if
[tex]f(x) = \sqrt{x} + 12[/tex]
and
[tex]g(x) = 2 \sqrt{x} [/tex]
what is the value of
[tex](f - g)(144)[/tex]
?​

Answers

Answer 1

Answer:

0

Step-by-step explanation:

We have the two functions:

[tex]f(x)=\sqrt{x}+12\text{ and } g(x)=2\sqrt{x}[/tex]

And we want to find (f-g)(144).

This is the same thing to f(144)-g(144).

So, let’s determine the value of f(144) and g(144) first:

[tex]\begin{aligned} f(144)&=\sqrt{144}+12 \\ &=12+12 \\ &=24\end{aligned}[/tex]

And:

[tex]\begin{aligned} g(144)&=2\sqrt{144} \\ &=2(12) \\ &=24 \end{aligned}[/tex]

Hence:

[tex]\begin{aligned} (f-g)(144) &= f(144)-g(144) \\ &=24-24 \\ &=0 \end{aligned}[/tex]

Our final answer is 0.

Answer 2

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[tex](f - g)(x) = \sqrt{x} + 12 - 2 \sqrt{x} \\ [/tex]

[tex](f - g)(x) = - \sqrt{x} + 12[/tex]

[tex](f - g)(144) = - \sqrt{144} + 12[/tex]

[tex](f - g)(144) = - \sqrt{ {12}^{2} } + 12 [/tex]

[tex](f - g)(144) = - (12) + 12[/tex]

[tex](f - g)(144) = - 12 + 12[/tex]

[tex](f - g)(144) = 0[/tex]

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Answers

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Answers

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Step-by-step explanation:

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The value of x is "12".

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[tex]\to \frac{1}{2}x-5=10-\frac{3}{4}x \\\\\to \frac{1}{2}x+ \frac{3}{4}x=10+5 \\\\\to \frac{2+3}{4}x=15 \\\\\to \frac{5}{4}x=15 \\\\\to x=15 \times \frac{4}{5}\\\\\to x=3 \times 4\\\\\to x=12[/tex]

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brainly.com/question/19793439

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Answer:

A solid cylindrical metal is melted and recast into cubes of metal of sides 3cm . The base radius of the initi… Get the answers you need, ... is melted and recast into cubes of metal of sides 3cm . The base radius of the initial cylindrical metal is 10.5cm and height is 63cm. How many cubes will be made.

Step-by-step explanation:

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Answers

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