the following four waves are sent along strings with the same linear densities (x is in meters and t is in seconds). rank the waves according to (a) their wave speed and (b) the tension in the strings along which they travel, greatest first:

Answers

Answer 1

(a) If we consider the waves to travel in a straight line (x = 0), according to their wave speed,

Wave A is the slowest wave and it travels at a speed of 0.5 meters per secondWave B is the next slow wave and it travels at a speed of 1 meter per second Wave C is the fastest wave and it travels at a speed of 2 meters per second Wave D is the fourth and final slow wave and it travel at a speed of 1.

(b) The waves are ranked according to the tension in the strings along which they travel, with the greatest first,

The waves with the lowest tension (wave A and C) travel along the strings with a lower linear density. Wave B travels along the string with a higher linear density, so it has greater tension. Wave D travels along the string with an even higher linear density, so it has even greater tension.

In waves, what does linear density mean?

The linear density of the string and the tension in the string both affect the wave's speed. The linear density is the mass divided by the string's length. In general, the square root of the ratio of the medium's elastic to inertial properties determines a wave's speed.

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Related Questions

Which component of a galaxy consists of tiny particles that look smoky or cloudy and
can be found in the space between stars?

Answers

Cosmic Dust.

Why? When stars explode, or die, they releases dust and gas.

To solve this we must be knowing each and every concept related to galaxy. Therefore, cosmic dust of a galaxy consists of tiny particles that look smoky or cloudy and can be found in the space between stars.

What is galaxy?

Galaxies are collections of stars as well as other celestial objects that are gravitationally bound. The cosmos contains and over 100 billion galaxies, each of which has stunning formations seen in photographs captured by telescopes of the far sky.

According to Samuel, a galaxy's shape is the result of continual interactions between its many components. The majority of the mass is provided by the dark matter, which uses gravity to hold everything together. Cosmic dust of a galaxy consists of tiny particles that look smoky or cloudy and can be found in the space between stars.

Therefore, cosmic dust of a galaxy consists of tiny particles that look smoky or cloudy and can be found in the space between stars.

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S A nonuniform electric field is given by the expression→E = ay i^ + bz j^ + cxk^where a, b , and c are constants. Determine the electric flux through a rectangular surface in the x y plane, extending from x=0 to x=w and from y=0 to y=h .

Answers

The electric flux is 2chω² where the k^ term was eliminated since k. k^ =0

The electric force per unit charge is referred to as the electric field. It is assumed that the field's direction corresponds to the force it would apply to a positive test charge. From a positive point charge, the electric field radiates outward, and from a negative point charge, it radiates in.

We are given an electric field in the general form

E→ =ay i^+bz j^+cx k^

In the xy plane z=0 so that the electric field reduces to

E→ =ay i^+cx k^

To obtain the flux, we integrate

ϕ E=∫ E→⋅d A→ =∫ (ay i^ +cx k^) ⋅k^

dAϕE=ch∫

x=0w

​xdx=2chω²

where the k^ term was eliminated since k. k^ =0

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A wire carrying a current I is bent into the shape of an equilateral triangle of side L. (a) Find the magnitude of the magnetic field at the center of the triangle.

Answers

The magnetic field at the center of the triangle is [tex]\frac{4.50 \mu_{0} I}{\pi L}[/tex].

An equilateral triangle with side L is formed by the bend of a wire carrying a current I.

The magnetic field created by a straight wire is given as:

[tex]B = \frac{ \mu_{0} I}{2 \pi a}[/tex]

The cosines of the complementary angles are identical to the sines of the angles that appear in that equation.

The magnetic field from a distance "a" from the wire,

We obtain:

[tex]tan{~}30^{\circ} = \frac{a}{L/2}\\a = 0.2887L[/tex]

Therefore, the  magnetic field at P which is the center of the triangle will be:

[tex]B = \frac{\mu_{0} I}{4 \pi a}(cos{~}\theta_{1} - cos{~}\theta_{2})[/tex]

[tex]B = \frac{\mu_{0} I}{4 \pi \times 0.2887L}(cos{~}30^{\circ} - cos{~}150^{\circ})[/tex]

[tex]B = \frac{\mu_{0} I \times 1.732}{\pi \times L}[/tex]

[tex]B = \frac{1.50 \mu_{0} I}{ \pi L}[/tex]

Every side produces the same amount of field in the same direction, which in the illustration is perpendicular to the paper.

Therefore, the total field is:

[tex]\frac{1.50 \mu_{0} I}{ \pi L} = \frac{4.50 \mu_{0} I}{ \pi L}[/tex]

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Plucking on a tight metal wire causes it to vibrate. What type of energy would that produce?

A. Light
B. Chemical
C. Sound
D. Thermal


Question 2: A burning candle exhibits what types of energy?

A Light and Thermal Energy
B Light Energy only
C Sound and Light Energy
DTheraml Energy only

Answers

Question one :sound Energy
Question two :light and thermal energy
I hope this helps you
A little bit I can do

Question 10 While looking in the yard, Jill noticed that the areas directly under the trees had less grass than the other areas in the yard. Which of the following is the BEST explanation for this observation? A The trees are blocking the sunlight. B The grass is receiving too much fertilizer. 2 C The areas under the trees are too cool for grass to grow. D The areas under the trees are receiving less water.​

Answers

Answer:

The trees are blocking the sunlight.

Explanation:

B is obviously not the answer because fertilizer wouldn't have that effect. For C, shade doesn't change the temperature that much that it would inhibit plant growth. For D, even if the tree blocks the water, the surrounding ground will still be wet and therefore the grass should still have a sufficient amount of water to grow.  Sunlight can't be gotten from somewhere else, unlike water, so this would inhibit plant growth.

Phase conductors 6 awg and smaller ____ permitted to be re-identified as equipment ground conductors using green paint, tape, or other effective means

Answers

Phase conductors 6 awg and smaller are not permitted to be re-identified as equipment ground conductors using green paint, tape, or other effective means.

Depending on the type of system offered, the grounded conductor of a service is typically a neutral conductor, though it can also be a phase conductor. A grounded phase conductor and no grounded neutral conductor are present in a corner-grounded delta system, for instance. The unbalanced load is returned to the source by the neutral. The conductor that has been purposefully grounded is the grounded conductor. The neutral is the conductor that is purposefully grounded in the majority of wiring systems used in industrial facilities, businesses, and homes. For safety reasons, the grounding conductor is employed. The grounding wire does not carry current under typical circumstances. The grounding wire offers a low resistance channel for the current in a fault situation.

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PLEASE HELP ME

Which modes of heat transfer require a medium? Which does not? Explain why a medium is/is not
needed for each response.

Answers

Answer:

Conduction and convection requires Modes of transfer of heat ! Radiation doesn't require any medium !!

In terms of heat transfer, radiation is the emission of thermal energy in the form of infrared waves. ... Since heat is carried by electromagnetic waves, it does not need a physical medium to transfer it. Instead it radiates through space - this is how the Earth is heated by the Sun despite space being a vacuum

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Aluminium is a non magnetic metal. However, it can become magnetised under special conditions. Explain how. (4 marks)​

Answers

Answer:

Exposing it to a very strong magnetic field

Explanation:

Aluminium is a non magnetic metal thus it is not magnetic under normal conditions. This is because it interacts with other magnets. The only condition that magnetism can be induced in aluminium is exposing it to a very strong magnetic field.

if your guitar pick is producing a harsh sound, you should use your fingernail instead relax your wrist, arm, and shoulder make sure your wrist and arm are at a ninety degree angle press the pick more firmly onto the strings

Answers

If your guitar pick is producing a harsh sound, you should make sure your wrist and arm are at a ninety degree angle.

Making of harsh sounds due to the pick from a guitar is seen often during guitar practices from beginners. There are numerous reasons for this. One of the reasons that can be considered as the most often mistake is the way a guitarist holds the pick. In order to avoid the sound produced by the pick, make sure that your wrist and arm are in a ninety degree angle.

This will provide a comfortable position to use the picks. You should not hold the pick firmly either. Try to hold the pick gently. Remember lesser the pick gets in contact with the string, lesser the sound produced. Also try to use a proper pick for guitar.

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I’ll give brainliest if it’s correct ;-;z
Someone help!!!
3 different earthquakes that were measured with broadband seismographs, 3 earthquakes long period, and 3 earthquakes measured with short period instruments.

Answers

Explanation:

what is the question? could you pls provide it

Science: PLEASE HELP DUE IN 5 minutes!

Answers

Answer:

It is the process in which animals eat each other in the food chain. From producers (like grass) to the top of the food chain (which depends on the climate and habitat)

Explanation:

A certain superconducting magnet in the form of a solenoid of length 0.500m can generate a magnetic field of 9.00T in its core when its coils carry a current of 75.0A . Find the number of turns in the solenoid.

Answers

The number of turns in the solenoid is [tex]4.78\times 10^4 \ turns[/tex].

Solenoids are essentially coils of cord. These generate a magnetic subject which strives a pressure over a steel element.A solenoid is a fundamental time period for a coil of cord that we use as an electromagnet.We additionally consult with the tool which could convert electric power into mechanical power as a solenoid.Actually it generates a magnetic subject for developing linear movement from the electrical cutting-edge. With using a magnetic subject.Magnetic field at the centre of a solenoid of length 'L' having 'N' number of turns with a current 'I' is given by   [tex]B=\frac{u_0NI}{L}[/tex]   ...(1)  where [tex]u_0[/tex] is the permittivity of free space whose value is [tex]4\pi \times10^{-7}Tm/A[/tex]  .

It is given that superconducting magnet in the form of a solenoid of length 0.500m can generate a magnetic field of 9.00T in its core when its coils carry a current of 75.0A .

Putting above values in equation (1) , we get

[tex]9.00=\frac{4\pi \times10^{-7}\times N \times75.0}{0.500} \\\\N=\frac{9.00\times0.500}{4\pi \times10^{-7}\times75.0} \\\\N=4.78\times10^4 \ turns[/tex]

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What does resistance refer to in a circuit?

Answers

Answer:

Resistance is a measure of the opposite to current flow in an electrical circuit. Resistance is measured in ohms.

Hope this helps

How fast would a girl who rides her bike at 18 m/s for 15 s. Have been traveling if she had covered the same distance in 10 s?

Answers

Answer:

From first equation of motion:

[tex]{ \rm{v = u + at}} \\ { \rm{18 = 0 + (a \times 15)}} \\ { \rm{18 = 15a}} \\ \\ { \boxed{ \rm{ \: a = \frac{18}{15} \: m {s}^{ - 2} }}}[/tex]

For the second case:

[tex]{ \rm{v = u + at}} \\ { \rm{v = 0 + ( \frac{18}{15} \times 10)}} \\ \\ { \rm{v = 12 \: {ms}^{ - 1} }}[/tex]

Tessa uses a toy slingshot to launch a tennis ball across the park for her dog to fetch. For her first launch, she
uses 100 N of force. Her second launch uses 200 N of force, and her third launch uses 300 N. Which launch had
the greatest acceleration of the tennis ball?

Answers

Answer:

See the explanation below.

Explanation:

To solve this problem we must apply Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration and this force can be calculated by means of the following equation.

F = m*a

where:

F = force [N] (units of Newtons)

m = mass [kg]

a = acceleration [m/s²]

The mass of the tennis ball will always be the same therefore it will never change.

Now clearing a:

[tex]a=\frac{F}{m}[/tex]

If the mass of the ball remains the same:

[tex]a = \frac{100}{m} ; a = \frac{200}{m};a =\frac{300}{m}[/tex]

We see that for a force of 300 [N], the acceleration exerted on the ball must be greater. Therefore with the force of 300 [N] the greatest acceleration is achieved.

Look at the picture

Answers

Answer:

Your answer is d

Explanation:

What is the relationship between magnetism and the movement of electrical charges in generators ( the device).

Answers

Answer:

Electricity and magnetism are two related phenomena produced by the electromagnetic force. Together, they form electromagnetism. A moving electric charge generates a magnetic field. A magnetic field induces electric charge movement, producing an electric current.

Explanation:

What is the force of gravity acting on a 2000 kg spacecraft when it is about the Earth at a in orbit distance of 8.375 x 106 m?​

Answers

Answer:

W = 13.44 KN

Explanation:

First, we need to find the value of acceleration due to gravity at the specified height:

[tex]g' = g(1-2\frac{h}{R})[/tex]

where,

g' = value of acceleration due to gravity at given height = ?

g = value of acceleration due to gravity at surface of earth = 9.81 m/s²

h = height of space craft = 8.375 x 10⁶ m - 6.37 x 10⁶ m = 2.005 x 10⁶ m

R = Radius of Earth = 6.37 x 10⁶ m

Therefore,

[tex]g' = (9.81\ m/s^2)(1-2\frac{2.005\ x\ 10^6\ m}{6.37\ x\ 10^6\ m})\\\\g' = (9.81\ m/s^2)(1 - 0.315)\\g' = 6.72\ m/s^2[/tex]

Now, we can find the weight or force of gravity on space craft:

[tex]W = mg'[/tex]

where,

W = Force of gravity on space craft = ?

m = mass of space craft = 2000 kg

Therefore,

[tex]W = (2000 kg)(6.72\ m/s^2)[/tex]

W = 13.44 KN

Hi im really confused:
How much energy would be needed to raise the temperature of the air in a room by 5.0°C if the room measures 4.0m x 4.0m x 3.0m? (Density of air = 1.0kg/m³)
Assume that the room has no furniture and that the walls gain no thermal energy.

Answers

The energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ

U = [tex]c_{p}[/tex] m ΔT

U = Energy

[tex]c_{p}[/tex] = Specific heat

m = Mass

ΔT = Change in temperature

ρ = Density

V = Volume

ρ = 1000 g / m³ (Dry air )

= 1 J / g K

ΔT = 5 °C

V = 4 * 4 * 3

V = 48 m³

m = ρ V

m = 1000 * 48

m = 48000 g

U = 1 * 48000 * 7

U = 336000 J

U = 336 kJ

Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ

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A 0.5-kg ball accelerated at 50 m/s 2 . What force was applied?

Answers

Answer:

25N

Explanation:

soln:

given,

mass(m)=0.5kg

acceleration(a)=50m/s^2

force(F)=?

we know,

F=m*a

or,F=0.5*50

•°•F=25N

7. A student is rotating an object on a rope that is 4.5m long. If we increase the length
of the rope so that the student rotates in uniform circular motion with the mass
rotating 9.0 m away from the center of the rotation (2x farther), what will be the
effect on the tangential velocity for the athlete if we keep the time for 1 revolution
the same?
It will be 16 times greater
0
O
It will be 2 times greater
0
о
It will be 4 times greater
0
It will be the same
CLEAR ALL
7 08 09 10 0 11
NEXT >
REVIEW & SUBMIT

Answers

The tangential velocity is proportional to the length of the rope hence when the length of the rope is doubled, the tangential velocity becomes two times greater.

We know that the tangential velocity of an object moving along a circular path depends on its radius and it's angular velocity.

In this case, we have been told that the motion of the object is uniform meaning that the angular velocity is held constant and the length of the rope which is the radius was doubled.

Since the tangential velocity is directly proportional to the length of the rope, the tangential velocity will be two times greater when the length of the rope is doubled.

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A proton having an initial velvocity of 20.0i Mm/s enters a uniform magnetic field of magnitude 0.300 T with a direction perpendicular to the proton's velocity. It leaves the field-filled region with velocity -20.0j Mm/s. Determine(a) the direction of the magnetic field.

Answers

The the direction of magnetic field is perpendicular to the velocity of proton and is directed towards the + z axis.

We have a proton entering a uniform magnetic field which is in a direction perpendicular to the proton's velocity.

We have to determine the direction of magnetic field.

What is the magnitude of force on the charged particle moving in a uniform magnetic field?

The magnitude of force on the charged particle moving in a uniform magnetic field is given by -

F = qvB sinθ

According to the question, we have -

Entering Velocity (v) = 20 i  m/s.

Magnetic field intensity (B) = 0.3 T.

Leaving velocity (u) = - 20 j  m/s.

Now -

F = q |v| |B| sinθ

F = 1.6 x [tex]10^{-19}[/tex] x 20 x 0.3 x sin(90)

F = 9.6 x  [tex]10^{-19}[/tex]  Newton.

Now, using the Fleming's left hand rule, the the direction of magnetic field is perpendicular to the velocity of proton and is directed towards the + z axis. The force is towards the '- y' axis. Therefore -

B = + 0.3 k

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a ping-pong ball is held submerged in a bucket of water by a string attached to the bucket's bottom. part a salt is now added to the water in the bucket, increasing the density of the liquid. what happens to the tension in the string ?

Answers

The tension force in the string will increase because the difference between the densities became increased.

What is the free body diagram?

Free-body diagrams are utilized to display the relative direction and strength of all forces that are being applied to an item in a certain scenario. A unique illustration of the geometric diagrams that were covered in a previous lesson is the free-body diagram. We will make use of these graphics throughout the entire study of physics.

A thread fastened to the bucket's base is holding a ping-pong ball immersed in water. The water in the bucket is now supplemented with salt, making the liquid denser.

Before adding the salt let T be the tension in the string.

Due to the growing disparity in densities, the force applied to the rope will increase.

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Supposing d(t) is known to have value D,
what procedure will find the time t at which
this happens?
2. Set d(t) equal to v^2/a
6. Set a to zero

Answers

You don’t set it to zero because that’s not how to do it

a sound has a frequency of 230 hz. what is the velocity of this sound if it has a wavelength of 46 cm?​

Answers

Answer:

V=f×λ

Where,

V is the velocity of the wave measure using m/s.

f is the frequency of the wave measured using Hz.

λ is the wavelength of the wave measured using m.

transform 46 cm in m = 0.46m and there u have it

Explanation:

water flows through a 4.0-cm-diameter horizontal pipe at a speed of 1.3 m/s. the pipe then narrows down to a diameter of 2.0 cm.

Answers

The pipe's large and narrow sections have different water pressures of "12.78 KPa."

The ideas of Bernoulli's Theorem and the continuity equation are involved in this query. Finding the pressure difference requires substituting the appropriate values.

What is Bernoulli's theorem explain?

Therefore, Bernoulli's theorem states that a drop in fluid pressure is connected with an increase in fluid velocity if the fluid flows horizontally so that there is no change in gravitational potential energy.

Bernoulli's theorem states that as long as an ideal liquid is incompressible, viscous, and flows in a streamline, the total amount of energy it possesses at any given place remains constant. Kinetic, potential, and pressure energy all add up to a constant. P+21pv2+pgh=Constant.

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help me please!!!!!!!!!!!!!!!

Answers

Answer:

10

Explanation:

would

In the year 2000, a company made $4.7 million in profit. For each consecutive year after that, their profit increased by 15%. How much would the company's profit be in the year 2004, to the nearest tenth of a million dollars?

Answers

Answer: $8.2 million.

Explanation:

If we have a quantity A, and we have an increase of x%, this can be written as:

A + (x%/100%)*A

Now, for this particular case we have:

In year 2000 (we can define this year as the year zero, y = 0) the initial value is $4.7 million.

The next year, y = 1, there is an increase of 15%, then we will have a profit of:

P = $4.7 million + (15%/100%)*$4.7 million = $4.7 million +  0.15*$4.7 million

P = $4.7 million*(1 + 0.15) = $4.7 million*(1.15)

in the next year, y = 2, the profit will be:

P =  $4.7 million*(1.15) + (15%/100%)* $4.7 million*(1.15)

  = $4.7 million*(1.15) + 0.15* $4.7 million*(1.15)

   = $4.7 million*(1.15)^2

We already can see the pattern, the profit in the year y will be:

P(y) = $4.7 million*(1.15)^y

In particular, in the year 2004 we have y = 4, then the profit that year will be:

P(4) = $4.7 million*(1.15)^4 = $8.2 million.

Long ding dong what it do?

Answers

Answer:

nun wbu

Explanation:

Answer:

long very very

What does this tell you about the direction and magnitude of the acceleration acting on the cannonball throughout its duration of flight?

Answers

Answer:

Direction remains the same but velocity changes.

Explanation:

This tell us about the direction and magnitude of the acceleration acting on the cannonball throughout its duration of flight that its direction remains the same but its magnitude of the acceleration is continuously changing. The cannonball moves in the direction in which the cannon was fired while the velocity is highest after the fire but decreases when goes higher and when it comes back to the ground so its velocity increases against so we can say that both positive and negative acceleration occurs. Positive acceleration means increase in the magnitude of velocity whereas negative acceleration means decrease in velocity.

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