How many moles of HCL are in 18 grams? (Use the molar mass to convert miles to grams. Round you answer to 2 decimal places.)

Answer:

Its the first one. The cells are arranged for structure.

Explanation:

Animal cells do not need to maintain a shape since out bodies do it for us. Plant cells need something for structure.

Answer:

See explanation

Explanation:

Nucleosynthesis is the process that creates new atomic nuclei from pre-existing ones via nuclear reactions.

A nuclear reaction involves the nucleus of atoms. It means the transformation of one element to another.

In the image attached i have shown the equations representing the nucleosynthesis of O, Ne, Na and Mg.

The nucleosynthesis of O involves the bombardment of C-12 with alpha particles, gamma rays are produced.

The nucleosynthesis of Ne involves the bombardment of O-16 with alpha particles, gamma rays are produced.

The nucleosynthesis of Na involves the bombardment of Ne-20 with alpha particles, protons are produced.

The nucleosynthesis of Mg involves the bombardment of Ne-20 with alpha particles, gamma rays are produced.

Answer:

16.86%

Explanation:

Na3N is sodium nitride.

% of N = mass of N/ molar mass of Na3N *100

% of N = 14/83*100= 16.86%

The percent composition of nitrogen in sodium nitride is 16.86%

Sodium nitride is an inorganic compound that is used in preservatives and antidote for cyanide poisoning.

The molar mass of Na3N is 83 M

The mass of Na3N is 14 g

[tex]% \;of \;N = \dfrac{mass of N}{ molar mass of Na3N } \times 100[/tex]

[tex]\% \;of \;N = \dfrac{mass\; of \;N}{molar\; mass\; of\; Na3N} \times 100\\\\\\\% \;of \;N = \dfrac{14}{83} \times 100 = 16.86\%[/tex]

Thus, the  percent composition of nitrogen in sodium nitride is 16.86%.

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Answer: D) 1.30 and 2.60

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in ml

molarity  of [tex]MgCl_2[/tex] = [tex]\frac{0.325\times 1000}{250ml}=1.30 M[/tex]

[tex]MgCl_2\rightarrow Mg^{2+}+Cl^{-}[/tex]

As 1 mole of [tex]MgCl_2[/tex] dissociates to give one mole of [tex]Mg^{2+}[/tex] and two moles of  [tex]Cl^-[/tex] ions .

Molarity of [tex]Mg^{2+}[/tex] = 1.30 M

Molarity of [tex]Cl^{-}[/tex] = [tex]1.3 M\times 2=2.60M[/tex]

Answer:

Decreases

Explanation:

F = GM1M2/R²

please mark me brainliest and 5 star

Answer: selenium dichloride

Explanation:

Response:

Sorry but I think you forgot to attach or include something, thanks for the points tho!

Other:

Brainliest? Thanks!

Answer:

How do you determine the overall order of a reaction?

The overall order of the reaction is found by adding up the individual orders. For example, if the reaction is first order with respect to both A and B (a = 1 and b = 1), the overall order is 2. We call this an overall second order reaction.

Explanation:

Answer:

A or C.... Any one. If i am wrong let me know!

Answer:

(d) catapleurotic

Explanation:

Phosphoenolpyruvate carbokinase (PEPCK) is usually used in the conversion of oxaloacetate to phosphoenolpyruvate (an important intermediate in glycolysis and gluconeogenesis, C₃H₅O₆P). The main function of this catapleurotic enzymes is in the catalysis of the forward conversion of oxaloacetate to phosphoenolpyruvate.

Answer:

Explanation:

One that forms over the Indian Ocean is called a maritime tropical air mass and is warm and humid. Air masses are classified on weather maps using two or three letters. A lowercase letter describes the amount of moisture in the air mass: m for maritime (moist) and c for continental (dry).

The letter 'c' of an air mass represents moisture content.

An air mass can be described as a volume of air defined by its humidity and temperature. Air masses are classified depending on latitude and their continental or maritime source regions. Warmer air masses are deemed tropical while Colder air masses are termed polar or arctic.

The maritime and monsoon air masses are moist while Continental and superior air masses are dry. When an air mass will move away from its source region, water bodies and underlying vegetation can quickly modify its character.

The first letter "c" represents its moisture properties in continental air masses (dry) while "m" represents maritime air masses. The letter "T" stands for Tropical, "A" stands for Arctic or Antarctic,  "E" stands for Equatorial, "P" stands for Polar, "M" stands for monsoon, and "S" stands for adiabatically drying and warming air.

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Answer:

f = 0.084 s⁻¹

Explanation:

Given data:

Frequency of light = ?

Wavelength = 35.6 m

Solution:

Formula:

Speed of light = wavelength × frequency

Speed of light = 3× 10⁸ m/s

by putting values,

3× 10⁸ m/s = 35.6 m ×  f

f = 3× 10⁸ m/s / 35.6 m

f = 0.084 s⁻¹

The number of moles of acetone is 4.1 moles.

Let us recall that specific gravity refers to the ratio of the density of a substance to the density of water. Also noting that the density of water has been set to 1 g/mL, the density of the acetone solution is 0.784 g/mL.

Density = mass/volume

mass = Density * volume

mass = 0.784 g/mL *  300.0 mL

= 235.2 g

Number of moles = mass/molar mass

Molar mass of acetone = 58 g/mol

Number of moles of acetone = 235.2 g/ 58 g/mol

= 4.1 moles

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Answer:

A and B

Explanation:

Trust me I just did it on a p e x

Answer: he’s correct it’s d and b for me but it’s the same answers

Explanation:

Answer:

Following are the solution to the given points:

Explanation:

In point a, the answer is only ions because of [tex]NH_4Cl[/tex] has a strong electrolyte.

In point b, the answer is the only molecules because of ethanol [tex]CH_3CH_2OH[/tex], it has a nonelectrolyte.

In point c, the answer is the few ions because of hydrocyanic acid HCN, which has a weak electrolyte.

(a) Only ions.

(b) Only Molecules.

(c) Few ions.

(a) In this, only ions should be considered as it contains strong electrolyte.

(b) In this, only molecules should be considered as it contains non-electrolyte.

(c) In this, few ions should be considered due to hydrocyanic acid HCN, that contains weak electrolyte.

Therefore we can conclude that

(a) Only ions.

(b) Only Molecules.

(c) Few ions.

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Answer:

vapor pressure of methanol at 12.0C = 75.09 torr

Explanation:

Using Clausius Clapeyron equation

, we have that

ln (P2/P1)= (ΔHvap /R) (1/T1 - 1/T2)

Given

At Normal boiling point,

Temperature T1= 64.6°C = 64.6 + 273 = 337.6 K, Pressure,P1 = 1 atm

Heat of vaporization  = 35.2 kJ/mol

Changing to  J/mol

=35.2 x 1000= 35200 J/mol

Temperature , T2 = 12.0oC = 12 + 273 = 285 K

Using gas constant, R = 8.314 J/mol.K

ln (P2/P1)= -(ΔHvap /R) (1/T1 - 1/T2)

ln (P2/ 1 atm) = (35200 J/mol/ (8.314 J/mol.K) X( 1/337.6 - 1/285)

ln (P2/ 1 atm) =4,233.822 X (0.00296-0.003508)

ln (P2/ 1 atm)  = 4,233.822468  x-0.0005466866

ln (P2/ 1 atm)=  -2.31457

P2 = e^⁻2.31457 x 1 atm

P2=0.098808atm

= 0.098808atm  x760 = 75.09 torr

Answer:

Add Items to it

Explanation:

Lol I took the test. Sorry If I'm incorrect

Answer:

add items to the box to increase its mass on the self it is on

Explanation: :p

The energy produced by burning : -32.92 kJ

Delta H reaction (ΔH) is the amount of heat change between the system and its environment

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)

The enthalpy and heat(energy) can be formulated :

[tex]\tt \Delta H=\dfrac{Q}{n}\rightarrow n=mol[/tex]

The enthalpy of combustion of naphthalene (MW = 128.17 g/mol) is -5139.6 kJ/mol.

The energy released for 0.8210 g of naphthalene :

[tex]\tt Q=\Delta H\times n\\\\Q=-5139.6~kJ/mol\times \dfrac{0.8210~g}{128.17~g/mol}~\\\\Q=-32.92~kJ[/tex]

The mass of a single bromine molecule, Br₂ is 2.654 x 10⁻²² g.

Bromine is a diatomic element. It has a symbol Br and the atomic number is 35. Bromine is a naturally occurring element which is liquid at room temperature.

Molar mass of Br₂ is 159.808 g/mol. The molar mass of bromine is 79.904 g/mol. In Br₂, there are two bromine atoms.

To calculate the mass of a single bromine molecule -

In 1 mole of Br₂, there is Avogadro's number of molecules.

Avogadro's number = 6.022 x 10²³

Therefore, 1 mole = 6.022 x 10²³

1 mole of bromine has mass of 79.9 g/mol

So, it gives us -

1/6.022 x 10²³ = 1.66 x 10²³/79.9 = 2.654 x 10⁻²²g

For the mass of a single bromine molecule, Br₂ = 2.654 x 10⁻²² g

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Explanation:

A chemical change is a change in which a new kind of substance is produced. Such changes are always accompanied by energy changes.

They are mostly reversible.

Some examples of such reactions are combustion, rusting of iron, precipitation, rancidity of butter, souring of milk.

Answer:

D. Each jar contains the same number of atoms

Explanation:

Each of jar containing 1 mole of the element has consisted of an equal number of atoms.

Each jar has been consisted of 1 mole of gas. The number of atoms in a mole of gas can be calculated with Avogadro's number.

Avogadro number has been the constant, that relates the particles and the sample constituents. The value of the Avogadro number has been [tex]\rm 6.023\;\times\;10^2^3[/tex] .

1 mole of gas = Avogadro's number molecules

Thus, each of them containing 1 mole of the element has consisted of an equal number of atoms.

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Answer:

Polonium

Selenium

Sulfur

Oxygen

Explanation:

If you see in the Table S of the periodic Table there is a column that says First Ionization Energy (kJ/mol) and you can see the numbersof these elements so then you just put it in order

Polonium 812

Selenium 941

Sulfur 1000

Oxygen 1314

The theoretical yield (in kilograms) of water produced from this reaction : 0.285 kg

Reaction

2C₁₂H₂₄O₁₁ + 25O₂ → 24CO₂ + 24H₂O

mass of C₁₂H₂₄O₁₁ - isomaltitol = 454 g

mol C₁₂H₂₄O₁₁(MW=344.31 g/mol) :

[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{454}{344.31 g/mol}\\\\mol=1.319[/tex]

mol H₂O based on C₁₂H₂₄O₁₁ as limiting reactant(O₂-oxygen as an excess)

From the equation above, mol ratio of C₁₂H₂₄O₁₁  : H₂O = 2 : 24, so mol H₂O:

[tex]\tt mol~H_2O=\dfrac{24}{2}\times 1.319=15.828[/tex]

then mass H₂O (MW=18 g/mol) :

[tex]\tt mass=mol\times MW\\\\mass=15.828\times 18=284.904~g=0.285~kg[/tex]

This question is incomplete, the complete question is;

In a typical calorimetry experiment (similar to what you did with the combustion of cheese balls), a small bag of Skittles (10.0 g) was combusted and the temperature of the water (1.00 kg) increased by 40.0 °C.

a) How much energy (in calories and Food calories) was released by the combustion of the Skittles

b) How many small bags of skittles would a 140 lb person have to eat in order to equal the amount of food calories burned by walking a marathon?

Marathon = 26.2 miles, average person burns 0.453 food calories/mile pound)

Answer:

a)

Number of calories = 40000 Cal

Number of food calorie = 40 KCal

b)

41.54 bags of skittles are required

Explanation:

Given that;

mass of water = 1kg = 1000g

change in Temp ΔT = 40°C

specific heat of H₂O = 4.84 = 1 Cal

Now

heat absorbed by the water = MSΔT

= 1000gm × 1 cal × 40°C = 40000 Cal

so

Number of calories = 40000 Cal

(since food calories = 1000 small calories)

so

Number of food calorie = 40 KCal

Next

number of mile lb , if the man runs in the marathon will be;

26.2 × 140

= 3668 mile lb  

0.453 food calorie is burned for 1 mile pound.

So, amount of food calorie required if the man runs in the marathon will be

0.435 × 3668 mile lb

= 1661.60 food calires.

now

40KCal food calorie is released by 10gm.

So, 1661.60 cal will be released from

⇒ (10gm × 1661.60) / 40 = 415.4 gm

now

1 bag = 10gm,

therefore 415.4 gm = 41.54 bags

∴ 41.54 bags of skittles are required

Answer:

d. all of the above are levels of organization

Explanation:

The followings are the levels of the organization in an ecosystem

1. Individual

2. Population

3. Community

4. Ecosystem

5. Biome

6. Biosphere

So as per the given situation, it involved all three levels that are mentioned in the question

hence, the correct option is d.

Therefore the same is to be considered

The given option are all consisting in the level of organization of ecosystem. Thus, option D is correct.

The ecosystem has been the geographical representation comprising plants, animals, and other biotic and abiotic components.

The ecosystem has been organized in the levels for the understanding of the working and the activity of the ecosystem. The levels of the ecosystem has been:

The organizational levels of the ecosystem have been comprised of community, population, and ecosystem. Thus all the given are level or organizations in the question. Thus, option D is correct.

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Answer:

In first shell only 2 electrons are present in hydrogen only one electron is present in valence shell. To complete its duplet hydrogen can share lose or gain only one electron to form chemical bond.

Hydrogen can form only one bond.

Explanation: