Theres a rectangle with the measurements of length 5 meters and width 3 meters, what would 3 meters and 5 meters be in a scale factor of 1 to 50 centimeters

Answer:

Seems correct. I would never use pen for a math assignment though ;-;

Here’s the answer sheet lol.

Step-by-step explanation:

The transformation is rotation 90° clockwise followed by a reflection over the y-axis

The question is given as

Which of the following BEST represents this transformation?

From the question, we have the figure shown to be

A transformation of a figure from Quadrant II to Quadrant IV

From the figure, we can see that the shapes in both quadrants have the same dimensions

This means that the shapes are not dilated

However, the orientation of the figures are difference

Because of the positioning of the shapes, we can conclude that the transformaton is rotation 90° clockwise followed by a reflection over the y-axis

Hence, the transformation is rotation 90° clockwise followed by a reflection over the y-axis

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If Upper pointing arrow with height of 11 and length of 9. Rectangular base of arrow has length of 7 and height of 8. All units are in centimeters. The area of the arrow by decomposing it into rectangles and triangles is: 69.5 square centimeters.

First step is to determine the Area of triangle using this formula

Area of triangle= ½×breadth ×height

Where:

Breadth=9

Height of triangle= 11 - 8

Height of triangle = 3cm

Area of triangle= ½ × 9 × 3

Area of triangle = 13.5 cm²

Second step is to determine the area of rectangle

Area of rectangle= length × breadth

Area of rectangle= 8 × 7

Area of rectangle= 56 cm²

Third step is to determine the total area

Total area=Area of triangles+ Area of rectangle

Total area = 13.5 + 56

Total area= 69.5 cm²

Therefore the area of the arrow by decomposing it into rectangles and triangles is: 69.5 square centimeters.

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Answer:

10 hours

Step-by-step explanation:

Unit rate   18 items / 15 hrs = 1.2 items pe hour

12 items / 1.2 items / hour    = 10 hours

[tex]27x^{12}[/tex] smaller cubes will fit in the larger cube.

Given,

Side length of the smaller cube = [tex]x^{2}[/tex] units.

Side length of the larger cube = [tex]3x^{6}[/tex] units.

We have to find the number of smaller cubes that can be fitted in the larger cube.

Volume of cube is given by the formula,

Volume = (side)³

Volume of the larger cube = [tex](3x^{6} )^{3}[/tex]   =  [tex]27x^{18}[/tex]units³

Volume of the smaller cube = [tex](x^{2} )^{3}[/tex] = [tex]x^{6}[/tex] units³

Let the number of smaller cube that can be fitted in the larger cube = n

Volume of  n cubes = [tex]nx^{6}[/tex] units³

If space inside the larger cube will be occupied by 'n' smaller cubes,

  volume of n smaller cubes = Volume of a larger cube

                                      [tex]nx^{6}[/tex]           =  [tex]27x^{18}[/tex]

                                       n             = [tex]27x^{12}[/tex]

Therefore, [tex]27x^{12}[/tex] smaller cubes can be fitted in the larger cube.

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Answer:

4.1

Step-by-step explanation:

madookoo doo doo

Based on the attached graph, the point that is located at (5,-2) is point F

The graph that completes the question is added as an attachment

The point located at (5,-2) implies that the coordinates of the point are

x-coordinate = 5

y-coordinate = -2

From the attached graph, we can see that the point F has the following properties

x-coordinate = 5

y-coordinate = -2

This means that the point F is located at (5,-2)

Hence, the point that is located at (5,-2) is point F

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a) Jeremy get to keep 85%

b) $6.273 is Jeremy's hourly take home wage.

Given,

Jeremy has a job at the movie theatre.

Hourly wage of Jeremy = $7.38

The % of income withheld for taxes and social security = 15%

7.38 × (15/100) = 1.107

That is, $1.107 from Jeremy's income is withheld for taxes and social security.

a) Percentage of income Jeremy get to keep:

= 100% - Withheld percentage

= 100 - 15

= 85

So, Jeremy gets 85% of his income to keep with him.

b) Jeremy's hourly take home wage:

Total income - Withheld amount

7.38 - 1.107 = 6.273

That is, Jeremy's hourly take home wage is $6.273.

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the range of the function g(x) will be y ≤ 0.

We know that the absolute value function g(x) can be written as:

g(x) = a*|x|

Remember that the range of f(x) = |x| is y > 0, and a is a negative number, so the function is reflected over the horizontal axis.

Then the maximum value will be when x = 0, then:

g(0) = a*|0| = 0, that is the maximum.

And then the function opens downwards. Then the range will be y ≤ 0.

So the range of the absolute value function g(x) is the set of all real values equal to or smaller than zero.

