The concentration will be 156 minutes later when the rate at which a certain drug is eliminated by the body follows first-order kinetics, with a half life of 78 minutes is 0.275 ug/mL
Half life: It is known as the time needed to minimize the initial concentration to half. It is denoted by the symbol t1/2
For a first order reaction,
t1/2=0.693/k1
The half-life time for a first order reaction is unaffected by the substrate's starting concentration.
Half life of the given drug is 78 min
Total time is 156 min
Number of half lives corresponding to 156 min is 156/78=2
Therefore, the concentration of drug reduced in 156 min =2^2=4 times
Therefore, the number of half-life is present in the given total time is determined by dividing the total time with half-life of the drug.
The initial concentration is 1.1 ug/mL
Final concentration is 1.1/4=0.275 ug/mL
The concentration of drug after 156 min is 0.275 ug/mL
Half life is the period for which the initial concentration of a substance becomes half of initial concentration.Learn more about half life at:
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(C3H8) What mass of carbon dioxide (in kg ) is produced upon the complete combustion of 40.2 L of propane (approximate contents of two 5-gallon tanks)? Assume that the density of the liquid propane in the tank is 0.621 g/mL . (Hint: Begin by writing a balanced equation for the combustion reaction.)
The mass of carbon dioxide is obtained as 236 g of carbon dioxide.
What mass of carbon dioxide is produced?We know that the first step when we are trying to solve any type of question that involves stoichiometry is that we have to obtain the balanced reaction equation. This would show us the kind of interaction that is able to take place in order to obtain the results that we seek.
The reaction equation is given as;
C 3 H 8 + 5 O 2 → 3 CO 2 + 4 H 2 O
If 1 mole of propane occupies 22.4 L
x mole of propane occupies 40.2 L
x = 1 mole * 40.2 L /22.4 L
x = 1.79 moles
Now;
1 mole of propane produced 3 moles of carbon dioxide
1.79 moles of propane produced 1.79 moles * 3 moles/1 mole
= 5.37 moles of carbon dioxide
Mass of carbon dioxide =5.37 moles * 44 g/mol = 236 g of carbon dioxide.
The mass of carbon dioxide is obtained as 236 g of carbon dioxide.
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See attached. Thank you very much!!! :)
The functional groups that are present the compound is shown in the image is;
HaloalkaneAlkeneAmineWhat is the functional group?The functional group is the atom, group of atoms or bond that is responsible for the chemical reactivity of the members of a particular family of organic compounds. We have to note that there are several families of organic compounds and the reactivity of these families is determined mostly by the kind of functional group that we have in that particular molecule.
Now we have the structure that has been shown in the image attached. We now have to look at the image and determine the kind of functional groups that we have in the molecule. In this case, we are actually looking out for the very points along the chain where a chemical reaction is possible.
We can see that the functional groups that we have here are;
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Specify the hybridization at the atoms labelled a-d.
For each atom enter one of the following: sp3, dsp2, sp2, sp3d, or sp.
The orbitals where you can find each of the bonds;
a - sp3
b - sp3
c - sp2
d- sp3
What is hybridization?The term hybridization is the term that is used to describe the mixture of atomic orbitals which can be used to combine with other orbitals of relevant energy.
Let us recall that in some cases, the energy that is required in bonding could only be obtained by the hybridization of orbitals in which orbitals are mixed. The mixed orbitals are orbitals that are very close to each other in energy and help in the formation of bond.
Now let us try to write the orbitals where you can find each of the bonds;
a - sp3
b - sp3
c - sp2
d- sp3
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Describe one way in which energy is transferred when magnesium combusts
Explanation:
When magnesium reacts with oxygen, it produces light bright enough to blind you temporarily. Magnesium burns so bright because the reaction releases a lot of heat. As a result of this exothermic reaction, magnesium gives two electrons to oxygen, forming powdery magnesium oxide (MgO).
C. In what orbital is an electron located that has quantum numbers of: n = 5, 1= 0, m₁ = 0, ms=-1? (1
point)
The electron is in the 5s orbital.
What is an orbital?The term orbital is the region in space where there is a high probability of finding an electron. There are four quantum numbers that define an orbital and these are;
Principal quantum number
Orbital quantum number
Spin quantum number
Magnetic quantum number
Let us now look at the sets of quantum numbers as given, a look at the principal and the orbital quantum numbers (m and l) tell us that the electron is in the 5s orbital.
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Solid zinc(II) sulfide reacts with aqueous hydrobromic acid (HBr) to form aqueous zinc(II) bromide and dihydrogen sulfide gas.
The equation of the double displacement reaction is:
ZnS (s) + 2 HBr (aq) → ZnBr₂ (aq) + H₂S (g)What type of reaction occurs between solid zinc(II) sulfide reacts with aqueous hydrobromic acid (HBr)?The reaction between solid zinc(II) sulfide reacts with aqueous hydrobromic acid (HBr) is an example of a double displacement reaction.
In the reaction, bromide ion from the hydrobromic acid and the sulfide ion from the zinc sulfide both displace each other from their respective positive ions to form new products. The products formed are aqueous zinc(II) bromide and dihydrogen sulfide gas.
The equation of the double displacement reaction is given below:
ZnS (s) + 2 HBr (aq) → ZnBr₂ (aq) + H₂S (g)
The zinc sulfide exists as a solid whereas the hydrobromic acid is an aqueous solution. The zinc (ii) bromide formed exists as an aqueous solution whereas dihydrogen sulfide is a gas.
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Note that the complete question is given below:
Solid zinc(II) sulfide reacts with aqueous hydrobromic acid (HBr) to form aqueous zinc(II) bromide and dihydrogen sulfide gas.
Express your answer as a chemical equation. Identify all of the phases in your answer.
Which of the following is a physical change?
A) Magnesium reduces dry ice, forming black
carbon and MgO.
B) Water forms hydrogen and oxygen gases
via electrolysis.
C) The pH of water is raised by dissolving
sodium hydroxide.
D) Ice forms as water is poured onto dry ice.
E) Water hydrates cobalt chloride, turning
it from blue to pink.
Ice forms as water is poured onto dry ice is a physical change .
So , option D is correct one .
The physical change is explained in following points ,
A physical change is one that simply affects the physical nature of the substance without changing their chemical properties .Its chemical properties remain unchanged .Usually, increasing the temperature or applying pressure—or both—will cause a physical change .Reversing the condition—lowering the temperature, the pressure, or both—restores the material's initial state .In other words, physical changes are reversible .to learn more about physical change please click here ,
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Cs(s)+HBr(aq)= what is the answer
Explanation:
Cs(s)+HBr(aq)=H(g)+CsBr(aq)
BUFFERS BUFFERS AND BUFFER CAPACI
INTRODUCTION
LABORATORY SIMULATION
How to calculate the pH of a buffer solution
1) Calculate the pH of a solution prepared by dissolving 2.05 g of sodium acetate, CH3COONa, in 50.0 mL of 0.25 Macetic
acid, CH3COOH(aq). Assume the volume change upon dissolving the sodium acetate is negligible. K₂ of CH3COOH is
1.75 X 10.5.
pH =
The pH of the solution prepared by dissolving sodium acetate and acetic acid is 5.05.
Given -
CH3COONa = 2.05g
So, Number of moles of CH3COONa = 2.05 / 82.03 = 0.024
∴ Molarity = 0.024 / 0.05
= 0.48 M
and CH3COOH = 0.25 M
pH of buffer - The equilibrium constant (Ka) of the weak acid and the ratio of weak base (A-) to weak acid (HA) in solution are the two variables that determine the pH of a buffer.
1) Various weak acids have different equilibrium constants (Ka).
2) Ka tells us how much of the HA in the solution will be dissolved into H+ and A-.
According to the question -
CH3COOH ⇄ CH3COO⁻ (aq) + H⁻ (aq)
Ka = [CH3COO⁻] [H⁺] / {CH3COOH]
[H⁺] = Ka x [CH3COOH] / [CH3COO⁻]
[H⁺] = 1.75 x 10⁻⁵ [0.25] / [ 0.48]
[H⁺] = 0.43 x 10⁻⁵ / 0.48
= 0.89 x 10⁻⁵
pH = -log [H⁺]
∴ pH = - log [0.89 x 10⁻⁵]
pH = 5.05
Hence, the pH of the solution will be 5.05.
