Answer:
The value is [tex]S_a = 72.56 \ dB[/tex]
Explanation:
From the question we are told that
The sound level is [tex]S = 60 dB[/tex]
The distance from the source is d = 1 m
The number of sources is n = 18
Generally the sound which the person is been exposed to is mathematically represented as
[tex]S_a = S + 10log(18)[/tex]
=> [tex]S_a = 60 + 10log(18)[/tex]
=> [tex]S_a = 72.56 \ dB[/tex]
Suppose you exert a force of 180 N tangential to a 0.280-m-radius, 75.0-kg grindstone (a solid disk). (a)What torque is exerted
Answer:
[tex]\tau = 50.4Nm\\[/tex]
Explanation:
Torque is expressed according to the formula;
[tex]\tau = Fr\\[/tex]
F is the force exerted
r is the radius
Given
F = 180N
r = 0.280m
Required
Torque
Substitute into the formula and get torque
[tex]\tau = 180 \times 0.280\\\tau = 50.4Nm\\[/tex]
Hence the torque exerted is 50.4Nm
An object with mass 3.3 kg is executing simple harmonic motion, attached to a spring with spring constant 260 N/m . When the object is 0.017 m from its equilibrium position, it is moving with a speed of 0.40 m/s . Part A Calculate the amplitude of the motion. Express your answer to two significant figures and include the appropriate units.
Answer: the amplitude of the motion is 0.048 m
Explanation:
Given that;
mass m = 3.3 kg
spring constant k = 260 N/m
When the object is x = 0.017 m from its equilibrium position,
it is moving with a speed of v = 0.40 m/s
amplitude of the motion = ?
we know that;
formula for Potential of the string PE = 1/2kx²------1
Kinetic energy KE = 1/2mv² --------2
Now expression for the maximum potential energy of the spring is
PE_max = 1/2 kx²_max -----3
Now from conservation of Energy
PE_spring = PE + KE
from our equation 1, 2 and 3
1/2kx²_max = 1/2kx² + 1/2mv²
now we rearrange for x_max
x²_max = (1/2kx² + 1/2mv²) / 1/2k
x²_max = (kx² + mv²) / k
x_max = √ [(kx² + mv²) / k]
now we substitute our values into the equation
x_max = √ [(260(0.017)² + 3.3×(0.40)²) / 260]
= √((0.07514 + 0.528) / 260)
= √(0.60314 / 260)
= √ 0.002319
x_max = 0.048 m
Therefore the amplitude of the motion is 0.048 m
4. AN OBJECT INCREASES ITS VELOCITY
FROM 22 M/S TO 36 M/S IN 5 S. WHAT IS
THE ACCELERATION OF THE OBJECT?
ET
Answer:
it is accelerating 14 m/s
Explanation:
Answer: 14/5
Explanation:
The object changed its velocity from 22 m/s to 36 m/s which is an increase of 14 m/s
This occurred in 5 seconds so the acceleration is 14/5 = 2.8 m/s^2
How does cyanoacrylate compare to the elements
that make it up?
HELPPPPP NOWWWWW
Explanation:
It exists in the tube as single molecules in liquid form. But when they come into contact with water, the molecules react with hydroxide ions to form long polymer chains that set into a hard solid. As there is a thin layer of moisture covering most surfaces, cyanoacrylate can bond them together very effectively.
HELP PLEASE
When a magnet spins in a oil of wire it generates
A. Magnetism
B.convection
C. Radiation
D.electricity
Answer:
A, Magnetism
Explanation:
An ordinary electric generator produces electric power by spinning a strong magnet inside a set of wire coils. As the magnet spins, its magnetic field sweeps across the coils and gives rise to electric fields in those coils.
Hope this helps!!
An ice skater applies a horizontal force to a 150 N block on frictionless, level ice, causing the block to accelerate uniformly at to the right. After the skater
stops pushing the block, it slides onto a region of ice that is covered with a thin layer of sand. The coefficient of kinetic friction between the block and the
sand-covered ice is 0.36.
Calculate the magnitude of the force of friction acting on the block as it slides over the sand-covered ice
Answer:
The friction force has a magnitude of 54 N and points to the left
Explanation:
Friction Force
When an object is moving and encounters friction in the air or rough surfaces, it loses acceleration because the friction force opposes motion.
The friction force when an object is moving on a horizontal surface is calculated by:
[tex]Fr=\mu N[/tex]
Where \mu is the coefficient of static or kinetics friction and N is the normal force.
If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:
N = W
Thus, the friction force is:
[tex]Fr=\mu W[/tex]
The ice skater accelerates a block to the right on frictionless horizontal ice and then stops pushing it. The block continues to move at a constant speed when it finds a sand-covered surface with a kinetic coefficient of friction of 0.36.
The friction force is:
Fr=0.36*150
Fr = 54 N
The friction force has a magnitude of 54 N and points to the left
cooking utensils are made up of metal
Explanation:
Cooking utensils are made of metal such as copper, aluminium, brass, steel etc., so that heat is easily conducted through the base to their contents. But they are provided with handles of bad conductors
Two magnets are placed near each other on a space station orbiting Earth.
Their north and south poles are facing each other. Which statement explains
what will happen to the magnets?
O A. They will be attracted because they are in each other's magnetic
field.
B. They will be repelled because they are in each other's gravitational
field.
O C. They will be attracted because they are in each other's electric
field.
O D. They will be repelled because they are in each other's magnetic
field.
Two magnets are placed near each other on a space station orbiting Earth and their north and south poles are facing each other then they will be attracted because they are in each other's magnetic field. The correct option is A.
What is a magnetic field?A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted.
For a simple bar magnet, N-pole and S-pole are the points on a magnet that have the strongest magnetic field. The magnetic field originates from the north pole and terminates in the south pole of a magnet.
For two magnets placed in space with north and south poles are facing each other they will be attracted because they are in each other's magnetic field. Therefore the correct option is A.
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you pick up a 3.8 kg can of paint from the ground a lift it to a height of 1.4 m. you hold the can stationary for half a minute, waiting for a friend on a ladder to take it. how much work do you do duting this time (when the can of paint is stationary)?
Answer:
No work
Explanation:
During the time of holding the can stationary, no work is being done by the person carrying the can.
The can is simply at rest.
Work is done when a force is applied to move a body through a certain distance.Work done = force x distance
In the instance given in this problem, only when the paint was lifted up is work done.
When the paint is stationary and being supported by the person, no work is done.
Which statement best describes why specific heat capacity is often more useful than heat capacity for scientists when comparing two materials?
Answer:
Specific heat capacity is an intensive property and does not depend on sample size.
Explanation:
1. On a force vs. mass graph, what would be the slope of the line?
2. On a Free Body Diagram, if the forces are all balanced, what do you know about the
object? Can it be moving?
1. By Newton's second law,
F = m a
so the slope of the line would represent the mass of the object.
2. If all the forces are balanced, then the object is in equilibrium with zero net force, which in turn means the object is not accelerating. So the object is either motionless or moving at a constant speed.
1. Final position minus the initial position is called
A 125 g pendulum bob hung on a string of length 35 cm has the same period as when the bob is hung from a spring and caused to oscillate. What is the spring’s elastic constant?a) 3.5 N/mb) 5.2 N/mc) 1.9 N/md) 27 N/m
Answer:
k = 3.5 N/m
Explanation:
It is given that the time period the bob in pendulum is the same as its time period in spring mass system:
[tex]Time\ Period\ of\ Pendulum = Time\ Period\ of\ Spring-Mass\ System\\2\pi \sqrt{\frac{l}{g}} = 2\pi \sqrt{\frac{m}{k}[/tex]
[tex]\frac{l}{g} = \frac{m}{k}\\\\ k = g\frac{m}{l}[/tex]
where,
k = spring constant = ?
g = acceleration due to gravity = 9.81 m/s²
m = mass of bob = 125 g = 0.125 kg
l = length of pendulum = 35 cm = 0.35 m
Therefore,
[tex]k = (9.81\ m/s^2)(\frac{0.125\ kg}{0.35\ m})\\\\[/tex]
k = 3.5 N/m
A monatomic ideal gas with volume 0.230 L is rapidly compressed, so the process can be considered adiabatic. If the gas is initially at 1.01 105 Pa and 3.00 102 K and the final temperature is 489 K, find the work done by the gas on the environment, Wenv.
Answer:
The value is [tex]W = - 17.53 \ J[/tex]
Explanation:
From the question we are told that
The volume is [tex]V = 0.230 \ L = 0.230 *10^{-3} \ m^{-3}[/tex]
The initial pressure is [tex]P_1 = 1.01105 \ Pa[/tex]
The initial temperature is [tex]T_1 = 3.00*10^2 \ K[/tex]
The final temperature is [tex]T_2 = 489 \ K[/tex]
Generally for an adiabatic process the workdone is mathematically represented as
[tex]W = - \Delta U[/tex]
Here [tex]\Delta U[/tex] is the internal energy of the system which is mathematically represented as
[tex]\Delta U = \frac{3}{2} * nR \Delta T[/tex]
So
[tex]W = - \frac{3}{2} * nR \Delta T[/tex]
Generally from ideal gas equation we have that
[tex]n = \frac{P_1V }{ RT_1 }[/tex]
Here R is the gas constant with value [tex]R = 8.314 J/mol\cdot K[/tex]
So
[tex]n = \frac{1.01 *0^{5} * 0.230 *10^{-3}}{ 8.314 * 3.0*10^2 }[/tex]
=> [tex]n = 0.009313 \ mol[/tex]
So
[tex]W = - \frac{3}{2} * 0.009313 * 8.314 * (451 - 3.00*10^2)[/tex]
=> [tex]W = - 17.53 \ J[/tex]
a 16-slug mass is raised by 10 ft. the PE of the mass increased by?
Answer:
The PE of the mass increased by 6,972.95 J
Explanation:
Gravitational Potential Energy
It's the energy stored in an object because of its vertical position or height in a gravitational field.
It can be calculated with the equation:
U=m.g.h
Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8 m/s^2.
We are given the mass of m=16 slug raised by a height h=10 ft. Both units will be converted to SI standard:
1 slug = 14.59 Kg, thus
16 slug = 16*14.59 Kg=233.44 Kg
1 ft = 0.3048 m, thus:
10 ft = 10*0.3048 m = 3.048 m
Thus, the PE of the mass increased by:
U = 233.44 * 9.8 * 3.048 = 6,972.95 J
the PE of the mass increased by 6,972.95 J
The potential energy will be "5120 ft.lb".
According to the question,
Mass,
m = 16 slugsHeight,
h = 10 ftAs we know the formula,
→ [tex]U = mgh[/tex]
By substituting the values, we get
→ [tex]= 16\times 32\times 10[/tex]
→ [tex]= 5120 \ ft.lb[/tex]
Thus the response above is correct.
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In an oil drop experiment, a drop with a weight of 1.9 x 10-14 N was suspended when the potential difference between 2 plates that were 63 mm apart was 780 V. What was the charge on the drop?
Answer:
Study More You will get it :L
As the mass of a body increases, its gravitational force of attraction to the Earth...
Answer:
the answer may be mass and distance
What do you mean by pressure of a liquid? Write its Sl unit.
Answer:
Explanation:
The pressure of a liquid is the rate of the force applied by the liquid on a surface per unit area of the surface.
i.e P = [tex]\frac{F}{A}[/tex]
where P is the pressure, F is the force and A is the area.
The depth of the liquid determines its pressure at a definite lower point. As the pressure of a liquid at the bottom of a its container is greater than the pressure at the top of the liquid.
Thus,
P = σhg
where P is the pressure, σ is the density of the liquid, h is the height and g is the force of gravity.
It is measured in Pascals or N[tex]m^{-2}[/tex].
The pressure of liquid has a lot of applications, viz: siphon, force pump, lift pump etc.
What fraction of an iceberg is submerged? (ρice = 917 kg/m3, ,ρsea = 1030 kg/m3.)
Answer:
Choice d. Approximately [tex]89\%[/tex] of the volume of this iceberg would be submerged.
Explanation:
Let [tex]V_\text{ice}[/tex] denote the total volume of this iceberg. Let [tex]V_\text{submerged}[/tex] denote the volume of the portion that is under the liquid.
The mass of that iceberg would be [tex]\rho_\text{ice} \cdot V_\text{ice}[/tex]. Let [tex]g[/tex] denote the gravitational field strength ([tex]g \approx 9.81\; \rm N \cdot kg^{-1}[/tex] near the surface of the earth.) The weight of that iceberg would be: [tex]\rho_\text{ice} \cdot V_\text{ice} \cdot g[/tex].
If the iceberg is going to be lifted out of the sea, it would take water with volume [tex]V_\text{submerged}[/tex] to fill the space that the iceberg has previously taken. The mass of that much sea water would be [tex]\rho_\text{sea} \cdot V_\text{submerged}[/tex].
Archimedes' Principle suggests that the weight of that much water will be exactly equal to the buoyancy on the iceberg. By Archimedes' Principle:
[tex]\text{buoyancy} = \rho_\text{sea} \cdot V_\text{submerged} \cdot g[/tex].
The buoyancy on the iceberg should balance the weight of this iceberg. In other words:
[tex]\underbrace{\rho_\text{ice} \cdot V_\text{ice} \cdot g}_\text{weight of iceberg} = \underbrace{\rho_\text{sea} \cdot V_\text{submerged} \cdot g}_\text{buoyancy on iceberg}[/tex].
Rearrange this equation to find the ratio between [tex]V_\text{submerged}[/tex] and [tex]V_\text{ice}[/tex]:
[tex]\begin{aligned} &\frac{V_\text{submerged}}{V_\text{ice}} \\&= \frac{\rho_\text{ice} \cdot g}{\rho_\text{sea} \cdot g}\\ &= \frac{\rho_\text{ice}}{\rho_\text{sea}}\ = \frac{917\; \rm kg \cdot m^{-3}}{1030\; \rm kg \cdot m^{-3}} \approx 0.89 \end{aligned}[/tex].
In other words, [tex]89\%[/tex] of the volume of this iceberg would have been submerged for buoyancy to balance the weight of this iceberg.
Max observes a spaceship traveling toward him at 0.75c. He measures its length and finds that the spaceship is 250 m long. The ship brakes hard and skids to a stop on a nearby airstrip. Max remeasures the spaceship. What length does he find
Answer:
380m
Explanation:
We have the speed of the spaceship v = 0.75c
Max measures contracted length L of the spaceship as it travels
We have been given L = 250m
As this ship stops he is going to get exact length of the ship = Lol
We solve using this formula
L = Lo√ 1-v²/c²
From the formula above we make Lo subject of the formula
When we input values
Lo = 250/√1-(0.75c/c)²
= 250/√1-(0.75)²
= 250/√0.4375
= 250/0.6614
= 377.98
This is approximately 380
(2)
(Total 6 marks)
6
Karen wants to pump up her car tyre.
Her pump has a piston with an area of 7 cm^2
175 N
area = 7 cm^2
Karen pushes the handle down with a force of 175 N.
(a)
What pressure does she exert on the air in the pump?
Answer:
250000Pa
Explanation:
Given parameters:
Force applied = 175N
Area = 7cm²
Unknown:
Pressure exerted by the air in the pump = ?
Solution:
Pressure is the force per unit area acting on a body;
Pressure = [tex]\frac{force }{area}[/tex]
Area = 7cm² ;
10000cm² = 1m²
7cm² is 7 x 10⁻⁴m²
Pressure = [tex]\frac{175}{0.0007}[/tex] = 250000Pa
Choose the correct answer
Answer:
1.(c) 7
2.(d) 900
3.(b) two
4.(c) 0.0007
5.(d)0.0004
Explanation:
(1) White light after reflection through prism splits into 7 colors.
(2) Arabs and Chinese knew about lenses in about 900 AD
(3) There are Two more colors in the spectrum which cannot be seen with naked eye.
(4) Wavelength of red light is 0.0007mm
(5) Wavelength of violet light is 0.0004mm
Runner A is initially 8.0 mi west of a flagpole and is running with a constant velocity of 7.0 mi/h due east. Runner B is initially 8.0 mi east of the flagpole and is running with a constant velocity of 6.0 mi/h due
west. How far are the runners from the flagpole when they meet?
The runners meet at 0.615mi away from the flagpole due to constant velocity.
Velocity informs us of the rate of change of your position, or how quickly your location is altering in relation to time. The difference between your end and beginning positions is referred to as displacement in physics, and velocity is defined as displacement divided by time. Additionally, an object is considered to be moving with constant velocity if it covers the same distance every second.
A vector is a speed that is constant. For a quantity to be fully described, it needs both a magnitude and a direction. Distance per time units is defined as constant velocity. The velocity tells you how quickly your distance is changing per unit of time or how quickly your location is changing.
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Which component of an atom contains the MAJORITY
of its mass?
Answer:
proton and neutrons
Explanation:
electron has negligible mass
A daring squirrel runs toward a cat, then turns around to safety. A graph of its velocity over time is shown
below.
Answer:
it's 1.0
Explanation:
kahn academee
When a tennis ball is spun around in a circle on a string and the string breaks the tennis ball
will be pulled in a curved path away from the center because of Centrifugal force
True or false
Answer:
False
whenever the string breaks, the ball will follow the straight line tangential path
Explanation:
No, the ball will not follow a curved path after the string breaks. Since, the the direction of velocity is tangential to each point of the circular motion. Therefore, it changes at every point. This produces an acceleration in the circle called centripetal acceleration. There is also a tangential component of acceleration acting on the ball during this motion.
So, whenever the string breaks, the ball will follow the straight line tangential path. Hence, the given statement is false.
what is the velocity of this graph between points b and c
Answer:
D.) 0 m/s
Explanation:
This is a position versus time graph. These graphs compare the position of an object versus the elapsed time. You can find the velocity of position vs. time graphs by determining the slope between the two points.
The formula used to find slope is:
y₁ - y₂ = m(x₁ - x₂)
In this formula, "x₁" and "y₁" represent the values from one point, "x₂" and "y₂" represent the values from the second point, and "m" represents the slope.
If the first point, B, is at (1, 6) and the second point, C, is at (3, 6)...
6 - 6 = m(1 - 3) <----- Insert values from points
0 = m(-2) <----- Subtract
0 = m <----- Divide both sides by -2
In this case, the slope between point B and point C is 0. Thus, there is a constant velocity of 0 m/s between the points.
Starting with the definitions of momentum and kinetic energy, derive an equation for the kinetic energy of a particle expressed as a function of its momentum.
Answer:
[tex]K.E = (\frac{1}{2})Pv[/tex]
Explanation:
The momentum of a particle is defined as the product of its mass and velocity:
[tex]P = mv[/tex] -------------------- equation (1)
where,
P = momentum of the particle
m = mass of the particle
v = velocity of the particle
The kinetic energy of the particle is given as follows:
[tex]K.E = (\frac{1}{2})mv^2\\\\K.E = (\frac{1}{2})v(mv)[/tex]
using equation (1), we get:
[tex]K.E = (\frac{1}{2})Pv[/tex]
g volume of 0.025 m3. If the temperature of the gas is 290 K, what is the rms speed of the gas atoms
This question is incomplete, the complete question is;
Argon gas (a monatomic gas) is sometimes used to insulate a double-pane window for purposes of insulation. In a particular window, the space in between two glass sheets has a volume of 0.025 m³.
If the temperature of the gas is 290 K . what is the rms speed of the gas atoms ?
The atomic mass of Argon is 39.9 u.
(1 u = 1.66 x 10⁻²⁷ kg) Enter your answer in m/s.
Enter your Answer in m/s
Answer: the rms speed of the gas atoms is 425.754 m/s
Explanation:
Given that;
mass of Argon = 39.9 u
and 1 u = 1.66 x 10⁻²⁷ kg
so 39.9 × 1.66 x 10⁻²⁷ kg = 6.6234 x 10⁻²⁶
Temperature T = 290 K
Now
V_rms = √( 3KT / M)
where Boltzmann's constant K = 1.38 × 10⁻²³ m²kg s⁻² K⁻¹
so we substitute
V_rms = √( 3 × 1.38 × 10⁻²³ × 290 / 6.6234 x 10⁻²⁶)
V_rms = √( 181266.419)
V_rms = 425.754 m/s
Therefore the rms speed of the gas atoms is 425.754 m/s
The terms transverse or longitudinal are often used to describe the types of pulses. To what feature of a pulse do these terms refer:____________
Explanation:
Transverse pulse or waves are those in which elements of the pulse move perpendicular to the propagation of the pulse. Whereas, Longitudinal waves are those in which elements of the wave are in same direction as the propagation of the wave. For example Light is a transverse pulse whereas sound is a longitudinal wave.