if a resistor with a current of 20 ma through it converts 12 j of electrical energy into heat energy in 60 s, what is the voltage across the resistor?

Answer:

6000 meters

Explanation:

Because 6kilometers is 6000 maters

D. The distance traveled by the baseball during the given time is 62.32 m.

The distance traveled by the baseball is calculated as follows;

s = vt - ¹/₂gt²

where;

The given parameters;

v, initial velocity of the baseball = 85 mph = 38 m/s

g is acceleration due to gravity = 9.8 m/s²

t is the time of motion, = 5.4 seconds

Substitute the given parameters and solve for the distance travelled by the baseball as shown below.

s = (38 m/s)(5.4 s) - ¹/₂(9.8 m/s²)(5.4 s)²

s = 205.2 - 142.88

s = 62.32 m

Thus, the distance traveled by the baseball during the given time is 62.32 m.

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The capacitor's energy becomes 0.5 J when the dielectrics have been inserted between its plates.

The quantity of energy held in the form of an electric charge in an electric device is referred to as capacitance.

Data provided

C = 10 mF = 0.01 F is the parallel-plate capacitor's capacitance.

V' = 20 V is the power supply's potential.

The material has a dielectric constant of 4.0.

First, let's determine the charge that the capacitor has stored:

[tex]C^{\prime}=\epsilon \times C[/tex]

Solving as,

[tex]\begin{aligned}&C^{\prime}=4.0 \times 0.01 \\&C^{\prime}=0.04 \mathrm{~F}\end{aligned}[/tex]

Now, the expression for the energy stored in the capacitor is,

[tex]U^{\prime}=\frac{q^2}{2 C^{\prime}}[/tex]

Hence

[tex]\begin{aligned}U^{\prime} &=\frac{0.2^2}{2 \times 0.04} \\U^{\prime} &=0.5 \mathrm{~J}\end{aligned}[/tex]

Thus, we may say that the capacitor's energy reserves are 0. 5J

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The two displacements are different because their direction can be different from each other even if their magnitude is equal.

Displacement is a vector quantity. Its magnitude is equal to the distance traveled by the body only if the body always travels in straight lines. Two displacements may be different even if their magnitude is the same but the direction in which they took place is different

So as we know, 'displacement' always consists of a magnitude and a direction.  Given in the question, the two cars that start at the same point have displacements with the same magnitude that is equal to 5 km.  But it could be possible that their displacements are different if they drive in different directions, which seems to be the case.

-- 12 m/s² towards the right and 12 m/s² towards the left are different accelerations

-- 30 Kph South-East and 30 Kph South-West are the same speed but different velocities as their directions are different.

-- 10 km North and 10 km South are the same distance but different displacements due to the same reasons.

Therefore the two displacements are different because their direction can be different from each other even if their magnitude is equal.

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The correct answer is d = 41.8m

The phrase "displacement" refers to a change in the location of an object. It is a magnitude and direction vector quantity. It is represented with an arrow pointing from the beginning to the finish.

The spatial distance between two points is measured via the shortest path between them. Because it is a vector quantity, it has a magnitude and a direction.

Given,

[tex]V_1[/tex]= 7.5 m/s

[tex]t_1[/tex]= 2.4 s

[tex]V_2[/tex] = 6.8 m/s

[tex]t_2[/tex] = 3.5 s

[tex]V_1 = d_1/t_1[/tex]

[tex]d_1 = V_1t_1[/tex]

[tex]d_1[/tex] = 7.5 m/s (2.4 s)

[tex]d_1[/tex]= 18 m

[tex]V_2[/tex] = [tex]d_2/t_2[/tex]

[tex]d_2 = V_2t_2[/tex]

[tex]d_2[/tex] = 6.8 m/s (3.5 s)

[tex]d_2[/tex]= 23.8 m

Total displacement d = [tex]d_1 + d_2[/tex]

d = 18m + 23.8m

d = 41.8m

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Answer:

Time to reach ground = t = 6 sec

Explanation:

Acceleration due to gravity = g = 9.8 m/s²

Initial Velocity of the Rock = Vi = 0 m/s (Because, the rock will be at rest, initially)

When a rock is dropped and takes 6 seconds to touch the ground, its maximum speed will be [tex]6^{th}[/tex] second.

