Lucretia who works part time as a substance abuse counselor ,earns $18.15 per hour and works 20 hours per week. she is single and claims one withholding allowance. she lives in a state with no income tax

Answer: 10

Step-by-step explanation:

Whenever you have a subtraction symbol next to a negative it automatically becomes positive.

Answer: a

Step-by-step explanation:

First term

[tex]\int \sqrt{10x-15} \mathrm{dx}[/tex]

We can use the substitution u=10x-15, meaning dx = 1/10 du.

[tex]=\frac{1}{10} \int \sqrt{u} \mathrm{du}\\\\=\frac{1}{15}u^{3/2}+C\\\\=\frac{1}{15}(10x-15)^{3/2}+C[/tex]

Second term

[tex]\int (10x-15)^{10} \mathrm{dx}[/tex]

We can use the substitution u=10x-15, meaning dx = 1/10 du.

[tex]=\frac{1}{10} \int u^{10} \mathrm{du}\\\\=\frac{1}{110} u^{11}+C\\ \\ =\frac{1}{110}(10x-15)^{11}+C[/tex]

Third term

[tex]\int \frac{1}{10x-15} \mathrm{dx}[/tex]

We can use the substitution u=10x-15, meaning dx = 1/10 du.

[tex]=\frac{1}{10} \int \frac{1}{u} \mathrm{du}\\\\=\frac{1}{10} \ln u+C\\\\=\frac{1}{10} \ln(10x-15)+C[/tex]

Adding these results, we get the answer to be a.

The rate of change of the cost in dollars with respect to the number of t-shirts printed is $0.75 per shirt.

An equation is an expression that shows the relationship between two or more numbers and variables.

A linear function is in the form:

y = mx + b

Where m is the rate of  change and b is the initial value of y.

Given that the cost f(x) in dollars for printing x, t-shirts is given by:

f(x) = 100 + 0.75(x - 50)

f(x) = 0.75x + 62.5

Comparing with linear function, the rate of change is 0.75

The rate of change of the cost in dollars with respect to the number of t-shirts printed is $0.75 per shirt.

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The average balance of the account is $1126.37.

An average is one number chosen to represent a group of numbers; it is often the sum of the numbers divided by the number of numbers in the group.

Consider the table that shows the balance (in dollars) of a bank account for three months.

Months            Account Balance

1                       $1285.12

2                       $961.36

3                       $1132.63

As we are aware, the following formula for the mean or average of any set of data:

Mean, [tex]\overline X=\frac{\sum X}{n}[/tex]

where,  ∑X is the sum of all the observations in the data and n  is the number of observations in the data

Therefore, the average balance in the account is:

[tex]Average{~}balance=\frac{1285.12+961.36+1132.63}{3}[/tex]

[tex]Average{~}balance=\frac{3379.11}{3}[/tex]

Average balance = $ 1126.37

So, the account's average balance is $1126.37.

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The complete question is mentioned below:

The table shows the balance (in dollars) of a bank account each month for three months. What is the average balance of the account?

Table:

Month 1, account balance: $1285.12

Month 2, account balance: $961.36

Month 3, account balance: $1132.63

The average balance of the account is $1126.37

Average: An average is one number chosen to represent a group of numbers; it is often the sum of the numbers divided by the number of numbers in the group.

Consider the table that shows the balance (in dollars) of a bank account for three months.

Months            Account Balance

1                       $1285.12

2                       $961.36

3                       $1132.63

As we are aware, the following formula for the mean or average of any

set of data,

Mean,

where,  ∑X is the sum of all the observations in the data and n  is the number of observations in the data

Therefore, the average balance in the account is,

Average balance of the account = $ 1126.37

So, the account's average balance is $1126.37

The complete question is mentioned below,

The table shows the balance (in dollars) of a bank account each month for three months.

Table:

Month 1, account balance: $1285.12

Month 2, account balance: $961.36

Month 3, account balance: $1132.63

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Answer:

2500

Step-by-step explanation:

1×10^6/10=10%

=1×10^5 then divide by 10 will give 10

=1×10^4 divide by 4 to get 2.5 of the original 10%

=2.5×10^3

=2500

The average yearly salary of the final year is 67000 in dollars.

An average is a single number selected to stand in for a collection of numbers; it is frequently the product of the sum of the numbers divided by the total number of the collection. For example, the average of the integers 2, 3, 4, 7, and 9 is 5.

Let x = the average salary of an individual with the bachelor's degree, in dollars.

Then the average salary of an individual with master's degree is (2x - 35000)in dollars.

