Answers:
1. Chemistry
2. Cold
3. Heat
4. Protons and neutrons
5. Positive
6. Neutral
7. True
8. Nucleus
9. Protons
10. Nobel gasses
11. Dmitri Mendeleev
12. the bottom of the square
13. True
14. Helium
Why do some transition metals have multiple oxidation states?
Transition metals have multiple oxidation states because of their
sublevel.
Answer:
Transition metals can have multiple oxidation states because of their electrons. The transition metals have several electrons with similar energies, so one or all of them can be removed, depending the circumstances. This results in different oxidation states.
Answer:
The answers are "partially filled" and "d" on Plato
Explanation:
If 35.00 mL of 3.00 M KOH reacted completely (according to our equation), what mass of aluminum has reacted?
Answer:
Explanation:
25 Mass
The mass of the aluminum that has reacted is equal to 2.84 grams.
What is the balanced chemical equation?A chemical equation of a reaction contains of reactants, formed products, and an arrow indicating the direction of the given reaction. The balanced chemical equation in which the number of atoms is equal on either side of the equation. The law of conservation of mass should be followed by a balanced equation.
The chemical equation of the reaction of the KOH and Al is :
[tex]Al + KOH + H_2O \longrightarrow KAl(OH)_4 + H_2[/tex]
From the above equation, we can say that one mole of aluminum is reacting with one mole of KOH.
Given the volume and concentration of KOH are 35 ml and 3.0 M.
The moles of KOH = 3 × 0.035 = 0.105 mol
Therefore, the moles of Al will react = 0.105 mol
The mass of Al will react with KOH = 0.105 × 27 = 2.84 g
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Balance chemical equation hbr(aq)+o2(g) h20+br2
Answer:
2HBr + O2 = H20 +Br2
Explanation:
Answer:
4hbr(aq) + O2(g) = 2H2O + 2Br2
Explanation:
Ammonia (NH3) is the active cleaning ingredient in Windex and is also the main contributor to the odor of stale cat urine. Ammonia has a ΔH°vap of 23.35 kJ/mol and a ΔS°vap of 97.43 J/mol·K. What is the normal boiling point of ammonia
Answer:
[tex]T_b=239.7K=-33.49\°C[/tex]
Explanation:
Hello!
In this case, since the relationship between entropy and enthalpy for any process is defined below:
[tex]S=\frac{H}{T}[/tex]
For the vaporization of ammonia or any liquid, we can write:
[tex]\Delta S_{vap}=\frac{\Delta H_{vap}}{T_{vap}}[/tex]
In such a way, solving the temperature of vaporization, or boiling point, we have:
[tex]T_{vap}=\frac{\Delta H_{vap}}{\Delta S_{vap}}[/tex]
Plugging in the given enthalpy and entropy of vaporization we obtain:
[tex]T_{vap}=T_b=\frac{23350\frac{J}{mol} }{97.43\frac{J}{mol*K}} \\\\T_b=239.7K=-33.49\°C[/tex]
Best regards!
From the information provided in the question, the boiling point of ammonia is 240 K.
Entropy is the degree of disorderliness in a system. The entropy of a system can be obtained using the relation;
ΔS°vap = ΔH°vap /T
Now;
ΔH°vap = 23.35 kJ/mol
ΔS°vap = 97.43 J/mol·K
T = ?
Making T the subject of the formula and substituting values;
T = ΔH°vap /ΔS°vap
T = 23.35 × 10^3J/mol/97.43 J/mol·K
T = 240 K
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Which pair of elements would you expect to have similar properties?
Li and Fe
At and F
F and o
Ge and As
The compound stannous(II) nitride is incorrectly named. Rename the compound correctly.
Answer:
Answer: Tin (II) nitride
Please i really need help it's due today
Answer:
there is your answer hope it helped :3
What factors affect the speed of a wave? Check all that apply. the amplitude of the wave the energy of the wave the temperature of the medium the type of wave the type of medium
Answer:
I believe its 1,2, and 5
Explanation:
C D E
temperature of medium
type of wave
type of medium
What is the molality of 6 grams of salt in 10 grams of solution?
Answer:
maalat ang salt
Explanation:
Which of these statements best answers the question: What is art?
Answer:
You didn't provide any statements. If it is an option, art is a form of expression. Something created from imagination that expresses the thoughts and emotions of the artist.
The statement that best answers the question: What is art is that—Art is a form of visual language. Therefore, the correct option is A.
What is an art?Art is a diverse range of human activities and products that are created with the intention of expressing the imagination, emotions, or ideas, or to make a statement, in a visually appealing way.
Art can take many forms, including visual arts (such as painting, sculpture, and photography), performing arts (such as music, dance, and theater), and literary arts (such as poetry and prose).
It is typically seen as a form of communication and can be used to convey ideas, emotions, or political, social or cultural messages. It can also be used to simply evoke a response or emotion in the viewer, or to create a sense of beauty or aesthetic enjoyment. Therefore, the correct option is A.
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The question is incomplete, but most probably the complete question is,
Which of these statements best answers the question: What is art?
A. Art is a form of visual language.
B. Art is a form of written language.
C. Art is a form of spoken language.
D. Art is a form of dance language.
Determine the vapor pressure of a solution at 25°C that contains 76.6 g of glucose (C6H12O6 ) in 250.0 mL of water. The vapor pressure of pure water at 25°C is 23.8 torr
Answer:
[tex]23.093\ \text{torr}[/tex]
Explanation:
[tex]M_g[/tex] = Molar mass of glucose = 180.2 g/mol
[tex]M_w[/tex] = Molar mass of water = 18 g/mol
[tex]m_g[/tex] = Mass of glucose = 76.6 g
[tex]m_w[/tex] = Mass of water = [tex]250\times 1\ \text{g/mL}=250\text{g}[/tex]
[tex]P_0[/tex] = Vapor pressure of pure water at 25°C = 23.8 torr
The mole fraction of glucose is
[tex]x_g=\dfrac{\dfrac{m_g}{M_g}}{\dfrac{m_g}{M_g}+\dfrac{m_w}{M_w}}=\dfrac{\dfrac{76.6}{180.2}}{\dfrac{76.6}{180.2}+\dfrac{250}{18}}\\\Rightarrow x_g=0.0297[/tex]
Mole fraction of the solute would be
[tex]\dfrac{P_0-P}{P_0}=x_g\\\Rightarrow 0.0297=\dfrac{23.8-P}{23.8}\\\Rightarrow P=23.8-0.0297\times23.8\\\Rightarrow P=23.093\ \text{torr}[/tex]
The vapor pressure of the solution is [tex]23.093\ \text{torr}[/tex].
The reaction between iron(II) oxide and carbon monoxide produces iron and carbon dioxide. How many moles of iron can be obtained when 1.50 mol FeO reacts with an excess of CO ?
FeO+CO⟶Fe+CO2
Answer:
1.5 moles of Fe produced.
Explanation:
Given data:
Moles of FeO react = 1.50 mol
Moles of iron produced = ?
Solution:
Chemical equation:
FeO + CO → Fe + CO₂
Now we will compare the moles of ironoxide with iron.
FeO : Fe
1 : 1
1.5 : 1.5
Thus from 1.5 moles of FeO 1.5 moles of Fe are produced.
1.5 moles of Fe can be obtained when 1.50 mol of FeO reacts with an excess
of CO
Moles of FeO reacted = 1.50 mol
Moles of iron produced = ? mol
The chemical equation is given as
FeO + CO → Fe + CO₂
Comparisons of FeO and Fe show they are in the ratio 1 : 1
FeO : Fe
1.5 : 1.5
which translates to the number of moles being equal
Therefore, 1.5 moles of FeO 1.5 moles of Fe are produced.
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How does body temperature, energy level, and water level affect a person’s ability to survive?
What shape is the s sublevel? *
sphere
freaky
peanut
daisy
Answer:
Sphere
Explanation:
The shape of the s-sublevel is spherical in shape.
This sublevel has an azimuthal quantum number of 0 and it is spherical in shape;
p - sublevel has a dumb-bell shape d - sublevel has double dumb - bell shape f - sublevel has a complex shapeWhich numerical setup can be used to calculate the
atomic mass of the element bromine?
Answer:
From the numerical steps highlighted under explanation, the average atomic mass of bromine is 79.91 u
Explanation:
The steps to be taken will involve;
1) Find the number of isotopes of bromine.
2) Identify the atomic mass and relative abundance of each of the isotopes.
3) Multiply the atomic mass of each of the isotopes by their corresponding values relative abundance value.
4) Add the value in step 3 above to get the average atomic mass of bromine.
Now;
Bromine has 2 isotopes namely;
Isotope 1: Atomic mass = 78.92amu and a relative abundance of 50.69%.
Isotope 2: Atomic mass = 80.92amu and a relative abundance of 49.31%.
Using step 3 above, we have;
(78.92 × 50.69%)
And (80.92 × 49.31%)
Using step 4 above, we have;
(78.92 × 50.69%) + (80.92 × 49.31%) ≈ 79.91 u
The atomic mass of bromine has been calculated as 79.9062 amu.
The relative atomic mass of the element has been given as the mass of each isotope with respect to their abundance.
The atomic mass has been given as:
[tex]amu=\sum mass\;\times\;\% Abundance[/tex]
The available isotopes of Bromine have been:
Isotope 1 = 78.92 amu, and 0.5069 % abundance
Isotope 2= 80.92 amu, and 0.4931 % abundance
Submitting the values for the atomic mass unit of bromine ([tex]amu_{\text{Br}}[/tex]):
[tex]amu_{\text {Br}}= (78.92\;\times\;0.5069)\;+\;(80.92\;\times\;0.4931)\\amu_{\text{Br}}=40.0045\;+\;39.9016\\amu_{\text{Br}}=79.9062[/tex]
The atomic mass of bromine has been calculated as 79.9062 amu.
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How many liters of CH3OH gas are formed when 3.20 L of H2 gas are completely reacted at STP according to the following chemical reaction?
Remember 1 mol of an ideal gas has a volume of 22.4 L at STP
CO(g) + 2 H₂(g) → CH₃OH(g)
Answer:
1.6 L CH3OH
Explanation:
3.20 L H2 x (1 mol H2/22.4 L H2) x (1 mol CH3OH/2 mol H2) x (22.4 L CH3OH/1 mol CH3OH) = 1.60 LCH3OH
1.602 liters of CH₃OH gas are formed when 3.20 L of H₂ gas are completely reacted at STP according to the following chemical reaction:
CO(g) + 2 H₂(g) → CH₃OH(g)
Remember 1 mol of an ideal gas has a volume of 22.4 L at STP
To find the volume of CH₃OH gas formed when 3.20 L of H₂ gas is completely reacted, we need to use stoichiometry and the given balanced chemical equation.
The balanced equation is:
CO(g) + 2 H₂(g) → CH₃OH(g)
From the balanced equation, we can see that 1 mol of CO reacts with 2 moles of H₂ to produce 1 mole of CH₃OH.
Step 1: Convert the given volume of H₂ gas to moles at STP.
Using the information provided, 1 mol of any ideal gas at STP (Standard Temperature and Pressure) occupies 22.4 L.
Number of moles of H₂ gas = Volume of H2 gas at STP / Volume of 1 mol of H₂ gas at STP
Number of moles of H₂ gas = 3.20 L / 22.4 L/mol
Number of moles of H₂ gas = 0.14286 moles (rounded to 5 decimal places)
Step 2: Use stoichiometry to find the moles of CH₃OH formed.
From the balanced equation, we know that 1 mol of CO reacts with 2 moles of H₂ to produce 1 mole of CH₃OH.
Since the ratio of H₂ to CH₃OH is 2:1, the number of moles of CH₃OH formed will be half of the moles of H₂ used in the reaction.
Number of moles of CH₃OH = (1/2) * Number of moles of H₂
Number of moles of CH₃OH = (1/2) * 0.14286
Number of moles of CH₃OH = 0.07143 moles (rounded to 5 decimal places)
Step 3: Convert the moles of CH₃OH to volume at STP.
Using the information provided, 1 mol of any ideal gas at STP (Standard Temperature and Pressure) occupies 22.4 L.
Volume of CH₃OH gas at STP = Number of moles of CH₃OH * Volume of 1 mol of CH₃OH gas at STP
Volume of CH₃OH gas at STP = 0.07143 moles * 22.4 L/mol
Volume of CH₃OH gas at STP = 1.602 L (rounded to 3 decimal places)
Therefore, approximately 1.602 liters of CH₃OH gas are formed when 3.20 liters of H₂ gas are completely reacted at STP.
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What is the mole fraction of water in a solution that contains 8.0 mol of ethanol (C2H5OH) and 1.6 mol of water?
Answer:
the mole fraction of water in a solution is 0.17
Explanation:
The computation of the mole fraction of water in a solution is shown below:
Given that
Ethanol be 8.0 mol
And, the water be 1.6 mol
Based on the above information, the mole fraction of water in a solution is
= Water ÷ (Water + ethanol)
= 1.6 mol ÷ (1.6 mol + 8.0 mol)
= 1.6 mol ÷ 9.6 mol
= 0.17
Hence, the mole fraction of water in a solution is 0.17
Assume that the top of your head has a surface area of 25 cm x 25 cm. How many newtons of force push on your head at sea level? If you estimate this area to be 100 in2, what is the force in pounds?
Answer:
(a) 6332.812 N (b) 1469.59 pounds.
Explanation:
Given that,
The surface area of the top of yu head is 25 cm x 25 cm
Area = 625 cm² = 0.0625 m²
Atmospheric pressure on it is 101325 Pa.
(a) Pressure acting on an object is given by force acting per unit area. It can be written as :
[tex]P=\dfrac{F}{A}\\\\F=PA\\\\F=101325\ Pa\times 0.0625\ m^2\\\\F=6332.812\ N[/tex]
6332.812 N of force is acting on your head at sea level.
(b) If area, A = 100 in²
We know that,
1 atm = 14.6959 pounds/in²
[tex]P=\dfrac{F}{A}\\\\F=PA\\\\F=14.6959 \ \text{Pounds}/in^2\times 100\ in^2\\\\F=1469.59\ \text{pounds}[/tex]
So, the force is 1469.59 pounds.
A. The force required to push your head at sea level is 6332.8125 N
B. The force in pound is 1469.59 lb
A. Determination of the force required at sea level.
Pressure (P) = 101325 Nm²
Area (A) = 25 cm × 25 cm = 0.25 m × 0.25 m = 0.0625 m²
Force (F) =?P = F / A
Cross multiply
F = PA
F = 101325 × 0.0625
F = 6332.8125 NTherefore, the force required to push your head at sea level is 6332.8125 N
B. Determination of the force in pounds
Area (A) = 100 in²
Pressure (P) = 14.6959 pound / in²
Force (F) =?F = PA
F = 14.6959 × 100
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The initial concentration of NOCl in the second-order reaction 2NOClâ2NO+Cl2 is 0.878M. After 763,200 seconds, the concentration of NOCl is 0.83M. What is the rate constant k for the reaction? Report your answer in scientific notation rounded to two significant figures. Use the multiplication symbol when reporting your answer rather than the letter x. Provide your answer below: $$ 1/M s
Answer:
[tex]k=8.63x10^{-8}\frac{1}{M*s}[/tex]
Explanation:
Hello!
In this case, since the differential rate law of a second-order reaction is:
[tex]\frac{dC_A}{dt}=-kC_A^2[/tex]
Whereas A stands for NOCl and the corresponding integrated rate law is:
[tex]\frac{1}{C_A} =kt+\frac{1}{C_A_0}[/tex]
Thus, since we know the concentrations and the elapsed time, we compute the rate constant as shown below:
[tex]k=( \frac{1}{C_A}-\frac{1}{C_A_0} )/t\\\\k=( \frac{1}{0.83M}-\frac{1}{0.878M} )/763,200s\\\\k=8.63x10^{-8}\frac{1}{M*s}[/tex]
Best regards!
A teacher is giving a lecture on the changes in world population over the last decade. Which is the best visual aid for
the teacher to use?
O a bar graph
O a map
• a line graph
O a diagram
Answer:
The correct answer would be C.) a line graph
Explanation:
I just did the assignment on edge 2020 and got it right
The following concerns the combustion of nitromethane (CH3NO2 - a popular fuel for top-fuel dragsters) according to the reaction below:_______. 2 CH3N02 (1) + ž02(g) → 2C02) + 3H20 (1) + N2(9) a. Burning 121 L of nitromethane at constant pressure releases 1.6 x 100 kJ of energy. What is the enthalpy of combustion of this reaction? The density of nitromethane is 1.16 g/cm². b. Assume you transfer heat involved in the previous problem to 1 kL of water that is initially at 25.0 °C. What is the final temperature of the water?
Answer:
695.8kJ/mol = Enthalpy of combustion
Final temperature = 407.4°C
Explanation:
Taken the reaction:
2CH₃NO₂ + 3/2 O₂ → 2CO₂ + 3H₂O + N₂
The enthalpy of the reaction is the heat released when 1 mole of nitromethane are in combustion.
We need to find the moles presents in 121L of nitromethane using its density and molar mass (61.04g/mol). As these moles releases 1.6x10⁶kJ, we need to find heat released per mole of nitromethane
Mass nitromethane:
121L = 121000cm³ * (1.16g/cm³) = 140360g
Moles:
140360g * (1mol / 61.04g) = 2299.5 moles of nitromethane
Heat released per mole of nitromethane:
1.6x10⁶kJ / 2299.5 mol = 695.8kJ/mol = Enthalpy of combustion
The symbol - is because the heat is released, a + symbol is when the heat is absorbed.
Using:
Q = m×C×ΔT
Where Q is heat (1.6x10⁶kJ = 1.6x10⁹J)
m is mass of water:
1kL = 1000L = 1x10⁶mL = 1x10⁶g
C is specific heat of water: 4.184J/g°C
And ΔT is change in temperature.
Solving for ΔT:
1.6x10⁹J = 1x10⁶g * 4.184J/g°C * ΔT
ΔT = 382.4°C
As initial temperature was 25°C, final temperature is:
382.4°C + 25°C =
407.4°C
The inside window pane in your house feels very cold to touch on a winter night. How does the heat transfer?
Question 9 options:
A. Heat transfers from the window pane to your hand.
B. Heat transfers from your hand to the window pane.
Answer:
its B
Explanation:
Because its can only go cold to hot. -hope this help :)
What is the ratio of potassium atoms to oxygen atoms in potassium oxide (K2O)?
K20
K = 1+
0 = 2-
K/0 = 1/2
the answer is K:O = 1:2
Select the best answer from the choices below. Light has many properties of waves, but sometimes it also behaves like:
Answer:
A photon
Explanation:
When electrons pass close to the standing wave of light, they hit the particles that are called photons
How many oxygen atoms will there be in the balanced equation of Al+O2-Al2O3
Answer: 10
Explanation:
4Al + 2O2 --> 2Al2O3
This is the balanced equation so there are 2*2 +2*3 = 4+6 =10
given that the only known ionic charges of lead are pb(ii) and pb(iv), how can you explain the existence of the pb2o3 salt
Answer:
See Explanation
Explanation:
Pb2O3 is better formulated as PbO.PbO2. It is actually a mixture of the two oxides of lead, lead II oxide and lead IV oxide.
This implies that this compound Pb2O3 (sometimes called lead sesquioxide) is a mixture of the oxides of lead in its two known oxidation states +II and +IV.
Hence Pb2O3 contains PbO and PbO2 units.
PLZ HELP PLZ
NO WRONG ANSWERS
Answer:
it is C
Explanation:
because Potassium iodide (KI) is an ionic compound which is made of the following ions: K+I−
What does this image represent?
Amine group
Carbonyl group
Ether group
Hydroxyl group
Answer:
ether group
Explanation: I looked it up
Visible light has an average wavelength of 550 nm. How much energy would be in this wavelength of light? 5 x 10-19
Answer:
E = 3.6×10⁻¹⁹ J
Explanation:
Given data:
Wavelength = 550 nm (550 ×10⁻⁹ nm)
Energy of wave = ?
Solution:
Formula:
E = h c/λ
c = 3×10⁸ m/s
h = 6.63×10⁻³⁴ Js
Now we will put the values in formula.
E = 6.63×10⁻³⁴ Js × 3×10⁸ m/s /550 ×10⁻⁹ nm
E = 19.89×10⁻²⁶ J.m /550 ×10⁻⁹ nm
E = 0.036×10⁻¹⁷ J
E = 3.6×10⁻¹⁹ J
According to the following reaction, how many moles of hydrobromic acid are necessary to form 0.274 moles bromine?
hydrobromic acid (aq) —>hydrogen (g) + bromine (1)
moles hydrobromic acid
Answer:
0.548 moles of HBr are required
Explanation:
Given data:
Number of moles of hydrobromic acid = ?
Moles of bromine formed = 0.274 mol
Solution:
Chemical equation:
2HBr → H₂ + Br₂
Now we will compare the moles of HBr with Br₂.
Br₂ : HBr
1 : 2
0.274 : 2×0.274=0.548
Thus, 0.548 moles of HBr are required.