Suppose that the distance an aircraft travels along a runway before takeoff is given by ​, where d is measured in meters from the starting point and t is measured in seconds from the time the brakes are released. The aircraft will become airborne when its speed reaches. How long will it take to become​ airborne, and what distance will it travel in that​ time?.

Answer:

4 meters............

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Answer:

This equation for acceleration can be used to calculate the acceleration of an object when its mass and the net force acting on it are known.

so it wa The equation for the acceleration can be rewritten as to calculate the nets force acting on an object when its mass and acceleration

Answer: F=ma

Explanation:

Answer:

inside of our brain and the above the nose

The final speed of the ball when it accelerate uniformly at a rate of 3.52 m/s² for 23.3 m is 12.81 m/s.

Speed can be defined as the ratio of distance to time.

The S.I unit of speed is m/s.

To calculate the final speed of the ball, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the final speed of the ball is 12.81 m/s.

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Answer:

1.emit

2.absorb

3.reflect

not sure of the last one..hopes this helps : )

Explanation:

Emission nebulae emit light. Dark nebulae absorb visible radiation and reflect non-visible radiation.

Nebulae are distinguishable space regions of interstellar dust as well as a gas where stars are created.

Emission nebulae emit a kind of ultraviolet light from space that strikes ions in a nebula, driving the ions to emit visible light at different frequencies.

Dark nebulae form as a result of interstellar clouds with high dust concentrations and do not emit visible radiation. They usually absorb visible radiation and reflect non-visible radiation

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Answer:

[tex]speed = \frac{distance}{time}[/tex]

Explanation:

The equation linking speed, distance and time is speed equals to distance divided by time!

Hope this helps! Have a great day :)

Answer:

burns

Explanation:

Answer:

acceleration due to gravity is constant anywhere on the earth .its value is 9.8m/s²

Answer: decibels

Explanation:

The vertical magnetic field required to keep the rod moving at a constant speed is  IBd=[tex](u_{k} )[/tex]mg.

When describing the distribution of the magnetic force in the area surrounding and inside of a magnetic object, we use the metaphor of a magnetic field.

The most of us are somewhat familiar with common magnetic items and are aware that there may be forces present between them. We know that magnets have two poles, and that two magnets can be attracted (opposite poles) or repellent depending on how they are oriented (similar poles). We understand that this occurs in some area that surrounds a magnet. Described by the magnetic field, this area.

Mathematics uses a vector field to represent the magnetic field. An array of several vectors drawn on a grid can be used to directly plot this vector field.

Explanation:

Given mass of rod ,m

current carrying= I  

Separation between rails =d

The kinetic friction coefficient, uk

The force of magnetic field (F) is perp. to the magnetic field.

Let required magnetic field be B.

Now balancing forces in y-direction,

       N=mg

And. in x-direction,

       F=f

      IBd= [tex]u_{k}[/tex]N

      IBd=[tex](u_{k} )[/tex]mg

B=[tex]\frac{u_{k} mg}{Id}[/tex]

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Answer:

15 kg

Explanation:

mass=force÷acceleration

force: 75N

acceleration: 5 m/s^2

mass = 75 / 5

= 15 kg

If the answer made sense, please give me brainliest :)

Answer:

The average speed for the entire run is 12 km/h.

Explanation:      

The average speed is given by the following equation:

[tex] \overline{v} = \frac{d_{T}}{t_{T}} [/tex]

Where:

[tex]d_{T}[/tex]: is the total distance

[tex]t_{T}[/tex]: is the total time

If during the first hour, they ran a total of 13 kilometers and then, they ran 5.0 kilometers during the next half an hour we have:

[tex] d_{T} = 13 km + 5 km = 18 km [/tex]

[tex] t_{T} = 1 h + \frac{1}{2} h = 1.5 h [/tex]

Hence, the average speed is:

[tex] \overline{v} = \frac{d_{T}}{t_{T}} = \frac{18 km}{1.5 h} = 12 km/h [/tex]

Therefore, the average speed for the entire run is 12 km/h.

I hope it helps you!                                                                                      

No, it is not true that wet soil is easily picked up by the wind and carried away.

A strong wind rolls and lifts large volumes of soil and dust particles carrying them away and depositing them at some distant place.

In geology, we study that wind has the ability to carve the earth's surface through erosion and weathering processes.

However, wind can not pick up and carry only dry and lightweight particles of soil and dust.

