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The final velocity of Luis is 29.4 m/s

It is given that

Acceleration a = 9.8m/s^2, time t = 3.0 second

initial velocity = 0 m/s

Free fall is characterised as a scenario where an object is only affected by gravity. The ball experiences an external force, which quickens its motion. Gravitational acceleration is another name for this rate of free fall acceleration. A downward motion without any beginning force or speed is called a free fall.

The primary indicator of an object's position and speed is its velocity. It is the distance that an object travels in one unit of time. The displacement of the item in one unit of time can be used to define velocity.

using v = u + at

v = 0 + 9.8 x 3

v = 29.4 m/s

Hence, final velocity of Luis is 29.4 m/s

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The equations that are accurate regarding the displacement by Aliyah is d vector = - 160 m and the distance travelled by Aliyah is d = 580 m

Total distance travelled = 210 + 370

Total distance travelled = 580 m

Displacement = Final position - Initial position

Final position = 370 - 210

Final position = 160 m

Displacement = 160 - 0

Displacement = 160 m South

Displacement = - 160 m

Distance travelled is a scalar quantity. So direction is not taken into consideration. Displacement is a vector quantity. Since her overall displacement is towards the south direction its value is negative.

Therefore, The equations that are accurate are:

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The breaking acceleration of the car must be - 44.5 m/s² so that the car stops in time and avoid hitting the Ilama.

Given in the question

The car is driving at the speed of 14 m/s and the reaction time is 0.05 seconds. So the distance traveled by car before hitting the break is,

Distance = Speed × time

Distance = 14 × 0.05

Distance = 0.7 meters

So, now the Ilama is 2.9 meters away and the distance traveled before hitting the break is 0.7 meters.

So the stopping distance = Distance of Ilama  - distance traveled before hitting the break

So stopping Distance = s = 2.9 - 0.7

stopping Distance = s = 2.2 m

Now we have

Initial Velocity = u = 14 m/s

Final Velocity = v = 0 m/s [ as after applying the break, the car comes to rest]

Stopping Distance = s = 2.2 m

Using the third equation of motion

v² - u² = 2as

Put in the value, we get

(0)² - (14)² = 2a(2.2)

4.4a =  - 196

a = -196/4.4

a = - 44.5 m/s²

Therefore, the breaking acceleration of the car must be - 44.5 m/s².

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The distance below the intended target the dart hit is 0.26 m.

The time taken for the  dart to fall is calculated as follows;

X = Vxt

where;

t = X/Vx

t = 2.7/12

t = 0.23 seconds

h = vt + ¹/₂gt²

where;

h = ¹/₂gt²

h = ¹/₂(9.8)(0.23²)

h = 0.26 m

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If a runner accelerated from rest for 12 s, at which time the runner has traveled 100 m, then the runner's average and final velocities would be  8.33 m /s  and 16.66 m/s.

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

By using the second equation of motion given by newton,

S = ut + 1/2at²

100 = 0 + 0.5*a*12*12

a = 100 / 72

a =  1.388 meters / second²

The final velocity of the runner = 12*1.388

                                                    =16.66 m/s

The average velocity = 16.66 /2

                                    =8.33 m /s

Thus, the average velocity of the runner would be 8.33 m /s  and the final velocity of the runner would be 16.66 m/s

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The voltage drop in the second resistor such that the drop in the first resistor is 7 volts using conservation of potential in a loop we get the value of potential drop to be equal to 8 volts .

Voltage is a physical quantity that is responsible for movement of charges in a wire the difference in potential between two points causes the flow of charges.

Its S.I unit is voltage (V)

Electric current is a physical quantity which refers to the flow of electric charge per unit area across a cross section of unit area.

Its S.I unit is ampere (A).

Given:

Total voltage across the circuit = 15 V

Voltage drop across first resistor = 7V

Resistance of first resistor = 10002 ohm

Resistance of second resistor= 22002 ohm

Now we know about conservation of charge and Kirchhoff's law.

Kirchhoff law states that the sum of potential in a loop is always conserved. In first resistor we noticed a drop of 7 volt it means that the remaining voltage must drop across the second resistor.

Therefore, the drop in the voltage using conservation of potential in a loop we get the value of potential drop to be equal to 8 Volt .

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Note: The question is incomplete in the portal. Here is the complete question.

Question: Two resistors with resistance R₁ equal to 10002 and R₂ equal to 22002 respectively are connected in series circuit, such that the potential drop through the first resistor of resistance 10002 is of 7V find the voltage drop in second resistor using divider rule.

The correct answer is 10498.3.

The speed of an object is calculated when it moves from one spot to another in time interval t by dividing the distance between the two locations by the time interval. As a result of this definition, the longer it will take the object to travel the specified distance, the greater the separation between the two points.

x = x_0 + (v_x) t

In case of cheetah:

x_0 = 0;

v_c = 97.1 km/h

x = 97.1t _____(1)

In case of gazelle;

x_0 = 52.2 m = 52.2 × 10^-3 km

v_c = 79.2 km/hr

x = 52.2 × 10^-3 + 79.2t ______(2)

equating 1 and 2

52.2 × 10^-3 + 79.2t = 97.1t

52.2 × 10^-3 = 97.1t - 79.2t

52.2 × 10^-3 = 17.9t

52.2 × 10^-3×3600/17.9 = t

t = 10498.3

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Answer:

9.5m/s west

Explanation:

Average v= (Final v+Initial v)/2

Average v=(0+19m/s)/2

=9.5m/s west

The average for each checkpoint is:

point 1 t_{avg} = 2.07 sec

point 2 t_{avg} = 3.16 sec

point 3 t_{avg} = 4.11 sec

point 4 t_{avg} = 4.92 sec

We have the graph for each interval.

The magnitude of the average is:

t_{avg} = Σ ( t_(i) / n)

where t_{avg} is the average time, t_(i) each time the magnitude is measured and n is the number of times the measurement is repeated for the same point.

The table for the times measured for each interval is:

Measurement        times for each interval

                           1          2             3            4

1                         2.02    3.17       4.12        4.93

2                         2.05    3.07       3.98        4.81

3                         2.15    3.25       4.23         5.01

Now, the average time to reach the get married checkpoint is:

For point 1:

t_{avg} = (2.02 + 2.05 + 2.15) / 3

t_{avg} = 2.07 s

For point 2:

t_{avg} = (3.17 +3.07 + 3.25) / 3

t_{avg} = 3.16 s

For point 3:

t_{avg} = (4.12 + 3.98 + 4.23) / 3

t_{avg} = 4.11 s

For checkpoint 4:

t_{avg} = (4.93 + 4.81 + 5.01) / 3

t_{avg} = 4.917 s

We employ the significant figures criterion for the sum, which is steady in that the result must be provided with the least amount of decimal places.

t_{avg} = 4.92 s

Therefore, the average times for each checkpoint are:

point 1: t_{avg} = 2.07 s

point 2: t_{avg} = 3.16 s

point 3: t_{avg} = 4.11 s

point 4: t_{avg} = 4.92 s

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The force applied on the object caused a change in the acceleration of the object, from certain periods, the acceleration increased, in some periods it remained constant, while in some periods, the acceleration decreased to zero.

The acceleration of an object an object is the change in the velocity of the object with time.

a = Δv/Δt

where;

From the given graph, we will explain the impact of the applied force on acceleration in the following points;

Thus, the force applied on the object caused a change in the acceleration of the object, from certain periods, the acceleration increased, in some periods it remained constant, while in some periods, the acceleration decreased to zero.

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Strategy and tactics are important in sports and games as they help the players define their objectives, work towards them and achieve them using their competitive advantage.

Strategy in sports refers to the plans used to reduce uncertainty that following one course of action will worsen the team's position, that is using another plan.

Strategy is important is it enables the player to have a predefined target and also work towards them.

Tactics are actions and strategies planned to achieve an overall objective in sport that objective is predominantly to win.

Tactics can depend on a number of factors such as opposition, players available for selection, the importance of the game and possibly even weather.

Thus, Strategy and tactics are important in sports and games as they help the players define their objectives, work towards them and achieve them using their competitive advantage.

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The types of memories that are stored in the collective unconscious include instinctive patterns and archetypes from ancestral heritage.

The collective unconscious can be defined as  the part of the human mind  that contains distinct types of memories and also instinctive impulses in humans which may shape some of our behaviors regarding specific situations and also environmental contexts (e.g., during danger situations).

In conclusion, the types of memories that are stored in the collective unconscious include instinctive patterns and archetypes from ancestral heritage.

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The phenomenon due to which the colored glass appears white when crushed into a fine powder is known as total internal reflection. Thus, the correct option for this question is A.

Total internal reflection may be defined as a phenomenon that significantly involves the reflection of a ray back to the identical medium when glancing from a denser medium to a rarer medium in such a way that the angle of incidence is found to be greater than its critical angle.

Due to this phenomenon of total internal reflection, not partial but complete reflection of a ray of light within a medium occurred within the surroundings of a medium such as water or glass. As a result of this, the colored glass appears white when crushed into fine powder.

Therefore, the total internal reflection is the phenomenon due to which the colored glass appears white when crushed into a fine powder. Thus, the correct option for this question is A.

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Walking, running, and breathing are examples of motion. For rolling of ball, the street is a frame of reference and an insect on the ball is an inappropriate frame of reference.

A frame of reference, also known as a reference frame, is a perspective used in physics to assess whether an object is moving.  A frame of reference is an environment or object that is thought to be stationary. The Earth itself, despite its motion, serves as the most frequently used frame of reference.

Some examples of motion are:

Motion is a part of many of our daily activities, including walking, running, closing doors, etc.

Another illustration of motion is the passage of air into and out of our lungs.

The vehicles that transport passengers between the point of pickup and the destination have motion.

A ball is rolling down the street that it is moving.

For a ball rolling down the street, the street is an appropriate frame of reference as it is rest as compared to the ball.

For the same example, the insect sitting on the rolling ball is a part of the rolling ball.

Therefore, the insect is an inappropriate frame of reference for the motion of the ball rolling down the street.

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Answer:

It is unbalanced

Explanation:

There are 5 more newtons of force being exerted toward the right.

Frequency of the waves is 0.05 Hz

Number of complete wavelength, λ = 6

therefore distance covered = 6 Wavelength

Time taken to complete 6 wavelengths, t = 2 min

Since 1 min = 60 sec

2 min = 2 * 60 = 120 sec

Frequency can be defined as the number of wave cycles completed per second by a wave.

As we know, Velocity = [tex]\frac{Distance}{Time}[/tex] = [tex]\frac{6 Wavelength}{120}[/tex]

F = [tex]\frac{Velocity}{Wavelength}[/tex]

F = [tex]\frac{6 wavelength}{120 wavelength}[/tex]

F = [tex]\frac{6}{120}[/tex]

F = 0.05 Hz

Therefore frequency of the navigation buoy floating on the sea oscillates as a wave is 0.05 Hz.

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[tex] { \sqrt[ \frac{ { \infty \binom{ log_{ \tan( \gamma \beta log( \alpha \sin( \csc(\%) ) ) ) }(?) }{?} }^{?} }{?} \times \frac{?}{?} ]{?} }^{2} [/tex]

The structure of the kangaroo paw flower fits with a bird pollinator because of its tabular structure.

The tabular structure of the kangaroo paw flower fits with a bird pollinator because it gives easy access to the nectar of the flower. These flowers are covered with hairs and have pointed lobes, which are in curved shape at their tips that gives them the appearance of kangaroo paws. These curved tips and tabular structure provides good access to the bird pollinators as well as the colorful petals also attracts the pollinators towards itself.

So we can conclude that The structure of the kangaroo paw flower fits with a bird pollinator because of its tabular structure.

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Answer:

1520.03cm²

Explanation:

AL=2πrh=2·π·14.4·16.8

Behavioral geneticists can ascertain how genes affect the environment and population by examining close relatives. Additional explanation Individual variances result from variations in hereditary variables.

Gender, disorders/diseases, blood type, and other characteristics that each person possesses can be handed down to their offspring. The expansion of the human population is facilitated by these genetic variations. The carrying capacity of the ecosystem is influenced by the population. The ability of the environment to provide the resources it possesses for a creature's life within reasonable bounds is known as carrying capacity. Environmental issues will arise if the population surpasses the carrying capacity of the resources generated or made available.

These issues include a lack of available natural resources, the growth of pollution, or competition for scarce natural resources. so that initiatives to manage or control the environment, such as recycling or processing industrial waste, can be made. To lessen environmental exploitation that affects the entire human population, the study of human behavior based on the nature of genes will be helpful. Studying close relatives enables behavioral geneticists to ascertain the effect of humans from the nature of their genes on the carrying capacity of the environment and their effect on living populations. The population of quality and productive human resources will have a positive impact on the environment.

