Answer:
answer is FALSE
Explanation:
AMPLITUDE IS THE MAXIMUM AMOUNT OF DISPLACEMENT OF A PARTICLE ON THE MEDIUM FROM ITS REST POSITION
AND WAVELENGTH can be measured as crest to crest
Amplitude of a wave is the strength of the wave. It is measured from the central line of the wave to the top of the crest or bottom of the trough. Therefore, the statement is false.
What is amplitude?Amplitude is a parameter measuring the strength of a wave. It is the maximum displacement moved by the wave from its equilibrium position. The vibrational path will be twice that of the amplitude of the wave.
As the amplitude of the wave increases its intensity increases. Both are in direct proportion with the frequency and energy of a wave. For instance the amplification of sound waves increases the intensity of waves that we hear.
The distance between two consecutive crests or troughs is the wavelength of the wave not amplitude. Amplitude is measured from the axis line to the top of the crest thus, from exact middle of the wave crest to the top or to the bottom of trough. Thus, the statement is false.
To find more on amplitude, refer here:
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Spring 1 and Spring 2 are the same type of spring. Both springs were pushed or compressed into different positions and clamped into place
L
Which spring has less potential energy?
Answer:
spring 1 has less potential energy
Explanation:
since spring 2 is clampped down further it will have a greater effect but since sping 1 is barely clamped down it wont show as much energy
A brick of gold is 0.1 m wide, 0.1 m high, and 0.2 m long. The density of gold is 19,300 kg/m3. What pressure does the brick exert on the table if the brick is resting on its side?
Answer:
[tex]P=18,933.3Pa=18.9kPa[/tex]
Explanation:
Hello!
In this case, since we can compute the volume of the brick as shown below:
[tex]V=0.1m*0.1m*0.2m=0.002m^3[/tex]
Next, we can compute the mass of the brick given its density:
[tex]\rho =m/V\\\\m=V*\rho\\\\m=0.002m^3*19,300kg/m^3\\\\m=38.6kg[/tex]
Now, since the force exerted on the table corresponds to the weight of the brick, we use the gravity to obtain:
[tex]W=38.6kg*9.81m/s^2=378.7N[/tex]
Finally, since the surface of the brick in contact with the table corresponds to the 0.1x0.2 area (length and width), the area on which the weight force is exerted is:
[tex]A=0.1m*0.2m=0.02m^2[/tex]
Therefore, the pressure is:
[tex]P=\frac{F}{A}=\frac{W}{A}=\frac{378.7N}{0.02m^2}\\\\P=18,933.3Pa=18.9kPa[/tex]
Best regards!
Im pretty sure I know which one just makin sure
This is for my sister
______________________ is the body's normal reaction to help the body return to a more stable temperature when a person is really cold.
pacing
walking
shivering
freezing
Answer:
shivering raises your body temperature
A cannon shoots a 40 kg ball at a sailing ship and when it hits the
wall of the vessel it applies 2000N of force. How much was it
decelerated?
Answer:
ANSWER : 2000 / 40 = 50 m / s
Name at least two other viruses that are at all time lows due to vaccines.
A 40.0-kg football player leaps through the air to collide with and tackle a 50.0-kg player heading toward him, also in the air. If the 40.0-kg player is heading to the right at 9.0 m/s and the 50.0-kg player is heading toward the left at 2.0 m/s, what is the speed and direction of the tangled players
Answer:
The speed and direction of the tangled players is 2.89 m/s towards right.
Explanation:
Given;
mass of the player heading right, m₁ = 40 kg
initial velocity of the player heading right, u₁ = 9.0 m/s
mass of the player heading left, m₂ = 50 kg
initial velocity of the player heading left, u₂ = -2.0 m/s
let the speed of the tangled players = v
Apply the law of conservation of linear momentum;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(40 x 9) + (50 x - 2) = v(40 + 50)
360 - 100 = v(90)
260 = v(90)
v = 260 / 90
v = 2.89 m/s (towards right, since it is in position direction)
Therefore, the speed and direction of the tangled players is 2.89 m/s towards right.
what is the name of first magnet
Answer:
[tex]magnetite[/tex]
[tex]hope \: helps...[/tex]
A rectangular tank 6 m long and 3 m wide contains water up to a depth of 2.5 m.
Calculate the pressure and resultant hydrostatic force on the base of the tank.
Answer:
P = 24525 [Pa]
Explanation:
The pressure at the bottom of any vessel can be determined, only by knowing the depth or height of the liquid level. By means of the following equation.
[tex]P=Ro*g*h[/tex]
where:
P = pressure [Pa]
Ro = density of the water = 1000 [kg/m³]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 2.5 [m]
Now replacing:
[tex]P=1000*9.81*2.5\\P=24525 [Pa][/tex]
What is the difference between Helium3, and Helium?
Explanation:
Helium is the type of atom, with 2 protons in the nucleus.
He-3 (which is the proper form), is an isotope of helium that has an atomic number of 3 (so 2 protons and 1 electron).
The most abundant helium isotope is He-4, just an extra fact.
If an object at the surface of the Earth has a weight Wt, what would be the weight of the object if it was transported to the surface of a planet that is one-sixth the mass of Earth and has a radius one third that of Earth
Answer:
We know that the gravitational acceleration in the surface of the Earth can be written as:
g = G*M/r^2
Where:
M = mass of the Earth
r = radius of the Earth.
G = gravitational constant.
The weight of an object of mass m, is written as:
W = m*g = m*(G*M/r^2)
Now, if we move our object to a place that has a mass equal to 1/6 times the mass of the Earth, and 1/3 the radius of the earth.
The gravitational acceleration on this planet is written as:
g' = G*(M/6)/(r/3)^2 = (1/6)*(G*M)/(r^2/9) = (9/6)*(G*M/r^2) = (3/2)*g
then the weight on this planet is:
W' = m*g' = m*(3/2)*g = (3/2)*(m*g)
and m*g was the weight on Earth, then:
W' = (3/2)*(m*g) = (3/2)*W
The new weight is 3/2 times the weight on Earth.
What type of lever has the fulcrum between the resistance arm and the effort arm?
A) type 3 lever
B) type 2 lever
C) none of these
D) type 1 lever
E) type 4 lever
The world’s largest wind turbine has blades that are 80 m long and makes 1 revolution every 5.7 seconds.
What is the velocity for one of the blades?
(THIS IS PHYSICS, CIRCULAR MOTION)
Answer:
88.14 m/s
Explanation:
From the question given above, the following data were obtained:
Radius (r) = length of blade = 80 m
Revolution (rev) = 1
Time (t) = 5.7 s
Velocity (v) =?
The velocity of the blade can be obtained by using the following formula:
v = (rev × 2πr) / t
NOTE: Pi (π) = 3.14
v = (1 × 2 × 3.14 × 80) / 5.7
v = 502.4 / 5.7
v = 88.14 m/s
Therefore, the velocity of the blade is 88.14 m/s
Are vaccines 100% effective and safe for absolutely everyone?
A military jet cruising at an altitude of and speed of burns fuel at the rate of . How would you calculate the amount of fuel the jet consumes on a mission
Answer:
Calculate the time (in minutes) that it would take for the jet to cover the distance at the given speed.Multiply the time with the rate of burning of fuel by the jet.Explanation:
A military jet cruising at an altitude of 12.0 km and speed of 1200 km/h burns fuel at the rate of 80.1 L/min. How would you calculate the amount of fuel the jet consumes on a 750 km mission?
In order to calculate the amount of fuel that would be consumed, first, there is a need to find the time it will take to complete the 750 km mission.
Recall that: speed = distance/time, at a speed of 1200 km/h, the time taken to cover a distance of 750 km would be;
time = distance/speed
= 750/1200 = 0.625 h
The rate of fuel burning is 80.1 Liters in a minute, there are 60 minutes in 1 hr;
1 hr = 60 minutes
0.625 h = 0.625 x 60 = 37.5 minutes
It takes 37.5 minutes to cover 750 km and the fuel burning rate is 80.1 liters per minute, hence, the amount of fuel consumed by the jet would be;
80.1 x 37.5 = 3000 liters
6/7 and 24/28 what is the answer proportion or no
Given that,
6/7 and 24/28
To find,
The above number are in proportion or not.
Solution,
First number is 6/7
Other number is 24/28
Multiply numerator and denominator by 4 to the first number.
[tex]\dfrac{6}{7}=\dfrac{6}{7}\times \dfrac{4}{4}\\\\=\dfrac{6\times 4}{7\times 4}\\\\=\dfrac{24}{28}[/tex]
So, 6/7 and 24/28 are in proportion.
Fraction A is proportional to fraction B because the value of fraction A is equal to fraction B.
Given the following data:
Fraction A = [tex]\frac{6}{7}[/tex]Fraction B = [tex]\frac{24}{28}[/tex]In this exercise, you're required to determine whether or not the two fractions are proportionate i.e whether fraction A is proportional to fraction B.
Two fractions are considered to be proportionate when the value of fraction A is equal to fraction B.
We would write fraction B in its simplest form by dividing both the numerator and denominator by their highest common factor (HCF).
HCF of 24 and 28 = 4.
Dividing by 4, we have:
[tex]Fraction\;B =\frac{24}{28}=\frac{6}{7}[/tex]
In conclusion, fraction A is proportional to fraction B because the value of fraction A is equal to fraction B.
