Answer:
1 x 10¹⁷
Explanation:
Given data:
Radius of the earth = 6000km
Radius of an atom = 60pm
Now, how many orders is the radius of the earth larger than an atom
Solution:
To solve this problem, let us express both quantity as the same unit;
1000m = 1km
6000km = 6000 x 10³m = 6 x 10⁶m
60pm;
1 x 10⁻¹²m = 1pm
60pm = 60 x 1 x 10⁻¹²m = 6 x 10⁻¹¹m
Now;
The order: [tex]\frac{6 x 10^{6} }{6 x 10^{-11} }[/tex] = 1 x 10¹⁷
A spring with a constant of 92N/m is compressed 2.8 cm. How much potential energy is stored in the spring?
PE= J
Answer:
0.036J
Explanation:
Given parameters:
Spring constant , K = 92N/m
Compression = 2.8cm = 0.028m
Unknown:
Potential energy = ?
Solution:
To solve this problem;
P.E =[tex]\frac{1}{2}[/tex] K e²
K is the spring constant
e is the compression
so;
P.E = [tex]\frac{1}{2}[/tex] x 92 x 0.028² = 0.036J
Two motorcycles start at the same point. One motorcycle travels 15 km due north and stops. The second motorcycle travels 32 km due west and stops. Which value is closest to the distance between the motorcycles when they stop?.
Two motorcycles start at the same point, one motorcycle travels 15 km due north and stops, the second motorcycle travels 32 km due west and stops, value closest to the distance between the motorcycles when they stop is 35.3 km.
What is Meant by Kilometers to Miles?In general, kilometers to miles is the conversion of distance from the kilometers to miles. kilometers and miles are used to measure length from one point to the other. In metric system, kilometer is the unit of length and it is considered as the International System of Units, whereas miles are used in the imperial and US customary units. The kilometer is abbreviated as “km”, and mile is abbreviated as “mi”. These two measures are mostly used to measure the geographical land areas.
You are aware that hypotenuse of a right triangle is shorter than the total of the legs and longer than the longest leg.
The relevant distance in this geometry is greater than the 32 km and less than 15+32 = 47 km. The only option that falls within acceptable range is 35.3 kilometers.
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Convert 93 nanometer to meters.
Answer:
9.3e-8 Meters
) observer a, who is at rest in the laboratory, is studying a particle that is moving through the laboratory at a speed of v
The distance between the markers in the laboratory where the particle is produced and where it decays is 30.24m.
What is radioactive decay?
Radioactive decay, also known as nuclear decay, radioactivity, radioactive disintegration, or radioactive decay, is the process by which an unstable atomic nucleus loses energy through radiation. A substance that has unstable nuclei is regarded as radioactive. Alpha decay, beta decay, and gamma decay are three of the most frequent kinds of decay, and they all entail the emission of one or more particles. Beta decay is a result of the weak force, while the nuclear force and electromagnetism are in charge of the other two mechanisms. Electron capture, which occurs when an unstable nucleus seizes an inner electron from one of the electron shells, is the fourth prevalent kind of decay.
Explanation:
From the perspective of observer A, the particle had a lifetime of 112 ns and moved at a speed of 0.9c.
0.9c = 2.7e8 m/s
112 ns = 1.12e-7 s
Since we already know the time and speed from the viewpoint of observer A, we can use those to determine the distance from that viewpoint without the need for any modifications.
[tex]d=v*t=2.7e8*1.12e-7=30.24m[/tex]
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Calculate the current in the above circuit.
Answer:
4 A
Explanation:
From the question given above, the following data were obtained:
Voltage (V) = 12 V
Resistance (R) = 3 Ω
Current (I) =?
From ohm's law,
Voltage (V) = Current (I) × Resistance (R)
V = IR
With the above formula, we can obtain the current flowing in the circuit as illustrated below:
Voltage (V) = 12 V
Resistance (R) = 3 Ω
Current (I) =?
V = IR
12 = I × 3
Divide both side by 3
I = 12/3
I = 4 A
Therefore, the current flowing in the circuit is 4 A.
Please answer the pictures below in sequential order, (there's more than 1) I'd really appreciate it. Happy holidays guys!
