Answer:
Mass and velocity are both directly proportional to the momentum. If you increase either mass or velocity, the momentum of the object increases proportionally. If you double the mass or velocity you double the momentum.
Explanation:
A box has a mass of 30kg and accelerates at a rate of 3 m/s. If the force of friction on the box is 20N, how much force did YOU exert in order to move it?
The Force applied on the box to accelerates it at a rate of 3 m/s² is 404 N.
What is force?Force is a pull or push effect on a body.
The force on a body is related to the mass and the acceleration of the body.
The formula to calculate force is given below:
Force = mass * accelerationConsidering the given question;
The force involved are:
frictional forcea net force which produces acceleration of the boxthe force of gravity on the boxThe force applied on the boxForce applied = Net force + weight of the body + frictional force
weight of the body = mass * acceleration due to gravity, g
Weight of the body = 30 * 9.8 m/s
Weight of the body = 294 N
Net Force = 30 * 3 = 90 N
Force applied = 90 N + 294 N + 20 N
Force applied = 404 N
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Give 3 examples of how organs systems work together
The digestive system, the circulatory system and the respiratory system all these works together for the maintenance of the body.
What are the three ways that how organs system work together?
1. The heart pumps the blood in our body, the lungs bring the oxygen in and eliminates the carbon dioxide out of the body, and the skin provides the protection and work as a barrier and safe the internal body organs.
2. The digestive, respiratory and circulatory system all these organs works together for extracting the wastes from our body but also absorbing the necessary nutrients which is good for body.
3. Our circulatory system carries the oxygen, minerals, nutrients and water and provide to cell in our body. The cells eliminated the wastes of the body through the respiratory system, by our excretory system and from our skin.
So we can conclude that the digestive system, the circulatory system and the respiratory system all these works together for the maintenance of the body.
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What do you observe now do the same with the second plastic shopping bag square
The observation is that we will observe a large shadow in dark color on the wall.
How to illustrate the information?The light will be blocked if we place our largest plastic shopping bag between the light source and the wall.
When something stops the path of the light, the light can't pass through it, and we may see a black shadow where it can't.
Therefore, we may state that a shadow will be visible when a bag is held between a light source and a wall.
If the bag is transparent, we will still be able to see a shadow, but it won't be as dark as previously because transparent materials let some light through but not as much as other materials do.
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What do you observe if you switch on your light source. make sure it's shining onto a wall hold your largest plastic shopping bag square between the light source and the wall
Which of the following settings describe a displacement vs time graph that looks like this
Answer:
Image result for Which of the following settings describe a displacement vs time graph that looks like this
Displacement time graph for rest is a straight line with zero slope. Displacement time graph for uniform motion is a straight line with non-zero slope. Displacement time graph for uniform acceleration is a parabola. The three scenarios are shown in the attached plot.
Explanation:
. A man rows a boat in still water at 6.0km/h, he wishes to
row due north across a river 3.0km wide which is flowing
due east at 2.0km/h. calculate
a. The direction in which he must head the boat
b. The time taken to reach the other bank
The direction in which he must head the boat is 30° West of North. The time taken to reach the other bank is 0.86 hours.
Velocity of boat with respect to water, [tex]V_{BW}[/tex] = 6 km / h
Velocity of river, [tex]V_{W}[/tex] = 2 km / h E
If the boat has to reach the exact opposite side of the river from the starting point, the boat should go upstream.
Velocity of boat in upstream, [tex]V_{B}[/tex] = [tex]V_{BW}[/tex] - [tex]V_{W}[/tex]
[tex]V_{B}[/tex] = 6 - 2
[tex]V_{B}[/tex] = 4 km / h
θ = [tex]sin^{-1}[/tex] ( [tex]V_{W}[/tex] / [tex]V_{B}[/tex] )
θ = [tex]sin^{-1}[/tex] ( 2 / 4 )
θ = [tex]sin^{-1}[/tex] ( 0.5 )
θ = 30° W of N
cos θ = Adjacent side / Hypotenuse
cos 30° = 3 km / Distance covered by the boat
Distance covered by the boat = 3 / 0.87
Distance covered by the boat = 3.45 km
t = d / v
t = 3.45 / 4
t = 0.86 hr
Therefore,
The direction in which he must head the boat is 30° West of NorthThe time taken to reach the other bank is 0.86 hours.To know more about speed of boat in a river
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3) If the displacement of an object, x, is related to velocity, v, according to the relation .x = Av,
the constant, A, has the dimension of which of the following?
