Two numbers have a difference of 13. The sum of twice one number and 3 times the other number is 1. Write a system of equations and solve the system to find the two numbers. You need not show 7 steps for this problem. Just show the system, solve the system, and write the two numbers.

Answer:

first number = 8

second number = -5

Step-by-step explanation:

Let

x = first number

y = second number

Two numbers have a difference of 13.

x - y = 13

The sum of twice one number and 3 times the other number is 1

2x + 3y = 1

x - y = 13 (1)

2x + 3y = 1. (2)

From (1)

x = 13 + y

Substitute into (2)

2x + 3y = 1.

2(13 + y) + 3y = 1

26 + 2y + 3y = 1

26 + 5y = 1

5y = 1 - 26

5y = -25

y = -25/5

y = -5

Substitute y = -5 into (1)

x - y = 13

x - (-5) = 13

x + 5 = 13

x = 13 - 5

x = 8

The obtained number is 12. And the system of equations is 2c + 4p = 40

Although each chicken has two legs and each pig has four legs, the total number of animal legs is:

2c + 4p = 40

Once we simplify the above equation, we get

c + 2p = 20

We also know that there are 16 animal heads in total, which can be expressed as:

c + p = 16

We can solve for "c" that use these two equations.

Once we multiply the second equation by 2, we get:

2c + 2p = 32

Once we subtract this equation from that, we get:

2p = 8

Once we solve for "p," we get:

p = 4

Substituting this "p" value into the second equation yields:

c + 4 = 16

Once we solve for "c," we get:

c = 12

As an outcome, your parents hold 12 chickens.

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