Joey is 13 years and 5 months old. His friend Suzy is 4,860 days old.

Who is older?

How many months old is the older person?

Answer:

-5

Step-by-step explanation:

each number in that line is just being subtracted by 5 each time. like 45-5=40 and 40-5=35 and so on.

Answer:

A. 1/5

Step-by-step explanation:

The chances of drawing another orange would be 20%. And since means 1/5 in fraction form, A. is the answer.

Answer:

9669

Step-by-step explanation:

69

Answer:

с ) 20%

Step-by-step explanation:

There are 5 orange candies, and 25 total candies to choose from. If you only want to pick the orange candies, then the probability would be 5/25, or 1/5.

1/5, in percentage, is 20%.

Answer:

3/18

Step-by-step explanation:

Answer:

18:3

Step-by-step explanation:

acorns go first then squirrels cause the question says acorns TO squirrels

Answer:

13n+2

Step-by-step explanation:

find the difference between the numbers which is 13

》13n

from 13 to 15 you add 2

》13n+2

Answer:

7

Step-by-step explanation:

21,30,39,39,47,47,48.

basically 6|2 means 62 same with the others.

HOpe this helps plz hit the crown :D

Answer: Required expression: [tex]\dfrac14\times(18+16)[/tex]

Result: [tex]\dfrac{17}{2}[/tex]

Step-by-step explanation:

Given phrase:  [tex]" \dfrac14\text{ of the sum of } 18\text{ and }6. "[/tex]

Required expression: [tex]\dfrac14\times(18+16)[/tex]    ['+' used to express sum, 'x' used in place of 'of']

Since 18+16 = 34

Then,

[tex]\dfrac14\times(18+16)=\dfrac14\times34 \\\\=\dfrac{1}{2}\times17\ \ \text{[Divide numerator and denominator by 2]}\\\\=\dfrac{17}{2}[/tex]

Hence,     [tex]\dfrac14\times(18+16)=\dfrac{17}{2}.[/tex]  

Answer:

The equation for the nth term of  the given arithmetic sequence is: [tex]\mathbf{a_n=13n+22}[/tex]

Step-by-step explanation:

We need to write an equation for the nth term of  the arithmetic sequence:

15,28,41 ....

The equation for arithmetic sequence is: [tex]a_n=a_1+(n-1)d[/tex]

Where [tex]a_n[/tex] is the nth term, [tex]a_1[/tex] is first term and d is common difference

In the given sequence we have:

a₁ = 15

a₂ = 28

We can find common difference using the formula:

[tex]a_n=a_1+(n-1)d\\Put\: n=2, a_2=28\: and\: a_1=15\\a_2=a_1+(2-1)d\\28=15+d\\d=28-15\\d=13[/tex]

So, the common difference d is 13

Now, equation for nth term will be:

[tex]a_n=a_1+(n-1)d\\Put\:a_1=15, d=13\\a_n=15+(n-1)13\\Solving:\\a_n=15+13n-13\\a_n=13n+2[/tex]

So, the equation for the nth term of  the given arithmetic sequence is: [tex]\mathbf{a_n=13n+22}[/tex]

where n=1,2,3..

Answer:

23

Step-by-step explanation:

sythenic division hard asab

Answer:

[tex]y = \frac{5}{3}x +9[/tex]

Step-by-step explanation:

Given

The attached table

Required

Determine the equation

First: We calculate the slope (m)

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Where:

[tex](x_1,y_1) = (-6,-1)[/tex]

[tex](x_2,y_2) = (0,9)[/tex]

The slope becomes:

[tex]m = \frac{9-(-1)}{0 - (-6)}[/tex]

[tex]m = \frac{9+1}{0+6}[/tex]

[tex]m = \frac{10}{6}[/tex]

[tex]m = \frac{5}{3}[/tex]

The equation is then calculated as:

[tex]y - y_2 = m(x-x_2)[/tex]

So, we have:

[tex]y - 9 = \frac{5}{3}(x - 0)[/tex]

[tex]y - 9 = \frac{5}{3}x[/tex]

Make y the subject

[tex]y = \frac{5}{3}x +9[/tex]

Answer:

1.25, 40

1.6, 30

Step-by-step explanation:

First, we'll state that the lbs of candy worth $1.25 is A and the lbs of candy worth $1.6 is B.

