The region around the earth where charged particles are trapped and spiral around is called:______.

Answers

Answer 1

The region around the earth where charged particles are trapped and spiral around is called magnetosphere .

The motion of charged particle in electric and magnetic field.

F = q(v x B).

Where, the magnetic force becomes centripetal force due to its direction towards the circular motion of the particle.

Hence, if the field (B) and velocity (v ) are perpendicular to each other, then the particle takes a circular path.

And in the above equation , F is magnetic force on charge particle q & B is the magnetic field .

The magnetosphere of the earth can be explained in term of astronomy and planetary science as that, a magnetosphere is a region of space surrounding an astronomical object in which charged particles are affected by that object's magnetic field.

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Related Questions

A cannon ball is shot horizontally off a 86.5 m hill with an initial horizontal velocity of 105 m/s. What horizontal distance will the cannon ball travel?

Answers

Answer:

H = 86.5 m = 1/2 g t^2        to get time for cannon ball to fall 86.5 m

t = (2 * 86.5 / 9.8)^1/2 = 4.20 sec

S = Vx t = 105 m/s * 4.2 s = 441 m        horizontal distance

A small amount of sodium hydroxide is added to water. When the chemical 1 point

reaction reaches equilibrium, the pH is 12. Which statement and conclusion
about sodium hydroxide is correct?
O
The negative log of the concentration of OH-ions is 12. Sodium hydroxide is a
strong base.
O
The negative log of the concentration of OH-ions is 2. Sodium hydroxide is a strong
acid.
The negative log of the concentration of OH-ions is 12. Sodium hydroxide is a
strong acid.
O
The negative log of the concentration of OH-ions is 2. Sodium hydroxide is a strong
base.

Answers

The concentration of (OH −) Hydroxide ions increase when the excessive base is added to the solution of Sodium Hydroxide as the base itself dissociates to give out OH −  ions which increase their concentration per unit volume.

when sodium hydroxide NaOH dissolves in water it separates into positively charged sodium ions cations and negatively charged hydroxide ions anions. these ions move round in the water, free and unbiased of every other, although cations have a tendency to be surrounded greater intently with the aid of anions and vice versa.

Sodium while sodium is added to water, the sodium melts to form a ball that moves around at the surface. It fizzes unexpectedly, and the hydrogen produced may also burn with an orange flame before the sodium disappears. The resulting huge concentration of OH- makes the solution greater basic and results in a dramatic growth inside the pH.

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which is larger

a, same size
b, 2 ft
c, 2 m

for anyone who wants points answer this :)​

Answers

The answer is C. 2 meters ^_^
The answer is C. 2 meters

You drive in a straight line at 20.0 m/s for 10.0 miles, then at 34.0 m/s for another 10.0 miles.
the average speed?

Answers

The average speed for the two events is 25.2 m/s

What is Average Speed ?

Average speed is the ratio of the total distance travelled by a body to the total time. It is measured in m/s

If you drive in a straight line at 20.0 m/s for 10.0 miles, then at 34.0 m/s for another 10.0 miles. To calculate the average speed, first convert the mile to meter

1 mile = 1609.34 m

10 miles = 10 × 1609.34 = 16093.4 m

Calculate the time for each event.

speed = distance / time

time = distance / speed

T1 = 16093.4 / 20

T1 = 804.67 s

T2 = 16093.4 / 34

T2 = 473.34 s

Total time t = T1 + T2

t = 804.67 + 473.34

t = 1278.01 s

Total distance s = 16093.4 + 16093.4

s = 32186.8 m

Average speed = s / t

Average speed = 32186.8 / 1278.01

Average speed = 25.19 m/s

Therefore, the average speed for the two events is 25.2 m/s approximately.

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What causes the curved, upper surface of water that commonly appears when using a graduated cylinder?

Answers

The stronger force of attraction between the molecule of the material and the walls of container caused the upper surface to be curved and the curved surface is known as Concave meniscus.

When the molecules of the solution or nay solvent attached to the walls of the container due to stronger attraction with the walls, it create a concave surface at the top, which is known as Meniscus and principle behind Meniscus is surface tension.

In contrast, a convex meniscus develops when the liquid’s dissolved particles are more attracted to one another than to the substance of the container, for example in barometers.

When the surface of a liquid, like as water, comes into contact with another phase (a solid, liquid, or gas), a phenomenon known as surface tension takes place, which resist the external force acting on it.

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Help me with this high school physics question!

Answers

Answer:

[tex]6.373219 \times 10^6 \; meters[/tex]
or
[tex]\rm 6.373 \times 10^6 \; meters\; or\;3 \;significant \;decimal \;digits[/tex]

Explanation:

The gravitational force can be calculated with the formula:
[tex]\boxed {F_g=\dfrac{GMm}{R^2}}[/tex]

where
[tex]\rm F_g = gravitational \; force\\G = gravitational constant\\M = mass\;of\;earth\\m = mass\; of\; the \; person\\[/tex]
[tex]\rm R\;=\;distance\;from\;center\;of\;earth\;to\;surface[/tex]

Multiplying both sides of the above equation by R and dividing both sides by [tex]\rm F_g[/tex] gives us a R² in terms of the others

==> [tex]\rm R^2 = \dfrac{GMm}{F_g}[/tex]   (1)

Given

[tex]F_g = 1030 N, M = 5.97\times 10^24\;kg\; \;and \;m = 105kg\\\\[/tex]

and knowing that [tex]\rm G = 6.67 \times 10^{-11} \; Nm^2/kg^2[/tex]

substitute these values to get

[tex]\rm R^2 =\dfrac{(6.67 \times 10^{-11})(5.97 \times 10^{24})(105)}{1030}[/tex]

[tex]\rm 4.05931 \times 10^{13} = 40.5931 \times 10^{10}\\\\R = \sqrt{40.5931 x 10^{12}} \\\\= 6.373219 \times 10^6 \; meters\\\\[/tex]

What is the equation describing the voltage across the capacitor, vc, as the capacitor is discharging in terms of the peak voltage v0 and the time constant of the circuit τ?.

Answers

Vc=Vo * e^(-t/τ) is the equation describing the voltage across the capacitor, vc, as the capacitor is discharging in terms of the peak voltage v0 and the time constant of the circuit τ.

As we all know, a capacitor is a device that stores electrical energy in an electric field. It is composed of two conducting plates separated by an insulating material called a dielectric. When a voltage is applied to the plates, an electric field is created across the dielectric, and this field stores energy.

The voltage across a capacitor, as it is discharged, follows the equation vc=vo*e^(-t/τ). This equation describes the voltage across the capacitor, vc, in terms of the peak voltage v0 and the time constant of the circuit τ. The time constant is simply the time it takes for the voltage across the capacitor to decay to 1/e of its initial value.

So what does this all mean? Basically, the voltage across a capacitor will decay exponentially over time, and the time constant of the circuit will determine how quickly this decay occurs.

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A horse can run at a speed of 12 m/s. At this rate, how long will it take for it to travel 52 m? (Express your answer in sec, rounded to one decimal place.)

Answers

A horse that can run at a speed of 12 m/s will travel a distance of 52 m in a period of 4.33 seconds

We know that,

v = d / t

where,

v = Velocity

d = Distance

t = Time

Given that,

v = 12 m / s

d = 52 m

t = d / v

t = 52 / 12

t = 4.33 s

Velocity is the displacement of an object in a given amount of time. It is denoted by V.

Therefore, the time taken by the horse is 4.33 seconds

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Which event occurs when an atom undergoes nuclear fusion?
OA. Its nucleus loses all its mass.
OB. Its nucleus combines with another nucleus.
C. Its nucleus breaks apart.
OD. Its nucleus absorbs energy.

Answers

Answer:According to the context, its nucleus breaks apart is an event that occurs when an atom undergoes nuclear fission.

Explanation:

a daring ranch hand sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. (don't try this at home.) the speed of the horse is 9.28 m/s and the vertical distance from the limb to the saddle is 3.00 m.

Answers

Using time and velocity relationship, we concluded that he horse will be in air for 0.80 seconds.

What is the relationship between time and velocity?

velocity-time. In evenly accelerated, straight-line motion, the relationship between velocity and time is straightforward. The magnitude of the velocity change increases with lengthier acceleration. When acceleration is constant, the change in velocity is exactly proportional to time.

Both the horse and the human have constant accelerations, which are 0 for the horse and g downward for the human.

(A) Take into account the man's vertical motion after he leaves the limb (with v₀ = 0, yi = 3m).

Finding the man's time of fall from y = y₀ + vt + 1/2 a t² requires modeling him as a particle with continuous acceleration.

when v₀ = 0

t = √(2(y - y₀)/a)

= √ (2(0 - 3) / -9.28)

= √0.64

= 0.80s

Complete Question -

A daring ranch hand sitting on a tree limb wishes to drop vertically onto a horse galloping under the tree. The constant speed of the horse is 10.0m/s, and the distance from the limb to the level of the saddle is 3.00m. (a) For what time interval is he in the air?

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a ball is kicked at an angle of 33 degrees relative to horizontal with a velocity of 70m/s. how much of this velocity is in the vertical direction? group of answer choices

Answers

velocity is in the vertical direction is 38.124m/s

Projectile motion may be defined as a particle moves along the curved pat with the constant acceleration when through near the earth surface.

It is a parabolic because it is affected by gravity.

along x axis velocity responsible for horizontal motion

along y axis velocity responsible for vertical motion

path followed by a projectile is known as a trajectory.

a ball is kicked at an angle of degrees = 33 degree

velocity  of ball, v= 70m/s

v has two components one in horizontal and in one vertical.

velocity is in the vertical direction is given by

[tex]v_{x} = v sin\theta[/tex]

[tex]v_{x} = 70 sin(33)[/tex]

[tex]v_{x} = 38.124[/tex]m/s

velocity is in the vertical direction is 38.124m/s

The given question is incomplete. The complete que is

a ball is kicked at an angle of 33 degrees relative to horizontal with a velocity of 70m/s. how much of this velocity is in the vertical direction? group of answer choices

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A load weighing 0.3 kg was suspended on the left edge of a homogeneous beam weighing 0.4 kg. At what distance from the left edge it is necessary to establish a fulcrum so that the lever is in balance, if the length of the beam is 70cm,​

Answers

The "arm" of the lever is the handle or bar; it is the portion that you push or pull against. The point on which the lever rotates or balances is known as the "fulcrum.

What is  a fulcrum and Lever?

The pivotal point of the beam is known as the fulcrum. A load is applied at the other end of a lever when an effort is exerted to one end of the lever. A mass will be raised as a result.

Torque is essential to the operation of levers. The point on which the lever rotates or balances is known as the "fulcrum. Your hand's fingers serve as the fulcrum when using a fork. A lever's pivot point serves as an illustration of a fulcrum.

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a golfer wants a new set of clubs to improve her game. in an experiment, she goes to the driving range and compares the distance she hits a bucket of golf balls with drivers of different materials in the head before making her purchase decision. in this simple experiment, the independent variable is the group of answer choices swing speed of the golf club prior to striking the golf ball. wind direction when the experiment took place. type of material used to make the club head. distance the golf ball traveled. type of material used to make the golf ball.

Answers

In this simple experiment, the independent variable is the type of material used to make the club head.

What is a club head?

In golf, the bottom of the club is called the club head, or simply the head.

It is the portion of the golf club intended to strike the ball.

Clubheads are also found on putters, irons, hybrids, woods, and drivers.

Many male amateur golfers play the game at clubhead speeds of 80 to 90 mph.

The fastest LPGA pros average 90 to 100 mph. Golfers on the tour typically swing the club at rates of 110 to 115 mph or even more, while long-drive competitors can reach 140 mph.

In golf, torso rotation and wrist position at impact are the best ways to manage clubface angles.

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which areas in the atmosphere could have the lowest concentration of water vapor

Answers

Answer:

Thermosphere. Located between about 80 and 700 kilometers (50 and 440 miles) above Earth's surface is the thermosphere, whose lowest part contains the ionosphere. In this layer, temperatures increase with altitude due to the very low density of molecules found here. It is both cloud- and water vapor-free

Explanation:

i might be wrong

As a freely falling object picks up downward speed, what happens to the power supplied by the gravitational force?.

Answers

As a freely falling object picks up downward speed. What happens to the power supplied by the gravitational force? The power will increase because (Power=work/time; work=f(d); and F x d/t; FV).

What Is Gravity?Greatness is the estimation or supreme esteem of an amount. A size is spoken to by a positive, genuine number.Some illustrations of the drive of gravity incorporate: The drive that holds the gasses within the sun. The drive that causes a ball you toss within the discuss to come down once more. The drive causes a car to coast downhill once you aren't venturing on the gas. The drive that causes a glass you drop to drop to the floor.Forces are the way that vitality is exchanged from one protest to another when they connected, but powers are not the vitality itself. Gravity may be a constrain, so it fair gives one way for objects to trade and change vitality to diverse states.

As a freely falling object picks up downward speed. What happens to the power supplied by the gravitational force? The power will increase because (Power=work/time; work=f(d); and F x d/t; FV).

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A vector with a magnitude of 22 m points due north. A second vector has a magnitude of 12 m, and points due south. What is the magnitude of the resultant?​

Answers

10m North. Since they are forces going in opposite directions, find the larger of the two and subtract the smaller one from it. Also, since theyre pulling from both sides, the side with the stronger magnitude will become smaller after you subtract since that opposite force is acting on it from the other side holding it back.

A simple pendulum has time period of 2s. It is called second pendulum. Fimd the length of second pendulum on earth and moon(gm=g/6)

Answers

The length of the second pendulum on earth is 1m and on the moon 1/6m.

Given:

The time period of a second pendulum T = 2s

By using the formula T = 2π √l/g we can calculate the length of the pendulum on earth and the moon.

Here g = acceleration due to gravity and

l = the length of the pendulum.

Now

l = g(T/ 2π)^2

l = 9.8 m/s^2(2s / 2 x 3.14)^2

le = 1 m

Now calculate the length of the pendulum on the moon

T =  2π √lm/gm      ∴ gm = ge/6

Now putting the value of g we get.

or 2 = 2 π √lm / ge/6

2 = 2 π √6lm / π ^2le

lm = le/6

now given le = 1m

lm = 1/6 m

Thus the length of the second pendulum on earth is 1m and on the moon 1/6m.

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A stone is thrown vertically downward from a cliff 208.0-m tall. during the last half second of its flight, the stone travels a distance of 48.5 m. find the initial speed of the stone.

Answers

A stone is thrown vertically downward from a cliff, the initial speed of the stone is 76.246m/s.

Calculation

Height of the cliff = 208m

Distance travelled during last half second = 48.5 m

According to the second equation of motion:

[tex]s1= vt + 1/2 gt^{2}[/tex]

[tex]v= (2x_{1} - gt^{2})/2t[/tex]

v= [tex]\frac{2(48.5) - (9.8)(0.5)^{2} }{2(0.5)}[/tex]

v= 94.55 m/s

If the initial speed of the ball is u,

then again from the equation of motion, we get initial speed as

u=[tex]\sqrt{v^2 - 2gh}[/tex]

=[tex]\sqrt{94.55^2 -2(9.8)(208-48.5)}[/tex]

u= 76.246 m/s

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you are on an airplane traveling 30° south of due west at 120 m/s with respect to the air. the air is moving with a speed 47 m/s with respect to the ground due north. 1)what is the speed of the plane with respect to the ground?

Answers

Answer:

Vp = 120 cos 210 + 120 sin 210 = Vi1 + Vy1     due East zero coordinates

Vp = -103.9 i - 60 j      vector description of velocity of plane

Vw = 47 j         vector description of wind

V = Vp + Vw = -103.9 i - 13 j

V = (103.9^2 + 13^2)^1/2 = 104.7

Cos θ = -103.9 / 104.7 =  187.1 deg     X-component of final velocity

Sin θ = -13 / 104.7 = 187.13 deg      Y-component of final velocity

(Final velocity = 104.7 m/s        7.1 deg S of W)

An object is dropped from a 32 m tall building. How fast will it be going when it strikes
the ground?

Answers

Answer: 25.04m/s

Explanation:

v^2 = v^2o + 2a(x-xo)

v^2 = velocity 

v^2o = initial velocity 

a = acceleration 

x = final position/distance 

xo = initial position/distance

In this case, the initial velocity is 0 since the ball wasn't moving before it was dropped. The final position is 32 as the motion ended after the ball traveled 32m. The initial position is 0. The acceleration is 9.8m/s (free fall). Plug these numbers into the formula: 

v^2 = 0 + 2(9.8)(32)

v^2 = 25.04396135 

Round to get 25.04m/s

experimenter a uses a test charge q0 and experimenter b uses a test charge 2q0 to measure an electric field produced by stationary charges. a finds a field that is:

Answers

A finds a field that is the same as the field found by B.

How to find the electric field?

The physical field that surrounds electrically charged particles and acts to either attract or repel all other charged particles in the field is known as an electric field (or E-field). Additionally, it describes the physical environment of a system of charged particles.

No matter how large the test charge is, stationary charges always produce the same electric field at a certain area.

At a distance "r" from it, the electric field created by a stationary charge "q" is given as

[tex]E = K_{q} /r^{2}[/tex]

Thus, the appropriate option is e) the same as the field found by B.

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the average weight of an elephant is 4000N the surface area of thr sole of its foot is 0.1m^2 calculate the pressure by one foot of an elephant

Answers

Answer

Explanation:pressure = Force/area

Force = 4000N

Area=0.1m

pressure = 4000/0.1

=40000P.a

Which of the following is a liquid?
OA. Steak
OB. Sugar
OC. Juice
OD. Smoke

Answers

Answer: Juice

Explanation:

Juice would be the answer. Your answer is C

In a competition, an athlete threw a flying disk 137.4 meters through the air. while in flight, the disk traveled at an average speed of 10.9 m/s. how long did the disk remain in the air?

Answers

The answer is 12.6 seconds.

What is the average speed?The distance traveled is divided by the time interval to determine average speed.For instance, someone traveling at an average speed of 40 miles divided by 40 minutes, or 1 mile per minute, is traveling 20 miles north and then 20 miles south (60 mph).Distance is divided by time to obtain average speed, expressed in miles per hour. Okay, let's speak about average speed. Instantaneous speed refers to the distance you are traveling at a given moment. The total distance you will go over a period of time at an average speed of 100 kilometers per hour is thus.

How long did the disk remain in the air:

Given data:

d= 137.4 meters

v=10.9 m/s

v=d/t

t=d/v

t=137.4/10.9

t=12.6 seconds.

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the football team at enormous state university (esu) uses vector displacements to record its plays, with the origin taken to be the position of the ball before the play starts. in a certain pass play, the receiver starts at 1.0i^−5.0j^, where the units are yards, i^ is to the right, and j^ is downfield. subsequent displacements of the receiver are 7.0i^ (he is in motion before the snap), 8.0j^ (breaks downfield), −7.0i^ 3.0j^ (zigs), and 11.0i^ 12.0j^ (zags). meanwhile, the quarterback has dropped straight back to a position −7.0j^.

Answers

We shall use the ideas connected to the vector sum to develop this issue. To achieve this, we will add the person's displacement vectors to determine the total distance he has gone from the initial point (0 position) to the destination position.

Then quarterback will throw the ball 44.4 yards in a particular direction with the angle of  54.16 °

t = 25.1seconds.

X(t)= 16cos75°t

Y(t)= 6 + (Vosin75°t - 16t^2)

Converting 78 yards to feet :

1 yard = 3 feet

78feet =?

78×3=234 feet

Y(t)= number of feet above the ground at t seconds

VoCos75° t = 234

t = 234/(VoCos75°)

At this time,4 = y(234/VoCos75°)

4 = 6 + VoSin75°(234/VoCos75) - 16(234/VoCos75°)^2

Vo= 140.66ft/s

Time,t= 234/(140.66× Cos75°)

t = 25.087seconds

t= 25.1 seconds (1 decimal place)

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How many valence electrons does the ground-state electron configuration of nitrogen have?.

Answers

The last shell of nitrogen has five electrons, according to the nitrogen's electron arrangement. Therefore, nitrogen has five valence electrons.

What are valence electrons?

The valence shell is the final shell to be formed after the configuration of the electrons.

A valence electron is any electron that is present in a valence shell as a whole.

Eg: Since nitrogen has a 7-atomic structure, the atom will contain seven electrons.

Nitrogen's ground state electrical arrangement will be 1s22s22p3.

It has 5 valence electrons.

The number of valence electrons for neutral atoms is the same as its main group number.

An element's column on the periodic table can be used to determine its major group number.

Carbon, for instance, belongs to group 4 and has four valence electrons. With 6 valence electrons, oxygen belongs to group 6.

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which of the following best represents r = a - b

Answers

Option A from the following options represents the resultant vector r = a-b, therefore the correct answer is option A.

What is a vector quantity?

The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.

Examples of vector quantities are displacement, velocity acceleration, force, etc.

As given in the problem we have to find out which of the following vector best represents r = a - b,

As per the triangle law of the vector addition, the resultant sum is represented by the closing side of the triangle in regular order.

Thus, the correct answer is option A.

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Change 1m² into cm², mm² and km²

Answers

Answer:

1m² = 10000cm²

1m² = 1000000mm²

1m² = 1e-6km²

Which of these coloured stars has the highest surface temperature?
A orange
B red
C white
D yellow

Answers

C white, white is hotter then red

consider a uniformly charged ring in the xy plane, centered at the origin. the ring has radius aaa and positive charge qqq distributed evenly along its circumference.

Answers

The electric field along the [tex]z[/tex] axis is [tex]E\left( z \right) = \frac{{kqz}}{{{{\left( {{z^2} + {a^2}} \right)}^{\frac{3}{2}}}}}[/tex]

The radius of the ring is: [tex]a[/tex]

The charge on the ring is: [tex]q[/tex]

The coulomb's constant is: [tex]k = \frac{1}{{4\pi {\varepsilon _0}}}[/tex]

The expression of the electric field is: [tex]E = \frac{{kq}}{{{r^2}}}[/tex] .......(i)

Here,

[tex]r[/tex] ⇒ distance = [tex]\sqrt {{z^2} + {a^2}}[/tex]

Now, putting [tex]r[/tex] in equation (i), we get,

[tex]\begin{array}{c}\\E = \frac{{kq}}{{{{\left( {\sqrt {{z^2} + {a^2}} } \right)}^2}}}\\\\ = \frac{{kq}}{{\left( {{z^2} + {a^2}} \right)}}\\\end{array}[/tex]

The electric field along the z-direction is

[tex]dE\left( z \right) = dE\cos \theta[/tex] ........(ii)

here, [tex]\cos \theta = \frac{z}{{\sqrt {{z^2} + {a^2}} }}[/tex]

Integrating equation (ii), we get,

[tex]\begin{array}{c}\\\int {d{E_z}} = \int {dE\cos \theta } \\\\E\left( z \right) = E\cos \theta \\\end{array}[/tex].......(iii)

Now substituting the values in equation (iii), we get,

[tex]\begin{array}{c}\\E\left( z \right) = \left( {\frac{{kq}}{{\left( {{z^2} + {a^2}} \right)}}} \right)\left( {\frac{z}{{\left( {\sqrt {{z^2} + {a^2}} } \right)}}} \right)\\\\ = \frac{{kqz}}{{{{\left( {{z^2} + {a^2}} \right)}^{\frac{3}{2}}}}}\\\end{array}[/tex]

Therefore, the electric field along the [tex]z[/tex] axis is [tex]E\left( z \right) = \frac{{kqz}}{{{{\left( {{z^2} + {a^2}} \right)}^{\frac{3}{2}}}}}[/tex]

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Consider a uniformly charged ring in the [tex]xy[/tex] plane, centered at the origin. The ring has radius [tex]a[/tex] and positive charge [tex]q[/tex] distributed evenly along its circumference. What is the magnitude of the electric field along the positive [tex]z[/tex] axis? Use k in your answer, where [tex]k = \frac{1}{4 \pi \epsilon_0}[/tex]

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