Answer:
See the explanation below.
Explanation:
To solve this problem we must apply Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration and this force can be calculated by means of the following equation.
F = m*a
where:
F = force [N] (units of Newtons)
m = mass [kg]
a = acceleration [m/s²]
The mass of the tennis ball will always be the same therefore it will never change.
Now clearing a:
[tex]a=\frac{F}{m}[/tex]
If the mass of the ball remains the same:
[tex]a = \frac{100}{m} ; a = \frac{200}{m};a =\frac{300}{m}[/tex]
We see that for a force of 300 [N], the acceleration exerted on the ball must be greater. Therefore with the force of 300 [N] the greatest acceleration is achieved.
Sheila uses a 45N force on her bowling ball across a 15m lane. What work did she do on the bowling ball? Show your work.
Answer:
675J
Explanation:
Given parameters:
Force = 45N
Distance = 15m
Unknown:
Work done by Sheila = ?
Solution:
Work done by a body is the amount of force applied to make a body move through a distance;
Work done = Force x distance
Now;
Work done = 45 x 15 = 675J
Suppose we have a 600 kilogram great "yellow" shark swimming to the right at a speed of 3 meters traveled each second as it tries to get lunch. An unsuspecting 100 kilogram blue fin tuna is minding its own business swimming to the left at a speed of 0.5 meters traveled each second. GULP! After the great "yellow" shark "collides" with the blue fin tuna, what is the velocity of the well fed shark?
Answer:
2.64 m/s
Explanation:
Given that a 600 kilogram great "yellow" shark swimming to the right at a speed of 3 meters traveled each second as it tries to get lunch. An unsuspecting 100 kilogram blue fin tuna is minding its own business swimming to the left at a speed of 0.5 meters traveled each second. GULP! After the great "yellow" shark "collides" with the blue fin tuna
Momentum = MV
Momentum of the yellow shark before collision = 600 × 3 = 1800 kgm/s
Momentum of the tun final before collision = 100 × 0.5 = 50 kgm/s
Total momentum before collision = 1800 + 50 = 1850 kgm/s
Let's assume that they move together after collision. Then,
1850 = ( 600 + 100 ) V
1850 = 700V
V = 1850 / 700
V = 2.64285 m/s
Therefore, the momentum of the shark after collision is 2.64 m/ s approximately
the Heat required to raise the temp. of 20 g water from 25 C to 36 C
Mathew throws a ball straight up in the air. it rises for a period of time and then begins to drop. At which points in the balls journey will be gravity be the greatest force acting on the ball
Answer: The greatest force of gravity on the ball will occur at the point when the ball is near to hit the ground ... hope this helps have a good day :P
which names are correct for fm−→−? select each correct answer. fp−→− ray f p fd−→− ray f d mf−→− ray m f fw−→−
The correct answer is FM-MF
The crust of the Earth does not naturally contain ferromium. The heaviest element that can be created by neutron bombardment of lighter elements, fermium was first discovered in December 1952 by American scientists from the Argonne National Laboratory near Chicago, Illinois, the Los Alamos National Laboratory in Los Alamos, New Mexico, and The University of California Laboratory in Berkeley. Fermium is the heaviest element that can be synthesized in macroscopic quantities.
We can prove this by saying that if a point's distance from another point is six units, then the distance between those two points will also be six units. Therefore, FM-MF
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Please help me I need it
Answer:
Parallel circuits :)
Show FORMULA AND SOLUTION:
What acceleration will result when a 12N net force applied to a 3kg object? A 6kg object?
Answer:
2m/s²
Explanation:
F = 12 N
m = 3kg
a = ?
F = ma
a = F/m = 12/3 = 4 m/s²
when m = 6kg
a = F/m = 12/6
a = 2 m/s²
PLEASE HELP ME
What is the net force acting on the car?
Under which condition is the resultanat vector equal to zero?
Which astronomer measured the motion of stars in the sky?
A. William Herschel
B.Harlow Shapley
C.Vesto Slipher
D. Edwin Hubble
Edwin Hubble was the astronomer which measured the motion of stars in the sky and is therefore denoted as option D.
What is Astronomy?This refers to an aspect of a science called natural science and is the study of celestial bodies such as the moon, stars etc and the different phenomena which occurs between them.
