what are the laws of newton​

Answer:

D

Explanation:

5+25=30

Answer:

C. lenses refract light; mirrors do not

This question involves the concepts of reflection and refraction.

The comparison of lenses and mirrors in their interaction with light is "C. Lenses refract light; mirrors do not.".

When it comes to the interaction with light, the key difference between lenses and mirrors is the difference of refraction and reflection. Reflection means the complete rebound of the light rays after striking on a surface without any absorption or transmission. On the other hand, refraction is the  bending of light rays, while passing through a medium, without any rebound or absorption.

Lenses are tansparent from both sides, so they refract the light rays. While, mirrors are coated opaque from one side, so they reflect back the light rays.

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Answer: it causes some parts of the earth to get more radiation than others.

Explanation: earth rotates around the sun on a tilted axis so the Rays of the sun cause earth to have more radiation than it needs.

Answer:

Because shoes protect our feet from some of the most harmful platforms

Gravel has some small pebbles on it sometimes (or other sharp objects)

Gravel is pretty hard.

Answer:

Potential difference and charge will also increase.

Explanation:

Asking that :

What will happen to the charge and potential difference if the plate area were increased while the plate separation remains unchanged?

The charge is directly proportional to area of the plate. That is, increase in area of the plate of a capacitor will lead to the increase in the charges between the plates.

And since charge is also proportional to the magnitude of potential difference between the plates from the definition of capacitance of a capacitor which says that:

Q = CV

Therefore, increase in the area of the plate will also lead to increase in potential difference between the plates.

Therefore, if the plate area were increased while the plate separation remains unchanged, the charge and potential difference between them will also increase.

Answer:

0.25m

Explanation:

Given parameters:

Spring constant , K  = 120N/m

Work done  = 3.75J

Unknown:

magnitude of extension = ?

Solution:

To solve this problem;

           Work done  = [tex]\frac{1}{2}[/tex]kx²  

K is the spring constant

x is the extension

               3.75  =  [tex]\frac{1}{2}[/tex] x 120x²

               3.75  = 60x²

                x²  = 0.06

                x = √0.06  = 0.25m

Answer:

Q' = 320 J

Explanation:

The arrangements are given in attachment. The Fourier's Law of Heat Conduction states that:

Q = KAΔT/L

where,

Q = Heat Transferred

K = Constant (Conduction Coefficient)

A = Surface Area of Heat Transfer

ΔT = Difference of Temperature between two surfaces

L = Length between surfaces

For Arrangement AL

Q = 80 J

Therefore,

80 = KAΔT/L   ------------- equation (1)

Now, for arrangement B:

A' = 2 A (As, the rods are now connected in parallel with each other)

L' = L/2

Therefore,

Q' = K(2A)ΔT/(L/2)

Q' = 4 KAΔT/L

using equation (1)

Q' = 4(80 J)

Q' = 320 J

Answer:

13.5

Explanation:

The acceleration that the same net force would cause to a different box is 14 [tex]m/s^2[/tex].

Given the following data:

Mass of box A = 8 kg

Acceleration = 3.5 [tex]m/s^2[/tex]

Mass of box B = 2 kg

To find the acceleration that the same net force would cause to a different box:

First of all, we would determine the net force acting on box A by applying Newton's Second Law of Motion.

Mathematically, Newton's Second Law of Motion is given by the formula;

[tex]Net\;force = mass \times acceleration\\\\Net\;force = 8 \times 3.5[/tex]

Net force = 28 Newton.

Now, we can determine the acceleration for box B since the same net force act on it.

[tex]Acceleration = \frac{Net\;force}{mass} \\\\Acceleration = \frac{28}{2 }[/tex]

Acceleration = 14 [tex]m/s^2[/tex]

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Answer:

biking to school

Explanation:

plato

Answer:

Work done, W = 2 J

Explanation:

Given that,

Weight of a book, W = F = 1 N

It is lifted to a height of 2 m

We need to find the work done. It can be calculated using the formula as follows :

W = F d

Put all the values,

W = 1 N × 2 m

W = 2 J

So, 2J of work was done.

