Please help me with this question!!

Permutation P-values should never be zero: calculating exact P-values when permutations are randomly drawn

This is a research paper whose authors are Belinda Phipson , Gordon K Smyth,

Abstract:

Conclusions:

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Answer:

x = 35y/27

y = 27x/35

Answer:

k = -1/3

Step-by-step explanation:

1. Simplify by distributing

3k + 15 = -6k + 12

Move -6 onto the left side by adding 6k onto both sides =

9k + 15 = 12

Now subtract 15 on both sides=

9k = -3

Now divide both sides by 9=

k = -1/3

Answer:

k=-1/3

Step-by-step explanation:

3k+15=-6k+12

15-12=-6k-3k

3=-9k

k=-1/3

Quadratic equation for stream of water; (x-6)² = -36/5(y-5)

Using symmetry;

if (0,0) is taken as origin and maximum height is reached by stream at (6,5); the stream will strike the ground at (12,0);

Equation of a parabola whose mouth is open toward negative y- axis;

x² = -4ay

Parabola vertex shifted from (0,0) to (6,5);

(x-6)² = -4a(y-5);

Put x = 0, y = 0, as it lies on parabola;

36 = -4a(-5);

36 = 20a;

a = 36/20;

Quadratic equation for stream of water; (x-6)² = -36/5(y-5);

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Answer:

6 2/5 pages

Step-by-step explanation:

Since we know how much he can type in half an hour, for a full hour you simply add two of the same value:

3 1/5 + 3 1/5

3+3 = 6, and 1/5 + 1/5 = 2/5

So the final answer would be 6 2/5 pages

I hope this helps :)

Marissa says that lines a and d will eventually intersect is a wrong statement as they are skew lines. Therefore option D is correct.

A and D are both in different planes, skew lines are line that will never intersect because they are noncoplanar, meaning they are never in  the same plane. If they aren't in the same plane, they can't intersect.

Two or more lines that doesn't have any intersections but they are not parallel.

Skew lines are also called as agonic lines. Since two lines in a plane must be parallel or intersect ,skew lines can only exist  in three dimensions or more dimensions.

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Step-by-step explanation:

[tex] = \sqrt{a} \times \sqrt[3]{a} \\ = {a}^{ \frac{1}{2} } \times {a}^{ \frac{1}{3} } \\ = {a}^{ \frac{1}{3} + \frac{1}{2} } \\ = {a}^{ \frac{5}{6} } [/tex]

I CONVERTED THE TERMS TO BE IN A POWER FORM TO SOLVE THIS EASILY

AND USED THE LAW OF EXPONENT..MULTIPLYING POWERS OF THE SAME BASE WE KEEP ONE BASE AND ADD THE EXPONENTS.

Julie will make 3.5 litres of punch

Julie is making a punch for her birthday

She first pours 2 litres if ginger ale

She then adds 750 millilitres of grape juice

Convert 750 millilitres to litres

750/1000

= 0.75 × 2

= 1.5

Total number of litres= 1.5 + 2

= 3.5 litres

Hence Julie makes 3.5 litres of punch

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Height of the tree is 16ft

There is a tree and a wall.

height of the wall = 4ft

Base of the wall = 6ft

tanθ for wall = height of the wall/Base of the wall

                     =  4/6

                     = 2/3

Height of the tree be h

base of the tree = 24ft

tanθ for tree= h/24

tanθ for wall = tanθ for tree

2/3 = h/24

h=(2/3)(24)

 = 16ft

Height of the tree is 16ft.

Height, altitude, and elevation all refer to the vertical distance between something's top and bottom or between a base and something above it. Height is something measured vertically, whether it is high or low.

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A simple random sample is a subset of a statistical population in which each member of the subset has an equal probability of being chosen. A simple random sample is meant to be an unbiased representation of a group.

Random sampling, or probability sampling, is a sampling method that allows for the randomization of sample selection, i.e., each sample has the same probability as other samples to be selected to serve as a representation of an entire population.

Simple random sampling is the randomized selection of a small segment of individuals or members of a whole population. It provides each individual or member of a population with an equal and fair probability of being chosen. The simple random sampling method is one of the most convenient and simple sample selection techniques.

Simple random samples are determined by assigning sequential values to each item within a population, then randomly selecting those values.