An astronomer called Edwin Hubble was responsible for the measurement of the motion of stars through when he was in the process of the formulation of his law which involves the determination of distances to galaxies and quasars which is therefore the reason why option D was chosen as the correct choice.
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An over-caffeinated student stands on a table which weighs 600 newtons. The student has a mass of 50 kg. What is the weight of the student? What is the weight of the student AND the table combined? Now, what is the TOTAL normal force on the table by the floor?
Answer:50kg
Explanation:
what yall notice about this please help me out
Answer:
There is a blue sky with clouds
There is cracks in the ground and the ground is brown
There is stuff in the dictance
Explanation:
Hope this helps
write down the kirchhoff's laws in the adjoining circuit , find the current in each resistors
Answer:
You need a motor and a battery
Explanation:
The currents through 4 ohm, 2 ohm and 5 ohm are 0.42 amp, 0.15 amp and 0.26 amp respectively.
What are the Kirchhoff's laws ?
Kirchhoff's Current Law states that no charge is lost and that the total current flowing into a junction or node equals the charge leaving it.
Kirchhoff's Voltage Law states that for any closed network, the voltage around a loop is equal to the total of all voltage drops in that loop and is equal to zero.
Let the current through 4 ohm is I₁.
the current through 2 ohm is I₂.
Applying Kirchhoff's Current Law, current through 5 ohm is I = I₁ + I₂.
Applying Kirchhoff's Voltage Law in two loops we get:
4 I₁ + 5(I₁+I₂) = 3
2I₂ + 5(I₁+I₂) = 1
Hence, I₁ = 0.42 amp
I₂ = - 0.15 amp
I₃ = 0.26 amp
Hence, the currents through 4 ohm, 2 ohm and 5 ohm are 0.42 amp, 0.15 amp and 0.26 amp respectively.
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Hey everyone,
right now
I want you to stop
stop whatever you are doing
walk to a mirror
look in it
look at your face
your gorgeous face
look at your eyes
how they shine
look at your hair
it's perfect
you are beautiful
I hope you realize
you are pretty freakin amazing <3
Answer:
oooh thanks
Explanation:
..................
Answer:
awwww thx you are to :)
Explanation:
would a larger, more heavier ball fall faster than a smaller and lighter ball?
Answer:
the larger-heavier would fall faster than lighter-smaller ball
Explanation:
why do we not consider the electromagnetic force when we describe the force between the earth and the sun?
Electromagnetic force can not be considered because it very less as compared to gravitational force.
There are four types of Nuclear Forces :
1. Gravitational force
2. Electromagnetic force
3. Strong nuclear force
4. Weak nuclear force
The force acting between the sun and the earth is gravitational force it is about
3.54 ×10²²N
Earth rotates around the sun because it is contained in the sun's gravitational field.
Due to the centripetal force Earth doesn't falls into the sun.
Electromagnetic force can not be considered because it very less as compared to gravitational force. The electromagnetic force between two charged bodies is nearly equal to 10⁵N.
Electromagnetic force can not be considered because it very less as compared to gravitational force.
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If you weight 100 pounds on earth how much would you weight on the moon
Answer:
You should weigh about 16 pounds.
Explanation:
To find this, you need to find your weight and divide it by 6 to find your weight on the moon.
How can you drop two eggs the fewest amount of times, without them breaking?
Answer:
Both eggs are identical. The aim is to find out the highest floor from which an egg will not break when dropped out of a window from that floor. If an egg is dropped and does not break, it is undamaged and can be dropped again. However, once an egg is broken, that's it for that egg.
please help me swear will mark brainiest
Answer:
I think that is d option 1.0Nm anticlockwise
the armature windings of a dc motor have a resistance of 6.5 ω . the motor is connected to a 120-v line, and when the motor reaches full speed against its normal load, the back emf is 108 v. the load is increased so it causes the motor to run at half speed.
