Treatment of 2-amino-2-methylcyclohexanone with methyl 2,4-dibromobutanoate in the presence of a nonnucleophilic base, , involves two successive SN2 reactions and gives compound A. Propose a structural formula for compound A.

Answer:

The marshmallow goes through a chemical change called combustion

Explanation:

Dont know if this helps but

According to Le Châtelier’s principle or reactions in chemical equilibrium;

2 NH₃ (g) → 3 H₂ (g) + N₂(g) : addition of N₂ shifts equilibrium to the left

N₂ (g) + O₂(g) → 2 NO (g) : addition of N₂ shifts equilibrium to the right

2 NO (g) → N₂ (g) + O₂ : addition of N₂ shifts equilibrium to the left

4 NH₃ (g) + 3 O₂ (g) → 2 N₂ (g) + 6 H₂O (g) : addition of N₂ shifts equilibrium to the left

Equilibrium in a chemical reaction refers to the point in a chemical reaction in which the rate of the formation of product from the reactants or the forward reaction is equal to the rate of formation of reactants from products or the backward reaction.

For equilibrium to be achieved in a chemical reaction the reaction must occur in a closed or isolated system.

The condition that occur in a reaction in equilibrium are described by Le Châtelier’s principle which states that for a reaction in equilibrium, the equilibrium position will shift to annul any constraint or change imposed on the system.

Considering the given reactions:

2 NH₃ (g) → 3 H₂ (g) + N₂(g) : addition of N₂ shifts equilibrium to the left

N₂ (g) + O₂(g) → 2 NO (g) : addition of N₂ shifts equilibrium to the right

2 NO (g) → N₂ (g) + O₂ : addition of N₂ shifts equilibrium to the left

4 NH₃ (g) + 3 O₂ (g) → 2 N₂ (g) + 6 H₂O (g) : addition of N₂ shifts equilibrium to the left

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The correct answer is: Atoms are the building blocks that make up elements. At the center of each atom is a nucleus composed of small particles called protons and neutrons. Nuclei is the plural of nucleus; option C.

The atomic number of an element is the number of protons present in the nucleus of the atom of the element.

The nucleus is the center of the atom and is the heaviest part of the atom.

Another sub-atomic particle fund in the nucleus is the neutron.

Elements are named according to the number of protons in the nuclei.. This is because the number of protons in the nucleus of any given atom whereas the neutron number may vary, Also, electrons are easily removed from atoms of elements.

In conclusion, the number of protos in atom is used to name the atom.

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Answer:

an electron charge is -1

Direct relationship means increase in one variable leads to increase in other variable and vice-versa. inverse relationship means  increase in one variable leads to decrease in other variable.

Direct relation defined as when both the variables decreases together or both the variables increases together.

On graph , let one variable is x and other is y , So  x increases when y increases or x decreases when y decreases. direct relationship on graph has positive slope.

Mathematically expressed as y = kx   ( k is constant)

Inverse relationship defines as when one variable increases while other decrease or when one variable decreases while other increases. inverse relationship has negative slope on graph.    

Mathematically expressed as y = k/x

Thus,Direct relationship means increase in one variable leads to increase in other variable and vice-versa. inverse relationship means  increase in one variable increases it leads to decrease in other variable.

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Answer:

Percent Composition (C)  =  71.40%

Explanation:

To find the percent composition of carbon by mass, you need to (1) calculate the molar mass of C₂₀H₂₉FO₃ (using the atomic masses of each atom in the molecule), then (2) calculate the total amount of carbon in C₂₀H₂₉FO₃ (using the atomic mass of carbon), and then (3) calculate the percent composition of carbon.

(Step 1)

Atomic Mass (C): 12.011 g/mol

Atomic Mass (H): 1.008 g/mol

Atomic Mass (F): 18.998 g/mol

Atomic Mass (O): 15.999 g/mol

Molar Mass (C₂₀H₂₉FO₃):

20(12.011 g/mol) + 29(1.008 g/mol) + 18.998 g/mol + 3(15.999 g/mol)

=  336.447 g/mol

(Step 2)

Atomic Mass (C): 12.011 g/mol

Total Mass (C): 20(12.011 g/mol) = 240.22 g/mol

(Step 3)

                                                  mass of carbon
Percent Composition (C)  =  -----------------------------  x  100%
                                                 mass of molecule

                                                   240.22 grams
Percent Composition (C)  =  -----------------------------  x  100%
                                                  336.447 grams

Percent Composition (C)  =  71.40%

The reaction condition making use of hydrazine (NH₂-NH₂) and hydroxyl ions cannot be used for the mentioned transformation.

Which catalysts are used for conversion of nitro compound to aniline?

Catalysts used for the reduction of nitro compound to aniline are palladium catalysts ,although iron and nickel along with HCl can also be used as they all belong to d-block of the periodic table, which are well-known for their properties to be used as a catalyst.

