Answer:
While driving in reverse gear it necessary to have reverse audible alarm , a spotter and a rear view mirror.
Explanation:
It is prefer that to not drive a vehicle in reverse. But if we are driving in reverse gear it is necessary to have a reverse audible alarm , a spotter and a rear view mirror.
A small probe P is gently forced against the circular surface with a vertical force F as shown . Determine the n- and t-components of this force as functions of the horizontal positions.
This question is incomplete, its missing an image which will be uploaded along this Answer.
Answer:
the normal component of force F_n is F((√(r²-s²)) / r)
the tangential component of force F_t is F(s/r)
Explanation:
Given the data in the image;
from the free body diagram, we write the expression for ∅
sin∅ = s/r
cos∅ = (√(r²-s²)) / r
now expression for normal component of force is;
F_n = Fcos∅
we substitute
F_n = F((√(r²-s²)) / r)
Therefore, the normal component of force F_n is F((√(r²-s²)) / r)
Also for force F_t
F_t = Fsin∅
we substitute
F_t = F(s/r)
Therefore, the tangential component of force F_t is F(s/r)
An earth dam is in danger of failing. A pump is needed to quickly drain the small lake behind the dam. The total energy head required to move water over the top of the dam is 2.43 m. The only pump available is an old 10-cm diameter propeller pump. The power requirement for the motor is 1,000 w and the pump-motor combination has a low efficiency of 50%. Estimate the drawdown (how many centimeters the lake goes down) in the first 2-hour period if the lake has a surface area of 5,000 m2. (Note: Assume that the energy head the pump must overcome does not change much as the lake is lowered in the first 2 hours.)
Answer: the drawdown of the lake in centimeters is 3.02 cm
Explanation:
Given data;
Power of motor = 1000 W
efficiency M = 50% = 0.5
so Effective power = 1000 × 0.5 = 500 W
time t = 2 hrs = 2 × 60 × 60 = 7200 secs
so
Energy = p × t = 500 × 7200 = 3,600,000 J
Now Energy required to pump water to height h = mgh (J)
3,600,000 J = mgh
m = 3,600,000 / gh
given that; h is 2.43 and we know that g is 9.81, we substitute
m = 3,600,000 / (9.81 × 2.43)
m = 3,600,000 / 23.8383
m = 151017.48 kg
Now we know that, Volume = Mass / Density [density of water]
so, Volume = 151017.48 / 1000
Volume = 151.01748 kg/m³
given that surface area = 5000 m²
Drawdown = 151.01748 / 5000
Drawdown = 0.3020 m
we convert to centimeter
Drawdown = 0.3020 m × 100
Drawdown = 3.02 cm
Therefore the drawdown of the lake in centimeters is 3.02 cm
A centrifugal pump is installed in a pipeline to raise water14.9 m into an elevated holding tank. The length of the ductileiron pipeline (f=0.019) connecting the reservoirs is 22.4 m. Thepipe is 5.0 cm in diameter and the performance curve of the pump isgiven by Hp =23.9?7.59Q2 where Hp is in meters, Q is in liters persecond, and the equation is valid for flows up to 1.5 L/s. Usingthis pump, what flow do you expect in the pipeline if minor lossesare ignored? What pump head is required for this flow?
Answer:
Hp = 23.86 m
Hence, 23.86 m head pump is required for this flow.
Explanation:
Solution:
Data Given:
Elevation = Z = 14.9 m
Friction of the ductile iron pipe = f = 0.019
Length of the ductile iron pipe connecting the reservoirs = 22.4 m
Diameter of the Pipe = D = 0.5 cm
Radius of the Pipe = r = D/2 = 0.25 cm
Performance Curve of the Pump = Hp = 23.9 - 7.59[tex]Q^{2}[/tex] , where Hp is in meters.
[tex]Q^{}[/tex] is in Liters/second and equation is valid for 1.5 L/s
We are asked to find out the pump head required for this flow.
We need to apply the energy equation for this problem:
Energy Equation:
[tex]\frac{P1}{\beta 1} + \frac{v1^{2} }{2g} + Z1 + Hp = \frac{P2}{\beta 2} + \frac{v2^{2} }{2g} + Z2 + H_{L}[/tex]
where, [tex]\beta[/tex] = specific weight of the fluid.