The current in the load will be 10 A.
given,
resistance of the load (R) = 6.5Ω
voltage in the load (V) = 120V
Back emf in the load (E)= 108V
now to measure current we will use the formula
current (I)= {voltage (V)-Back emf (E)}/resistance(R)
now as the speed is halved so will the back electro motive force will be halved.
i.e.
back electro motive force will be = 108V/2
=54V
now,
substituting this value in the formula we get,
current (I) = (120-54)/6.5
current (I) = 66/6.5
current (I) =10A
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Omar and ahmed are lifting weights in the gym. Each lifts a weight of 200N. Omar lifts the weight to a height of 2.0m, whereas ahmed lifts it to a height of 2.1m. Who does more work in lifting the weight.
Answer:
Ahmed did more work in lifting the weight than Omar.
Explanation:
Work done can be determined as the product of a force and the distance moved in the direction of the force.
Work done = F x s
In the given question, since the weight is lifted through a height, then the work done equals potential energy.
i.e Work done = Potential energy
= mgh
But,
Force = weight = mg
So that,
Work done = Fh
where F is the weight and h is the height.
i. Work done by Omar = Fh
= 200 x 2.0
= 400
Work done by Omar is 400 Nm.
ii. Work done by Ahmed = Fh
= 200 x 2.1
= 420
Work done by Ahmed is 420 Nm.
Thus, Ahmed did more work in lifting the weight than Omar.
sheila uses a 45N force on her bowling ball across a 15M lane. what work did she do on the bowling ball? show your work.
Answer:
Work=force × distance
=45×15
=675
Explanation:
need thanks and make me brainiest if it helps you
A linearly polarized microwave of wavelength 1.50cm is directed along the positive x axis. The electric field vector has a maximum value of 175V/m and vibrates in the x y plane. Assuming the magnetic field component of the wave can be written in the form B=Bmax sin (k x-Ω t) give values for (f) If this wave were directed at normal incidence onto a perfectly reflecting sheet, what radiation pressure would it exert?
The radiation pressure directed at normal incidence onto a perfectly reflecting sheet is 2.71 × 10⁻⁷ Pa
What radiation pressure would it exert?Given that a linearly polarized microwave of wavelength 1.50cm is directed along the positive x axis and the electric field vector has a maximum value of 175V/m and vibrates in the x y plane.
Also, assuming the magnetic field component of the wave can be written in the form B=Bmax sin (k x-Ω t) give values for (f) If this wave were directed at normal incidence onto a perfectly reflecting sheet, we desire to find the radiation pressure.
The radiation pressure for total reflection is given by P = 2I/c where
I = intensity = E²/2μ₀c where E = maximum electric field = 175 V/m, μ₀ = permeability of free space = 4π × 10⁻⁷ T/m and c = speed of light = 3 × 10⁸ m/sSo, P = 2I/c
P = 2E²/2μ₀c ÷ c
P = E²/μ₀c²
Substituting the values of the variables intot he equation, we have
P = E²/μ₀c²
P = (175 V/m)²/[4π × 10⁻⁷ T/m × (3 × 10⁸ m/s)²]
P = 30625 V²/m²/[4π × 10⁻⁷ T/m × 9 × 10¹⁶ m²/s²]
P = 30625 V²/m²/[36π × 10⁹ Tm/s²]
P = 30625 V²/m²/113.097 × 10⁹ Tm/s²
P = 270.78 × 10⁻⁹ Pa
P = 2.7078 × 10⁻⁷ Pa
P ≅ 2.71 × 10⁻⁷ Pa
So, the radiation pressure directed at normal incidence onto a perfectly reflecting sheet is 2.71 × 10⁻⁷ Pa
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suppose the aqueous humor in a person’s eye exerts a force of 0.295 n on the 1.15-cm2 area of the cornea.
The aqueous humor in a person’s eye exerts a force of 0.295 n on the 1.15-cm2 area of the cornea pressure is this in mm Hg P = 2565.2173 N/m².
Equation :Pressure is defined as the normal force F per unit area A over which the force is applied or
P = F / A
Where :
P is the pressure acting on the cornea .
F if the force acting on the cornea .
A is the area of the cornea .
Givens : F = 0.3 N and A = 0.00011 m
Plugging known information to get :
P = F / A
P = 0.295 / 0.000115
P = 2565.2173
P =2565.2173 N/m²
What produces aqueous humor?The ciliary body produces aqueous humor, which travels along the uveoscleral pathway from the posterior chamber through the pupil and anterior chamber (shown by dashed lines and arrowheads) to the ciliary muscle and suprachoroidal region.
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I understand the question you are looking for :
suppose the aqueous humor in a person’s eye exerts a force of 0.295 n on the 1.15-cm2 area of the cornea. What pressure is this in mm Hg?
Explain how inductive reasoning is inferior to deductive reasoning in establishing theory.
Answer: Created Fall 2016 by Ronald Wilson Inductive reasoning uses a set of specific observations to reach an overarching conclusion; it is the opposite of deductive reasoning. So, a few particular premises create a pattern which gives way to a broad idea that is likely true.
Explanation: No explanation lol. But I hope this is helpful!
In his experiments on "cathode rays" during which he discovered the electron, J. J. Thomson showed that the same beam deflections resulted with tubes having cathodes made of different materials and containing various gases before evacuation.(d) Could Thomson observe any deflection of the beam due to gravitation? Do a calculation to argue for your answer. Note: To obtain a visibly glowing patch on the fluorescent screen, the potential difference between the slits and the cathode must be 100V or more.
Thomson could not observe any deflection of the beam due to gravitation.
What is a cathode ray?Cathode ray refers to the beam of electrons that moves from the negatively charged cathode to the positive anode at the other end of the pipe.
J. J. Thomson demonstrated that the identical beam deflections produced tubes with cathodes composed of varied materials and containing a range of gases prior to evacuation.
The gravitational force is approximately 10⁴⁰.
The movement of the light beam shouldn't be impacted because it is 10²⁸ times weaker than the electric force.
Thomson was unable to detect any gravitational beam deflection.
Thus, Thomson could not observe any deflection of the beam due to gravitation.
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Consider (a) an electron (b) a photon, and (c) a proton, all moving in vacuum. Choose all correct answers for each question. (iii) Which carry energy?
Electron , photon and proton carry energy which is option (a) , (b) ,(c)
An electron is a solid negatively charged factor of an atom. Electrons exist outdoor of and surrounding the atom nucleus. Each electron includes one unit of bad charge (1.602 x 10-19 coulomb)A proton is a subatomic particle discovered withinside the nucleus of each atom. The particle has a advantageous electric charge, identical and contrary to that of the electron Photon is a subatomic particle, having strength and momentum however no mass or electric powered charge, this is the quantum unit of electromagnetic radiation, together with light.Photons are massless, but they have energy [tex]E = hv= \frac{hc}{\lambda}[/tex]
Here 'h' is called Planck's constant .
For electron and proton energy is given by
[tex]E=\frac{1}{2} \times mv^2[/tex]
Where m is the mass of the particle and v is the speed of particle .
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Is Ampère's law valid for all closed paths surrounding a conductor? Why is it not useful for calculating →B for all such paths?
Although not always practical, Ampere's law is true for all closed channels around a conductor. The integral can be calculated along many different paths, although it is difficult to do so. Think about a path that is circular but not coaxial with a long, straight wire that carries current. If the current in a conductor has enough symmetry to allow the line integral to be reduced to the size of B times an integral, Ampere's law can be used to calculate B.
What applications does Ampere's Law have?Ampere's Law is applied to,
Find the magnetic induction caused by a long wire carrying current.Analyze the magnetic field a toroid has.Find the magnetic field produced by a long conducting cylinder that carries current.Ascertain the conductor's magnetic field.To learn more about Ampere's Law, visit:
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A rocket is launched and the observer measuring the rocket altitude is standing at a distance of 200 feet from the launcher. When the rocket reaches apogee, the observer measures an angle of 45° using an altitude scope. Calculate the altitude of the rocket to the nearest foot.
Answer:
100 foot
Explanation:
Using the formula for calculating range to calculate the speed first as shown;
Range R = U²sin 2theta/gU is the speed
theta is the observe angle
g is the acceleration due to gravity.
200 = U²sin 2(45)/9.8
Usin90 = 200 * 9.8
U² = 1960
U = √1960
U = 44.27 m/s
Get the required altitude
Altitude H = u²/2g
H = 44.27²/2(9.8)
H = 1,959.8329/19.6
H = 99.99 feet
Hence the altitude of the rocket to the nearest foot is 100 foot