Answer:

a) s = 79 m W

b) s = 2 km S

c) s = 250 m W

d) s = 0 km  

Explanation:

We take the following sign convention for the directions:

North (N)  ---> positive

South (S)  ---> negative

East (E) ---> negative

West (W)  ---> positive

a)

45 m W, 34 m W

s = 45 m + 34 m

s = 79 m W

b)

5 km N, 7 km S

s = 5 km - 7 km

s = - 2 km

s = 2 km S

c)

350 m E , 800 m W, 200 m E

s = -350 m + 800 m - 200 m

s = 250 m

s = 250 m W

d)

850 km N, 850 km S

s = 850 km - 850 km

s = 0 km

Answer:

Explanation:

The giant star must have at least once been the more massive star and then subsequently transferred some of its mass to its companion, the other star.

The two stars would be around the same age, so the more massive one would have turned into a giant first before the other one did or even had a chance to

Answer:

Diameter of the piston would be 0.71 m (71.1 cm)

Explanation:

From the principle of pressure;

[tex]\frac{F_{1} }{A_{1} }[/tex] = [tex]\frac{F_{2} }{A_{2} }[/tex]

Let [tex]F_{1}[/tex] = 2903.57 lb, [tex]F_{2}[/tex] = 24.41 lbs, [tex]r_{2}[/tex] = 3.26 cm = 0.0326 m.

[tex]A_{2}[/tex] = [tex]\pi r^{2}[/tex]

    = [tex]\frac{22}{7}[/tex] x [tex](0.0326)^{2}[/tex]

    = 0.00334 [tex]m^{2}[/tex]

So that:

[tex]\frac{2903.57}{A_{1} }[/tex] = [tex]\frac{24.41}{0.00334}[/tex]

[tex]A_{1}[/tex] = [tex]\frac{2903.57*0.00334}{24.41}[/tex]

    = 0.3973

[tex]A_{1}[/tex] = 0.4 [tex]m^{2}[/tex]

The radius of the piston can be determined by:

[tex]A_{1}[/tex] = [tex]\pi r^{2}[/tex]

0.3973 = [tex]\frac{22}{7}[/tex] x [tex]r^{2}[/tex]

[tex]r^{2}[/tex] = [tex]\frac{0.3973*7}{22}[/tex]

   = 0.1264

r = [tex]\sqrt{0.1264}[/tex]

 = 0.3555

r = 0.36 m

Diameter of the piston = 2 x r

                                     = 2 x 0.3555

                                     = 0.711

Diameter of the piston would be 0.71 m (71.1 cm).

Answer:

the graph that show Change in velocity is no A

The graph that showing the velocity with respect to time for a free falling body is figure C where, the downward velocity will be higher due to the acceleration due to gravity.

Velocity of a moving body is the measure of the distance covered per unit time. Thus, it is the ratio of distance to the time. Velocity is expressed in the units of Km/h, m/s. miles/h, ft./s etc.

The rate of change of velocity is called acceleration. The acceleration by the force of a gravitational field is called acceleration due to gravity g having the value 9.8 m/s².

The velocity - time graph shows a diagonal relation for a free falling body. A free falling body is initially at rest and falls downward with the negative velocity with the acceleration due to gravity. Therefore, figure B shows the change in velocity of a free falling body.

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Given :

Current, I = 3.75 A .

Magnetic Field, [tex]B = 2.61\times 10^{-4}\ T[/tex]

To Find :

The distance from the wire.

Solution :

We know,

[tex]B = K\dfrac{2i}{d}\\\\d = 10^{-7}\times \dfrac{2\times 3.75}{2.61\times 10^{-4}}\\\\d = 0.00287\ m \\\\d = 2.87\times 10^{-3}\ m[/tex]

Hence, this is the required solution.

Answer:

1.45

Explanation:

Refractive index of the liquid is given as;

Refractive index = [tex]\frac{speed of light in vacuum}{speed of light in liquid}[/tex]

But,

speed = [tex]\frac{distance}{time}[/tex]

Since a certain light of specific wavelength was used during the same time, let the time be represented by t.

So that;

speed of light in vacuum = [tex]\frac{3500}{t}[/tex]

speed of light in the liquid = [tex]\frac{2350}{t}[/tex]

Refractive index = [tex]\frac{3500}{t}[/tex] ÷ [tex]\frac{2350}{t}[/tex]

                            = [tex]\frac{3500}{t}[/tex] x [tex]\frac{t}{2350}[/tex]

Refractive index = [tex]\frac{3500}{2350}[/tex]

                          = 1.4536

                          = 1.45

The refractive index of the liquid is 1.45.