Answer:
happy holidays
Explanation:
Two neutral objects, 1 and 2, are suspended by strings near one another. Object 2 is touched by a positively-charged insulated rod.
Immediately after the insulated rod is removed, Object 1 and Object 2 repel. What causes the two objects to repel?
Answer:
When 2 objects are in contact with one another and one of them receives a positive or a negative charge, then the objects will repel one another because they are similarly charged.
If an object is not moving, the forces acting upon it are...
A.Balanced
B. Weak
C.Unbalanced
D.Hulk SMASH!
A wire is formed into a circle having a diameter of 10.0cm and is placed in a uniform magnetic field of 3.00mT . The wire carries a current of 5.00 A. Find (b) the range of potential energies of the wire-field system for different orientations of the circle.
The range of potential energies of the wire-field system for different orientations of the circle are -
θ U
0° 375 π x [tex]10^{-7}[/tex]
90° 0
180° - 375 π x [tex]10^{-7}[/tex]
We have current carrying wire in a form of a circle placed in a uniform magnetic field.
We have to the range of potential energies of the wire-field system for different orientations of the circle.
What is the formula to calculate the Magnetic Potential Energy?The formula to calculate the magnetic potential energy is -
U = M.B = MB cos [tex]$\theta[/tex]
where -
M is the Dipole Moment.
B is the Magnetic Field Intensity.
According to the question, we have -
U = M.B = MB cos [tex]$\theta[/tex]
We can write M = IA (I is current and A is cross sectional Area)
U = IAB cos [tex]$\theta[/tex]
U = Iπ[tex]r^{2}[/tex]B cos [tex]$\theta[/tex]
For [tex]$\theta[/tex] = 0° →
U(Max) = MB cos(0) = MB = Iπ[tex]r^{2}[/tex]B = 5 × π × [tex]( 0.05 ) ^{2}[/tex] × 3 × [tex]10^{-3}[/tex] =
375 π x [tex]10^{-7}[/tex].
For [tex]$\theta[/tex] = 90° →
U = MB cos (90) = 0
For [tex]$\theta[/tex] = 180° →
U(Min) = MB cos(0) = - MB = - Iπ[tex]r^{2}[/tex]B = - 5 × π × [tex]( 0.05 ) ^{2}[/tex] × 3 × [tex]10^{-3}[/tex] =
- 375 π x [tex]10^{-7}[/tex].
Hence, the range of potential energies of the wire-field system for different orientations of the circle are -
θ U
0° 375 π x [tex]10^{-7}[/tex]
90° 0
180° - 375 π x [tex]10^{-7}[/tex]
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The magnetic moment of the Earth is approximately 8.00 ×10²²A.m² . Imagine that the planetary magnetic field were caused by the complete magnetization of a huge iron deposit. with density 7900 kg / m³, and approximately 8.50×10²⁸ atoms / m³, (a) How many unpaired electrons, each with a magnetic moment of 9.27 ×10⁻²⁴A.m² , would participate?
[tex]4.315 \times10^{45}[/tex] unpaired electrons,are required each with a magnetic moment of 9.27 ×10⁻²⁴A.m² , to participate .
Magnetic moment, additionally referred to as dipole moment, may be a live of the tendency of associate degree object to align with a field of force. torsion may be a vector amount. Objects tend to be placed in order that their torsion vectors square measure parallel to the lines of magnetism. The direction of the torsion points from the South Pole of the magnet to the North Pole. The field of force made by a magnet is directly proportional to its torsion."Magnetic moment is outlined because the magnetic strength and orientation of a magnet or alternative object that produces a field of force."It is given that magnetic moment of the Earth is approximately 8.00 ×10²²A.m² .
Number of unpaired is found by dividing the magnetic moment of the Earth to the given magnetic moment of 9.27 ×10⁻²⁴A.m²
[tex]n=\frac{8.00\times10^{22}}{9.27\times10^{-24}} \\\\n=8.63\times10^{45}[/tex]
Each iron atom has two unpaired electrons, so the number of iron atoms required is [tex]\frac{1}{2}\times 8.63\times10^{45}=4.315\times10^{45}[/tex] electrons.
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two particles, one with charge −3.77 μc and one with charge 6.91 μc, are 5.84 cm apart. what is the magnitude of the force that one particle exerts on the other?
The magnitude of the force that one particle exerts on the other = [tex]6.8644 \times 10^{13}[/tex] N
Charge of one particle,[tex]Q_1[/tex] = -3.77 μC
Charge of the other particle,[tex]Q_2[/tex] = 6.91 μC
The opposite signs of the charges implies the presence of force of attraction between the particles.
Given distance between particles, r = 5.84 cm = 0.0584 m
Coulomb's law states that the magnitude of the force exerted between two particles is directly proportional to the product of magnitude of charges of the particle and inversely proportional to the square of the distance between the particles.
From this we can infer the equation, [tex]F=\frac{kQ_1Q_2}{r^2}[/tex]
where F is the force between the particles and k =[tex]9\times 10^9 Nm^2C^{-2}[/tex] is the Coulomb's Constant.
So F = (9 x 10^9 x 3.77 x 6.91)/(0.0584 x 0.0584)
= [tex]6.8644 \times 10^{13}[/tex] N
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A power supply is connected to an electric motor using two low resistance wires. the battery supplies 800 j of energy. how much of this energy will be transferred to the kinetic store of the motor?
The energy transfer to the kinetic store of the motor will be less than 800 J because some of the energy is dissipated in the surrounding.
A piece of electrical equipment that is used to supply power to the electrical load is called an electric power supply.
The basic objective of this device is to transfer power from the source to the consumer with the correct amount of voltage, frequency, and current.
Furthermore, this device transforms alternative current (AC) into low voltage direct current (DC).
It consists of four major elements: filter, transformer, regulator circuits, and rectifier.
To put it simply, a power supply transforms Ac voltage to DC voltage.
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This is when one person is guiding another
On a very cold day in upstate New York, the temperature is -25°C , which is equivalent to what Fahrenheit temperature? (a) -46°F (b) -77°F(c) 18°F(d) -25°F(e) -13°F
Considering the conversion between Celsius degree and Fahrenheit degree, the correct answer is option (e): -25°C is equivalent to -13 Fahrenheit temperature.
Celsius degree
The Celsius degree, represented as °C, is the unit created by Anders Celsius. This scale is also called the "Centigrade scale" and in it the temperature is divided into 100 degrees, with 0º C being the freezing point of water and 100º C the boiling point of water.
Fahrenheit degreeThe Fahrenheit degree is the unit of temperature proposed by Gabriel Fahrenheit in 1724, whose scale sets zero and one hundred in the freezing and evaporation temperatures of ammonium chloride in water. On this temperature scale, unlike the Celsius scale, the freezing point of water is 32º F while the boiling point of water is 212º F.
Conversion of Celsius degree to Fahrenheit degreeTo perform the conversion, the expression must be applied:
°F= °C× 9/5 + 32
Temperature in this caseOn a very cold day in upstate New York, the temperature is -25°C. Fahrenheit temperature is calculated as:
°F= (-25°C)× 9/5 + 32
Solving:
°F= -13
In summary, the correct answer is option (e): -25°C is equivalent to -13 Fahrenheit temperature.
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Review. A wire having a linear mass density of 1.00 g/cm is placed on a horizontal surface that has a coefficient of kinetic friction of 0.200. The wire carries a current of 1.50 A toward the east and slides horizontally to the north at constant velocity. What are (b) the direction of the smallest magnetic field that enables the wire to move in this fashion?
The direction of the smallest magnetic field that enables the wire to move in this fashion to East.
A magnetic force in the direction of north that is equal in strength to the friction force will be required.
Fm - f = 0
I L B = uk mg = 0.
(1.50 x 1 x B) - (0.20 x 0.1 x 9.8) = 0
B = 0.131 T
b) the magnetic force, Fm = IL x B. (cross product )
- > north F
What emf is induced across the ends of the wire?
The formula can be used to calculate the magnetic force for a moving charge particle;
∈= Bvlsinθ
Due to the parallel motion of the wire, the angle between the magnetic field and velocity is zero degrees.
B = 0.500 T
v = 1.50 m/s
l = 0.200 m
Therefore,
∈ = (0.500 T) (1.50 m/s) * (0.200 m) *sin 0
∈=0.15 * sin 0
∈= 0
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Mankind causes major disruptions within ecosystems
- true
-false
Answer:
true
Explanation:
common sense i am just guessing.
