The five number summary of a dataset was found to be:
45, 50, 57, 65, 70

Option 2. The description of the rigid motion transformation would be the dilation of the figure by the scale factor of 1/2.

The term rigid motion transformation has to do with the fact that when an object is moved the size and the shape of the object would still have to stay the same. This is different for the non rigid motion. This because the size and the shape would have to increase in this case.

When the object is moved from one area to the other and it remains the same then we would have to say that the rigid transformation has occurred.

Hence we would have to say that Option 2. The description of the rigid motion transformation would be the dilation of the figure by the scale factor of 1/2.

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Answer: -12x+8y

Step-by-step explanation:

Based on the given conditions, formulate: (-9x+3y)+(-3x+5y)

Determine the sign: -9x+3y-3x+5Y

Combine like terms: -12x+8y

A number between 67 and 113 which is a multiple 4, 6 and 9 is 108

In this question, Greg must choose a number between 67 and 113 that is a multiple 4, 6 and 9.

We need to find the numbers which follow above conditions.

First we find the numbers between 67 and 113 that is a multiple 4.

68, 72, 76, 80, 84, 88, 92, 96, 100, 104, 108, 112

the numbers between 67 and 113 that is a multiple 6 are:

72, 78, 84, 90, 96, 102, 108

the numbers between 67 and 113 that is a multiple 9 are:

72, 81, 90, 99, 108

We can observe that a common number between 67 and 113 which is a multiple 4, 6 and 9 is 108

Therefore, a number between 67 and 113 which is a multiple 4, 6 and 9 is 108

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Answer:

$560.33

Step-by-step explanation:

Hotel: 79.95*2*2=$319.8

Dinner: 182-50=$132

Breakfast:

Rental:

Hotel+dinner+breakfast+rental: 319.8+132+35.09+73.44=$560.33

The required simplified value of the given expression is  6 / 35m² - 1/4. Option C is correct.

To determine the simplified value of the negative three-fifths times m times quantity negative two-sevenths times m minus one-fourth end quantity.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
negative three-fifths times m times quantity negative two-sevenths times m minus one-fourth can be interpreted as,
= -3/5m *  - 2/7m - 1/4
= 6 / 35m² - 1/4

Thus, the required simplified value of the given expression is  6 / 35m² - 1/4. Option C is correct.

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Answer:

x=3 and her is right

Answer whyyyy

Step-by-step explanation:

Answer:

hello! it's all explained in the photo :)

Step-by-step explanation:

Answer:

That means you would only be able to fit 11 cases since 8 × 11 = 88. Any more cases would exceed 90 items.

Step-by-step explanation:

The number which represents the situation of a withdrawal of $36 is -$36.

In this question, we have to find out the number or integer which represents the situation of a withdrawal of $36. This question is from integers topic and for that we should have the definition of integers in our mind. So, an integer is defined as number which can be represented without the fractional form. It contains whole numbers and negative of natural numbers. The integers are generally denoted by the symbol 'Ζ'. And, the integers can be negative or positive.

In this question we have asked withdrawal of $36 from any source. So, withdrawal basically means money will decrease, so it will become negative.

To represent a withdrawal of $36, we will use the negative sign.

Hence, -$36 is the correct representation of the situation of a withdrawal of $36.

Therefore, -$36 is the required answer.

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The two inequalities that can be used to find the solution are x-1 < 3 and x-1 > -3.

The given inequality is 3 + 2|x-1| < 9.

The absolute value |x-1| can be (x-1) or -(x-1).

We need to solve this inequality for this two cases.

So first if |x-1| = (x-1), then,

3 + 2|x-1| < 9

⇒ 3 + 2(x-1) < 9

⇒ 2(x-1) < 6

⇒ x-1 < 3

⇒ x < 4 is the solution.

Now if |x-1| = -(x-1), then,

3 + 2|x-1| < 9

⇒ 3 - 2(x-1) < 9

⇒ -2(x-1) < 6

⇒ -(x-1) < 3  

⇒ x-1 > -3  [When multiplied with (-1), the inequality reverses]

⇒ x > -2 is the solution.

Going through these steps, we can conclude that the two inequalities that can be used to find the solution to the absolute value inequality,

3 + 2|x-1| < 9 are x-1 < 3 and x-1 > -3.

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3.0 CUBIC YARDS I WILL NEED TO ORDER TO PUT A 2 INCH THICK LAYER OF TOPSOIL

As a result, the problem gives you the volume of the space you are trying to fill with soil ( 20ft by 24ft by 2 in). Let's measure everything in feet first, and then we can measure the volume in yards. You may acquire a volume of approximately (rounding to two decimal places)80.00  cubic feet by converting 2 inches to feet, or 2/12. Then, to obtain your volume, multiply that by 20 times 24. Since there are 3 feet in 1 yard, we divide this volume in yards by 3, giving us 3.0 cubic yards. You will need 3.0 cubic yards if the business only sells in 1/4 cubic yard increments.

V = (20')(24')(2'/12)

V = 80f[tex]t^{3}[/tex]

1 [tex]yd^{3}[/tex] = 27 [tex]ft3[/tex]

80[tex]ft3[/tex] / 27[tex]ft3[/tex] ≈ 3.0

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The solution of the given inequality |x - 7| + 8 < 11 is  4 < x < 10.

In mathematics, an inequality is an interaction between two expressions as well as values which are not equitable to each other. Inequality results from a lack of balance.

As per the given relation;

|x - 7| + 8 < 11

Subtract both side by -8.

|x - 7| + 8 - 8 < 11 - 8

|x - 7|  < 3

Removing modulus will give the relation as;

- 3 < x - 7 < 3

Add 7 on both side.

- 3 + 7 < x - 7 + 7 < 3 + 7

4 < x < 10

Thus, the solution of the x lied between 4 and 10 with the condition that;

4 < x < 10.

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The numbers that can divide 648 evenly, using the divisibility tests, include 1, 2, 3, 4, 6, 8, 9, 12, and 18 and some multiples of any two numbers.

A divisibility test is performed to identify whether a number can be divided evenly by a fixed divisor without a remainder and without actually performing the division process.

Divisibility by 1: Every number is divisible by 1 = 648 (648/1).

Divisibility by 2: 648 is an even number and divisible by 2 = 324.

Divisibility by 3: Sum the digits (18). 18 is divisible by 3 = 6 (18/3).

Divisibility by 4: The last two digits (4 and 8) form a number (12) that is divisible by 4

Divisibility by 6:  It is divisible by 2 and by 3

Divisibility by 8: If the hundreds digit is even, the number formed by the last two digits must be divisible by 8.

Divisibility by 9: Sum the digits (18). 18 is divisible by 9

Divisibility by 12: 648 is divisible by 3 and by 4.

Divisibility by 18: 648 is divisible by 2 and by 9.

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Answer:

172.63

Step-by-step explanation:

First let's write the problem as an expression

56.6% * 305

Let's convert 56.6 to a decimal

0.566% * 305

Now finish by multiplying

0.566% * 305
172.63

Answer:

4

Step-by-step explanation:

First let's begin at the top of the fraction, 18+6

18+6
24

Now let's look at the bottom of the fraction, 3*2

3*2
6

We now have 24/6, so we will simplify the fraction to get our answer by dividing 24 by 6

24/6
4

283,000 newspaper copies will be distributed among the 13 cities evenly.

Out of the four basic mathematical operations, division is frequently regarded as the most challenging. Once we fully comprehend the procedure and guidelines, we can use a calculator without error to perform increasingly challenging calculations.

We can divide or "share" numbers using division to arrive at an answer. Take 10 ÷  2 as an example. How would we arrive at the solution? (ten divided by two). This is equivalent to "sharing" 10 candies between 2 kids. The total quantity of candies that each child receives must be the same. The solution in this instance is 5.

No. of newspaper circulated a day = 3,679,000

No. of cities to be distributes among = 13

No. of newspaper a city will receive = 3,679,000/ 13

                                                            = 283,000

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Answer:  R=PV/nT

Step-by-step explanation:

PV=nRT

divide both sides by nT

PV/nT =nRT/nT

R=PV/nT

i hope this was helpful

The given equation solved for R has R=PV/nT.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

The given equation is PV=nRT.

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.

Now, R=PV/nT

Therefore, the given equation solved for R has R=PV/nT.

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answer:

[tex] \frac{6}{5} [/tex]

Answer:

i also can't at all

Step-by-step explanation:

This is hard for me

The weight of the trout is 6.17 pounds.

We know that the weight of a trout varies jointly as its length and the square of its girth.

If W is the weight, x is the length and y is the girth, then:

W = k*x*y^2

Where k is a constant.

We know that one trout with:

x = 26 in

y = 18in

Has a weight of 10.5, then we can write:

10.5 = k*(26)*(18)^2 = k*8,424

Solving for k we get:

10.5/8,424 = k

Then the equation is:

W = (10.5/8,424)*x*y^2

Now, our trout has:

x = 22 in

y = 15 in

Then the weight is:

W =  (10.5/8,424)*22*15^2 = 6.17

The weight of the trout is 6.17 pounds.

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Answer:

3/10

Step-by-step explanation:

it is really simple just do 1/10+1/10+1/10=3/10

An example of a function is: The area of a square is a always a function of the length and width.

A counterexample of the function is: The area of a square is a function of the diagonal.

This a term used in mathematics to represent a mathematical relations. This is usually of three parts: the inputs, the output, and the relationship between them.

In the example the sides of the square is the input, the area is the output while the formula is the relationship.

Counter example is used to show a flaw in a mathematical statement where the conclusion is not in agreement with the statement.

In the given example providing a method of calculating area of squares using the diagonals counters the initial statement that has it that area of a square is a always a function of the length and width.

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smaller number = y

larger number = x

x - y = 69

4y = x + 3

you can solve this using substitution

x = 69 + y

(isolating one of the variables)

4y = 69 + y + 3

(substituting 69 + y for x into the other equation)

4y = 72 + y

3y = 72

y = 24

(simplify)

x - 24 = 69

x = 93

(substituting 24 into one of the original equations)

Answer:  2

Step-by-step explanation:

[tex]\sqrt{\frac{36}{9} }[/tex]=

[tex]\frac{\sqrt{36}}{\sqrt{9}}[/tex]=

6/3=2

The answer is 2. I have no explanation because I searched it up at a website.

Answer:

Expression for f(x) = [tex]\frac{\sqrt{x + 1} - 4}{7}[/tex]

Domain in interval notation: [tex]\:[-1,\:\infty \:)[/tex]

Step-by-step explanation:

[tex]\textrm{Let }f(x)\text{ represent the function}[/tex]

Step 1: Add 1 to [tex]x[/tex]  ==>   x + 1

Step 2: Take square root ==> [tex]\sqrt{x+1}[/tex]

Step 3: Subtract 4: ==>  [tex]\sqrt{x+1} - 4[/tex]

Step 4: Divide by 7 ==> [tex]\frac{\sqrt{x+1} - 4}{7}[/tex]

The expression for f(x) is [tex]\frac{\sqrt{x+1} - 4}{7}[/tex]

The domain of a function is the set of all inputs  for which the function is real and defined

[tex]\sqrt{x+1}[/tex] is real only for positive values of the square root

This means

[tex]\sqrt{x+1} \ge 0[/tex]

Squaring both sides we get

[tex]x + 1 \ge 0[/tex]

Subtracting 1 from both sides we get

[tex]x \ge -1[/tex]

This is the lower limit for [tex]x.[/tex] There is no upper limit

The domain of[tex]f(x)[/tex] is therefore

[tex]x \ge -1[/tex]

In interval notation it is expressed as

[tex][-1,\infty)[/tex]

Note the square bracket on the left and parenthesis on the right. This notation means that -1 is part of the domain but [tex]\infty[/tex]  is not included since at [tex]\infty[/tex]  the function is not defined

Answer:

The answer is B

Step-by-step explanation:

Just look at the numbers, that is the only one with the correct range.

The scores on the test are centered around 66 and vary from 43 to 85. Therefore, the correct option  is option B.

Distributions are objects that generalise the traditional idea of functions used for mathematical analysis. They are often referred to as Schwartz distributions or generalised functions. Functions with no classically defined derivatives can be distinguished using distributions.

In the theory of partial differential equations, distributions are frequently utilised because it may be simpler to prove the existence of distributional solutions (weak solutions) rather classical solutions or because there may not be any suitable classical solutions. The scores on the test are centered around 66 and vary from 43 to 85.

Therefore, the correct option is option B.

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Answer:

Step-by-step explanation: you have to tell us how much money was made in order to find out how many of each

Answer: The location of P is -9

Step-by-step explanation: