According to uniform motion, the initial projection angle is 73.89⁰.
We need to know about uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From question above, we know that
vpeak = 1/2 vt
2vpeak = vt
when projectile at maximum height should equal
vpeak = vx = vo.cosθ
When the projectile reaches a half its maximum height, the time taken is
t = 1/2 tpeak
t = 1/2 (vo sinθ/g)
t = vo sinθ/2g
Find the speed at its half maximum height.
vty = voy + a . t
vty = vo.sinθ - g.vo sinθ/2g
vty = vo sinθ/2
vtx = vo cosθ
vt = √vty² + vtx²
2vpeak = √(vo sinθ/2)² + (vo cosθ)²
2 . cosθ = √(sinθ/2)² + (cosθ)²
4cos²θ = 1/4 . sin²θ + cos²θ
3cos²θ = 1/4 . sin²θ
sin²θ / cos²θ = 12
tan²θ = 12
tanθ = √12
θ = 73.89⁰
Find more on uniform motion at: https://brainly.com/question/28040370
#SPJ4
identify the fringe or fringes that result from the interference of two waves whose path difference differs by exactly 2λ2λ . enter the letter(s) indicating the fringe(s) in alphabetical order. for example, if you think that fringes a and c are both correct,
The waves that differ is:
Δx = 2λ
The constructive interference is equal: ΔΦ = 2nπ
If
n = 0, central bright fringe
n = ±1, first maxima on both fringes
n = ±2, second maxima on both fringes
What is maxima?
The maxima and minima of a function, collectively referred to as extrema in mathematical analysis, are the highest and lowest values of the function, either on the whole domain or within a specific range.
Therefore,
identify the fringe or fringes that result from the interference of two waves whose path difference differs by exactly 2λ2λ . enter the letter(s) indicating the fringe(s) in alphabetical order. for example, if you think that fringes a and c are both correct,
The waves that differ is:
Δx = 2λ
The equation for phase difference is:
The constructive interference is equal: ΔΦ = 2nπ
If
n = 0, central bright fringe
n = ±1, first maxima on both fringes
n = ±2, second maxima on both fringes
To learn more about maxima from the given link:
https://brainly.com/question/18687565
#SPJ4
When a coin is tossed in the air, it travels upward, gradually slows down, momentarily reaches zero speed, then moves back
downward with increasing speed. Which statement best explains this change in the coin's motion?
a.The force of gravity causes the coin to change its velocity.
b.The coin's inertia decreases on the way up and increases on the way down.
c.The action-reaction force pair of gravity and the applied force cancel each other.
d.The coin remains in its state of upward motion until the force.
A. The force of gravity causes the coin to change its velocity.
What is the effect of force gravity on the upward motion of an object?
Force of gravity always act toward the center of the earth , so when an object is thrown up, the force of gravity will act in opposite direction of motion, that's toward the center of earth.
This will cause the object moving upwards to slow down due to the force of gravity acting on the opposite direction of the object's upward motion.
When a coin is tossed in the air, it travels upward, gradually slows down, momentarily reaches zero speed, then moves back downward with increasing speed due to effect of force of gravity.
Thus, the statement that best explains the change in the coin's motion is "The force of gravity causes the coin to change its velocity".
Learn more about force of gravity here: https://brainly.com/question/10119978
#SPJ1
a monkey is swinging from a tree. on the first swing, she passes through an arc whose length is 24. with each swing, she travels along an arc that is half as long as the arc of the previous swing
L = 24 + 12 + 6 + 3 + 1.5 + 0.75 + 0.375 + 0.1875 + ......+ 0.5X(n-1) expression gives the total length the monkey swings in her first n swings.
How to find the expression?The first swing's length was 24 meters.
The monkey only covers half of the arc's length in each swing.
First, n swings' cumulative length equals?
Total swing length is equal to the initial swing's length plus 0.5 times that amount plus the next number of swings.
i.e., Total length of n swings = length of first swing + 0.5 X length of first swing + .....+ length of n swings
L = 24 + 12 + 6 + 3 + 1.5 + 0.75 + 0.375 + 0.1875 + ...
