The volume of the solution in milliliters that will need to be delivered when the concentration of the solution is 5.00 mg/mL is 55.4 mL
The given solution contains 5mg in 1 mL
1 mg of cleocin will be present in 1/5 ml of solution.
277 mg of cleocin IV will be present in 1/5x277
that is 55.4 mL of solution
So the volume of solution is 55.4 mL
The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value. The unitary method is used to write the value of a single unit from a given multiple.To learn more about unitary method visit:
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Which of the following measurements have four significant figures? Select all that apply. A.1,001g B.120.0mL C.0.0007cm D.5,000s
Answer:
The answer(s) will be A and B
Explanation:
Hope this helps and may God bless you<3
Cells are not as large as this cube.Explain why in terms of a cell’s surface area-to-volume ratio.
Cells cannot be as large as a cube because the surface area to volume ratio decreases as cell size increases.
What are cells?
The cell is the fundamental structural and functional unit of all living things. Every cell is made up of cytoplasm surrounded by a membrane that includes several biomolecules such as proteins and nucleic acids.
Cells cannot be as large as a cube because the surface area to volume ratio decreases as cell size increases. As a result, if the cell develops beyond a certain point, the cell contents will be unable to cross the cellular membrane as quickly in order to accommodate the increased cellular volume.
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1. If the absorbance of a 0.000040 M dye sample is 0.43 in a cuvette of path length 1.0 cm, what is the extinction coefficient of the dye?
The molar extinction coefficient of the given dye will be calculated as 10,750 M⁻¹cm⁻¹ which is done by the formula given by Beer Lambert's Law.
According to the Beer-Lambert law, there is a linear relationship between a solution's concentration and absorbance, making it possible to determine a solution's concentration by observing its absorbance.
Beer Lambert's -equation is as follows:
A=ϵbc
where:
A is absorption
ϵ represents the molar extinction coefficient.
b is the length of the path (in cm)
c here refers to molar concentration
The data provided for the stock solution can be used to compute the molar extinction coefficient:
A= ∈bc
0.43= ∈(1cm) ( 0.000040)
∈=10,750 M⁻¹cm⁻¹
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I need help please..
The mass of the object is obtained as 608.5 grams.
What is density?The term density refers to the ratio of the mass to the volume of an object. The density of an object does not change thus we could use the density of an object to identify that object. If we have the density of the object, that alone could be used to trace the exact kind of material that we are dealing with.
Now we know that the density of the object is 6.095 g/cm^2
Volume of the object is obtained as 99.830 mL
Density = mass/volume
mass = density * volume
mass = 6.095 g/cm^2 * 99.830 mL
mass = 608.5 grams
Hence, the mass of the object is obtained as 608.5 grams.
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100 points! In the picture below
A biochemical engineer isolates a bacterial gene fragment and dissolves a 12.0−mg sample in enough water to make 30.0 mL of solution. The osmotic pressure of the solution is 0.340 torr at 25°C. (a) What is the molar mass of the gene fragment? g/mol (b) If the solution density is 0.997 g/mL, how large is the freezing point depression for this solution (Kf of water = 1.86°C/m)?
The molar mass of the gene is 2.22 * 10^4 g/mol and the freezing point depression is 3.35 * 10^-5 °C
What is the molar mass?We know that the osmotic pressure is obtained by the use of the formula';
π = iCRT
i = Van't Hof factor
C = concentration of the solution
R = gas constant
T = temperature
C = π/iRT
C = 0.340/1 * 62.4 * 298
C = 1.8 * 10^-5 M
Now;
n/M = C * V
12 * 10^-3/M = 1.8 * 10^-5 * 30 * 10^-3
M = 12 * 10^-3/1.8 * 10^-5 * 30 * 10^-3
M = 12 * 10^-3/ 5.4 * 10^-7
M = 2.22 * 10^4 g/mol
Mass of the solution is obtained from density * volume = 0.997 g/mL * 30.0 mL = 29.91 g
Molality of the solute = 12 * 10^-3g/ 2.22 * 10^4 g/mol * 1/ 29.91 * 10^-3
= 1.8 * 10^-5 m
ΔT = K m i
ΔT = 1.86°C/m * 1.8 * 10^-5 m * 1
ΔT = 3.35 * 10^-5 °C
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Phthalonitrile (C₈H₄N₂) is produced by the ammoxidation of o-xylene (C₈H₁₀) according to the following reaction:
C₈H₁₀(l) + O₂(g) + NH₃(g) → C₈H₄N₂(s) + H₂O(l)
How many moles of water would be produced by the complete ammoxidation of 145.0 grams of o-xylene?
0.6066 moles of water are produced by complete ammoxidation of 145 g of o-xylene.
How are number of moles calculated?Number of moles are calculated by dividing the mass by the molar mass of the substance.In the reaction between o-xylene ,ammonia and oxygen pthalonitrile is produced.
Here, the number of o-xylene is calculated by the above mentioned formula which is 1.365 moles.Then, as per stoichiometry and balanced chemical equation ,
1.365 moles of o-xylene×8 moles of water/1 mole of xylene ×18 g water
=0.6066 moles
Thus,0.6066 moles of water are produced from 145 g of o-xylene.
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12. What structures does the fish have that are NOT present in the fly?
A car travels 65km/hour and gets 15miles/gallon of gasoline. How many gallons are needed for a 3 hour trip?
Answer:
pls check your question again i think you question is wrong.
Number of O atoms in 8.25x10-3 mol Al(NO3)3
A graduated cylinder is filled to 20mL. A piece of silver is added to the cylinder and the volume of water increases to
30mL. The density of silver is 10.49 g/mL, what is the mass of this piece of silver?
Answer:
104.9 g
Explanation:
If you add a piece of silver to water which increases the volume of the water from 20 mL to 30 mL, according to water displacement, the piece of silver must be 10 mL (30 mL - 20 mL = 10 mL).
You can find the mass by multiplying the volume of silver by the density. The denisty exists as a ratio comparing the mass (g) of silver per every 1 mL. It is important to arrange the ratio in a way that allows for the cancellation of units (mL should be in the denominator).
10 mL 10.49 g
-------------- x ----------------- = 104.9 g
1 mL
The surface temperature on Mercury has been measured to be 603 K . What is this temperature in degrees Celsius? 603 K=
If the surface temperature on Mercury has been measured to be 603 K, this temperature is equivalent to 329.84°C (degrees Celsius).
What is temperature?Temperature is the measure of cold or heat, often measurable with a thermometer.
Kelvin, which is denoted by K, is the International System of Units (S.I unit) or the base unit of thermodynamic temperature.
However, Kelvin can be converted to degree Celsius as follows:
K = 273.16 + °C
According to this question, the surface temperature on Mercury has been measured to be 603 K. This temperature can be converted to °C as follows:
603K = 273.16K + °C
°C = 603 - 273.16
°C = 329.84°C
Therefore, if the surface temperature on Mercury has been measured to be 603 K, this temperature is equivalent to 329.84°C (degrees Celsius).
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How many P atoms are there in 4.35 moles of P?
Answer:
2.6187E24 same as 2.6187 × 10^24
Explanation:
we must use 1 conversion fact 6.02E23
1. Convert to Atoms of P from Moles of P
4.35 × 6.02E23 = 2.6187E24
Please let me know if i need to further eloborate :)
classify matter, compounds, an chemical reaction
The substance is pure matter, it is either an element or a compound. If a substance can be divided into its component elements matter, it is a compound.
If a substance is not chemically pure, it is either a homogeneous mixture or a heterogeneous mixture.
If the composition remains the same throughout, the combination is homogeneous.
The two major categories into which matter can be categorised are pure substances and mixtures. Pure substances and mixtures are the two major categories into which matter may be divided.
A sort of matter known as a pure substance has qualities that are continuous throughout the sample and a stable composition that makes it the same everywhere. A matter is a substance made up of two or more different components.
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Watch the video above and write a short summary of some of the major steps.
Make sure to use the following words in your summary:
mandrel
graphite or carbon fiber
flag
blank
epoxy
emery powder
guides
seat
wrap
and anything else you found interesting.
Answer:
Explanation:
5568 is c
Answer:
the carbon fiber hood on the drift car guided eyes to the car and the driver in the seat blankly stairs
What is the concentration in molarity of a solution which is 4.61 %m/v
xylene (MM = 106.2 g/mol ) in toluene (MM = 92.30 g/mol)?
