Help with basic algebra problem! Show the steps please!!!! Will give brainliest!!

Answer:

the value of 5 in 635,482 is 5,000

Step-by-step explanation:

to determine the place value of 5 you would have to start from the left to the right.

Answer:

Given the length of all 3 segments is 38, we are counting two-thirds of 38. You would find this by multiplication.

Step-by-step explanation:

Conversion to improper fractions/Simplification

[tex]\frac{38}{1} \times \frac{2}{3} = \frac{76}{3}\\\\\frac{76}{3} = 76 \div 3 = 25\frac{1}{3}[/tex]

Therefore, HN = [tex]\sf 25\frac{1}{3}[/tex]

3[tex]x^{-1}[/tex] = 72 => x = 0.4167, by basic algebra.

Given: 3[tex]x^{-1}[/tex] = 72

=> [tex]x^{-1}[/tex] = [tex]\frac{72}{3} =[/tex] 24

=> [tex]\frac{1}{x}=24[/tex]

=> x = 0.4167

Hence, 3[tex]x^{-1}[/tex] = 72 => x = 0.4167, by basic algebra.

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Answer:

Step-by-step explanation:

a = g - b - c

x = (n - p)7n

Answer:

Check options down below!

Step-by-step explanation:

If solving for n:

n = -m/2 - 5/6

If solving for m:

m = -2n - 5/3

If the expression is log₃9x⁵,then the expanded form of this expression is [tex]log_{3}[/tex]9 +5[tex]log_{3}[/tex]x.

Given that the expression is log₃9x⁵.

We are required to find the expanded form of the expression.

Product property of logarithms says that the logarithm of a product is equal to a sum of logarithms and because logs are exponents, and we multiply like bases, we can add the exponents.

The expression is log₃9x⁵.

log₃9x⁵=is [tex]log_{3}[/tex]9 +[tex]log_{3}[/tex][tex]x^{5}[/tex]

= [tex]log_{3}[/tex]9 +5[tex]log_{3}[/tex]x

Hence if the expression is log₃9x⁵,then the expanded form of this expression is  [tex]log_{3}[/tex]9 +5[tex]log_{3}[/tex]x.

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Answer:

A

Step-by-step explanation:

each step has added one extra side you might have trouble thinking it’s d but the pattern is x color (I’m colorblind) blue x blue so your answer is a

Both numbers are rational numbers, so the correct answer is (C).

So,

39/7 is already a rational number as it is already in a fraction with a denominator not equal to zero.

Therefore, both numbers are rational numbers, so the correct answer is (C).

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According to the given solving we can say that both numbers are rational.

The correct option is C.

The ratio or fraction among two numbers, p/q, where both p and q are the numerator and denominator, respectively, can be expressed as a rational number. For example, 3/7 and any integer represent rational numbers..

Rational numbers can really be expressed as ratios (such P/Q and Q0), while irrational numbers can indeed be expressed as a fraction. Both of these numbers, nevertheless, are real and can be displayed on a number line.

39/7 and-0.3287

The decimal number as a fraction:

0.3287  = 0.3287/1

this can be written as:

[tex]\frac{0.3287}{1}[/tex] x [tex]\frac{1000}{1000}[/tex]  = [tex]\frac{3287}{1000}[/tex]

So we can say that:

-0.3287 = [tex]\frac{-0.3287}{1000}[/tex]

According to the given solving we can say that both numbers are rational number.

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Write 2 and 32 as a product of their prime factors then in index form. 2 = 2^1. 32 = 2x2x2x2x2 = 2^5. Use power rule (a^m)^n = a^mn to simplify:

32= 2^5

2= 2^1

(2^1)^1/2 x (2^5)^1/2 = 2^1/2 x (2^4/2x2^1/2)

2^1/2x4x2^1/2 = 4 x (2^1/2) ^2 = 4x2 = 8

=8

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Answer: $4.8

Step-by-step explanation:

80*0.06=4.8

Answer:

AWSOME IMAGE!