The force of gravity causes a rock to accelerate when it is dropped from a cliff. On Earth, the acceleration caused by gravity is roughly 9.8 meters per second squared (m/s2). This indicates that the rock's speed increases by 9.8 m/s per second as it falls.

According to the question, it takes the rock 6 seconds to hit the ground. It takes the rock exactly this long to fall from the cliff to the ground.

One must comprehend that the rock's speed rises steadily as it falls in order to determine the moment at which it is moving at its fastest. The rock's initial velocity (Vi) is 0 m/s because it begins at rest. The acceleration brought on by gravity causes it to move faster as it drops.

The rock will reach its highest speed just before it touches the ground because its velocity is constantly rising. As a result, the rock is moving at its fastest at the moment of impact (t = 6 sec).

Thus, the maximum speed will be at T= 6 seconds.

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The speed at which the driver must drive for the remaining time to complete the trip in the usual time is 61.25 miles per hour.

The total distance the driver should cover is 500 miles and this should be completed in 9 hours.

Based on the information provided, the regular speed is:

However, we know today he has covered 110 miles and he is 20 minutes late. This means, there are 390 miles to cover and the remaining time is 6.7 hours.

Based on this, let's calculate the new speed:

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When a light source falls on an object if it is a opaque object it will form shadow.

And the light falls on the largest cardboard there will be a big shadow formed in the wall. Now when we take a second cardboard the shadow will form in accordance with that cardboard that if the cardboard is more it will form small shadow

And when we do with the same third cardboard or small cardboard the shadow will be according to the size of the cupboard now when we keep a plastic shopping bag in between the light source and the wall if the plastic bag is transparent the light will pass through the plastic bag and if the plastic bag is opaque the light will not pass through the bag and a shadow will be not be formed

Here we can conclude that if a light is passing through a pack object the light cannot pass through the object and it will format shadow but when the light is passing through a transparent object that light will pass through the object and there will be no shadow formed

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The voltage of the source is 12 Volts or 12 Joules per Coulomb.

The difference in electric potential between two points is known as voltage or electric potential difference.

In a static electric field, this difference is defined as the amount of work per unit of charge required to move a test charge between the two points.

Work per unit charge is expressed in SI units as joules per coulomb, with 1 volt equaling 1 joule of work per 1 coulomb of charge.

The voltage or potential difference between two points in a system can be measured using a voltmeter. 

Given in the question

Energy provided = 12 J

Charge = 1 Coulomb  

We know Voltage = (Energy or Work done)/(Charge)

Put in the value, we get

Voltage = 12/1 Volt or J/C

Voltage = 12 Volt

Hence, the voltage of the source is 12 Volts or 12 Joules per Coulomb.

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The friction force that is exerted on the car's rotating wheels causes an imbalanced force to be applied to the vehicle, which then accelerates. The center of the circle the car is turning is the target of both the unbalanced force and the acceleration. Your body, however, continues to move and is in motion.

An object's motion may vary if an imbalanced force is applied to it. The small car will alter speed, direction, or even halt if a heavier, faster toy car moves into its path or along its side. The small toy car is being subjected to a stronger force, which is why its motion has changed.

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Answer: Option 4 (last graph)

Explanation:

1. Since you're driving at a constant speed, the line for your car will be linear. This rules out the first option.

2. This is a position time graph (x-t) graph. This means that to be moving forwards, there should be a positive slope. Option 3 can be eliminated as your car has a slope of 0. A slope of 0 on a position time graph shows an object at rest, not an object in motion.

3. The 2nd option can be ruled out as it represents that you are going faster than the other car. The steeper the slope = the faster the speed.

4. This ultimately leaves you with the last option as your final answer!

The negatively charged electric plate is avoided in favor of the positively charged electric plate by the cathode ray. Thomson was able to estimate the mass-to-charge ratio of the particles by measuring the degree to which the ray was refracted by a magnetic field.

The negatively charged electric plate is avoided in favor of the positively charged electric plate by the cathode ray. Thomson was able to estimate the mass-to-charge ratio of the particles by measuring the degree to which the ray was refracted by a magnetic field.

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The exit area of the nozzle is 0.000861 m² which is calculated using ideal gas equation.

Velocity = 280 m/s

Rate = 2.5 kg/s

Pressure = 2 MPa

Temperature = 400°C

Using equation of Ideal gas

PV= RT

V= RT/P

V= 0.0965 [tex]m^{3}[/tex]/ kg

Using equation of continuity

(dm/dt) = [tex]A_{1}[/tex]v/V

[tex]A_{1}[/tex]= 0.000861 [tex]m^{2}[/tex].

A theoretical gas known as an ideal gas is made up of several randomly moving point particles with no interparticle interactions. Because it abides by the ideal gas law, a condensed equation of state, and is amenable to statistical mechanics analysis, the ideal gas concept is helpful.

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Amount of work done required to raise one end of the chain is 158.6 J

Work is said to be done when a  force act on a body and it displaced from its position.

It's unit is joule.

W = F × S

where

W = work done

F = force applied

S = displacement

Force acting on the chain with respect to the distance is given by

F = mgx / 10

m is mass

m = 90 kg

g is gravity (9.8 m/s2 for g.)

90× 9.8× x / 10

F = 88.2x Newton

To calculate the amount of work done.

[tex]W = \int\limits^f_i{F(x)} \, dx[/tex]

[tex]W = \int\limits^6_0 {F(x)} \, dx[/tex]

[tex]W = 88.2\int\limits^6_0 {x} \, dx[/tex]

[tex]W = 88.2 | \frac{x^2}{2}|^{6} _{0}[/tex]

W = 88.3( 6² - 0²)/2

W = 88.2 (36- 0) /2

W = 88.2 × 18

W = 158.6 J

Amount of work done required to raise one end of the chain is 158.6 J

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The average velocity of Tim is 1 m/s.

Average velocity is the ratio of total displacement to total time.

The S.I unit of velocity is m/s.

To calculate the average velocity, we use the formula below.

Formula:

Where:

From the question

Given:

Substitute these values into equation 1

Hence, the average velocity of Tim is 1 m/s.

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The work done by polytropic process is -69.88 kJ.

The work for the polytropic process is determined using  

P . v^n = constant.

where P is pressure, V is specific volume

As we know that

W = m∫Pdv

W = m(P2v2 - P1v1) / (1 - n)

In order to evaluate this expression, we need to determine the specific volumes and the polytropic exponent, n.

State 1: v1 = vg1 = 0.0993 m3/kg

State 2: at 12 bar, 80oC; v2 = 0.02051 m3/kg

Hence by using polytropic exponent

P1 / P2 = (v2 / v1)^n

n = ln(2/12) / ln(0.02051/0.0993)

n = 1.136

Find the work done

W = m(P2v2 - P1v1) / (1 - n)

W = 2kg(12bar . 0.02051m³/kg - 2 . 0.0993) / (1 - 1.136) x (10⁵ N/m²/1 bar) x (1 kJ / 10³ Nm)

W = -69.88 kJ

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Answer:

it should be true

Explanation:

:) hope it's right

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force applied on the item determines the object's acceleration.

A train starts from rest and accelerate uniformly until it attains a velocity of 8m/s in 10 seconds. calculate the acceleration of the train​.

a = 8/10

a = 0.8m/s2

The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t). This enables you to calculate the change in velocity in meters per second squared (m/s2). Since acceleration is a vector quantity, both its magnitude and its direction are included.

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Force, Friction (static and kinetic), (balanced and unbalanced).

Materials - Tape, spring scales, measuring tape, string, wooden blocks, wooden blocks with sandpaper on the bottom, and different surfaces.

Procedure - 1. To test and gather information on surface friction, each group will look at four distinct surfaces (a concrete floor, a lab desk, a lab floor, and a carpet).

2. Each item should have a string firmly tied around it (a plain block of wood and the wood with sandpaper). Connect the string's looped end to the spring scale.

3. The 50 cm measuring line should be fastened to your surface. Your beginning point will be in the front, and your finishing point will be at the back.

4. Pull the unadorned wood block across the designated surface at a SLOW, STEADY SPEED for 50 cm. Note the amount of force (in N) necessary to pull the object.

