Show your work on the following problems.
1.
An airplane accelerates down a run-way at 3.20 m/s? for 32.8 s until is finally lifts off the ground
Determine the distance traveled before take-off.
2.A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. De
acceleration of the car and the distance traveled.
3.
A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the
acceleration of the car and the distance traveled.
4.
A bullet leaves a rifle with a muzzle velocity of 521 m/s. While accelerating through the barrel of
the rifle, the bullet moves a distance of 0.840 m. Determine the acceleration of the bullet (assume a
uniform acceleration).

Answer: Option 4 (last graph)

Explanation:

1. Since you're driving at a constant speed, the line for your car will be linear. This rules out the first option.

2. This is a position time graph (x-t) graph. This means that to be moving forwards, there should be a positive slope. Option 3 can be eliminated as your car has a slope of 0. A slope of 0 on a position time graph shows an object at rest, not an object in motion.

3. The 2nd option can be ruled out as it represents that you are going faster than the other car. The steeper the slope = the faster the speed.

4. This ultimately leaves you with the last option as your final answer!

Answer:

6000 meters

Explanation:

Because 6kilometers is 6000 maters

The capacitor's energy becomes 0.5 J when the dielectrics have been inserted between its plates.

The quantity of energy held in the form of an electric charge in an electric device is referred to as capacitance.

Data provided

C = 10 mF = 0.01 F is the parallel-plate capacitor's capacitance.

V' = 20 V is the power supply's potential.

The material has a dielectric constant of 4.0.

First, let's determine the charge that the capacitor has stored:

[tex]C^{\prime}=\epsilon \times C[/tex]

Solving as,

[tex]\begin{aligned}&C^{\prime}=4.0 \times 0.01 \\&C^{\prime}=0.04 \mathrm{~F}\end{aligned}[/tex]

Now, the expression for the energy stored in the capacitor is,

[tex]U^{\prime}=\frac{q^2}{2 C^{\prime}}[/tex]

Hence

[tex]\begin{aligned}U^{\prime} &=\frac{0.2^2}{2 \times 0.04} \\U^{\prime} &=0.5 \mathrm{~J}\end{aligned}[/tex]

Thus, we may say that the capacitor's energy reserves are 0. 5J

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The eccentricity of Venus is = 0.0068. That is option C.

The orbital eccentricity is defined as the measurement that is used to show how an orbit deviates from the shape of a circle.

The Venus is one of the planets of the universe that is the second closest to the sun.

The Venus is one of the planets that has a small orbital eccentricity being 0.006772 which is approximately 0.0068. This means that it is closest to being circular in shape.

The planets with the largest orbital eccentricity is the planet Mercury with orbital eccentricity of 0.2056.

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Answer:  Problem 03.043 - Velocity-time graph The figure shows a plot of vx(for a car traveling in a straight line. Vx (m/s) 20 | 15 20 7(s) What is aav.x between t = 9.00 s and t = 110 s? 7 m/s2 What is Vav,x for the time interval from t= 9.00 s to r= 110 s? What is Vav.x for the interval t = 0 to t= 15.0 s? m/s What is the increase in the car's speed between 10.0 s and 15.0 s? m/s How far does the car travel from time t = 100 s to t = 170 s?

The answer is 03.043 but i dont know maybe my brain is incorrect but I got 03.043. :| hope it helped if its correct.

Explanation: Well, I havent done math in a while bc im not in school anymore so i forgot all that stuff :|

Amount of work done required to raise one end of the chain is 158.6 J

Work is said to be done when a  force act on a body and it displaced from its position.

It's unit is joule.

W = F × S

where

W = work done

F = force applied

S = displacement

Force acting on the chain with respect to the distance is given by

F = mgx / 10

m is mass

m = 90 kg

g is gravity (9.8 m/s2 for g.)

90× 9.8× x / 10

F = 88.2x Newton

To calculate the amount of work done.