a) acceleration
b) length
c) time
d) area
If the displacement of an object, x, is related to velocity, v, according to the relation .x = Av the dimension of which of the following is time.
What is displacement?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a lecturer moves to the right in relation to a whiteboard. Displacement describes this shift in location.
A = x/v
since x is displacement and v is velocity
x/v = m/(m/s) = s
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how does the distance from an eye chart affecr the number of letters that are recognized on a line?
The correct answer is eye chart, the position of the viewer, light in the room.
The number of letters identified on a particular line is directly related to the distance between an eye chart and the person undergoing an eye test.
Distances from the eye chart are used to identify defects in a patient's visual sight. Someone is nearsighted if they are unable to perceive objects in the distance. He will therefore see a hazy image of the letters if he looks away from the eye chart and tries to read it.
And someone with long sight is unable to perceive nearby objects. One will not be able to read the letters on the chart if they are closer to him because of his farsightedness.
Therefore, the distance from the eye chart affects the ability to perceive the letters that are displayed there.
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Marissa's car accelerates at a rate Of 42.60 m/?. How long does it take
for Marissa's car to accelerate from a speed of 88.5 km/h to a speed of
96.5 km/h?
The correct answer is 0.0539 sec.
Since we are aware that a body's position changes over time, the concept of velocity is introduced. The vector quantity known as velocity is sometimes referred to as the rate of change of location. The body's velocity increases as it changes position more quickly over time.
The acceleration of the car is 42.60 m/s^2.
Initial speed u = 88.5 km/h = 24.5 m/s
final speed v = 96.5 km/h = 26.8 m/s
The amount of time the car needs to travel from a speed of 24.5 m/s to a speed of 26.8 m/s must be determined. An object's acceleration is determined by:
t = v-u/a
t = (26.8 - 24.5) / 42.6
t = 0.0539 sec
Therefore, it takes the car 0.0539 seconds to increase from a speed of 24.5 m/s to a speed of 26.8 m/s. This is the necessary remedy as a result.
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Calculate the potential energy stored in a cart of mass 506.8 g elevated to a height of 20.60 cm. Your
result should be reported in Joules.
A cart of mass 506.8 g elevated to a height of 20.60 cm has a stored potential energy of 1.024 J.
The energy that is held within an object because of its position in relation to a zero point is known as potential energy. An object has gravitational potential energy if it is positioned at a height above (or below) the zero height.
P.E. = mgh, where m is the mass in kilograms, g is the acceleration caused by gravity (9.8 m/s2 at the earth's surface), and h is the height in meters, which is the formula for gravitational force.
Here,
Mass M = 0.5068 kg
Acceleration due to gravity, g = [tex]9.81 \frac{m}{s^{2} }[/tex]
Height, h = 0.2060 m
PE = m × g × h
= (0.5068) × (9.81) × (0.2060)
= 1.024 J
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1.5 kg ball has an acceleration of 9.0 m/s^2 to the left. what is the net force acting on the ball
1.5 kg ball has an acceleration of 9.0 m/s^2 to the left. what is the net force acting on the ball 13.50 N Leftwards
What is acceleration ?The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.
Any object's mass and acceleration in the force's direction are multiplied together to form the net force exerted on it.
Here, F = m*a
F = 1.5*9.0 = 13.50 N
Since, the acceleration is to the left, the net force also acts towards left.
13.50 N Leftwards
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anybody knows what's is diffraction of waves
Answer: the spreading of waves around obstacles
Explanation:
HELP
Find the value of each calculation, rounded to the correct number of significant figures.
15.2÷4.368=
The value of 15.2 ÷ 4.368 rounded to the correct number of significant figures is 3.47985348.
What is significant figures?Significant figures is a digit that is meaningful with respect to the precision of a measurement.
Significant figures constitutes a digit that is nonzero, followed by a nonzero digit, or (for trailing zeroes) justified by the precision of the derivation or measurement.
According to this question, the following arithmetic expression is given:
15.2 ÷ 4.368 = 3.47985348
No. of significant figures: 9No. of decimals: 8Scientific notation: 3.47985348 × 100Therefore, the value of 15.2 ÷ 4.368 rounded to the correct number of significant figures is 3.47985348.
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the muscles in a grasshopper's legs can propel the insect upward at 3.0m/s how high can the grasshopper jump
The grasshopper attains an initial velocity of 3m/seconds and with this velocity can attain a maximum height of 0.4591 metre.
What is acceleration due to gravity?Acceleration due to gravity is a constant acceleration (changes if the change in height is considerable to earth's diameter) that an object experiences towards earth. Its value near the surface is 9.8u.
Given:
Initial velocity attained by the grasshopper=3m/s
Acceleration due to gravity=9.8u
According to Newton's third law every action has an equal and opposite reaction.
It's mathematical expression for motion is v^2=u^2-2×a×s
Where-
v is final velocity of the grasshopper
u is initial velocity of the grasshopper
a is acceleration due to gravity
s is the total distance
We can only apply Newton's law of motion for those bodies which have constant acceleration. The grasshopper also has a constant acceleration due to gravity which pulls it downward.
According to question for maximum displacement the final velocity will become zero
Substituting these value in Newton's third equation of motion we get
0 - 9 = 2 × 9.8 × s
Maximum displacement of the grasshopper = 0.4591 metre.
The grasshopper attains an initial velocity of 3m/seconds and with this velocity can attain a maximum height of 0.4591 metre.
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Starting from rest at the center of a skating rink, the two skaters shown push off from each other over a time period of 1.2 seconds.
What is the force of the push by the smaller skater?
SEE PICTURE.
Answer:
100N
Explanation:
Just took test answer is 100n
Rhea, with a radius of 7.63 x 105 m, is the second-largest moon of the planet Saturn. If the mass of Rhea is 2.31 x 1021kg, what is the acceleration due to gravity on the surface of this moon?
The acceleration due to gravity on the surface of this moon:
Solution:
R = 7·63x105 m m
M = 2·31x10² 1 kg
g= GM/R2
= 6.67x10" x 2.3 x [tex]10^{21}[/tex]/[tex](7.63*10^{5} )^{2}[/tex]
=g = 15.4077 x [tex]10^{10}[/tex]/[tex](7.63)^{2} * 10^{10}[/tex]
= g = 0·2646 m/s².
An object on the Moon weighs 1/6 of its weight on the Earth's surface. This is because the gravitational acceleration on the Moon is six times that of Earth. The value of g is determined by the mass of the gigantic body and its radius. It depends on your body. The value of g is constant for months. g is called gravitational acceleration. The acceleration of an object in free fall under the influence of gravity. Expressed as the rate of increase in velocity per unit time, it is assigned a standard value of 980.665 centimeters per second per second.
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N
5
+5 +11
B
10
To
20
D
30
Hint: Fine the slop for each line to determine the speed
time (sec)
40
A
G
10
4
On this graph, positive positions and directions of travel are considered to be North.
1. During which time interval (AB, BC, CD, DE, EF, FG) was the cart traveling at its greatest speed?
2. During which time interval(s) (AB, BC, CD, DE, EF, FG) was the cart at rest?
3. During which time interval(s) (AB, BC, CD, DE, EF, (FG) did the cart travel in a negative direction?
4. What was the cart's instantaneous speed at 6 seconds?
5. What was the cart's instantaneous speed at 22 seconds?
6. What was the cart's instantaneous speed at 40 seconds?
7. Describe the cart's behavior between 18 and 32 seconds. (location, speed, direction of travel, and distance traveled
Answer:
h
Explanation:
1) FG
Explanation:
During which time interval (AB, BC, CD, DE, EF, FG) was the cart traveling at its greatest speed?
