O LINEAR EQUATIONS AND INEQUALITIES
Finding a percentage of a total amount: Real-world situations
Das
A file that is 244 megabytes is being downloaded. If the download is 18.5% complete, how many megabytes have been downloaded? Round your answer to the
nearest tenth.
megabytes

The number of cashews in the can are 52.

Here, we are given that the ratio of walnuts to peanuts in a can of mixed nuts is 3 to 5.

⇒ walnuts : peanuts = 3 : 5

The number of walnuts in the packet are = 18

⇒ 18 : peanuts = 3 : 5

18/ peanuts = 3/5

peanuts = (5/3) × 18

peanuts = 30

Now, we know that the total number of nuts = 100

⇒ cashews + walnuts + peanuts = 100

cashews + 18 + 30 = 100

cashews + 48 = 100

cashews = 100 - 48

cashews = 52

Thus, the number of cashews in the can are 52.

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Answer: no she dosen't

Step-by-step explanation:

If you were to add up all three numbers

49.95+19.95+21.95=91.85

Which means she is $1.85 short to buy all of the items

The inequality for 2/3 I 4v + 6 I - 2 ≤ 10 is -6≤v≤3.

Given the inequality is 2/3 I 4v + 6 I - 2 ≤ 10

Isolate the variable by dividing each side by factors that don't contain the variable.

2/3 I 4v + 6 I  ≤ 10 +2

arrange the constants on the right side.

2/3 I4v + 6I ≤ 12

multiply the terms.

8v + 12/3 ≤ 12    or -8v - 12/3 ≤ 12

8v + 12 ≤ 36       or  -8v -12 ≤ 36

8v ≤ 36 -12         or  -8v ≤ 36 + 12

8v ≤ 24               or   -8v ≤ 48

v ≤ 24/8              or    v ≤ 48/8

v ≤ 3                   or    v≥-6

therefore, -6 ≤ v ≤ 3.

Hence the inequality is -6 ≤ v ≤ 3.

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An expression in math is a sentence with a minimum of two numbers or variables and at least one math operation. a) R=R is a reflexive property.

b) 5-P  Substitution Property, c) If 3 = x and y = -2 Then the expression y = x + b can be written as -2 = 3 + b is a substitution property, d) a=4 Then it can be said that a = b e)DEIR then DF = LR Segment Addition Postulate

f)VW - WY - VT is a Transitive Property

What is Expression?

An expression in math is a sentence with a minimum of two numbers or variables and at least one math operation.

We have match the given expression with an appropriate property.

a) R=R is a reflexive property.

b) 5-P  Substitution Property

c) If 3 = x and y = -2 Then the expression y = x + b can be written as -2 = 3 + b is a substitution property

d) a=4 Then it can be said that a = b  

e)DEIR then DF = LR Segment Addition Postulate

f)VW - WY - VT is a Transitive Property

Therefore .a) R=R is a reflexive property. b) 5-P  Substitution Property, c) If 3 = x and y = -2 Then the expression y = x + b can be written as -2 = 3 + b is a substitution property, d) a=4 Then it can be said that a = b e)DEIR then DF = LR Segment Addition Postulate f)VW - WY - VT is a Transitive Property.

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Answer:

24/15

Step-by-step explanation:

120 : 75 =

120/5 : 75/5 =

24 : 15 =

24/15

Answer:

8 : 5 or 8/5

Step-by-step explanation:

starts as 120 : 75

divide both by 5

= 24 : 15

divide both by 3

= 8 : 5 or 8/5

you just need to get them down to the smallest they can. in this case it is 8 and 5. for every 8 $10 bills there are, you have 5 $20 bills.