Step-by-step explanation:

You make it??!!!

Answer: AIght thx for the points

Step-by-step explanation:

Answer:

It would be 5^3 or 5 cubed.  Power a is 3

Step-by-step explanation:

Answer:

b) 16

c) 3

Step-by-step explanation:

b)

[tex](10 - 3 \times 2)^2\\\to (10 - 6)^2\\\to 4^2 \to 16[/tex]

c)

[tex]5^a = 125\\\to 5^a = 5^3\\\to a = 3[/tex]

since we know both triangles are similar then we can say that

[tex]\cfrac{TV}{QS}~~ = ~~\cfrac{TU}{QR}\implies \cfrac{x}{30}~~ = ~~\cfrac{13}{39}\implies 39x=390\implies x=\cfrac{390}{39}\implies \boxed{x=10}[/tex]

The measures of the angles are

1. Angle TLN, MZQ and NLM

The angles TLN and NLM are supplementary angles

So, we have

TLN + NLM = 180

This gives

3x - 18 + y = 180

Also, we have

TLN + MZQ = 180

So, we have

3x - 18 + 5x + 14 = 180

Evaluate the like terms

8x -4 = 180

This gives

8x = 184

Divide

x = 23

Substitute x = 23 in 3x - 18 + y = 180

3 x 23 - 18 + y = 180

Evaluate

51 + y = 180

So, we have

y = 129

The above computations imply that:

TLN = 3 x 23- 18 = 51 degrees

NLM = y = 129 degrees

MZQ = 5 x 23 + 14 = 129 degrees

2. Angle JZQ and TLN

The above means that

JZQ = TLN

So, we have

9x + 9 = 8x + 19

Evaluate

x = 10

So, we have

JZQ = TLN = 9 * 10 + 9

JZQ = TLN = 99 degrees

3. Angle ZMR, LMO and LMR

The angles ZMR and LMO are congruent angles

So, we have

ZMR = LMO

This gives

x + 14 = 2x - 6

Evaluate

x = 20

Also, we have

LMR + LMO = 180

So, we have

y + 2x - 6 = 180

y + 2 x 10 - 6 = 180

y + 14 = 180

So, we have

y = 166

The above computations imply that:

LMO= ZMR = 20 + 14 = 34 degrees

LMR = y = 166 degrees

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The given expressions and their verbal descriptions (meaning) are as follows;

The given mathematical expressions and their correct verbal expressions or meaning are as follows;

2•(x - 3) can be described as two times or twice the difference between x and 3

[tex]x + \frac{3}{4} [/tex]

The above mathematical expression can be described as three fourths added to x, which is the same as; three fourths more than x.

'5 + x' can be described as the sum of five and x, which is the same as the sum of five and the number, x.

[tex] \frac{3}{4} \cdot x[/tex], The expression means the product of three fourths and x, which is the same as three fourths part of x.

5 - x can be written as the difference between five and x, which is the same as five less x

x - 5 can be written as the difference between x and 5, which means a number that is 5 less than x

2•x - 3 can be written as two times x minus three, which can be described as twice x minus three

[tex] \frac{5}{x} [/tex] can be written as fI've divided by x. which can be written as the quotient of 5 and x

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Answer to this question is:

Domain of given function is (-∞,-1)∪(-1,0)∪(0,∞),{x|x≠0,-1}

Range of given function is (-∞,0)∪(0,∞),{y|y≠0}

Inverse of given function  does not exist

The domain is all values of x that make the expression defined.The entire range of independent variable values is the domain of a function.

This definition can be stated simply as follows: The domain is the collection of all x-values that can be used to make the function "work" and produce actual y-values.

When choosing the domain, keep in mind that a fraction's denominator (bottom) cannot be 0.

Interval Notation:(-∞,-1)∪(-1,0)∪(0,∞)

Set-Builder Notation:{x|x≠0,-1}

The set of all valid y values constitutes the range..Graph may be used to find the values.

Interval Notation:(-∞,0)∪(0,∞)

Set-Builder Notation:{y|y≠0}

For calculation of inverse:

There is no inverse for any function that is not strictly monotonic. Whenever the first derivative of a function is ALWAYS zero, positive, or ALWAYS negative, the function is said to be monotonic. Basically, a function does not have an inverse function if there are two inputs for which the output is the same.

∴Domain of given function is (-∞,-1)∪(-1,0)∪(0,∞),{x|x≠0,-1}

Range of given function is (-∞,0)∪(0,∞),{y|y≠0}

Inverse of given function does not exist.

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The inverse function of the function y = log₂ 4x is f ⁻¹(x) = 2ˣ/4.

Given the function is :

y = log₂4x

we are asked to find the inverse of the function.

steps to find inverse function are:

now interchange the positions of x and y in the function.

x = log₂4y

the next step is to isolate the dependent variables.

f ⁻¹(x) = 2ˣ/4

hence, we get the inverse of the given function as f ⁻¹(x) = 2ˣ/4

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Answer:

press the stars.

Step-by-step explanation:

Answer: y = 25x + b

Step-by-step explanation:

The length and distance across the canyon is 5196.15 feet and it is more than 1 mile.

a) To find the length of canyon, we will sine function. As per the sine theta = length of opposite side ÷ hypotenuse. Keep the values in formula to find the hypotenuse, which is the length of the canyon wall.

sin 60 = 4500 ÷ hypotenuse

Hypotenuse = 4500 ÷ (✓3/2)

Hypotenuse = 4500 × 2 ÷ ✓3

Hypotenuse = 9000 ÷ ✓3

Hypotenuse = 5196.15 feet

The length of the canyon wall is 5196.15 feet.

b) To find the distance across the canyon, we will use cosine function. As per the cos theta = base ÷ hypotenuse. Keep the values in formula to find the base, which is half the length of the distance across the canyon.

cos 60 = base ÷ 5196.15

cos 60 × 5196.15 = base

Base = (1/2) × 5196.15

Base = 2958.075 feet

Total distance across the canyon = 2958.075 + 2958.075

Tota distance across the canyon = 5196.15 feet

c) Using the relation, 5280 feet = 1 mile

5196.15 feet = 5196.15 ÷ 5280 mile

5196.15 feet = 1.12 miles

So, distance across the canyon is more than 1 mile.

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Answer:

Not enough info.

Step-by-step explanation:

The result of simplifying each number 10¹/₂ . 10¹/₂ using the exponent rules is 10

To solve this exercise we have to resolve algebraic operations following the exponent rules.

10¹/₂ . 10¹/₂

Using the product rule that indicates that: the exponent result will be the addition of these exponents, we have:

10(¹/₂⁺¹/₂)

10(²/₂)

10¹

10

In mathematics an exponent is the number of time that a number, called (base) is multiplied by itself. It is also called, power or index.

Example: 3² = 3*3 = 9

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Michelle’s overtime hourly payment is 35.22

Given that ,

Equation represents Michelle’s regular hourly and overtime wage

= 130 (x – 38) + 950% > 38

We have to find Michelle’s overtime hourly payment.

Let’s solve the above given equation:

130 (x – 38) + 950% x 38 = 0

130x – 4940 + (950/100) x 38 = 0

130x – 4940 + 9.5 x 38 = 0

130x – 4940 + 361 = 0

130x – 4579 = 0

130x = 4579

X = 4579 / 130

X = 35.22

That is, Michelle’s overtime hourly payment is 35.22.

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By the use of algebra properties, the expression (- 3 · m⁻⁴) · (- 5 · m⁷) is equivalent to 15 · m³.

In this question we find a product of two monomials, each monomial has a constant, a variable and a grade and the entire expression must be simplified by means of algebra properties. The complete procedure of simplification is now presented:

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