The molarity of the given solution will be 0.434 M . Since the concentration is given in percentage in mass/volume form, the molarity of the solution will be calculated as follows:
Here,
Concentration= 4.61% m/v
Molecular mas of xylene= 106.2g/mol
Moecular mass of toulene = 92.30g/mol
Molarity is defined to be as moles of solute present per liter of solution. Here we are dealing with two liquids, the one having greater amount will be taken as the solvent and the one having lower amount will be taken as the solute
4.61% m/v = 4.61 g xylene/100 ml toulene
= 4.61 g xylene/L
Now Converting this to moles / L we will get:
46.1 g xylene x 1
mol/106.2 g = 0.434 moles xylene per L of toulene
Molarity (M) = No of moles of solute / Volume of solute( L)
= 0.434 moles / 1 L
= 0.434 M
So, the concentration of the given solution in molarity will be equal 0.434M
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How good were your predictions in the warm-up?
can't give an answer to your question if there isn't a picture or being specific in the question.
Answer: 2 Out of 4
Explanation:
Bc my mom told me
8. Gold and copper are both metallic conductors that have resistivity in the range of 2 x 10-²
2m. The semiconductor silicon has a resistivity of 6.4 x 102m. On an atomic level, what
causes the resistivity of silicon to be so much higher?
Gold and copper are both metallic conductors that have resistivity in the range of 2 x 10-².
The semiconductor silicon has a resistivity of 6.4 x 102m.
Gold and copper are metals whereas silicon is a semiconductor . Metals are good conductors and semi conductors are not as good as metals and hence they have more resistivity. This can be attributed to band gap at the atomic level. The energy gap between valence band and conduction band is very less in metals but considerable more in semiconductors. For conduction to happen, the electrons must move from valence band to conduction band. This is easier in metals and hence resistivity is lesser in metals than in semiconductors.To know more about semiconductor visit :
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the half life of throium is 18.72 days. how many days are required for 1000 gr to become 250 gr?
how many helium atoms have have the same mass as four atom of lithium
Answer:
1 helium has 4 atomic mass and 1 sulfur has 32 atomic mas.
a king brings a bar of gold to you and tells you he was told it was real gold, but he is wondering if that is true. his gold bar has a mass of 10 grams and has a volume of 1.05. using the chart below, is the kings gold bar real gold, if not, what metal is it?
The density of the given gold bar is 9.52 .
The density of gold metal used for jewellery is 19.32g/cm³
Given gold bar has mass of 10 grams and has volume of 1.05.
Density = mass /volume ⇒D =10/ 1.05= 9.52 g/cm³
so, the gold bar king has is not pure gold.
The acid test for gold is by rubbing the gold-colored item on black stone, which will leave an easily visible mark. The mark is then tested by applying nitric acid, which dissolves the mark of item that is not gold. If the mark remains same, it is tested by applying aqua regia (nitric acid and hydrochloric acid).
In a nitric acid test, a jeweler places a few drops of the acid on the piece of item and watches for the reaction. With copper, the reaction causes the liquid to turn green, give off fumes, and bubble. This response is called a hard cupric reaction and indicates that the item is not real gold
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Calculate the velocity of an electron ejected if 690.0 nm of light is applied to the surface. A wavelength of 795 nm has sufficient energy
to eject electrons.
The speed of an electron expelled from a surface when light with a wavelength of 690.0 nm is delivered. A wavelength of 795 nm has sufficient energy to eject electrons is v = 2.886 × 10⁵ m/s.
What are frequency and wavelength?The wavelength, which will also apply to troughs, is the separation between two wave crests. The frequency is measured in cycles per second (Hz), which is the quantity of vibrations that cross a specific area in a second (Hertz). In this article, the relationship between wavelength and frequency is covered.
Briefing:hf = Φ + KE
Φ = Work function is energy required to remove an electron in (J)
h = Planck’s constant = 6.626 x 10⁻³⁴ J • s
f = threshold frequency or higher
KE = maximum kinetic energy of emitted electrons (J)
Electron mass is 9.109 x 10⁻³¹ kg kg and the speed of light is 2.998 x 10⁸ m/s
The energy of a photon of 795 nm light will give the work function Φ.