v1 = 0
P1 = P2 = P
Z1 = 0
Z2 = 14.9
Hence,
New equation is:
[tex]Hp = \frac{v2^{2} }{2g} + Z2 + H_{L}[/tex]
And
[tex]H_{L}[/tex] = [tex]\frac{fLv^{2} }{2gD}[/tex]
So,
[tex]Hp = \frac{v2^{2} }{2g} + Z2 + \frac{fLv^{2} }{2gD}[/tex]
Now, converting formula of v into terms of Q, we get
Hp = 23.9 - 7.59[tex]Q^{2}[/tex]
[tex]Hp = \frac{Q2^{2} }{2(9.81)(\frac{\pi }{4}(0.05^{2}))^{2} } + 14.9 + \frac{(0.09)(22.4)Q^{2} }{12.1(0.05)^{2} }[/tex]
23.9 - 7.59[tex]Q^{2}[/tex] = [tex]\frac{Q2^{2} }{2(9.81)(\frac{\pi }{4}(0.05^{2}))^{2} } + 14.9 + \frac{(0.09)(22.4)Q^{2} }{12.1(0.05)^{2} }[/tex]
Solving for Q, we will get
9 - 7.59[tex]Q^{2}[/tex] = 13233.71[tex]Q^{2}[/tex] + 112555.37[tex]Q^{2}[/tex]
[tex]Q^{}[/tex] = 7.154 x [tex]10^{-5}[/tex] [tex]m^{3}/s[/tex]
Converting it into L/s
Q = 0.0715 L/s
Putting this value of Q into the Hp equation to get the required answer:
Hp = 23.9 - 7.59[tex]Q^{2}[/tex]
Hp = 23.9 - 7.59 x [tex]0.0715^{2}[/tex]
Hp = Pump head
Hp = 23.86 m
Hence, 23.86 m head pump is required for this flow.
In the given example, which type of interior designer is Sarah? Sarah is an interior designer. The state in which she resides applies practice acts to interior design professionals. Therefore, Sarah carries the title of a ____ interior designer.
Answer:
Sarah is a professional interior designer.
Therefore, Sarah carries the title of a _registered___ interior designer.
Explanation:
Some states require only the licensed designers to carry out interior designs, while some others allow both the licensed and unlicensed interior designers to carry on the work of interior designers. In the states where only the licensed designers are allowed to use the title of interior designer, they are registered after passing the state-prescribed examinations and meeting some professional experience requirements. The most common exam is the National Council for Interior Design Qualification (NCIDQ) examination, which only bachelor degree holders in interior design are allowed to sit for.
Two technicians are discussing hd-obd for trucks technician a says that the simplest most familiar definition is the diagnostic function of electronic control system to identify or self-diagnose system fault and report fault codes technician b says automotive and light duty truck versions of OBD is called OBD2 who is correct
Answer:
Two technicians are discussing HD-OBD for trucks
Technician a says that the simplest most familiar definition is the diagnostic function of electronic control system to identify or self-diagnose system fault and report fault codes.
Technician A is correct.
Explanation:
Onboard Diagnostics (OBD) is a vehicle's self-diagnostic tool which enables technicians to access the diagnostic information for the purpose of performance monitoring and analyzing repair needs of vehicles. OBD2 is the diagnostic system that is included in every vehicle made after 1996. The diagnostics can check the engine and other vehicle systems and also communicate possible vehicular glitches that happen.
Most of the work that engineers do with fluids occurs in nature. True False
Answer:
It's False
Explanation:
I did the assignment
Find the derivative of y = sin(ln(5x2 − 2x))
Answer:
[tex]y = \cos[\ln x + \ln (5\cdot x - 2)]\cdot \left(\frac{1}{x} + \frac{5}{5\cdot x-2} \right)[/tex]
Explanation:
Let [tex]y = \sin[\ln(5\cdot x^{2}-2\cdot x)][/tex] and we proceed to find the derivative by the following steps:
1) [tex]y = \sin[\ln(5\cdot x^{2}-2\cdot x)][/tex] Given
2) [tex]y = \sin [\ln[x\cdot (5\cdot x - 2)]][/tex] Distributive property
3) [tex]y = \sin[\ln x + \ln (5\cdot x - 2 )][/tex] [tex]\ln (a\cdot b) = \ln a + \ln b[/tex]
4) [tex]y = \cos[\ln x + \ln (5\cdot x - 2)]\cdot \left(\frac{1}{x} + \frac{5}{5\cdot x-2} \right)[/tex] [tex]\frac{d}{dx} (\sin x) = \cos x[/tex]/[tex]\frac{d}{dx}(\ln x) = \frac{1}{x}[/tex]/[tex]\frac{d}{dx}(c\cdot x^{n}) = n\cdot c\cdot x^{n-1}[/tex]/Rule of chain/Result
How did ancient machines pave the way for improvement
Answer:
----------
Explanation:
Ancient machines have paved the way for improvement by being the foundation for change. these machines made it possible to find flaws so in the next generations, they could fix, develop, and produce better quality machines. eventually this process has reached the present time but after today, the process will continue to produce even better quality machines than the time before. I hope this helps!