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The Height of the rocket ship rises above the launch pad after 94 seconds of flight is 47m

Constant upward Acceleration(a) = 6.3m/sec²

Initial Upward Velocity [tex]V_{i}[/tex] = 0

Final Upward Velocity [tex]V_{f}[/tex] = a × t

= 6.3 × 94

= 592.2 m/sec

Let Height be h

Using relation:

[tex]V_{f2}[/tex]² + [tex]V_{i^{2} }[/tex]² = 2 × a × h

592.2 - 0 = 2 × a × h

h = 592.2 / (2× a)

= 592.2 / 2*6.3

= 47 m

So height above the ground is 47  m

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Answer:

50km

cuz he ran so fast in 100 seconds

Answer:

-5

Explanation:

the red line is showing that you are going down to -8 and the blue line is showing that you should go up, which means you are adding three to -8. When 3 is added to -8, you get -5.

Answer:h

Explanation:

The final velocity of the ball that is dropped from a height of 200m is v = 44.73 m/s .

The rate at which an object is travelling in one direction is referred to as its velocity. an automobile traveling north on a highway, or a rocket taking off. Its velocity vector's absolute value always is equal to the motion's speed because it is a scalar.

Given the initial velocity of the ball (u) =  0

Distance travelled by the ball (s) = 200m

Acceleration (a) = 10 m/s²

As we know:

v² = u² + 2as

Putting values:

v² = 0+2 × (10 m/s²) × (200 m)

v = 44.73 m/s.

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In the graphing of constant speed, we get a plateau while when we graph increasing acceleration, we have a straight line graph

The term speed refers to the change in the position of an object with time. If the speed changes by equal amounts in equal time intervals then we could say that the object is undergoing uniform acceleration. If the speed does not increase by equal amounts in equal time intervals then the objects is not undergoing a uniform acceleration.'

Thus if we plot the speed of a body against the time taken, the slope of the graph is taken to be the acceleration of the body. If the plot of the speed against the acceleration is a straight line graph that had  started from the origin of the graph then we have a case of uniform acceleration.

Thus, in the graphing of constant speed, we get a plateau while when we graph increasing acceleration, we have a straight line graph that starts from origin.

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If a roller coaster loop were perfectly circular, the peak speed would be equal to vmin=gR, where g=9.8m/s2 and R is the radius of the "circle."

Because friction and drag start depriving the car of energy right away, the first hill of a roller coaster is always the steepest part of the ride. A car's energy is virtually completely gravitational potential energy at the summit of the first slope (because its velocity is zero or almost zero).

The transformation of potential energy into kinetic energy drives the motion of a roller coaster. The potential energy of the roller coaster vehicles increases as they are propelled to the summit of the first hill. Potential energy is transformed into kinetic energy as the vehicles fall.

The potential energy will be 0 at the base of the hill.

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This implies that the opening price was 21080.28.

Closing index = 21029.47

plus down movement =50.81

The Dow Jones Industrial Average measures the stock price performance of 30 large companies listed on US stock exchanges. Stock index. Others include the S&P 500 Index and NASDAQ.

The Opening Price Index represents the average opening price of the day before the trading day. During trading, the price must have experienced fluctuations, ups and downs. However, at the end of the trading day, the closing price was reported at 21029.47, down 50.81.

Adding back from this closing index report, the opening price was 50.81 or about 51 basis points higher than the closing price.

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Raven's percentage error of the measurement is 5.26%

Percentage error = (absolute error / standard measurement) × 100

The pecenrage error of the measurement can be obtained as illustrated below:

Percentage error = (absolute error / standard measurement) × 100

Percentage error = (0.006 / 0.114) × 100

Percentage error = 5.26%

Thus, the perecentage error of Raven's measurement is 5.26%

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Answer:

I think the answer is 5.26%

but please let me know if I was wrong.

5.26% is the answer I got

Explanation:

The total distance (in kilometers) that India has plowed into Asia is 330,000 km.

The total distance (in kilometers) that India has plowed into Asia is calculated as follows;

distance = speed x time

distance = 6 cm/year x (55 x 10⁶ years)

distance = 330,000,000 cm

distance = 330,000 km

Thus, the total distance (in kilometers) that India has plowed into Asia is 330,000 km.

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