Two identical clocks are in the same house, one upstairs in a bedroom and the other downstairs in the kitchen. Which clock runs slower? Explain.

The acceleration of the car is 0.8049[tex]m/s^{2}[/tex].It takes 13.802s to travel the 230 m.

In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies. Acceleration is a vector quantity (in that they have magnitude and direction). The direction of an object's acceleration is determined by the direction of the net force acting on it. Newton's Second Law states that the combined effect of two factors determines how much an item accelerates: 

(i) It follows that  the magnitude of the net balance of all external forces acting on the object is directly proportional to the magnitude of this net resulting force, and

(ii) the mass of the thing, depending on the materials out of which it is constructed, is inversely proportional to the mass of the thing.

Calculations:

40 km/hr ----- 11.11m/s

80 km/hr ----- 22.22m/s

[tex]v^{2} -u^{2} =2as\\22.22^{2} - 11.11^{2} = 2 x a x 230\\ 370.296=460a\\ a= 0.8049m/s^{2} \\[/tex]

Time taken

v-u=at

22.22-11.11= 0.8049 x t

t=13.802s

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The angle θ is 36.3° and the angle ϕ is 26.4°.

A vector quantity is a quantity having both magnitude and direction.

To add vector quantities and get their resultants, we need to apply the parallelogram law of vector addition

Let A and B are two vectors and C is their resultant, then according to the parallelogram law

C^2 = A^2 + B^2 + 2ABcosθ, where  θ is the angle between the two vectors

On applying the parallelogram law in the given diagram,

(40)^2 = 30^2 + 60^2 - 2(30)(60)cosθ

Θ = 36.3°

And

30^2 = 40^2 + 60^2 - 2(40)(60)cosϕ

Φ = 26.4°

Thus, the angle θ is 36.3° and the angle ϕ is 26.4°.

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The horizontal component of the magnetic field is 12.6 μT.

The magnetic influence on moving electric currents, electric charges, and magnetic materials is described by a magnetic field, which is a vector field. When a charge moves through a magnetic field, a force that is perpendicular to both its own velocity and the magnetic field operates on it.

The horizontal component of the Earth's magnetic field is perpendicular to the axis of a circular coil with five turns and a diameter of D = 30.0 cm that is vertically orientated.

A coil current of I = 0.600 A causes a horizontal compass to deflect 45.0° from magnetic north when it is positioned in the coil's center.

Let B be the magnetic field and R be the radius of the circular coil.

Then the horizontal component of the Earth's magnetic field is given as:

[tex]B(h) = B(coil) = \frac{\mu_{0} NI}{2R}[/tex]

[tex]B(h) =\frac{4 \pi \times 10^{-7}\times(5)\times(0.6)}{0.3}[/tex]

B(h) = 12.6 μT

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The answers for question numbers 3 and 4 is correct. For question number 9, the average speed is 2.5 mi /hr and for question number 10 the speed is 5 yards / s.

We know that,

v = d / t

where,

v = Speed

d = Distance

t = Time

1 ) v = 360 / 6 = 60 km / h

2 ) v = 120 / 3 = 40 mi / h

3 ) v = 18 / 6 = 3 m / s

4 ) v = 1000 / 20 = 50 m / min

5 ) t = 6pm - 5 pm = 1 hr

    v = 2.5 / 1 = 2.5 mi / hr

6 ) v = 1.5 / 0.33 = 4.5 mi / hr ( Since 20 min = 20 / 60 = 0.33 hr )

   d = 4.5 * 1 = 4.5 mi

7 ) d = 20 * 1 = 20 mi ( Since 60 min = 1 hr )

8 ) d = 60 * 2 = 120 mi

9 ) Distance per lap = 0.5 mi

     Total laps = 10

     Total distance = 10 * 0.5 = 5 mi

     v = 5 / 2 = 2.5 mi / hr

10 ) v = 100 / 20 = 5 yards / s

Therefore, the answer for:

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The dot product of velocity vector and acceleration vector at maximum height is equal to zero.

[tex]$\overrightarrow{v}.\overrightarrow{a}= 0[/tex]

We have a football player who kicked a football in order to do a goal.

We have to determine the relationship between the direction of the velocity and acceleration vectors when the football reaches its maximum height.

Projectile motion is the two - dimensional motion of an object thrown or projected into the air such that it moves under the influence of acceleration of gravity.

According to the question -

Assume that the velocity with which the projectile was fired is u m/s.

Therefore, it can be resolved into two components as -

[tex]\overrightarrow{u} =[/tex] u(x) + u(y) = u cosθ [tex]a_{x}[/tex] + u sinθ [tex]a_{y}[/tex].

Now, when the projectile reaches the maximum height, it will no longer cover any vertical height but it will keep moving in the horizontal direction. Therefore - the vertical component of the velocity will become zero. Therefore -

[tex]\overrightarrow{u} =[/tex] u(x) + u(y) = u cosθ [tex]a_{x}[/tex] + 0 = u cosθ [tex]a_{x}[/tex]

Now, refer to the figure attached for reference -

At the maximum height, the velocity vector is in the horizontal direction and the vector for the acceleration due to gravity is vertically downwards.

Therefore - the acceleration vector and velocity vector will have an angle of 90° between them. Assume -

Velocity at maximum height = v = u cosθ [tex]a_{x}[/tex]

and acceleration = a = g = 9.8 m/[tex]s^{2}[/tex]

Therefore -

The dot product of velocity vector and acceleration vector is equal to zero.

[tex]\overrightarrow{v}.\overrightarrow{a}= 0[/tex]

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The average velocity or displacement of a particle for the first time interval is Δs / Δt = 6 cm/s.

Solution:

As we know that displacement is calculated in centimeters and the unit of time is second.

The average velocity for the first interval [1,2] is given

Δs / Δt = s (t2) - s (t) / t2 - t1

Δs / Δt = 2sin2  π  + 3cos 2 π -  ( 2sin π + 3cos π ) / 2 - 1

Δs / Δt = 2(0) + 3(1) - 2(0) - 3 (-1) / 1

Δs / Δt = 6 cm/s

Thus the average velocity or displacement of a particle for the first time interval is Δs / Δt = 6 cm/s

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The complete question is:

The displacement of a particle moving back and forth along a line is given by the following equation s(t) = 2sin π t + 3cos π t. Estimate the instantaneous velocity of the particle when t = 1

Answer:

the action of taking out something, especially using effort or force.

Explanation:

35 kilometers per hour is equivalent to 9.73 metres per seconds.

Speed is the rate of distance that is traversed in a given time. It can be calculated by dividing the distance moved by the time taken as follows:

Speed = distance/time

Speed can be measured in the following units;

The conversion factor of kilometers per hour to metres per seconds is as follows:

1 kilometre per hour = 0.278 metre per second

35 kilometers per hour = 9.73 metres per seconds

Therefore, 35 kilometers per hour is equivalent to 9.73 metres per seconds.

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Hence , the rise and fall of the amplitude of the sound causes the variation from loud to soft .

The variation from loud to soft sound created by a twin-engine craft may be explained by the idea of formation of beats.

When 2 sound waves of nearly equal frequencies square measure created at the same time, then the intensity of the resultant sound created by their superposition will increase and reduces as an alternative with time. This increase and reduce within the intensity of sound square measure referred to as the development of beats.

Let us suppose that at a specific time the 2 waves of slightly totally different frequencies square measure in section, i.e. the crest of the primary wave falls on the crest of the second wave, thus at this point the resultant amplitude is most, therefore we tend to hear a louder sound. however since there's a small variation in frequencies there comes a time once the 2 waves square measure out of section, I.e. the crest of 1 wave falls on the trough of the opposite, here the resultant amplitude becomes zero and that we hear no sound. This rise and fall of amplitude continue and what we tend to hear could be a beat. Similar is that the case in an exceedingly twin-engine craft which ends within the variation of loud and soft sound.

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The resultant force is 10.77 pounds.

We need to know about vector to solve this problem. Force is included to vector because it has magnitude and also direction. The resultant force can be determined using cosine law. It can be written as

F² = F1² + F2² - 2F1 . F2 cos(θ⁰)

From the question above, we know that:

F1 = 10 pounds

F2 = 14 pounds

θ = 50°

By substituting the parameter, we get

F² = F1² + F2² - 2F1 . F2 cos(θ⁰)

F² = 10² + 14² - 2. 10 . 14 cos(50⁰)

F² = 100 + 196 - 280 . 0.64

F² = 100 + 196 - 280 . 0.64

F² = 116.02

F = 10.77 pounds

Hence, the resultant force is 10.77 pounds.

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The relativistic time it takes the proton to travel the milky way is 9.877 × 10⁻⁷ s

Since the question has to do with relativistic motion, we need to find the relativistic time it takes the proton to travel the milky way. First, we use the equation for relativistic kinetic energy, we have

K = mc(γ - 1) where

So, making γ subject of the formula, we have

γ  = K/mc + 1

Substituting the values of the variables into the equation, we have

γ  = K/mc + 1

γ  = 1.602J/(1.6726 × 10⁻²⁷ kg × 3 × 10⁸ m/s) + 1

γ  = 1.602J/(5.0178 × 10⁻¹⁹ J) + 1

γ  = 0.3193 × 10¹⁹ + 1

γ  = 3.193 × 10¹⁸

Now since the proper diameter of the milky way d = 10⁵ ly, since the length moved by the proton is going to be contracted, the actual distance moved by the proton is

d' = d/γ

= 10⁵ ly/3.193 × 10¹⁸

= 0.3132 × 10⁻⁻¹³ ly

= 0.3132 × 10⁻⁻¹³ × 9.46 × 10¹⁵ m

= 2.963 × 10² m

Next we need to find the velocity of the proton from

γ = 1/[√(1 - (v/c)²]

3.193 × 10¹⁸ = 1/[√(1 - (v/c)²]

√(1 - (v/c)² = 1/3.193 × 10¹⁸

√(1 - (v/c)² = 0.3132 × 10¹⁸

1 - (v/c)² = (0.3132 × 10⁻¹⁸)²

1 - (v/c)² = 0.0981 × 10⁻³⁶

(v/c)² = 1 - 0.0981 × 10⁻³⁶

(v/c)² = 1 - 0.0000000000000000000000000000000000981

(v/c)² = 0.9999999999999999999999999999999999019

(v/c)² ≅ 0.99999

(v/c) = √0.99999

v/c = 0.999994999987

v = 0.999994999987c

So, the time it takes the proton to travel the milky way is t = d/v

= 2.963 × 10² m/0.999994999987c

= 2.963 × 10² m/2.99998499996 × 10⁸ m/s

= 0.9877 × 10⁻⁶ s

= 9.877 × 10⁻⁷ s

So, the time it takes the proton to travel the milky way is 9.877 × 10⁻⁷ s

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The signal will travel into the space as far as 3.654 x 10^11 meters.

Speed is the distance travel by a body per time taken. Speed is a scalar quantity.

Suppose a radio signal travels from earth and through space at a speed of 3.0 × 108 m/s. how far into space did the signal travel during the first 20.3 minutes?

Speed V = distance / time

3 x 10^8 = s / 1218

s = 3 x 10^8 x 1218

s = 3.654 x 10^11 m

Therefore, the signal will travel into the space as far as 3.654 x 10^11 meters.

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No, the speed does not depend on position, it depends on the change of position.

An item can start at x = -3 and be moving by the time it reaches x = 0 since we know that the displacement is independent of the coordinate system's origin.

Speed is characterized as the rate at which an object's position changes in any direction. The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity. Speed is defined as s = distance/time.

There are four different forms of speed.

constant speed

varying speed

typical speed

Instantaneous speed

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Answer:

8.33 m/s^2

Explanation:

The equation for force is Force = mass * acceleration. The force is 500 N, and the mass is 60 kg, so substituting those into the equation you get that 500 = 60 * acceleration. Divide 500 by 60 to get the acceleration, which is 8.33 m/s^2.

Hope this helps! Let me know if you have any confusion!

The possible hypothesis "different masses of objects fall to the ground at different rates" is a tenable hypothesis.

Thus, A reasonable explanation for an observation is a hypothesis. Every experiment begins with the formulation of a hypothesis. The experiment would now either support or refute the theory that has been proposed.

Remember that an experiment requires both an independent and a dependent variable. The dependent variable is the one that changes when the independent variable changes, but the independent variable is the one that we must keep manipulating.

In this situation, "different masses of objects fall to the ground at different rates" is a tenable hypothesis.

Thus, The possible hypothesis "different masses of objects fall to the ground at different rates" is a tenable hypothesis.

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When the syringe is compressed the pressure spike to a value more than twice its initial value because the temperature of the gas increases.

Pressure is the force applied perpendicularly to an object's surface in relation to the area across which it is applied (symbol: p or P). Gauge pressure is the pressure when compared to the ambient pressure.