Saturated refrigerant-134a vapor at 15 psia is compressed reversibly in an adiabatic compressor to 80 psia. Determine the work input to the compressor. Use the tables for R-134a.
The initial enthalpy and the entropy of the saturated water can be found out from the table of A-12E
i.e. [tex]$h_1= 101 \ \text{Btu/lbm}$[/tex]
[tex]$s_1 = 0.22717 \text{ Btu/lbmR}$[/tex]
Since the process mentioned above is an adiabatic compression process, the entropy will remain constant throughout the process. Therefore, we take the value of entropy and the final pressure using the table with few interpolations and also approximations to find the final enthalpy. It is given by :
[tex]$h_2= 116.09 \text{ Btu/lbm}$[/tex]
So the work input from the energy balance equation :
[tex]$\dot{W} + \dot{m}h_1 = \dot{m}h_2$[/tex]
[tex]$w=h_2 - h_1$[/tex]
= 116.09 - 101
= 15.09
Therefore, [tex]$w= 15.09 \text{ Btu/lbm}$[/tex]
What should Kimi have done to ensure that she was acting legally and ethically?
Answer:
Kimi have done to ensure that she was acting legally and ethically by following the measure that are discussed below in detail.
Explanation:
Legal measures are those measures that are outlined in regulatory laws. Ethical measures are based on the human postulates of morality and wrongdoing. The distinctions between them are these: Legal measures are based on transcribed law, while ethical measures are based on human rights and violations.
Find and write the mathematical problem formulation of shortest path problem
Which of the following statements are true about staying safe while
working around all caught-in caught-between hazards?
Select two answers that apply.
What you should do changes based on hazards you’re exposed to.
You should be aware of any hazards that are present
You should be aware of the only hazards indicated as critical by management
What you should do is the exact same no matter the hazard
Answer:
What you should do changes based on the hazards you're exposed to.
You should be aware of any hazards that are present.
are considered a form of personal protective equipment (PPE) for eyes.
Answer:
All of the above
Explanation:
what document is the primary reference document when making ethical decisions?
The current at resonance in a series L-C-R circuit is 0.2mA. If the applied voltage is 250mV at a frequency of 100 kHz and the circuit capacitance is 0.04 microfrad . Find the circuit resistance and inductance
Answer:
The resistance of the circuit is 1250 ohmsThe inductance of the circuit is 0.063 mH.Explanation:
Given;
current at resonance, I = 0.2 mA
applied voltage, V = 250 mV
resonance frequency, f₀ = 100 kHz
capacitance of the circuit, C = 0.04 μF
At resonance, capacitive reactance ([tex]X_c[/tex]) is equal to inductive reactance ([tex]X_l[/tex]),
[tex]Z = \sqrt{R^2 + (X_ l - X_c)^2} \\\\But \ X_l= X_c\\\\Z = R[/tex]
Where;
R is the resistance of the circuit, calculated as;
[tex]R = \frac{V}{I} \\\\R = \frac{250 \ \times \ 10^{-3}}{0.2 \ \times \ 10^{-3}} \\\\R = 1250 \ ohms[/tex]
The inductive reactance is calculated as;
[tex]X_l = X_c = \frac{1}{\omega C} = \frac{1}{2\pi f_o C} = \frac{1}{2\pi (100\times 10^3)(0.04\times 10^{-6} ) } = 39.789 \ ohms\\[/tex]
The inductance is calculated as;
[tex]X_l = \omega L = 2\pi f_o L\\\\L = \frac{X_l}{2\pi f_o}\\\\L = \frac{39.789}{2\pi (100 \times 10^3)} \\\\L= 6.3 \ \times \ 10^{-5} \ H\\\\L = 0.063 \times \ 10^{-3} \ H\\\\L = 0.063 \ mH[/tex]
The powertrain system is one of the major systems on the vehicle. Tech A states that this system helps to power the vehicle down the road. Tech B states that this system usually contains the engine and transmission. Who is correct?
Answer:
The powertrain system is one of the major systems on the vehicle.
Tech B states that this system usually contains the engine and transmission.
Technician B is correct.
Explanation:
The powertrain system contains three interconnected systems: the engine, the transmission, and the drivetrain. The engine part is the power source of the powertrain that ensures vehicular movement. The transmission system converts the engine's power into the normal movement of the vehicle. The drivetrain consists of the transmission, driveshafts, and the axles. These three parts of the powertrain system work seamlessly to ensure that the vehicle is able to move with some speed back and front, as may be desired.
