The ratio of right-handed students to left-handed students is 8 to 3.There are 520 right-handed students in school.How many students are left-handed

Given :

The Ironman endurance race has a 2.4 miles swim.

Javier can swim 0.5 miles in 20 minutes.

To Find :

How much time in hours it takes to complete the race.

Solution :

Speed of Javier :

[tex]s=\dfrac{2.4}{\dfrac{20}{60}}\ mph\\\\s= 7.2\ mph[/tex]

Let, time taken to cover 2.4 miles is t .

So,

[tex]t = \dfrac{2.4}{7.2}\ hours\\\\t = 0.33\ hours[/tex]

Hence, this is the required solution.

Answer:

59 years and younger

Step-by-step explanation:

Answer:

1st one  m=0

y= 0.49875311x  / cm

No horizonal asymptotes

x= 1/2 + 2.005 mcy

2nd one is

slope 1/2

y intercept (0,2)

x      y

-4     0

0       2

Step-by-step explanation:

for 2

starting point ay y 2 make a point

then rise over run

go up 1 and to the right 2 and point , then up 1 and to the right 2 and point

there is your graph

Answer:

602,000

Step-by-step explanation:

Answer:

602,0000

Step-by-step explanation:

10^5 = 100,000

6.02 x 100,000

I simply moved the numbers forward by 5 spaces.

Answer:

B, 36

Because, a composite number has factors

The others are prime

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

Step-by-step explanation:

This is  a proportion question.

change 2.6 to a decimal. 2/6 = 1/3 = 0.3333333

change 3/5 to a decimal 3/5 = 0.6

3.3333 / 2.6 = x / 4                 Cross multiply

4*3.33333 = 2.6x                    Combine the left.

13.33333= 2.6x                       Divide by 2.6

13.3333/2.6 = x

x = 5.128 spoons of syrup.

Answer:

a= 3b+4c/2

Step-by-step explanation:

2a=3b+4c

a= 3b+4c/2

Answer:

c)15

Step-by-step explanation:

Confirmed by rsm

A percentage is a way to describe a part of a whole. x is 133¹/₃% of y. The correct option is D.

A percentage is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25 which is equal to 25%.

To convert a fraction to a percentage, convert the fraction to decimal form and then multiply by 100 with the '%' symbol.

Given that 15% of x equals 20% of y. Therefore, we can write,

15% of x = 20% of y

(15/100) × x = (20/100) × y

Multiply both the sides of the equation by 100,

(15/100) × x × 100 = (20/100) × y × 100

15x = 20y

x/y = 20/15

Divide both the sides of the equation by 5,

x/y = 4/3

Now, the percentage of x that is y is,

Percentage = (x/y) × 100%

                   = (x/y) × 100%

                   = (4/3) × 100%

                   = 133.33%

                   = 133 ¹/₃ %

Hence, x is 133.33¹/₃% of y.

Learn more about Percentages here:

https://brainly.com/question/6972121

#SPJ2

Answer:

15/32

Step-by-step explanation:

First convert 1 1/3 to improper fraction:

  1 1/3 = 4/3

5/8 divided by 4/3 is same as...

  [tex]\frac{5}{8} * \frac{3}{4} = \frac{15}{32}[/tex]

Answer:

Sin 90 = 1/1 = 1

Use trigonometry formula and a triangle with lengths of 1

Answer:

In 4 Hours

Step-by-step explanation:

1 hour:   A: 30.25           B: 34.25

2 hours: A: 35.5             B: 38.5

3 Hours: A: 40.75          B: 42.75

4 Hours: A: 46                B: 46

Answer:

If the lines BC and DE are parallel, the value of c is c=-2

Step-by-step explanation:

We are given line segment BC with end points B(2, 2) and C(9,6) and line segment DE with endpoints  D(c, -7) and E(5, -3).

Using slope formula: [tex]Slope=\frac{y_2-y_1}{x_2-x_1}[/tex] we can find point c

When 2 lines are parallel there slope is same.

So, Slope of line BC =Slope of Line DE

[tex]\frac{y_2-y_1}{x_2-x_1}=\frac{y_2-y_1}{x_2-x_1}[/tex]

We have:

[tex]x_1=2, y_1=2, x_2=9, y_2=6 \ for \ line \ BC \ and \\\x_1=c, y_1=-7, x_2=5, y_2=-3 \ for \ line \ DE \[/tex]

Putting values and finding c

[tex]\frac{6-2}{9-2}=\frac{-3-(-7)}{5-c}\\ \frac{4}{7}=\frac{-3+7}{5-c} \\ \frac{4}{7}=\frac{4}{5-c} \\Cross \ multiply:\\4(5-c)=4*7\\20-4c=28\\-4c=28-20\\-4c=8\\c=\frac{8}{-4}\\c=-2[/tex]

So, If the lines BC and DE are parallel, the value of c is c=-2

Answer:

144.

The reason is because 1 ft = 12 in, (1 ft)2 = (12 in)2 = 144 in2.

Answer:

It is -2/3

Step-by-step explanation:

Answer:

En la caja registradora hay 200 monedas de cinco pesos, 20 monedas de 10 pesos y 582 monedas un peso.

Step-by-step explanation:

De acuerdo a la información, puedes escribir las siguientes ecuaciones:

x+y+z=802 (1)

5x+10y+z=1782 (2)

x=10y (3)

Primero debes reemplazar (3) en (1) y (2):

10y+y+z=802

11y+z=802 (4)

5(10y)+10y+z=1782

50y+10y+z=1782

60y+z=1782 (5)

Ahora, tienes dos ecuaciones:

11y+z=802 (4)

60y+z=1782 (5)

Puedes despejar z en (4):

z=802-11y (6)

Después, puedes reemplazar (6) en (5):

60y+802-11y=1782

49y=1782-802

y=980/49

y=20

Puedes reemplazar el valor de y en (3) para encontrar x:

x=10y

x=10(20)

x=200

Puedes reemplazar el valor de y en (6) para encontrar z:

z=802-11(20)

z=802-220

z=582

De acuerdo a esto, en la caja registradora hay 200 monedas de cinco pesos, 20 monedas de 10 pesos y 582 monedas de un peso.

Answer:192

Step-by-step explanation:

Calculate the area l*w or s*s

Divide the two areas to get the number of 1*1 from 1 plywood then multiply by their number which is 6 here

4*8=32/1=32*6=192

Answer:

C

Step-by-step explanation:

Khan academy .-.

Answer:

sas - meaning side angle side

Step-by-step explanation:

Answer:

I think -4

Step-by-step explanation:

Answer:

k = 146

m= 106

Kirchoff has $146

Maxi has $106

Step-by-step explanation:

For the purpose of the equations, I’ll call Kirchoff and Maxi a and b respectively.

a - 20 = b + 20 (equation 1)

2(b - 22) = a + 22 (equation 2)

We can juggle those around for

a = b +40 (equation 1r (re-arranged)) and

2b - 44 = a + 22 so 2b - 66 = a (equation 2r (rearranged))

The equations are now:

a = b + 40 (new equation 1) and

a = 2b - 66 (new equation 2)

Substitute from new equation 1 to new equation 2:

b + 40 = 2b - 66 so 40 = b - 66 making b = 106.

Plug b = 106 into new equations 1 and 2 for:

a = 106 + 40 (new equation 1) and

a = 212 - 66 (new equation 2)

This gives a = 146 and b = 106

TEST: There’s a gap of $40, so giving $20 from a to b makes them equal.

SECOND TEST: Subtracting $22 from b makes it $84 and giving that sum to a makes it $168, twice as much. The tests work.

Kirchoff has $146 and Maxi has $106.

Answer:

x=12

Step-by-step explanation:

The right angle is congruent to the other side. So 90-20=70. 6x-2=70. Add 2 to both sides to cancel out the minus 2. 6x=72 72/6=12

Answer:

[tex]\huge\boxed{\sf x = 12}[/tex]

Step-by-step explanation:

6x - 2 + 20 = 90     [Complementary Angles]

6x + 18 = 90

Subtracting 18 to both sides

6x = 90 - 18

6x = 72

Dividing both sides by 6

x = 12

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

looks delicious

Step-by-step explanation:

Answer:

Man looks so good!

Step-by-step explanation:

Send me some in the mail. lol ☺☻♥

Answer:

y=4, y=2

Step-by-step explanation:

Answer:

63/48

Step-by-step explanation:

21/4÷12/3

21/4×3/12

63/48.

So the final answer is 63/48

Answer:

1/35

Step-by-step explanation:

Answer:

(7,3)

Step-by-step explanation:

Answer:

34 edges

Step-by-step explanation:

Euler's formula for polyhedron states

F + V - E = 2

where F is number of faces, V, number of vertices, E number of edges

Here F = 16, V = 20, thus

16 + 20 - E = 2, that is

36 - E = 2 ( subtract 36 from both sides )

- E = - 34 ( multiply both sides by - 1 )

E = 34

Answer:

-4

Step-by-step explanation:

1-2=-1+3=2-4=-2+5=3-6=-3+101=98-102=-4

I hope I am right

Answer:

A system of the equation of a circle and a linear equation

A system of the equation of a parabola and a linear equation

Step-by-step explanation:

Let us verify our answer

A system of the equation of a circle and a linear equation

Let an equation of a circle as [tex]x^2+ y^2 = 1[/tex] ..........(1)

Let a liner equation Y = x ............(2)

substitute (2) in (1)

[tex]x^2 + x^2 = 1\\2x^2 = 1\\[/tex]

[tex]x^2 = \frac{1}{\sqrt{2} } \\x = +\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }[/tex]  so Y = [tex]+\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }[/tex]

so the two solution are ( [tex](\frac{1}{\sqrt{2} } ,\frac{1}{\sqrt{2} }) (-\frac{1}{\sqrt{2} }, -\frac{1}{\sqrt{2} }[/tex])

A system of the equation of a parabola and a linear equation

Let equation of Parabola be [tex]y^2 = x[/tex]

and linear equation y = x

substitute

[tex]x^2 = x\\x^2 - x= 0\\x(x-1) = \\x = 0 , 1[/tex]

Y = 0,1

so the two solutions will be (0,0) and (1,1)

Answer:

x = 3 and -1

Step-by-step explanation:

5(x²-2x-3)

(x-3)(x+1)

Answer:

Zero's are: x= 3, -1

Step-by-step explanation:

With factoring, and determining the middle ground, finding the zeroes will come back to this result.