5. Pull the wood block with the sandpaper on it across the designated surface at a SLOW, STEADY SPEED for 50 cm. Note the amount of force (in N) necessary to pull the object.

6. Step 5 must be repeated twice more. Put your findings in a table and on the class data spreadsheet.

REPEAT STEPS 1-6 FOR EACH SURFACE!

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The quarterback will throw the ball 44.4 yards in a particular direction with the angle of  54.16 °

We shall use the ideas connected to the vector sum to develop this issue. To achieve this, we will add the person's displacement vectors to determine the total distance he has gone from the initial point (0 position) to the destination position.

[tex]\overrightarrow R[/tex] =  [tex](+1.0 \^{i} - 5\^{j}) + (7\^{i}) + (+12\^{j}) + (6.0\^{i} + 4.0\^{j}) + (+ 12.0\^{i} + 18.0\^{j})[/tex]

[tex]\overrightarrow R[/tex] = [tex]26\^{i} + 29\^{j}[/tex]

subtracting the quarterback's position [tex]\overrightarrow Q[/tex]

[tex]\overrightarrow Q[/tex] = [tex]-7.0\^{j}[/tex]

We can now get the relative location of the two individuals by subtracting the vectors; hence, the position between the individual and the quarterback is

[tex]\overrightarrow R[/tex] - [tex]\overrightarrow Q[/tex] =  [tex]26\^{i} + 29\^{j}[/tex] - ([tex]-7.0\^{j}[/tex])

          = [tex]26\^{i} + 36\^{j}[/tex]

The magnitude of the relative distance would be calculated using vector characteristics

[tex]|\overrightarrow R - \overrightarrow Q|[/tex] = [tex]\sqrt{26^2 + 36^2}[/tex]

[tex]|\overrightarrow R - \overrightarrow Q|[/tex] = 44.40 yards

The vector's direction would be determined by the tangent of the two vectors, which is

[tex]\theta = tan ^{-1} (\frac{36}{26} )[/tex] = 54.16°

As a result, with regard to 54.16 °, the quarterback will throw the ball 44.4 yards in one direction.

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Full question

At Enormous State University (ESU), the football team records its plays using vector displacements, with the origin taken to be the position of the ball before the play starts. In a certain pass play, the receiver starts at +1.0 i^ - 5.0 j^, where the units are yards, i^ is to the right, and j^ is downfield. Subsequent displacements of the receiver are +7.0 i^ (in motion before the snap), +12 j^ (breaks downfield), ?6.0i^+4.0j^ (zigs), and +12.0i^+18.0j^ (zags). Meanwhile, the quarterback has dropped straight back to a position ?7.0j^.

Part A

How far must the quarterback throw the ball? (Like the coach, you will be well advised to diagram the situation before solving it numerically.)

Part B

In which direction must the quarterback throw the ball?

Answer:  Problem 03.043 - Velocity-time graph The figure shows a plot of vx(for a car traveling in a straight line. Vx (m/s) 20 | 15 20 7(s) What is aav.x between t = 9.00 s and t = 110 s? 7 m/s2 What is Vav,x for the time interval from t= 9.00 s to r= 110 s? What is Vav.x for the interval t = 0 to t= 15.0 s? m/s What is the increase in the car's speed between 10.0 s and 15.0 s? m/s How far does the car travel from time t = 100 s to t = 170 s?

The answer is 03.043 but i dont know maybe my brain is incorrect but I got 03.043. :| hope it helped if its correct.

Explanation: Well, I havent done math in a while bc im not in school anymore so i forgot all that stuff :|

Answer:

you did not show a timeline luckly i did the the quiz it is the second timeline

Explanation:

Answer:

b

Explanation:

I did the test

Answer:

If a stream channel is 5 meters wide and 3 meters deep, and the velocity of the water moving through the channel is 10 meters/second, what is the stream's discharge (include units)? ... and deposition (point bars) occurs on the inside

Explanation:

A car is travelling with a acceleration of 4 m/s². Assuming the car starts from rest, The time need to accelerate to the speed of 40 m/s is (t)=10 s.