Various units are used to express pressure. The pound-force per square inch (psi), which is equal to one newton per square metre (N/m2) in the SI, is the standard unit of pressure in the imperial and U.S. customary systems. Some of these results derive from dividing a unit of force by a unit of area. The atmosphere, which is equal to this pressure, and the torr, which is defined as 1760 of this, are two other ways to describe pressure.

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Answer:

gogle it

Explanation:

i cant help

The block's third dimension is 2.77 cm.

The mass of the osmium block is 1 kg.

The dimensions of the rectangular osmium block are 4 cm × 4 cm.

Density is defined as the mass of the object by the volume of the object.

density = mass / volume

Now, the volume of a rectangle is:

Volume = length × breadth × height

And now let's assume that the block's height is y.

Then,

Volume = length × breadth × height

Volume = 4 cm × 4 cm × y cm

Osmium now has a density of ρ = 22.57 g/cm³.

Therefore, the density of the rectangular osmium will be:

density = mass / volume

[tex]\rho = \frac{1{~}kg}{4{~}cm {~}\times {~}4{~}cm {~}\times {~} y}[/tex]

[tex]22.57 {~}g/cm^{3}=\frac{1000{~}g}{4{~}cm \times 4{~}cm \times y}[/tex]

[tex]16{{~}cm^{2} \times y{~} =\frac{1000{~}g}{22.57{~} g/cm^{3}}[/tex]

16y cm² = 44.31 cm³

Dividing each side of the equation by 16 cm²,

( 16y cm² ÷ 16 cm²) = ( 44.31 cm³ ÷ 16 cm² )

y = 2.77 cm

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The complete question is mentioned below:

The density of osmium is 22.57 g/cm³. If a 1.00kg rectangular block of osmium has two dimensions of 4.00 cm x 4.00 cm, calculate the third dimension of the block.

Answer:

Analytical

Explanation:

The force on each balloon is 2×10^−3 N.

Consider two balloons of diameter 0.200m each with a mass of 1.00g hanging apart with 0.0500m separation on the ends of string making angles of 10.0° with the vertical.

[tex]\sum F_{y} = Tcos10\textdegree - mg = 0\\\\T = \frac{mg}{cos10\textdegree } \\\\\sum F_{y} = Tsin10\textdegree - mg = 0\\[/tex]

So,

[tex]F_{e} = \frac{mg}{cos10\textdegree }sin10\textdegree = mgtan10\textdegree \\\\= (0.00100kg)(9.8m/s^{2})tan10\textdegree \\\\F_{e} = 2 \times 10^{-3}N[/tex]

A force is an influence that can change the motion of an object. A force can cause an object with mass to change its velocity (e.g. moving from a state of rest), i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity. It is measured in the SI unit of newton (N).

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The magnitude of the electric field along the positive z axis due to the ring is equal to Ez = kqz/√(z² + a²)^{3/2}.

Given the following data:

Radius of ring = a.

Charge of ring = q.

Coulomb's constant, k = = 1/4πε₀.

An electric field can be defined as a region in which charged particles are placed with force being applied on the particle as a result of the field.

In order to determine the magnitude of the electric field along the positive z axis, we would apply Coulomb's law in order to find the electric field due to a point charge:

[tex]E = k\frac{q}{r^2}[/tex]

Where:

Note: The value of r is equal to √(z² + a²) and cosθ is equal to z/√(z² + a²).

Substituting the value of r into Coulomb's law, we have;

[tex]E = k\frac{q}{(\sqrt{z^2 + a^2}) ^2}[/tex]

Along the z-direction, the electric field is given by:

dz = dEcosθ

Integrating, we have:

∫dz = ∫dEcosθ

Ez = Ecosθ

[tex]E_z = (\frac{kq}{(\sqrt{z^2 + a^2}) ^2})\frac{z}{\sqrt{z^2 + a^2}} \\\\E_z = \frac{kqz}{(\sqrt{z^2 + a^2}) ^\frac{3}{2} }[/tex]

Ez = kqz/√(z² + a²)^{3/2}.

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Complete Question:

Consider a uniformly charged ring in the xy plane, centered at the origin. The ring has radius a and positive charge q distributed evenly along its circumference. What is the magnitude of the electric field along the positive z axis due to the ring? Use k in your answer, where k = 1/4πε₀

If a car slows down from +32 meters / seconds  to +8 meters / seconds in 4 seconds, then the acceleration of the car would be  -6 meters / second².

The rate of change of the velocity with respect to time is known as the acceleration of the object.

We can calculate the acceleration of the car by using the first equation of motion,

v = u +at

8= 32 + a×4

a =8-32 / 4

a = -6 meters / second²

Thus, the acceleration of the car would be -6 meters / second².

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A balloon clings to a wall after it is negatively charged by rubbing because the wall is positively charged.

Yes, opposite charges attract each other. When a positive charge and a negative charge interact with each other, their forces act from the direction of positive to the direction of negative charge. As a result opposite charges attract each other while on the other hand, similar charges repel each other because their forces move in the opposite direction so they repel each other.

So we can conclude that a balloon clings to a wall after it is negatively charged by rubbing because the wall is positively charged.

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Option(c) is Kilometer is correct. Kilometer unit for length is greater than a meter.

Worldwide adoption of the International System of Units (SI) as a system of measurement units is widespread. For convenience, this updated version of the metric system is based on the number 10. The metric prefixes or the SI prefixes are a collection of prefixes that have been established. According on the prefixes, the unit is either a multiple or a fraction of base ten. It enables the zeros of very small or very high numbers to be reduced, for example, from 7,500,000 Joules to 1 nanometer and from 0.000000001 meter to 7.5 Megajoules, respectively. Additionally, some SI prefixes have a group of symbols before the unit symbol.

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Answer:

1. A

2. D

3. B

4. C

Explanation:

1. A- Aristotle thought that the Earth was flat and that anyone who sailed off the edge of the ocean would fall of Earth, this theory of course later got disproved by Kepler and other scientists

2. D- Kepler suggested the modern model of the Solar System because after months and months of looking out the telescope and making models of the Solar System, Kepler finally made the conclusion of the official Solar System.

3. B- Egyptians thought did not move and all the planets, including the sun revolved around it. Later, Kepler disproved this theory with the modern Solar System.

4. C- This is the path that planets follow to revolve around the Sun. People first thought that planets moved in a circular motion but actually they moved in a ellipse because the Sun's gravity pulled planets closer at some parts more than others.

The charge-to-mass ratio in the second case is 4 times less because of e/M = 0.96x10⁸ N.

The electron beam that travels from the negatively charged cathode to the positively charged anode at the opposite end of the vacuum tube is known as a cathode ray.

As the electron, J. J. Thomson showed that the same beam deflections resulted in tubes having cathodes made of different materials and containing various gases before evacuation.

The elect's load = 1.6x10⁻¹⁹ C

The mass = 9.1x10⁻³¹ kg

e/m = 1.6x10⁻¹⁹/ 9.1x10⁻³¹ = 0.1 758 10 10¹² N

The homogenize has an electron of charge of 1.6x10⁻¹⁹ C

The mass M = 1.673x10⁻²⁷ ka

e/M = 1.6x10⁻¹⁹/1.67x10⁻²⁷ = 0.96x10⁸ N

In the second case, it is 4 times less

Thus, the charge-to-mass ratio in the second case is 4 times less because of e/M = 0.96x10⁸ N.

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The best advice Marta’s supervisor could give her regarding the long answers she is giving is to adapt her communication style (option D).

Communication is the concept or state of exchanging data or information between entities.

A communication is said to be effective when the information passed across is perfectly understood by the recipient.

According to this question, Marta gives long and involved answers to every question, even simple ones. She also uses technical vocabulary even if the people she is talking to do not understand it.

This means that the best advice Marta’s supervisor could give her regarding the long answers she is giving, so as to communicate effectively, is to adapt her communication style.

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The work done by the spring force while it is compressed to the length of 6m is 0.58 J.

The definition of work done includes both the forces applied to the body and the total displacement of the body. When we apply force "F" to a block, the body moves with some acceleration, or, additionally, its speed increases or decreases depending on the direction of the force. The system's kinetic energy changes as speed increases or decreases. Since we are aware that energy cannot be created or destroyed, it must be changed into another form. This perspective refers to it as completed work. When negative energy is finished, the energy declines, and when positive energy is finished, the energy rises.

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Answer:

The farmer is moving at 10 m / 40 s = .4 m/s

2 min 20 sec = 140 sec

The farmer will have moved 140 * .4 = 56 m

To cover the x-axis twice he will have moved x = 10

56 - 50 = 6 m   and he will have moved a distance of 6 on the y-axis

S = (10^2 + 6^2)^1/2 = 11.7 m from the origin