The atomic mass of an element is:
A. The number of protons and electrons
B. The number of protons and neutrons

Explanation:

"Compound: A substance that is made up of more than one type of atom bonded together. 

Mixture: A combination of two or more elements or compounds which have not reacted to bond together; each part in the mixture retains its own properties."

- Libre Texts

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Answer:

Explanation:

Sodium and Iodine are in columns 2 and 17. They will be ionic.

Copper and oxygen will be ionic. Oxygen is a powerful receiver of electrons.

Magnesium and Chlorine same answer as the first one.

Carbon and Sulfur. Not so much. They do not form an ionic bond. They are basically closer to being two non metals.

Answer:

Explanation:

What occurs here (the description in the question) is condensation. Condensation is the process in which water changes from it's gaseous state (steam) to it's liquid state. When the hot air leaves the oven, and it touches/ passes through the glasses of John (that is of a lower thermal energy), the hot air would lose some of it's thermal energy (due to the lower thermal energy of the glasses) and then transits back to liquid forming the visible fog steam on the glasses.

Answer:

Yes

Explanation:

A krypton atom will remain the same despite changing the number of neutrons they contain.

The neutron is a nuclear particle found within an atom.

Answer:

They need more oxhygen to fraction to incresse

Explanation:

Answer:

0.45 grams of hydrogen and 3.53 grams of oxygen will be formed, when 4.05 grams of water is used.

Explanation:

The given reaction is [tex]2H_20 \rightarrow 2H_2 + O_2[/tex]

2 moles of [tex]H_2O[/tex] is used to form 2 moles of [tex]H_2[/tex] and 1 mole of [tex]O_2[/tex]

As 1 mole of [tex]H_2O=18 g[/tex], 1 mole of [tex]H_2=2 g[/tex], and 1 mole of [tex]O_2=32 g[/tex].

So, 36 grams of [tex]H_2O[/tex] is used to form 4 grams of [tex]H_2[/tex] and 32 grams of [tex]O_2[/tex]

Therefore, 1 gram of [tex]H_2O[/tex] is used to form 4/36 grams of [tex]H_2[/tex] and 32/36 grams of [tex]O_2[/tex]

Therefore, 4.05 gram of [tex]H_2O[/tex] is used to form (1/9)4.09=0.45 grams of [tex]H_2[/tex] and (8/9)4.05=3.53 grams of [tex]O_2[/tex].

Hence, 0.45 grams of hydrogen and 3.53 grams of oxygen will be formed, when 4.05 grams of water is used.

Answer:

just multiply 18.6 to molar mass of cuso4.5h20

Explanation:

if you have any doubt comment

Answer: Hello! I do believe the answer is A.

Explanation: please mark me brainliest! hope this helps

Answer:

B

Explanation:

Answer:

Ion exchange.

Explanation:

One of the ways in which water can be treated is through the process known as ION EXCHANGE. Using this for treating water has to do basically with the transfer or say the exchange of ions.

Ion exchanges is done by exchanging ions which are considered as 'unfit' or contaminants by the ones that are "fit".

Ions from what is known as zeolite or resin is been exchanged with the ions in the water. Cations are exchanged with cations and anions are exchanged with anions.

NB: this method is a good method or removing contaminants that are ions but not contaminants that are not ions.

Answer:

Q8) True

Q9) First ionization energy

Q10) A metal oxide

Explanation:

One of the properties of group one elements (alkali metals) is that they combine with water to form basic solutions. E.g 2Na(s)+2H2O(l)→2NaOH(aq)+H2​(g).

An inverse relationship exists between the distance of the outermost electron in the atom from the nucleus and the first ionization energy. As the distance between the outermost electron and the nucleus in group 17 elements increases, their first ionization energies decreases accordingly.

Group 1 elements react with oxygen to yield the corresponding metal oxides. E.g  4 Na + O2 --> 2 Na2O

Answer:

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Explanation:

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Answer:

[CH3NH3]+ +OH- ----> CH3NH2 +H2O

Answer:

H=mc∆T

H=15×4.18×20

H=1254J

Answer:

Explanation: I saw that you answered someone else's same question with toothpaste. What toothpaste did you use?

Answer:

When balancing redox reactions under acidic conditions in aqueous solution, oxygen is balanced by adding water as much as oxygen we have, on the opposite side, where the oxygens are.

Explanation:

We can see this redox balance, in order to determine what we said.

The unbalanced reaction is: MnO₂  +  HCl  →  MnCl₂ + Cl₂ + H₂O

The HCl determines, we are in acidic conditions.

We need to determine the half reactions:

Mn⁴⁺  →  Mn²⁺  (In this case, the oxidation number decreased)

This is the reduction. Mn caught 2 electrons

Mn⁴⁺  + 2e⁻  →  Mn²⁺

Cl⁻ → Cl₂

In ground state, the oxidation number is 0. The chloride was oxidized to chlorine. As Cl is a dyatomic molecule, we need 2 chlorides to balance so finally it released 2 electrons. This is the oxidation (ox. number has increased) 2Cl⁻ → Cl₂ + 2e⁻

Mn⁴⁺  + 2e⁻  →  Mn²⁺

2Cl⁻ → Cl₂ + 2e⁻

Mn⁴⁺  + 2Cl⁻ →  Mn²⁺ + Cl₂

Now we balance the oxygen. In reactant side, we have 2, so we complete with 2 water in the product side. We add water as much as oxygen we have, on the opposite side, where the oxygens are. (If we have 2 oxygen in reactant side, and we have 1 water, we need 1 more water)

So, as we added 2 H₂O, we complete with protons, on the opposite side

Mn⁴⁺  + 4H⁺  + 4Cl⁻ →  Mn²⁺ + 2Cl⁻ + Cl₂ + 2H₂O

(Notice, we had 2Cl⁻, but globally we have 4H⁺. At least, we have 4HCl)

The balanced equation is: MnO₂  + 4HCl →  MnCl₂ + Cl₂ + 2H₂O

Answer:

Mn

Explanation:

The cation in the chemical formula MnSe is the Mn specie.

The catalytic effects 'lower temperatures and pressures can be used' would be most beneficial for the oil industry.

A catalyst is a chemical substance that has the potential to speed up the velocity if a particular reaction.

In conclusion, the catalytic effects 'lower temperatures and pressures can be used' would be most beneficial for the oil industry.

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Answer:

B

Explanation:

Answer:

The mass of ammonia (NH3) that contains [tex]1.00 \times 10^12[/tex] hydrogen atoms is [tex]9.4\times 10^{-12}[/tex] g.

Explanation:

As [tex]6.022\times 10^{23}[/tex] atoms of hydrogen = 1 mole of the hydrogen atom

Therefore, [tex]10^{12}[/tex] atoms of hydrogen [tex]= \frac{1}{6.022 \times 10^{23}}\times 10^{12}=1.66\times 10^{-12}[/tex] moles of the hydrogen atom.

Now, there are 3 moles of hydrogen atoms in 1 mole of ammonia [tex](NH_3)[/tex].

As the mass of 1 mole of ammonia is 17g, so

when there are 3 moles of hydrogen atoms, then the mass of ammonia = 17 g

Therefore, when there are [tex]1.66\times 10^{-12}[/tex] moles of hydrogen atoms, then the mass of ammonia [tex]= \frac{17}{3}\times 1.66\times 10^{-12}=9.4\times 10^{-12[/tex] g.

Hence, the mass of ammonia [tex](NH_3)[/tex] that contains [tex]1.00 \times 10^12[/tex] hydrogen atoms is [tex]9.4\times 10^{-12}[/tex] g.

The mass of Ba(CIO₃)₂ : 121.72 g

Reaction

Ba(OH)₂ + 2HCIO₃ ----> Ba(CIO₃)₂ + 2H₂O

Limiting reactant :

Ba(OH)₂ : 2HCIO₃ =

mol Ba(CIO₃)₂ based on limiting reactant(HCIO₃) :

[tex]\tt \dfrac{1}{2}\times 0.8=0.4[/tex]

MW Ba(CIO₃)₂ =Ba+2.Cl+6.O=137.3 + 2 x 35.5 + 6 x 16 = 304.3

mass of Ba(CIO₃)₂ :

[tex]\tt mass=mol\times MW\\\\mass=0.4\times 304.3=121.72~g[/tex]

Answer:

26.5 is your answer thank you

Answer:

There are 58 people in the cinema.

Explanation:

This number is actually exact and not subject to sig, digit rules.