It can not carry wet soil or heavy particles like rocks, wet sand, pebbles, and sediments from one place to another.

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Answer:

c

Explanation:

u only use 10% of your brain

Answer:

D

Explanation:

Isostatic equilibrium is the state of gravitational equilibrium between Earth 's crust and the mantle.

Answer:

i think 35 cubic meters of water

Explanation:

Answer:

Atoms and molecules

Explanation:

Answer:

C.

Explanation:

kase anjan na yung sagot ohh

The maximum magnetic field Bmax is 5.833 × 10⁻⁷ T

Given that a linearly polarized microwave of wavelength 1.50cm is directed along the positive x axis and the electric field vector has a maximum value of 175V/m and vibrates in the x y plane.

And Assuming the magnetic field component of the wave can be written in the form B=Bmax sin (k x-Ω t), we need to find the expression for the maximum magnetic field Bmax.

Since the microwave is an electromagnetic wave, we use the relationship between the maximum magnetic field and maximum electric field of an electromagnetic wave is given by c = E/B where

Making B subject of ther formula, we have

B = E/c

Given that

Substituting the values of the variables into the equation, we have

B = E/c

B = 175 V/m ÷ 3 × 10⁸ m/s

B = 58.33 × 10⁻⁸ T

B = 5.833 × 10⁻⁷ T

So, the maximum magnetic field Bmax is 5.833 × 10⁻⁷ T

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[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

In first 40 km, it travels with speed of 30 kmph

So, time taken in this span is :

[tex]\qquad \sf  \dashrightarrow \: \dfrac{40}{30} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{4}{3} \: \:hours[/tex]

And let's assume that it travels with uniform speed of x kmph during next 40 km

Now, time taken in this span of time is :

[tex]\qquad \sf  \dashrightarrow \: \dfrac{40}{x} \: \: kmph [/tex]

Now, we know the formula to find average velocity ~

[tex]\qquad \sf  \dashrightarrow \: v_{avg} = \dfrac{total \: \: distance \: \: covered}{total \: \: time \: \: taken} [/tex]

[tex]\qquad \sf  \dashrightarrow \: 40 = \dfrac{80}{ \frac{40}{30} + \frac{40}{x} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{40}{30} + \dfrac{4 0}{x} = \dfrac{80}{40} [/tex]

[tex]\qquad \sf  \dashrightarrow \: 40 \bigg( \dfrac{1}{30} + \dfrac{1}{ {x}^{} } \bigg) = \dfrac{80}{40} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{30} + \dfrac{1}{ {x}^{} } = \dfrac{2}{40} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{x} = \dfrac{1}{20} - \dfrac{1}{30} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{x} = \dfrac{3 - 2}{60} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{x} = \dfrac{1}{60} [/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 60 \: \: kmph[/tex]

So, for next 40 km, he need to maintain average speed of 60 kmph, in order to keep an average of 40 kmph for the whole trip ~

Answer: Northwest.

Explanation:

After the collision the second object which was at rest would change its direction and move towards the Northwest. The object in motion was coming from the east and traveling towards the west, where it deflects against a stationery object which changes its direction to southeast. And the object which was at rest moves toward the northwest.

R₁ = 28. 535 v  and  R₂  10.125 Ω  are the resistance are wired in series with a battery.

Let  R₁  and R₂ be the  two Resistance

resistance - which resists the flow of current.

R₁ - Resistance of 1st resistor

R₂ - Resistance of 2nd resistor

V = Voltage = 12V

I = O.31A ( in series)

I  = 1.6 A ( in parallel)

when two resistance connected in series then

Rs = R₁ + R₂

V = IRs = 12 /0.31 V

R₁+R₂ = 38.700Ω   (equation1.)

When two resistance connected in parallel then the value of R is.

    [tex]R_{p} =\frac { R_{1} R_{2}}{R_{1} + R_{2} }[/tex]

V = I Rp

V=  I (R₂ R₁ /R₁ +R₂)

R₁ R₂ = 290.25 Ω  

As we know

(R₁ - R₂ ) ² = (R₁ + R₂ ) ² - 4R1R2

Using above values we get,

 (R₁ - R₂ ) ²  = (38.70) ²  - 4x 290.25

 (R₁ - R₂ ) ²   = 336.69  Ω  

R₁ - R₂ = 18.34     (equation 2 )

Using equation 1 and 2 we get

R₁+ R₂ = 38.70 52

R₁ - R₂ = 18.34

R₁ = 28.535 Ω  

Using the value of  R₁ in equation 1 we get

R₂ = 38·700 -  28.535

R₂ = 10.125 Ω  

R₁ = 28. 535 v  and  R₂  10.125 Ω  are the resistors are wired in series with a battery.

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Answer:

Air slows down The fall of any object including a ball.

A limitation of modeling the effect of gravity on a falling object by using a ball dropped from different heights is: gravity varies slightly at different heights. Hence, option (C) is correct.

Gravity is a fundamental interaction in physics that causes all objects with mass or energy to attract one another. The electromagnetic force is 10³⁶ times stronger than gravity  the weak interaction is 10²⁹ times weaker than gravity, and gravity is by far the weakest of the four fundamental interactions.

As a result, it has no appreciable impact on subatomic particle level phenomena. However, at the macroscopic level, gravity is the most important interaction between things and governs the motion of planets, stars, galaxies, and even light.

As gravity is inversely proportional to the square of distance, it varies slightly at different heights. Hence, option (C) is correct.

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A copper wire that is 1 mm thick and 30 cm long is connected to a 1 v battery. (the resistivity of copper is 1.69 x 10-8 ω⋅m). The power is 154.82 W.

As we know the formula of Power:

P = V²/R ......(i)

Where,

P = power dissipated, V = voltage R = resistance

Now,

R = Lρ/A .....(ii)

Where,

L = length of the wire, A = cross-sectional area,  ρ = resistivity of the wire.

From eq (i) and eq(ii),

P = V²/(Lρ/A)

P = AV²/Lρ........ (iiI)

Here,

A = πd²/4, Where d = 1 mm

A = (3.14×0.001²/4) = 7.85×10⁻⁷ m²

Putting the value of A and the given values from the question in equation (iii).

P = (7.85×10⁻⁷×1²)/(0.3×1.69 x 10⁻⁸)

P = 154.82 W

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Answer:

.98m

Explanation:

Answer:

Given that the mass of the earth = 6 x 1024 kg, mass of the sun = 2 x 1030 kg, average distance between the two is 1.5 x 10-11 m and G = 6.67 x 10-11 Nm2kg-2

Explanation:

The Earth's magnetic field lines appear to emanate perpendicularly from the poles and go round along the Earth from the  South Pole to the North Pole. Therefore, the Earth's magnetic field is generally not parallel to the ground at every location. It is parallel to the earth at the equator near the earth's surface.

The Earth's magnetic field, also known as the geomagnetic field, is a magnetic field that extends from the Earth's interior into space, where it interacts with the solar wind, a stream of charged particles emanating from the Sun.

The magnetic field  varies in strength over the earth's surface. It is strongest at the poles and weakest at the equator.

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The total flux of electric field created by each balloon is 1.7×10^4N/C.

Consider two balloons of diameter 0.200m each with mass 1.00g hanging apart with 0.0500m separation on the ends of string making angles of 10.0° with the vertical.

The electric flux created by each balloon is:

[tex]\phi_{e} = \frac{q}{\epsilon_{0} } = \frac{1.2 \times10^{4}C }{8.85\times10^{-12}C^{2}/N \cdot m^{2}} = 1.4 \times 10^{4} N\cdot m^{2}/C\\[/tex]

Gauss Law states that the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux in an area is defined as the electric field multiplied by the area of the surface projected in a plane and perpendicular to the field.

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Answer:

2

1

2

1

3

1

Explanation:

I'm pretty sure these are right. you might want to go back and check the first and third, but the other 4 are right

The greater mass will have greater acceleration is a fact from second law of motion. Thus, first situation is an example of second law. Spilling of water from the glass indicates the first law , that is law of inertia.

Newton' s first law of motion states that, every body tends to continue on the state of motion or rest until an external force acts upon it. This law is called law of inertia.

Second law states that the force applied on a body is directly proportional to the mass and acceleration.

Newton's third law states that, for every action there is an equal and opposite reaction. The first statement indicates the second law of motion and water spilling indicates the law of inertia.

As the mass increases, more force to be applied and acceleration decreases with mass. Thus third situation indicates second law. The magician pulling the cloth from stationary, hence it is first law.

A rocket launches by a force applied on the space and an opposing force from the fuel make it move indicating the third law. The last situation indicates the first law. Hence, the labeling is as 2,1,2,1,3,1.

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