Answer: The correct order of energy transformation is from CHEMICAL ENERGY to ELECTRICAL ENERGY to LIGHT ENERGY
Explanation:
Energy which is simply defined as the ability to perform work is made up of different forms, these include:
- Mechanical energy: Associated with machines at work.
- LIGHT ENERGY: produced by light bulbs
- ELECTRICAL ENERGY: taking in by television set and other electrical appliances.
- CHEMICAL ENERGY: stores in food and other fuels
- Sound energy: Produced by vibrating objects example piano, drums.
According to the law of conservation of energy, energy can neither be created nor destroyed in a closed system, but can be transformed from one form to another, thereby keeping the energy in the closed system constant. From the question, the circuit is an example of a closed system and the order of energy transformation taking place is from the battery (CHEMICAL ENERGY) to ELECTRICAL ENERGY(power source) to LIGHT ENERGY(bulb). I hope this helps, thanks.
A linearly polarized microwave of wavelength 1.50cm is directed along the positive x axis. The electric field vector has a maximum value of 175V/m and vibrates in the x y plane. Assuming the magnetic field component of the wave can be written in the form B=Bmax sin (k x-Ω t) give values for (f) If this wave were directed at normal incidence onto a perfectly reflecting sheet, what radiation pressure would it exert?
The radiation pressure directed at normal incidence onto a perfectly reflecting sheet is 2.71 × 10⁻⁷ Pa
What radiation pressure would it exert?Given that a linearly polarized microwave of wavelength 1.50cm is directed along the positive x axis and the electric field vector has a maximum value of 175V/m and vibrates in the x y plane.
Also, assuming the magnetic field component of the wave can be written in the form B=Bmax sin (k x-Ω t) give values for (f) If this wave were directed at normal incidence onto a perfectly reflecting sheet, we desire to find the radiation pressure.
The radiation pressure for total reflection is given by P = 2I/c where
I = intensity = E²/2μ₀c where E = maximum electric field = 175 V/m, μ₀ = permeability of free space = 4π × 10⁻⁷ T/m and c = speed of light = 3 × 10⁸ m/sSo, P = 2I/c
P = 2E²/2μ₀c ÷ c
P = E²/μ₀c²
Substituting the values of the variables intot he equation, we have
P = E²/μ₀c²
P = (175 V/m)²/[4π × 10⁻⁷ T/m × (3 × 10⁸ m/s)²]
P = 30625 V²/m²/[4π × 10⁻⁷ T/m × 9 × 10¹⁶ m²/s²]
P = 30625 V²/m²/[36π × 10⁹ Tm/s²]
P = 30625 V²/m²/113.097 × 10⁹ Tm/s²
P = 270.78 × 10⁻⁹ Pa
P = 2.7078 × 10⁻⁷ Pa
P ≅ 2.71 × 10⁻⁷ Pa
So, the radiation pressure directed at normal incidence onto a perfectly reflecting sheet is 2.71 × 10⁻⁷ Pa
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what make molecules
Answer:
Molecules are made up of atoms that are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons among atoms. The atoms of certain elements readily bond with other atoms to form molecules. ... The element helium is a one-atom molecule. I hope this helps :)
Answer:
atoms held together by chemical bonds
Explanation:
PLEASE HELP ME! I'M BEGGING! PLEASE HELP! Using what you have learned about energy conversions, describe the energy transfer or transformation for each of the following items:
a. Clapping your hands
b. Turning on a light
1) Clapping your hands - Energy is converted from mechanical energy to sound energy
2) Turning on a light - Energy is converted from electrical energy to heat and light energy
What are energy conversions?Energy is converted from one form to another and it neither created nor destroyed. This is the first law of thermodynamics. This law means that energy does not get lost in the system. We can not have the energy in the system just suddenly vanish into the thin air. It must have to change from one form to the next.
Now we know that the conversion of energy from one form to the next is not a hundred percent efficient process, some energy may ne lost on the way! This is the statement that we could call the second law of thermodynamics.
Let us look at the energy conversions in the following cases;
1) Clapping your hands - Energy is converted from mechanical energy to sound energy
2) Turning on a light - Energy is converted from electrical energy to heat and light energy
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Suppose all six equal-length strings of an acoustic guitar are played without fingering, that is, without being pressed down at any frets. What quantities are the same for all six strings? Choose all correct answers. (a) the fundamental frequency (b) the fundamental wavelength of the string wave (c) the fundamental wavelength of the sound emitted (d) the speed of the string wave (e) the speed of the sound emitted.
Only elementary wavelength of the string wave is same for all six strings that is choice (b) .
Harmonic, conjointly known as merely elementary wave, is outlined because the lowest frequency of a periodic wave. In music, the foundation is that the pitch of the note that's perceived because the lowest partial gift. The wavelength of sound is that the distance between the analog points of 2 ordered waves.a ) every note includes a totally different harmonic (notes E, B, G, D, A, E).
b) Correct. The wavelength depends solely on the chord length and boundary conditions and is that the same for all six strings.
c) Corresponds to the basic tone, since the basic wavelength of the radiated sound varies from string to string.
d) String wave rate depends on the mass density and tension of the string. All half-dozen strings square measure totally different, therefore the wave speed is additionally totally different.
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Is Ampère's law valid for all closed paths surrounding a conductor? Why is it not useful for calculating →B for all such paths?
Although not always practical, Ampere's law is true for all closed channels around a conductor. The integral can be calculated along many different paths, although it is difficult to do so. Think about a path that is circular but not coaxial with a long, straight wire that carries current. If the current in a conductor has enough symmetry to allow the line integral to be reduced to the size of B times an integral, Ampere's law can be used to calculate B.
What applications does Ampere's Law have?Ampere's Law is applied to,
Find the magnetic induction caused by a long wire carrying current.Analyze the magnetic field a toroid has.Find the magnetic field produced by a long conducting cylinder that carries current.Ascertain the conductor's magnetic field.To learn more about Ampere's Law, visit:
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how would you derive relation between momentum and newton's second law
Answer:
F = Δ(mv)/Δt = ma
Explanation:
Newton's second law states that the force exerted on an object is equal to the rate of change of its momentum.
Let F represent force and p momentum and p = mv where m = mass and v = velocity
This implies that F = Δp/Δt = Δ(mv)/Δt if the mass is constant, we have
F = mΔv/Δt and we know that acceleration, a = Δv/Δt
So, F = ma which is Newton's second Law.
The motion of a transparent medium influences the speed of light. This effect was first observed by Fizeau in1851. Consider a light beam in water. The water moves with speed v in a horizontal pipe. Assume the light travels in the same direction as the water moves. The speed of light with respect to the water is c / n , where n=1.33 is the index of refraction of water.(a) Use the velocity transformation equation to show that the speed of the light measured in the laboratory frame isu = c/n (1 + nv/c / 1+ v/nc)
It is proved that the speed of the light measured in the laboratory frame is , u =c/n(1+ nv/c)/(1+ v/nc) .
Given ,
The motion of a transparent medium influences the speed of light .
The water moves with speed v in a horizontal pipe .
Assume that the light travels in the same direction as the water moves .
The speed of the light with respect to the water is c/n
Where n = 1.33 is the refractive index of water .
Let us assume ,
u' be the speed of light in water , in the frame moving with the water .
u' is related to the refractive index of water ,n as :
u'=c/n
where , c is the speed of light .
let , u be the speed of light in water in the lab frame .
Now , u and u' are related as : u = (u'+ v )/(1+ u'v/c^2)
Here v is the speed of water in the horizontal pipe .
we know the value of u' , so by substituting the value , we will get ,
u= (c/n+ v)/(1+cv/nc^2)
u= c/n(1+ nv/c)/(1+v/nc)
Hence , it is proved that the speed of the light measured in the laboratory frame is , u =c/n(1+ nv/c)/(1+ v/nc) .
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which names are correct for fm−→−? select each correct answer. fp−→− ray f p fd−→− ray f d mf−→− ray m f fw−→−
The correct answer is FM-MF
The crust of the Earth does not naturally contain ferromium. The heaviest element that can be created by neutron bombardment of lighter elements, fermium was first discovered in December 1952 by American scientists from the Argonne National Laboratory near Chicago, Illinois, the Los Alamos National Laboratory in Los Alamos, New Mexico, and The University of California Laboratory in Berkeley. Fermium is the heaviest element that can be synthesized in macroscopic quantities.
We can prove this by saying that if a point's distance from another point is six units, then the distance between those two points will also be six units. Therefore, FM-MF
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Omar and ahmed are lifting weights in the gym. Each lifts a weight of 200N. Omar lifts the weight to a height of 2.0m, whereas ahmed lifts it to a height of 2.1m. Who does more work in lifting the weight.
Answer:
Ahmed did more work in lifting the weight than Omar.
Explanation:
Work done can be determined as the product of a force and the distance moved in the direction of the force.
Work done = F x s
In the given question, since the weight is lifted through a height, then the work done equals potential energy.
i.e Work done = Potential energy
= mgh
But,
Force = weight = mg
So that,
Work done = Fh
where F is the weight and h is the height.
i. Work done by Omar = Fh
= 200 x 2.0
= 400
Work done by Omar is 400 Nm.
ii. Work done by Ahmed = Fh
= 200 x 2.1
= 420
Work done by Ahmed is 420 Nm.
Thus, Ahmed did more work in lifting the weight than Omar.
Simple pendulum takes 0.01 s to reach the maximum displacement from the equilibrium position, so it's frequency equals.......
a)20 HZ
b)25 HZ
c)50 HZ
c)100 HZ
Simple pendulum takes 0.01 s to reach the maximum displacement from the equilibrium position, so it's frequency equals to 100 Hz
The time period of a simple pendulum: It is defined as the time taken by the pendulum to finish one full oscillation and is denoted by “T”. The amplitude of simple pendulum: It is defined as the distance travelled by the pendulum from the equilibrium position to one side.
The frequency of the pendulum defines how many times the pendulum moves back and forth in a specific period of time
time period of simple pendulum = 1 / frequency
given
time period = 0.01 second
frequency = 1 / 0.01
= 100 Hz
correct answer will be d) 100 HZ
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Kangaroos are strong jumpers and can leap over an object 1.8 m high. Calculate a kangaroo's minimum vertical speed when it leaves the ground.
The kangaroo's minimum vertical speed when it leaves the ground is 5.94 m/s
Data obtained from the questionThe following data were obtained from the question given above:
Maximum height (h) = 1.8 mFinal velocity (v) = 0 m/s (at maximum height) Acceleration due to gravity (g) = 9.8 m/s²Initial velocity (u) =?How to determine the initial velocity of the kangarooWe can determine the inintial velocity of the kangaroo as follow:
v² = u² – 2gh (since the ball is going against gravity)
0² = u² – (2 × 9.8 × 1.8)
0 = u² – 35.28
Collect like terms
u² = 0 + 35.28
u² = 35.28
Take the square root of both side
u = √35.28
u = 5.94 m/s
From the above calculation, we can conclude that the minimum vertical speed of the kangaroo when it leaves the ground is 5.94 m/s
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An alien spaceship traveling at 0.600 c toward the Earth launches a landing craft. The landing craft travels in the same direction with a speed of 0.800 c relative to the mother ship. As measured on the Earth, the spaceship is 0.200 ly from the Earth when the landing craft is launched.(b) What is the distance to the Earth at the moment of the landing craft's launch as measured by the aliens?
The distance to the Earth at the moment of the landing craft's launch as measured by the aliens is 0.16 light years.
To find the answer, we have to know about the Lorentz transformation.
What is the distance to the Earth at the moment of the landing craft's launch as measured by the aliens?It is given that, an alien spaceship traveling at 0.600 c toward the Earth, in the same direction the landing craft travels with a speed of 0.800 c relative to the mother ship. We have to find the distance to the Earth at the moment of the landing craft's launch as measured by the aliens.