According to the sum of these salaries is 118000 dollars:

x + (2x-35000) = 118000

by solving we get

x = 153000/3

x = 51000

Hence, The average salary of an individual with the bachelor's degree is 51000 in dollars.  

the average salary of an individual with the master's degree (2*51000 - 35000) = 67000 in dollars.

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The fractional representation of each plot is given by 12/67 , 79/335 , 58/335 , 143/670 and 133/670 .

A fraction denotes a component of a whole or, more broadly, any number of equal pieces. A common or simple fraction is made up of a non-zero denominator that is displayed below (or after) the line that the numerator is displayed above (or before a slash, as in the case of 12). Compound fractions, and mixed numeral fractions are examples of uncommon fractions that use numerators and denominators.

The total area of the lot is given by (19750+15000+14500+17875+16625) =83750 square feet.

Fractional representation of Lot 1= 15000 ÷ 83750 = 12/67

Fractional representation of Lot 2= 19750 ÷ 83750 = 79/335

Fractional representation of Lot 3= 14500 ÷ 83750 = 58/335

Fractional representation of Lot 4= 17875 ÷ 83750 = 143/670

Fractional representation of Lot 5= 16625 ÷ 83750 = 133/670

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The required number is 874 and 423.

What is arithmetic?

Arithmetic is the branch of mathematics that deals with the study of numbers using various operations on them. Basic operations of math are addition, subtraction, multiplication and division. These operations are denoted by the given symbols.

Given:

My  number has 2 periods, There are digits 8,7,4 in that order and 4,2,3 in that order.

According to given question we have

First period=4(Ones) , 7(Tens) , 8(Hundreds)

Number        Hundred           Tens             Ones

874                    8                       7                     4

Second Period =3(Ones) , 2(Tens) , 4(Hundreds)

Number        Hundred           Tens             Ones

423                 4                       2                     3

Therefore, the required number is 874 and 423.

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Every point in the interval [2, 6] has an equal probability of occurring, 1/(6 - 2) = 1/4. So the PDF of X is

[tex]f_X(x) = \begin{cases} \frac14 & \text{if } 2 \le x \le 6 \\ 0 & \text{otherwise} \end{cases}[/tex]

Compute the CDF by integrating the PDF.

• If [tex]x<2[/tex], we have

[tex]\displaystyle \int_{-\infty}^x f_X(t) \, dt = \int_{-\infty}^x 0 \, dt = 0[/tex]

• If [tex]2\le x< 6[/tex], we have

[tex]\displaystyle \int_{-\infty}^x f_X(t) \, dt = \int_{-\infty}^2 f_X(t) \, dt + \int_2^x f_X(t) \, dt \\\\ ~~~~~~~~~~~~~~~~~ = \int_{-\infty}^2 0 \, dt + \int_2^x \frac{dt}4 \\\\ ~~~~~~~~~~~~~~~~~ = 0 + \frac14 \int_2^x \, dt \\\\ ~~~~~~~~~~~~~~~~~ = \frac{x-2}4[/tex]

• If [tex]x\ge6[/tex], we have

[tex]\displaystyle \int_{-\infty}^x f_X(t) \, dt = \int_{-\infty}^2 f_X(t) \, dt + \int_2^6 f_X(t) \, dt + \int_6^x f_X(t) \, dt \\\\ ~~~~~~~~~~~~~~~~~ = \int_{-\infty}^2 0 \, dt + \int_2^6 \frac{dt}4 + \int_6^x 0 \, dt \\\\ ~~~~~~~~~~~~~~~~~ = 0 + 1 + 0 \\\\ ~~~~~~~~~~~~~~~~~ = 1[/tex]

Putting the pieces together, we find the CDF to be

[tex]\boxed{F_X(x) = \begin{cases} 0 & \text{if } x < 2 \\\\ \dfrac{x-2}4 & \text{if } 2\le x < 6 \\\\ 1 & \text{if } x\ge6 \end{cases}}[/tex]

Compute the expectation of X.

[tex]\Bbb E[X] = \displaystyle \int_{-\infty}^\infty x\,f_X(x)\,dx \\\\ ~~~~~~~ = \int_{-\infty}^2 0 \, dx + \int_2^6 \frac x4 \, dx + \int_6^\infty 0 \, dx \\\\ ~~~~~~~ = 0 + \frac{6^2 - 2^2}8 + 0 \\\\ ~~~~~~~ = \boxed{4}[/tex]

[tex]she \: paid = 2(1.69) + 1(1.49) + 1(1.09) + 0.68=6.64 \\ change = 10 - 6.64 = 3.36[/tex]

Answer:

Step-by-step explanation:

A triangle has a base of 7.2 centimeters and height of 10.24 centimeters. A large triangle has a base of question mark centimeters and a height of 25.6 centimeters.