Answer: True
Explanation: For instance cutting trees for paper.
Hope this helps!! Brainlist? Plz
M With particular experimental methods, it is possible to produce and observe in a long, thin rod both a transverse wave whose speed depends primarily on tension in the rod and a longitudinal wave whose speed is determined by Young's modulus and the density of the material according to the expression v = √(Y/rho) . The transverse wave can be modeled as a wave in a stretched string. A particular metal rod is 150cm long and has a radius of 0.200cm and a mass of 50.9 g . Young's modulus for the material is 6.80× 10¹⁰N/m² . What must the tension in the rod be if the ratio of the speed of longitudinal waves to the speed of transverse waves is 8.00 ?
The tension in the rod when the ratio of speed is 8 is 1.34 × 10⁴ N.
The longitudinal waves speed is determined using the density of the material and the Youngs modulus with the expression:
v = √(Y/rho)
A wave in a stretched string can be used to represent the transverse wave.
The length of the metal rod is 150 cm and the radius of the rod is cm.
The mass of the rod is 50.9 g.
Now, the Youngs modulus for the material is 6.80× 10¹⁰ N/m².
For the longitudinal wave
v(l) = (Y/ρ)^{1/2}
For the transverse wave :
v(T) = (Y/μ)^{3/2}
Now, we need
v(L) / v(T) = 8
And we know,
T = (μY) / (64ρ) where μ= m /L
And the density, ρ = mass / volume = (m) / (πr²L)
Therefore,
T = (πr²Y) / 64
T = (π)(2 × 10⁻³)² × (6.8 × 10¹⁰) / 64
T = 1.34 × 10⁴ N
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What is the displacement of the object from 12 seconds to 16 seconds ?
Answer:
Displacement is the distance between an object’s initial position and its final position and is usually measured or defined along a straight line. Since this is a calculation that measures distance, the standard unit is the meter (m).
Explanation:
One long wire carries current 30.0 A to the left along the x axis. A second long wire carries current 50.0 A to the right along the line (y = 0.280m, z = 0). (c) What If? A uniform electric field is applied to allow this particle to pass through this region unelected. Calculate the required vector electric field.
The vector electric field is [tex]-1.73 \times 10^{4} {~}\hat{j} {~}N/C[/tex] .
A stream of charged particles, such as electrons or ions, flowing through an electrical conductor or a vacuum is known as an electric current.
One long wire carries a current I = 30.0 A to the left along the x-axis. I' = 50.0 A of current is being carried by a second lengthy wire to the right along the line (y = 0.280 m, z = 0).
Now,
The charge of a particle is q = - 2.00 μC which is moving with a velocity of [tex]v = 150\hat{i} {~}Mm/s[/tex].
At y = 0.1 m the total magnetic field is:
B = 1.16 × 10⁻⁴ T
Then the force on the particle is:
F =q(v × B)
[tex]F = (-2 \times 10^{-6} )[ ( 150 \times 10^{6})\hat{j} \times (1.16 \times 10^{-4})\hat{k} ][/tex]
F = 3.47 × 10⁻² N
A uniform electric field is applied.
Then the vector electric field will be:
F = qE
3.47 × 10⁻² = (-2 × 10⁻⁶ )E
[tex]E = -1.73 \times 10^{4}{~}\hat{j} {~}N/C[/tex]
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Technetium-99m is a radioactive isotope commonly used in medicine as a radioactive tracer. A radioactive tracer is an isotope injected into the body to help create images for diagnosis of health
problems. Technetium-99m has a half-life of 6 hours. If a patient receives a dose of technetium-99m one morning, about what percentage of the technetium-99m will be left in the patient's body 12
hours later?
A
6.25%
B
12.5%
С
25.0%
D
93.8%
Answer:
C. 25.0%
Explanation:
Radioactive decay of an atom follows the equation:
ln[A] = -kt + ln[A]₀
Where [A] could be taken as an amount of radioactive atom after time t,
k is rate constant = ln 2 / Half-Life = ln 2 / 6hours = 0.1155hours⁻¹
[A]₀ is initial amount of the isotope = 100%
Replacing:
ln[A] = -0.1155hours⁻¹ *12hours+ ln[100%]
ln[A] = 3.2192
[A] = 25.0%
Right solution is:
C. 25.0%
bob hits a baseball.what two systems are working together to make this happen
Answer:
Kinetic Energy and Mechanical energy
Explanation:
Q|C A bat, moving at 5.00 m/s , is chasing a flying insect. If the bat emits a 40.0 -kHz chirp and receives back an echo at 40.4 kHz , (b) Will the bat be able to catch the insect? Explain.
The bat's observation of the echo's frequency is 41.2 kHz
A bat flies speedily in this problem [tex]$$v_{\text {bat }}=5.0 \mathrm{~m} / \mathrm{s}$$[/tex] .
It makes a frequency chirp [tex]$$f_S=40 \mathrm{kHz}=4.0 \times$$10^{4} Hz.[/tex]
An adjacent wall reflects the sound. We determine the echo's frequency based on the bat's observations.
(b) Sound propagates at a speed of [tex]v=345 \mathrm{~m} / \mathrm{s}[/tex]
The sound will undergo two Doppler shifts. The first Doppler change occurs when the sound travels toward the wall, and the second Doppler shift occurs as the sound returns to the bat.
[tex]\begin{aligned}f_{O, 1} &=f_S\left(\frac{v+v_O}{v-v_S}\right) \\&=f_S\left(\frac{v+0}{v-\left(+v_{\mathrm{bat}}\right)}\right) \\f_{O, 1} &=f_S\left(\frac{v}{v-v_{\mathrm{bat}}}\right)\end{aligned}[/tex]
The moving bat, which moves in the direction of the source, serves as the observer in the second Doppler shift. The wall that isn't moving is the source. The bat's frequency observations must be
[tex]\begin{aligned}f_{\text {echo }} &=f_{O, 1}\left(\frac{v+v_O}{v-v_S}\right) \\&=f_{O, 1}\left(\frac{v+\left(+v_{\text {bat }}\right)}{v-0}\right) \\&=f_{O, 1}\left(\frac{v+v_{\text {bat }}}{v}\right) \\&=f_S\left(\frac{v}{v-v_{\mathrm{bat}}}\right)\left(\frac{v+v_{\text {bat }}}{v}\right) \\\Rightarrow f_{\text {echo }} &=f_S\left(\frac{v+v_{\mathrm{bat}}}{v-v_{\mathrm{bat}}}\right)\end{aligned}[/tex]
By substituting values in the equation, we get
[tex]\begin{aligned}f_{\text {echo }} &=f_S\left(\frac{v+v_{\text {bat }}}{v-v_{\text {bat }}}\right) \\&=\left(4.0 \times 10^4 \mathrm{~Hz}\right)\left(\frac{345+5.0}{345-5.0}\right) \\&=4.11765 \times 10^4 \mathrm{~Hz} \\f_{\text {echo }} &=41.2 \mathrm{kHz}\end{aligned}[/tex]
Hence, The bat's observation of the echo's frequency is 41.2 kHz.
Is the frequency of echo high?Ultrasound, which has frequencies above human hearing, is used in echocardiography. Pressure waves take the form of sound waves, which can go through any material.
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Bats have poor vision and use echo-location to find their way.The frequency produced by bats is 100kHz. If the speed of the sound is 345m/s , how deep is the cave if the bat makes peeping sounds that return to the bat after 0,15s??
The distance covered is 25.9 m.
How deep is the cave?We know that the speed of sound refers to the speed with which an sound moves in an object.
Given that;
speed of sound = 345m/s
Time taken = 0.15s
We know that;
v = 2d/t
v = speed of sound
d = distance
t = time taken
vt = 2d
d = vt/2
d = 345m/s * 0.15s/2
d = 25.9 m
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A net force is acting on an object. The object is moving in a
straight line under the effect of this force. If the net force
acting on the object is doubled, how will this affect the
object?
Answer:
The object's velocity would increase due to the change in force.
Explanation:
Which of the following is not a component of a normal experiment?
A. Control group
OB. Dependent variable
C. Independent variable
D. Validity group
Reset Selection
Answer:
D. Validity group
Explanation:
A validity group is not necessarily a component of a normal experiment.
A normal experiment is made up of the dependent variables, independent variables, and most times the control group.
The dependent variable is one that relies on the outcome of the effect produced from the experimental designThe independent variable is the one that causes a desired effect under the study. The control group is a group that does not receive any treatment nor attenuation of the conditions.What are the two forces that act on the orbit of a planet?
A) Velocity of planet and gravity between sun and planet.
B) Gravity between the aphelion and perihelion.
C) Gravity between planet and sun and the velocity of the sun.
D) Orbits of other planets and gravity between sun and planet.
HELP PLEASE!
The two forces that act on the orbit of a planet are velocity of planet and gravity between sun and planet.
What is gravity?The force that pulls items toward the center of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity. Gravity applies to everything that has mass. Gravity is stronger for objects with higher mass. Along with distance, gravity weakens as well. Therefore, the gravitational pull of two things becomes stronger the closer they are to one another.
The mass of the Earth is what creates gravity. The combined gravitational force of all of its mass acts on the mass in your body.
Velocity of the planet is also related to its gravity.
Forces that acts on the orbit of a planet is force due to velocity and gravity.
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dynamical stability of giant planets: the critical adiabatic index in the presence of a solid core kundu, s.k., coughlin, e.r., youdin, a.n., armitage, p.j., 2021, mnras, submitted
The critical adiabatic index in the presence of a solid core dynamical stability of giant planets is called adiabatic index.
What is adiabatic index?In warm material science and thermodynamics, the intensity limit proportion, otherwise called the adiabatic record, the proportion of explicit warms, or Laplace's coefficient, is the proportion of the intensity limit at steady strain to warm limit at consistent volume. The Adiabatic Index adding machine processes the adiabatic list ( γ) otherwise called the intensity limit proportion or proportion of explicit warms. Accordingly, for normally happening diatomic gases at close to standard circumstances, the adiabatic file can be roughly viewed as around 7/5 or 1.4. The particular intensity proportion or adiabatic list is connected with the levels of opportunity () of a gas particle by the situation.
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how does the thickness of wood affect its stability
Answer:
Making the lumber thick will make it stiff, which seems good. On the other hand, with thicker lumber, differences in expansion on the two faces have more leverage to make the lumber move.
what is the electric force on a due to b in component form? express your answer in terms of the unit vectors i^ and j^ . use the 'unit vector' button to denote unit vectors in your answer.
The electric force on a due to b in component form = [tex]\bold{0\vec i+72\times10^{-9}\vec j\ N}[/tex]
Charge of A = 4 nC = [tex]4\times 10^{-9}[/tex] C
Charge of B = -8 nC = [tex]-8\times 10^{-9}[/tex] C
A is on the origin, (0,0) and B is at the point (0 cm,2cm).
Therefore, distance between charges A and B, r = [tex]\sqrt{(0-0^2)+(0-2)^2} =2[/tex]
Using Coulomb's law, the electric force is directly proportional to the product of charges and inversely proportional to the square of distance between charges.
i.e., [tex]F_{A\ on\ B}=\frac{kq_1q_2}{r^2}[/tex], where k = [tex]9\times 10^9 Nm^2C^{-2}[/tex], the Coulomb constant.
So [tex]F_{A\ on\ B}=\frac{9\times 10^9\times 4\times 10^{-9}\times 8\times 10^{-9}}{2^2} = \bold{72\times 10^{-9} N}[/tex]
Since there is no x-component for this force,
the electric force on a due to b in component form = [tex]\bold{0\vec i+72\times10^{-9}\vec j\ N}[/tex]
The question incomplete. Find the complete question here:
Object A, which has been charged to +4.0 nC is at the origin. Object B, which has been charged to -8.0 nC, is at (x, y)=(0.0 cm, 2.0 cm). What is the electric force on A due to B in component form? Express your answer in terms of the unit vectors i and j. Use the 'unit vector button to denote unit vectors in your answer.
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The image above shows two opposite forces acting on a rope, what can we say is true about the affect of the forces on
the rope?
Answer:
your answer is D
Explanation:
..........
Answer:
d
Explanation:
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