It is given that; the spaceship is 0.200 ly from the Earth when the landing craft is launched.By Lorentz transformation equation, the value of the distance to the Earth at the moment of the landing craft's launch as measured by the aliens will be,[tex]L=L_0\sqrt{1-\frac{V^2}{c^2} } =0.2ly\sqrt{1-\frac{(0.6c)^2}{c^2} }=0.2ly\sqrt{1-0.36}= 0.16ly[/tex]
Thus, we can conclude that, the distance to the Earth at the moment of the landing craft's launch as measured by the aliens is 0.16 light years.
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A rocket is launched and the observer measuring the rocket altitude is standing at a distance of 200 feet from the launcher. When the rocket reaches apogee, the observer measures an angle of 45° using an altitude scope. Calculate the altitude of the rocket to the nearest foot.
Answer:
100 foot
Explanation:
Using the formula for calculating range to calculate the speed first as shown;
Range R = U²sin 2theta/gU is the speed
theta is the observe angle
g is the acceleration due to gravity.
200 = U²sin 2(45)/9.8
Usin90 = 200 * 9.8
U² = 1960
U = √1960
U = 44.27 m/s
Get the required altitude
Altitude H = u²/2g
H = 44.27²/2(9.8)
H = 1,959.8329/19.6
H = 99.99 feet
Hence the altitude of the rocket to the nearest foot is 100 foot
An ion rocket engine produces 1 newton of thrust. What acceleration can it give to a space probe with a mass of 1000kg?.
By using the thrust force, the acceleration is 0.001 m/s².
We need to know about force to solve this problem. According to second Newton's Law, the force applied to an object will be proportional to mass and acceleration. Hence, it can be written as
F = m . a
where F is force, m is mass and a is acceleration
From the question above, we know that
F = 1 N
m = 1000 kg
By substituting the given parameters, we can calculate the acceleration
F = m . a
1 = 1000 . a
a = 1/1000
a = 0.001 m/s²
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Suppose a 1,500 kg speedboat is traveling with a velocity of 13 m/s. what is the speedboat’s momentum? 115 kg • meters per second 1,513 kg • meters per second 19,500 kg • meters per second
The speedboat momentum is 19,500 kg.m/s.
We need to know about momentum to solve this problem. Momentum can be defined as the degree of difficulty to stop a moving object. It can be determined by
P = m . v
where P is momentum (kgm/s), m is mass (kg) and v is velocity (m/s).
From the question above, we know that:
m = 1500 kg
v = 13 m / s
By substituting the given parameters, we can calculate the momentum
P = m . v
P = 1500 . 13
P = 19,500 kg . m / s
Hence, the speedboat momentum is 19,500 kg.m/s.
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Answer:19,500 kg
Explanation:your welcome!:)
if 1 m = 100 cm , then how many cm^2 are there in a m^2 ?? please hel[p
Answer:if 1 m = 100 cm then there should be 200 cm in m^2
Explanation:
suppose the aqueous humor in a person’s eye exerts a force of 0.295 n on the 1.15-cm2 area of the cornea.
The aqueous humor in a person’s eye exerts a force of 0.295 n on the 1.15-cm2 area of the cornea pressure is this in mm Hg P = 2565.2173 N/m².
Equation :Pressure is defined as the normal force F per unit area A over which the force is applied or
P = F / A
Where :
P is the pressure acting on the cornea .
F if the force acting on the cornea .
A is the area of the cornea .
Givens : F = 0.3 N and A = 0.00011 m
Plugging known information to get :
P = F / A
P = 0.295 / 0.000115
P = 2565.2173
P =2565.2173 N/m²
What produces aqueous humor?The ciliary body produces aqueous humor, which travels along the uveoscleral pathway from the posterior chamber through the pupil and anterior chamber (shown by dashed lines and arrowheads) to the ciliary muscle and suprachoroidal region.
