John walks four kilometers east, two kilometers north as shown in the diagram below. What is John’s displacement

4 km

11 km

2 km north

7 km east

Answer:

114N

Explanation:

gravity on earth: 10m/s (exact: 9.82)

mass if chicken = 300/10 = 30Kg

weight of chicken on mercury = 3.8 x 30 = 114N (you wrote 0.38 but Mercury's gravity is about 3.7)

Answer:

113.15 g

Explanation:

That's because the planets weigh different amounts, and therefore the force of gravity is different from planet to planet. For example, if you weigh 100 pounds on Earth, you would weigh only 38 pounds on Mercury. That's because Mercury weighs less than Earth, and therefore its gravity would pull less on your body.

Answer:

[tex]v_m \approx -4.38\; \rm m \cdot s^{-1}[/tex] (moving toward the incline.)

[tex]v_M \approx 4.02\; \rm m \cdot s^{-1}[/tex] (moving away from the incline.)

(Assumption: [tex]g = 9.81\; \rm m \cdot s^{-2}[/tex].)

Explanation:

If [tex]g = 9.81\; \rm m \cdot s^{-2}[/tex], the potential energy of the block of [tex]m = 2.20\; \rm kg[/tex] would be [tex]m \cdot g\cdot h = 2.20\; \rm kg \times 9.81\; \rm m \cdot s^{-2} \times 3.60\; \rm m \approx 77.695\; \rm J[/tex] when it was at the top of the incline.

If friction is negligible, all these energies would be converted to kinetic energy when this block reaches the bottom of the incline. There shouldn't be any energy loss along the horizontal surface, either. Therefore, the kinetic energy of this [tex]m = 2.20\; \rm kg\![/tex] block right before the collision would also be approximately [tex]77.695\; \rm J[/tex].

Calculate the velocity of that [tex]m = 2.20\; \rm kg[/tex] based on its kinetic energy:

[tex]\displaystyle v_m(\text{initial}) = \sqrt{\frac{2\times (\text{Kinetic Energy})}{m}} \approx \sqrt{\frac{2 \times 77.695\; \rm J}{2.20\; \rm kg}} \approx 8.4043\; \rm m \cdot s^{-1}}[/tex].

A collision is considered as an elastic collision if both momentum and kinetic energy are conserved.

Initial momentum of the two blocks:

[tex]p_m = m \cdot v_m(\text{initial}) \approx 2.20\; \rm kg \times 8.4043\; \rm m \cdot s^{-1} \approx 18.489\; \rm kg \cdot m \cdot s^{-1}[/tex].

[tex]p_M = M \cdot v_M(\text{initial}) \approx 2.20\; \rm kg \times 0\; \rm m \cdot s^{-1} \approx 0\; \rm kg \cdot m \cdot s^{-1}[/tex].

Sum of the momentum of each block right before the collision: approximately [tex]18.489\; \rm kg \cdot m \cdot s^{-1}[/tex].

Sum of the momentum of each block right after the collision: [tex](m\cdot v_m + m \cdot v_M)[/tex].

For momentum to conserve in this collision, [tex]v_m[/tex] and [tex]v_M[/tex] should ensure that [tex]m\cdot v_m + m \cdot v_M \approx 18.489\; \rm kg \cdot m \cdot s^{-1}[/tex].

Kinetic energy of the two blocks right before the collision: approximately [tex]77.695\; \rm J[/tex] and [tex]0\; \rm J[/tex]. Sum of these two values: approximately [tex]77.695\; \rm J\![/tex].

Sum of the energy of each block right after the collision:

[tex]\displaystyle \left(\frac{1}{2}\, m \cdot {v_m}^2 + \frac{1}{2}\, M \cdot {v_M}^2\right)[/tex].

Similarly, for kinetic energy to conserve in this collision, [tex]v_m[/tex] and [tex]v_M[/tex] should ensure that [tex]\displaystyle \frac{1}{2}\, m \cdot {v_m}^2 + \frac{1}{2}\, M \cdot {v_M}^2 \approx 77.695\; \rm J[/tex].

Combine to obtain two equations about [tex]v_m[/tex] and [tex]v_M[/tex] (given that [tex]m = 2.20\; \rm kg[/tex] whereas [tex]M = 7.00\; \rm kg[/tex].)

[tex]\left\lbrace\begin{aligned}& m\cdot v_m + m \cdot v_M \approx 18.489\; \rm kg \cdot m \cdot s^{-1} \\ & \frac{1}{2}\, m \cdot {v_m}^2 + \frac{1}{2}\, M \cdot {v_M}^2 \approx 77.695\; \rm J\end{aligned}\right.[/tex].

Solve for [tex]v_m[/tex] and [tex]v_M[/tex] (ignore the root where [tex]v_M = 0[/tex].)

[tex]\left\lbrace\begin{aligned}& v_m \approx -4.38\; \rm m\cdot s^{-1} \\ & v_M \approx 4.02\; \rm m \cdot s^{-1}\end{aligned}\right.[/tex].

