Astronomers observe a typical star using a telescope and a spectrometer. they will see?
Astronomers observe a typical star using a telescope and a spectrometer, they will see an absorption spectrum and is therefore denoted as option B.
What is an Absorption spectrum?This is referred to as the percentage of incident radiation which have been absorbed by the material over a range of different frequencies.
Astronomers are referred to as scientists who are involved in the study planets and space with the use of instruments such as telescope and a spectrometer and they are most likely to see an absorption spectrum due to the different frequencies of light which are present in space.
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The options are:
an emission spectruman absorption spectruma continuous spectrummore than one of the above.For each question, select the right answer from the choices below:
a Object A weighs 30 N on Earth. Object B weighs 30 N on the Moon (which
has a gravitational field strength 1/6 the size of Earth's). Which object has the greater mass?
i. A
ii. B
iii. neither of them
iv. depends on air resistance
Option (ii) B is the correct option. The object on the moon has greater mass.
To resolve this, utilize the formulas Force = Mass * Acceleration.
The equation can be used to find the mass given the force in Newtons, using 9.8 m/s² for the acceleration of gravity of the earth and 1.6 m/s² for the moon.
Calculating the mass on earth:
30 N = 9.8 m/s² * mass
This results in a mass of 3.0 kg for the object on Earth.
Calculating the mass of the moon:
30 N = 1.6 m/s²2 * mass
Thus, the moon's object has a mass of 19. kg.
This can be explained by the fact that the earth has a stronger gravitational pull than the moon, producing more force per kilogram of mass. As a result, the moon's mass must be bigger to produce the same amount of force at a lower acceleration from gravity (1.6 m/s² vs. 9.8 m/s²).
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Photons of wavelength 0.024 a are incident on free electrons. (a) find the wavelength of a photon which is scattered 3
When Photons of wavelength 0.024 a are incident on free electrons, the wavelength of a photon which is scattered 30° is 0.0576 x [tex]10^{-11}[/tex] and for the one scattering at 120° is 0.38 x [tex]10^{-11}[/tex] A.
How can the Compton effect be used to determine the energy of scattered photons?The incident photon’s energy is equal to the scattered photon’s energy minus the total of the recoil electron’s kinetic energy and binding energy.
Compton scattering causes the loss of an electron and ionization of the absorbing atom, just like photoelectric absorption does.
What is the scattered photon’s wavelength?After the scattering event and before, the photon’s wavelength varies by ∆λ = (h/mc) (1-cosφ). Here, c is the speed of light, m is the rest mass of the electron, and is the angle at which the photon is scattered. H is the Planck constant.
Given photon wavelength λ = 0.024A
φ = 30°
From the Compton effect we know that
∆λ = λ1 - λ = h/mc (1-cosφ)
λ1 = [tex]\frac{6.62*10^{-34}}{9.1}[/tex] x [tex]10^{-3}[/tex] x 3 x [tex]10^{8}[/tex] (1- cos30°) + 0.024A
= 0.0576 x [tex]10^{-11}[/tex] A
And then calculating the same for
φ = 120°
we get,
λ1 = 0.38 x [tex]10^{-11}[/tex]A
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Complete Question
Photons of wavelength 0.024A are incident on free electrons.
(a) Find the wavelength of a photon which is scattered 30° from the incident direction and the kinetic energy imparted to the recoil electron
(b) Do the same if the scattering angle is 120°.
REVIEW
1 A train travelled along a
straight track from a particular
stop back to its depot.
This 5.0 km journey took
12 minutes. Calculate the
train's average speed. (Give
your answer in km/h.)
According to given data, the average speed of train is 25 km/h.
Equation :Given data,
distance = 5 km
time = 12 minutes
average speed = ?
changing time from minute to hour
So,
hour = 12 / 60
hour = 0.2
Then to calculate speed use the formula,
s = d / t
s = 5km / 0.2hr
s = 25 km/h
What is speed?Velocity is the rate and direction of an object's movement, whereas speed is the time rate at which an object is moving along a path. In other words, velocity is a vector value, whereas speed is a scalar value. It has a dimension of time-distance. As a result, the basic unit of time and the basic unit of distance are combined to form the SI unit of speed. Thus, the metre per second (m/s) is the SI unit of speed.
