Need help ASAP, thanks in advance

For each question, choose answer choice a-e and explain why you chose that answer.

The weight of the box is changed to 50 N.

The weight of the box is changed to 200 N.

The applied force is increased to 50 N.

The applied force is increased to 80 N.

The coefficient of static friction is increased to 0.7.

The coefficient of kinetic friction is increased to 0.5.

The coefficient of kinetic friction is increased to 0.5 and the coefficient of static friction is increased to 0.7.

The weight of the box is changed to 200 N and the coefficient of static friction is increased to 0.7.

The weight of the box is changed to 200 N and the coefficient of kinetic friction is increased to 0.5.

The weight of the box is changed to 200 N and the applied force is increased to 50 N.

Answer:

maximum velocity,then u draw your diagram then u calculate for max velocity then the answer u get use it for total shape

Since Joe is running towards the goal line and slowing down, the option that describes this motion is negative velocity, negative acceleration.

A negative velocity occurs when an object moves in the negative direction.

Example of negative velocity;

If a car is moving away from you (reference point) then the velocity is positive.

If a car is coming towards you (reference point) then the same vector reverses direction and hence the velocity is negative.

If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion. Thus, the acceleration of the object will be negative.

Thus, since Joe is running towards the goal line and slowing down, the option that describes this motion is negative velocity, negative acceleration.

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The 15 km/s velocity is equivalent to 15000 m/s and 54000 km/h.

Velocity is a vector quantity. It consist both a direction and a magnitude. The magnitude of velocity is called speed. Its S.I. unit is a meter/second. It also has other units like Km/h and Km/s. Its dimensional formula is [[tex]LT^{-1}[/tex]].

Given in the question

Velocity is 15 Km over a second

We can infer from the given value that the body moves 15 km per second.

1 Km = 1000 m

1 Km × 15  = 15 × 1000 m

So 15 Km = 15000 m

Hence we can say that the body travels 15000 meters in a second.

As a result, its velocity in m/s is 15000 m/s.

Now

15 kilometers can be covered in 1 second.

Distance traveled in 3600 seconds = 3600 × 15 Km

So the total distance traveled in 3600 seconds is 54000 kilometers.

Also 3600 seconds = 1 hour

In other words, The body travels 54000km in 1 hour, hence its velocity is 54000 km/h.

Therefore, the 15 km/h velocity is equal to 15000 m/s and 54000 km/h.

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The distance from the home plate the fielder will be when he catches the ball is 63.47 m

From the question given above, the following data were obtained:

The distance (i.e range) the fielder will be when he catches the ball can be obtained as follow:

R = u²Sine(2θ) / g

R = 26.8² × Sine (2×60) / 9.8

R = 622.014 / 9.8

R = 63.47 m

Thus, the distance the fielder will be is 63.47 m

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Answer:

19.6 Newtons

Explanation:

[tex]\displaystyle \textsf{The weight of the block is W= mg where m is the mass and g the acceleration due to gravity}[/tex]

[tex]\sf W = 5kg, \; and\; g = 9.80 m/s^2[/tex]

[tex]\sf W = 5 x 9.8 = 49\; Newtons[/tex]

[tex]\textsf {If the coefficient of static friction is } $\mu_s$, the force to be applied for the block to slip is given by the equation}:\\\mathsf {f_s = \mu_s \times W}\\\\\textsf {So force required, given $\mu_s$ = 0.4 is: }\\\\\\\mathsf {f_s = 0.4 \times 49 = 19.6 } \textsf{ Newtons }[/tex]

The possible ergonomic solution that could help Daniel reduce hos back pain caused by sitting long on his chair is a standing desk.

Ergonomics is defined as the science of creating a working environment that suits the capabilities and limitations of the worker while providing the best working experience.

If Daniel's physician has told him that he needs to spend less time in his office chair because sitting for so long is causing him to have back pain. The possible ergonomic solution that could help him include the following.

Thus, the possible ergonomic solution that could help Daniel reduce hos back pain caused by sitting long on his chair is a standing desk.

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Answer: B. A standing desk

Explanation: I remember getting it right on my test.

F. The situation in which the work done is positive is, "Pushing a box on the floor across the room.".

The work done on an object is said to be positive work when force applied on the object causes a displacement of the object in the same direction.

Some of the examples of positive work include the following:

From the given options, the only option in which the applied force is in the same direction as the box's displacement is option F "Pushing a box on the floor across the room".

Thus, the situation in which the work done is positive is, "Pushing a box on the floor across the room.".

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(a) Capacitance = 4.43 * 10⁻¹¹ F

(b) Magnitude of the charge on each plate = 2.9238 * 10⁻⁸ C

(c) Stored Energy = 8.7714 * 10⁻⁶

(d) The electric field between the plates = 6.0 * 10⁴ V/m

(e) The energy density between the plates = 1.45 J/m³

(A) The ability of a conductor or group of conductors to store a separated electric charge for a given change in electrical potential is known as its capacitance. The term "capacitance" also suggests the storage of electrical energy.

Capacitance (C) = A∈ / d = [tex]\frac{55 * 10^{-4}* 8.86 * 10^{-12}}{0.011}[/tex] = 4.43 * 10⁻¹¹ F

Therefore, Capacitance = 4.43 * 10⁻¹¹ F

(B) The force per charge on any particular test charge situated within the electric field is used to calculate the electric field vector's magnitude. Either the source charge or the test charge could be directly affected by the force acting on it.

The magnitude of the charge on each plate (Q) = CV

Q = 4.43 * 10⁻¹¹ * 660 = 2.9238 * 10⁻⁸ C

Therefore, the magnitude of the charge on each plate = 2.9238 * 10⁻⁸ C

(C) The energy that a thing retains due to its position in relation to other objects, internal tensions, electric charge, or other causes is known as stored energy.

Stored Energy (U) = 0.5 CV² = 8.7714 * 10⁻⁶ J

Therefore, Stored Energy = 8.7714 * 10⁻⁶ J

(D) The region or place where the influences of the plates' charges are visible is the electric field between the plates. For instance, any charged plate will produce an electric force to either attract or repel a charged particle if it is placed close to it.

The electric field between the plates (E) = V / d = 660 / 0.011 = 6 * 10⁴ V/m

Therefore,  The electric field between the plates = 6.0 * 10⁴ V/m

(E) The quantity of energy that can be held in a specific system, substance, or area of space is known as its energy density. Energy per volume or mass can be used to measure energy density. A system or material has more energy stored in it when its energy density is higher.

The energy density between the plates (u) = U / Ad = [tex]\frac{8.7714 * 10^{-6} }{(55 * 10^{-4}) (1.1 * 10^{-3})} = \frac{0.0000063}{0.0055 * 0.0011} = \frac{0.00000878}{0.00000605} = \frac{878}{605} = 1.45 Jm^{3}[/tex]

Therefore, The energy density between the plates = 1.45 J/m³

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The magnitude of vector B is determined as 24.5 units.

A resultant vector is defined as a single vector that produces the same effect as is produced by a number of vectors collectively.

The given parameters;

The magnitude of vector B is calculated as follows;

B² = R² - A²

where;

B = √(35² - 25²)

B = 24.5 units

Thus, the magnitude of vector B is determined as 24.5 units.

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Dean's acceleration while slowing down on his skateboards a = -1.5 m/s².

To find the acceleration of skateboards

Using formula,

a = Δv/Δt

where,

a is acceleration

Δv is change in speed

Δt is time

By putting the given values,

a = 1.0 m/s - 5.5 m/s / 3 s

a = - 4.5 m/s / 3s

a = -1.5 m/s²

When an object is moving in a positive direction, the acceleration is negative, but the rate of change of velocity is positive (velocity is decreasing). When an object moves in the reverse or opposite direction, we can define these two accelerations as well (right to left).

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Answer:

Mass and velocity are both directly proportional to the momentum. If you increase either mass or velocity, the momentum of the object increases proportionally. If you double the mass or velocity you double the momentum.

Explanation:

(a) The distance traveled by the driver before stopping is 20.57 m.

(b) When you have traveled only half the distance in part (a), your speed is greater than 6.0 m/s.

(c) The speed of your car when you have traveled half the distance in part (a) is 8.49 m/s.

The distance traveled by the driver before stopping is calculated as follows;

v² = u² + 2as

when the car stops, the final velocity, v = 0

0 = u² + 2as

0 = 12² + 2(-3.5)s

0 = 144 - 7s

7s = 144

s = 144/7

s = 20.57 m

v² = (12²) - 2(3.5)(0.5 x 20.57)

v² = 72.005

v = √72.005

v = 8.49 m/s

Thus, when you have traveled only half the distance in part (a), your speed is greater than 6.0 m/s.

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Answer:

It shapes into the form of the container because water is a liquid.

Explanation:

The required velocity of the plane relative to air with a velocity of 55 km / h S is 373.42 km / h

v = d / t

d = 1400 km ( 43° E of S )

t = 3.4 hrs

[tex]V_{pg}[/tex] = d / t

[tex]V_{pg}[/tex] = 1400 / 3.4

[tex]V_{pg}[/tex] = 411.75 km / h ( SE )

[tex]V_{ag}[/tex] = 55 km / h ( S )

[tex]V_{pgx}[/tex] = sin 43° ( 411.75 )

[tex]V_{pgx}[/tex] = 280.81 km / h ( E )

[tex]V_{pgy}[/tex] = cos 43° ( 411.75 )

[tex]V_{pgy}[/tex] = 301.14 km / h ( S )

[tex]V_{x}[/tex] = [tex]V_{pgx}[/tex] - [tex]V_{agx}[/tex]

[tex]V_{x}[/tex] = 280.81 - 0

[tex]V_{x}[/tex] = 280.81 km/ h

[tex]V_{y}[/tex] = [tex]V_{pgy}[/tex] - [tex]V_{agy}[/tex]

[tex]V_{y}[/tex] = 301.14 - 55

[tex]V_{y}[/tex] = 246.14 km / h

V² = [tex]V_{x}[/tex]² + [tex]V_{y}[/tex]²

V = √ [ ( 280.81 )² + ( 246.14 )² ]

V = 373.42 km / h

tan θ = [tex]V_{y}[/tex] / [tex]V_{x}[/tex]

θ = [tex]tan^{-1}[/tex] ( 246.14 / 280.81 )

θ =  [tex]tan^{-1}[/tex] ( 0.88 )

θ = 41.35° ( S of E )

Therefore, the required velocity of the plane relative to air is 373.42 km / h at 41.35 S of E

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The magnitude and direction of the object's displacement is 7 m and west direction respectively.

The displacement of an object is the change in the position of the object. Displacement is a vector quantity because it has both magnitude and direction.

To find the sum of the vectors, we find the displacement of the vectors.

Initial position of the vector = 10 m east

final position of the vector = 3 m west

displacement of the vector = final position - initial position

displacement of the vector = 3 m - 10 m

displacement of the vector = - 7 m

magnitude of the displacement = 7 m

direction of the displacement = west

Thus, the magnitude and direction of the object's displacement is 7 m and west direction respectively.

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A pen name is the name used by the writer instead of their real name when publishing. This name is called as pseudonym or a fake name. The author's real name is probably known to the publisher, but not to the public.

If I'll be the writer, I'll use Dark Shadow as my pen name.

Dark Shadow effectively acts as a living appendage that obeys his master's every command. It is sentient, capable of speech, and loyally protects its host regardless of its state. Also it is short and sweet name and can be pronounced easily.

Also thee is a drawback in seeking secrecy with the pen name. The Guardian article says, "If you try to keep your identity secret, you can't go to events or festivals; be pictured in newspapers, or be open about your possible success. And, if you become hugely successful, you'll have to come out eventually – as Madeleine Wickham, the author of the Sophie Kinsella books, did. "

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The total displacement is 4317.34 meters and the average speeds of the legs are 27.36m, 54.72m, 27.35m.

The overall distance the object covers in a given amount of time is its average speed. A scalar value represents the average speed. It has no direction and is indicated by the magnitude.

a = 2.25 m/s2 ; t1 = 19 s ; t = 2.50 min = 150 sec ; a' = -9.09 m/s2  t3 = 4.70 s

(a)The velocity at the end of the first interval will be given by

V = u + at = 0 + a t1 = 2.25 x 19 = 42.75 m/s

This velocity will remain the same throughout the second period in accordance with point (2) and serve as the initial velocity for the third interval.

We now see that, if s is the displacement, s = u t + 1/2 a t2

In our situation, the sum of the displacements in the specified three intervals will represent the total displacement.

[tex]\Delta s(total) = \Deltas1 + \Deltas2 + \Deltas3[/tex]

[tex]\Delta s(total) = [0 + 1/2 x 2.88 x (19)2) + [54.72 x 66 + 0] + ( 54.72 x 6.8 + 1/2 x (-8.05) x (6.8)2][/tex]

[tex]\Delta s(total) = 519.84 + 3611.52 + 185.98 = 4317.34 meters[/tex]

Hence,

[tex]\Delta s(total) = 4317.34 meters = 4.32 Km.[/tex]

(b)Speed for leg 1 will be

v1 = [tex]\Delta s1 / t1 = 519.84 / 19 = 27.36 m/s[/tex]

Speed for leg 2 will be

[tex]v2 = \Delta s2 / t2 = 3611.52 / 66 = 54.72 m/s[/tex]

Speed for leg 3 will be

[tex]v2 = \Delta s3 / t3 = 3611.52 / 66 = 185.98 / 6.8 = 27.35 m/s[/tex]

The average velocity of the complete trip will be given as follows:

V = [tex]\Delta s(total) / t(total)[/tex]

t(total) = t1 + t2 + t3 = 19 + 66 + 6.8 = 91.8 s

[tex]V = \Delta s(total) / t(total) = 4317.34 meters / 91.8 = 47.03 m/s[/tex]

Hence, V = 47.03 m/s

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From the given graph, it is shown that James is running the race with the same speed while Rachel changes his speed time-to-time. It can be inferred from the graph that James wins the race.

Speed is the distance travelled by an object in a particular time. In the race, James run with a constant speed throughout the race and Rachel changes its speed after some time.

By looking at the graph, we can say that James catch up Rachel 17.5 minutes after the start of the race where they both completed 1750m distance.

Speed of James can be calculated by the formula:

Speed = Distance/Time

Speed = 3000m/30min

Speed of James = 100m/min.

Different speeds of Rachel can be calculated by the same formula:

For the first 1000m he completes the distance in 5 min. therefore, the speed will be:

Speed = 1000m/5min.

Speed = 200m/min.

For the next 1500m. he covers the distance in 25min. therefore, the speed here will be:

Speed = 1500m/25min.

Speed = 60m/min.

For the next 500m. he covers the distance in 5 min. therefore, the speed will be:

Speed = 500m/5min.

Speed= 100m/min.

As, James covers the same distance earlier than Rachel. James cover the the distance in 30 minutes while Rachel covers the same distance in 35 minutes. James will be the winner of the race.

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The acceleration of a car that travels on a straight level road starting from rest and going at 32 ft/s at the end of 4.2s is 7.62ft/s².

The acceleration of a moving car can be calculated by dividing the speed by the time taken as follows:

Acceleration = Speed ÷ time

According to this question, a car travels on a straight level road starting from rest the car is going 32 ft/s (22mi/h) at the end of 4.2s. The acceleration can be calculated as follows:

Acceleration = 32ft/s ÷ 4.2s

Acceleration = 7.62ft/s²

Therefore, the acceleration of a car that travels on a straight level road starting from rest and going at 32 ft/s at the end of 4.2s is 7.62ft/s².

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Answer:

[tex] log( \beta e \alpha \sin( \cot( \sec( \binom{? \times \frac{ \\ \infty }{?} }{?} ) ) ) ) [/tex]

Science is the study of how the world functions through the systematic process of data collection known as the scientific method.

Repeated trials are when a measurement is performed more than once at least three times, most often five but the more the better.

The likelihood that a measurement made once will yield an accurate result is substantially smaller. However, if you measure it multiple times, you may average the results to produce a value that is considerably more accurate.

In repeated trials, the same thing is measured repeatedly to increase the accuracy of your results. This is essential since data in the actual world frequently varies and nothing is flawless. Your average will get more closely to the genuine value as you perform more trials.

Therefore, Science is the study of how the world functions through the systematic process of data collection known as the scientific method.

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The statement ' The hemisphere tilted towards the Sun experiences summer and the hemisphere tilted away from the Sun experiences winter.' is true.

The variation in seasons is due to the slight tilt of the earth on its axis towards the sun. This tilt is approximately equal to 29 and 1/2 degrees.

Due to this tilt of the earth, the north pole or the south pole of the northern or the southern hemisphere respectively never directly faces the sun.

But when the respective hemisphere is tilted towards the sun, it is as close to the sun as it is physically possible, and therefore that hemisphere experiences the summer season.

Whereas the other hemisphere which is tilted away from the sun is as far from it as possible and receives very little sunlight and hence experiences the winter season.

In the context of the above discussion, the statement ' The hemisphere tilted towards the Sun experiences summer and the hemisphere tilted away from the Sun experiences winter.' is true.

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Answer:

5.2s

Explanation:

We care about the vertical component of the velocity, which, in our case, is [tex]v_y=55 sin 68\° m/s \approx 51 m/s[/tex]. The projectile is affected by gravity, which means its velocity will decrease by [tex]g= 9.81 m/s[/tex] each second. Remembering that at maximum height velocity is zero, we can write [tex]0=51-9.81 t \rightarrow t= \frac{51}{9.81}\approx 5.2s[/tex]

(A) Experiments use one type of statistical test; correlational methods use a different type of statistical test

Correlational research:

Experimental research:

Difference between experimental and correlational methods:

You alter an independent variable and track its impact on a dependent variable in an experimental design. Other factors cannot affect the outcomes because they are under control. You measure variables in a correlational design without changing any of them.

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The velocity of the rain with respect to car is 43.3 km/h and the velocity of the rain with respect to earth is 50 km/h.

Relative velocity is the velocity of one object with respect to another using a frame of reference.

Velocity of the rain with respect to the car

V(rc) = 50 km/h x sin(60)

V(rc) = 43.3 km/h

Velocity of the rain with respect to the earth

V(re) = speed of the car =  50 km/h

Thus, the velocity of the rain with respect to car as frame of reference is 43.3 km/h and the velocity of the rain with respect to earth as the frame of reference is 50 km/h.

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The distance travelled by the motorbike while it is moving at a constant speed is 150m

From the graph, we form the relationship between the speed s and the change in the time t for the journey, i.e. from t = 20sec to t = 30sec speed  s is constant = 15m/s

As the formulae states that

Speed = Distance / Time

Distance = Speed × change in time

⇒15 × ( 30 - 20 )

⇒15 × 10

⇒150m

Hence the Distance travelled by bike was 150m

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The speed of the mass at the time the tension is measured is 6.12m/s

centripetal force - It is a force which makes a body follow a curved path.

It is directed inward towards center of rotation.

for example - gravitational force of sun is a centripetal force that keeps earth rotating around it.

the centripetal force on the swinging mass

Fc = mv²/r

where Fc is the centripetal force

m is the mass of body

v is the velocity

r is the radius

m = 1.5

r = 2.3 m

F = 24.5 N

To calculate the speed we put values in above equation

Fc = mv²/r

v = sqrt(Fc x r / m)

v = [tex]\sqrt[]{\frac{F *m}{r} }[/tex]

[tex]v = \sqrt[]{\frac{24.5*1.5}{2.3} }[/tex]

v = 6.12m/s

The speed of the mass at the time the tension is measured is 6.12m/s

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The maximum distance covered by the car from point A to B will be 120 meters, and the minimum distance covered by the car will be 25 meters.

Measuring is the most important scientific concept. Many different types of quantifiable quantities can be measured using base or physical fundamental units. One such quantifiable quantity is speed, which computes the proportion of a moving object's distance travelled to its travel time.

According to the question,

Point A and B are taken on X-axis and point B,C and D are taken on y-axis.

On going from point A to B,

Time taken= 10 seconds

Speed= 12 m/s

Distance covered will be : Speed × time

=12 × 10 sec

Distance= 120 meters

On going from Point B to C,

Time taken= 5 Seconds

Speed= 5 m/s

Distance covered by car will be : Speed × Time

=5 × 5 sec

Distance= 25 meters.

Now, On going from point C to D,

Time taken= 15 seconds

Speed= 2 m/s

Distance covered = speed × time

= 2 × 15 sec

Distance= 30 meters

Hence, the maximum distance covered by car is 120 meters when it goes from point A to B and the minimum distance covered by car is 25 meters when it goes from Point B to C.

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