Tech A says that pushing on the brake pedal stops the vehicle by converting chemical energy into thermal
energy. Tech B says that brake pedal pressure is transmitted to the brakes hydraulically. Who is correct?

It is important to choose the appropriate magnification for your needs so that you can properly examine the specimen under study.

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An elevator is being lifted up an elevator shaft at a constant speed by a steel cable. All frictional effects are negligible. In this situation, forces on the elevator are such that the upward force of the cable is equal to the downward force of gravity.

As per Newton's 2nd regulation F = ma, acceleration needs a force proportional to mass. So when the elevator is accelerating upwards, it has to not handiest oppose gravity however provides greater pressure for the upward acceleration. This calls for an expanded ordinary force

Friction is the pressure resisting the relative motion of strong surfaces, fluid layers, and cloth factors sliding against each other. There are several types of friction: Dry friction is a pressure that opposes the relative lateral movement of two solid surfaces in touch.

The gravitational force is a pressure that draws any gadgets with mass. We call the gravitational pressure attractive as it usually attempts to pull masses collectively, it in no way pushes them apart. In fact, each item, which includes you, is pulling on each other object in the entire universe.

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Answer:

standard

Explanation:

we sometimes use weights of known mass to balance with an object of unknown mass to determine that objects weight.

The final velocity of the car, given the data is 32.88 m/s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

The following data were obtained from the question:

The final velocity of the car can be obtained as follow:

a = (v – u) / t

1.6 = (v – 22) / 6.8

Cross multiply

v – 22 = 1.6 × 6.8

v – 22 = 10.88

Collect like terms

v = 10.88 + 22

v = 32.88 m/s

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Answer:

10

Explanation:

2*3^2-8

2*9-8

18-8

10

The player has to apply a force of 1956.5N to start tackling sled in motion.

Coefficient of static friction μ[tex]_{s}[/tex] = 0.70

Weight of sled = mg

                        = 590N

Weight of Player A = [tex]m_{a}g[/tex]

                               = 100 × 9.8

                              = 980N

Weight of Player B = [tex]m_{b}g[/tex]

                               = 125 × 9.8

                              = 1225N

Combined weight of sled:

W =  (590+980+1225)N

   = 2795N

Now, friction on sled:

f = μ[tex]_{s}[/tex]R

  = 0.70 × 2795

  = 1956.5N

Therefore, the player has to apply force equal to static friction to start tackling sled in motion.

∴ Force = Static friction =  1956.5N

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Magnitude of the magnetic fields from largest to smallest is,

[tex]B_{e}\; > \;B_{c}\; > \;B_{b}\; > \;B_{a}\; > \;B_{d}[/tex]

We know that,

[tex]Permeability\;of\;free\;space,\;\mu_{0} = 4 \times \pi \times 10^{-7}\;H/m\\[/tex]

[tex]l=length[/tex]

[tex]I=current[/tex]

(a)

[tex]Radial\;distance,\;r = 2\;cm=0.02\;m[/tex]

[tex]Current,\;I = 3\;A[/tex]

We know that, Magnetic equation,

[tex]B_{a} =\frac{\mu_{0} \times I}{2\times \pi\times r}[/tex]

Substitute the known values in the above magnetic field equation,

[tex]B_{a}=\frac{4 \times \pi \times 10^{-7} \times 3}{2\times \pi\times 0.02}[/tex]

By solving the equation, we get

[tex]B_{a}=3 \times 10^{-5}\;T[/tex]

(b)

[tex]Radius\;of\;the\;coil,\;r = 0.02\;m[/tex]

[tex]Number\;of\;turns,\;N = 10[/tex]

[tex]Current,\;I = 0.3\;A[/tex]

We know that, Magnetic equation,

[tex]B_{b} =\frac{\mu_{0} \times N \times I}{2\times r}[/tex]

Substitute the known values in the above magnetic field equation,

[tex]B_{b}=\frac{4 \times \pi \times 10^{-7} \times 10 \times 0.3}{2 \times 0.02}[/tex]

By solving the equation, we get

[tex]B_{b}=9.425 \times 10^{-5}\;T[/tex]