[tex]W = \int\limits^f_i{F(x)} \, dx[/tex]

[tex]W = \int\limits^6_0 {F(x)} \, dx[/tex]

[tex]W = 88.2\int\limits^6_0 {x} \, dx[/tex]

[tex]W = 88.2 | \frac{x^2}{2}|^{6} _{0}[/tex]

W = 88.3( 6² - 0²)/2

W = 88.2 (36- 0) /2

W = 88.2 × 18

W = 158.6 J

Amount of work done required to raise one end of the chain is 158.6 J

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The car travels a distance of 820m in the first 34s after the light changes to green.

Acceleration, a = 2ms⁻²

Initial velocity, u = 0 ms⁻¹ (Since the car start from rest)

Final velocity, v = 20 ms⁻¹

From first equation of motion,

v - u = at

20 - 0 = 2 × t

20 = 2t

t = 10s

From second equation of motion,

S = ut + ¹/₂ at²

Distance travelled during 10s:

S₁ = 0 × 10 + ¹/₂ × (10)²

S₁ = 100m

Distance travelled for the remaining 36s:

S₂ = v × t

S₂ = 20 × 36

S₂ = 720m

Total distance travelled:

S = S₁ + S₂

S = 100 + 720

S = 820m

Therefore, the car travels a distance of 820m in the first 34s after the light changes to green.

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The friction force that is exerted on the car's rotating wheels causes an imbalanced force to be applied to the vehicle, which then accelerates. The center of the circle the car is turning is the target of both the unbalanced force and the acceleration. Your body, however, continues to move and is in motion.

An object's motion may vary if an imbalanced force is applied to it. The small car will alter speed, direction, or even halt if a heavier, faster toy car moves into its path or along its side. The small toy car is being subjected to a stronger force, which is why its motion has changed.

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The maximum height reached by the bullet is 12,500 m.

The velocity of the of the bullet at 10s is 600 m/s.

The velocity of the of the bullet at 20s is 700 m/s.

The velocity of the of the bullet at 60s is 1,700 m/s.

The time required for the object to move to maximum height is 50.5 seconds.

The height reacted by the bullet at time, t = 20 seconds is 12,000 m.

The height risen by the bullet when the first velocity is 40 m/s is 80 m.

The maximum height reached by the bullet is calculated as follows;

v² = u² - 2gh

v² = 2gh

h = v² /2g

h = (500²)/(2 x 10)

h = 12,500 m

v = u + at

when t = 10 s

v = 500 m/s  +  10(10)

v = 600 m/s

when the time, t = 20 seconds

v = 500 + 20(10)

v = 700 m/s

when the time, t = 60 s

v = 500 + 20(60)

v = 1,700 m/s

t = √(2h/g)

t = √(2 x 12,500 / 9.8)

t = 50.5 seconds

h = ut + ¹/₂gt²

h = (500 x 20)  +  ¹/₂(10)(20²)

h = 12,000 m

h = v² /2g

h = (40²)/(2 x 10)

h = 80 m

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If it takes 4.6 seconds for an object to fall a certain distance from rest on earth, then it would take 10.29 seconds to fall the same distance on planet X.

There are three equations of motion given by  Newton,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

Keep in mind that these calculations only apply to uniform acceleration.

As given in the problem, The acceleration due to gravity on planet X is one-fifth that on the surface of the earth. If it takes 4.6 s for an object to fall a certain distance from rest on earth, then we have to find how long would it take to fall the same distance on planet X,

By using the second equation of motion given by newton,

Let us suppose the acceleration due to gravity on the earth is 10 m / s²

S = ut + 1/2at²

  = 0 + 0.5×10×4.6²

  = 105.8 meters

The acceleration due to gravity on planet X = 2 meters / second

S = ut + 1/2at²

105.8 = 0 + 0.5×2×t²

t² = 105.8

t = 10.29 seconds

Thus, it would take 10.29 seconds to fall the same distance on planet X

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The magnitude of the force in newtons needed to supply 100 newton-meters of torque to the bolt is   359N.