Therefore, the expression is
L = 24 + 12 + 6 + 3 + 1.5 + 0.75 + 0.375 + 0.1875 + ......+ 0.5X(n-1)
To learn more about length, refer
https://brainly.com/question/16651806
#SPJ4
A car and a delivery truck both start from rest and accelerate at the same rate. However, the car accelerates for twice the amount of time as the truck. What is the final speed of the car compared to the truck?.
Answer: twice as much
Explanation:
you're welcome!
A car goes from 30 m/s to 10 m/s how long does it take with a acceleration of -2
[tex] \large \bf \implies{s = 200 \: m}[/tex]
Step-by-step explanation:Given :Initial velocity (u) = 30 m/sFinal velocity (v) = 10 m/sAcceleration (a) = -2 m/s²To Find :-Distance (s) = ?Solution :-Using third equation of motion we have find the distance :2as = v² - u²Putting the values according to equation :2 × (-2) × s = (10)² - (30)²-4s = 100 - 900-4s = -800[tex]s = \frac{ \cancel{- 800}}{ \cancel{- 4}}[/tex]s = 200 mShe takes a random sample of mcdonald's restaurants from florida, georgia, alabama, and tennessee, and calculates a chi-square test statistic of 2.589 and a p-value = 0.7682.
Option A) Since the p-value is greater than 0.05, we have no evidence that the sandwiches are not purchased similarly across all the four different states as per the statistical data.
How do statistics work?A statistic, according to the Longman Dictionary of Contemporary English, is a person who has perished as a result of a specific type of accident or illness and is merely another statistic.
These things cannot be reduced to a statistic data.
In conclusion, there are a total of five reasons to study statistics. These are, to be able to conduct research efficiently, to read and evaluate journal articles, to further develop critical thinking and then also develop proper analytical skills, to act as an informed consumer, and to then recognize the times whenever you get the need to hire outside statistical help.
As per the question,
p = 0.7682
and thus, we have p > 0.05
And if p > 0.05 then we fail to reject the null hypothesis and results are not significant.
To know more about statistics visit:
https://brainly.com/question/8058700
#SPJ4
How much force is needed to accelerate a 1400 kg car from rest to 14 meters/sec in 7 seconds?
Answer:
2800 N
Explanation:
Acceleration = change in velocity / change in time
= 14 m/s / 7 s = 2 m/s^2
F = ma
= 1400 (2) = 2800 N
If a score in a distribution changes in numerical value, it will necessary change ______.
If a score in a distribution change in numerical value, it will necessarily change mean.
Will the mean of distribution always change if a new score is added to it?Increasing a current score: Changing one score into another will change the mean since every score in a distribution affects the mean’s value.
The mean will increase in value if an existing score is valued higher. The value of the mean will fall if an existing score’s value is reduced.
The frequency distribution of which is split in half.There are 50% of observations on either side of the median value, which divides the distribution in half.
The median value is the midpoint in distribution with an odd number of observations.
To know more about the mean visit:
https://brainly.com/question/17002881
#SPJ4
When a 4.62 kg object is placed on top of a vertical spring, the spring compresses a distance of 2.28 cm. what is the force constant of the spring?
The force constant of the spring that compresses a distance of 2.28 cm when a 4.62 kg object is placed on top is 1.59 kN/m.
CalculationWhen the object comes to equilibrium, we have
∑[tex]F_{y}[/tex] = -k(-[tex]y_{0}[/tex]) -mg =0
The force constant
k=[tex]\frac{mg}{y_{0} }[/tex] = [tex]\frac{4.25*9.80}{2.62*10^{-2} }[/tex]
=1.59 x [tex]10^{3}[/tex] N
=1.59 KN/m
What is the formula for the spring constant?Spring constant is used to identify whether a spring is stable or unstable, and consequently, what system it should be employed in. It is stated mathematically as k = - F/x, which reworks Hooke’s Law.
Where x is the displacement caused by the spring in N/m, F is the force applied over x, and k is the spring constant.
To know more about spring force visit:
https://brainly.com/question/14655680
#SPJ4
An athlete from your school's cross country team goes for a training
run. she runs 3.6 km east, 4.5 km north, then another 2.4 km east. at the
end of her run, how far is the athlete from her starting position?
(remember, you can rearrange the vectors to make a right triangle and
use pythagorean theorem).
2.4 km
4.5 km
- 3.6 km
The athlete is 7.5 km North east from the starting point.