A box with a mass of 30kg accelerates at a rate of 3m/s. If the force of friction on the box is 20N, how much force did you exert in order to move it?
The force exerted in order to move the box is 404 N.
What is force?Force is a pull or push effect on a body.
The force on a body is related to the mass and the acceleration of the body.
The acceleration of a body is inversely related to the mass of of the body and directly related to the force acting on it.
Force = mass * acceleration.
Net force = Force applied - (weight of the body + frictional force)
Force applied = Net force + weight of the body + frictional force
Weight of the body = 30 * 9.8 m/s = 294 N
Net Force = 30 * 3 = 90 N
Force applied = 90 N + 294 N + 20 N
Force applied = 404 N
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An archer shoots an arrow over flat ground. The speed of the arrow is 45m/s. A.) What is the maximum possible range of the arrow? B.) At this range, what is the maximum height? C.) What 2 angles will give a range of 90 meters?
the answer is 80 degrees so simple try solving again
A bicycle tire contains 2.00L of gas at an absolute pressure of 7.00 x 10 5 N/m2 and temperatures
The final pressure of the tire will be 6.99 N/m²
The initial volume of tire = 2.00 L
The initial pressure of the tire = 7.00 × 10 5 N/m²
The initial temperature of the tire was 31 °C
P1V1 = P2V2
7.00 × 10 5 N/m² × V1 = 101325×100
V1 ⇒ 1.45×10^(-5) m³ = 1.45×10^(-2) L
Therefore new pressure = initial pressure - (pressure of released gas filling the entire 2 L)
The pressure of released gas filling the entire:
2 L = 2 L/(7.00 × 10^5 N/m² × 1.45×10^(-5) m³)
⇒ 1.197 ×10^(-4) N/m²
New pressure = 7.00 × 10^5 N/m² - 1.197 ×10^(-4) N/m²
⇒ 6.99 N/m²
Hence the New Pressure of the tire is 6.99 N/m²
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A long rectangular, yellow sign with diagonal black stripes on it means:
O There is a highway ahead
O Be prepared to stop
O The guardrails of a narrow bridge are ending
OYou are going the wrong way
A long rectangular, yellow sign with diagonal black stripes on it means Be prepared to stop.
Hazard warning signs consist of black diagonal stripes on a yellow background. WA-36 signs are used to mark roadway obstructions that are passable from either side. Hazard warning signs consist of black diagonal stripes on a yellow background. WA-36 signs are used to mark roadway obstructions that are passable from either side.
Warning sign. These signs warn of dangerous or unusual conditions such as curves, turns, inclines, and side streets. They are usually diamond-shaped and have black letters or symbols on a yellow background. These markings, yellow diagonal lines, are found on roads and highways to indicate narrow roads or obstructions in the lane. This area resembles a triangle with a solid yellow diagonal line inside the outline.
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i. ii. iii. An object travels from the rest with a constant acceleration of 10m/s². Determine the speed v at the end of 10s. the average speed for the 10s interval. the distance covered after 10s
20m/s is the average speed for the 10s interval
Given, a=10m/s 2u=0m/s (dropping)
t=2secSo, v=u+at=0+10(2)=20m/s
Velocity after 2sec=20m/s
Acceleration is it always the same?There will always be non-zero acceleration whenever there is a change in velocity, whether it is brought on by a change in speed or a change in direction. Stephen J If the net force is not constant, acceleration is not constant either.
When motion is accelerated continuously, the speed rises by the same amount every second. Free fall is the most illustrative and significant example. Gravity causes a constant acceleration when anything is thrown or dropped, with a constant value of around 10 metres per second squared.
When the magnitude and direction of the rate at which an item is changing its location stay constant, the object has constant velocity.
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3. An object is dropped from 600m, If it is initially at rest, how fast will it go as it
Hits the ground?