The amount that encapsulates the force's power is known as its magnitude. Consider the following scenario: the force is 10 N in the east. The direction is indicated by "towards east," while the force is indicated by "10." Magnitude may be thought of as simply the "value" or "amount" of any physical quantity.

The force applied that applies torque is:

Fz = 100 N-m / .3m = 333.33 N

Find the angle:

theta = tan^-1 ( 5/2) = 68.19 degrees

Total force:

F= 333.33 / sin(68.19) = 359N

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One of the light spots will have to get 330 units brighter than the other for her to be able to tell the difference.

In the case of the first bulb, she noticed the difference when the right was 0.10 % brighter than the other one.

100  * 0.10 = 10

100 + 10 = 110

If we apply the same sense in the second case, one of the spots will have to be 0.10% brighter than the other.

300 * 0.10=30

300+30 = 330

In order to tell the difference, the other spot should be at 330 units of brightness.

The unit of brightness is Lumen. It is use to calculate the total amount of brightness emitted from a source over a unit of time.

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Answer:

you did not show a timeline luckly i did the the quiz it is the second timeline

Explanation:

Answer:

b

Explanation:

I did the test

Answer:

146.4 s

Explanation:

Distance / rate = time

205 m / 1.4 m/s =  146.4 s

By using uniform motion, the high up the slope will it strike is 730.62 m.

We need to know about uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

θ = 70⁰

vi = 200 m/s

x = 300 m

Find the initial velocity in x and y axis

vx = vi cosθ = 68.40 m/s

vy = vi sinθ = 187.94 m/s

Find the time taken to reach 300 m

vx = x / t

68.4 = 300 / t

t = 4.39 second

Find the time taken to reach maximum height

vt = vo + a . t

0 = vy - g . t

vy = gt

187.94 = 9.8 . t

t = 19.18 second

The motion of projectile is raising to maximum height, hence

s = vo . t + 1/2 . a . t²

h = vy . t - 1/2 . g . t²

h = 187.94 . 4.39 - 1/2 . 9.8 . 4.39²

h = 730.62 m

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The average velocity of Tim is 1 m/s.

Average velocity is the ratio of total displacement to total time.

The S.I unit of velocity is m/s.

To calculate the average velocity, we use the formula below.

Formula:

Where:

From the question

Given:

Substitute these values into equation 1

Hence, the average velocity of Tim is 1 m/s.

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According to the research, the correct option is weak interaction. A type of fundamental force is weak interaction.

They are those that cannot be explained based on other more basic ones, where the particles interact by virtue of some characteristic that they possess and according to physics, four fundamental forces are recognized at the quantum level:

In this sense, weak interaction is manifested in the transmission of particles where neutrinos and antineutrinos are emitted, without electrical charge and whose mass is very small or even zero, as in the case of the photon.

Therefore, we can conclude that according to the research, the correct option is weak interaction. A type of fundamental force is weak interaction.

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Copper sulfate is a salt that is made up of the copper ion and the sulfate ion further, the sulfate ion is the combination of the sulfur and the oxygen atom.

The chemical compound is a combination of two or more  either similar or dissimilar chemical elements

As given in the problem we have to compare copper sulfate with the elements that form copper sulfate,

The salt copper sulfate is composed of the copper ion and the sulfate ion. In addition, the sulfate ion is a mixture of sulfur and oxygen atoms.

The chemical formula for the copper sulfate is CuSO₄ which is made up of a Copper (Cu) atom, Sulphur (S)  atom, and Oxygen (O) atom.

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By calculating, a) frequency = 100 Hz b)wavelength = 4 cm  C )Speed = 400 cm/s d) Amplitude =  2 cm e)period = 0.01 s f)wave number  = 0.5π  g)angular velocity = 200π. ​

Given in question

Y = 2 sin π (0.5x - 200t)

Y = 2 sin (0.5πx - 200πt)

Comparing it with the standard form of a wave equation:

Y = Asin (kx - ωt) where

A= amplitude

K = wave number = 2π/λ where λ = wavelength

ω = Angular velocity = 2πf where f = frequency

We get

a) 2πf = 200π

    f = 100 Hz

b) 2π/λ =0.5π

   λ = 2π/0.5π

   λ = 4 cm

c) Speed v = ω/k

v = 200π/0.5π

v = 400 cm/s

d) A= amplitude = 2 cm

e)  period = 1/f = 0.01 s

f) K = wave number = 0.5π

g) ω = Angular velocity = 200π

Therefore, by comparing  a) frequency = 100 Hz b)wavelength = 4 cm  C )Speed = 400 cm/s d) Amplitude =  2 cm e)period = 0.01 s f)wave number  = 0.5π  g)angular velocity = 200π. ​

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If Abby runs for 8 seconds at this constant speed, Abby will travel 20 meters at this constant speed.

The Speed = 10/4 = 2.5 m/s

Distance = speed x time d=st

In 8 seconds, d=2.5 x 8 = 20 meters

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is traveling along a path. In other words, velocity is regarded as a vector, whereas speed is a scalar value.

Use the speed formula, s = d/t, which states that speed is equal to distance divided by time, to solve for speed or rate.

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The magnitude of the resulting forces applied to the nails if they are located at A and B is 64.44 N, at B and C is 120.83 N and at A and C is 56.86 N.

We know that,

C = F d

where,

C = Couple

F = Magnitude of resulting forces

d = Distance between two points

Given that,

C = 29 N m

[tex]d_{AB}[/tex] = 450 mm = 0.45 m

[tex]d_{BC}[/tex] = 240 mm = 0.24 m

F = C / d

The magnitude of the resulting forces applied to the nails if they are located at A and B is

F = 29 / [tex]d_{AB}[/tex] = 29 / 0.45

F = 64.44 N

The magnitude of the resulting forces applied to the nails if they are located at B and C is

F = 29 / [tex]d_{BC}[/tex]  = 29 / 0.24

F = 120.83 N

The magnitude of the resulting forces applied to the nails if they are located at A and C is

F = 29 / [tex]d_{AC}[/tex]  

[tex]d_{BC}[/tex]  = √ ( [tex]d_{AB}[/tex] )² + ( [tex]d_{BC}[/tex] )²

[tex]d_{BC}[/tex]  = √ ( 0.45² + 0.24² )

[tex]d_{BC}[/tex]  = 0.51 m

F = 29 / 0.51

F = 56.86 N

A Couple is two parallel forces of equal magnitude acting in opposite direction.

Therefore, the magnitude of the resulting forces applied to the nails if they are located at

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The amount of metal in a closed cylindrical can that is 10 cm high and 4 cm in diameter if the metal on the top and the bottom is 0.1 cm thick and the metal on the sides is 0.05 cm thick is 8.8 cm.

The formula for calculating the volume of a cylinder is given below.

V = πr^2 h

Get the differential of the volume as shown:

dV = V/ h dh + V / r dr

V/ h = πr^2

V/ h  = 2  πr h

Now, the differential becomes

dV =  πr^2dh +  2πrh dr

Given the following parameters i.e. diameter and height

dh = 0.1 + 0.1 = 0.2 cm

dr = 0.05 cm

h = 10 cm

d = 4 cm  

r = 2cm

Substituting the values in the above equation, we get

dV = 3.14(2)^2(0.2)  + 2(3.14)(2)(10)(0.05)

dV = 2.512 + 6.28

dV = 8.792 cm

dV = 8.8 cm

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The exit area of the nozzle is 0.000861 m² which is calculated using ideal gas equation.

Velocity = 280 m/s

Rate = 2.5 kg/s

Pressure = 2 MPa

Temperature = 400°C

Using equation of Ideal gas

PV= RT

V= RT/P

V= 0.0965 [tex]m^{3}[/tex]/ kg

Using equation of continuity

(dm/dt) = [tex]A_{1}[/tex]v/V

[tex]A_{1}[/tex]= 0.000861 [tex]m^{2}[/tex].

A theoretical gas known as an ideal gas is made up of several randomly moving point particles with no interparticle interactions. Because it abides by the ideal gas law, a condensed equation of state, and is amenable to statistical mechanics analysis, the ideal gas concept is helpful.

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D. The distance traveled by the baseball during the given time is 62.32 m.

The distance traveled by the baseball is calculated as follows;

s = vt - ¹/₂gt²

where;

The given parameters;

v, initial velocity of the baseball = 85 mph = 38 m/s

g is acceleration due to gravity = 9.8 m/s²

t is the time of motion, = 5.4 seconds

Substitute the given parameters and solve for the distance travelled by the baseball as shown below.

s = (38 m/s)(5.4 s) - ¹/₂(9.8 m/s²)(5.4 s)²

s = 205.2 - 142.88

s = 62.32 m

Thus, the distance traveled by the baseball during the given time is 62.32 m.

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The speed at which the driver must drive for the remaining time to complete the trip in the usual time is 61.25 miles per hour.

The total distance the driver should cover is 500 miles and this should be completed in 9 hours.

Based on the information provided, the regular speed is:

However, we know today he has covered 110 miles and he is 20 minutes late. This means, there are 390 miles to cover and the remaining time is 6.7 hours.

Based on this, let's calculate the new speed:

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Bob and Carol are both observing the moon at exactly the same time. However, bob is in Miami and carol is in Los Angeles. Bob observes the moon in the first quarter phase. Carl will also observe the moon in the first quarter phase.

The moon cycle consists of four primary and secondary phases.

The four primary phases are New Moon, First Quarter Phase , Full Moon, and the Last Quarter.

During the new moon and full moon periods, there are definite chances of solar and lunar eclipses.

The secondary phases of the moon are waxing crescent, waxing gibbous, waning gibbous, and waning crescent.

In the southern hemisphere and northern hemisphere, people observe the same phases of the moon.

As Miami and Los Angeles are in the southern hemisphere i.e. south of the equator, therefore, people living in that hemisphere will observe the moon in the same phases.  Thus Bob and Carol will also observe the moon in the first quarter phase from different cities.

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The time spent in air by the ball is 2.04 seconds.

The maximum height reached by the ball is 20.41 m.

The time of motion of the ball is calculated as follows;

v = u - gt

where;

0 = u - gt

gt = u

t = u/g

given;

t = (20) / 9.8

t = 2.04 s

The maximum height reached by the ball is calculated as follows;

v² = u² - 2gh

0 = u² - 2gh

2gh = u²

h = u²/2g

h = (20²) / (2 x 9.8)

h = 20.41 m

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The amount of gravitational potential energy lost when a pound of water falls from the top of the falls to the bottom is 233.55 Joules.

The gravitational potential energy of a body is due to virtue of its position. A body of mass 'm' at height 'h' is given by -

P.E. = mgh

Given in the is Niagara falls which 170 feet tall. A pound of water falls from the top of the falls to the bottom of the fall. From this we can write -

Height of Niagra falls = 170 feet tall = 51.81 m

Mass of water = 1 pound = 0.46kg

Assume that the potential energy of the pound of water at 170 feet tall is (P[1]) and that at the bottom is (P[2]).

Now, at the top of falls, the potential energy of 1 pound of water = P[1] =

m x g x h = 0.46 x 9.8 x 51.81 = 233.55 J

At the bottom of the falls -

P[2] = 0

The amount of gravitational potential energy lost =  P[1]  -  P[2] =

233.55 - 0 = 233.55 joules.

Therefore, the amount of gravitational potential energy lost when a pound of water falls from the top of the falls to the bottom is 233.55 Joules.

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Answer:  The difference is in how the carrier wave is modulated, or altered

Explanation:

With AM radio, the amplitude, or overall strength, of the signal is varied to incorporate the sound information. With FM, the frequency (the number of times each second that the current changes direction) of the carrier signal is varied

couldnt read that so gave my input hope it helps or is closly related to one of the answers

Answer: C. FM radio waves carry more energy than AM radio waves. This is supported by the fact that FM radio waves have a shorter wavelength compared to AM radio waves.

Explanation: