Study the red pre-image and the associated blue dilation image. The center of dilation is (2, 2). What is the scale factor of the dilation? 1/3 StartFragment, 1/3, 8 StartFragment, 8, 12 StartFragment, 12, 3

Answer:

x = 84

Step-by-step explanation:

-12(x+12) + 1177 = 10 + 15

-12x - 144 + 1177 = 25

1033 = 25 + 12x

1008 = 12x

x = 84

Answer: -119 feet relative to the surface of the water.

Step-by-step explanation:

Shark Depth ( x ) + Distance from Shark and Diver ( 38 ) = Divers position (-157)
x = -119

The diver is at -157 feet relative to the surface. The shark is swimming 38 feet above the diver, making its position -119 feet relative to the surface.

Given that,

Diver's depth: -157 feet (relative to the surface of the water)

Shark's position: 38 feet above the diver

The question asks for the position of the shark relative to the surface of the water.

The position of the shark can be determined by adding the distance above the diver to the depth of the diver.

So, the position of the shark would be:

-157 feet (diver's depth) + 38 feet (distance above the diver) = -119 feet relative to the surface of the water.

Hence,

The shark is located at -119 feet relative to the surface of the water.

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Answer: (FINDING THE PRODUCT)

Exact form:

-3/16

Decimal form:

-0.1875

Step-by-step explanation:

<3

Answer:

13/40

Please mark my answer as the brainliest, that would mean a lot to me

Step-by-step explanation:

5/8 - 3/10

50/80 - 24/80

26/80

13/40

Answer:

Step-by-step explanation:

more taking a shower you use almost 3 gallons per a shower

Answer:

the length of her garden will have to be 5.5ft

22÷4=5.5

Answer: Answer choice 'B'

Step-by-step explanation:

4.00 + 0.75 + 0.40 + 0.03 = $5.18. This is Jill's amount.

3.00 + 0.40 + 0.02 = $3.42. This is Mark's amount.

To find out how much more money Jill has in comparison to how much mark has, we need to subtract Jill's money by Mark's money ($5.18 - $3.42)

if done correctly, your answer should be $1.76 (answer 'B')

The cutoff score is  mathematically given as

x_n=70.32 (cutoff)

This is further explained below.

Generally, the equation for is  mathematically given as

[tex]&P\left(X > x_0\right)=0.15 \Rightarrow P\left(X < x_0\right)=0.85 \\[/tex]

[tex]&\Rightarrow P\left(\frac{X-\mu}{\sigma} < \frac{x_0-\mu}{\sigma}\right)=0.85 \\[/tex]

[tex]&\Rightarrow P\left(Z < \frac{x_0-\mu}{\sigma}\right)=0.85 \\\\&\Rightarrow \frac{x_0-\mu}{\sigma}=\text { invNorm }(0.85) \\\\&\Rightarrow x_0=\mu+\sigma \times \text { invNorm }(0.85)[/tex]

Use z-table to get inv Norm() = 1.04

x_0=62+8 *(1.04)=70.32

In conclusion, Top 15% are above x_n=70.32 (cutoff)

Clearly this is 85th percentile

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There were 733 general tickets sold and 255 reserved tickets.

Let the general admission = g

Let the reserved seats = r

Therefore, the appropriate equation will be:

g + r = 988

4g + 6.5r = 4589.50

From equation i r = 988 - g

4g + 6.5r = 4589.50

4g + 6.5(988 - g) = 4589.50

4g + 6422 - 6.5g = 4589.50

6.5g - 4g = 6422 - 4589.50

2.5g = 1832.50

g = 1832.50/2.5

g = 733

Since g + r = 988

r = 988 - 733

r = 255

Therefore, there were 733 general tickets sold and 255 reserved tickets.

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1.  'x' = -18/4

2. 'x' = -4/3

The equations are Not Equivalent.

An equation between two variables that gives a straight line when plotted on a graph. Or we can say,

A linear equation is defined as an equation that is written in the form of Ax+By=C. It is the combination of two variables and a constant value present in them.  

We have given

(x/3) - 2 = (5x/3) + 3

(5x/3) - (x/3) = -2 - 3

4x/3 = -6

  4x = -6 × 3

    x = -18/4

In first equation we got the value of x is -18/4.

Two systems of linear equations are equivalent if and only if they have the same set of solutions.  

To determine the equivalent of linear equation,

First, we need to find the value of "x" for each equation. If "x" is the same for both equations, then they are equivalent. If "x" is different then the equations are not equivalent.

We have equation

x(x + 1) = (x + 2)²

x² + x = x² + 4 + 4x        

(We have solved  (x + 2)² by using algebraic identity (a + b)² = a² + b² + 2ab.)

  4x - x = x²- x² - 4

       3x = -4  

         x = -4/3

In the second equation we got the value of x is -4/3.

Hence, as we can see it clearly that the value of x is not same in both equations so this is Not Equivalent.

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[tex]\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360} ~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=10\\ \theta =85 \end{cases}\implies \begin{array}{llll} A=\cfrac{(85)\pi (10)^2}{360} \\\\\\ A=\cfrac{425\pi }{18}\implies A\approx 74.18~cm^2 \end{array}[/tex]

Answer:

6.8%

Step-by-step explanation:

[tex]\frac{21447.20}{315400}[/tex]  When you divide this, you get 0.068.  This is in decimal form.  To change to a percent move the decimal to places to the right 6.8%

Answer: (-1.5, 0)

Step-by-step explanation:

Use the midpoint formula, [tex](\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})[/tex]. Plug in the points into the equation to get [tex](\frac{-5+2}{2},\frac{5-5}{2})[/tex] = (-1.5, 0)

Answer:

78 dollars

Step-by-step explanation:

9.75 multiplied by 8 is 78.

There is a 96.37% probability that the company will find 2 or more defective products.

There is a 2.08% probability that the company will find 4 or more defective products.

There is a 0.02% probability that the company will find 5 or more defective products. So company will give profit.

There are only two possible outcomes for each product: either it is defective or it is not. The binomial distribution is used to answer this question because each product's defect probability is independent of all other products.

Binomial probability distribution

The probability of precisely x successes on n repeated trials is known as the binomial probability.

[tex]P_x = \;^nC_r.p^x.q^{n-x}[/tex]

Where,

Px = binomial probability,

 [tex]\;^nC_r =[/tex] number of combination

p = probability of success on a single trial

q = probability of failure on a single trial = (1 - p)

n = number of trials

x = number of times for a specific outcome within n trials

So, from question,

1) The probability that, 2 or fewer defective products is;

P(X≤2) = P(X=0) +  P(X=1)+ P(X=2) -----------------(1)

So,

[tex]P_x = \;^nC_r.p^x.q^{n-x}[/tex]

P(X=0) = [tex]\;^{20}C_0.p^0.q^{20-0}[/tex] =  [tex]\; 1.(1-p)^{20-0}[/tex] = (1-0.037)²⁰ = (0.963)²⁰ =  0.4704

P(X=1) = [tex]\;^{20}C_1.p^1.q^{20-1}[/tex] =  [tex]\; 20.(0.037).(0.963)^{19}[/tex]  = 0.3614

P(X=2) = [tex]\;^{20}C_2.p^2.q^{20-2}[/tex] =  [tex]\;190\times(0.037)^2\times(0.963)^{18}[/tex] = 0.1319

Now, putting the all values in equation (1)

P(X≤2) = P(X=0) +  P(X=1)+ P(X=2) -----------------(1)

           = 0.4704 + 0.3614 + 0.1319

P(X≤2) = 0.9637 = 96.37%

There is a 96.37% probability that the company will find 2 or more defective products.

2)

1.23% are defective means p = 0.0123

The probability that find 4 or more defective products are;

 P(X≤4) = 1 - P(X< 4) -----------(2)

 P(X< 4) = P(X=0) + P(X=1)+ P(X=2) + P(X=3)-----------------(3)

So,

P(X=0) =  = [tex]\;^{20}C_0.p^0.q^{20-0}[/tex] =  [tex]\; (0.9877)^{20}[/tex] = 0.7807

P(X=1) = [tex]\;^{20}C_1.p^1.(1-p)^{20-1}[/tex] =  [tex]20\times (0.0123)\times (0.9877)^{19}[/tex] = 0.1944

P(X=2) = [tex]\;^{20}C_2.p^2.(1-p)^{20-2}[/tex] =  [tex]190\times (0.0123)^2\times (0.9877)^{18}[/tex] = 0.0024

P(X=3) = [tex]\;^{20}C_3.p^3.(1-p)^{20-3}[/tex] =  [tex]1140\times (0.0123)^3\times (0.9877)^{18}[/tex] = 0.0017

So,

P(X< 4) = 0.7807+0.1944+0.0024+0.0017 =0.9792

 P(X≤4) = 1 - P(X< 4) = 1 - 0.9792 = 0.0208 = 2.08%

There is a 2.08% probability that the company will find 4 or more defective products.

3)

1.28% are defective means p = 0.0128

The probability that find 5 or more defective products are;

 P(X≤5) = 1 - P(X< 5) -----------(4)

 P(X< 5) = P(X=0) + P(X=1)+ P(X=2) + P(X=3)+ P(X=4)-----------------(5)

So,

P(X=0) =  = [tex]\;^{20}C_0.p^0.q^{20-0}[/tex] =  [tex]\; (0.9872)^{20}[/tex] = 0.7728

P(X=1) = [tex]\;^{20}C_1.p^1.(1-p)^{20-1}[/tex] =  [tex]20\times (0.0128)\times (0.9872)^{19}[/tex] = 0.2004

P(X=2) = [tex]\;^{20}C_2.p^2.(1-p)^{20-2}[/tex] =  [tex]190\times (0.0128)^2\times (0.9872)^{18}[/tex] = 0.0246

P(X=3) = [tex]\;^{20}C_3.p^3.(1-p)^{20-3}[/tex] =  [tex]1140\times (0.0128)^3\times (0.9872)^{18}[/tex] = 0.0019

P(X=4) = [tex]\;^{20}C_4.p^4.(1-p)^{20-4}[/tex] =  [tex]4845 \times (0.0128)^3\times (0.9872)^{18}[/tex] = 0.0001

So,

  P(X< 5) = 0.7728+0.2004+0.0246+0.0019+0.0001 = 0.9998

  P(X≤5) = 1 - P(X< 5) = 1 - 0.9998 = 0.0002 = 0.02%

There is a 0.02% probability that the company will find 5 or more defective products. So company will give profit.

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Answer:

You will translate A up until it is equal with A', then you will reflect the figure over the line of symmetry that will be half way between line segments CD and C'D'

Step-by-step explanation:

I am not sure if the polygon is drawn on a coordinate plane.  I cannot see any horizontal or vertical lines to tell you exactly how many units to move up.

The slope of the equation is -7. Then the slope of the perpendicular line will be 1/7.

Let the equation of the line be y = mx + c. Then the equation of the perpendicular line that is perpendicular to the line y = mx + c is given as y = -(1/m) + d. If the slope of the line is m, then the slope of the perpendicular line will be negative 1/m.

The equation of the line is given as,

y = - 7x

The slope of the equation is -7. Then the slope of the perpendicular line will be

⇒ -(1/(-7))

⇒ 1/7

The slope of the equation is -7. Then the slope of the perpendicular line will be 1/7.

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The answer is (2) 2f-5=86; I hope- :\

Answer:

Mathematics shaping the modern world.

The slope of  P=(-4,-1) Q=(-3,-3) is -2.

Given,

 P=(-4,-1)

Q=(-3,-3)

The  slope  between two points   P=(x₁, y₁)

Q=(x₂ ,y₂)

slope = (y₂-y₁)/(x₂-x₁)

So slope between  P=(-4,-1)   Q=(-3,-3) is

 [(-3)-(-1) ]/ [(-3)-(-4)]

=-2/1

=-2

A line's steepness and direction are measured by the line's slope. Without actually using a compass, determining the slope of lines in a coordinate plane can assist in forecasting whether the lines are parallel, perpendicular, or none at all.

Any two different points on a line may be used to compute the slope of any line. The ratio of "vertical change" to "horizontal change" between two separate locations on a line is calculated using the slope of a line formula.

The increase divided by the run, or the ratio of the rise to the run, is known as the line's slope. In the coordinate plane, it describes the slope of the line. Finding the slope between two separate locations and calculating the slope of a line are related tasks. In general, we require the values of any two separate coordinates of a line in order to determine its slope.

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The median is a better measure of center for the male's data, while the mean is a better for the female's data.

When we get data which can be compared relatively with each other, for finding quartiles, we arrange them in ascending or descending order.

Quartiles are then selected as 3 points such that they create four groups in the data, each groups approximately possessing 25% of the data.

(a) The IQR of the male's data

From the given male's boxplot, we have the following data elements;

Upper quartile (Q3) = 14

Lower quartile (Q1) = 2

Then the IQR is calculated as:

IQR = Q3 - Q1

So, we have:

IQR = 14 - 2

IQR = 12

Hence, the IQR for the given males' data is 12

(b) The difference between the median values can be calculated as;

Median of male's data = 14

Median of female's data = 9

The difference (d) between the median values is;

d = 14 - 9

d = 5

Hence, the difference between the median values of each data set is 5

(c) The distribution of data

It is found that the median is a better measure of center for the male's data, while the mean is a better measure of center for the female's data.

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The median is a better measure of center for the male's data, while the mean is a better for the female's data.

What are quartiles?

When we get data which can be compared relatively with each other, for finding quartiles, we arrange them in ascending or descending order.

Quartiles are then selected as 3 points such that they create four groups in the data, each groups approximately possessing 25% of the data.

(a) The IQR of the male's data

From the given male's boxplot, we have the following data elements;

Upper quartile (Q3) = 14

Lower quartile (Q1) = 2

Then the IQR is calculated as:

IQR = Q3 - Q1

So, we have:

IQR = 14 - 2

IQR = 12

Hence, the IQR for the given males' data is 12

(b) The difference between the median values can be calculated as;

Median of male's data = 14

Median of female's data = 9

The difference (d) between the median values is;

d = 14 - 9

d = 5

Hence, the difference between the median values of each data set is 5

(c) The distribution of data

It is found that the median is a better measure of center for the male's data, while the mean is a better measure of center for the female's data.

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Answer:

Results of the Assembly elections in five States are indeed a shot in the arm for the Bharatiya Janata Party (BJP), which won in all four States where it was in power. The Hindu editorial captures the broad trends that emerge out of these results. Prime Minister Narendra Modi has said these results have sealed the outcome of the 2024 Lok Sabha elections too in the BJP’s favour. He said people have rejected caste and dynastic politics.

There is a real number whose product with every real number equals zero

a. Some real number has the property that its product with every real number equals 0.

b. There is a real number a such that the product of á and any real equals zero.

c. There is a real number á with the property that for every real number b, the product of a and b equals zero.

Answer:

[tex]\sf p =\sqrt{\dfrac{q+3}{5}}[/tex]

Step-by-step explanation:

To find p in terms of q, we have to isolate p.

[tex]\sf \sqrt{(5p^2 - 1)^2}-2 = q\\\\[/tex]

 5p² - 1 - 2 = q

      5p² - 3 = q

Add 3 to both sides,

              5p² = q + 3

Divide both sides by 5,

                [tex]\sf p^2 = \dfrac{q+3}{5}\\\\\text{Take square root,}\\\\p =\sqrt{\dfrac{q+3}{5}}[/tex]

From the graph of the piecewise function, we have that:

a) The range of the function is (-∞,7).

b) The vertical asymptote is of x = 2, and the horizontal asymptotes are y = -1 and y = -2.

c) The end behavior of the function is described as follows: As x -> -∞, y -> -2 and as x -> ∞, y -> -1.

A piecewise function is a function that has different definitions, depending on the input.

For this problem, the definitions of the function are given as follows:

The graph of the function is given at the end of the answer.

The range of the function is the set that contains all the output values of the function, and in a graph, this is the values of y.

Hence:

The range of the function is (-∞,7).

The asymptotes of the functions are the values of x for which the function is not defined. In this problem, the function is not defined for x = 2, hence the vertical asymptote is of x = 2.

The horizontal asymptotes are the values of the function when it goes to infinity, hence they are y = -2 and y = -1.

The end behavior is given by the limits of the function as it goes to infinity, being closely related to the horizontal asympotes.

Hence:

As x -> -∞, y -> -2 and as x -> ∞, y -> -1.

Please ignore the (60,1) point plotted on the graph, it should be (60,-1).

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The interval in which the function has positive average rate of change is x > √3

The function is given as

f(x) = x^3 - 9x

Differentiate the above function to determine the average rate of change

So, we have

f'(x) = 3x^2 - 9

Set the function to greater than 0

So, we have

3x^2 - 9 > 0

Add 9 to both sides

3x^2 > 9

Divide by 3

x^2 > 3

Take the square root of both sides

x > √3

Hence, the interval in which the function has positive average rate of change is x > √3

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Answer:

example of compound interest with solution

The value of the function f(3) is 1

The graph represents the given parameter

The value of f(3) implies that we calculate the value of the function when x = 3

From the graph, we have

f(x) = 1, when x = 3

This means that

f(3) = 1

The above is calculated by substituting 3 for x in the equation f(x) = 1

Hence,  the value of f(3) is 1

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