Consider the athlete's starting point as A. After running 3.6 km east from A, consider the point as B. After running 4.5 km north from B, consider the point as C. After running 2.4 km from C, consider the point as D.So the distance from starting point to ending point is AD.Total distance travelled east is 3.6 + 2.4 = 6 kmTotal distance travelled east is 4.5 kmThis forms a right angled triangle, where AD is the hypotenuse and the distance travelled east and north are the other two sidesAccording to Pythagoras theorem,
[tex]AD^{2}[/tex] = [tex]6^{2}[/tex] + [tex]4.5^{2}[/tex]
AD = √ 36 + 20.25
AD = √ 56.25
AD = 7.5 km
Therefore, the athlete is 7.5 km North east from the starting point.
To know more about Pythagoras theorem
https://brainly.com/question/343682
#SPJ4
A stalled car has a mass of 1,000 kg. It is pushed forward with a force of
2,000 N. At what rate does the car accelerate?
O 0.5 m/s
O
0.5 m/s/s
0.5 m/s/s Forward
YAN
2 m/s
O2 m/s/s
O2 m/s/s Forward
The acceleration of the stalled car is 0.5 m/ s^2 forward.
By the formula of force we know that F = m X a
so in this question, mass = 1000kg , and F = 2000N
so acceleration of the car = 2000N= 1000kg X a
a = 1000kg / 2000N, = 0.5 m/ s^2 forward.
Force is a factor that has the power to alter an object's motion. An object with mass can change its velocity, or acceleration, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
To learn more about acceleration :
https://brainly.com/question/12550364
#SPJ9
Acceleration of the stalled car is 2 m / s ² in forward direction .
Force is defined as the rate of change of momentum or as the product of mass and acceleration .
F = m ( v - u ) / t
F = m x a
F = Force
m = Mass
a = Acceleration
It is given that ,
F = 2,000 N
m = 1,000 kg
Since , F = m x a
So ,
a = F / m
a = 2,000 N / 1,000 kg
a = 2 m / s ² Forward
Hence , Acceleration of the stalled car is 2 m / s ² in forward direction .
To know more about acceleration , kindly check :
https://brainly.com/question/460763
#SPJ9
Nellie whirls a tether ball in a horizontal circular path over her head. if the action force is nellie pulling on the string, the reaction force is?
The reaction force is string pulling on the Nellie when a tether ball in a horizontal circular path over her head .
A reaction force is a force that acts in the opposite direction to an action force. i.e. Newton's third law of motion describes action and reaction forces and the law states that for every action force, there is an equal and opposite reaction force.
There are Newton's three law of motion which can be describe as ,
The first law is can be stated as, an object will not change its motion unless a external force acts on it.
The second law is describe as, the force on an object is equal to its mass times its acceleration. i.e.
F = ma
In above equation F is force , m is mass and a is acceleration on an object.
The third law can be explained as, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
Therefore , from the above discussion can be said as Nellie whirls a tether ball in a horizontal circulars path over her head. if the action force is nellie pulling on the string, the reaction force is string pulling on the Nellie.
To know more about reaction force
https://brainly.com/question/13609752
#SPJ1
A passenger elevator travels from the first floor to the 60th floor, a distance of 210m, in 35s. What is the elevator’s speed?
The speed of the elevator, given that it travels a distance of 210 m in 35 s is 6 m/s
Formula for speedThe formula for calculating the speed of an object is given as follow:
Speed = distance / time
How do I calculate the speed of the elevator?Considering the question given above, we can obtain the speed of the elevator as follow:
Distance = 210 mTime = 35 sSpeed =?Speed = distance / time
Speed = 210 / 35
Speed = 6 m/s
From the calculation made above, we can see that the speed of the elevator is 6 m/s
Learn more about speed:
https://brainly.com/question/680492
#SPJ1
A plane is traveling 50m drops a package of explores of 134m the acceleration of gravity is 9.8 where does the package strike
Explanation:
Throughout this question, we will be taking the position at which the package is dropped as the origin.
We know that the package lands 100 m from the initial position. We have to investigate the position in the horizontal direction.
To do that, let's first calculate the time of flight of the package.
Here is what we know about the vertical motion taking the downward direction as the positive direction:
the vertical displacement is
s
=
100
m
.
the acceleration is
a
=
g
=
9.81
m
/
s
2
.
the initial velocity of the package is
u
=
0
m
/
s
.
By using an equation that connects the details that we have with the time of flight
t
, we get the time of flight as follows:
s
=
u
t
+
1
2
a
t
2
s
=
0
+
0.5
a
t
2
Make
t
the subject
0.5
a
t
2
=
s
t
2
=
s
0.5
a
t
=
√
s
0.5
a
=
√
100
m
0.5
(
9.81
m
/
s
2
)
≈
4.52
s
The horizontal displacement
x
equals the product of the horizontal velocity
v
x
=
40.0
m
/
s
and the time of flight
t
=
4.52
s
, i.e.
x
=
v
x
t
=
40.0
m
/
s
(
4.52
s
)
≈
181
m
The package will strike the ground at
(
181
m
;
−
100
m
)
.
Part b)
The horizontal component of the velocity is constant throughout the flight and is
v
x
=
40.0
m
/
s
.
For the downward motion, here is what we know:
the vertical displacement is
s
=
100
m
.
the acceleration is
a
=
g
=
9.81
m
/
s
2
.
the initial velocity of the package is
u
=
0
m
/
s
.
By applying an equation that combines the details that we have with the final instantaneous velocity
v
=
v
y
, we get the final instantaneous velocity as follows:
v
2
=
u
2
+
2
a
s
v
=
√
u
2
+
2
a
s
v
y
=
√
(
0
m
/
s
)
2
+
2
(
9.8
m
/
s
2
)
(
100
m
)
≈
44.3
m
/
s
The velocity vector at the instant the package just hits the ground is (40.0 m/s ; 44.3 m/s).
Part c)
At the instant that the plane hits the ground, the plane's position is (181 m ; 0 m): i.e. the plane is directly on top of the package and 100 meters above the ground. This is because horizontally, the plane and the package move with the same velocity.
Part d)
The vertical component of the velocity of the package increases at a steady rate. In fact, the rate or gradient is the acceleration
g
=
9.8
m
/
s
2
.
the ear is composed of outer, middle, and inner parts. the large gathers sound waves of air and directs them into the to the .
The ear is composed of outer, middle, and inner parts. The large external auricle gathers sound waves of air and directs them into the external acoustic meatus to the tympanic membrane.
What is tympanic membrane?
A second name for the tympanic membrane is the eardrum. It divides the middle ear from the outer ear. The tympanic membrane vibrates as sound waves enter it. The middle ear's minuscule bones are thus exposed to the vibrations. The vibrating signals are then sent from the middle ear bones to the inner ear.
Therefore,
The ear is composed of outer, middle, and inner parts. The large external auricle gathers sound waves of air and directs them into the external acoustic meatus to the tympanic membrane.
To learn more about tympanic membrane from the given link:
https://brainly.com/question/9395447
#SPJ4
Imagine a time-position graph where the velocity of an object is constant. What will be observed on the graph concerning the slope of the line segment as well as the velocity of the object? (1 p
O The slope of the line is positive, and the object will be stationary.
O The slope of the line is negative, and the object will be stationary.
O The slope of the line is equal to zero and the object will be stationary.
O The slope of the line is equal to zero and the object will be in motion.
D. The slope of the line is equal to zero and the object will be in motion.
What is constant velocity?Velocity of a body is said to be constant, if it covers equal distances in equal intervals of time, and also does not change the direction it is moving in
To have a constant velocity, an object must have a constant speed in a constant direction.
Slope of the position time graphslope = change in velocity / change in time
if the velocity is constant, then change in velocity = 0
slope = 0/change in time = 0
In constant velocity, the object will be in motion, but the velocity of the object will not change.
Thus, the slope of the line is equal to zero and the object will be in motion.
Learn more about constant velocity here: https://brainly.com/question/529176
#SPJ1
========================================================
Hello! Lets begin!
1. Which answer best describes displacement?
A) Displacement is a vector quality showing total length of an area traveled by a particular object.2. Kelley is playing pool and hits the cue into the nine ball, which is directly in the center of the pool table. The nine ball travels a total of 7 meters before stopping, 1 meter to the left of the initial starting point of the nine ball. Which sentence reflects the correct statement regarding distance and displacement when considering the motion of the nine ball?
D) The nine ball traveled a distance of 7 meters and was displaced by 1 meter.3. What is velocity?
B) Velocity is a vector quantity that tells the distance an object has traveled over a period of time.4. Imagine a time-position graph where the velocity of an object is constant. What will be observed on the graph concerning the slope of the line segment as well as the velocity of the object?
C) The slope of the line is equal to zero and the object will be stationary.5. Select the option that best summarizes the reason for the use of position-time graphs when studying physical science.
B) The position-time graphs show the relationship between the position of an object (shown on the y-axis) and the time (shown on the x-axis) to show velocity._______________________________________________________
Good luck my peeps! ;D
a brick is dropped (zero initial speed) from the roof of a building. the brick strikes the ground in 1.90 s. you may ignore air resistance, so the brick is in free fall.
If A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90s then the building is 17.69 meters tall.
What is velocity?Velocity is the directional speed of a moving item as an indication of its rate of change in position as seen from a specific frame of reference and measured by a specific time standard (e.g., 60 km/h northbound). The idea of velocity is crucial in kinematics, the part of classical mechanics that explains the motion of bodies.
A physical vector quantity called velocity requires both magnitude and direction to be defined. Speed is a coherent derived unit that expresses the scalar absolute value (magnitude) of velocity. Its quantity is expressed in SI units (metric system) of metres per second (m/s or ms1). For example, "5 meters per second" is a scalar while "5 meters per second east" is a vector.
We have given that
u = 0 m/s (initial velocity)
t = 1.90 s (time)
a = g = 9.80 m/s² (acceleration = falling = gravity)
We will use the second equation of motion to determine the height(S) of the building in meters:
⇒ S = [tex]ut + \frac{1}{2} at^2[/tex]
⇒ S = (0)(1.90) + [tex]\frac{1}{2}[/tex](9.80)(1.90)²
⇒ S = 4.9 × 3.61
= 17.69 meters
Learn more about velocity
brainly.com/question/80295?source=archive
#SPJ4
Full question
A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90 s. You may ignore air resistance, so the brick is in free fall. (a) How tall, in meters, is the building?
Think of the total distance you have covered in your lifetime. Is it
possible for you to move in some direction to reduce this distance to zero
You can move in some direction to reduce this distance to zero if the body remains at rest position.
How distance is zero?The distance can be zero when the object is present at rest position. Distance is defined as the length covered by a body. The distance can also be defined as the length of the path between two points. Displacement and distance are used for the measurement of length covered by a body. There is one difference between distance and displacement which is displacement can be zero but distance cannot be zero until it stops moving because distance is the total path covered by a body but displacement is the shortest distance between two points. If the distance is not covered by a body means the body can't move then the distance will be zero.
So we can conclude that You can move in some direction to reduce this distance to zero if the body remains at rest position.
Learn more about distance here: https://brainly.com/question/71956
#SPJ1
a parallel-plate capacitor has 2.2 cm × 2.2 cm electrodes with surface charge densities ±1.0×10−6c/m2. a proton traveling parallel to the electrodes at 1.4×106 m/s enters the center of the gap between them.
The distance has the proton been deflected sideways when it reaches the far edge of the capacitor is [tex]1.08 * 10^-3[/tex].
What is parallel-Plate Capacitor:
When two parallel plates are connected across a battery, the plates are charged and an electric field is established between them, and this setup is known as the parallel plate capacitor.
The parallel plate capacitor formula is given by:
C = k∈0 A / d.
Now,
The electric field is, E = sigma/epsilon_{o} = (1 * 10 ^ - 6)/(8.85 * 10 ^ - 12) = 1.129 * 10 ^ 5 * N / C
The force on the proton is (F) = q E = 1.6 * 10 ^ - 19 * 1.129 * 10 ^ 3 = 1.81 * 10 ^ - 14 * N
So, the acceleration of the proton is,
a = F/m = (1.81 * 10 ^ - 14)/(1.67 * 10 ^ - 27) = 1.084 * 10 ^ 13 * m / (s ^ 2)
Time taken to cross the plate is (t) = d/u = (2.4 * 10 ^ - 2)/(1.7 * 10 ^ 6) = 1.41 * 10 ^ - 8
Therefore, the required distance travelled distance is,
d = u t + 1/2 * a * t ^ 2
d = 0 + 1/2 * 1.084 * 10 ^ 13 * (1.41 * 10 ^ - 4) ^ 2
d = 1.08 * 10 ^ - 3 * m
Therefore, the distance is 1.08*10^-3 m
A parallel-plate capacitor has 2.4 cm × 2.4 cm electrodes with surface charge densities ±1.0×10^−6C/m2. A proton traveling parallel to the electrodes at 1.4×10^6 m/s enters the center of the gap between them.