λ = 795 nm = 7.95 x 10⁻⁹ m
E = (hc/λ) = 2.499 x 10⁻¹⁹ J
Find the energy of a photon with wavelength λ = 336.0 nm = 3.360 x 10⁻⁷ m
m = 9.1 * 10⁻³¹ kg
1/2mv² = hc (1/690×10⁻⁹ - 1/795 × 10⁻⁹)
1/2mv² = 6.62 × 10⁻³⁴ × 2.998 ×10⁸ (10⁹/690 - 0.001258 × 10⁹⁹)
1/2mv² = 19.874 × 10⁻²⁶ (0.001449 × 10⁻⁹ - 0.001258 × 10⁻⁹)
1/2mv² = 19.847 × 10⁻²⁶ (1.44 * 10⁻⁶ - 1.258 × 10⁶)
1/2mv² = 19.847 × 10⁻²⁰ (1.449 - 1.258)
1/2mv² = 19.847 × 10⁻²⁰ × 0.191
1/2mv² = 3.791 × 10⁻²⁰
v² = 3.791 × 10⁻²⁰/m
v² = 7.582 × 10⁻²⁰/9.1 × 10⁻³¹
v² = 0.8332 × 10¹¹
v² = √8.332 × 10¹⁰
v = 2.886 × 10⁵ m/s.
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A farmer used too much pesticide (bug spray) and it washed down into the pond environment. What could happen to the Biotic AND Abiotic factors in the pond?
In a pond, the biotic factors include:
fishescrabssnailsplanktonalgaeThe abiotic factors are:
sunlighttemperaturerainfalldissolved mineralsWhat are the biotic and abiotic factors in a pond?Biotic factors are the living components of an environment whose activities affect the environment.
Biotic factors include plants, animals, bacteria, fungi, etc,
Abiotic factors are the non-living components of an environment that affect the environment.
Biotic and abiotic factors interact with each other.
In a pond, the biotic factors include:
fishescrabssnailsplanktonalgaeThe abiotic factors include:
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Aluminium having atomic mass 27 g mol crystallises in face centred pack
The number of unit cells in the given quantity is 2.23x10²³ unit cells
:Given Aluminum has an atomic mass of 27g mol-1
>Crystal is face-centered cubic structure
>number of aluminium atoms in l0 g mass
so w =10g
> the number of unit cells in the given quantity is to be calculated
Number of atoms of Al = (mass /molar mass ) x Nₐ
=(w/M)xNa , where Na =6.022x 10²³
There are 4 atoms present in the unit cell it will crystallize in a face-centered cubic crystal
.>.On solving the above values
we get the number of unit cells as= (10/27)x 6.022x10²³ unit cells
The number of unit cells in the given quantity is 2.23x10²³ unit cells
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How many cubic centimeters are there in 8.14 yd3
Express the volume in cubic centimeters to three significant figures.
The number of cubic centimeters (cm³) in 8.14 yd³ is 6.22×10⁶ cm³
Conversion scaleCubic yard (yd³) can be converted to cubic centimeters (cm³) by using the folloing scale
1 yd³ = 764555 cm³
With the above conversion scale, we can obtain the number of cubic centimeters (cm³) in 8.14 yd³. Details below
From the question given above, filling data were obtained:
Volume (in yd³) = 8.14 yd³ Volume (in cm³) =?1 yd³ = 764555 cm³
Therefore,
8.14 yd³ = (8.14 yd³ × 764555 cm³) / 1 yd³
8.14 yd³ = 6.22×10⁶ cm³
From the calculation made above, we can conclude that there are 6.22×10⁶ cubic centimeters in 8.14 yd³
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How do you compare the direction of the applied force and friction force
The comparison of the direction of the applied force and friction force is that Friction force always acts opposite to the direction of the applied force.
Applied force define as the force applied to by an object to other object.applied force is contact force or a non contact force.
Friction force is the force exerted by a surface that resist the motion of body or against motion of body.friction is contact force. When the applied force increases , the frictional force also increases. when the applied force is larger than friction force object will move.
Example , if we applied force to the right direction the friction force acts in left direction.that is opposite to applied force.
