Answer:
The river current influences the motion of the boat and carries it downstream. The motorboat may be moving with a velocity of 4 m/s directly across the river, yet the resultant velocity of the boat will be greater than 4 m/s and at an angle in the downstream direction.
Explanation:
A girl on a backyard trampoline bounces straight upward with an initial speed of 4.5m/s. What is the girl's velocity when she returns to the trampoline?
(I would like a step-by-step explanation so I can understand the answer please. Thank You)
Answer: Final speed,Vf= -4.5m/s
It is the same speed but in opposite direction,coming down against gravity.
Explanation:
Calculating distance,d= (Vf^2-Vo^2)/2g
d=(0-4.5^2)/(2×9.8)
d= -20.25/19.6
d= -0.053m
Vf^2=Vo^2 + 2gd
Vf= Sqrt(0 +2×9.8(×-0.053))
Vf=V=-4.5m/s
a cyclist sprints at the end of a race to clinch a victory. she has an initial velocity of 11.5 m/s and accelerates at a rate of 0.500 m/s2 for 7.00 s. (a) what is her final velocity? (b) the cyclist continues
(a) The final velocity is v{f}}= =15m/s
(b) the cyclist continues the tsaved =5.28s
(c) Δt=4.18s ,d=49.3m
The questions discusses more about:
What is velocity?
When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Therefore,
a cyclist sprints at the end of a race to clinch a victory. she has an initial velocity of 11.5 m/s and accelerates at a rate of 0.500 m/s2 for 7.00 s. (a) what is her final velocity? (b) the cyclist continues
(a)v{f}}= =15m/s
(b)tsaved =5.28s
(c) Δt=4.18s ,d=49.3m
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By deflecting cathode rays with a magnetic field thomson was able to measure what property of electrons?.
The negatively charged electric plate is avoided in favor of the positively charged electric plate by the cathode ray. Thomson was able to estimate the mass-to-charge ratio of the particles by measuring the degree to which the ray was refracted by a magnetic field.
What property of the electron did Thomson measure?J.J. Thomson measured the electron's mass in terms of its physical characteristics.Similar experiments were conducted with cathode rays and magnets by William Crookes, who came to the conclusion that cathode rays were made up of negatively charged molecules based on his observations of the rays' deflection by magnetic fields.J.J. Thomson used a Crookes, or cathode ray, tube to conduct experiments that discovered the electron in 1897. He provided evidence that cathode rays have a negative charge.The negatively charged electric plate is avoided in favor of the positively charged electric plate by the cathode ray. Thomson was able to estimate the mass-to-charge ratio of the particles by measuring the degree to which the ray was refracted by a magnetic field.
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An ocean liner is cruising at 10 meters/second and is about to approach a stationary ferryboat. A parcel is released from the ocean liner from a height of 5.5 meters above the ferryboat’s deck. Calculate the distance at which the ferryman should position the boat from the point horizontally below the point of release so that the parcel lands inside the boat.
Answer:
If a stream channel is 5 meters wide and 3 meters deep, and the velocity of the water moving through the channel is 10 meters/second, what is the stream's discharge (include units)? ... and deposition (point bars) occurs on the inside
Explanation:
If the rate of change of [c] is 0. 049 m/min. What is the rate of change of [a] in m/s? hint given in feedback answer:
By unit conversion, the rate of change in m/s is 8.17 x 10¯⁴ m/s.
We need to know about the rate of change unit conversion to solve this problem. The unit conversion of rate change can be used to convert a unit to another unit. It can be defined as
a = xb
where a is unit a, b is unit b and x is the constant of conversion.
From the question above, we know that
Q = 0.049 m / min
Convert time unit to second by using the unit conversion (1 min = 60 s) and we get the rate of change
Q = 0.049 m / 60 s
Q = 8.17 x 10¯⁴ m/s
Hence, the rate of change in m/s is 8.17 x 10¯⁴ m/s.
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The graph below shows Claire's speed during a parachute jump. At certain points the force of Claire's weight balanced the force of air resistance. Add up the numbers of these points (e.g. 1 and 3 and 5 would be 9).
What's the answer?
The points at which Claire's weight balanced the force of air resistance are 2, 3 and 5. The sum of these points is 10.
What is force?We know that force is a vector quantity. This implies that force has both magnitude and direction. The direction of the force determines the sign that the force would carry. In this case there are two forces that acts on Claire as she jumps out of the parachute. These two forces are the Claire's weight balanced and the force of air resistance.
The two forces tend to act in the opposing directions. The points at which the two forces are balanced, the speed time graph shows a plateau to indicate that the speed is not changing with time.
The points at which Claire's weight balanced the force of air resistance are 2, 3 and 5. The sum of these points is 10.
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A car acccelerates at 4m/s/s. Assuming the car starts from rest, how much time does it need to accelerate to a speed of 40 m/s?
A car is travelling with a acceleration of 4 m/s². Assuming the car starts from rest, The time need to accelerate to the speed of 40 m/s is (t)=10 s.
What is time?Time is a scalar quantity. its shows the period when the process happened. It can be measured in hour, minute, seconds etc.
How can we calculate the time?To calculate the time need to accelerate to the wanted speed we are using the formula, v=u+at
Here we are given,
u= the initial velocity of the car = 0m/s [Note: the car starts from rest]
a= the acceleration of the car = 4 m/s².
v= the final velocity of the car = 40 m/s.
we have to calculate the time need to accelerate to the wanted speed =t
Now, we put the values in the above equation,
v=u+at
Or, t= v/a [Note: u=0]
Or, t= 40/4
Or, t=10 m/s.
From the above calculation, we can say that the time need to accelerate to the wanted speed is (t)=10 s
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4. A bird flies with an average velocity of 7.5 m/s east from one branch to
another in 2.4 s. It then pauses before flying with an average velocity of 6.8
m/s east for 3.5 s to another branch. What is the bird's total displacement
from its starting point?
2
The correct answer is d = 41.8m
The phrase "displacement" refers to a change in the location of an object. It is a magnitude and direction vector quantity. It is represented with an arrow pointing from the beginning to the finish.
The spatial distance between two points is measured via the shortest path between them. Because it is a vector quantity, it has a magnitude and a direction.
Given,
[tex]V_1[/tex]= 7.5 m/s
[tex]t_1[/tex]= 2.4 s
[tex]V_2[/tex] = 6.8 m/s
[tex]t_2[/tex] = 3.5 s
[tex]V_1 = d_1/t_1[/tex]
[tex]d_1 = V_1t_1[/tex]
[tex]d_1[/tex] = 7.5 m/s (2.4 s)
[tex]d_1[/tex]= 18 m
[tex]V_2[/tex] = [tex]d_2/t_2[/tex]
[tex]d_2 = V_2t_2[/tex]
[tex]d_2[/tex] = 6.8 m/s (3.5 s)
[tex]d_2[/tex]= 23.8 m
Total displacement d = [tex]d_1 + d_2[/tex]
d = 18m + 23.8m
d = 41.8m
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According to history, the concept that all matter is composed of atoms was first proposed by.
The Greek philosopher Democritus, but not widely accepted until modern times.
Who first proposed the idea of atoms?It is believed that Leucippus of Miletus, who lived in the fifth-century bce, invented the atomic philosophy. About 430 BCE, his illustrious pupil Democritus of Abdera gave the fundamental components of matter the atomos—literally, "indivisible"—name.The concept of the atom was first proposed by the Greek philosopher Democritus in 450 B.C.The oldest person whose dedication to atomism is extensively documented is Leucippus (5th century BCE). He is typically given the credit for developing atomism.John Dalton, an English chemist, conducted several experiments in the early 1800s that helped solidify the concept of atoms. After the "dead of chemistry" in the previous 2000 years, he created the first atomic theory. Dalton proposed the idea that atoms make up all matter.According to history, the concept that all matter is composed of atoms was first proposed by: the Greek philosopher Democritus, but not widely accepted until modern times
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show that the decay of power density for a wave radiated by an antenna (1/r2) results from the increase in the area of a sphere centered on the antenna and the fact that the total radiated power is conserved.
The answer is P/4π[tex]r^{2}[/tex] or 1/r2
How to calculate radiated power density?Radiated power density = S
Radiator = r
S = K/r2
Area of the sphere surrounding the antenna [tex]A_{sph}[/tex] = 4π[tex]r^{2}[/tex]
The total power radiated through a sphere of radius r is
P = [tex]S[/tex][tex]A_{sph}[/tex] = (K/r2)4π[tex]r^{2}[/tex]
= 4πK≈r°
Therefore,
The total power radiated remains constant with radius
S = P/[tex]A_{sph}[/tex]
= P/4π[tex]r^{2}[/tex] or 1/r2
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An object is lifted from the surface of a spherical planet to an altitude equal to the radius of the planet. As a result, what happens to the mass and weight of the object?.
An object is lifted from the surface of a spherical planet to an altitude equal to the radius of the planet. The mass remains the same but the weight of the object decreases.
As the object goes up the surface of a spherical planet, the force of gravity acting on the object decreases.
According to the gravity at height formula:
g1 = g (1 – 2h/R)
where g1 is the gravity at height h. R is the radius of the planet and g is the gravity at the planet's surface.
Now,
The weight is directly proportional to gravity. As the object goes up, the gravity decreases and hence the weight also decreases.
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the football team at enormous state university (esu) uses vector displacements to record its plays, with the origin taken to be the position of the ball before the play starts. in a certain pass play, the receiver starts at 1.0i^−5.0j^, where the units are yards, i^ is to the right, and j^ is downfield. subsequent displacements of the receiver are 7.0i^ (he is in motion before the snap), 8.0j^ (breaks downfield), −7.0i^ 3.0j^ (zigs), and 11.0i^ 12.0j^ (zags). meanwhile, the quarterback has dropped straight back to a position −7.0j^.
The quarterback will throw the ball 44.4 yards in a particular direction with the angle of 54.16 °
We shall use the ideas connected to the vector sum to develop this issue. To achieve this, we will add the person's displacement vectors to determine the total distance he has gone from the initial point (0 position) to the destination position.
[tex]\overrightarrow R[/tex] = [tex](+1.0 \^{i} - 5\^{j}) + (7\^{i}) + (+12\^{j}) + (6.0\^{i} + 4.0\^{j}) + (+ 12.0\^{i} + 18.0\^{j})[/tex]
[tex]\overrightarrow R[/tex] = [tex]26\^{i} + 29\^{j}[/tex]
subtracting the quarterback's position [tex]\overrightarrow Q[/tex]
[tex]\overrightarrow Q[/tex] = [tex]-7.0\^{j}[/tex]
We can now get the relative location of the two individuals by subtracting the vectors; hence, the position between the individual and the quarterback is
[tex]\overrightarrow R[/tex] - [tex]\overrightarrow Q[/tex] = [tex]26\^{i} + 29\^{j}[/tex] - ([tex]-7.0\^{j}[/tex])
= [tex]26\^{i} + 36\^{j}[/tex]
The magnitude of the relative distance would be calculated using vector characteristics
[tex]|\overrightarrow R - \overrightarrow Q|[/tex] = [tex]\sqrt{26^2 + 36^2}[/tex]
[tex]|\overrightarrow R - \overrightarrow Q|[/tex] = 44.40 yards
The vector's direction would be determined by the tangent of the two vectors, which is
[tex]\theta = tan ^{-1} (\frac{36}{26} )[/tex] = 54.16°
As a result, with regard to 54.16 °, the quarterback will throw the ball 44.4 yards in one direction.
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Full question
At Enormous State University (ESU), the football team records its plays using vector displacements, with the origin taken to be the position of the ball before the play starts. In a certain pass play, the receiver starts at +1.0 i^ - 5.0 j^, where the units are yards, i^ is to the right, and j^ is downfield. Subsequent displacements of the receiver are +7.0 i^ (in motion before the snap), +12 j^ (breaks downfield), ?6.0i^+4.0j^ (zigs), and +12.0i^+18.0j^ (zags). Meanwhile, the quarterback has dropped straight back to a position ?7.0j^.
Part A
How far must the quarterback throw the ball? (Like the coach, you will be well advised to diagram the situation before solving it numerically.)
Part B
In which direction must the quarterback throw the ball?
Two kg of refrigerant 134a undergoes a polytropic process in a piston–cylinder assembly from an initial state of saturated vapor at 2 bar to a final state of 12 bar, 80°c. Determine the work for the process, in kj.
The work done by polytropic process is -69.88 kJ.
The work for the polytropic process is determined using
P . v^n = constant.
where P is pressure, V is specific volume
As we know that
W = m∫Pdv
W = m(P2v2 - P1v1) / (1 - n)
In order to evaluate this expression, we need to determine the specific volumes and the polytropic exponent, n.
State 1: v1 = vg1 = 0.0993 m3/kg
State 2: at 12 bar, 80oC; v2 = 0.02051 m3/kg
Hence by using polytropic exponent
P1 / P2 = (v2 / v1)^n
n = ln(2/12) / ln(0.02051/0.0993)
n = 1.136
Find the work done
W = m(P2v2 - P1v1) / (1 - n)
W = 2kg(12bar . 0.02051m³/kg - 2 . 0.0993) / (1 - 1.136) x (10⁵ N/m²/1 bar) x (1 kJ / 10³ Nm)
W = -69.88 kJ
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Use dimensional analysis to calculate how many dozen donuts you would need to order to
feed a school of 456 students.
There are 38 dozens donuts needed to order to feed a school of 456 students.
How many dozen donuts you would need to order to feed a school of 456 students?There are 38 dozens of donuts you would need to order to feed a school of 456 students if each student eat one donut. We know that there are 12 units in one dozen so if we do the calculation of 456 divided by 12, we get 38. If each student receives one donut, 38 dozens of donut are required while on the other hand, if each student receives two donuts, then 76 dozens of donut are needed. If each student receives three donuts, then 114 dozens of donut are needed. If each student receives four donuts, 152 dozens of donut are needed.
So we can conclude that there are 38 dozens donuts needed to order to feed a school of 456 students.
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True or False: A "reference point" is needed to determine the position of an object.
if false please tell me the correct word(s) to replace reference point.
Answer:
it should be true
Explanation:
:) hope it's right
An airplane starts from rest and accelerates at a constant 3.00 m/s2 for 20.0 s. What is its displacement in this time?
The displacement in time of an airplane that starts from rest and accelerates at a constant 3.00 m/s² for 20.0 s is 600m.
How to calculate displacement?Displacement is a vector quantity which denotes distance with a directional component.
The displacement (s) of an object equals, velocity (u) times time (t), plus ½ times acceleration (a) times time squared (t²) as follows:
s = ut+ ½at²
Where:
s = displacementu = initial velocitya = accelerationt = times = (0 × 20) + ½ × 3 × 20²
s = 0 + 600
s = 600m
Therefore, the displacement in time of an airplane that starts from rest and accelerates at a constant 3.00 m/s² for 20.0 s is 600m.
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CAN SOMEONE PLEASE HELP ME WITH THIS GRADE 11 PHYSICS ASSIGNMENTTTTTT
The value of the normal force on the object of mass 50 kg such that it experiences a friction force of 5 Newton is equal to 490 Newton.
What is friction force?Friction force is a force that opposes the force. It acts in the direction opposite to the intention of the motion of the object ,it is a non conservative force in nature.
What is Normal force?Normal force is a type of force that's perpendicular to the surface of the object when it is placed in contact with another surface the SI unit of normal force is the same as force in general that is Newton.
Given:
Surface area of the sphere = 6 u
Mass of the sphere = 50 kg
First we use the mass value of the sphere, we will calculate the value of the weight of a sphere so that we know force against which against which the normal force will be acting.
Weight of the sphere = 50 × 9.8
Weight of the sphere = 490 Newton
Now since the normal force is being used to balance of the weight of the sphere we can say that the value of the normal force will be equal to 490 Newton.
Therefore, The value of the normal force on the object of mass that it experiences a friction force of 5 Newton is equal to 490 Newton.
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a train startes from rest and accelerate uniformly until it attains a velocity of 8m/s in 10 seconds. calculate the acceleration of the train
The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force applied on the item determines the object's acceleration.
A train starts from rest and accelerate uniformly until it attains a velocity of 8m/s in 10 seconds. calculate the acceleration of the train.
a = 8/10
a = 0.8m/s2
The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t). This enables you to calculate the change in velocity in meters per second squared (m/s2). Since acceleration is a vector quantity, both its magnitude and its direction are included.
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QUESTION 2: Switch on your light source. Make sure it is shining onto a wall Hold your largest cardboard square between the light source and the wall. . • 2a. What do you observe? . Now do the same with the second cardboard square. 2b. What do you observe? ▸ Now do the same with the third cardboard square. 2c. What do you observe? 2d. What differences do you observe between the shadows of the three sh QUESTION 33 Switch on your light source. Make sure it is shining onto a wali. Hold your largest plastic shopping bag square between the light sourc
When a light source falls on an object if it is a opaque object it will form shadow.
And the light falls on the largest cardboard there will be a big shadow formed in the wall. Now when we take a second cardboard the shadow will form in accordance with that cardboard that if the cardboard is more it will form small shadow
And when we do with the same third cardboard or small cardboard the shadow will be according to the size of the cupboard now when we keep a plastic shopping bag in between the light source and the wall if the plastic bag is transparent the light will pass through the plastic bag and if the plastic bag is opaque the light will not pass through the bag and a shadow will be not be formed
Here we can conclude that if a light is passing through a pack object the light cannot pass through the object and it will format shadow but when the light is passing through a transparent object that light will pass through the object and there will be no shadow formed
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A rock is dropped from a cliff and takes 6 seconds to hit the ground. At what time is the speed of the rock the highest??
Answer:
Time to reach ground = t = 6 sec
Explanation:
Acceleration due to gravity = g = 9.8 m/s²
Initial Velocity of the Rock = Vi = 0 m/s (Because, the rock will be at rest, initially)
When a rock is dropped and takes 6 seconds to touch the ground, its maximum speed will be [tex]6^{th}[/tex] second.
The force of gravity causes a rock to accelerate when it is dropped from a cliff. On Earth, the acceleration caused by gravity is roughly 9.8 meters per second squared (m/s2). This indicates that the rock's speed increases by 9.8 m/s per second as it falls.
According to the question, it takes the rock 6 seconds to hit the ground. It takes the rock exactly this long to fall from the cliff to the ground.
One must comprehend that the rock's speed rises steadily as it falls in order to determine the moment at which it is moving at its fastest. The rock's initial velocity (Vi) is 0 m/s because it begins at rest. The acceleration brought on by gravity causes it to move faster as it drops.
The rock will reach its highest speed just before it touches the ground because its velocity is constantly rising. As a result, the rock is moving at its fastest at the moment of impact (t = 6 sec).
Thus, the maximum speed will be at T= 6 seconds.
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You have been given sheets of four different materials, sand paper,polished wood, rubber and plastic. Design an activity to compare the amount of friction when a wooden block is pulled across sand paper, polished paper, wood and rubber
Force, Friction (static and kinetic), (balanced and unbalanced).
Materials - Tape, spring scales, measuring tape, string, wooden blocks, wooden blocks with sandpaper on the bottom, and different surfaces.
Procedure - 1. To test and gather information on surface friction, each group will look at four distinct surfaces (a concrete floor, a lab desk, a lab floor, and a carpet).
2. Each item should have a string firmly tied around it (a plain block of wood and the wood with sandpaper). Connect the string's looped end to the spring scale.
3. The 50 cm measuring line should be fastened to your surface. Your beginning point will be in the front, and your finishing point will be at the back.
4. Pull the unadorned wood block across the designated surface at a SLOW, STEADY SPEED for 50 cm. Note the amount of force (in N) necessary to pull the object.
5. Pull the wood block with the sandpaper on it across the designated surface at a SLOW, STEADY SPEED for 50 cm. Note the amount of force (in N) necessary to pull the object.
6. Step 5 must be repeated twice more. Put your findings in a table and on the class data spreadsheet.
REPEAT STEPS 1-6 FOR EACH SURFACE!
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According to the second law of thermodynamics, increases when energy is transferred from one form to another and some energy is lost as heat in the process.
According to the second law of thermodynamics, entropy increases when energy is transferred from one form to another and some energy is lost as heat in the process.
What is the second law of thermodynamics?The Second Law of Thermodynamics states that in an isolated system, the entropy of the entire system will increase over time a given period of time.
Entropy is a measure of the degree of randomness or disordeliness of a system.
According to the second law of thermodynamics, entropy increases when energy is transferred from one form to another and some energy is lost as heat in the process.
The second law of thermodynamics confirmed that as energy is transferred or transformed from one isolated system to another, the randomness of the system will increase.
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In which example would you be correct in describing an object in motion while
your friend would also be correct in describing that same object as being at
rest? *
a. you are driving a car toward the east and your friend drives past you in the opposite
direction with the same speed. in your frame of reference, you will be in motion. in
your friend's frame of reference, you will be at rest.
b. you are driving a car toward the east and your friend is standing at the bus stop. in
your frame of reference, you will be in motion. in your friend's frame of reference, you
will be at rest.
c. you are driving a car toward the east and your friend is standing at the bus stop. in
your frame of reference, your friend will be moving toward the west. in your friend's
frame of reference, he will be at rest.
d. you are driving a car toward the east and your friend is standing at the bus stop. in
o your frame of reference, your friend will be moving toward the east. in your friend's
frame of reference, he will be at rest.
The example that would be correct in describing an object in motion while your friend would also be correct in describing that same object as being at rest is option c. you are driving a car toward the east and your friend is standing at the bus stop. in your frame of reference, your friend will be moving toward the west. in your friend's frame of reference, he will be at rest.
What is an object in motion?Newton's first law of motion is known to be a law that is often known to be the law of inertia.
It is said to be one that states that an object that are found at rest are those that often stays at rest, and an object that are known to be in motion do often stays in motion and this is done in/with the same speed and in the same direction and it is only altered if it is said to be acted upon by a kind of an unbalanced force.
Option C was chosen because when one is moving in one direction in a vehicle, the object outside often moves in the opposite direction.
Therefore, The example that would be correct in describing an object in motion while your friend would also be correct in describing that same object as being at rest is option c. you are driving a car toward the east and your friend is standing at the bus stop. in your frame of reference, your friend will be moving toward the west. in your friend's frame of reference, he will be at rest.
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________ is a measure of your ability to work with and adapt to people from other backgrounds.
Answer:
Cultural intelligence
Explanation:
What is the voltage of a source which provides 12.0 J to each Coulomb of charge
present?
The voltage of the source is 12 Volts or 12 Joules per Coulomb.
The difference in electric potential between two points is known as voltage or electric potential difference.
In a static electric field, this difference is defined as the amount of work per unit of charge required to move a test charge between the two points.
Work per unit charge is expressed in SI units as joules per coulomb, with 1 volt equaling 1 joule of work per 1 coulomb of charge.
The voltage or potential difference between two points in a system can be measured using a voltmeter.
Given in the question
Energy provided = 12 J
Charge = 1 Coulomb
We know Voltage = (Energy or Work done)/(Charge)
Put in the value, we get
Voltage = 12/1 Volt or J/C
Voltage = 12 Volt
Hence, the voltage of the source is 12 Volts or 12 Joules per Coulomb.
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Helium-4 and Lithium -6 fuse to form a new product.
falling parachutist you bail out of the helicopter of example 3 and pull the ripcord of your parachute. now in eq. (3), so your downward velocity satisfies the initial value problem in order to investigate your chances of survival, construct a slope field for this differential equation and sketch the appropriate solution curve. what will your limiting velocity be? will a strategically located haystack do any good? how long will it take you to reach 95% of your limiting velocity?
You bail out of a helicopter and immediately open your parachute, so your downward velocity satisfies the initial value problem.
What is velocity ?Velocity is the rate of change in direction of an item in motion as seen from a specific point of view and as measured by a specific unit of time. In kinematics, the area of classical mechanics that studies how bodies move, velocity is a fundamental idea.
A physical vector quantity called velocity requires both magnitude and direction to be defined. Speed, a coherently derived unit whose quantity is measured in the SI (metric system) as metres per second, is the scalar absolute value (magnitude) of velocity. For instance, "5 meters per second" is a scalar while "5 meters per second east" is a vector.
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Convert the following number in scientific notation to standard notation: 3 × 10^3
ASAP I NEED IN 3 MINUTES PLS
The number 3 x 10 ³ in scientific notation can be written in standard notation as 3000.
What is Standard notation?Standard notation of a number is when a number is written with only number digits. For example - if the number is 2 x 10², then in standard from it can be written as 200.
Given is a number is a number in scientific notation. The number is -
3 x 10 ³.
Assume that the number -
A = 3 x 10 ³
and its expression in standard notation is B.
In order to write it in standard notation, we have to eliminate the 10ⁿ term which is 10 ³. 10 ³ can be written as 1000. Therefore, the number in standard notation will be -
A = 3 x 1000
A = 3000
Hence, in standard notation the number 3 x 10 ³ in scientific notation is 3000.
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!!Help pleaseee!!
Two cars start at the same point and drive in a straight line for 5 km. At the end of the drive their distances are the same but their displacements are different. Explain how this could happen. Illustrate with a diagram.
The two displacements are different because their direction can be different from each other even if their magnitude is equal.
Displacement is a vector quantity. Its magnitude is equal to the distance traveled by the body only if the body always travels in straight lines. Two displacements may be different even if their magnitude is the same but the direction in which they took place is different
So as we know, 'displacement' always consists of a magnitude and a direction. Given in the question, the two cars that start at the same point have displacements with the same magnitude that is equal to 5 km. But it could be possible that their displacements are different if they drive in different directions, which seems to be the case.
-- 12 m/s² towards the right and 12 m/s² towards the left are different accelerations
-- 30 Kph South-East and 30 Kph South-West are the same speed but different velocities as their directions are different.
-- 10 km North and 10 km South are the same distance but different displacements due to the same reasons.
Therefore the two displacements are different because their direction can be different from each other even if their magnitude is equal.
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Joanna claims that a large block of ice will cool a substance more than a small block of ice will at the same temperature. To support her claim, Joanna places two blocks of ice, one larger than the other, into separate beakers each containing some water. She compares the final water temperatures of the two beakers after each block of ice has melted.
She puts each block of ice in the same 3000 mL beaker, each with 2000 mL of water at room temperature, and measures the temperature before and after adding ice. Therefore, small blocks of ice will have the same temperature.
Joanna puts two blocks of ice (one larger than the other) into separate cups and fills each with water. She compares the final water temperature of the two cups after each block of ice melts.
Put each block of ice in the same 3000 mL beaker, each at room temperature, put 2000 mL of water in it, and measure the temperature before and after adding ice. This way you keep the water at the same temperature in the beginning, then the temperature changes after you add the ice, giving you a better idea of the final temperature reading.
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