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Is there any formula to calculate the height a ball will reach depending on the bounce number and it’s initial height? Alternatively, can any formula calculate the amount of times a ball will bounce without going into infinity?
Answer:
yeas
Explanation:
beac×high ×sides and after you fins tims you need to add beac+high and add the sides together and add what did you got from beac,high and sides and thin you will add every thing together
A fellow student reports his measurements of time for a speed calculation in minutes. How could he express that calculation using SI
base units?
convert minutes to meters and redo his calculations
convert minutes to hours and redo his calculation
convert minutes to seconds and redo his calculation
Okeep his calculation as it is
Convert minutes to seconds and redo his calculation.
How do we measure time?The quick response. Atomic clocks are the most precise timekeeping devices we have for measuring the length of time between two events. Atoms in the clocks jump from one energy level to another as a result of the precise frequency at which these clocks emit electromagnetic radiation, such as microwaves.
Time is an illusion, says theoretical physicist Carlo Rovelli, because our simple perception of its flow doesn't match up with physical reality. In fact, much more, including Isaac Newton's depiction of a constantly ticking clock, is illusory, according to Rovelli's claim in The Order of Time.
How do you calculate hours and minutes?In an hour, there are 60 minutes. Divide the amount of minutes by 60 to convert it to hours. For instance, 120/60=2 means that 2 hours are equal to 120 minutes.
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a boat can travel at a speed of 8 km/h in still water on a lake. in the flowing water of a stream, it can move at 8 km/h relative to the water in the stream. if the stream speed is 3 km/h, how fast can the boat move past a tree on the shore when it is traveling.
Relative velocity of the river with respect to shore, V = 20 km/h.
Relative velocity of the river with respect to shore ,V = 10 km/h
Velocity of the shore = 0 km/h
Relative velocity of the river with respect to shore:
[tex]V = V_{r} - V_{s}[/tex]
Velocity of the river [tex]V_{r}[/tex] = 10 km/h
Relative velocity of the boat with respect to river ,V'= 10 km/h
[tex]V^{'} = V_b} -V_{r}[/tex]
Velocity of the boat [tex]V_b}[/tex] = 20 km/h
Relative velocity of the boat with respect to shore, V":
[tex]V_{"} = V_{b} - V_{s}[/tex]
Relative velocity of the boat with respect to shore is 20 km/h.
What is Relative velocity?It is the pace at which one object's relative location changes in relation to another object over time.
Think about two trains that are traveling in the same direction and at the same pace. Even though the tracks, buildings, and trees on each side of the railway indicate that both trains are moving, to the observer of one train, the other train appears to be stationary. The other train seems to be moving at a constant speed.
The speed at which one thing moves in relation to another is known as the relative velocity of the two objects.
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The social cognitive perspective of personality focuses on social factors such as your parents guardians and teachers and cognition what does cognition mean
The social cognitive perspective of personality focuses on social factors such as your parents guardians and teachers and cognition means how we as individuals process and store information.
What is Cognition?This is referred to as the process in which information is stored and processed through the use of our senses, experience etc and is common to all individuals.
The social cognitive perspective of personality on the other hand focuses on social factors such as parents and also in which cognition is among and it is influenced by genetic and environmental factors which therefore makes it the most appropriate choice.
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Suppose a plane accelerates from rest for 30 s, achieving a takeoff speed of 80 m/s after traveling a distance of 1200 m down the runway. A smaller plane with the same acceleration has a takeoff speed of 40 m/s . Starting from rest, after what distance will this smaller plane reach its takeoff speed?
Answer:600 m is required for smaller plane to reach its takeoff speed. ... So 300 m is required for smaller plane to reach its takeoff speed.
Explanation:
Answer:
300 m
Explanation:
Find acceleration of first plane
v = a t
80 = a (30) shows a = 2.67 m/s^2
For the smaller plane
v = at
40 = 2.67 t shows t = 14.98 seconds
d = 1/2 a t^2
= 1/2 2.67 (14.98^2) = 299.6 = ~ 300 meters
Flying from LA to New York is a 3,944,000 meter trip. What order of magnitude is this measurement?
The order of magnitude of the distance between Los Angeles (LA) to New York (NY) is determined as 6.
What is the order of magnitude of a measurement?
An order of magnitude of a measurement is an approximation of the logarithm of a value relative to some contextually understood reference value, usually 10, interpreted as the base of the logarithm and the representative of values of magnitude one.
Also, the order of magnitude can be defined as the power of 10 a number is raised to when it's in scientific notation.
The given measurement;
m = 3,944,000 m
The measurement in scientific notation;
3,944,000 m = 3.944 x 10⁶ m
Thus, the order of magnitude of the distance between Los Angeles (LA) to New York (NY) is determined as 6.
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A boy and a girl are biking down a hill. The boy and the girl weigh the same, and they are using bikes that weigh the same. If the boy and girl are biking at the same speed, which child has more motion energy (kinetic energy)?
Answer:
neither.
they both are going at the same speed
Explanation:
Answer:
They have the same Kinetic Energy
Explanation:
KE = 1/2 m v^2 if the velocities are the same and the masses are the same .....then the Kinetic energies are the same
a uniform electric field exists in the region between two oppositely charged plane parallel plates. a proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate, 1.60 cmcm distant from the first, in a time interval of 3.80×10−6 ss .
The magnitude of the electric field is
[tex]1.29 \: \times 10 ^{ - 24} \: N/C.[/tex]
The time interval is t.
[tex]t = 3.8 \times 10 ^{ - 6} \: s[/tex]
The distance of the second proton from the first proton is d.
[tex]d = 1.60 \: 10^{ - 2} \: m[/tex]
[tex]∆x = \frac{1}{2} at ^{2} [/tex]
The magnitude of the electric field is,
[tex]E = \frac{ F}{e}[/tex]
[tex]E = \frac{ma}{e} [/tex]
[tex] = \frac{2 \: ∆x \: m}{e \: t ^{2} } [/tex]
[tex] = 2 \times \frac{(1.6 \times 10 ^{ - 2} )(1.9 \times 10 ^{ - 3}) }{(1.6 \times 10 ^{ - 19})(3.8 \times 10 ^{ - 6} ) ^{2} } [/tex]
[tex] = 1.29 \: \times 10 ^{ - 24} \: N/C[/tex]
Therefore, the magnitude of the electric field is
[tex]1.29 \: \times 10 ^{ - 24} \: N/C.[/tex]
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A bicyclist starts from rest and accelerates along a straight path to a speed of 12. 15 m/s in a time of 4. 5 seconds. What is the bicyclist’s acceleration to the nearest tenth of a m/s2?.
Answer:The cyclist's acceleration to the nearest tenth is: C. 2.7 .
Given the following data:
Initial velocity = 0 m/s (since the cyclist starts from rest).
Final velocity = 12.5 m/s.
Time = 4.5 seconds.
To find the cyclist's acceleration to the nearest tenth:
Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.
Mathematically, acceleration is given by the formula;
Where:
A is the acceleration.
V is the final velocity.
U is the initial velocity.
t is the time measured in seconds.
Substituting the given parameters into the formula, we have;
Acceleration, A = 2.7
Therefore, the cyclist's acceleration to the nearest tenth is 2.7 .
Explanation:
a string or rope will break apart if it is placed under too much tensile stress. thicker ropes can withstand more tension without breaking because the thicker the rope, the greater the cross-sectional area and the smaller the stress. one type of steel has density 7710 kg/m3 and will break if the tensile stress exceeds 7.0×108n/m2. you want to make a guitar string from a mass of 4.2 g of this type of steel. in use, the guitar string must be able to withstand a tension of 900 n without breaking. your job is the following.