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The relationship between the figure JKLM and it's image, J'K'L'M' following a dilation by a scale factor of 1 is that JKLM and J'K'L'M' have the same dimensions, and location

Scale factors are numbers that are used to multiply a quantity to scale it by a given rate.

Part A

In order to easily describe the relationship between the image J'K'L'M' and the original figure JKLM, the point J can be taken as the origin such that the image vertices are obtained by dilating the points on the original figure in their original direction relative to J using the specified scale factor.

The coordinates of the vertices of JKLM relative to J are;

J(0, 0), K(6, 0), L(6, -6), M(0, -6)

Distance of K from J = 6 - 0 = 6 units to the right of K

Therefore, using a scale factor of 1;

The distances of the vertices of square J'K'L'M' from point J are the same and in the same direction as the distances of the vertices of square JKLM from point J.

The vertices of J'K'L'M' using a scale factor of 1 are therefore located at the same coordinates as the vertices of square JKLM

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[tex] \large \bf\implies\frac{12}{61} [/tex]

[tex] \tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...[/tex]

We have to add 1 in numerator and -10 in denominator because

[tex] \tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...[Given][/tex]

[tex] \frac{8 \: + \: 1}{101 \: - \: 10} = \frac{9}{91} \\\\ \frac{9 + 1}{91 - 10} = \frac{10}{81} \\ \\ \frac{10 + 1}{81 - 10} = \frac{11}{71} \\ \\ \frac{11 + 1}{71 - 10} = \frac{12}{61} ...[/tex]

The difference is 1 in numerator so we add 1 and the difference is -10 in denominator so we subtract -10.

The coordinates of point D is (- 3, - 7).

A midpoint is a point that partitions a line segment in two parts of equal length. First, we must find the coordinates of point B by using the midpoint formula:

B(x, y) = 0.5 · A(x, y) + 0.5 · C(x, y)

B(x, y) = 0.5 · (- 9, - 4) + 0.5 · (- 1, 6)

B(x, y) = (- 4.5, - 2) + (- 0.5, 3)

B(x, y) = (- 5, 1)

And the location of point D is found by using the midpoint formula again:

E(x, y) = 0.5 · B(x, y) + 0.5 · D(x, y)

(- 4, - 3) = 0.5 · (- 5, 1) + 0.5 · D(x, y)

(- 4, - 3) = (- 2.5, 0.5) + 0.5 · D(x, y)

(- 8, - 6) = (- 5, 1) + D(x, y)

D(x, y) = (- 8, - 6) - (- 5, 1)

D(x, y) = (- 3, - 7)

The coordinates of point D is (- 3, - 7).

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Answer:

22,25,28,31

N=5

A1= 22

an= 35

22-34

d= 5-1

22+3=25

25+3=28

28+3=31

31+3=34

mwheheheheh

The addition of 113 and -56 using the number line gives the answer as 57.

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Step-by-step explanation:

Distribution first y=44-24+2

Simplify y=22

Hope this helps!

If you have any other questions feel free to ask!

Answer:

22

Step-by-step explanation:

Hey there!

To solve this, you need to follow PEMDAS

We do Parenthesis first:

44 - 24 + 2

Now we can simplify:

20 + 2

22

the domain of the graphed function is D: [-5, 3]

For a function f(x), we define the domain as the set of the inputs of the function.

So, to identify the domain, we need to look a the horizontal axis.

Doing that, we can see that the first value in the horizontal axis is x = -5, and the last value is x = 3.

Notice that in both cases we have solid dots, which means that these values do belong to the domain.

Then the domain of the graphed function is D: [-5, 3]

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Check the picture below.

Answer:

rational

Step-by-step explanation:

1 1/6 can also be expressed in the form 7/6

any number that can be expressed in a form of a/b is a rational number

He can make 5 pots of  macaroni and cheese.

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given:

Jason uses 3 1/2 cups of uncooked pasta.

He has= 18 1/2 cup of pasta

So, the numbers pots he can make

=18 1/2 ÷ 3 1/2

=37/2 ÷ 7/2

=37/2*2/7

=37/7

=5.28

= 5 pots

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1) 72 + 18 =90. Therefore the angles are complementary angles

2) Angles one and two are a pair of opposite angles made by two intersecting lines. Those are called vertical angles.

3) Those two are right angles, and two right angles add up to 180. So they are right angles and supplementary angles.

4) Adjacent angles

5) Vertical angles and supplementary (because both are right angles)

6) Right angles, supplementary, linear, adjacent angles.

7) Complementary and adjacent angles.

8) Angle of a straight line is 180. So 180-21 should equal x. x=159

9) As stated in number 2, vertical angles are congruent. x=129

10) 38 and x are complementary angles. (it shows a box on the angle formed by both of them, which means it is a right angle.) 90-38 = 52

11) Vertical angle rule. y = 93. The sum of 93, y, x, and z is 360, because the degree of a full circle is 360 degrees. so, 360-93-93 is 174. However, because of the vertical angle rule we will know that x=z. so 174/2 is 87.

x=87 and z=87

12) If you read the question, it states m∠PQR is 147, and ∠PQR is consisted of 119 and x. So, 147-119 is x. x=28

13) W and 34 are linear angles. Linear angles add up to 180 degrees. So, 180-34. w=146. Angle x is labeled with a box at the vertex of the angle. That indicates it is a right angle. x=90. The angle formed with 34 and z is labeled with a box at the vertex, indicating 34+z is 90. Therefore, 90-34=z. z=56. Finally, because angle x is linear with angle (y+z), we will know that y+z is equal to 90. Therefore, y+z=90, y+56=90, y=90-56, y=34

14) We are given that m∠AEC is 41. ∠AEC and ∠AED are linear angles. So, m∠AED = 180-41. m∠AEC=139

15) ∠DEF is a right angle, indicated by the box label at the vertex. ∠DEF and ∠CEF are linear angles, therefore m∠CEF = 180-90. m∠CEF=90

16) ∠DEB and ∠AEC are vertical angles. Therefore m∠AEC and m∠DEB are equal. ∠DEB=41

17) ∠DEB and ∠BEF form a right angle together. In question 16 we confirmed that m∠DEB is 41. Therefore m∠BEF is equal to 90-41.

m∠BEF=49

18) In question 15 we confirmed that m∠CEF is 90, and in question 17 we confirmed that m∠BEF is 49. So m∠CEB must be 90+49. m∠CEB=139

19) In question 15 we confirmed that m∠CEF is 90, and the direction states m∠AEC is 41. Therefore m∠AEF is 90+41. m∠AEF=131

20) Vertical angles are congruent. Therefore ∠PQR is the same degree measure as ∠SQT. m∠PQR=109

21) Complementary angles add up to 90. Therefore ∠2+∠3 = 90. And it is given that ∠2=24. Therefore ∠3 = 90-24.  ∠3=66

22) Supplementary angles add up to 180. Therefore ∠K+∠L= 180. And it is given that ∠K=56. Therefore ∠L = 180-56.  ∠L=124

Answer:729

Step-by-step explanation:someone else said it

Answer:

I’m not sureee

Step-by-step explanation:

Answer: x=48

i know the answer bc i just did it

For the given data set the lower quartile is 12 , the median is 15 and the upper quartile is 19 .

In the question ,

the data det is given as {11, 12, 12, 13, 14, 15, 16, 18, 19, 19, 20}

the median is the central value , that is 15.

For lower and upper quartile ,

the set is divided into two halves ,

the lower half is {11,12,12,13,14}

the median of the lower half (lower quartile) = 12

the upper half is {16,18,19,19,20}

the median of the upper half(upper quartile) = 19.

Therefore , for the given data set {11, 12, 12, 13, 14, 15, 16, 18, 19, 19, 20},  the lower quartile is 12 , the median is 15 and the upper quartile is 19 .

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The mean will increase by 1.6 miles.

It should be noted that from the information, in two weeks he plans on increasing the distance he runs on Monday and Tuesday by 1 mile, and the amount he runs on Friday, Saturday and Sunday by 2 miles.

The mean will be:

= (1 × 2) + (2 ×3) / 5

= (2 + 6)/5

= 8/5

= 1.6

The mean will increase by 1.6 miles.

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Answer:

x_2y=15

x_4y=_3

_6y=12

divide both sides by 6

y=_2

substitute y for x

In equation 1

x_2y=15

x_2 (_2)=15

x+4=15

x=15_4

x=11