Hydrazine cannot be used as a catalyst for the conversion of nitro compound to aniline as it is expensive as well as poisonous. Catalysts which are to be used for such conversions must be cost effective and safe to handle.

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Based on the equation of the reaction, there are two cesium atoms on the product side of the equation.

Cesium is a metallic element that is found in the group 1A of the period table.

Cesium therefore has one valence electro which it can donate to an electronegative element to form a compound wit the element.

Fluorine belongs to the group 7A of the period table known as the halogens.

Fluorine accepts one electro from an electropositive element to form a compound with the element.

The equation of the reaction between cesium and fluorine is given below:

There are two cesium atoms on the product and reactant side of the equation.

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The body of scientific knowledge is based on different Observations (Option C).

Observations in the scientific method are fundamental because it is the first step to raising scientific questions that may be explained through plausible hypotheses. Subsequently, hypotheses must be tested by experimental procedures.

In conclusion, the body of scientific knowledge is based on different Observations (Option C).

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The half life of radioactive iodine 137 is 8 days 0.0866 iodine nuclei are necessary to produce an activity of 1.0 micro Ci

Here given data is half life of radioactive iodine 137 = 8days

Activity of iodine is = 1.0micro Ci

Radioactive decay is the process by which an unstable atomic nucleus loses energy by radiation and the material containing unstable nuclei is considered radioactive

The interconnection between the decay constant and half-life of any sample can be given by the expression are

T1/2 = (0.693/R); T1/2 = 8

8 = 0.693/R;  R=0.0866 R=0.693×1.0/t1/2 = 0.0866

0.0866 iodine nuclei are necessary to produce an activity of 1.0 micro Ci

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The formal charges that the atoms bear in the compounds are;

1)

a - zero

b - plus half

c- zero

2)

a - zero

b - zero

c - plus one

The formal charge has to do with the charge that an atom appears to have in a compound. We could often decode the formal charge that  compound might posses just by an intent look at the compound.

We know that the outermost shell of all the atoms in a compound ought to have eight electrons. This implies that all the atoms of elements in a compound must obey the octet rule. The atoms that do not obey the octet rule must bear a formal charge.

The formal charges that the atoms bear in the compounds are;

1)

a - zero

b - plus half

c- zero

2)

a - zero

b - zero

c - plus one

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The compound formed is Boric/Boron Oxide B2O3

One of the boron oxides is boron oxide. It has the chemical formula B2O3 and is white, glassy, and solid. It usually always exists in the vitreous (amorphous) form, but with sufficient annealing, it can crystallize. One of the most challenging chemicals to crystallize is this one. Boron oxide is a highly insoluble, thermally stable source of the element that can be used in ceramic, glass, and optical applications.

Oxide compounds are not electrically conductive. Some perovskite structured oxides, on the other hand, are electronically conductive and find use as the cathode in solid oxide fuel cells and oxygen production systems. They are mixtures with at least one metallic cation and one oxygen anion. reactions.

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1409.36ml

chemist wants to make 5,748 mL of a solution with a concentration of 2.55 M. How many liters of a 10.40 M solution should be used to make this solution

from the above statement, we have got

[tex]M_1[/tex]= 2.55 M.                    [tex]M_2[/tex]=10.40 M

[tex]V_1[/tex]=  5,748 mL                     [tex]V_2[/tex]=?

now, from the formula,

[tex]M_1V_1=M_2V_2[/tex], In this M is molarity and V is Volume

now put the values in the equation,

2.55×5748=10.40×[tex]v_2[/tex]

[tex]V_2[/tex] = 2.55×5748÷10.40

[tex]V_2[/tex]= 14,657.4÷10.40

[tex]V_2[/tex]=1409.36ml

.The number of moles of solute dissolved in one liter of solution is known as the molarity, which is the concentration of a solution. it's unit is mole per litre. it is temperature dependent concentration.

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The process that completes the way that the the federal budget is created is that executive agencies submit budget requests.

The budget refers to the way in which the expenditure of the government is to be run in the coming year. It is customary that the executive must present their budget to the legislative arm of the government for consideration. It must be noted that the budget that has been drafted by the executive arm of government could only be passed into law by the legislative arm.

It is important to note that the legislative arm of government is composed of both the senate and the congress and the both chambers of the legislature must have to individually pass the appropriation bill before it could be passed into law by the president.

Hence, the process that completes the way that the the federal budget is created is that executive agencies submit budget requests.

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Answer:

17,650 m

Explanation:

100 cm = 1m so, 176.5 × 100 = 17,650m

PV= nRT, The total number of moles of chlorine gas  are 140.09.

What is the mole?

PV= nRT,

T = 120 C = 120 + 273=  393 K

R = 0.08314 L . bar/ mol

P= 26.1 bar

The volume of the vessel= 18.5 L.

PV= nRT, on substituting the value of

26.1 * 18.5 = n * 0.08314 * 393 K

482.85= n* 3.24

482.85/ 3.24= n

149.0 =n

Therefore, PV= nRT, The total number of moles of chlorine gas  are 140.09.

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Answer:

1+1=2

Explanation:

Answer:

How many atoms are in a mole of silver?

From Avogadro's number, we know that one mole of silver atoms is equal to 6.02 times 10 to the 23rd silver atoms

Explanation:

Answer:

it's 50.11 trust me I know thank you

-300;800 is the correct answer

With 25 grams of sodium chloride, 1.2 liters of a 0.35 M solution of sodium chloride may be created.

The quantity of solute dissolved in one liter of solution is known as molarity (M).

Molarity (M) is defined as the number of moles of a solute divided by the volume of the solution in litres.

M = n / v where

M stands for molarity, n for moles, and V for volume of solution.

NaCl's molar mass is 23 g/mol plus 35.5 g/mol.

= 58.5 g/mol

Now,

Given mass/molar mass equals the number of moles (n).

= 0.427

We must now determine the solution's volume.

M = 0.35 = 0.427 / v

V is 1.2 liters

Thus, 25 grams of sodium chloride might be used to create 1.2 liters of sodium chloride solution at 0.35M.

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Answer:

3 mol

Explanation:

According to the balanced chemical equation, on the macroscopic scale, 1 mol of Fe2O3 F e 2 O 3 reacts with 3 mol of CO .

Answer: 744 g

Explanation:

1 L=1000 ml

1.48 g/ml=

1.48*1000 g/L=1480 g/L

1480 g/L * 0.503 L=

744.44=744 g

Answer:

it is A trust me I know thank you

Time did it take a little debbie to run 15 m if she was running 3 m/s is 5 sec.

debbie  running speed = 3 m/s

so,

in one meter = 1/3 sec

we have to calculate the time taken by little debbie to run 15 meters ,

therefore,

Time = distance / speed

time take by debbie to run 15 m = 15 / 3 sec

                                                     = 5 sec.

so, time taken by little dubbie to cover the distance of  15 meter is 5 sec.

Hence, Time did it take a little debbie to run 15 m if she was running 3 m/s is 5 sec.

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The molar mass of the compound is 336.36mol

Molar mass defined as the mass of a sample of that compound divided by the amount of substance

Here given data is mass of sample = 132.0 g

Mass of nonvolatile compound =  4.300 mol = 4.300 mol ×84.16g = 361.88g

Vapor pressure of the solution = 85.00 mmHg

We have to find molar mass of compound = ?

Then we have formula is p⁰-p/p⁰ = W₂M₁/W₁M₂ where,

M2 = molar mass of sample

W1 = molar mass of compound

W2 = weight of compound

Then, 84.00-85.00/84.00 = 361.88×361.88/132.0

M2 = 361.88×361.88×84/132.0

M2 = 336.36mol

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The molecular formula of the given structure is C₁₀H₁₃N₅O₄ and its formula mass is 267 amu.

A molecule's formula mass (also known as formula weight) is the sum of the atomic weights of the atoms in the compound's empirical formula. The formula mass is expressed in atomic mass units (amu).

From the structure of the molecule, we can easily identify the molecular formula of the structure:

Therefore, the molecular formula of the given structure is C₁₀H₁₃N₅O₄.

Now,

Mass of Carbon = 12.011 u

                            = 10 × 12.011 u

                           = 120.11 u

Mass of Hydrogen = 1.00784 u

                              = 13 × 1.00784 u

                             = 13.10192 u

Mass of Nitrogen = 14.0067 u

                            = 5 × 14.0067 u

                            = 70.0335 u

Mass of Oxygen = 15.999 u

                           = 4 × 15.999 u

                           = 63.996 u

Formula mass of C₁₀H₁₃N₅O₄ = 120.11  + 13.10192 + 70.0335 + 63.996

                                                = 267.24142 u

Thus, the formula mass of the given structure i.e., C₁₀H₁₃N₅O₄ is 267.24142 u

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Mass of camphor is 252.47 g and mass is a measure of the amount of matter in a substance or an object

Camphor, an organic compound of penetrating, somewhat musty aroma, used for many centuries as a component of incense and as a medicinal. Modern uses of camphor have been as a plasticizer for cellulose nitrate and as an insect repellent, particularly for moths and the molecular formula is C₁₀H₁₆O

Here given data is camphor (C₁₀H₁₆0) that contains a billion (1.0 × 10°) carbon atoms

So, 1.0×10⁰ carbon atom×1 molecule of camphor/1 carbon atom

1 molecule of camphor×1 mole of camphor/Avogadro's number

1 molecule of camphor×1 mole of camphor/6.06×10²³ molecule

= 1.661 mole of camphor

1.661 mole of camphor ×152 g camphor = 252.47 g camphor

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