average speed = (v1+v2/2)
Vp = (66.67 + 66.67)/2
Vp = 66.67 [mi/h]
answer is 9 Billion due to the decrease in Cactus
can u plz help
Define: Medium
Answer:
Medium: something in a middle position, maybe in between sizes big or small, or in a situation it's not negative or positive it's just neutral. (I'm sorry if that wasn't helpful)
Explanation:
Why work and energy both have same unit? Give reasons?
Answer:
Explanation:
both have same unit because energy is defined as the ability to do work and work is the measure of transfer of energy when an objects moved from one place to another place so both are same thats why both have same units
A satellite of mass 1000kg is in a circular orbit around a planet. The centripetal acceleration of the satellite in its orbit is 5m/s^2. What is the gravitational force exerted on the satellite by the planet?
A. 0N
B. 200N
C. 5000N
D. 10000N
Answer: 5000N
Explanation:
The basic principle of a circular orbit is that Fg = m × ac, so as we have the mass and the centripetal acceleration (also called normal acceleration) we just have to operate. Fg = 1000kg × 5m/s² = 5000N
The gravitational force exerted on the satellite of mass 1000 kg moving in a circular orbit with a centripetal acceleration of 5 m/s² by the planet is 5000 N (option C).
The gravitational force exerted on the satellite by the planet will be equal to the planet's gravity, which is equal to the centripetal force, so:
[tex] F_{g} = F_{c} = ma_{c} [/tex]
Where:
m: is the mass of the satellite = 1000 kg
[tex]a_{c}[/tex]: is the centripetal acceleration = 5 m/s²
The, the force acting on the satellite is:
[tex] F_{c} = ma_{c} = 1000 kg*5 m/s^{2} = 5000 N [/tex]
Therefore, the gravitational force exerted on the satellite by the planet is 5000 N (option C).
Learn more here:
https://brainly.com/question/11332442?referrer=searchResultshttps://brainly.com/question/24783651?referrer=searchResultsI hope it helps you!
11. The professor who first
implemented a scientific approach in
order to investigate a problem, and
who is often referred to as ‘the father
of scientific methodology’, is:
a. Galileo
b. Democritus
c. Newton
d. Einstein
12. Which of the following adjustments
to a pendulum would affect the
period of oscillation?
a. Increasing the mass
b. Decreasing the length
c. Increasing the length
d. Increasing the angle of
displacement
13. The width of a desk was measured
using a meter ruler, which of the
following is the most appropriate
reading expressing the result?
a. 0.724 m
b. 0.7248 m
c. 0.72 m
d. 72 cm
Answer:Newton
Explanation:
Un automóvil se mueve hacia el norte siguiendo una trayectoria rectilínea con una velocidad constante, recorre 195 Km cada 1.3 h. ¿Calcula la velocidad con que se mueve?
Answer:
La velocidad con la que se mueve el automóvil es 150 [tex]\frac{km}{h}[/tex]
Explanation:
La velocidad es una magnitud que expresa la relación entre el espacio recorrido por un objeto, el tiempo empleado para ello y su dirección.
Es decir, la velocidad se define como la relación que se establece entre la distancia recorrida y el tiempo transcurrido en el movimiento de un móvil.
Se puede calcular la magnitud de la velocidad utilizando la siguiente expresión:
[tex]velocidad=\frac{distancia}{tiempo}[/tex]
En este caso:
distancia= 195 kmtiempo= 1.3 hReemplazando:
[tex]velocidad=\frac{195 km}{1.3 h}[/tex]
Resolviendo:
velocidad=150 [tex]\frac{km}{h}[/tex]
La velocidad con la que se mueve el automóvil es 150 [tex]\frac{km}{h}[/tex]
One particle has a charge of -1.87 x 10-9C, while another particle has a
charge of -1.10 x 10-9 C. If the two particles are separated by 0.05, what is
the electromagnetic force between them? The equation for Coulomb's law is
Fe = kqjge, and the constant, k, equals 9.00 x 10-9 Nm2/C2,
A. 7.41 x 10-6N
B. -7.41 x 10-6N
C. 3,70 x 10-7N
O
D. -3,70 x 10-7N
Answer:
7.41 x 10⁻²⁴ N
Explanation:
F = (K x the charges of the two particles)/ the square of the distance which is 0.05.
The answer is not here but it seems two of the options are the same so I'll assume its A since the answer isn't negative
Answer:
A
Explanation:
just did it
{hope it helps <3 }
A block of mass 3 kg is pushed 1 m along a frictionless horizontal table by a constant 16 N force directed 34◦ below the horizontal. Determine the work done by the applied force. Answer in units of J.
please help i'm a struggling physics student. Thanks so much!
Answer:
W = 13.26 [J]
Explanation:
Work in physics is defined as the product of force by the distance traveled by the object.
It is important to clarify that the force should be parallel to the direction of movement. In this way, we have to decompose the force into the X component of the movement.
Fx = 16*cos(34) = 13.26 [N]
W = F*d
where:
F = force = 13.26 [N]
d = distance = 1 [m]
W = 13.26*1
W = 13.26 [J]
Answer:
the guy above me is correct
Explanation:
What is the function of hammer and anvil in human ear
Answer:
Vibrations of the eardrum are in turn translated into oscillations of tiny bones (ossicles) found within the middle ear. The Hammer, Anvil, and Stirrup magnify the oscillations and relay this information to the chamber of the inner ear.
Answer:
The Hammer, Anvil, and Stirrup magnify the oscillations and relay this information to the chamber of the inner ear.
What is the Net Force acting
on the box below?