The maximum length the string can have is 13.02 meter.
(a) Determine the maximum length the string can have
Answer:
As we know that density(p)= mass(m)/volume(V)
Solve for volume(V)= mass/density
If the given mass value is in gram then we have to divide it by 1000 to get the value in kilogram so our mass in kg will be 3.7/1000= 0.0037 kg
And if density is in kg/m^3
Then volume will be V= 0.0037/7730 =>
4.79^10-7m^3
Now we know that stress = Force/Area
For Area = force/stress => 900/7*10^8=> 2795.95m^2
For length= volume/Area => 4.79^10-7/2795.95
Length= 13.02 m
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If we apply a potential difference of 4. 50 v between the ends of a wire that is 2. 50 m in length and 0. 654 mm in radius, the resulting current through the wire is 17. 6. What is the resistivity of the wire material?.
According to the resistance, the resistivity of wire material is 1.37 x 10¯⁷ Ωm.
We need to know about the resistance of conductive material to solve this problem. Resistance can be defined as the ratio of the voltage applied to current flow It can be written as
R = V / I
where R is resistance, V is voltage and I is current.
The resistance of the material depends on its resistivity and follows this equation
R = ρ . L / A
where ρ is resistivity, L is the length of the material and A is the surface.
From the question above, we know that
V = 4.5 V
L = 2.5 m
r = 0.654 mm = 6.54 x 10¯⁴ m
I = 17.6 A
Find the surface area
A = π . r²
A = π . ( 6.54 x 10¯⁴ )²
A = 1.34 x 10¯⁶ m²
Find the resistivity of the wire
R = V / I
ρ . 2.5 / (1.34 x 10¯⁶)= 4.5 / 17.6
ρ = 1.37 x 10¯⁷ Ωm
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define a system you interact with every day. is the system open, closed, or isolated? how do matter and energy flow into, out of, or within the system?
In daily life the common example of isolated system, closed system and open system is themosteel bottle , human body and ecosystem respectively.
Water in a thermos, or thermosteel bottle is an example of isolated system where no transfer of energy neither transfer of matter takes place between the system and surroundings. Although no system is perfectly isolated, after some instant there a hear loss takes place by some means.
There are three types of system in thermodynamics,
Open system – system which allows transfer of heat and matter between system and surroundings. For example- Ecosystem.Closed system – system which allows transfer of heat but no transfer of matter between system and surroundings. For example- human body. Isolated system – no transfer of energy neither transfer of matter takes place between the system and surroundings For example – thermosteel bottle.Thermodynamics is the branch of science is which we study about the heat, temperature, work and their relation to energy.
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at a distance from the slits which is large compared to their separation, what is the phase difference (in radians) in the light from the two slits at an angle of 25.8 ∘∘ from the centerline
∅=2021rad is the phase difference (in radians) in the light from the two slits.
using the formula below
Φ =( [tex]2\pi d/[/tex]β )sinα
∅=2021rad
What is phase difference?The time difference between the same points within the two sounds' wave cycles (the peaks or positive-going zero crossings, for example), expressed as a fraction of one wave cycle, determines the phase difference between two sound waves of the same frequency travelling past a fixed spot.
Phase shift occurs when the sine and cosine function graphs are moved to the left or right of where they usually are, or we can say that the function is moved horizontally how far from its normal position. Functions are typically moved from their normal place.
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Every time you inhale, oxygen makes its way to millions of tiny, sponge like sacs called ______that line the walls of your lungs.
Popliteal
Arterial
Alveoli
Capillaries
Every time you inhale, oxygen makes its way to millions of tiny, sponge like sacs called alveoli that line the walls of your lungs.
Lungs :Your lungs contain tiny, balloon-shaped air sacs called alveoli. Moving oxygen and carbon dioxide (CO2) molecules into and out of your bloodstream is what the alveoli are there for. Alveoli are a crucial component of your respiratory system, which includes the body parts that aid in breathing.
What lines walls of alveoli?An alveolus is made up of an extracellular matrix encircled by capillaries, a layer of simple squamous epithelium (extremely thin, flattened cells), and an epithelial layer. The alveolar membrane, also known as the respiratory membrane, which permits the exchange of gases, includes the epithelial lining.
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help! an asteroid is heading towards us at 15 km/s . scientists decide the best solution is to attach a rocket to the asteroid and fire it to change the trajectory of the asteroid. if the rocket is fired for 8 min, the scientists calculate that the new speed for the asteroid will be 21 km/s and its new trajectory will be at an angle of 33 ∘ to its original path.
The acceleration of the asteroid which is moving at a speed of 15km/s is [tex]a = (0.0058i + 0.023j)km/s^{2}[/tex].
What is trajectory ?A mass-moving object's route through space as a function of time is known as its trajectory or flight path. A full trajectory is defined by location and momentum at the same time in classical mechanics since a trajectory is determined by Hamiltonian mechanics using canonical coordinates.
[tex]v_{i} = 15km/s\\v_{f} = 21km/s(cos33i + sin33j)\\v_{f} = 21km/s(0.83i + 0.54j)\\t = 8 min = 480 s\\a = v_{f} - v_{i}/t\\a = 17.83i + 11.34j - 15i/480\\a = (0.0058i + 0.023j)km/s^{2}[/tex]
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Use the position-time graph below to answer the following questions.
What is the displacement of the object?
What is the distance travelled by the object?
Sketch the velocity-time graph that corresponds to this data.
Answer:49
Explanation:47484=4848489
From his observations of the phases of venus, galileo concluded that the ptolemaic model of planetary motion was wrong because it predicted.
Galileo’s telescopic discoveries of the moons of Jupiter are often mentioned. But they did not amount to proof that the Ptolemaic system was incorrect.
It's hard to tell you how big a shakeup this caused in astronomy at the time. Thanks to Galileo, we now knew that planets weren't perfect, ethereal lights in the sky. That things could orbit them, same as (most astronomers thought) things did around Earth, making Earth less special, and providing evidence that maybe that heliocentric theory wasn't that out there.
Basically, before Galileo, astronomers were looking at an unchanging, heavenly firmament, separate from Earth by its very heavenly nature.
After, they were studying planets - actual worlds like ours - and moons and the physical (as opposed to heavenly) reality of their place in the universe.
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After Thanksgiving, Kevin and Gamal use the turkey's wishbone
to
make a wish. If Kevin pulls on it with a force 0.17 N a larger than
the force Gamal pulls
with in the opposite direction, and the
wishbone has a mass of 13
g, what is the wishbone's initial
acceleration?
According to the given statement the wishbone's initial acceleration is 13.08 m/s².
How does acceleration work?Velocity's rate of change with time, both in terms of speed and direction. A point or item going straight ahead is accelerated when it increases or decelerates. Even if the speed remains constant, motion on a circular accelerates so because direction is always shifting.
Briefing:In this task, we calculate the acceleration for a given force and the mass on which the force was applied.
F[tex]_n_e_t[/tex] = 0.17 N
m = 13g
m = 1.3 × 10⁻² kg
a =?
F = m × a
a = F/m
a=0.17 N/1.3× 10⁻² kg
a=13.08 m/s²
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in example 2.6, we considered a simple model for a rocket launched from the surface of the earth. a better expression for a rocket's position measured from the center of the earth is given by
The expression for velocity is [tex]v(t)=\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}[/tex]
The expression for acceleration is [tex]a(t)=-\left ( \frac{gR_{E}^{2}}{[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{4}{3}} \right )[/tex]
The expression for the rocket's position as measured from the center of the earth is
[tex]y(t)=[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{2}{3}[/tex]
Let
[tex]x(t)=R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t[/tex]
We have,
[tex]y(t)=[x(t)]^\frac{2}{3}[/tex]
The velocity of the rocket as a function of time is given by
[tex]v(t)=\frac{\mathrm{d} y(t)}{\mathrm{d} t}=\frac{2}{3}[x(t)]^{-\frac{1}{3}}\frac{\mathrm{d} x(t)}{\mathrm{d} t}[/tex]
[tex]v(t)=\frac{\mathrm{d} y(t)}{\mathrm{d} t}=\frac{2}{3}\frac{1}{\sqrt[3]{x(t)}}\frac{\mathrm{d} x(t)}{\mathrm{d} t}[/tex]
Since
[tex]x(t)=R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t[/tex]
We have,
[tex]\frac{\mathrm{d} x(t)}{\mathrm{d} t}=3\sqrt{\frac{g}{2}}R_{E}[/tex]
[tex]v(t)=\frac{2}{3}\frac{1}{\sqrt[3]{x(t)}}\frac{\mathrm{d} x(t)}{\mathrm{d} t}[/tex]
[tex]v(t)=\frac{2}{3}\frac{1}{\sqrt[3]{x(t)}} X 3 \sqrt{\frac{g}{2}}R_{E}=\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}[/tex]
[tex]v(t)=\frac{\sqrt{2g}}{\left ( R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t \right )^\frac{1}{3}}R_{E}[/tex]
[tex]v(t)=\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}[/tex] .......(i)
The acceleration as a function of time is given by
[tex]a(t)=\frac{\mathrm{d} v(t)}{\mathrm{d} t}[/tex]
[tex]a(t)=\frac{\mathrm{d}}{\mathrm{d} t}\left (\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}\right )[/tex]
[tex]a(t)=\frac{\mathrm{d}}{\mathrm{d} t}\left ({\sqrt{2g}}R_{E}[x(t)]^{-\frac{1}{3}}\right )[/tex]
[tex]a(t)=\sqrt{2g}R_{E}\frac{\mathrm{d}}{\mathrm{d} t}[(x(t)]^{-\frac{1}{3}}[/tex]
[tex]a(t)=-\frac{1}{3}\sqrt{2g}R_{E} [(x(t)]^{-\frac{4}{3}}\frac{\mathrm{d} x(t)}{\mathrm{d} t}[/tex]
[tex]a(t)=-\frac{1}{3}\sqrt{2g}R_{E} [(x(t)]^{-\frac{4}{3}}3\sqrt{\frac{g}{2}}R_{E}[/tex]
[tex]a(t)=-gR_{E}^2 [(x(t)]^{-\frac{4}{3}}[/tex]
[tex]a(t)=-\left ( \frac{gR_{E}^{2}}{[x(t)]^\frac{4}{3}} \right )[/tex]
[tex]a(t)=-\left ( \frac{gR_{E}^{2}}{[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{4}{3}} \right )[/tex] .......(ii)
Therefore, the expression for velocity is [tex]v(t)=\frac{\sqrt{2g}}{\sqrt[3]{x(t)}}R_{E}[/tex]
& the expression for acceleration is [tex]a(t)=-\left ( \frac{gR_{E}^{2}}{[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{4}{3}} \right )[/tex]
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In Example 2.6, we considered a simple model for a rocket launched from the surface of the Earth. A better expression for a rocket's position measured from the center of the Earth is given by [tex]y(t)=[R_{E}^{\frac{3}{2}}+3\sqrt{\frac{g}{2}}R_{E}t]^\frac{2}{3}[/tex]
where RE is the radius of the Earth (6.38 ✕ 106 m) and g is the constant acceleration of an object in free fall near the Earth's surface (9.81 m/s2).
(a) Derive expressions for v(t) and a(t).
(Use the following as necessary: g, RE, and t. Do not substitute numerical values; use variables only.)
Can a car that has been traveling at different speeds in a straight line east have accelerated west?.
Yes. If a car is traveling eastward and slowing down, its acceleration is opposite to the direction of travel: its acceleration is westward.
A car that has been traveling at different speeds is already accelerating.
Now suppose it is traveling at different speeds means some force is applied to that car.
It is traveling in a straight line in the east and traveling at a different speed, which means the speed keeps on changing so sometimes it can be possible that acceleration can also be in the opposite direction to that in which it is traveling, so here it can be in the west as it is an easterly course of travel direction so no north or south direction movement.
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A train travelling at 22m/s accelerates uniformly at 0.85 m/s^2 for 25s. Calculate the distance travelled by the train at this time.
The distance travelled by the train travelling at 22 m/s, which accelerates uniformly at 0.85 m/s² for 25s is 815.62.
What is Second equation of motion?
The second equation of motion is used to calculate the distance traversed by the body moving with uniform velocity. Mathematically -
S = ut + 1/2 at²
Given in the question is a train travelling at 22 m/s accelerates uniformly at 0.85 m/s² for 25s. From this, we can write -
Initial velocity [u] = 22 m/s
acceleration [a] = 0.85 m/s²
time taken [t] = 25 s
In order to find the distance travelled by the train, we will use the second equation off motion -
S = ut + 1/2 at²
S = 22 x 25 + 1/2 x 0.85 x 25 x 25
S = 815.62 meters
Therefore, the distance travelled by the train travelling at 22 m/s, which accelerates uniformly at 0.85 m/s² for 25s is 815.62.
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HELP ASAPP PLEASE!!! I know that I got one correct but i’m not sure what the other one is.
Answer:
Replace distance with "direction"
Explanation:
the 25-m crane boom ao lies in the yz plane. determine the maximum permissible tension in cable ab if the absolute value of moments about the coordinate axes of the force exerted on a by cable ab must be |mx|≤ 61.6 kn·m, |my|≤ 13.6 kn·m, |mz|≤ 9.6 kn·m.
The maximum permissible tension in cable AB is 3.11 kN
Given that,
I [tex]M_{x}[/tex] I ≤ 61.6 kN.m
I [tex]M_{y}[/tex] I ≤ 13.6 kN.m
I [tex]M_{z}[/tex] I ≤ 9.6 kN.m
OC = √ [tex]OA^{2}[/tex] - [tex]AC^{2}[/tex]
OC = √ [tex]25^{2}[/tex] - [tex]15^{2}[/tex]
OC = 20 m
[tex]r_{A}[/tex] = 15j + 20k
AB = √ [tex]2.5^{2}[/tex] + [tex]15^{2}[/tex] = 15.2069 m
P = P AB / AB = ( P ) 2.5i - 15j / 15.2069
P = 0.164399P i - 0.98639P j
[tex]M_{o}[/tex] = [tex]r_{A}[/tex] * P = [tex]\left[\begin{array}{ccc}i&j&k\\0&15&20\\0.163499P&-0.98639P&0\end{array}\right][/tex]
[tex]M_{o}[/tex] = ( 19.7828P ) i + ( 3.2700P ) j - ( 2.4525P )k
I [tex]M_{x}[/tex] I ≤ 61.6
19.7828P ≤ 61.6
P ≤ 3.11 kN
I [tex]M_{y}[/tex] I ≤ 13.6
3.2700P ≤ 13.6
P ≤ 4.16 kN
I [tex]M_{z}[/tex] I ≤ 9.6
2.4525P ≤ 9.6
P ≤ 3.91 kN
Tension is the act of stretching. It is a force transmitted through a object when pulled by forces across opposite sides.
Therefore, the maximum permissible tension in cable AB is 3.11 kN
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three 3.0 -μc point charges are at the three corners of a square of side 0.50 m. the last corner is occupied by a −3.0 -μc charge. find the magnitude of the electric field at the center of the square.
The magnitude of the electric field at the center of the square is 4.32 * [tex]10^{5}[/tex] N / C
We know that,
The magnitude of the electric field by the one positive charge and other negative charge at the centre is
E = k ( [tex]q_{2}[/tex] - [tex]q_{4}[/tex] ) / [tex]r^{2}[/tex]
The distance of each charge from the centre of the square is
r = d / √ 2
where,
k = Coulomb's constant
[tex]q_{1}[/tex], [tex]q_{2}[/tex], [tex]q_{3}[/tex], [tex]q_{4}[/tex] = Point charges
d = Side of square
Given that,
[tex]q_{1}[/tex] = [tex]q_{2}[/tex] = [tex]q_{3}[/tex] = 3 μ C = 3 * [tex]10^{-6}[/tex] C
[tex]q_{4}[/tex] = - 3 μ C = - 3 * [tex]10^{-6}[/tex] C
d = 0.5 m
k = 9 * [tex]10^{9}[/tex] N m² / C²
E = k ( [tex]q_{2}[/tex] - [tex]q_{4}[/tex] ) / [tex]r^{2}[/tex]
E = 2 k / d² ( [tex]q_{2}[/tex] - [tex]q_{4}[/tex] )
E = 2 ( 9 * [tex]10^{9}[/tex] ) ( 3 * [tex]10^{-6}[/tex] - ( - 3 * [tex]10^{-6}[/tex] )) / 0.5²
E = 4.32 * [tex]10^{5}[/tex] N / C
Electric field is the field surrounding an electrically charged particle. If any other charged particle enters the field, it exerts force on the particle.
Therefore, the magnitude of the electric field at the center of the square is 4.32 * [tex]10^{5}[/tex] N / C
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FITT principle:
Frequency-is how regular or often a person does the plan of a target health-related physical activity. It depends on how determined you want to accomplish your target. The more often you train, the faster the result.
Intensity - is how hard a person exercise during a physical activity period. It can be measured in different ways, depending on the health-related component. For example, monitoring heart rate is one way to measure the intensity during aerobic endurance activities, but does not indicate intensity during flexibility activities. The harder you work, the faster your heart beats.
Time - is the duration of the physical activity. Together with the other aspects of the FITT principle, time varies depending on the target health-related fitness component. For example, in developing flexibility, stretching may take 10-30 seconds for each activity, while the minimum time for performing an aerobic exercise is 20 minutes of continuous action.
Type - refers to the physical activity chosen to improve a specific component of health-related fitness. Different events require different training programs. For example, if a person wants to increase core muscles, he or she must do exercises that target the oblique muscles, while another person wishing to improve his or her cardiovascular endurance needs to jog, run, swim or perform some other aerobic activities.
The FIIT plan required for different type of workout is shown in the image attached.
FIIT plan is used to monitor one's workout routine. It also helps to create workout routines that helps one's fitness goal which might differ from each person. It works based on four elements i.e., Frequency, Intensity, Time and Type.
Frequency refers to how often a workout needs to be done. Intensity refers to how hard a workout must be done. Time refers to the amount of time spent on the workout. Type refers to the king of exercise which suits one's final goal.
Therefore, the FIIT plan required for different type of workout is shown in the image attached.
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The net force on a moving object suddenly becomes zero and remains zero. The object will.
The net force on a moving object suddenly becomes zero and remains zero then the object will be in rest according to Newton's first law of motion.
The force on an object is equal to its mass times of its acceleration i.e.
F =ma
where , m is the mass , F is the force and a is the acceleration of the object. Its unit is Newton (N).
Newton's first law can be stated as , when an object at rest remains at rest, or if in motion, remains in motion at a constant velocity unless acted on by a net external force. A reaction force is a force that acts in the opposite direction to an action force.
Velocity of an object can be said as, the rate of change of displacement with respect to time of an object . Its unit is m/s and it is a vector quantity.
V = Δx/Δt
In here , V is velocity , Δx is change in displacement and Δt is change in time of an object.
In hence ,when the net force becomes zero F=0 the velocity of the object will be zero , then the object will remain at rest.
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