The velocity of the object as it hits the ground, given the data from the question is 108.486 m/s
How to determine the final velocityWe'll begin by obtaining the time take to reach the ground. this is illustrated below:
Height (h) = 600 mAcceleration due to gravity (g) = 9.8 m/s²Time (t) =?h = ½gt²
600 = ½ × 9.8 × t²
600 = 4.9 × t²
Divide both side by 4.9
t² = 600 / 4.9
Take the square root of both side
t = √(600 / 4.9)
t = 11.07 s
Finally, we can obtain the final velocity as follow:
Time (t) = 11.07 sInitial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Final velocity (v) =?v = u + gt
v = 0 + (9.8 × 11.07)
v = 0 + 25.088
v = 108.486 m/s
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Which of the following elements have the same amount of valence electrons as Sulfur (5)?
O N. Br, and Xe
O F, As, and Sn
O Si, P, and CI
O O, Se, and Te
Answer:
Explanation:
it's c
[Honors] Vector A points in the negative x direction and has a magnitude of 25 units. The Vector B points in the
positive y direction. Find the magnitude of B if A + B has a magnitude of 35 units
The magnitude of B if A + B has a magnitude of 35 units is 24.49 units.
On paper, operations involving coplanar vectors, including addition and subtraction, can be represented. In reality, vectors are simply straight lines with arrowheads that can be drawn quickly and easily on a flat surface using a few basic rules.
Vector A is along the x-axis and vector B is along +y axis. Thus 90 is the angle between A and B ,
given |A| = 25
|A + B| = 35
We know that resultant |R| = |A + B| = √(A^2 + B^2 + 2ABcos90°)
35 = √ 25^2 + B^2 + 0
35^2 = 25^2 + B^2
B = √35^2 - 25^2
B = √1225 - 625
B = √600
B = 24.49 units.
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Using something as a medium of exchange in transactions (money)
We can use currency as a medium of exchange in transactions because of its easy availability.
What is the basic medium of exchange for transaction?Currency is the most common medium of exchange accepted as a standard by all parties for settling economic transactions because every region or country has its specific type of currency in which they do transactions and carried out their economic activities world wide. Currency is also considered as a medium of exchange for goods and services. It is money that is present in the form of paper and coins which is issued by a government. Currency is generally accepted because of high value as a method of payment. U.S. dollars ($), euros (€), Japanese yen (¥), and pounds sterling (£) are the examples of currencies of different countries around the world.
So we can conclude that We can use currency as a medium of exchange in transactions because of its easy availability.
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you are flying a plane at a rate of 8m/s north. the wind is blowing 6m/s south. What is your resultant
Your resultant velocity will be along the + y - direction or north direction and has magnitude of 2 m/s.
What are vector quantities?The quantities that have both magnitude and direction are called vector quantities. Example - velocity, acceleration, force etc.
Given in the question is a plane flying at a rate of 8m/s north and the wind is blowing 6m/s south.
In order to find the resultant, refer to the diagram attached. The north direction is represented by +y axis and south direction is represented by -y axis.
The velocity vector representing you will be [v1] = 8 j
The velocity vector representing the wind will be [v2] = - 6 j
Resultant vector [v] = v1 - v2 [Opposite and unequal vectors]
v = 8 j - 6 j
v = 2 j
Therefore, you resultant velocity will be along the + y - direction or north direction and has magnitude of 2 m/s.
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Kinematics time question
For any physics free fall problem, a student is taught that the velocities on a graph have the same magnitude as those that are horizontally equivalent. For example, if you have two points that are both at the same height during free fall, one will be positive and the other will be negative--but they will be of the SAME magnitude.
Let's say we have a problem where an object was launched with a positive initial velocity in the upward direction. All we would have to do is change that upward initial velocity to downward (making it negative). Everything else stays the same, such as gravity.
Now here is the part where I get a bit confused. Why can we simply just use the inverse of the initial velocity without taking into account the time that has passed? Doesn't time start once the object leaves the starting point? If this is true, why can we use the same time for the kinematic equations?
The same kinematics equation is used to calculate initial velocity because the time taken to get to that point is the same time taken for the object to fall. Also, the acceleration due to gravity is constant only changing sign due to the direction of the motion.
What is kinematics?Kinematics is the study of the movement or motion of objects as well their forces that cause the motion.
Kinematics studies the interaction between forces that cause motion and the various forms of motion of the objects acted upon by the force.
Examples of kinematics include:
firing an arrowshooting a footballhitting a baseball with a baseball batThe following terms are terms involved in kinematics:
speed- this is the distance covered per unit time by a moving body.velocity- this is the displacement of a body per unit timeacceleration - this is the change in velocity of a body per unit time.In kinematics, a form of motion where a body is falling freely under gravity is known as free fall.
For a body undergoing free, its velocity could either be negative or positive depending on the direction of motion.
For a body moving against gravity, its velocity is negative whereas for a body falling to the earth, its velocity is positive.
For a body falling freely under gravity, its velocity is the same as gravity accelerates the body to a constant value of 9.81 m/s².
The time taken to get to that height above the ground is the same time it will take the objects to fall to ground.
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WILL GIVE BRAINLIEST!!!!
According to the giant impact hypothesis, the young proto-Earth and a Mars-sized protoplanet called Theia collided. The collision ejected material into space called ejecta material. What implication could this collision have for the Moon?
Group of answer choices
Ejecta material coalesced in the Moon and formed the protoplanet Theia that collided with Earth.
Theia collected ejecta material and with it became the Moon when it coalesced and set up in Earth’s orbit.
Ejecta material formed the Moon when it set up in Earth’s orbit, coalesced, cooled down, and solidified.
Theia brought ejecta material to Earth’s orbit and became the Moon when it cooled down, and solidified.
The implication that the collision will have for the moon is D. Theia brought ejecta material to Earth’s orbit and became the Moon when it cooled down, and solidified.
What does the giant impact theory explain?The hypothesis is the prevailing explanation accepted by the scientific community, and it contends that the moon developed as a result of an object slamming into the early Earth. Earth originated from the residual dust and gas cloud surrounding the newborn sun, just like the other planets.
The Moon may have formed from the ejecta of a collision between the proto-Earth and a planet the size of Mars, according to the giant-impact scenario, also known as the Big Splash or the Theia Impact.
Therefore, based on the information, the correct option is D.
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calculate the kinetic energy of a 820 kg compact car moving at 23 m/s.
Answer:
216,890 J
Explanation:
We first define the Kinetic Energy Formula:
K.E =
[tex] \frac{1}{2} m {v}^{2} [/tex]
where m is the mass of the object in kg, and v is the velocity in m/s.
Given from the information from the question, we substitute the values in to find K.E.
K.E of car =
[tex] \frac{1}{2} (820) {(23)}^{2} \\ = 216890 \: joules[/tex]
Note that the SI unit for Energy is Joules or J.
In proton beam therapy, a beam of high-energy protons is used to kill cancerous cells in a tumor. In one system, the beam, which consists of protons with an energy of 2.8×10−11J, has a current of 80 nA. The protons in the beam mostly come to rest within the tumor. The radiologist has ordered a total dose corresponding to 3.6×10−3J of energy to be deposited in the tumor. How long should the beam be in order to deliver the required dose?
The number of protons that strike the tumor each second is [tex]1.7*10^8[/tex] protons.
What is proton beam therapy?Since it do not produce proper outcomes, proton beam therapy is only appropriate for certain types of cancer, such as highly complex brain, head and neck cancers, and sarcomas.
Here, it is mentioned that
Energy of proton = [tex]2.8*10^{-11}[/tex] Joules.
Current = 84 nA = [tex]84*10^{-9}[/tex] Ampere.
As well as
Energy of total dose = [tex]3.4*10^{-3}[/tex]
The quantity of charge per unit time is mentioned as:
Q = It = Ne
Number of proton (N) = Q/e
[tex]N=\frac{2.8*10^{-11}}{1.602*10^{-19}}[/tex]
[tex]N=1.75*10^8[/tex]
Thus, this is the number of proton in the given scenario.
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