Answer:
(-10,-10)Step-by-step

explanation:

Yes 9x-9y=03x-4y=10In

elimination, we want both equations to have the same form and like terms to be lined up.  We have that.  We also need one of the columns with variables to contain opposites or same terms. Neither one of our columns with the variables contain this.  We can do a multiplication to the second equation so that the first terms of each are either opposites or sames. It doesn't matter which.  I like opposites because you just add the equations together. So I'm going to multiply the second equation by -3.I will rewrite the system with that manipulation:9x-9y=0-9x+12y=-30----------------------Add them up!0+3y=-30     3y=-30       y=-10So now once you find a variable, plug into either equation to find the other one.I'm going to use 9x-9y=0 where y=-10.So we are going to solve for x now.9x-9y=0 where y=-10.9x-9(-10)=0  where I plugged in -10 for y.9x+90=0  where I simplified -9(-10) as +90.9x     =-90 where I subtracted 90 on both sides.x=       -10 where I divided both sides by 9.The solution is (x,y)=(-10,-10)

Answer:

f(4)=9

Step-by-step explanation:

The given function is

F(x)=3x-3

so,

f(4)=3*4-3

f(4)=12-3

f(4)=9

putting 4 in place of x we get answer of the question.

Answer:

1/4 gallon

Step-by-step explanation:

Just multiply the numerator and denominator of the given rate by 2:

2(1/8) gallon 1/4 gallon

------------------ = ---------------- = 1/4 per gallon

2(1/2) hour 1 hour

Answer:

A

Step-by-step explanation:

1 Factor out the common term ss.

\frac{s(25{s}^{2}+12)}{5s}

5s

s(25s

2

+12)

​

2 Cancel s.

\frac{25{s}^{2}+12}{5}

5

25s

2

+12

​

The plane where the point is located and which has a fixed z coordinate (1,2,3) is y=2x.

Given that,

The plane where the point is located and which has a fixed z- coordinate (1,2,3).

The plane has the point (1, 2, 3) and the z-axis.

Any plane that has the z-axis is of the type that (0,0,1)

Therefore, By cross product of the two points we can find the equation.

Let take a matrix with x,y and z

We can se in the picture there is a matrix.

We now find the determination of that matrix .

determination means the scalar value calculated for a given square matrix is the determinant of a matrix. The determinant is a concept in linear algebra, and its components are square matrixes. It can be viewed as the matrix transformation's scaling factor. useful for performing calculus operations, computing the inverse of a matrix, and solving systems of linear equations.

-2x+y=0

y=2x

Therefore, The plane where the point is located and which has a fixed z coordinate (1,2,3) is y=2x.

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Answer:

help this yuo what is yuor problem

The value of P'(t) will be , P'(t) = -10t + 75 and value of P'(7) will be equal to 5 and rate of change of price will be $5 thousands per year in dollars.

It is given that median home price is represented by P(t) = -5t² + 75t - 30.

We have to find out the values of P'(t) and P'(7).

What is differentiation ?

Differentiation is a method in which the function's rate of change compared to the rate of change of the independent variable is calculated.

As per the question ;

The equation given is ;

P(t) = -5t² + 75t - 30

So ;

Differentiating the above equation with respect to t , we get ;

[tex]\frac{d}{dt}[/tex] (P(t)) = [tex]\frac{d}{dt}[/tex] ( -5t² + 75t - 30 )

[tex]\frac{d}{dt}[/tex] (P(t)) = P'(t) = -5 × 2 × t + 75

⇒ P'(t) = -10t + 75

And

The value of P'(7) will be ;

P'( t = 7) = -10 × 7 + 75

P'(7) = - 70 + 75

P'(7) = 5

Also ;

P(11) = 190

P(3) = 150

And

The rate of change of price will be ;

[tex]\frac{P(11) - P(3)}{11 - 3}[/tex]

= 190 - 150 / 8

= 40 / 8

= 5

Thus , the value of P'(t) will be , P'(t) = -10t + 75 and value of P'(7) will be equal to 5 and rate of change of price will be $5 thousands per year in dollars.