Read more: https://brainly.com/question/18676621
How many hours are in a full day and night? I have been told 24 hrs but is that right?
Answer:
its 24 hours
Explanation:
12 hours during the night and 12 hours during the day
Yes that's right...did anyone tell you something else?
Order the layers, with the oldest at the bottom and most recent at the top.
someone plz help will give brainliest if correct
Answer:
adbce i think
Explanation:
What is the first step in the event of a fire in a building?
A) Call 911.
B) Before opening a door, check to see if it is hot.
C) Stop, drop, and roll.
D) Leave the building quickly, if possible.
Answer:
B or C
Explanation:
i don't if I'm right or not
Anyone can help?? I need it done before 9am please!!
Answer:
The answer is below
Explanation:
The equation for a linear line graph is given by:
y = mx + b, where y and x are variables, m is the slope of the graph and b is the y intercept (that is value of y when x is zero).
The slope (m) of a line passing through two points [tex](x_1,y_1)\ and\ (x_2,y_2)[/tex] is given by:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
A) The first line passes through the point (0, 0) and (10, 60). It is represented as (time, velocity). Hence the slope is:
[tex]m=\frac{60 -0}{10-0}=6\ m/min^2[/tex]
B) The second line passes through the point (10, 60) and (15, 60). Hence the slope is:
[tex]m=\frac{60 -60}{15-10}=0\ m/min^2[/tex]
C) The third line passes through the point (15, 60) and (40, -40). Hence the slope is:
[tex]m=\frac{-40 -60}{40-15}=-4\ m/min^2[/tex]
D) The third line passes through the point (40, -40) and (55, 0). Hence the slope is:
[tex]m=\frac{0 -(-40)}{55-40}=2.67\ m/min^2[/tex]
A weight lifter lifts a 250 Newton weight up 1.5 meters. How much work did they do?
Answer:
375 J
Explanation:
Work done is the product of force and distance moved by the object.
W=F*d
Given that ;
Force= F= 250 N
Distance= d =1.5 m
W= 250 * 1.5 =375 J
Suppose you have an object tied to a rope and are rotating it over your head in uniform circular motion. What would have to do to the rope length in order to cut the centripetal force in half
Answer:
We must duplicate the length of the rope (R'=2R) to get
[tex]F'=\frac{1}{2}F[/tex]
Explanation:
The equation of the centripetal force is given by:
[tex]F_{c}=ma_{c}[/tex]
[tex]F_{c}=m\frac{v^{2}}{R}[/tex]
Where:
R is the length of the rope
m is the mass of the object
v is the speed of the object
If we want to reduce the centripetal force in half, we can duplicate the length of the rope (R'=2R), which means:
[tex]F'_{c}=m\frac{v^{2}}{R'}[/tex]
[tex]F'_{c}=m\frac{v^{2}}{2R}[/tex]
[tex]F'_{c}=\frac{1}{2}F_{c}[/tex]
I hope it helps you!
The PE of an object is 2500 j. What is the mass of the object if it 4.0 m above the ground?
Answer:
The answer is 5.0
Explanation:
Hope that helped :D
Water enters a shower head through a pipe of radius 0.0112 m at 3.25 m/s. What is it’s volume flow rate? (Unit= m^3/s)
Answer:
[tex]1.28 \times 10 ^{-3} m^3/s[/tex]
Explanation:
Given that the radius of the pipe, r =0.0112 m
So, the area of the cross-section, [tex]a= \pi (0.0112)^2 = 3.941\times 10^{-4} m^2[/tex]
Speed of water in the pipe, v=3.25 m/s
Volume flow rate =[tex]av= 3.941\times 10^{-4} \times 3.25 = 1.28\times 10 ^{-3} m^3/s[/tex]
Hence, the volume flow rate is [tex]1.28 \times 10 ^{-3} m^3/s[/tex]
Answer:
For Acellus the answer is 0.00128
Explanation:
Trust me
A 5 kg ball is dropped from a height of 200 meters on Earth.
a) What is the ball’s potential energy at its original height?
Answer:
9800 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 5 kg
Height (h) = 200 m
Potential energy (PE) =?
Potential energy (PE) is the energy stored in an object by virtue of its location. Mathematically, it is expressed as:
PE = mgh
Where:
PE => is the potential energy.
m => is the mass of the object.
g => is the acceleration due to gravity.
h => is the height to which the object is located.
With the above formula, we can obtain the potential energy of the ball at its original height as follow:
Mass (m) = 5 kg
Height (h) = 200 m
Acceleration due to gravity (g) = 9.8 m/s²
Potential energy (PE) =?
PE = mgh
PE = 5 × 9.8 × 200
PE = 9800 J
Therefore, the potential energy of the ball at its original height is 9800 J
A free falling asteroid is experiencing a force of gravity of 903 newtons. How much work, in joules, does gravity do on the asteroid over a distance of 126 meters?
Answer:
Workdone = 113778 Joules
Explanation:
Given the following data;
Force = 903N
Distance = 126m
To find the workdone;
Workdone = force * distance
Substituting into the equation, we have
Workdone = 903 * 126
Workdone = 113778 Joules
Therefore, the amount of work, in joules, the gravity did on the asteroid is 113778.
A cat swats a ball on the coffee table. The ball rolls horizontally off the edge of a table. Which statement is true?
A. The balls horizontal velocity changes at the rate of 9.8 meters/second every second.
B. As the ball falls to the ground, it moves along a parabolic path.
C. No external vertical forces acts on the ball.
D. The ball had a constant vertical velocity.
Answer:
D
Explanation:
1. What is the value of the acceleration that the car experiences? 2. What is the value of the change in velocity that the car experiences? 3. What is the value of the impulse on the car? 4. What is the value of the change in momentum that the car experiences? 5. What is the final velocity of the car at the end of 10 seconds? The car continues at this speed for a while. 6. What is the value of the change in momentum the car experiences as it continues at this velocity? 7. What is the value of the impulse on the car as it continues at this velocity? The brakes are applied to the car, causing it to come to rest in 4 s. 8. What is the value of the change in momentum that the car experiences? 9. What is the value of the impulse on the car? 10. What is the value of the force (average) that causes the car to stop? 11. What is the acceleration of the car as it stops?
Answer:
All the answers are solved and explained below.
Explanation:
Note: This questions lacks the initial and most necessary data to answer these following questions. I have found a related question. I will be considering that question to carry out the answers.
Question: A car with a mass of 1000 kg is at rest at a spotlight. when the light turns green, it is pushed by a net force of 2000 N for 10 s. (This was the information missing in this question).
Data Given:
m = 1000 kg
F = 2000N
t = 10s
Q1 Solution:
Acceleration = a = ?
F = ma
a = F/m
a = 2000/ 1000
a = 2 [tex]m/s^{2}[/tex]
Q2: Solution:
Change in velocity = Δv = ?
acceleration = change in velocity / time
a = Δv/t
Δv = axt
Δv = 2 x 10
Δv = 20 m/s
Q3: Solution:
Impulse = I = ?
Impulse = Force x time
I = 2000 x 10
I = 20000 Ns
Q4: Solution:
Change in Momentum = Δp = ?
Δp = mΔv
Δp = 1000 x 20
Δp = 20000 Kgm/s
Q5: Solution:
Final velocity of the car at the end of 10 seconds = vf = ?
Δp = m x Δv
Δp = m x (vf-vi)
Δp = 1000 x (vf - 0 )
20000 = 1000 x vf
vf = 20000/1000
vf = 20 m/s
Q6: Solution:
Change in momentum the car experiences as it continues at this velocity?
Δp = ?
Δp = mΔv
Δp = m x (0)
Δp = 0
Q7: Solution:
Impulse = Change in momentum
Impulse = Δp
Implulse = 0
Q8: Solution:
Change in momentum = Δp = mΔv
Δp = m(vf-vi)
Δp = 1000 x (0-20)
Δp = -20000 kgm/s
Q9: Solution:
Impulse = Δp
Impulse = -20000 Ns
Q10: Solution:
Impulse = ?
Impulse = F x t
F = impulse/t
F = -20000/4s
F = -5000 N
Q11: Solution:
F = ma
a = ?
a = F/m
a = -5000/1000
a = -5[tex]m/s^{2}[/tex]
8 th Grade Physical Science Worksheet Part A: Read the scenario and answer the questions. David read that Fox brake pads and Best Brake pads were the best on the market. He always used NAPA pads and believed they performed the best. He decided to test all three pads and determine which was the best. David used the same car for each set of pads. He drove 25 mph and applied the brakes at the same point on the track. David then measured how many feet the car took to stop after the brakes were applied. 1. The hypothesis was: 2. The effects of the ________________(independent variable) on the __________________________________ (dependent variable). 3. List three constants:
ITS ACTUALLY ASTRONOMY
What is the name for a star that has two shells of hydrogen and helium undergoing fusion?
A. asymptotic giant branch star
B.Supergiant
C. hypergiant
D. supernova
*please help thx*
Answer:
A. Asymptotic giant branch star
Explanation:
Hope this helped.
Answer:
asymptotic giant branch star
Explanation:
Plato/Edmentum
The Sun does NOT rotate the way Earth does. Which statement best describes the difference in their rotations?
A
The Sun had different periods of rotation at different latitudes.
B
The Sun does NOT rotate.
C
The Sun rotated in different directions of rotation at different latitudes.
D
The Sun rotates in the opposite direction from Earth's rotation