Therefore,The comparison of the direction of the applied force and friction force is that Friction force always acts opposite to the direction of the applied force.
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what are the cations and anions of NiS
The correct answer is cation Ni +2 and anion S 2-.
Nickel sulfide
It is discovered that the bonding in NiS is remarkably similar to that in NiO, with a covalent component resulting from bonds between the Ni 3d and the S 3p atom and an ionic contribution resulting from the donation of the Ni 4s electron to the S atom.
With heated concentrated nitric acid or aqua regia, NiS can be easily reactively dissolved, which is followed by sulphur precipitation.
F belongs to Group 7A, while Ni is in Group 5A. (EN: N=3.0, F=4.0) The NF3 molecule and each N-F bond are both polar. F possesses a partial positive charge in the N-F bond. The NF3 molecule and each N-F bond are both non-polar.
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8.31 (a) State whether or not the bonding in each substance is
likely to be covalent: (i) iron, (ii) sodium chloride, (iii) water,
(iv) oxygen, (v) argon. (b) A substance XY, formed from two
different elements, boils at -33 °C. Is XY likely to be a cova-
lent or an ionic substance?
a. (i) The bonding in iron is not covalent.
(ii) NaCl i.e. sodium chloride do not have covalent bond.
(v) Argon is an inert gas do not form molecules by any sort of bonding.
b. A substance XY, formed from two different elements, boils at -33 °C is XY likely to be covalent. Since its boiling point is much below zero degree Celsius, the binary compound is a gas at room temperature.
Metallic bonding is a type of bonding that exists in iron. Iron is a metal, and all metals have a specific kind of connection that isn't covalent or ionic called metallic bonding. The outer shells of neighboring atoms overlap during metallic bonding, and the outer shell electrons are free to move about the lattice.
The hydrogen and oxygen atoms in water share their electrons hence covalent bonding.
Sodium Chloride (NaCl) is a pure ionic compound and not a covalent compound. The two atoms transfer their electrons to form ions, Na+ and Cl-.
The two oxygen atoms share two pairs of electrons, so two covalent bonds hold the oxygen molecule together.
Argon is an inert gas do not form molecules by any sort of bonding.
For the substance XY, its boiling point is beyond zero which happens to be present in case of gases thus it is a covalent substance.
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Sodium bicarbonate (NaHCO3) is commonly known as baking soda. Sodium bicarbonate is a white solid that can dissolve in water. Under the proper conditions, sodium bicarbonate can release carbon dioxide (CO2) gas.
Select all of the physical properties of sodium bicarbonate
Sodium bicarbonate is a white crystalline powder. NaHCO3 + H+ (from tartaric acid)→ CO2 + H2O + Sodium tartrate.
Sodium bicarbonate:
Sodium bicarbonate is a white crystalline compound. It is alkaline. Sodium bicarbonate is a compound made up of sodium, hydrogen, carbon, and oxygen.
Sodium bicarbonate can be used as an antacid. It can also be used in making ear drops. It is used in cleaning the mouth and teeth because of its antibacterial properties.
The chemical reaction when sodium bicarbonate reacts with tartaric acid is given below:
NaHCO3 + H+ (from tartaric acid)→ CO2 + H2O + Sodium tartrate.
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You need to prepare 250ml of a 0.015 M CuSo4 solution. You are given .015M CuSO4 solution. What size volumetric pipet do you need to prepare your 250ml solution?
0.1 ml of volumetric pipette is required to prepare 250 ml of copper sulfate solution.
How to determine size of pipettes while making solutions?Size of pipettes is determined by a wide range of factors such as physical properties of liquid,precision and accuracy of results to be obtained.
For knowing what size of pipette is to be used for making 0.015 M copper sulfate solution ,first the mass of copper sulfate to be used in making the solution is to be determined.Substituting the known parameters in the molarity formula mass of copper sulfate to be used is determined.
M=mass/molar mass×1/volume of solution in liters
mass=0.015×159.60×0.25=0.5985 g
Now to find out the volume of pipette to be used,using the density formula the volume of pipette can be obtained.
volume=0.5985/3.6=0.1
Therefore,0.1 ml of pipette is to be used for preparing 250 ml of 0.015 M copper sulfate solution.
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