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The transformed function can be seen in the image below, and the rule is:

g(x)= x/3 + 7

Here we have the parent function, and we want to apply a translation of 7 units up and stretch it vertically by a scale factor of 3

First, we need to apply the translation, remember that a vertical translation of N units is written as:

g(x) = f(x) + N

If we want the translation to be upwards, then we need to use a positive value of N, so in this case we wil have:

g(x) = f(x) + 7

And now we apply a stretch of scale factor 3, this means that we need to divide the variable inside of the function by 3, so we get:

g(x) = f(x/3) + 7

This will give:

g(x)= x/3 + 7

Where we use the fact that f(x) = x

The graph of this function can be seen below.

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Answer:

[tex]10^{-4}[/tex]

Step-by-step explanation:

0.0001

1/10,000

1/[tex]10^{4}[/tex]

[tex]10^{-4}[/tex]

Answer:

25 spells

Step-by-step explanation:

each colored box is 5 spells so count by five to see how many spells Ginny casts

The number of spells is 25, that the spells Ginny casts.

Here, we have,

from the given information we get,

we have to find that number spells that the spells Ginny casts.

we have,

the tape diagram gives that,

the ratio of luna and ginny is:=>  4 : 5

so, let , Ginny casts = 5x spells

luna casts = 4x spells

now, we have,

ATQ, 4x+5x = 45

=> 9x= 45

=> x = 45/9

=> x = 5

so, we get,

Ginny casts = 5*5 spells

                    = 25 spells

Hence, The number of spells is 25, that the spells Ginny casts.

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Answer:2

Step-by-step explanation: x+1+2x=3x+1        3x+1=7        3x=7-1       x=6/3   x=2

hope it helps

Answer:

3

Step-by-step explanation:

x+1+2x=7

variables should be on the left and the whole number on the right.

something like this: x+2x=7-1

simplify the equation: 3x=6

find x: x= 6/3=2

so u know x is 2

then substitute the 2 into x. so 2+1 =3#

Your answer is three.

Answer:

Price per pound = $0.64

which means one pound of banana costs 0.64$.

so,If 1 pound costs 0.64$ then 6.7 pounds would cost:

1 pound = $0.64

6.7 pounds= 0.64× 6.7

that is equal to $4.288.

Step-by-step explanation:

Price per pound = $0.64

which means one pound of banana costs 0.64$.

so,If 1 pound costs 0.64$ then 6.7 pounds would cost:

1 pound = $0.64

6.7 pounds= 0.64× 6.7

that is equal to $4.288.

The price of an adult ticket is x= $10

What is mathematical expression?

A mathematical expression is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Let the adult ticket be x

Let the children ticket be y

first day,

1*x + 6*y = 52

x + 6y = 52   equation 1

second day,

1*x + 8*y = 66

x + 8y = 66   equation 2

Solving both the equations

Subtracting equation 2 -equation 1, we get

x + 8y - x - 6y = 66 - 52

2y = 14

y = 7

putting the value of y in equation 1, we get

x + 6*7 = 52

x = 52 - 42

x = 10

Therefore, price of an adult ticket is x= $10

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Answer:

length = 99 yards

Step-by-step explanation:

the perimeter (P) of a rectangle is calculated as

P = 2(l + w) ← l is the length and w the width

given  P = 356 and w = 79 , then

356 = 2(l + 79) ← divide both sides by 2

178 = l + 79 ( subtract 79 from both sides )

99 = l

the length of the field is 99 yards

it will be 7:8

Step-by-step explanation:

28/4 32/4

7 8

LCM can help us to compare the two of the given fractions. The correct option is A, -(3/4) < -(5/16).

The least common multiple that is divisible by both a and b is the smallest positive integer, lowest common multiple, or smallest common multiple of two numbers a and b, generally indicated by LCM.

Bring both the terms to the same denominator for easy comparison. Now, since the LCM of 4 and 16 is 16. Therefore, we can write the two of the fractions as,

-(3/4) = -(3×4)/(4×4) = -12/16

-(5/16) = -5/16

Further, we can write the comparison of the two fractions as,

-12/16 < -5/16

-(3/4) < -(5/16)

Hence, the correct option is A, -(3/4) < -(5/16).