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I understand the question you are looking for :
suppose the aqueous humor in a person’s eye exerts a force of 0.295 n on the 1.15-cm2 area of the cornea. What pressure is this in mm Hg?
sheila uses a 45N force on her bowling ball across a 15M lane. what work did she do on the bowling ball? show your work.
Answer:
Work=force × distance
=45×15
=675
Explanation:
need thanks and make me brainiest if it helps you
would a larger, more heavier ball fall faster than a smaller and lighter ball?
Answer:
the larger-heavier would fall faster than lighter-smaller ball
Explanation:
Under which condition is the resultanat vector equal to zero?
A 500N load is lifted to a height in 50 sec. Calculate the power.
Answer:
25000w
Explanation:
P=Fxs
p=500×50
p=25000 watts
If you weight 100 pounds on earth how much would you weight on the moon
Answer:
You should weigh about 16 pounds.
Explanation:
To find this, you need to find your weight and divide it by 6 to find your weight on the moon.
Show FORMULA AND SOLUTION:
What acceleration will result when a 12N net force applied to a 3kg object? A 6kg object?
Answer:
2m/s²
Explanation:
F = 12 N
m = 3kg
a = ?
F = ma
a = F/m = 12/3 = 4 m/s²
when m = 6kg
a = F/m = 12/6
a = 2 m/s²
why do we not consider the electromagnetic force when we describe the force between the earth and the sun?
Electromagnetic force can not be considered because it very less as compared to gravitational force.
There are four types of Nuclear Forces :
1. Gravitational force
2. Electromagnetic force
3. Strong nuclear force
4. Weak nuclear force
The force acting between the sun and the earth is gravitational force it is about
3.54 ×10²²N
Earth rotates around the sun because it is contained in the sun's gravitational field.
Due to the centripetal force Earth doesn't falls into the sun.
Electromagnetic force can not be considered because it very less as compared to gravitational force. The electromagnetic force between two charged bodies is nearly equal to 10⁵N.
Electromagnetic force can not be considered because it very less as compared to gravitational force.
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please help me swear will mark brainiest
Answer:
I think that is d option 1.0Nm anticlockwise
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if a charged plastic rod is brought near an uncharged metal rod on an insulating stand, an uncharged metal ball near the other end of the metal rod is attracted to this end of the rod. explain the motions of charges that give rise to this force
The phenomenon that is occurring is depicted in fig. Induction can be used to provide an explanation for this. As seen in Fig., when a negatively charged plastic rod is pushed close to a metal rod that is initially unaltered, the metal rod's left end picks up positive charges while the right end will pick up negative charges as a result of induction. when the empty metal ball is brought close to the metal rod's right end. The ball's near face subsequently develops a positive charge as a result of induction, and this positive charge attracts the rod since opposite charges are attracted to one another.
Define Induction?Electromagnetic induction, often known as induction, is the technique of creating electrical current in a conductor by exposing the conductor to a fluctuating magnetic field. Because the magnetic field is thought to have induced the current in the conductor, it is known as induction.
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please help meeee
Spongebob blows a 4 N bubble in the ocean and it floats upwards. The buoyancy of the
bubble is 8 N and water resistance is 1 N. Draw a FBD and attach a picture,
Answer:
whichever teacher gave you this question is a legend
Explanation:
Help please!!!!!!
!!
Answer:
9
Explanation:
about
is parabolic mirror used for finiding out the intensity of light?
The correct answer is :
Mirror Parabola A mirror with a parabola-shaped reflecting surface is referred to as a parabolic mirror. The mirror is employed in search lights because it can precisely converge a broad parallel beam of light at the focus. Therefore, even at a great distance, the intensity of the reflected beam is unaffected.
Parabolic In search lights, concave mirrors with sizable apertures are utilized. For searching items in search light, we require a powerful parallel beam of light. The reflected rays from an object placed at a concave mirror's focus are parallel to one another and likewise parallel to the main axis. So, we position a light source at the concave mirror's focal point.
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