Time is a scalar quantity. its shows the period when the process happened. It can be measured in hour, minute, seconds etc.

To calculate the time need to accelerate to the wanted speed we are using the formula, v=u+at

Here we are given,

u= the initial velocity of the car = 0m/s [Note: the car starts from rest]

a= the  acceleration of the car = 4 m/s².

v= the final velocity of the car = 40 m/s.

we have to calculate the time need to accelerate to the wanted speed =t

Now, we put the values in the above equation,

v=u+at

Or, t= v/a [Note: u=0]

Or, t= 40/4

Or, t=10 m/s.

From the above calculation, we can say that the time need to accelerate to the wanted speed is (t)=10 s

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The value of the normal force on the object of mass 50 kg such that it experiences a friction force of 5 Newton is equal to 490 Newton.

Friction force is a force that opposes the force. It acts in the direction opposite to the intention of the motion of the object ,it is a non conservative force in nature.

Normal force is a type of force that's perpendicular to the surface of the object when it is placed in contact with another surface the SI unit of normal force is the same as force in general that is Newton.

Given:

Surface area of the sphere = 6 u

Mass of the sphere = 50 kg

First we use the mass value of the sphere, we will calculate the value of the weight of a sphere so that we know force against which against which the normal force will be acting.

Weight of the sphere = 50 × 9.8

Weight of the sphere = 490 Newton

Now since the normal force is being used to balance of the weight of the sphere we can say that the value of the normal force will be equal to 490 Newton.

Therefore, The value of the normal force on the object of mass that it experiences a friction force of 5 Newton is equal to 490 Newton.

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The points at which  Claire's weight balanced the force of air resistance are 2, 3 and 5. The sum of these points is 10.

We know that force is a vector quantity. This implies that force has both magnitude and direction. The direction of the force determines the sign that the force would carry. In this case there are two forces that acts on Claire as she jumps out of the parachute. These two forces are the  Claire's weight balanced and the force of air resistance.

The two forces tend to act in the opposing directions. The points at which the two forces are balanced, the speed time graph shows a plateau to indicate that the speed is not changing with time.

The points at which  Claire's weight balanced the force of air resistance are 2, 3 and 5. The sum of these points is 10.

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The amount of metal in a closed cylindrical can that is 10 cm high and 4 cm in diameter if the metal on the top and the bottom is 0.1 cm thick and the metal on the sides is 0.05 cm thick is 8.8 cm.

The formula for calculating the volume of a cylinder is given below.

V = πr^2 h

Get the differential of the volume as shown:

dV = V/ h dh + V / r dr

V/ h = πr^2

V/ h  = 2  πr h

Now, the differential becomes

dV =  πr^2dh +  2πrh dr

Given the following parameters i.e. diameter and height

dh = 0.1 + 0.1 = 0.2 cm

dr = 0.05 cm

h = 10 cm

d = 4 cm  

r = 2cm

Substituting the values in the above equation, we get

dV = 3.14(2)^2(0.2)  + 2(3.14)(2)(10)(0.05)

dV = 2.512 + 6.28

dV = 8.792 cm

dV = 8.8 cm

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The amount of gravitational potential energy lost when a pound of water falls from the top of the falls to the bottom is 233.55 Joules.

The gravitational potential energy of a body is due to virtue of its position. A body of mass 'm' at height 'h' is given by -

P.E. = mgh

Given in the is Niagara falls which 170 feet tall. A pound of water falls from the top of the falls to the bottom of the fall. From this we can write -

Height of Niagra falls = 170 feet tall = 51.81 m

Mass of water = 1 pound = 0.46kg

Assume that the potential energy of the pound of water at 170 feet tall is (P[1]) and that at the bottom is (P[2]).

Now, at the top of falls, the potential energy of 1 pound of water = P[1] =

m x g x h = 0.46 x 9.8 x 51.81 = 233.55 J

At the bottom of the falls -

P[2] = 0

The amount of gravitational potential energy lost =  P[1]  -  P[2] =

233.55 - 0 = 233.55 joules.

Therefore, the amount of gravitational potential energy lost when a pound of water falls from the top of the falls to the bottom is 233.55 Joules.

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Answer:

Cultural intelligence

Explanation: