Answer:
4
Explanation:
Codons are usually in groups of 3. So AUA-UCU-AGG-CUU
Answer: 5
also try using the 6.6-6.7 bio flashcards on quizlet they might help
Removes water from waste and puts it back into the body; waste turns into solid here. *
Which of the following will lead to a change in current scientific theory?
A. a small group of scientist who studies the theory can make changes
B. A change in the world’s opinion
C. A change in the scientific evidence regarding the theory
D. The person who originally developed the theory can make changes
Answer:
C: A change in scientific evidence regarding the theory.
The option c. A change in the scientific evidence regarding the theory resulted in the change in current scientific theory.
What is a scientific theory?It is a theory that should be explained for the observations for the natural world that should be constructed by using the scientific method.
Also when there is any change in the scientific evidence with respect to the theory so it should have resulted in the change in the current scientific theory.
Hence, the option c is correct.
Learn more about scientific here: https://brainly.com/question/4638840
Which of the following is true about budding? Check all that apply, *
- The offspring usually breaks away from the parent.
- Happens only in multicellular organisms.
- The offspring is genetically identical to the parent.
- Happens only in unicellular organisms.
- The offspring is not genetically identical to the parent.
- Happens in multicellular and unicellular organisms.
Answer:
1,3,4
Explanation:
They are all correct because of what they say
Which of the following accurately describes an example of a vestigial structure?
After the loss of a single eye, with one eye still present, a patient is still able to see with one eye. The patient complains of
reduced vision and depth perception after recovery.
A patient is having severe abdominal pain due to a ruptured appendix. The patient has an appendectomy, in which the
appendix is removed. The patient recovers and notices no life changes due to this surgery.
O A patient has a benign mass on the head of the pancreas. The mass is removed, along with a portion of the pancreas. This
results in reduced insulin production in the patient, causing them to be incapable of using glucose for energy, without the
aid of medication. The patient will be required to take an insulin shot once daily.
O A patient has heart disease, and therefore needs a heart transplant. The patient's heart is then removed and replaced with
a functioning mechanical heart. The patient will remain on organ transplant rejection pills for the remainder of his/her life.
Answer:
A patient is having severe abdominal pain due to a ruptured appendix. The patient has an appendectomy, in which the
appendix is removed. The patient recovers and notices no life changes due to this surgery.
The energy that fuels food webs begins as light energy from the sun. True or False
Answer: i think its true. ( based of information i got)
Explanation: The Sun is the major source of energy for organisms and the ecosystems of which they are a part. Producers such as plants, algae, and cyanobacteria use the energy from sunlight to make organic matter from carbon dioxide and water. This establishes the beginning of energy flow through almost all food webs. also A food web consists of many food chains. A food chain only follows just one path as animals find food. eg: A hawk eats a snake, which has eaten a frog, which has eaten a grasshopper, which has eaten grass. A food web shows the many different paths plants and animals are connected.
sorry if this was not what u were looking for or this is incorrect!:( have an nice day! UwU
♡ The Question ♡
-The energy that fuels food webs begins as light energy from the sun. True or False?
* ୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*
♡ The Answer ♡
-True!
*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*
♡ The Explanation/Step-By-Step ♡
-No Explanation/Step-By-Step provided!
*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*
♡ Tips ♡
-No tips provided!
As with Part H. you have a total body concentration of 300 mOsM and body volume of 3 liters. You now add 2 liters of a 500 mOsM solution. The solution is equal parts NaCI (nonpenetrating) and urea (penetrating), so it has 250 mosmol/L NaCI and 250 mosmol/L urea. Answer the following questions about your new solution:
Drag the terms on the left to the appropriate blanks on the right to complete the sentences.
The solution is_______ osmotic to the body.
What is the concentration of nonpenetrating solutes (NP) in the solution?
What is the internal concentration of the body's cells? (All intracellular solutes are nonpenetrating.)
When the cells reach equilibrium after addition of the solution to the body, has cell volume increased, decreased, or stayed the same?
Based on your answer regarding water movement, the solution was ____ tonic to the body's cells.
increased
hyper
300 mosmol/L
Stayed the same
300 mosmol/L
Hypo
lso
decreased
stayed the same
Answer:
- The solution is hyperosmotic to the body.
- What is the concentration of nonpenetrating solutes (NP) in the solution? 500 mosmol/L
- What is the internal concentration of the body's cells? (All intracellular solutes are nonpenetrating.) 300 mosmol/L
- When the cells reach equilibrium after addition of the solution to the body, has cell volume increased, decreased, or stayed the same? increased
- Based on your answer regarding water movement, the solution was hypotonic to the body's cells.
Explanation:
A hyperosmotic (or hypertonic) solution is a solution with a greater solute concentration. If a cell is placed in a hyperosmotic solution the water will leave the cell and the cell will shrink. Conversely, a hypotonic solution is a solution that has a lower concentration of solute. If a cell is placed in a hypotonic solution the water will enter the cell through osmosis and the cell increases in size. In this case, the NaCl is a non-penetrating solute, and thereby the concentration in the body's cells maintains constant. Moreover, urea is a penetrating solute, thereby it will penetrate in the cells until the equilibrium is reached (i.e., the cells will increase in volume).
A woman with a straight hairline has as child with a man who is heterozygous
and has a widow's peak.
What is the mother's genotype?
Answer:
aa
Explanation:
A widow's peak is the dominant genotype so one must not have that trait. If it was presented then the woman would have the genotype.
A widow's peak is dominant so the man would be either AA or Aa. Since it stated that his is heterozygous (Hetero meaning two different), his genotype would be Aa (again since a widow's peak is the dominant, it only needs one dominant genotype)
How can you use genetics to study human inheritance?
Answer:
by analyzing how genes influence the development of phenotypic traits, i.e., by determining the association between phenotypic traits and changes in DNA sequence
Explanation:
Genetics is a discipline that studies how genetic variation, i.e., the variation in the Deoxiriibunicleinc acid (DNA) molecule, is associated with the transmission of heredity, and how the environment influences this process. The DNA is a molecule that carries the instructions to perform all metabolic functions (eg., reproduction, development, growth, etc). Thus, advancements in genetics enabled us to decipher how phenotypic traits pass from parents/ancestors to their offspring/descendence. Genes are segments of DNA that carry the information (genetic information) to determine each phenotypic trait. During reproduction, genes are passed from one generation to the next, thereby transmitting this information across generations.
In cocker spaniels, black coat color ( B) is dominant over red ( b), and solid color ( S) is dominant over spotted ( s). In the F 2 generation of a cross between BB ss with bb SS, what fraction of the offspring would be expected to be black and spotted
Answer:
The correct answer is -3/16
Explanation:
The cross between BBss and bbSS In cocker spaniels will form gametes that are - Bs and bS. As it is given that black coat color ( B) is dominant over red ( b), and solid color ( S) is dominant over spotted ( s) then f1 gen would be :
Bs Bs
bS BbSs BbSs
bS BbSs BbSs
Now F2 generation;
BS Bs bS bs
BS BBSS BBSs BbSS BbSs
Bs BBSs BBss BbSs Bbss
bS BbSS BbSs bbSS bbSs
bs BbSs Bbss bbSs bbss
Here black-spotted that is possible only in two cases, BBss or Bbss, are 3/16
Sum It Up
3. There are multiple types of mutations in DNA.
mutations occur when a single base is
changed to a different base pair.
mutations remove one or more bases from a segment of DNA,
resulting in a frameshift mutation.
mutations are also considered frameshift mutations, and occur when
one or more extra bases are added to a segment of DNA.
Check Answer
Answer:
substitution, deletion, insertion (in that order)
Explanation:
I did the assignment-
Mutations occur when a single base is changed to a different base pair; mutations remove one or more bases from a segment of DNA, resulting in a frameshift mutation, so this is also correct in other statements.
What is the significance of the DNA mutation?Mutations in DNA lie in their ability to alter the genetic information, and that altered information is passed on to next generations while Some mutations have no effect on the function of the proteins, but some have serious effects. It helps in the evolution process by providing a mechanism for the development of new traits, etc., in nature, so it has a significant role in it.
Hence, mutations occur when a single base is changed to a different base pair; mutations remove one or more bases from a segment of DNA, resulting in a frameshift mutation, so this is also correct in other statements.
Learn more about the DNA mutation here.
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what is a electrocardiograph technician
which statement correctly describes a feature of the rock cycle?
1 rocks are preserved through the process
2 rocks change from one type to another
3 different rock groups are not related to one another
4 rocks change from one type to another in specific order
Answer:
Rocks change from one type to another in a specific order.
Explanation:
A rock cycle can be described as a process that follows a sequence or a specific order in which the various rocks are transformed from one type to another.
Need answer please asap
What will happen if you keep increasing the temperature of a liquid?
Question 6 options:
It will solidify (turn into a solid)
It will transpire
It will boil and become a gas
It will remain a liquid
Answer:
It will boil and become a gas
Explanation:
Answer:
I'm pretty sure it will boil and become a gas
Explanation:
Please me help ASAP.
Answer: the second answer
Explanation:
Where does a 'thought' go when forgotten
Answer:
It dont go anywhere because it never existed
Explanation:
its gone its gone
true or false: Sex cells are haploid because they only contain one set of unpaired chromosomes.
Answer:
true
Explanation:
remember- Haploid it sounds like half, so when you think of half, always think of sex chromosomes. 23 chrom.
diploid- well its the other one so yeah 46 chrom.
The difference between z and 8
Rachel drove 300 miles from her home to Philadelphia to visit her sister and then returned home a week later. At the end of the trip what was her displacement and distance traveled in that order
Answer:
The correct answer would be - zero miles, 600 miles.
Explanation:
She started from the same point and after the trip, she ended it on the same point in Philadelphia therefore the displacement is expected to be zero.
The distance she traveled would be 2 into 300 miles as she traveled to her sister and traveled back from there so
Distance = 2*300
= 600 miles.
Thus, the correct answer would be - 0 and 600 miles.
You produced 639 plants with the following phenotypes round yellow gray 269 round yellow white 98 round green, gray 86 wrinkled yellow gray 88 round green white 27 wrinkled yellow white 34 wrinkled green gray 30 wrinkled green white 7 The (observed-expected)2 was as follows round yellow white 65.61 round green gray 15.21 wrinkled yellow gray 3.61 round green white 8.41 wrinkled yellow white 16.81 wrinkled green gray 0.01 wrinkled green white 9.00 What is the chi-square value
Note about the question:
Among the (observed-expected)² list, there is one value missing. This value corresponds to round yellow gray plants, and equals 0.002. This number was included in the explanation of the problem.
Answer:
The chi-square value is X² = 2.6813.
Explanation:
Available information:
Observed individuals numbers:
Total number in the population: 639Round yellow gray 269 round yellow-white 98 round green, gray 86 wrinkled yellow gray 88 round green white 27 wrinkled yellow white 34 wrinkled green gray 30 wrinkled green white 7The expected numbers
ratio 27:9:9:9:3:3:3:1 round yellow gray 269.58 round yellow white 89.86 round green gray 89.86 wrinkled yellow gray 89.86 round green white 29.95 wrinkled yellow white 29.95 wrinkled green gray 29.95 wrinkled green white 9.98The (observed-expected) ² numbers
round yellow gray 0.002round yellow white 65.61 round green gray 15.2wrinkled yellow gray 3.61 round green white 8.41 wrinkled yellow white 16.81 wrinkled green gray 0.01 wrinkled green white 9.00To get the chi-square value, we just need to replace the terms in the following equation.
Chi square= ∑ ((O-E)²/E)
Where,
∑ is the sum of the terms O refers to the Observed number of individual E refers to the Expected numbers of individualsX² = ∑ ((O-E)²/E)
X² = (0.002/269.58) + (65.61/89.86) + (15.2/89.86) + (3.61/89.86) + (8.41/29.95) + (16.81/29.95) + (0.01/29.95) + (9/9.98)
X² = 0.0000074 + 0.73 + 0.17 + 0.04 + 0.28 + 0.561 + 0.0003 + 0.9
X² = 2.6813
Among the (observed-anticipated)² list, there's one price missing. This price corresponds to spherical yellow-grey plants and equals 0.002. This variety became protected withinside the clarification of the problem.
The chi-square value is [tex]X^ 2 =2.6813.[/tex]
Information given.
Observed people numbers:
Total variety withinside the population: [tex]639[/tex]
Round yellow grey [tex]269[/tex]
spherical yellow-white 98
spherical inexperienced, grey 86
wrinkled yellow grey 88
spherical inexperienced white 27
wrinkled inexperienced grey 30
wrinkled inexperienced white 7
wrinkled yellow white 34
The anticipated numbers
ratio 27:9:9:9:3:3:3:1
spherical yellow grey 269.58
spherical yellow white 89.86
spherical inexperienced grey 89.86
wrinkled yellow grey 89.86
spherical inexperienced white 29.9!
wrinkled yellow white 29.95
wrinkled inexperienced grey 29.95
wrinkled inexperienced white 9.98
The (observed-anticipated) 2 numbers
spherical yellow grey 0.002
spherical yellow white 65.61
spherical inexperienced grey 15.2
wrinkled yellow grey 3.61 spherical inexperienced white 8.41
wrinkled yellow white 16.81
wrinkled inexperienced grey 0.01
wrinkled inexperienced white 9.00
To get the chi-square value, we simply want to update the phrases withinside the following equation.
[tex]Chi square = Sigma((O - E) ^ 2 / E)[/tex]
Where,
[tex]Σ[/tex] is the sum of the phrases
O refers back to the Observed variety of individual
E refers back to the Expected numbers of people
[tex]X ^ 2 = Sigma((O - E) ^ 2 / E)[/tex]
[tex]X^ 2 =(0.002/269.58)+(65.61/89.86)+ Chi quare = Sigma((O - E) ^ 2 / E)[/tex]
Where,
Σ is the sum of the phrases
O refers back to the Observed variety of individual
E refers back to the Expected numbers of people
[tex]X ^ 2 = Sigma((O - E) ^ 2 / E)[/tex]
[tex]X^ 2 =(0.002 / 9.58)+(65.61/ 89.86) + (15.2/89.86)+(3.61/89.86)+(8.41/29.95)+ (16.81/29.95) + (0.01/29.95) + (9/9.98)[/tex]
[tex]X^ 2 =0.0000074+0.73+0.17+0.04+ 0.28 + 0.561 + 0.0003 + 0.9[/tex]
[tex]X ^ 2 = 2.6813[/tex]
What is chi-square?
Pearson's chi-square test is utilized to inspect the job of chance in creating deviations among noticed and anticipated values. The test relies upon extraneous speculation since it requires hypothetical anticipated that values should be determined.
Hence it clearly calculates the value of chi-square.
To know more about chi-square refer to the link :
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In 2Fe304, there are how many oxygen atoms?
Please help fasttttt!!!!!
7 Identify What type of eclipse is shown in
the diagram?
Answer:
I dont know
Explanation:
I need points :)
what are the effects on the ecosystem and what is being done to help
Answer:
A lot of ecosystems are dying because of deforestation and climate Change, but there are some organizations out there like 4ocean that clean up the ocean and restore the enviorment.
Explanation:
HELPPPPPPPPPPPPPPPPPPPPPPPP
Answer:
I believe the answer is A
Explanation:
Answer:
physiological responses are things that make you begin to sweat and make your heart rate increase
Explanation:
So im thinking its B and C
and if it isnt multiple choice go with B
Name 6 most dangerous chemical found in a U.S house hold?
Answer:
Antifreeze.
Bleach.
Drain Cleaners.
Carpet or Upholstery Cleaners.
Ammonia.
Air fresheners.
Explanation:
Answer:
Swallowing antifreeze (ethylene glycol) may cause damage to the heart, brain, kidney, and other internal organs. Inhaling antifreeze is not as dangerous, but may cause dizziness. Being a strong corrosive substance, bleach can affect the respiratory system if inhaled.
Which part of a plant is the least complex
Answer:
Cells are the least complex part of a plant :>
Explanation:
PLEASE HELP!!! "Prior to cell division, DNA must be replicated. List the steps of DNA replication here: (*hint: there are 5 steps)"
Answer:
Step 1: Replication Fork Formation
Step 2: Primer Binding
Step 3: Elongation
Step 4: Termination
? was only 4?
i hoped this will help you.
Which part of a flowering plant transports pollen to the unfertilized egg cells?
A geneticist is mapping the chromosomes of the newly captured gremlin. Stripe is heterozygous for three linked genes with alleles Ee, Hh, and Bb, that determine if gremlins are evil (E), have hair (H), and biting teeth (B). In order to determine if the three genes are linked, a standard testcross was done, and the 1000 offspring had the following genotypes: 48 ee Hh bb 36 ee hh Bb 400 ee Hh Bb 4 Ee Hh Bb 426 Ee hh bb 46 Ee hh Bb 38 Ee Hh bb 2 ee hh bb What is the recombination frequency between genes E and H
Recombination frequency determines if two genes are linked or if they segregate independently from each other. The recombination frequency between E and H is 8%
What are linked genes?Linked genes are those that are too close to each other in the same chromosome and they do not segregate independently.
These are the linked genes that do not exhibit an independent distribution, and they are inherited together more frequently.
What is recombination frequency?Recombination frequency can be defined as the crossing over events frequency occurring between two genes.
The value of recombination frequency indicates weather genes are linked or not. The maximum recombination frequency is always 50%.
When RF is 50% or more, we can assume that genes are not linked.
In the exposed example, we can recognize the parental gametes in the descendants because their phenotypes are the most frequent, while the double recombinants are the less frequent.
Parental)
400 ee Hh Bb
426 Ee hh bb
Double recombinant)
4 Ee Hh Bb
2 ee hh bb
Simple recombinant)
48 ee Hh bb
36 ee hh Bb
46 Ee hh Bb
38 Ee Hh bb
We will call Region I to the area between genes E and H and Region II to the area between genes H and B.
------------E------------H--------------B-----------
/---RI------//------RII-----/
To calculate the recombination frequency between E and H we just need to consider region I. We will call P1 to the recombination frequency in this region.
P1 = (R + DR) / N
Where:
R is the number of simple recombinants in this region, DR is the number of double recombinants in each region, and N is the total number of individuals.Now, let us analyze the information.
We know that individuals carrying double recombinant gametes are
Ee Hh Bbee hh bbWe know that the recessive parent from the testcross could only provide the following gametes ⇒ ehb
This leads us to assume that the followings are the double recombinant gametes from the trihybrid parent,
EHBehbSince these gametes are the product of a double recombination event in region I and II, we can assume that the parental gametes of the trihybrid individual are
eHbEhBHence the simple recombinant gametes in region I are
EHbehBNow, according to this analysis, we know that
Simple recombinants in region I
36 ee hh Bb
38 Ee Hh bb
Double recombinants
4 Ee Hh Bb
2 ee hh bb
Total number of individuals
N = 1000
Recombination frequency in Region I
P1 = (R + DR) / N
P1 = (38 + 36 + 4 + 2) / 1000
P1 = 80 / 1000
P1 = 0.08 = 8%
The recombination frequency between genes E and H is P1 = 8%
You can learn more about recombination frequency at
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What is the world's smallest country?
Answer:
Vatican City is the smallest country in the world, with an area of 526,235.6 square yards.
Explanation: