Please help asap!!!!!! question 6(multiple choice worth 5 points) (order of operations mc) harry needs wood pieces to complete a project in woodshop class. he needs four pieces of wood that have a length of two and three fourths feet and five pieces of wood that are one and two thirds feet. what is the total amount of wood that harry will need for the project? four and four sevenths feet nineteen and one third feet four and two fifths feet one and two thirds feet

Answer:

−100x +10y+z

Step-by-step explanation:

I use the Expand Using Sum/Difference Formulas. When I plug in -100x + 10y +z it gives out the same thing.

The nth term of the sequence is 2n + 1

The formula known as the nth term allows us to locate any term in a series. The letter n stands for number. By changing the term number's value, we can create a series that uses the nth term (n).

The sequence 3,5,7,9.....

n =1

3 = 1 + 2

3 = 1 + (2×1)

n = 2

5 = 1 + 4

5 = 1 + (2×2)

n = 3

7 = 1 + 6

5 = 1 + (2×3)

n = 4

9 = 1 + 8

9 = 1 + (2×4)

9 = 1 + 8

Therefore, the expression for the Nth is 1+ 2n or 2n + 1

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KL = LM                         To find the measures of KL

8x-5 = 6x+3                

-6x      -6x                               8(4) - 5

___    ___                                32 - 5

2x - 5 = 3                                   27

   +5    +5

   __    __                        To find the measure of LM

2x = 8                                        6(4) + 3

---   ---                                         24 + 3

x = 4                                               27

Answer:

1.954

Step-by-step explanation:

4 is the thousandth and we wouldn’t round up because of 1

Answer: 1.954

1.9541 is to low to round up to the thousandths so it needs to be rounded down, giving the answer 1.954.

odd Answer:

make icecubes then drop them in hydrochloric acid

Step-by-step  Step-by-step  Step-by-step Step-by-step explanation

Answer:

-0.03

Step-by-step explanation:

[tex]3^{-3}=\frac{1}{3^3}\\=-\frac{1}{3^3}\\3^3=27\\=-\frac{1}{27}\\= -0.03[/tex]

Answer:

Part A

Plan 1

33

Plan 2

0.05x+16

0.05x+16=33

0.05x=17

17/0.05=340

341 calls would be enough.

Part B

AN easy way of doing this is by setting the equations equal to each other and then adding a variable to one side that would be the amount of calls made on plan B. Once you get rid of the initial price of 16 dollars, then you have 17 dollars to be set equal to plan B. You divide 17 by 0.05, which gives you 340, meaning that to make both plans equal to each other, you would have to make 340 calls. To make Plan 1 more economical, you would have to add 1 more call to set plan 2 0.05 cents more than Plan 2.

Step-by-step explanation:

An inverse function is one that reverses the action of another function.

The value of this function is y = 0.2.

Inverse operations are mathematical manipulations in which one operation reverses the action of the other, such as addition and subtraction, multiplication and division. In most cases, the inverse of a number is its reciprocal, i.e. [tex]x ^{- 1[/tex] = 1 / x. A number and its inverse (reciprocal) product equals one.

An inverse function is one that reverses the action of another function. A function g is the inverse of a function f if and only if y = f(x) and x = g. In other words, using f and then g is equivalent to doing nothing.

Let the given function be f(x) = 10x - 10

substitute the value of x = 0.2, then we get

f(0.2) = 10(0.2) - 10

simplifying the above equation be

f(0.2) = -8

y = 1/10(-8) +1

y = 0.2

Therefore, the value of y = 0.2.

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The percentage of decay for the exponential function: y = 104(2.05) x is 105%.

This equation represents exponential decay. Whenever the base is less than 1, the function represents decay. When the base is greater than 1, the function represents growth. In this case, the base is 2.05 which is 1.05 than 1, representing growth.

The formula for exponential decay is y=a(1-r)x.

r is the decay rate, expressed as a decimal.

In this case, r = 2.05 - 1 = 1.05 which represents 105%.

Therefore, the percentage of decay for the exponential function is 105%.

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Answer: A. 18.32

B. 20

C. 31.16

Step-by-step explanation:

2.29 times 8=18.32 dollars spent on goodie bags

160 divided by 8=20 dollars per hour

160+18.32=178.32

1209.48-178.32= 31.16 more than what was spent in parts a and b.

Answer:

see explanation

Step-by-step explanation:

calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 9, 31) and (x₂, y₂ ) = (15, - 41) ← 2 ordered pairs from the table

m = [tex]\frac{-41-31}{15-(-9)}[/tex] = [tex]\frac{-72}{15+9}[/tex] = [tex]\frac{-72}{24}[/tex] = - 3

the y- intercept is the value of g(x) when x = 0 , then from the table

y- intercept = 4

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept ) , then equation is

y = - 3x + 4

Answer:

Stop please. You use brainly for answering and asking questions.

Answer:$43.70

Step-by-step explanation:

120−54.67−13.49−8.14

=$43.70

Answer:

43.7

Step-by-step explanation:

120-54.67-13.49-8.14=43.7$

Answer:

0.0606060606 hope that's right if not I'm sorry

well, let's start like the crab, from the back, what would the amount be after 10 years, with a 10.5% annual rate, compounding annually of course.

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$750\\ r=rate\to 10.5\%\to \frac{10.5}{100}\dotfill &0.105\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &10 \end{cases} \\\\\\ A=750\left(1+\frac{0.105}{1}\right)^{1\cdot 10} \implies A=750(1.105)^{10}\implies \boxed{A \approx 2035.56}[/tex]

when will it double?  well, hmmm 750 doubled will be 1500, so

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$1500\\ P=\textit{original amount deposited}\dotfill &\$750\\ r=rate\to 10.5\%\to \frac{10.5}{100}\dotfill &0.105\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years \end{cases}[/tex]

[tex]1500=750\left(1+\frac{0.105}{1}\right)^{1\cdot t} \implies \cfrac{1500}{750}=(1.105)^t\implies 2=1.105^t \\\\\\ \log(2)=\log(1.105^t)\implies \log(2)=t\log(1.105) \\\\\\ \cfrac{\log(2)}{\log(1.105)}=t\implies 6.94\approx t\qquad \textit{about 6 years and 344 days}[/tex]

[tex]\begin{array}{llll} \textit{logarithm of factors} \\\\ \log_a(xy)\implies \log_a(x)+\log_a(y) \end{array} ~\hspace{4em} \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\cfrac{\log(2)}{2}+\cfrac{\log(4)}{3}\implies \cfrac{1}{2}\log(2)+\cfrac{1}{3}\log(4)\implies \log(2^{\frac{1}{2}})+\log(4^{\frac{1}{3}}) \\\\\\ \log(2^{\frac{1}{2}})+\log( ~~ (2^2)^{\frac{1}{3}} ~~ )\implies \log(2^{\frac{1}{2}})+\log(2^{\frac{2}{3}})\implies \log( ~~ 2^{\frac{1}{2}}\cdot 2^{\frac{2}{3}}~~) \\\\\\ \log( ~~ 2^{\frac{1}{2}+\frac{2}{3}} ~~ )\implies \log( ~~ 2^{\frac{3+4}{6}} ~~ )\implies \log (~~ 2^{\frac{7}{6}} ~~ )\implies {\LARGE \begin{array}{llll} \log(\sqrt[6]{128}) \end{array}}[/tex]

Based on the logical fallacy given by saying that they can either go to the amusement park or the library, the category is False dilemma.

A False dilemma is a logical fallacy where the speaker makes it seem as though there are no other options to be considered. The possibility of there being other options is therefore ignored.

In the above thought, the speaker says that they can either go to the amusement part or to the library. They then pick the library because the amusement park is too expensive.

This is a logical fallacy because there were other places they could have gone to that were not even considered.

In conclusion, the statement above that presents only two choices of places to go which were the library or the amusement park is an example of a false dilemma.

Rest of the question:

Identify the logical fallacy in the given statement.

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Approximately 1 gallon of 4 buckets will be needed to paint 90ft²of fences.

Formula used: N = kA / p

Given information:

So,

Determine k.

This is something you must work out with the units when solving for k.

Then, we get:

Now, solve for 90 ft² as follows:

So,

After rounding off, the answer will be 4 buckets of 1-gallon.

Therefore, approximately 1 gallon of 4 buckets will be needed to paint 90ft²of fences.

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Answer:

V= [tex]\sqrt[3]{36}[/tex]

Alternative Form

V≈3.301927

Evaluate

V

3

=36

Take the 3-th root on both sides of the equation

3

V

3

​

=

3

36

​

hope this helps now

Answer:

[tex]\mathrm{V=\sqrt[3]{36}}[/tex]

Step-by-step explanation:

Determine if 36 is a cube root

(a-b)•(a^2+ab+b^2) =

           a^3+a^2b+ab^2-ba^2-b^2a-b^3 =

           a^3+(a^2b-ba^2)+(ab^2-b^2a)-b^3 =

           a^3+0+0-b^3 =

           a^3-b^3

→ Using this checker, we can see that 36 is not a cube root because it cannot be factored as the difference between two perfect cubes.

Solve

v^3 - 36 = 0

v^3 = 36

v = ∛36

Two rational numbers between −7/2 and 4/3 are -20/6 and 7/6.

The two given rational numbers are −7/2 and 4/3.