(C)

[tex]Length\;of\;the\;solenoid,\;l = 2\;m[/tex]

[tex]Number\;of\;turns,\;N = 1000[/tex]

[tex]Current,\;I = 0.3\;A[/tex]

We know that, Magnetic equation,

[tex]B_{c} =\frac{\mu_{0} \times N \times I}{l}[/tex]

Substitute the known values in the above magnetic field equation,

[tex]B_{c}=\frac{4 \times \pi \times 10^{-7} \times 1000 \times 0.3}{2}[/tex]

By solving the equation, we get

[tex]B_{c}=18.85 \times 10^{-5}\;T[/tex]

(d)

[tex]Current\;through\;the\;bar,\;I = 300\;A[/tex]

At the center of the conductor if we consider an Amperian loop of zero radius, no current will be enclosed by this loop.

Hence, At the center of the conductor magnetic field will be zero

[tex]B_{d}=0[/tex]

(e)

[tex]1 mT=1 \times 10^{-3}[/tex]

Therefore,

[tex]B_{e}=1 \times 10^{-3}\;T[/tex]

Therefore, Magnitude of the magnetic fields from largest to smallest is,

[tex]B_{e}\; > \;B_{c}\; > \;B_{b}\; > \;B_{a}\; > \;B_{d}[/tex]

When placed inside a magnetic field, a material's permeability—which is defined as the number of magnetic lines of force that may pass through a specific surface—allows magnetic flux to pass through it.

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It is proved that when v<<c , then speed of the light measured in the laboratory frame is , u = c/n + v -v/n^2 .

Given ,

The motion of a transparent medium influences the speed of light .

The water moves with speed v in a horizontal pipe .

Assume that the light travels in the same direction as the water moves .

The speed of the light with respect to the water is c/n

Where n = 1.33 is the refractive index of water .

Let us assume ,

u' be the speed of light in water , in the frame moving with the water .

u' is related to the refractive index of water ,n as :

u'=c/n

where , c is the speed of light .

let , u be the speed of light in water in the lab frame .

Now , u and u' are related as : u = (u'+ v )/(1+ u'v/c^2)

Here v is the speed of water in the horizontal pipe .

we know the value of u' , so by substituting the value , we will get ,

u= (c/n+ v)/(1+cv/nc^2)

u= c/n(1+ nv/c)/(1+v/nc)

(b) We have , v<<c

v/c<<1 .

so , (1+v/nc )^-1 = (1-v/nc)

Now substituting this , we will get ,

u = c/n(1+nv/c) (1-v/nc)

u≈c/n(1+ nv/c-v/cn)

u≈c/n + v - v/n^2

Hence , it is proved that when v<<c , then speed of the light measured in the laboratory frame is , u = c/n + v -v/n^2 .

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Disclaimer : incomplete question , here is the complete question .

Question: The motion of a transparent medium influences the speed of light. This effect was first observed by Fizeau in1851. Consider a light beam in water. The water moves with speed v in a horizontal pipe. Assume the light travels in the same direction as the water moves. The speed of light with respect to the water is c / n , where n=1.33 is the index of refraction of water.(a) Use the velocity transformation equation to show that the speed of the light measured in the laboratory frame isu = c/n (1 + nv/c / 1+ v/nc) . (b) show that for v<<c , the expression from part (a) becomes , to a good approximation , u ≈ c/n + v - v/n^2 .

Answer:

Explanation:

it should be 3.2 m/s^2

The acceleration is 3.2 m/ s2. Acceleration is change in velocity per time.

Any procedure where the velocity varies is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.

A moving object can occasionally alter its velocity by the same amount every second. The data table above depicts an item altering its velocity by 10 m/s every second, as was described in the paragraph above. Since the velocity is changing by a fixed amount every second, this is known as a constant acceleration.

Therefore, The acceleration is 3.2 m/ s2. Acceleration is change in velocity per time.

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Answer:

D. Adapt your communication style.

Explanation:

It is quite difficult to gauge the protocol here given the lack of information about the work environment; but as a general answer, communication skills are always handy. Furthermore, it seems that Marta in particular struggles with this. Assuming Marta is providing a specialized service of a sort, she would need to understand that there is a reason why her services are required at all. Through this, hopefull she'll understand that they are most likely outside of this field of work, and ergo [she] must cater and gear her actions towards the interest of the person(s) in question.

It is to be noted that this is merely my surmise.

Answer:

Velocity ratio of simple machine is the ratio of distance traveled by the effort to the distance traveled by the load in the machine. As velocity ratio or ideal mechanical advantage is a simple ratio of two distances.Hence always remains constant. Option A is correct.

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Answer:

Velocity ratio of simple machine is the ratio of distance traveled by the effort to the distance traveled by the load in the machine. As velocity ratio or ideal mechanical advantage is a simple ratio of two distances.Hence always remains constant. Option A is correct.

Explanation:

EXTRA:Velocity ratio of a lever is 3 means distance travelled by effort is 3 times the distance travelled by the load. Efficiency of the pulley is 60% means 40% of the energy is lost in the machine due to the friction.

EXTRA:Ans:- MA of a lever is 3 it means that the load is 3 times of effort and VR of a lever is 4 it means that effort distance is 4 times of load distance.

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Answer:

Explanation:

The answer will be the 1.66N

According to the 1 equation of motion:

v=u+at; where v=final velocity, u=initial velocity, a= acceleration, t=time

According to the given value in question

0=5+a*0.60

a= -5/0.60

a=-13.88m/s2

Now according to the Newton’s 2 law

F=ma; where F=force, m=mass

F=0.12*13.88

F=1.66N

So, the average resultant force acting on the stone while it is being fired will be 1.66N.

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Magnetic field due to current in wire is 0.1308 Tesla.

The friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing those surfaces from moving. Typically, it is represented by the Greek letter mu.

Given:

[tex]Mass\;per\;unit\;length(\frac{m}{l})=1.0\;g/cm=0.1\;kg/m\\[/tex]

[tex]Coefficient\;of\;friction,\;(\mu)=0.2[/tex]

[tex]Current,\;(I)=1.5\;A[/tex]

[tex]According\;to\;the\;question,\;wire\;is\;moving\;on\;a\;surface\;with\;\mu\;and\;force\;that\;is[/tex][tex]moving\;the\;wire\;is\;magnetic\;force\;f_{m} , then,[/tex]

[tex]f_{m}=\mu f_{N} (f_{N}=normal\;reaction\;of\;wire)[/tex]

[tex]Also, f_{m}=B\;L\;I\;sin\propto[/tex]

Therefore,

[tex]B_{b}=\frac{\mu\;m\;g}{L\;I\;sin\propto}[/tex]

[tex]B=magnetic\;field[/tex]

[tex]f_{N}=mass \times accelaration\;due\;to\;gravity[/tex]

Therefore,

[tex]B_{b}=\frac{0.2\times0.1\times10}{1.5\times sin\propto}[/tex]

[tex]sin \propto = angle\;magnetic\;field\;and\;the\;current\;in\;the\;wire=sin\;90^{\circ}=1[/tex]

Therefore,

[tex]B_{b}=0.1308\;T[/tex]

Now, from the figure shown and using Fleming's Right Hand rule in which the fore finger indicates current that is in east direction and the thumb indicates force that is in north direction and then direction, shown by your middle finger shows the direction of induced magnetic field.

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The aphelion distance of Hailey's comet from the sun is 36 A. U.

The perihelion distance of Hailey's comet = 0.6 amu

The orbital period of Hailey's comet = 76 years

According to Kepler's law,

The time duration is T.

T = 76 years.

The semi-major axis is a.

The semi-major axis is,

[tex]T ^{2} =a ^{3} [/tex]

[tex]a = \sqrt[3]{(T) ^{2} }[/tex]

[tex]a = \sqrt[3]{(76) ^{2} }[/tex]

= 18 A. U

The aphelion distance of Hailey's comet from the sun is,

= 2 × a

= 2 × 18

= 36 A. U

Therefore, the aphelion distance of Hailey's comet from the sun is 36 A. U.

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The volume of the 4.00 cm length of the, 1.85 mm thick cylinder pump, that comes to thermal equilibrium with the air is approximately 6.24 cm³.

Parameters of the question found in a similar question found online are as follows;

Thickness of the steel cylinder, t = 1.85 mm

Length of steel cylinder that comes to thermal equilibrium with the air, l = 4.00 cm

Given parameters;

Inner diameter of the cylinder, d = 2.50–cm

Length of the cylinder = 50.0–cm

Required; Volume of the steel in the 4.00–cm length

Solution;

1.85 mm = 0.185 cm

Volume of the cylinder, V, is found as follows;

V = π•(D² - d²)/4 × l

Where;

D = The outer diameter of the cylindrical pump

d = The inner diameter

l = Length of the cylinder

Therefore;

D = d + 2•t

Which gives;

D = 2.5 + 2 × 0.185 = 2.87

V = (π•(2.87² - 2.5²)/4) × 4 ≈ 6.24

Therefore;

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The problem of early water runoff that engineers might be asked to solve is the issue of Impervious surfaces, or surfaces that are unable to absorb water.

They are:

In the water cycle, runoff is known to be when water just "streaming off" the surface of the ground. The rain need to also drains downhill, just like the water a person use to wash their  car does as a person work are all part of runoff.

Therefore, The problem of early water runoff that engineers might be asked to solve is the issue of Impervious surfaces, or surfaces that are unable to absorb water.

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When a moving thing slows down, gravity action must be taking place on the object.

Every item is subject to the gravitational pull of the earth, which pulls everything in the atmosphere toward the planet's surface.

Since there is no gravity nor a vacuum in space, the only reason the item is traveling is due to the attraction of the earth's gravitational field.

Therefore, when an item slows down while in motion, gravitational force must be at work. The moon's gravitational pull causes ocean tides, and on Earth, gravity gives weight to physical objects. Additionally, gravity is a key factor in a variety of biological processes, such as gravitropism, which controls plant development, and the fluid movement in multicellular organisms.

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The level of sound intensity at the late-night is β₂ = 67.0dB

Acoustic measurements are made with a sound level metre, often known as a sound pressure level metre (SPL). A hand-held device with a microphone is the most typical type. The condenser microphone is the best kind of microphone for sound level metres because it combines accuracy with stability and dependability. Sound waves generate changes in air pressure, which the microphone's diaphragm reacts to. The device is sometimes referred to as a sound pressure level metre because of this (SPL).

We are given:

The level of sound intensity in the afternoon is  β₁ = 80dB

No. of cars per min in the afternoon = 100

No. of cars per min in late night = 5

The level of sound intensity in the late night β₂ =?

The level of sound intensity in the late night I² =?

Reference sound intensity, I₀ = 10⁻¹²W/m²

The sound intensity level is given by: β = 10Log(I/I₀)

Numerically evaluating,

β₂ = 10 log (5X10⁻⁶/10⁻¹²)

β₂ = 67.0dB

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At a point 2 cm horizontally east of the wire's center, the magnetic field generated by the vertical wire is pointing south. As a result, option B south is the correct answer.

There are north and south poles on every magnet. The same poles repel one another whereas opposite poles are attracted to each other. The north-seeking poles of the iron's atoms pairing in the same direction when it is touched against a magnet. A magnetic field is produced by the force that the aligned atoms produce. The iron object has changed into a magnet. An electric current has the ability to magnetize specific materials. A magnetic field results from the flow of electricity through a coil of wire. But as quickly as the electric current is cut off, the field around the coil will disappear.

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The wavelength of the light beam required to turn back all the ejected electrons is 497 nm which is option (b).

It is given that work function (Ф) of monochromatic light is 2.50 eV.

Einstein photoelectric equation  is given by:

[tex]K.E_m_a_x=E-\phi[/tex]      ....(2)

where K.E(max) is the maximum kinetic energy.

Substituting (1) into (2) , we get

  [tex]ev_0=E-\phi\\1.6\times10^{-19} \times1=E-2.50\\E=1.6\times10^{-19}+2.50\\E=2.50eV[/tex]

As we know that [tex]E=\frac{hc}{\lambda}[/tex]  ....(3)

where Speed of light,[tex]c = 3\times10^8 m/s[/tex] and Planck's constant , [tex]h = 6.63\times 10^-^1^9Js = 4.14\times 10^-^1^5 eVs[/tex]

From equation (3) , we get

[tex]\lambda=\frac{hc}{E} \\\\\lambda=\frac{ 4.14\times 10^-^1^5 \times 3 \times10^8}{2.50} \\\\\lambda=\frac{1240\times10^-^9}{2.50} \\\\\lambda=496.8\times10^-^9\\\\\lambda=497nm[/tex]

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Answer: Given -

To find -

Solution -

[tex]A=\frac{v-u}{t}\\A=\frac{12-0}{36} \\A=\frac{12}{36} \\A=0.33m/s^2[/tex]

Therefore, the acceleration of the ball is 0.33 m/s².

I hope this helps.

If the table says that the atomic number of the element is 12 and the mass number of the element is 40, then the element has 12 protons and 28 neutrons, therefore the correct answer is option C.

It is the sum of the mass of all the protons as well as the neutrons that are present inside the nucleus.

The addition of protons and neutrons represents the mass number of any element.

The mass number of any element is the sum of the number of protons and the number of neutrons, therefore the correct answer is option C.

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One pith ball's charge, q1, is equal to 30 nC, or 30x10-9C.

the second pith ball's charge, q2 = -30n c= -30x 10-9 c

They are separated by d=8 cm, or 8x10-2 metres.

They repel one another by a force of F = (81/64) x 10-3.

F = 1.266x10^-3 N

The gravitational force is solely an attracting one in both the General Theory of Relativity and Newton's theory of gravity. But quantization of gravity demonstrates that there are opposing gravitational forces as well.

A force between two or more opposite or different charges is called attraction. Two charges that are at odds with one another are attracted to one another. A force between two or more like or comparable charges is called repulsion. Two identical charges separate themselves.

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To find the masses of both stars in a binary system, you must find the velocity of each star, the period of the orbit, and the average distance between the stars.

The displacement covered by an object in the unit of time is called velocity.

The formula of velocity is v = d/t and its dimensions are LT-1.

A unit of time in which a particle or object passes through a point to complete its one cycle is called a period. It is related to time.

The time-period is denoted by T and the formula is T = 2 π√ l / g.

In physics, distance is a vector quantity without any direction. It can be calculated as distance = speed x time i.e. d = v.t

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Answer:

The plates move toward each other

Explanation:

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GEO 1405 Chapter 2 Quiz

The molecule in the air that is moving at a speed 459 m/s during a time of 7.00 ms (milliseconds) if it didn’t collide with any other molecules would move a distance of: 3.213 m

The formula and procedure we will use to solve this exercise is:

x = v * t

Where:

Information about the problem:

By converting the time units from (ms) to (s) we have:

t = 7.00 ms * 1 s/1000 ms

t = 0.007 s

Applying the distance formula we have that:

x = v * t

x= 459 m/s * 0.007 s

x = 3.213 m

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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Answer:

Mass and gravity

Explanation:

[tex]{ \rm{weight = mass \times gravity}}[/tex]

Weight is the force exerted on an object due to gravity. The correct answer is mass and gravity. The correct option is an option  (3).

Weight requires both mass and gravity.

The formula for calculating weight is given by:

Weight = mass × gravitational acceleration

W = m × g

The gravitational acceleration is known by the strength of the gravitational field, which is typically constant at any given point.

The mass of an object and the strength of its gravitational field is its weight. It is the gravitational force that pulls an object toward the center of the Earth.

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Therefore, The correct option is (3).

The complete question is:

What does weight require?

1) gravity and volume

2) only mass

3) mass and gravity

4) mass and volume

Answer:

4m/s^2

Explanation:

u find the average of the two velocities then place the outcome in the acceleration formula given time as 6.3 seconds .....dividing the average of the velocities

The density of ice does not affect its melting rate. Adding objects will affect the melting rate.

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