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Answer:

x=is the number searched

we have to solve this equation:

(2/5)x=14

x=14*5/2=35

35

Step-by-step explanation:

Answer:

[tex]\textsf{Increasing function}: \quad \left[0, \dfrac{1}{16}\right)[/tex]

[tex]\textsf{Decreasing function}: \quad \left(\dfrac{1}{16}, \infty\right)[/tex]

Step-by-step explanation:

Given function:

[tex]f(x)=\sqrt{x}-2x[/tex]

As a negative number cannot be square rooted, the domain of the function is restricted to [0, ∞).

[tex]\textsf{A function is \textbf{increasing} when the \underline{gradient is positive}}\implies f'(x) > 0[/tex]

[tex]\textsf{A function is \textbf{decreasing} when the \underline{gradient is negative}} \implies f'(x) < 0[/tex]

Differentiating produces an algebraic expression for the gradient as a function of x.  Therefore, differentiate the given function:

[tex]\begin{aligned}f(x) & = \sqrt{x}-2x\\& = x^{\frac{1}{2}}-2x\\\implies f'(x) & = \dfrac{1}{2}x^{\left(\frac{1}{2}-1\right)}-2x^{(1-1)}\\ & = \dfrac{1}{2}x^{-\frac{1}{2}}-2x^0\\ & = \dfrac{1}{2\sqrt{x}}-2\end{aligned}[/tex]

Increasing function

To find the interval where f(x) is increasing, set the differentiated function to more than zero and solve for x:

[tex]\begin{aligned}f'(x) & > 0\\\implies \dfrac{1}{2\sqrt{x}}-2 & > 0\\\dfrac{1}{2\sqrt{x}} & > 2\\\ \dfrac{1}{2} & > 2\sqrt{x}\\\dfrac{1}{2 \cdot 2} & > \sqrt{x}\\ \dfrac{1}{4} & > \sqrt{x}\\ \sqrt{x} & < \dfrac{1}{4}\\\left(\sqrt{x}\right)^2 & < \left(\dfrac{1}{4}\right)^2\\ x & < \dfrac{1}{16}\end{aligned}[/tex]

As the domain is restricted, the function is increasing when:

[tex]\textsf{Solution}: \quad 0 \leq x < \dfrac{1}{16}[/tex]

[tex]\textsf{Interval notation}: \quad \left[0, \dfrac{1}{16}\right)[/tex]

Decreasing function

To find the interval where f(x) is decreasing, set the differentiated function to less than zero and solve for x:

[tex]\begin{aligned}f'(x) & < 0\\\implies \dfrac{1}{2\sqrt{x}}-2 & < 0\\\dfrac{1}{2\sqrt{x}} & < 2\\\ \dfrac{1}{2} & < 2\sqrt{x}\\\dfrac{1}{2 \cdot 2} & < \sqrt{x}\\ \dfrac{1}{4} & < \sqrt{x}\\ \sqrt{x} & > \dfrac{1}{4}\\\left(\sqrt{x}\right)^2 & > \left(\dfrac{1}{4}\right)^2\\ x & > \dfrac{1}{16}\end{aligned}[/tex]

Therefore, the function is decreasing when:

[tex]\textsf{Solution}: \quad x > \dfrac{1}{16}[/tex]

[tex]\textsf{Interval notation}: \quad \left(\dfrac{1}{16}, \infty\right)[/tex]

Note: The answer quoted in the original question is incorrect for the quoted function (please refer to the attached graph for proof).

Differentiation Rules

[tex]\boxed{\begin{minipage}{4.8 cm}\underline{Differentiating $ax^n$}\\\\If $y=ax^n$, then $\dfrac{\text{d}y}{\text{d}x}=nax^{n-1}$\\\end{minipage}}[/tex]

Answer:

B, J, C.

Collinear points means the points are on the same straight line, which means they have the same gradient. B, J, C are the only points on the sane straight line.

$829.08

Step-by-step explanation:

43,112 ÷ 52 = 829.08

Answer:

10-18i

Step-by-step explanation:

1(1-9i)+9(1-9i)

1-9i+9-9i

1+9-9i-9i

10-18i