A rational number is a number that is of the form p/q where p and q are integers and q is not equal to 0.

Now, two rational numbers between −7/2 and 4/3 can be found as follows:

Make denominators the same by taking the LCM of denominators.

LCM of 2 and 3 is 6.

Change denominators of both the rational numbers to 6 by multiplying the same number by numerator and denominator.

So, the rational numbers become −21/6 and 8/6.

Now, two rational numbers between −21/6 and 8/6 are -20/6 and 7/6.

Therefore, two rational numbers between −7/2 and 4/3 are -20/6 and 7/6.

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Answer:

Step-by-step explanation:

If you're solving for m:

3.18 + 2m = 12.7

-3.18            -3.18

Therefore making the new equation: 2m = 9.52

Divide- [tex]\frac{2m}{2\\} =\frac{9.52}{2}[/tex]

m = 4.76

The situations are classified as follows:

A claim is classified as science if there are experiments, or statistical tests, that prove the claim. In the cats experiment, there is evidence, hence it is science.

A claim is classified as biased when no experiments are made, the observations are made with the "eye test". One example is watching a NFL game and saying that the team that gets the most passing yards generally wins, without making statistical tests to verify this.

For this problem, the ad for the tire is based on bias, as there were no experiments, just the eye test.

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The area of the given rectangle is 6ft².

So, length 2 feet less than 3 times its width:

Then function: L = 3w - 2

Now, the area of the rectangle: l × w

Therefore, the area of the given rectangle is 6ft².

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Mackenzie can find the amount of flour used by using subtraction. She should subtract the flour left in the bag from 10 pounds.

Subtraction is one of the four basic mathematical operations.

It is used to calculate the amount left after a quantity is reduced.

When two variables are subtracted we use the following notation '-' .

Let us consider two variables x and y such that x is subtracted from y then mathematically it is denoted by y - x .

Mackenzie used some flour to bake bread. To calculate the amount she used from 10 pound bag , first she will have to find the amount of flour left in the bag.

Let a pounds of flour is left (a<10).

So to calculate the amount of flour used by her we simply subtract a from 10 pound.

Hence flour left is (10 - a) pounds.

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Answer:

the answer

Step-by-step explanation:

you got to write the answer in the blank boxes

Answer: 299^2 ft

Step-by-step explanation: Literally all you have to do is Base X Hight and you get the answer. The base is basically just the length.

Hope this helps!

The statement "As the value of x increases, the value of f(x) moves toward a constant." is true. Option  A

A relation between a collection of inputs and one output for each of those inputs is the definition of a function.

The given function is;

F(x)=(1/5)^x-2

The statement that is true of this function is as follows;

As the value of x increases, the value of f(x) moves toward a constant.

Therefore, the assertion that is true about this function is that when the value of x rises, the value of f(x) advances toward a constant. This is because of the way that the function works.

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CQ

Select the correct answer. Which statement is true of this function?

f(x)=(1/5)^x-2

A.

As the value of x increases, the value of f(x) moves toward a constant.

B.

The domain of the function is (-2, ∞).

C.

The function has a y-intercept at (0,-2).

D.

The function is increasing.

Express 64 as a product of its prime factors. The indices rule states

a^-n= 1/a^n. Apply the power rule (a^m)^-n= a^(-mn).

64 = 2x2x2x2x2x2 = 2^6

(1/2^6) = 2^-6

2^(-6x-1/6) = 2^(6x1/6) = 2^1

2^1 = 2

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Answer:

(2, 1 )

Step-by-step explanation:

2x + 3y = 7 → (1)

3x + 2y = 8 → (2)

multiplying (1) by 3 and (2) by - 2 and adding will eliminate x

6x + 9y = 21 → (3)

- 6x - 4y = - 16 → (4)

add (3) and (4) term by term to eliminate x

0 + 5y = 5

5y = 5 ( divide both sides by 5 )

y = 1

substitute y = 1 into either of the 2 equations and solve for x

substituting into (1)

2x + 3(1) = 7

2x + 3 = 7 ( subtract 3 from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

solution is (2, 1 )

According to the question, to calculate the relationship function model of the given equations which are as follows:

[tex]x=13[/tex] and [tex]y=17[/tex]

And the condition is the function is inverse in nature that means they vary inversely. And it can be represented as:

Equation: [tex]y = \frac{k}{x}[/tex]

[tex]17 = \frac{k}{13}[/tex]

[tex]k = 221[/tex]

Substituting the values to get the final expression:

[tex]y = \frac{221}{x}[/tex]

[tex]xy = 221[/tex]

Substitute the value of 'k' in the original equation. And the final expression is: [tex]xy =221[/tex]

What is function?

In mathematics, function can be defined as an expression or the rule or the law. It defines the relationship between dependent variable and the independent variable.

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