Answer:

The induced current is  [tex]I = 0.00066 \ A[/tex]

Explanation:

From the question we are told that

   The area is  [tex]A = 7.10 \ cm^2 = 7.10 *10^{-4} \ m^2[/tex]

   The initial  magnetic field is  [tex]B_i = 0.500 \ T[/tex]

    The magnetic field after t =1.07 s is  [tex]B_f = 2.10 \ T[/tex]

     The resistance of the loop is [tex]R = 1.60 \ \Omega[/tex]

Generally the electromagnetic field induced is mathematically represented as

   [tex]\epsilon = NA * \frac{B_f - B_i}{t}[/tex]

Where N is the number of turns which is 1 in the case of this question since there is only one loop

 So

       [tex]\epsilon = 1 * 7.10*10^{-4}* \frac{2.10 - 0.500}{1.07 }[/tex]

=>   [tex]\epsilon = 0.00106 \ V[/tex]

Generally the value of the current is mathematically represented as

        [tex]I = \frac{\epsilon}{R}[/tex]

       [tex]I = \frac{0.00106}{1.60}[/tex]

       [tex]I = 0.00066 \ A[/tex]

Answer:

V' = V/2

Explanation:

The voltage across a parallel plate capacitor is given as follows:

V = Q/C

where,

V = Voltage across capacitor

Q = Charge on Capacitor

C = Capacitance of Capacitor = A∈₀/d

Therefore,

V = Qd/A∈₀

where,

A = Area of plate

d = distance between plates

∈₀ = permittivity of free space

FOR CAPACITOR 1:

Q = Q

d = d

A = A

V = V

Therefore,

V = Qd/A∈₀   --------------- equation (1)

FOR CAPACITOR 2:

V' = ?

Q' = Q

d' = d

A' = 2A

Therefore,

V' = Q'd'/A'∈₀

V' = Qd/2A∈₀

V' = (1/2)(Qd/A∈₀)

using equation (1):

V' = V/2

Answer:

Explanation:

cross sectional area = .4 x .2 = .08 m²

Let n be the number of blocks required to make pressure = 2 atm

169 x n / .08 = 2 x 10⁵ N / m²

169 x n = .16 x 10⁵

n = 94.67

or 95 blocks .

Answer:should be a matter of vector analysis.

Pulling above the horizontal has less surface area for the opposing friction

Explanation:

Answer:

This question is incomplete.

Explanation:

This question is incomplete. However, it should be noted that the voltage, V, across resistors in parallel is the same (although there currents are not the same). Thus, if a voltage has been provided, it remains the same but if not provided, you can solve for it using the formulas below

V = IR

where V is the voltage. I is the current and R is the resistance

R in parallel can be calculated as R = 1/R₁ + 1/R₂ + 1/R₃ + ......

Answer:B

Explanation: The book is thinner making magnets attraction stronger, making the paper clip harder to move

Answer:

A. The acceleration is the same for both bullets.

Explanation:

The force of gravity is the attractive force applied by the earth on any object on its surface or neighborhood. And it is uniform under free fall at a definite location on the earth.

Since the the two bullets motion was at the same time and without air resistance, their acceleration would be the same before striking the surface of the water. This is because neglecting air resistance, all objects at the same height would fall with the same acceleration no matter their masses.

Answer:

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This is normally taken as the definition of inertia. ... If that velocity is zero, then the object remains at rest.

Explanation:

Answer:

Newton's First Law is about inertia; objects at rest stay at rest unless acted upon and objects in motion continue that motion in a straight line unless acted upon. The amount of inertia an object has is simply related to the mass of the object.

Answer:

it would be 49.03325 Newton.

Answer:

Newton's theory because he suggested that the greater the distance between objects, the weaker the pull of gravity.

Answer: The answer is Newton’s theory because he suggested that the greater the distance between objects, the weaker the pull of gravity

Explanation: Just took the test i hope this help you enjoy :D

Answer:

to show the arts and creativity of the person and to show also the culture of the place..

Explanation:

Answer:

The workdone is  [tex]W = 1.712 *10^{-20 } \ J[/tex]  

Explanation:

From the question we are told that

    The potential difference is  [tex]V = 107 mV = 107 *10^{-3} \ V[/tex]

Generally the charge on  [tex]Na^{+}[/tex] is  [tex]Q_{Na^{+}} = 1.60 *10^{-19 } \ C[/tex]

 Generally the workdone is mathematically represented as

         [tex]W = Q_{Na^{+}}V[/tex]

=>     [tex]W = 1.60 *10^{-19 } * 107 *10^{-3}[/tex]    

=>     [tex]W = 1.712 *10^{-20 } \ J[/tex]