The diagram represents the process of creating a scale drawing from an original using a scale factor of 0.4. The base of the original drawing must be:

17.6 cm

18 cm

33.5 cm

45 cm

--------------------

1st solution (using an equation)

10.24 : 7.2 = 25.6 : x

x = 7.2 * 25.6 : 10.24

x = 18cm

------------------------------------

2nd solution (using the scale factor)

7.2 : 0.4 =

18 cm

Answer: 18cm

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

15:10

15/10=1.5g/min

1.5x8=12.

A camel can drink 12L in 8 minutes.

Considering the definition of an equation and the way to solve it, the smallest four integers are 8, 10, 12, 14.

An equation is the equality existing between two algebraic expressions connected through the equals sign in which one or more unknown values appear.

The members of an equation are each of the expressions that appear on both sides of the equal sign.

The solution of a equation means determining the value that satisfies it. To solve an equation, keep in mind:

Being "x" n any integer, and knowing that:

So, the equation in this case is:

(2n + 2n +2 + 2n +4 + 2n + 6)÷ 4= 11

Solving:

(8n +12)÷ 4=11

8n +12= 11× 4

8n +12= 44

8n= 44 -12

8n= 32

n= 32 ÷ 8

n= 4

Then, the smallest four integers can be calculated as:

Finally, the smallest four integers are 8, 10, 12, 14.

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The sum of the terms till infinity of the sequence 1, 1 / 4, 1 / 16, 1 / 64 will be 4 / 3.

We have the sequence:

1, 1 / 4, 1 / 16, 1 / 64. ​

Initial term = a

a = 1

Common ratio = d

d = 1 / 4

The formula for the sum of the terms to infinity is given by:

S_∞ = a / (1 – r)

S_∞ = ( 1 ) / (1 – 1 / 4)

S_∞ = 1 / ( 3 / 4 )

S_∞ = 4 / 3

Therefore, we get that, the sum of the terms till infinity of the sequence 1, 1 / 4, 1 / 16, 1 / 64 will be 4 / 3.

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Table number 4 is showing the value of Y as a function of X.

A binary connection in mathematics links elements of one set, referred to as the domain, with elements of another set, referred to as the codomain. A new set of ordered pairs made up of elements from sets X and Y and x in X is known as a binary relation across these sets.

The variable Y as a function of X is represented by table number 4. Because for every value of X there is a different value of Y.

X                   Y

26               -26

-26              24

28               -28

-28              28

Therefore, table number 4 is showing the value of Y as a function of X.

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Answer:

[tex]2 \frac{5}{8} [/tex]

Step-by-step explanation:

[tex]1. \: \frac{1 \times 6 + 1}{6} \times 2 \frac{1}{4} \\ 2. \: \frac{6 + 1}{6} \times 2 \frac{1}{4} \\ 3. \: \frac{7}{6} \times 2 \frac{1}{4} \\ 4. \: \frac{7}{6} \times \frac{2 \times 4 + 1}{4} \\ 5. \: \frac{7}{6} \times \frac{8 + 1}{4} \\ 6. \: \frac{7}{6} \times \frac{9}{4} \\ 7. \: \frac{7 \times 9}{6 \times 4} \\ 8. \: \frac{63}{6 \times 4} \\ 9. \: \frac{63}{24} \\ 10. \: \frac{21}{8} \\ 11. \: 2 \frac{5}{8} [/tex]

Answer:

30 000

Step-by-step explanation:

30 000   if underlined digit is >= 5 round thousands up 1 ...o/w leave as is

30 000

The combined estimated weight of the two whales is 945.7 Pounds.

The estimated weight of a blue whale = 3.46 × 105

Total estimated weight of a blue whale = 363.3 Pounds

Now, the estimated weight of a sea whale = 5.6 × 104

Total estimated weight of a sea whale = 582.4 Pounds

For finding the combined estimated weight of the two whales,

we will add the total estimated weight of both whales.

Here is how we will do it:

Total estimated weight of a blue whale + Total estimated weight of a sea whale

= 363.3 Pounds + 582.4 Pounds

Hence, 945.7 Pounds will the combined estimated weight of the two whales.

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Step-by-step explanation:

the slope is a line is always the factor of x.

and it is the ratio (y coordinate difference / x coordinate difference) when going from one point to another.

y = 2x + 4

has the slope 2. which is 2/1. so, for every increase of x by 1 unit, y increases by 2 units.

and this line has a y-intercept of 4 (the y-value when x = 0).

remember, the slope-intercept form of a line is

y = ax + b

a is the slope, b is the y-intercept.

a perpendicular slope (90°) turns that ratio upside down and flips the sign (because if the original line was going up, the perpendicular line is going down and vice versa).

so, the slope of the perpendicular line is -1/2.

the y-intercept was already given to us, so the desired line equation is

y = -1/2 x + 3

or

y = -x/2 + 3

Answer:

D

Step-by-step explanation:

an = 3/4 × an-1

let's see for n = 2

a2 = 3/4 × a1 = 3/4 × 4

n = 3

a3 = 3/4 × a2 = 3/4 × 3/4 × a1 = 3/4 × 3/4 × 4 = 9/16 × 4

so, we see, we multiply 3/4 one time less than n by itself and then by 4.

that makes D the correct answer.

the multiplication by (n - 1) in answer C would add 3/4 n-1 times instead of multiplying it n-1 times.

to apply n-1 multiplications we need to use n-1 as exponent.

Answer: -6.25, -2, 3/4, 3, 5, 6, 67/10 would be the soliton

Answer:

0%

Step-by-step explanation:

The gain on the first oven = 18000 x 20% = 18000 x 20/100
= 18000 x 0.2 = 3600. Since it is a gain, we have to add this number

So selling price = 18000 + 3600 = 21600

The loss on the second oven is also the same 18000 x 0.2 = 3600. This time, it being a loss, selling price = 18000-3600 Total= 14400

The total before sales price of both ovens C  = 18000 + 18000 = 36,000

Total sold price S = 14, 400 + 21,600 = 36000

So net gain/loss = S - C = 36000 - 36000 = 0

So net gain/loss as percent = 0%

Answer:

  see attached

Step-by-step explanation:

You want the truth table for a logical implication that involves other logical expressions with up to three variables.

A truth table is conveniently produced using the logical operations available on a spreadsheet. The AND (∧), OR (∨), and NOT (¬) functions are built-in to the spreadsheet. The implication (→) function must use the equivalent:

  p → q ≡ ¬p∨q

If p, q, and r are in columns A, B, C, respectively, then the formulas in columns D through G are ...

The formulas are filled to the following rows.

The values of p, q, and r are entered manually. The spreadsheet computes the truth values for the formulas.

Answer:

Step-by-step explanation:

Discussion

Let's consider an rational number for a moment. If I tell you that the fraction you used was 1/3 and gave you the first couple of numbers as in

1/3 = 0.33333.....

and asked you what the next number is, you should be able to tell me that the number to write down is 3.

Even something like 1/7 is well behaved.

1/7 = 0,142857142857142857 .... and tell you I want the next number, you should be able to see it as 1.

But an irrational number can't be handled that way. If I ask for the next digit after 5 when taking the square root of 2, you would have no idea what I was talking about without the help of a calculator.

Now if you multiply a rational by an irrational, you just get a bigger irrational, but it remains irrational.

The statement is false.

The one time fee is -$17 and the one-time fee cannot not be applicable to this scenario because it is negative

The given parameters are

Hourly rate, r = 20.00

Number of hours, h = 5.5

Total amount = 93.00

The total amount is calculated as:

Total amount = One time fee + Hourly rate * Number of hours

So, we have

93.00 = One time fee + 20.00 * 5.5

Evaluate the product

So, we have

93.00 = One time fee + 110

Subtract 110 from both sides

So, we have

One time fee = 93.00 - 110

Evaluate the difference

So, we have

One time fee = -17

Hence, the one time fee is -$17

Amount cannot be negative.

This means that the one-time fee cannot not be applicable to this scenario

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[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

Domain : All values of x, for which function is defined.

i.e [tex]\boxed{\sf 0\leqslant x\leqslant 12} [/tex]

Range : All possible values of y, that can be obtained by putting value of x in the equation of function

i.e [tex]\boxed{\sf 0\leqslant y\leqslant 900} [/tex]

Two expressions with equal sign is equation, if (m/n)(x) for x=-3 is (m/n)(-3)=m(-3)/n(-3).

Two expressions with equal sign is called as Equation.

Given,
(m/n)(x) for x=-3

i.e means we need to find (m/n)(-3)

So we have to calculate by putting -3 in to two functions m and n.

(m/n)(-3)=m(-3)/n(-3)

Therefore (m/n)(x) for x=-3 is (m/n)(-3)=m(-3)/n(-3).

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