The displacement of the child : A. 0 m

Distance is a scalar quantity that indicates the length of the trajectory that is traveled by an object within a certain interval. Distance has no direction, only has a magnitude

Can be simplified distance = total meters traveled

Displacement is a vector quantity that shows changes in the position of objects in a certain interval of time. Displacement has magnitude and direction

Can be simplified displacement = distanced traveled from starting point to ending point

So the displacement of the child : 0 m

and the distance = the circumference of the rectangle :

[tex]\tt =2(l+W)\\\\=2(475+411)\\\\=1772~m[/tex]

Answer:

160 g

Explanation:

The chemical equation is:

C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(g)

According to the equation, 1 mol of glucose (C₆H₁₂O₆) reacts with 6 moles of O₂. We calculate the masses of the reactants from the molar masses of the chemical elements:

1 mol C₆H₁₂O₆ = (6 x 12 g/mol)+ (12 x 1 g/mol) + (6 x 16 g/mol) = 180 g

6 mol O₂ = 6 x (2 x 16 g/mol) = 6 x 32 g/mol = 192 g

So, 180 g of C₆H₁₂O₆ reacts with 192 g of O₂. The stoichiometric ratio is 192 g O₂/180 g C₆H₁₂O₆. To calculate the grams of O₂ needed to react with 150 g of C₆H₁₂O₆ we can simply multiply the stoichiometric ratio by the grams of C₆H₁₂O₆:

150 g C₆H₁₂O₆ x 192 g O₂/180 g C₆H₁₂O₆ = 160 g O₂

Therefore, 160 grams of O₂ are needed to fully react with 150 g of glucose.

Moles H₂ needed = 52.2

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

N₂(g)+3H₂(g)⇒2NH₃(g)

From the reaction equation above, the reaction coefficient shows the mole ratio of reagents and products

moles NH₃ produced = 34.8

mol H₂: moles NH₃ = 3: 2, so moles H₂ :  

[tex]\tt moles~H_2=\dfrac{coefficient~H_2}{coefficient~NH_3}\times moles~NH_3\\\\moles~H_2= \dfrac{3}{2}\times 34.8=52.2[/tex]

The difference about the presence of water on Earth that sets it apart from the other inner planets is that either the planet is too hot that the water vaporizes or too cold that the water freezes.

The primary components of inner planets, commonly referred to as terrestrial planets, are rocks and metals. In comparison to the outer planets, they are modest in both size and shape. They have a molten metal core and a solid surface. The Solar System's four innermost planets are as follows (Mercury, Venus, Earth, and Mars).

Most importantly, since the temperature permits liquid water to exist for long periods of time, Earth is unique in that the majority of our planet is covered with liquid water.

Only the Earth possesses liquid water because all the other planets and moons are either too hot or too cold, causing any water that may be present to boil away or freeze.

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The percent yield : 4. 84.58%

Reaction

CaCO₃ ⇄ CaO+CO₂

mass CaCO₃ = 2.3 × 10³ g

mol CaCO₃ (MW=100.0869 g/mol) :

[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{2.3\times 10^3}{100,0869}\\\\mol=22.98[/tex]

From the equation, mol CaCO₃ : CaO = 1 : 1, so mol CaO=22.98

mass CaO(MW=56.0774 g/mol)⇒ (theoretical) :

[tex]\tt mass=mol\times MW\\\\mass=22.98\times 56,0774\\\\mass=1288.659~g[/tex]

The percent yield :

[tex]\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{1090}{1288.659}\times 100\%\\\\\5yield=84.58\%[/tex]

Moles of potassium permanganate = 0.0008

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range  

Reaction

5Na2C2O4(aq) + 2KMnO4(aq) + 8H2SO4(aq) ---> 2MnSO4(aq) + K2SO4(aq) + 5Na2SO4(aq) +  10CO2(g) + 8H2O(1)

The end point ⇒titrant and analyte moles equal

titrant : potassium  permanganate-KMnO4

analyte : sodium oxalate - Na2C2O4

so moles of KMnO4 = moles of Na2C2O4

moles of Na2C2O4(mass = 0.2640 g, MW=134 g/mol) :

[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{0.264}{134 g/mol}\\\\mol=0.002[/tex]

From equation, mol ratio  Na2C2O4 : KMnO4 = 5 : 2, so mol KMnO4 :

[tex]\tt \dfrac{2}{5}\times 0.002=0.0008[/tex]