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The enthalpy of vaporization for methanol is 35.2 kJ/mol. Methanol has a vapor pressure of 101.3
kPa at 64.7 °C. Using the Clausius-Clapeyron equation, what is the vapor pressure for methanol at
57.2 °C? Give your answer in kPa, to the first decimal point.
The vapour pressure of methanol at 57.2°C is 66.3 kpa.
The enthalpy of vaporization for methanol,
=35.2 kj/mol = 35.2×1000 j/mol
at temperature T2= 64.7°C = 64.7 + 273 = 337.4 K
temperature T1 = 57.2 °C = 57.2 + 273 = 330.2 K
vapour pressure P2 = 101.3 kpa
vapor pressure P1 = ?
Clausius - Clapeyron equation is geven as :
ln ( P1 / P2 ) = ΔH / R ( 1 / T2 - 1 / T1 )
ln ( P1 / 101.3 kpa ) = 35200 j/mol / 8.314 j/Kmol × ( 1/337.4 K - 1/330.2 K)
ln ( P1 / 101.3 kpa) = [tex]e^{-0.423}[/tex]
P1 / 101.3 kpa = 0.655
P1 = 0.655 × 101.3 kpa
P1 = 66.3 kpa
Hence, The vapor pressure at 57.2°C is 66.3 kpa.
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Do you consider comparing consumer products on the basis of their components for use, safety, quality, and cost?
Comparing consumer products on the basis of their components like use, safety, quality, and cost is necessary as it creates awareness about the product among consumers.
Consumer Products - It is a kind of product that is bought by individuals for personal use or consumption. These are the end products or final goods reached to the end-user i.e consumer by retailer via various distribution channels. Ex- grocery, clothing, etc.
Marketing strategies are built based on different market segmentation and types of consumer products available to the target market.
Types of Consumer Products
There are four types of consumer products, they are:-
Convenience Products
Shopping Products
Specialty Products
Unsought Products.
Hence, it is necessary to compare consumer products on basis of the components like use, safety, quality, and cost. It also increases the competition as well as creates awareness among consumers.
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Convert 167 mL/h to units of liters per day. Show the unit analysis by dragging the conversion factors into the unit-factor slots.
On converting 167 mL/h , we get 4.008 L/d
Converting 167 mL/h to units of liters per day
1L=1000mL
1d=24hrs
So 167 mL/1h x1L/1000mLx24h/1d=4008L/1000d
=4.008 L/d
Unit conversion is the process of converting the measurement of a given amount between various units, often by multiplicative conversion factors that alter the value of the measured quantity without altering its effects.Unit conversion is a multi-step procedure that includes rounding, selecting the appropriate number of significant digits, and multiplying or dividing by a numerical factor.The conversion from one unit to another in order to ensure accuracy and prevent measurement misunderstanding.Learn more about unit conversion at:
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the ph of a 0.04 M Calcium hydroxide is
The pH of a 0.04 M Calcium hydroxide solution is 1.39.
How to calculate pH?pH refers to the degree of alkalinity and acidity of a solution.
It is the quantitative measure of the acidity or basicity of a solution. The term "pH" is used in chemistry to denote the values of the concentration of the hydrogen ion {H+}.
The pH scale runs from 0 to 14 where; a value of seven is considered neutral, less than seven acidic, and greater than seven basic.
To calculate the pH of an aqueous solution, one needs to know the concentration of the hydronium ion in moles per liter (molarity).
The pH of a solution can be calculated as the negative logarithm of a concentration or molarity as follows:
pH = - log {H+}
According to this question, a 0.04 M calcium hydroxide is given. The pH can be calculated as follows:
pH = - log {0.04}
pH = 1.39
Therefore, the pH of a 0.04 M calcium hydroxide solution is 1.39.
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Question 2 (3 points)
What is the empirical formula for a compound that contain 1.011 g of chromium and 0.467 g of oxygen. ?
Chromium oxide's empirical formula is Cr₂O₃
The simplest whole-number ratio of atoms in a compound is the empirical formula. The proportion of atoms to moles is the same. Our task then is to determine the molar ratio of Cr to O.
Cr's mass is 7.35 g.
10.74 g of chromium oxide are equal to 10.74 g of chromium and 10.74 g of oxygen.
O's mass is 10.74 g - 7.35 g, or 3.39 g.
Moles of Mg = 52.00 g Mg = 0.1413 mol Mg/7.35 g Mg = 1 mol Mg
Moles of O equal 3.39 g O to 1 mol O and 16.00 g O to 0.2119 mol O
For every 3 mol of O, there are 2 mol of Cr.
Chromium oxide's empirical formula is Cr₂O₃.
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6) Which of the following statements does not describe a physical property of chlorine?
A) Chlorine combines with sodium to form table salt.
B) The color of chorine gas is green.
C) The density of chlorine gas at standard temperature and pressure is 3.17 g/L.
D) The freezing point of chlorine is -101°C.
Answer:
the answer is A. Chlorine combines with sodium to form table salt
what is an hydroxide solution commonly used in labs
sodium hydroxide (NAOH) a.k.a causic soda commonly used in labs.
MOLAR MASS of naoh is 39.997 g/mol.It is dry hard brittle, white stocks in large fused opaque white-stone like masses having a dense crystalline fracture in small pellets/flakes.it is very delinquent and one of the strongest base , acts as a saponifying agent which is used in industrial purposes.It is an important industrial chemical as it is used on its own and is also used as a raw material in the production of other chemicals. The basis for the production of sodium hydroxide is the electrolysis of brine.To know more about sodium hydroxide visit :
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Answer: Sodium hydroxide (NaOH), also known as caustic soda or lye, is a highly versatile substance used in a variety of manufacturing processes.
Explanation: For Example: Sodium hydroxide is also the most common base used in chemical laboratories, being able to test for quite a number of cations (this is called Qualitative Inorganic Analysis), as well as to provide alkaline mediums for some reactions that need it, such as the Biuret test.
!!!!PLS HELP IM TIMED!!!!!!
Shonda's car gets an average of 27 miles per gallon. Gas costs $2.25 per gallon and she drives 892 miles to get from Baltimore, MD, to Orlando, FL. What are the conversion factors she could use to calculate the cost of gas to get from Baltimore to Orlando? How much will she spend on gas?
Answer:
74.25
Explanation:
27 miles = 1 gallon
1 mile = 1/27 mile
Distance to cover = 892 miles
We will multiply this number with gallons of gas used for 1 mile.
892 miles = 1/27 * 892
892 miles = 33.04 gallons of gas
Rounding off to nearest whole number;
892 miles = 33 gallons
Cost of one gallon of gas = $2.25
Cost of 33 gallons = 2.25*33 = $74.25
She will spend $74.25 on gas.
an isotopes of caesium-137 has a half-life of 30 years. if 1.0g of Cs-137 disintegrates over a period of 90 years, how many grams of Cs-137 would remain?
After 90 years amount of Cs-137 isotopes has a half-life of 30 years. would remain is equal to = 0.125 grams.
An important and useful factor of radioactive decay is half of life, which is the amount of time it takes for one half of a radioactive isotope to decay. The half of-life of a selected radioactive isotope is constant; it is unaffected by way of situations and is independent of the initial quantity of that isotope.
The half of life of a chemical reaction can be defined because the time is taken for the awareness of a given reactant to attain 50% of its preliminary awareness. The half of-life of a response is the time required for the reactant's attention to decrease to at least one-half of its initial price. The half of-life of a first-order response is consistent this is associated with the charge consistent for the reaction. t1/2 = 0.693/k
Since all radioactive reaction follows first-order reaction, The rate of reaction does not depend on initial concentration.
calculation:-
1 gram Cs-137 at T = 0
after the first half,
⇒0.5 gram Cs-137 at T = 30
After the second half,
⇒0.25 gram Cs-137 at T = 30.
After the third half,
⇒0.125 gram Cs-137 at T = 90 years.
Hence, after 90 years amount of Cs-137 would remain is equal to = 0.125 grams.
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Because of increasing evidence of damage to the ozone layer, chlorofluorocarbon (CFC) production was banned in 1996. However, many older cars still have air conditioners that use CFC-12 (CF2Cl2). These air conditioners are recharged from stockpiled supplies of CFC-12. Suppose that 100 million automobiles each contain 1.0 kg of CFC-12 and leak 24 % of their CFC-12 into the atmosphere per year.
How much chlorine, in kg , is added to the atmosphere each year due to these air conditioners?
The mass of chlorine is 9.9 * 10^6 kg.
Total mass of CFC = M(CFC) * number of cars = 1.0 kg * 1.00 * 10^8
= 1.00 * 10^8 kg
Mass of the leaked CFC ;
% leaked = m(leaked) *100 / m(total)
m(leaked) = o.24 * 1.00 * 10^8 kg
m(leaked) = 2.4 * 10^6 kg
Now no. of moles of CFC:
n(CFC) = m(CFC) / MM(CFC) = 2.4 * 10^9 g / 170.92 g/mol = 0.014 * 10^9 mol
= 1.4 * 10^7 mol
No. of moles of chlorine ;
n(Cl) = n(CFC)*2
= 1.4 * 10^7 mol *2
= 2.8 * 10^7 mol
Now at last the mass of the chlorine :
m(Cl) = n(Cl) * MM(Cl)
= 2.8 * 10^7 mol * 35.453 g/mol
= 99.2 * 10^10 g
Mass of Cl = 9.9 * 10^6 Kg
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I forgot how to do fragment sentences
Answer:
A sentence fragment is a sentence that is missing either its subject or its main verb.
Explanation:
Incorrect: Went to the store yesterday.
Incorrect: After the classes, the library. My life nowadays
Is atomic radius a periodic property of atoms?
Major periodic trends include atomic radius, ionization energy, electron affinity, electronegativity, valency and metallic character.
7.801x|02 please I need the answers asap
Answer:
795.702
Explanation:
(objectives & conclusion) why it is necessary to know the different apparatus in the laboratory and how to do it
It is important to know the different apparatus in the laboratory and how to do it because these apparatus are handled carefully, and the experiment is done very carefully to avoid any mistakes.
What is a laboratory?A laboratory is a place where all scientific apparatus and instruments are put and experiments are done. These places are kept safe and hygienic and all experiment is done precisely to get results.
Thus, knowing the various lab equipment and how to utilize it is crucial because errors might happen during experiments because of how carefully this equipment must be handled.
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Karl sane walked 2189 miles in 45 days, 7 hours, and 39 minutes.
What was his average speed in miles per day?
What is the volume of a rectangular
object with length 17 cm, width 11 cm,
and height 6 cm?
Answer:
1122 cm cubed
Explanation:
The formula for volume of a rectangle would be length times height times width, so just do 17 * 11 * 6 to get your answer, which should be 1122 with units of cm cubed, or cm^3.
Hope this helps! Let me know if you have any confusion!
An intermediate step in the industrial production of nitric acid involves the reaction of ammonia with oxygen gas to form nitrogen monoxide and water. How many grams of nitrogen monoxide can form by the reaction of 507 g of ammonia and 845 g of oxygen?
g nitrogen monoxide
Taking into account the reaction stoichiometry, 633.75 grams of nitrogen monoxide can form by the reaction of 507 g of ammonia and 845 g of oxygen
Reaction stoichiometryIn first place, the balanced reaction is:
4 NH₃ + 5 O₂ → 4 NO + 6 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
NH₃: 4 molesO₂: 5 molesNO: 4 molesH₂O: 6 molesThe molar mass of the compounds is:
NH₃: 17 g/moleO₂: 32 g/moleNO: 30 g/moleH₂O: 18 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
NH₃: 4 moles× 17 g/mole= 68 gramsO₂: 5 moles× 32 g/mole= 160 gramsNO: 4 moles× 30 g/mole= 120 gramsH₂O: 6 moles× 18 g/mole= 108 gramsLimiting reagentThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. This means the when the limiting reagent is finished, the chemical reaction will stop.
Limiting reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 68 grams of NH₃ reacts with 160 grams of O₂, 507 grams of NH₃ reacts with how much mass of O₂?
mass of O₂= (507 grams of NH₃×160 grams of O₂)÷ 68 grams of NH₃
mass of O₂= 1,192.94 grams
But 1,192.94 grams of O₂ are not available, 845 grams are available. Since you have less mass than you need to react with 507 grams of NH₃, O₂ will be the limiting reagent.
Mass of nitrogen monoxide formedThe following rule of three can be applied: if by reaction stoichiometry 160 grams of O₂ form 120 grams of NO, 845 grams of O₂ form how much mass of NO?
mass of NO= (845 grams of O₂×120 grams of NO)÷ 160 grams of O₂
mass of NO= 633.75 grams
Finally, 633.75 grams of nitrogen monoxide can form by the reaction of 507 g of ammonia and 845 g of oxygen.
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Assume the specific heat of the solution is equal to the specific heat of water
When we assume the specific heat of the solution is equal to the specific heat of water ΔHdissolution is 27×10⁻⁵
A calorimeter is a device used for heat measurements necessary for calorimetry
Here given data is 4.79g = KBr and are dissolved in 109.00g water and temperature is 21.08°C and according to calorimeter heat of capacity = 1.84 J/°C
We have to calculate enthalpy of dissolution of KBr = ?
ΔHdissolution = 27×10⁻⁵
KBr+H₂0→KBr ΔH=?
qreaction = -qcal
1.79×1.84(-2.4) = 0.8936 J
1000 = -0.0008936
4.79+109.00 = 522.11 g
qcal = 522.11 g×1.84(-2.4) = -2305 J
qreaction = -qcal = -2305 J
n(KBr) = 4.79/74.55gmol⁻¹ = 0.0642mol
2305/ 0.0642mol = 0.00002787mol⁻¹
= 27×10⁻⁵
ΔHdissolution = 27×10⁻⁵
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How many total atoms are in 0.160 g of [tex]P_{2}[/tex][tex]O_{5}[/tex]?
total atoms:
The total number of atoms in 0.160g of P2O5 is 3 x 10^21 atoms.
What are atoms?
Atoms are defined as a smallest unit into which a matter can be divided without the release of electrically charged particles.
First calculate the number of mole of P2O5
Mass of P2O5 = 0.160 g
Molar mass of P2O5 = 142g/mole
Number of mole of P2O5 = mass/ molar mass
n = 0.160/142 g/mole
n = 0.0011 mole of P2O5
One mole of P2O5 has five mole of oxygen.
Using conversion factor
= 0.0011 mole of P2O5 x [ 5 mole of oxygen/ 1 mole of P2O5]
= 0.0055 mole of oxygen
Total number of atoms = 0.0055 x 6.02 x 10^23 atom/mole
= 3 x 10^21 atoms
Thus, the total number of atoms in 0.160g of P2O5 is 3 x 10^21 atoms.
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How many moles at gold (Au) atoms are in 87-89 of Au
The calculated answer is 1.99 x 10/21 x Au
Gold has a molar mass of 196.96657 g/m. The mass of 1 mole of gold atoms, which is commonly given in grams, is referred to as the molar mass of gold.
Divide the specified mass by the molar mass of gold, which is 196.966569 g/mol, to determine the moles.
The term "atomic weight" refers to an atom's overall weight. With the addition of a small amount from the electrons, it is roughly equal to the sum of the protons and neutrons. The number of neutrons an atom has has a significant impact on the stability of the nucleus and, consequently, the radioactivity of the atom. The average mass of an element's atoms expressed in atomic mass units is known as its atomic mass (amu, also known as daltons, D). Gold has a molar mass of 196.96657 g/m. The mass of 1 mole of gold atoms, which is commonly given in grams, is referred to as the molar mass of gold.
Divide the specified mass by the molar mass of gold, which is 196.966569 g/mol, to determine the moles.
(Atomic weight in g/mol on the periodic table).
0.00330 mol = 0.650 g Au = 196.966569 gmol Au Gold atoms 1 mole of atoms is equal to 6.02210/23 atoms.
double the estimated mol Au by several.
6.022×10/23 atoms1mol.
0.00330mol Au = 6.022 x 10/23 x 1 mol
= 1.99 x 10/21 x Au
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A chemist is called by the highway patrol to identify a clear colorless liquid that was spilled on the freeway. What tests could the chemist do to identify whether the liquid is a mixture or a substance?
A chemist is called by the highway patrol to identify a clear colorless liquid that was spilled on the freeway. The test chemist could do to identify whether the liquid is a mixture or a substance is melting point.
If it is to be identified that whether a liquid is a mixture or a pure substance, testing the melting point is preferably considered.
Melting point is a a range of temperature of a substance from which the first crystal starts melting.
Pure substances have sharp melting point but an impure substance or a mixture melts over a given range of temperature.
By looking at the overall composition, pure substance and mixture can be identified visually but it is quite difficult in case of a clear, colorless liquid.
Therefore, melting points can be used to find out whether a liquid is a mixture or a substance.
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