By what distance has the proton been deflected sideways when it reaches the far edge of the capacitor? Assume the field is uniform inside the capacitor and zero outside the capacitor
To know more about "Parallel plate capacitor"
Refer this link:
https://brainly.com/question/27164418
#SPJ4
Calculate the energy of a photon with a wavelength of 410nm. 4.85 x 10^-19 j 4.85 x 10^-20 j 4.85 x 10^-18 j 2.06 x 10^19 j 2.06 x 10^20 j
The energy of a photon with wavelength of 410nm can be calculated as 4.85 x [tex]10^{-19}[/tex] j
How do you determine a photon’s energy?Any energy unit, such as the electron volt (eV) or the joule (J), can be used to express photon energy.
P = F × E (equation 3)
P = F × hc/l (equation 4)
P (mW) is equal to 1.989 10-10 F/l (nm)
How can I determine energy based on wavelength?Ensure that your wavelength is expressed in meters.
The wavelength is multiplied by the speed of light, which is roughly 300,000,000 m/s, to determine the wave’s frequency.
Add the Planck constant, 6.626 1034 J/Hz, to the frequency.
The resulting figure represents a photon’s energy.
Calculation[tex]\lambda[/tex] = 410nm = 410 x 10^(-9).
E = hc/[tex]\lambda[/tex] = [6.626 x 10^(-34) x 3 x 10^(8) ] / 410 x 10^(-19)
= 0.0485 x 10^(-17)
= 4.85 x 10^(-19)
To know more about photons, visit:
https://brainly.com/question/20912241
#SPJ4
A hockey player is standing on his skates on the Rideau Canal when an opposing player, moving with a uniform speed of 2.8 m/s, skates by with the puck. After 3.0 s, the first player makes up his mind to chase his opponent. If he accelerates uniformly at 3.5 m/s^2
a. How long does it take him to catch his opponent?
b. How far has he travelled in this time? (Assume the player with the puck remains in motion at a constant speed.)
After 3.0 s, If the first player makes up his mind to chase his opponent. If he accelerates uniformly at 3.5 m/s^2 then it would take 3.13 seconds to catch his opponent.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
As given in the problem, a hockey player is standing on his skates on the Rideau Canal when an opposing player, moving with a uniform speed of 2.8 m/s, skates by with the puck. After 3.0 s, the first player makes up his mind to chase his opponent. If he accelerates uniformly at 3.5 m/s^2,
Let us assume the time taken to catch up would be t seconds.
The distance traveled by the hockey player = 2.8×3 + 2.8×t
By using the second equation of the motion,
s = ut+0.5at² = 2.8×3 + 2.8×t
1.75t² - 2.8t -8.4 = 0
t = 3.13 seconds
The distance traveled by the hockey player to catch up = 2.8×(3+3.13)
=17.164 meters
Thus, it would take 3.13 seconds to catch his opponent.
To learn more about equations of motion from here, refer to the link;
brainly.com/question/5955789
#SPJ1
For the diagram below, a siren is going off in the distance to the left. The
diagram shows the diffraction of the siren's sound wave around the wall. If
you were behind the wall (position labeled "X") what would you hear?
Sound waves
from source to
the left, rooving
to the right.
OA. You would not hear anything because there is no sound wave at
that position.
OB. You would not hear anything, because the wall would block the
sound of the siren.
OC. You would hear the siren, but the pitch would sound higher.
OD. You would hear the siren and think it was located at the opening in
the wall.
Answer:c
Explanation:
13. How are controlled experiments useful?
How much heat energy is required to raise the temperature of 7 kg of Copper from 0°C to 10°C?
Answer:
H= Mass × specific heat capacity ×change in temperature
= 2×380×(10-0)
=2×380×10
=7600 Joules
An object is lifted from the surface of a spherical planet to an altitude equal to the radius of the planet. As a result, what happens to the mass and weight of the object?.
Answer:
SEE below
Explanation:
MASS is a measure of the amount of matter in an object....it will remain the same ....
WEIGHT is a measure of gravitational pull on the object and is inversely dependent on the square of the distance between the two bodies...so weight will be LESS than on the surface of the planet
a golfer hits a golf ball with an initial velocity of 250.00 ft/s at an angle of 25° with the horizontal. knowing that the fairway slopes downward at an average angle of 5°, determine the distance d between the golfer and point b where the ball first lands.
The distance d between the golfer and point b where the ball first lands is 4933.17 ft
Initial velocity = 250.0ft/s
Launch angle ([tex]\theta[/tex] )= 25°
slope angle([tex]\phi[/tex]) = 5°
Let d is the distance on the slope after which projectile lands
∴ horizontal distance covered by projectile
x = dcos[tex]\theta[/tex]
Vertical distance covered by projectile
y = dsin[tex]\theta[/tex]
now Considering horizontal motion
Initial horizontal velocity [tex]v_{x} = v cos25[/tex]
then position after time t
d cos5 = 250cos25×t
d = 227.44t ---------1.
when we consider vertical motion then
Initial vertical velocity [tex]v_{y} = v sin25[/tex]
[tex]v_{y} = v sin\theta t-\frac{1}{2}gt^{2}[/tex]
-d sin5 = 250 sin25.t - gt²/2
-d = 1212.25t - 56.221 t²
1212.25t - 56.221 t² + d = 0 ----2
put value of d in equation 2
1212.25t - 56.221t² + 227.44t =0
t(1212.25+227.44 - 56.221 t) =0
t(1234.69 - 56.221 t) = 0
t = 21.96 ,t≠0
substitute the value of t in equation 1
d = 227.44t
d = 227.44×21.96
d = 4933.17 ft
The distance d between the golfer and point b where the ball first lands is 4933.17 ft
To know more about projectile
https://brainly.com/question/13321326
#SPJ4
To a stationary observer, a man jogs east at 6 m/s and a woman jogs west at 2 m/s. from the man's frame of reference, what is the woman's velocity?
Answer: 8m/s west I think
To a stationary observer, a man jogs east at 6 m/s and a woman jogs west at 2 m/s. From the man's frame of reference, the woman's velocity is 4 m/s.
What is Velocity?
Velocity is a term that defines that how much a particle covered the distance in a particular time. Velocity is a vector quantity. It can be measured in m/s or cm/s.
How can we calculate the velocity?To calculate the velocity we are using the formula, Δv= v₁-v₂
Here we are given,
v₁= According to a stationary observer, velocity of a man=6 m/s East.
v₂=According to a stationary observer, velocity of a woman= 2 m/s West.
We have to calculate the woman's velocity, from the man's frame of reference= Δv
Now we put the values in the above equation, we get
Δv= v₁-v₂
Or, Δv= 6-2
Or, Δv=4m/s.
According to the calculation we can say that, From the man's frame of reference, the woman's velocity is 4 m/s.
Learn more about velocity:
https://brainly.com/question/25749514
#SPJ1
during a braking test, a car is brought to rest beginning from an initial speed of 60 mi∕hr in a distance of 120 ft. with the same constant deceleration, what would be the stopping distance s from an initial speed of 80 mi∕hr?
The stopping distance s from an initial speed of 80 mi∕hr will be 219 ft.
Here we can define the value t = 0s as the moment when the car starts decelerating.
At this point, the acceleration of the car is given by the equation:
A(t) = -10 ft/s^2
Where the negative sign is because the car is decelerating.
To get the velocity equation of the car, we integrate over time, to get:
V(t) = (-10 ft/s^2)*t + V0
Where V0 is the initial velocity of the car, we know that this is 88 ft/s
Then the velocity equation is:
V(t) = (-10 ft/s^2)*t + 88ft/s
To get the position equation we need to integrate again, this time we get:
P(t) = (1/2)*(-10 ft/s^2)*t^2 + (88ft/s)*t + P0
Where P0 is the initial position of the car, we do not know this, but it does not matter for now.
We want to find the total distance that the car traveled in a 3 seconds interval.
This will be equal to the difference in the position at t = 3s and the position at t = 0s
distance = P(3s) - P(0s)
= ( (1/2)*(-10 ft/s^2)*(3s)^2+ (88ft/s)*3s + P0) - ( (1/2)*(-10 ft/s^2)*(0s)^2 + (88ft/s)*0s + P0)
= ( (1/2)*(-10 ft/s^2)*9s^2+ (88ft/s)*3s + P0) - ( P0)
= (1/2)*(-10 ft/s^2)*9s^2+ (88ft/s)*3s = 219ft
The car advanced a distance of 219 ft in the 3 seconds interval.
To learn more about similar question from the given link:
brainly.com/question/24196985
#SPJ4
Which of the following is an example of an energy transfer?
Elastic energy becomes kinetic energy as a ball bounces
OA billiard ball collides with a second billiard ball which is initially at rest, making it move.
Elastic potential energy is initially at rest, making it move.
Elastic potential energy is what causes a ball to bounce or rebound because it is transformed into kinetic energy and used to raise the ball back up. However, because some of the ball's energy was transferred to the ground or changed into sound (in the noise it makes upon impact) and heat energy, the ball won't go as high as it did at first (friction with the table). Additionally, even though we cannot see it, the ball alters once it strikes the ground or a table, energy is needed to take shape for a brief period of time.
Because of this, each bounce has a slightly lower height than the one before it. The ball has some kinetic energy when it hits the floor, but some of it is changed, so it loses some of it each time it bounces. After a few bounces, the ball has so little kinetic energy remaining that it stops bouncing.
Thus the correct answer is option A.
To learn more about elastic potential energy refer the link:
https://brainly.com/question/14687790
#SPJ1
a group of students prepare for a robotic competition and build a robot that can launch large spheres of mass m in the horizontal direction with a variable speed and from a variable vertical position and a fixed horizontal position x
Gravity is the sole force acting on the body during free fall motion.
The student should launch the sphere at 2v0 because it will land in the 3 point zone at a distance of around 1.41D.
The variables mentioned are;
the sphere's travel distance when thrown from a height, H = D
The speed at which the ball travels to D = v0
The launcher's current available height is H/2.
The available speeds are v0 and 2v0.
Using the formula H = ut + (1/2)gt2, where u is the beginning velocity of the ball's vertical motion, the following is obtained:
H = (1/2)·g·t²
The time it takes for the ball to fall from H is given by t = ((2H/g)).
The length, D = v0 (2H/g),
we obtain when the height is H/2;
t = √(2·H/(2·g)) = √(H/g)
D1 = v0 (H/g) is the distance traveled.
D = (2) v0 (H/g) = ((2)) D1 follows.
D₁ = D/(√2) ≈ 0.71·D
D₁ ≈ 0.71·D
We have at pace 2v0;
D2 = 2v0 (H/g) = 2 v2 v0 (H/g) = 2 v0 (2H/g) = 2D1 1.41D
D₂ ≈ 1.41·D
The 2 point zone is equal to D/2 x D = 0.5 D x D. (This is where position D1 0.71D is placed)
The 3 Point Zone is located at position D2 1.41D and is defined as D x 3D/2 = D x 1.5D.
The student should launch the sphere at the speed, 2v0, such that the ball will land at D2 1.41D, which is in the 3 Point Zone, given that the ball lands at D2, where it is in the 3 Point Zone.
Complete Question -A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizontal direction with variable speed and from a variable vertical position and a fixed horizontal position x=0.
The robot is calibrated by adjusting the speed at which the sphere is launched and the height of the robot’s sphere launcher. Depending on where the spheres land on the ground, students earn points based on the accuracy of the robot. The robot is calibrated so that when the spheres are launched from a vertical position y=H and speed v0, they consistently land on the ground on a target that is at a position x=D. Positive directions for vector quantities are indicated in the figure.
When the students arrive at the competition, it is determined that the height of the sphere launcher can no longer be adjusted due to a mechanical malfunction. Therefore, the spheres must be launched at a vertical position of y=H2. However, the spheres may be launched at speed v0 or 2v0.
Question: In a clear response that may also contain diagrams and/or equations, describe which speed, v0 or 2v0, the students should launch the sphere at so that they earn the maximum number of points in the competition.
To learn more about free fall from given link
https://brainly.com/question/17457573
#SPJ4