Neha and Suhani are playing with two identical pendulums. They leave the bob from a certain position and wait for it to return to the same point. The one who waits for a shorter time wins. Neha leaves her pendulum from point L and Suhani leaves her pendulum from point P (see figure). What happens?
a. Neha wins as her bob comes back faster.
b. Suhani wins as her bob comes back faster.
c. No one wins as the bobs come back at the same time.
d. We cannot say any of the above for sure.

When a light source is turned on, it emits photons that scatter in different directions and hit every object that is present around it.

This is referred to as the path in which electric current can flow around and comprises of some components such as resistors, bulb etc. There are two types which include open and closed circuit.

When the light source is turned on, the circuit is closed and there is complete flow of electrons which powers up the bulb and gives rise to the emission of the photons which hits objects around it thereby giving rise to the illumination of the area.

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Magnetic field does the cable crew ate at points outside the cable will be zero .

Mathematically, Ampere's law circuital law is given by

 ∫B.dl = u₀I   ......(2)  where u₀ is the permitivity of free space whose value is [tex]4\pi \times10^{-7}Tm/A[/tex]  and I is the total current threading in the loop .

It is given that coaxial cable carries current 2.00 A in one direct tin, and the sheath around it carries current 2.00A in the opposite direction.

Hence the total current in the loop will be

  [tex]I=2+(-2)=0[/tex]

Putting this value of current in equation (2) , we get

[tex]B=0[/tex]

As the total current is zero , so the magnetic field will be zero .

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Magnetic field does the cable crew ate at points outside the cable will be zero .

Mathematically, Ampere's law circuital law is given by

 ∫B.dl = u₀I   ......(2)  where u₀ is the permitivity of free space whose value is [tex]4\pi \times10^{-7}Tm/A[/tex]  and I is the total current threading in the loop .

It is given that coaxial cable carries current 2.00 A in one direct tin, and the sheath around it carries current 2.00A in the opposite direction.

Hence the total current in the loop will be

  [tex]I=2+(-2)=0[/tex]

Putting this value of current in equation (2) , we get

[tex]B=0[/tex]

As the total current is zero , so the magnetic field will be zero .

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Magnetic field does the cable crew ate at points outside the cable will be zero .

Mathematically, Ampere's law circuital law is given by

 ∫B.dl = u₀I   ......(2)  where u₀ is the permitivity of free space whose value is [tex]4\pi \times10^{-7}Tm/A[/tex]  and I is the total current threading in the loop .

It is given that coaxial cable carries current 2.00 A in one direct tin, and the sheath around it carries current 2.00A in the opposite direction.

Hence the total current in the loop will be

  [tex]I=2+(-2)=0[/tex]

Putting this value of current in equation (2) , we get

[tex]B=0[/tex]

As the total current is zero , so the magnetic field will be zero .

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Answer:

1. The force of friction [tex]F_f =0.72 \times F_n[/tex]

2. The total travel time is approximately 0.884 seconds

The range is approximately 2.209 m

The maximum height reached is approximately 0.383 m

3. The time it will take the cyclist to stop is approximately 25.806 seconds

4. The time it will take the ball to reach the ground is approximately 2.020 seconds

Explanation:

1. Given that the coefficient of static friction, μ = 0.72, we have;

[tex]F_f = \mu \cdot F_n = 0.72 \times F_n[/tex]

2. The given parameters are;

The initial velocity of the car, v = 5 m/s

The direction of the vehicle = 60° to the horizontal

Therefore, we have;

The vertical component of the velocity, [tex]v_y[/tex] = 5 × sin(60°) = 2.5×√3

[tex]v_y[/tex] = 2.5×√3 m/s

The total travel time, t = 2·u·sin(θ)/g = 2 × 5 × sin(60°)/9.8 ≈ 0.884

The total travel time, t ≈ 0.884 seconds

The range, R = (u²·sin(2·θ))/g = 5² × sin(120°)/9.8 ≈ 2.209

The maximum height is given from the v² = [tex]u_y[/tex]² - 2·g·h

Where;

v = The final velocity = 0 m/s at maximum height

h = [tex]h_{(max)}[/tex] = The maximum height

[tex]u_y[/tex] = The initial vertical velocity = 2.5·√3

∴ 0² = 2.5·√3² - 2 × 9.8 × [tex]h_{(max)}[/tex]

2.5·√3² = 2 × 9.8 × [tex]h_{(max)}[/tex]

[tex]h_{(max)}[/tex] = 2.5·√3²/(2 × 9.8) ≈ 0.383

The maximum height = [tex]h_{(max)}[/tex] = 0.383 m

3. The given parameters are;

The initial velocity of the cyclist, v₀ = 16 m/s

The deceleration of the cyclist, a = -0.62 m/s²

At the point the cyclist stops, the final velocity, [tex]v_f[/tex] = 0

Therefore, from the given kinematic equations, we have;

[tex]v_f[/tex] = v₀ + a·t

Where t, is the time it will take the cyclist to stop

∴ t = ([tex]v_f[/tex] - v₀)/a = (0 - 16)/(-0.62) ≈ 25.806

Therefore, the time it will take the cyclist to stop = t ≈ 25.806 seconds

4. The time, t, it will take the ball to reach the ground, from a height, h = 20 meters is given by the equation of free fall as follows;

h = 1/2·g·t²

Where;

g = The acceleration due to gravity = 9.8 m/s²

Therefore, we have;

t² = h/(1/2·g)

t = √(h/(1/2·g)) = √(20/(1/2 × 9.8)) = 2.0203050891 ≈ 2.02

The time it will take the ball to reach the ground, t ≈ 2.020 seconds.

The bunny’s displacement at t=12 s is 12 m.

The bunny’s acceleration when slowing down is -0.083 m/s².

The displacement of an object is the change in position of the object.

The displacement of the object at time, t = 12 seconds, is the change in position from time, t = 0 seconds to time, t = 12 seconds.

Δx = v(t₂ - t₁)

Δx = 1 m/s (12 s - 0 s)

Δx = 12 m

The bunny’s acceleration when slowing down is calculated as follows;

a = (v - u)/(t₂ - t₁)

a = (0 - 1 m/s) / (12 s - 0 s)

a = -0.083 m/s²

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Answer:

The bunny’s displacement at t=12 s is 12 m.

The bunny’s acceleration when slowing down is -0.083 m/s².

The torque required, in n∙m per meter of rod length, to hold the inner rod fixed is 0.535N.m/rod length

Angular velocity, ω = 160rev/min

ω (rad/s) =  (2π×160)/(60) = 16.74rad/s

Tangential velocity,

(V) = ωr

r is radius  = 14/2 = 7cm = 0.07m

Tangential velocity of the sleeve

(V)= ωr

V = 16.74  rad/s×0.07m

V  = 1.171m/s

Distance between the cylinders,

h= (14-12)/2 = 1cm

h = 0.01 m

Shear stress on glycerin is given by

τ = μ×V/h

μ is the dynamic viscosity of glycerin  at 20°C = 1.49 kg/m.s

∴ τ = (1.49 ×1.171 )/(0.01)

  τ = 174.4 N/m²

Shearing force (F) = shear stress × area

F = τ × A

F = τ * 2πrL          [A=2πrL (area of cylinder )]

F/L = (17.4×2π×0.07)

F/L =  7.649N/m

To hold the inner rod fixed

the opposite torque by inner rod must be equal to torque produced by the shearing force.

Torque/length (N.m/length) = [force/length (N/m) * radius]

τ /L = 7.649 ×0.07 =  0.535N.m/rod length

The torque required, in n∙m per meter of rod length, to hold the inner rod fixed is 0.535N.m/rod length

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The electric field for 100 cm is 1.62 MN/C

Length of the straight filament = (100cm) (1m/100cm) = 1m

Electric field for the straight conductor = [tex]E = \frac{2k_{e} \lambda}{r}[/tex]

E = [2(8.99 × 10^9 N·m^2/C^2)(90.0 × 10^-6 C/m)] / 1 m

E = 1.62 MN/C

The electric field is directed radially inward, toward the filament.

The electric field is a force produced by a charge near its surroundings. This force is exerted on other charges when brought in the vicinity of this field. SI unit of the electric field is N/C (Force/Charge).

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The answers to the following questions are 1. Group B, 2. secret ingredient, 3. bad breath, 4. not effective cent percent, 5. the placebo effect.

1. The group of people who received the normal mint which does not contain Mr. krab's secret ingredient for breath mint is the control group. So, Group B of people are in the control group.

2. Independent variable in the one for which the research is being conducted. So in this case the secret ingredient in the breath mint is the independent variable.

3. Dependent variable is the one that affects the result of the research. So, the bad breath, in this case, is the dependernt variable.

4. The Group A of fifty people received the secret ingredient in breath mint; 30 people it reported better breath. Therefore the mint that has a secret ingredient is successful in reducing the amount of bad breaths in the individual but does not appear to be effective cent percent.

5. The 10 people in group B may have reported fresher breath due to the 'placebo' effect. It is the effect where the physical or mental health of the individual appears to improve after a fake, dummy, or sample treatment is given to him/her.

Therefore, 1. Group B, 2. secret ingredient, 3. bad breath, 4. not effective cent percent, 5. the placebo effect.

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Answer:

2.5 m/s North

Explanation:

Took the quiz on K12 it was right

Answer: Ptolemy or Kepler or Tycho Brache

Answer:

Point A

Explanation:

There are 3 states of equilibrium, which are as follows:

1. Stable Equilibrium

2. Unstable Equilibrium

3. Neutral Equilibrium

1. Stable Equilibrium:

A body is said to be in stable equilibrium, if it comes back to its original position, when it is slightly  displaced. In this case the center of mass of the body is raised up as compared to the initial position.

Example: A book lying on a table, a map hanging on the wall, a stone suspended by a spring.

2. Unstable Equilibrium:

A body is said to be in unstable equilibrium if it does not come back to its original position when it is  slightly displaced. In this case the center of mass of the body is lowered, as compared to the initial position.

Example: A vertical standing pencil, a stick balanced on finger, a funnel resting on its pointed end.

3. Neutral Equilibrium:

A body is said to be in neutral equilibrium, if on being slightly displaced it does not come back to its  original position but occupies a new position similar to its original position. In this case the center of mass of the body remains at same height.

Example: A spherical ball on floor, a cone resting in horizontal position.

So, it is clear from the figure that when we will remove displacement the bus will come back to its original position. Therefore, this is the case of stable equilibrium.

So, the center of mass must have raised up. The original center of mass of the bus must be in the center. So, now the center of mass should have moved above center of bus, vertically.

Therefore, the center of mass of the bus is at point A  

Answer: The correct order of energy transformation is from CHEMICAL ENERGY to ELECTRICAL ENERGY to LIGHT ENERGY

Explanation:

Energy which is simply defined as the ability to perform work is made up of different forms, these include:

- Mechanical energy: Associated with machines at work.

- LIGHT ENERGY: produced by light bulbs

- ELECTRICAL ENERGY: taking in by television set and other electrical appliances.

- CHEMICAL ENERGY: stores in food and other fuels

- Sound energy: Produced by vibrating objects example piano, drums.

According to the law of conservation of energy, energy can neither be created nor destroyed in a closed system, but can be transformed from one form to another, thereby keeping the energy in the closed system constant. From the question, the circuit is an example of a closed system and the order of energy transformation taking place is from the battery (CHEMICAL ENERGY) to ELECTRICAL ENERGY(power source) to LIGHT ENERGY(bulb). I hope this helps, thanks.

(a) The horizontal component of its velocity is 12 m/s.

(b) The speed with which the block is moving at the end of the given time  is 25.36 m/s.

The horizontal component of velocity is the velocity of a projectile directed along x - axis or x direction of the projectile path.

The horizontal component of a velocity is not affected by gravity since the velocity is directed along horizontal path.

This causes the horizontal component of velocity to be constant. That is the initial horizontal velocity is equal to the final horizontal velocity.

Since the rock is thrown horizontally, the horizontal component of its velocity will be constant and equal to 12 m/s.

The final speed of the block at end of the 2.28 s will due to change in vertical velocity.

The final vertical velocity of the block is calculated as follows;

v = u + gt

where;

v = 0 + gt

v = gt

v = (9.8)(2.28)

v = 22.34 m/s

The resultant final speed if calculated as follows;

v = √(Vx² + Vy²)

where;

v = √(12² + 22.34²)

v = 25.36 m/s

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Answer:

2 m/s²

Explanation:

If changes speed by 2 meters per second each second means:

2 m/s²

Because it changes constantly it veloctity.

Remember the aceleration changes the velocity.

Answer:

c. 2 m/s2

is the right answer.

Answer:

D

Explanation:

In order to qualify for the finals in a racing event the race car wit an average speed of 250 km/h on a track with a total length of 1600 m must finish  the track in a time of: 23.04 seg

The formula and procedure we will use to solve this exercise is:

t = x/v

Where:

Information about the problem:

By converting the distance units from (m) to (km) we have:

x=1600 m * 1 km/1000 m

x = 1.6 km

Applying the time formula we have that:

t = x/v

t = 1.6 km / 250 km/h

t = 6.4 *10^-3 h

By converting the time units from (h) to (seg) we have:

t = 6.4 *10^-3 h * 3600 seg/1 h

t= 23.04 seg

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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Answer: 2.72727272......g/cm3^

Explanation:

D = g/cm^3

soo d = 15/5.5

A 15-g block of aluminum has a volume of 5.5 cm. Its density will be 2.73 kg /  [tex]cm^{3}[/tex]

Density is the measurement of how tightly a material is packed together. It is defined as the mass per unit volume. Density is defined as the ratio of mass of the object to the volume of the object. Different substances have different densities.

The mathematical expression for density is as follows: Density=Mass * Volume. The mass of a substance is expressed in kilograms and the volume is expressed in liter.

Density is an important concept because it allows us to determine what substances will float and what substances will sink when placed in a liquid. Generally, substances float so long as their density is less than the density of the liquid they are placed in.

Density Symbol: ρ

Density Formula: ρ = m/V, where ρ is the density, m is the mass of the object and V is the volume of the object.

Density = mass / volume

mass = 15 kg

volume = 5.5 [tex]cm^{3}[/tex]

density = 15 / 5.5 = 2.73 kg /  [tex]cm^{3}[/tex]

A 15-g block of aluminum has a volume of 5.5 cm. Its density will be 2.73 kg /  [tex]cm^{3}[/tex]

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Answer: Planets would be pulled into the sun

Explanation:

This is the correct answer.

Answer:

Newton, symbol N

Explanation:

newton, symbol N

Answer:If kinetic energy increases, so does the thermal energy, and vice versa.

Please brainliest!

"Choice-C" is the answer.

Answer:

A.B = -38

Explanation:

A = 2i + 9j and B = -i - 4j.

So, A.B = (2i + 9j).(-i - 4j)

= 2i.(-i) + 2i.(-4j) + 9j.(-i) + 9j.(-4j)

= -2i.i - 8i.j - 9j.i - 36j.j

since i.i = 1, j.j = 1, i.j = 0 and j.i = 0, we have

A.B = -2(1) - 8(0) - 9(0) - 36(1)

A.B = -2 - 0 - 0 - 36

A.B = -38

Answer:

Stars create new elements in their cores bu squeezing elements together in a process called unclear fusion. First stars fuse hydrogen atoms into heluim. Helium atorm then fuse to create berylluim and so on until fusion in the star’s core has created every element up to icon.

Answer:

B is the answer

Explanation:

Plastics degrade when exposed to ultraviolet (UV) light from the sun. UV exposure can make a chemical reaction in the plastic, resulting in the scission, or severing, of those large polymer molecules if exposed long enough.

Plastics degrade when exposed to ultraviolet (UV) light from the sun. UV light can cause a chemical reaction in the plastic, resulting in the scission, or severing, of those large polymer molecules if exposed long enough.

When exposed to ultraviolet (UV) light from the sun, plastics degrade. If exposed to UV light for an extended period of time, it can cause a chemical reaction in the plastic, resulting in the scission, or severing, of those large polymer molecules.

Thus, light can cause the plastic to melt.

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1.plants,most algae and cyanobacteria

2.during photosynthesis cells use carbon dioxide and energy from the sun to make sugar molecules and oxygen

3.carbon dioxide+water---Glucose+oxygen

4.chloryphil

5.it absorbs blue and red good and absorbs green poorly

6 In plants, photosynthesis takes place in chloroplasts, which contain the chlorophyll. Chloroplasts are surrounded by a double membrane and contain a third inner membrane, called the thylakoid membrane, that forms long folds within the organelle

Explanation:

#31 = crest

#32 = Trough

#33 = Wavelength

#34 = Amplitude

-TheUnknownScientist

Answer:

vaat hachi upar vada ni.

Answer:

The velocity of the cross-wind was 375 km/hr South

Explanation:

The given speed of the airplane, v₀ = 500.0 km/hr W

The direction the airplane is headed = West

The direction of the wind encountered = Southbound wind

The final velocity of the airplane, R = 625 km/hr

The final direction of the airplane = South West SW

Let vₐ represent the velocity of the cross-wind

Therefore, we have the given velocities in vector form as follows;

R = -500.0·i - vₐ·j

Also, we have;

[tex]\left | R \right | = 625 = \sqrt{v_0^2 + v_a^2} = \sqrt{(-500)^2 + (-v_a)^2}[/tex]

625² = (-500)² + (-vₐ)²

(-vₐ)² = 625² - (-500)² = 140625

-vₐ = 375

vₐ = -375 km/hr North = 375 km/hr South

The velocity of the cross-wind = vₐ = 375 km/hr South

The electric flux through the hole is [tex]56.45\ webber[/tex] .

It is given , hollow sphere of radius 10.0cm surrounds a 10.0-μC charge.

The whole surface of hollow sphere [tex]= 4\pi r^2[/tex]

                                                            [tex]= 4\times 3.14\times (10 \times 10^{-2})^2 \\\\= 12.56\times 10^{-2} m^2[/tex]

Area of the hole ( both side ) [tex]= 2\times \pi r^2[/tex]

                                               [tex]= 2\times 3.14 \times (10^-^3)^2\\= 6.28 \times 10^-^6 m^2[/tex]

According to Gauss's theorem, the flow from a particular charge in the center is given by

 [tex]\phi= \frac{10\times10^-^6}{8.85\times 10^-^1^2}\\\\\phi=1.13\times10^6[/tex]

This flux flows through the surface of the sphere, so the flux  per unit area which is given by

[tex]= \frac{ 1.13\times 10^6 }{ 12.56\times 10^-^2} \\\\= 8.99 \times 10^6 \ weber / m^2[/tex]

Flux through area of hole is given by :

[tex]= 8.99\times10^6 \times6.28 \times 10^-^6\\ = 56.45 \ weber[/tex]

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