The collision flipped the sign of the velocity of the [tex]m = 2.20\; \rm kg[/tex] block. In other words, this block is moving backwards towards the incline after the collision.

Answer:

The septic tank of an abandoned property.

Almost anywhere at a closed refinery (most refineries will never be torn down due to the massive remediation costs involved when they are. Find a good hiding spot there and place the body in the open or bury it)

Numerous quarries are around and most are filled with water. If you ensure that the body will not float to the surface, they are often great disposal locations.

Inside the wall of a home or building - If the body is allowed to desiccate (mummify) then there will be little or no odor. Simply open a wall,insert the body and replaster or drywall it and paint over it.

Underneath an area to be used as a pen or feed lot for domesticated animals. The weight of the animals, plus their manure and the straw placed down to control it will form its own "cap" over the burial site.

In plain sight - The roof of tall abandoned building (hidden from overhead viewing) , an open area in a remote part of the country (after staying there for 2-3 days to see if anyone comes along), or in a storm drain along a lightly used state or county road.

Answer:

Electricity is the flow of electrical power or charge. It is a secondary energy source which means that we get it from the conversion of other sources of energy, like coal, natural gas, oil, nuclear power and other natural sources, which are called primary sources.

Answer:

The acceleration of the horse during this time interval is 24.286 m/min²

Explanation:

Given;

initial velocity of the horse during the gallop, u = 543 m /min

final velocity of the horse during the gallop, v = 628 m /min

time of motion, t = 3.5 minutes

The acceleration of the horse is given by the change in velocity per change in time;

[tex]a = \frac{v-u}{t}\\\\a = \frac{628-543}{3.5}\\\\a = 24.286 \ m/min^2[/tex]

Therefore, the acceleration of the horse during this time interval is 24.286 m/min²

Answer:

Usually when climbing, it's best to be in the small front ring and the largest back ring. If your cadence is about 100 rpm, then whatever gear you're in is fine. It depends on the road, but as long as your pedaling is at a level you're comfortable with, you're fine.

Explanation:

Google answer by the way.

Answer:

The largest surface area window that can be used is [tex]A=0.01\ m^2[/tex]

Explanation:

Pressure

The pressure is defined as force per unit area. The SI unit for pressure is the Pascal (Pa), defined as Newton per square meter.

If a force F acts on a surface area A, the pressure is calculated as:

[tex]\displaystyle P=\frac{F}{A}[/tex]

The pressure at a depth of 90 m is P=1 Mpa= 1,000,000 Pa and the submarine's window can only take a force of F=10 kN=10,000 N.

We need to calculate the largest surface area of the window. We can solve the equation for A:

[tex]\displaystyle A=\frac{F}{P}[/tex]

Substituting:

[tex]\displaystyle A=\frac{10,000}{1,000,000}[/tex]

[tex]A=0.01\ m^2[/tex]

The largest surface area window that can be used is [tex]\mathbf{A=0.01\ m^2}[/tex]

Answer:

hi

Explanation:

how r u

Given :

A rectangular solid box of aluminum is heated.

To Find :

Which of the following is not true.

A) Its mass remains constant

C) its density increase

B) Its volume increase

D) none of the above​

Solution :

We know, when an object is heated it expands.

Objects expands means that the volume increases but mass remains same by conservation of mass.

Since mass remains constant and volume increases.

So, density will decrease.

Hence, this is the required solution.

Answer:

Acceleration due to Gravity:

Explanation:

Here g is acceleration due to gravity. So C. 3.8 m/s2

Answer: Watts

Explanation: In the International System of Units (SI), thermal conductivity is measured in watts per meter-kelvin (W/(m•k)).

Answer:

the car slowed at a rate of 2.93 mph

Answer:

Explanation:

The average speed of the ball can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question we have

[tex]v = \frac{50}{5} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

they are :

Explanation:

Explanation:

Cells are the basic building blocks of all living things. The human body is composed of trillions of cells. They provide structure for the body, take in nutrients from food, convert those nutrients into energy, and carry out specialized functions.

Answer:

a

Explanation:

Answer:

I'm not sure.

Explanation:

Look up the statistics

Answer: honestly girls cheat more than guys, its statically proven that females cheat more than guys its because they dont believe in value in a relationship

Explanation:

Answer:

false

Explanation:

there is difference in m/s and m.s

Answer:

12.495m/s

Explanation:

Horizontal displacement is the range of the projectile motion.

The range is expressed as;

R = 2U/g

U is the speed at which the rock is thrown (initial speed)

g is the acceleration due to gravity.

Given

R = 255cm = 2.55m

g = 9.8m/s²

Required

Speed U

Substitute the given parameters into the formula as shown;

2.55 = 2U/9.8

Cross multiply

2U = 2.55×9.8

2U = 24.99

U = 24.99/2

U = 12.495m/s

Hence the speed that you thew the rock is 12.495m/s

You push against a wall, and the wall applies a force to your  hands. (A)

Answer:

0.364

I believe... Good luck!

Answer:

[tex]F=8.64\times 10^{-9}\ N[/tex]

Explanation:

Given that,

Mass of student 1, m₁ = 120 kg

Mass of student 2, m₂ = 108 kg

Let they are at a distance of 10 m.

We need to find the gravitational pull they have on each other. The gravitational force acting between two objects is given by :

[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{120\times 108}{(10)^2}\\\\=8.64\times 10^{-9}\ N[/tex]

So, the gravitational pull between students is [tex]8.64\times 10^{-9}\ N[/tex].

Answer:

101 J

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 101 \ Joules}}[/tex]

Explanation:

Kinetic energy can be found using the following formula:

[tex]KE=\frac{1}{2}mv^2[/tex]

The mass of the baseball is 0.140 kilograms and the velocity is 38.0 meters per second.

[tex]m= 0.140 \ kg \\v= 38.0 \ m/s[/tex]

Substitute the values into the formula.

[tex]KE=\frac{1}{2} [0.140 \ kg][(38.0 \ m/s)^2][/tex]

First, evaluate the exponent.

[tex]KE=\frac{1}{2}(0.140 \ kg)(1444 \ m^2/s^2)[/tex]

Multiply the two numbers in parentheses together.

[tex]KE=\frac{1}{2}(202.16 \ kg*m^2/s^2)[/tex]

Multiply the fraction by the number, or divide the number by 2.

[tex]KE=101.08 \ kg*m^2/s^2[/tex]

Round to the nearest whole number. The 0 in the tenth place tells us we can leave the number as is.

[tex]KE\approx 101 \ kg*m^2/s^2[/tex]

1 kg*m²/s² is equal to 1 Joule. Therefore, our answer of 101 kg*m²/s² is equal to 101 Joules (J).

[tex]KE\approx 101 \ J[/tex]

The kinetic energy of the baseball is about 101 Joules.

Answer:

Entonces la velocidad es 2 [tex]\frac{m}{s}[/tex] hacia la derecha, mientras que la rapidez es 2 [tex]\frac{m}{s}[/tex].

Explanation:

La rapidez es una magnitud escalar que relaciona la distancia recorrida con el tiempo mientras que la velocidad es una magnitud vectorial que relaciona el cambio de posición (o desplazamiento) con el tiempo.

Es decir, la rapidez es una magnitud física que expresa el valor numérico y la unidad de una distancia en relación con el tiempo.

Matemáticamente,  es expresada como el cociente entre el camino recorrido y el tiempo transcurrido:

[tex]rapidez=\frac{distancia}{tiempo}[/tex]

Por otro lado, la velocidad expresa cómo se está moviendo un objeto en cada momento, informando la dirección, el sentido y la rapidez del movimiento (la velocidad se refiere al intervalo de tiempo que le toma a un objeto desplazarse hacia una dirección determinada y, al involucrar la dirección o sentido del movimiento, es una magnitud vectorial).

Matemáticamente, la velocidad es calculada como el cociente entre el desplazamiento que realizó un cuerpo  y el tiempo total  que le llevó realizarlo.

[tex]velocidad=\frac{desplazamiento}{tiempo}[/tex]

En este caso, sabes que:

Reemplazando obtenes que la aceleración es:

[tex]rapidez=\frac{10m}{5 s}[/tex]

rapidez= 2 [tex]\frac{m}{s}[/tex]

y la velocidad es:

[tex]velocidad=\frac{10m}{5s}[/tex]

velocidad= 2 [tex]\frac{m}{s}[/tex] hacia la derecha.

Entonces la velocidad es 2 [tex]\frac{m}{s}[/tex] hacia la derecha, mientras que la rapidez es 2 [tex]\frac{m}{s}[/tex].

8n downwards

since downwards force is greater than upwards just minus

Answer:

a

When the lift is moving upward   [tex]F = 1120 \ N[/tex]

b

When the lift is moving downward   [tex]F = 820 \ N[/tex]

Explanation:

From the question we are told that

     The mass of the man is [tex]m = 100 \ kg[/tex]

     The upward acceleration is  [tex]a_u = 1.2 \ m/s^ 2[/tex]

     The downward acceleration is  [tex]a_d = 1.80 \ m/s^2[/tex]

Generally the force which the scale will read  when the man is moving downward is according to Newton second law represented as  

      [tex]F + mg = ma[/tex]

        [tex]F = m (g - a_d)[/tex]

Here [tex]g = 10 m/s^2[/tex]

=>     [tex]F = 100 (10 - 1.8)[/tex]

=>     [tex]F = 820 \ N[/tex]

Generally the force which the scale will read  when the man is moving upward  is according to Newton second law represented as  

       [tex]F - mg = ma[/tex]

        [tex]F = m (g + a_u)[/tex]

Here [tex]g = 10 m/s^2[/tex]

=>     [tex]F = 100 (10 + 1.2)[/tex]

=>     [tex]F = 1120 \ N[/tex]

Answer:

hola me llamo bruno y tu?

Explanation:

pero yo soy de mexico