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Answer:

34

Step-by-step explanation:

hutbjj jugo uva bombom

The probabilities of all possible outcomes must sum to 1. So the missing probability is

1 - 1/2 - 3/10 - 1/20 = (20 - 10 - 6 - 1)/20 = 3/20

√10 is greater than √2 + √3 .

First we assume that  √10 is greater than √2 + √3. Then we check if this relation is true.

So suppose that  √10 > √2 + √3

On squaring both sides and using the algebraic identity [tex](a+b)^2=a^2+b^2+2ab[/tex],

⇒ 10 > 2 + 3 + 2√6

⇒ 10 > 5 + 2√6

Subtracting 5 from both sides, we get,

⇒ 5 > 2√6

Again squaring on both sides,

⇒ 25 > 4 x 6

⇒ 25 > 24

This is a true relation. So our assumption that √10 is greater than √2 + √3 was right.

Therefore, √10 > √2 + √3

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The temperature of the liquid at 3PM will be -7.5 °C

The initial temperature of the liquid at 9 AM  = 0°C

Given that the temperature changes by -5/4 °C each hour.

That is the rate of change of temperature = -5/4 °C

We have to find the temperature of the liquid at 3 PM.

Let x denote the number of hours.

Then the temperature after x hours, t = 0 + ( -5/4)x = -(5/4)x is the linear equation modelling this set up.

So from 9 AM to 3PM, the number of hours =  6 hours

Put x = 6 .

Then, t = (-5/4) x 6

            = -7.5

Therefore, the temperature of the liquid at 3 PM = -7.5°C

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Using it's concept, the domain of the relation is given as follows:

x ≥ 0.

In a graph, the domain and the range are found as follows:

From the graph, we have that the weights of the packages assume all values to the right of 0, hence the domain of the relation is given as follows:

x ≥ 0.

The relation is incomplete, and is given by the graph at the end of the answer.

The question asked is the domain of the relation.

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Answer: |81 - (-29)|==> C

Step-by-step explanation:

h=high temperature

h=81

l=low temperature

l=-29

d=difference in high and low temperature

h-l=d

81-(-29)=d

81+29=d

d=110 ==> |81 - (-29)|=|81 +29|=|110|=110

|81 - (-29)|==> C

|81 -29|=|52|=52

-29 + 81=81-29=52

Yes  , the set of real numbers closed under addition because on adding them we get a new number .

If the operation produces even one part outside of the set, the operation isn't closed.

The set of real numbers is closed below addition. If you add 2 real numbers, you'll get another complex quantity. there's no chance of ever obtaining something apart from another complex quantity.

5 + 12 = 17

2.5 + 3.4 = 5.9

As , we get another quantity on adding real number , hence it is closed under addition.

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Answer:

x=4 that is it i believe and bc i did it

Radical expression containing third root terms will be first multiplied and then simplified to its simplest form.

A radical expression is a mathematical expression containing a radical symbol (√). A radical expression contains three distinct parts:

1. A radical symbol which is the square root sign.

2. A radicand which is a component inside the radical,

3. A degree which is the root represented by the radical.

In the given expression, the radicand is 9 while the degree is 3.

As the degree is the same for both the terms, we can multiply the radicand.

Multiplying the radicand terms,

∛(9*9)=∛81

Simplifying the radicand,

∛(3*3*3*3)

Taking the cube root and simplifying,

3∛3

Hence, ∛9.∛9 = 3∛3

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Answer:

63

Step-by-step explanation:

Numbers divisible by 9:

18, 27, 36, 45, 63, 72, 81, 90 and 99.

Numbers divisible by 7:

7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98.

Least common multiple=63

The function C(F) to calculate the temperature in degrees Celsius for a given temperature in degrees Fahrenheit will be equal to [tex][(\frac{5}{9}F) -\frac{160}{9}][/tex]

As per the question statement,  the formula [F(C) = 9/5C + 32] is to calculate the temperature in degrees Fahrenheit for a given a temperature in degrees Celsius.

We are required to determine the function to calculate the temperature in degrees Celsius for a given temperature in degrees Fahrenheit.

Since, [F(C) = 9/5C + 32],

[tex]or, [F = \frac{9}{5} C + 32]\\or, (F-32)= \frac{9}{5} C\\or, \frac{9}{5} C=(F-32)\\or,C=\frac{5}{9} (F-32)\\or,C=\frac{5}{9}F-\frac{160}{9}[/tex]

That is, the function to calculate the temperature in degrees Celsius for a given temperature in degrees Fahrenheit is [tex]C(F)=[(\frac{5}{9}F) -\frac{160}{9}][/tex].

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Answer:

inverse

C(F)=5/9F-106/9

check all

Step-by-step explanation:

23

The translation of the polygon 3 units down and 4 units left is;

A''(-2, -4)

B"(-3, -7)

C"(-1, -8)

D"(1, -6)

We are given the coordinates of the polygon as;

A(2, -1), B(1, -4), C(3, -5), D(5, -3)

Now, we are told that all points are translated 3 units down and 4 units left. Thus, the new coordinates are;

A'(2, -1 - 3) = A'(2, -4)

B(1, -4 - 3) = B'(1, -7)

C(3, -5 - 3) = C'(3, -8)

D(5 , -3 - 3) = D'(5, -6)

Translation of 4 units left is now;

A''(2 - 4, -4) = A''(-2, -4)

B"(1 - 4, -7) = B"(-3, -7)

C"(3 - 4, -8) = C"(-1, -8)

D"(5 - 4, -6) = D"(1, -6)

The translation of the polygon 3 units down and 4 units left is;

A''(-2, -4)

B"(-3, -7)

C"(-1, -8)

D"(1, -6)

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Answer: Pretty sure its B. The same shape and size.

Step-by-step explanation:

The logarithmic expression as a single logarithm is log. a³/b²

A logarithmic and even sometimes log function is the inverse of an exponential function. We could employ a log function to find an exponent.

We should be able to transform between logarithmic as well as exponential forms in order to calculate earthquake magnitudes and otherwise correlate the magnitudes of two distinct earthquakes.

Let's use this information to make our log. Here is the logarithmic function:

Now, as for the represented expression;

= 3 log a-2 log b

Using the power rule in both of the terms.

=  log a³- log b²

Now, applying the Quotient Rule,

= log a³/b²

Therefore, the obtained single logarithm for the given logarithmic expression is log a³/b².

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The single logarithm for the given expression (2 log₄6 - log₄9) is 1.

The given logarithmic expression is 2 log₄6 - log₄9.

Use the ability rule of the logarithm logₐ(Xⁿ) = n logₐ(X), to get 2

log₄6 - log₄9= log₄6² - log₄9

= log₄36 - log₄9          (Since 6² = 36)

Use the quotient rule of the logarithm logₐ(X/Y) = logₐ(X) - logₐ(Y), to get:

log₄36 - log₄9= log₄(36/9) = log₄(4)      

(Dividing 36 by 9, to get, 36 ÷ 9 = 4)

= 1                (Since logₐ(a) = 1)

Therefore, the one logarithm for the given logarithmic expression (2 log₄6 - log₄9) is 1

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According to the given equation(4 e x⁻¹=64) the value will be = x=4ln(2)−(−1).

Logarithms are another technique to express exponents. An integer's baseline logarithm matches another number. A logarithm is the inverse of exponentiation.

Given : 4 e x⁻¹=64

STEPS USING DEFINITION OF LOGARITHM

4e ^(x−1) =64

To resolve the equation, use exponents and logarithms laws.

4e^x−1 =64

Divide both sides by 4.

e^x−1 =16

Take the logarithm of something like the equation's two sides.

loge^x−1 = log16

Divide both sides by log(e).

[tex]x-1=\frac{\log (16)}{\log (e)}\\[/tex]

By the change-of-base formula [tex]\frac{\log (a)}{\log (b)}=\log _b(a)[/tex]

x−1=log e(16)

add1 from both components of the equation.

According to the given equation(4 e x⁻¹=64) the value will be = x=4ln(2)−(−1)

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No valid conclusion drawn from the statements.

You can "detach" the hypothesis from the conclusion using the law of detachment. More specifically, if p and p -q are known to be true, we can infer that q is true. On the other hand, we can cram conditional statements together using the law of syllogism. When p-q and q-r are known to be true, they can be combined to form p-r. After all, it would be silly-gism to go through q when we can just go from p to r.

P = quadrilateral has diagonals

Q = quadrilateral diagonals bisect each other

R= the quadrilateral is a parallelogram

Statement P is true because all quadrilaterals have 2 diagonals that runs from one edge to another eg square, rectangle, parallelogram, kite etc

Statement Q is False because not all quadrilateral's diagonals bisect each other as in the case of trapezium, likewise quadrilateral whose diagonals bisects each other are not only parallelogram, kite, square and rectangle diagonals bisect each other.

Statement R is False because a quadrilateral whose diagonals bisect each other is not only parallelogram. Square, rectangle and Kite diagonals also bisect each other, and they are also parallelogram.

Therefore, no valid conclusion made from the statements because parallelogram is not the only quadrilateral whose diagonals bisect each other and not all quadrilateral's diagonals bisect each other.

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Answer:

27

Step-by-step explanation:

Answer:

the answer is the 235⁰ ok that