1 british gallon = .....litres.
a:4.546
b:3.785
c.5.456
d.7.385
Answer:
c
Explanation:
I live in britian
A 280 km long pipeline connects two pumping stations. It is desired to pump 0.56 m3/s of oil through a 0.62 m diameter line, the discharge station is 250 m lower in elevation than the upstream station, and the discharge pressure is to be maintained at 300 kPa. The oil has a dynamic viscosity of 3.645 x 10-3 Pa·s and a density of 810 kg/m3. The pipe is constructed of commercial steel and the inlet pressure may be taken as 1 atmosphere. Considering the mechanical-energy friction loss Ff, determine the power required to pump the oil if the power efficiency is 70%. Develop a sketch of the piping system considered.
Ignore energy losses due to contraction, expansion & 90° bends!!!
Which one of the following would appear as a thin line on a drawing?
A. Centerline
B. Cutting plane line
C. Short break line
D. Outline
Answer:
try b
Explanation:
one number is 11 more than another number. find the two number if three times the larger number exceeds four times the smaller number by 4
Answer:
a = 40
b = 29
Explanation:
Give a place holder for the numbers that we don't know.
Lets call the two numbers a and b.
From the given info, we can write an expression and solve it:
"one number is 11 more than another number"
a = 11 + b
from this, we know that a > b.
''three times the larger number exceeds four times the smaller number by 4"
3a = 4b + 4
Now we have 2 equations, we can use them to solve using whatever method you want.
a = 11 + b
3a = 4b + 4
I will be using matrices RREF to solve for this.
a - b = 11
3a - 4b = 4
[tex]\begin{bmatrix}1 & -1 & 11\\3 & -4 & 4 \end{bmatrix}[/tex]
[tex]\begin{bmatrix}1 & 0 & 40\\0 & 1 & 29 \end{bmatrix}[/tex]
a = 40
b = 29
A set of civil construction plans shows a distance of 131 meters across the front of a piece of property. You need to convert this value to feet. You know that one foot equals approximately 0.305 meters. What is the distance in feet, to the nearest tenth of a foot?
The distance when the civil construction plans shows a distance of 131 meters across the front of a piece of property is 430 feet.
How to calculate the distance?From the information given, it was stated that the civil construction plans shows a distance of 131 meters across the front of a piece of property.
Therefore, since one foot equals approximately 0.305 meters, the distance will be:
= 131/0.305
= 429.5 feet
= 430 feet approximately
In conclusion, the distance is 430 feet.
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For the beam loaded as shown in Fig Q2a. perform the following task:
Calculate the support reactions at A and E;
(i)
Draw the shear force diagram for the beam showing all important
values;
>
(iii)
Draw the bending moment diagram for the beam showing all
important values.
6 kN
10 KN
2 kN/m
B
D
1 m
1 m
1 m
1 m
Answer:
a
Explanation:
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Omg I just got 17/25 questions wrong using this on an Ag test , but got 100’s every time on health
Answer:
sorry im answering questions for the points cuz im built dfferent
Explanation:
Answer: That happens to me too sometimes. I hate when people give the wrong answers...like if u don't know the answer, then don't respond
When handling chemicals and solvents, technicians are recommended to
Answer:
To wear PPEHave prior knowledge of explosive levels and elemental propertiesKnow procedure to eliminate any threatAnswer
have PPE on wash hands after
Explanation:
What is electrical energy being transformed into? How do you know?
meaning of construction
Answer:
the action of building something, typically a large structure.
Explanation:
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Typical journal-to-bearing clearance is......
A) 0.00015 to 0.00018 inch
B)0.0005 to 0.0025 inch
C) 0.15 to 0.25 inch
D)0.02 to 0.035 inch
The typical journal-to-bearing clearance for engines is,
B) 0.0005 to 0.0025 inch
Given that,
To find the typical journal-to-bearing clearance for engines.
Now, The range 0.0005 to 0.0025 inch represents the recommended clearance between the rotating journal of the crankshaft and the bearing surface to ensure proper lubrication and minimal friction.
Hence, The correct option for typical journal-to-bearing clearance for engines is,
B) 0.0005 to 0.0025 inch.
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please help me solve this
Answer:
Following are the solution to this question:
Explanation:
[tex]\to \Sigma F_x = ma_x \\\\\to 3200 t^2 -440 (9.81) (\frac{8}{17}) = 440 (a) \\\\\to 3200 t^2 -2031.24 = 440 (a)\\\\\to a= 7.27t^2 -4.616\\\\\to dv=a.dt \\\\\to \int^{v}_{2} dv = \int^{2}_{0} (7.27t^2 -4.616) dt\\\\\to v-2 = 7.27 \frac{t^3}{3} - 4.616 t^{2}_{0}\\\\\to v-2 = 7.27 \frac{2^3}{3} - 4.616 {2} \\\\\to v-2 = 10.154\\\\\to v= 12.154 \ \frac{m}{s}\\[/tex]
Why did the computer go to the doctor ?
Answer:
because it had a virus
Explanation:
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