We write the equations: A + B = 70, (This is the lbs)

and, 1.25A + 1.6B = 1.4(70) (This is money)

Next, choose an equation you want to solve for, in this case, I'll choose A.

In the lbs equation, subtract A from both sides, A - A + B = 70 to get B = 70 - A

Now substitute this equation into the money equation.

1.25A + 1.6(70 - A) = 98

1.25A + 112 - 1.6A = 98

-0.35A = -14

multiply by negative

0.35A = 14

divide

A = 40

Then, you substitute 40 into the lbs equation, 40 + B = 70, making B = 30! Done!

Answer:

72

i think i remember doing this

Answer: Poop man

Step-by-step explanation: You throw your poop

Answer:

2 is the required answer.

Step-by-step explanation:

Solution:

Given:

-5x+3y=2..............(i)

Putting the value of y=2x in the equation (i); we get:

i.e -5x+3×2x=2

or, -5x+6x=2

or, x=2

i.e. x=2

y=2x=2×2=4

Answer:

6 dollars per dozen

Step-by-step explanation:

This is a fraction equal to

6 dollars ÷ 1 dozen

We want a unit rate where

1 is in the denominator,

so we divide top and bottom by 1

6 dollars ÷ 1

1 dozen ÷ 1

=  

6 dollars

1 dozen

=  

6 dollars

dozen

= 6 dollars per dozen

answer is there a photo or something we can see

Step-by-step explanation:

because just saying plot 5 doesn't make sense so we probably need a photo or more information

taking

Y=2x+3____(1)

Y=-3x+3____(2)

making take equation 1 and equate to 2 since y=2x+3

2x+3=-3x + 3

2x+3x=3-3

5x=0 so

substitute x=0 in equation(2)

y=-3(0)+3

y=3

Answer:

Thanks for the points :3

:):):):):):):):):):):):)):):):):):):):)

Answer:

1. 5

2. -1

3.-41

4. 55

5.-155

Step-by-step explanation:

Answer:

1) 5

2) -1

3) - 41

4) 55

5) -155

Answer:

8

Step-by-step explanation:

（10-2 is 8)

Hope this helps!

Step-by-step explanation:

done

....................

Answer: 15,625

Step-by-step explanation: 5x5x5x5x5x5= 15,625

Answer:

Allowance for doubtful account Dr 4850 , To Account receivable Cr 4850

Step-by-step explanation:

Journal Entry                                    Debit    Credit

Allowance for doubtful account    $4850  

To Account receivable                                   $4850

A debit to the allowance for doubtful accounts is to reduce the allowance balance that was previously established and a credit to the accounts receivable is to remove the amount that will not be collected.

Answer: =10

Step-by-step explanation:

Given:

The expression is

[tex]\dfrac{8}{3}-\dfrac{5}{6}-\dfrac{2}{12}[/tex]

To find:

The expression which is equivalent to the given expression.

Solution:

We have,

[tex]\dfrac{8}{3}-\dfrac{5}{6}-\dfrac{2}{12}[/tex]

It can be written as

[tex]=\dfrac{8}{3}-\dfrac{5}{6}-\dfrac{1}{6}[/tex]

Taking LCM, we get

[tex]=\dfrac{16-5-1}{6}[/tex]

[tex]=\dfrac{10}{6}[/tex]

[tex]=\dfrac{5}{3}[/tex]

The mixed fraction of this improper fraction is

[tex]=\dfrac{1\times 3+2}{3}[/tex]

[tex]=1\dfrac{2}{3}[/tex]

So, the expression [tex]1\dfrac{2}{3}[/tex] is equivalent to the given expression.

Therefore, the correct option is A.